Casho went shopping for a new pair of sneakers because of a sale. The price on the tag was $25, but Casho paid $22. 50 before tax. Find the percent discount

The value of x which is not a solution to the inequality 5 - 2x ≥ -3, is x = 6.

To find out which value is not a solution to the inequality 5 - 2x ≥ -3, we can substitute each value into the inequality and see if it is true or false.

Let's start with the first value, [tex]x=4[/tex]:

5 - 2(4) ≥ -3
5 - 8 ≥ -3
-3 ≥ -3

Since -3 is greater than or equal to -3, x = 4 is a solution of the inequality.

Now let's try x = 6:

5 - 2(6) ≥ -3
5 - 12 ≥ -3
-7 ≥ -3

Since -7 is less than -3, x = 6 is not a solution of the inequality.

Therefore, the answer is x = 6.

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To find the value of a² + bc√(-d) when a = -3, b = 2, c = 100, and d = -2, follow these steps:

Step 1: Substitute the values into the expression.
a² + bc√(-d) = (-3)² + (2)(100)√(-(-2))

Step 2: Simplify the expression.
(-3)² + (2)(100)√(2) = 9 + 200√2

So, the value of a² + bc√(-d) when

a = -3,

b = 2,

c = 100,

d = -2 is 9 + 200√2.

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57 students most likely got heads between 45 and 60 times.

To determine the number of students who got heads between 45 and 60 times, we'll use the normal distribution properties. First, we need to calculate the z-scores for 45 and 60:

Z = (X - μ) / σ

For 45 heads:
Z1 = (45 - 50) / 5 = -1

For 60 heads:
Z2 = (60 - 50) / 5 = 2

Next, we need to find the probability that a student falls between these z-scores. We can do this by looking up the z-scores in a standard normal distribution table or using a calculator. The probabilities corresponding to these z-scores are:

P(Z1) = 0.1587
P(Z2) = 0.9772

Now, subtract P(Z1) from P(Z2) to get the probability of a student's result falling between 45 and 60 heads:

P(45 ≤ X ≤ 60) = P(Z2) - P(Z1) = 0.9772 - 0.1587 = 0.8185

Finally, multiply this probability by the total number of students (70) and round to the nearest whole number:

Number of students = 0.8185 * 70 ≈ 57

So, approximately 57 students most likely got heads between 45 and 60 times.

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Answer is The smaller angle is 35°.

To solve for the acute angles in a right triangle when sin(5x)° = cos(3x + 2)°, we need to use trigonometric identities.

Recall that sin(x) = cos(90 - x) for any angle x. Using this identity, we can rewrite sin(5x)° as cos(90 - 5x)°.

Similarly, cos(x) = sin(90 - x) for any angle x. Using this identity, we can rewrite cos(3x + 2)° as sin(90 - (3x + 2))°, which simplifies to sin(88 - 3x)°.

Now we have cos(90 - 5x)° = sin(88 - 3x)°. Since these two expressions are equal, we can set them equal to each other and solve for x:

cos(90 - 5x)° = sin(88 - 3x)°

sin(5x)° = sin(88 - 3x)°

5x = 88 - 3x

8x = 88

x = 11

Therefore, the acute angles in the right triangle are 5x° and 90 - 5x°, or 55° and 35°. The smaller angle is 35°.

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Using various laws of integers we can say that if a is a positive integer and b is a negative integer, statement A is False, B is True, C s True and D is false.

Here we are given that a is a positive integer while b is a negative integer.

A. The statement says that the difference (a - b) could be negative.

According to the subtraction law of integers, when a negative number is subtracted from a positive number, that is we have

2 - (-3)

Here the 2 minus signs will make a positive to give

2 + 3 = 5

Hence (a - b) will be a positive number since b is negative.

B.

The difference (b - a) cannot be positive.

Since a is positive and b is negative, according to the above example we will get

-3 - 2 = -5

Hence it is true that the difference (b - a) can't be positive.

C.

The sum (a + b) could be positive.

Here, we can see that a is a positive number while b is a negative number. In the light of above example, we will get

2 - 3 = -1

Here the sum is nagative as 3 > 2, but if we had

3 + (-2), then the answer would have been 1. Hence (a + b) can be positive. Hence the statement is true.

D.

The sum (b + a) must be negative.

Integers have commutative properties. Hence a + b = b + a

Hence if a + b can be positive, then b + a can also be positive.

Hence the statement is False.

