Camille buys a cake for $\$24.99$ . She also buys $12$ brownies. Each brownie costs the same amount. She spends $\$39.99$ on the cake and the brownies.

Camille finds the cost of each brownie by calculating $(39.99\ -\ 24.99)\ \div\ 12$ . Tanya finds the cost of each brownie by solving the equation $39.99\ +\ 12b\ =\ 24.99$ , where $b$ is the cost of each brownie.

Which approach uses the sequence of operations necessary to find the cost of each brownie: Camille’s, Tanya’s, both, or neither? Explain why.

Respond in the space provided.

Answer:

39.99-24.99=15

15/12=$1.25

$1.25 per brownies

Camille approach correct sequence.

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Camille buys a cake for $24.99.

She bought total 12 brownies.

She spend total $39.99 on cake and brownies.

So, to calculate the cost of each brownies

24. 99 + 12b = 39.99

12b = 39.99 - 24.99

12b = 15

b = $1.25

Learn more about Unitary Method here:

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