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The mover is communicating that the weight of the table and 4 chairs combined, represented as t+4C, is greater than or equal to 100 pounds.

The expression t+4C represents the total weight of the table and 4 chairs. The mover's invoice states that this total weight is greater than or equal to 100 pounds, which means that the combined weight of the table and chairs is at least 100 pounds. Therefore, the correct answer is D, "The table and 4 chairs weigh at least 100 pounds."

To solve this mathematically, we can use algebraic inequalities. The inequality t+4C >_ 100 can be rearranged as t >_ 100-4C. This means that the weight of the table t must be greater than or equal to 100 minus four times the weight of a single chair C.

If each chair weighs less than 25 pounds, then the total weight of the table and 4 chairs combined will be at least 100 pounds. So D is correct answer.

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El intervalo correspondiente de millas que Juana puede manejar su nuevo auto está entre 10,000 y 14,000 millas.

Para determinar el intervalo correspondiente de millas que Juana puede manejar su nuevo auto, podemos resolver la fórmula del costo anual en términos de la variable m (millas recorridas por año). Dado que el costo anual está entre $6400 y $7100, podemos establecer la siguiente desigualdad:

6400 ≤ 0.35m + 2200 ≤ 7100

Restando 2200 en los tres lados de la desigualdad, obtenemos:

4200 ≤ 0.35m ≤ 4900

Dividiendo por 0.35 en los tres lados, obtenemos:

12000 ≤ m ≤ 14000

Por lo tanto, Juana puede manejar su nuevo auto en un intervalo de millas que va desde 12000 millas hasta 14000 millas por año.

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The volume of the prism in 120 cubic centimeter.

Volume is a measure of the amount of space occupied by a three-dimensional object. It is a scalar quantity that characterizes the "size" or "capacity" of an object in three dimensions.

A prism is a three-dimensional geometric shape that has two parallel and congruent bases connected by lateral faces that are typically rectangular or parallelogram-shaped. Prisms are classified based on the shape of their base, such as rectangular prisms, triangular prisms, pentagonal prisms, hexagonal prisms, and so on. The lateral faces of a prism are perpendicular to the bases, and the bases are usually parallel to each other.

According to the given information:

Given the measures of prism is length = 8cm, breadth = 6 cm, height = 5 cm

The formula for volume of prism = 1/2 l*b*h

                                                      = 1/2 8*6*5

                                                      = 120 cubic centimeter

Hence the volume of prism is 120 cubic centimeter.

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the partial derivative ∂z/∂y using implicit differentiation of e^z + sin(5x^2) + 2y = 0 is:
To calculate the partial derivative ∂z/∂y using implicit differentiation of e* + sin (5x^2) + 2y = 0, we first need to differentiate both sides of the equation with respect to y.

We get:

d/dy(e^z + sin(5x^2) + 2y) = d/dy(0)

Using the chain rule, the left-hand side becomes:

∂(e^z)/∂z * ∂z/∂y + ∂(sin(5x^2))/∂y + 2

We can simplify this by recognizing that ∂(sin(5x^2))/∂y = 0, since sin(5x^2) does not depend on y. Thus, we are left with:

∂(e^z)/∂z * ∂z/∂y + 2 = 0

Now, we need to solve for ∂z/∂y:

∂z/∂y = -2 / ∂(e^z)/∂z

To find ∂(e^z)/∂z, we differentiate e^z with respect to z, giving:

∂(e^z)/∂z = e^z

Substituting this into the expression for ∂z/∂y, we get:

∂z/∂y = -2 / e^z

Therefore, the partial derivative ∂z/∂y using implicit differentiation of e^z + sin(5x^2) + 2y = 0 is:

∂z/∂y = -2 / e^z

Note that we cannot simplify this any further without knowing the value of z.
To find the partial derivative ∂z/∂y using implicit differentiation for the equation e^z + sin(5x^2) + 2y = 0, we will first differentiate the equation with respect to y, treating z as a function of x and y.

Differentiating both sides with respect to y:

∂/∂y (e^z) + ∂/∂y (sin(5x^2)) + ∂/∂y (2y) = ∂/∂y (0)

Using the chain rule for the first term, we get:

(e^z) * (∂z/∂y) + 0 + 2 = 0

Now, solve for ∂z/∂y:

∂z/∂y = -2 / e^z

So, the partial derivative ∂z/∂y for the given equation is:

∂z/∂y = -2 / e^z

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The predicted exam grade for 1 hour of studying is 66. Therefore the residual for 1 hours of studying can be calculated as Residual = Actual Exam Grade - 66.

To find the residual for 1 hour of studying, we first need to determine the predicted exam grade and compare it to the actual exam grade for that specific data point.

Using the line of best fit equation y = 6x + 60, we can find the predicted exam grade for 1 hour of studying:

y = 6(1) + 60
y = 6 + 60
y = 66

So, the predicted exam grade for 1 hour of studying is 66. To calculate the residual, you need the actual exam grade for 1 hour of studying. If that information is not provided, the residual cannot be calculated. If the actual grade is provided, subtract the predicted grade from the actual grade to find the residual:

Residual = Actual Exam Grade - Predicted Exam Grade

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The relative frequency of people who strongly agree with the statement "I feel respected by those I work for" is 0.312, or 31.2%.

This means that out of the 500 employees surveyed, 156 strongly agreed with the statement. To find the relative frequency, you simply divide the number of people who strongly agree by the total number of people surveyed (156/500).

This result suggests that the majority of employees feel respected by their employers, which is a positive sign for the workplace culture.

However, it's important to note that there are still a significant number of employees who either disagree or feel neutral about this statement, indicating that there may be room for improvement in terms of fostering a more respectful and supportive work environment.

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When the value of x is 7 the value of p will be equal to 8.

It is given that P varies inversely with x, so we can write that

p=k/x

where k is the proportionality constant.

here we can find the value of k by substituting the value of p and x with 7 and 8 in the relation that is given above, we get:

7=k/8

k=7*8

k=56

we the value of k to be 56 after putting the values in the relation.

Now if x is changed to 7, and k is equal to 56 we can get the value of p by putting the known values in the same relation.

p=k/x

p=56/7

p=8.

Therefore, when the value of x is 7 the value for p will be equal to 8.

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The decimal form of 4/5 is 0.80, and it is equivalent to 80% as a percent.

To convert the fraction 4/5 into a decimal and a percent, we start by dividing the numerator (4) by the denominator (5). The result is 0.80 as a decimal.

In decimal form, 4/5 is written as 0.80. The "0" before the decimal point represents whole units, and the "80" after the decimal point represents hundredths.

To express this decimal as a percent, we multiply it by 100, as a percent is a representation of parts per hundred. So, 0.80 multiplied by 100 equals 80. Therefore, 4/5 is equivalent to 80% when expressed as a percentage.

In summary, 4/5 as a decimal is 0.80, which means it represents 80 hundredths, and as a percent, it is 80%, which signifies 80 parts per hundred. This conversion is particularly useful in various mathematical and real-world applications, such as calculating discounts, grades, proportions, and percentages in everyday life and business contexts.

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Based on the equation, when Lisa sells 24 copies of Math is Fun, her total pay will be $3140.

The equation relating P to N is:

P = 1700 + 60N

This is because her base salary is $1700, and she earns an additional $60 for each copy of Math is Fun she sells.

In order to find her total pay if she sells 24 copies of Math is Fun, we simply need to substitute N = 24 into the equation:

P = 1700 + 60(24)

P = 1700 + 1440

P = 3140

Therefore, if Lisa sells 24 copies of Math is Fun, her total pay will be $3140.

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Answer:

a. x = 68

b. x = 55

c. x = 18

Step-by-step explanation:

Formula

Inscribed angle = Central angle/2

a.

x = 136/2

x = 68

b.

x = ( 360 - 150 - 100 )/2

= 110/2

x = 55

c.

x = 18

The sample is being used with such referrals of a qualitative researcher studied women's decision to delay childbearing until their late 30s is Snowball, option C.

A non-probability sampling technique called snowball sampling entails the recruitment of new units by existing units to make up the sample. Research regarding people with certain characteristics who would be hard to find otherwise can benefit from snowball sampling (e.g., people with a rare disease).

Snowball sampling, sometimes referred to as chain sampling or network sampling, starts with one or more research participants. Following then, it proceeds based on recommendations from those individuals. This procedure is repeated until the required sample is obtained or a saturation point is reached.

The selection is based on a variety of factors, including:

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Complete question;

A qualitative researcher studied women's decision to delay

childbearing until their late 30s. Initial study participants

referred friends who had made similar decisions. What type

of sample is being used with such referrals?

A.Convenience

B.Volunteer

C.Snowball

D. Purposive

Answer:

we know that given triangle is right angled triangle.

➢ By using Phythagoras Theorem:-

[tex] \sf \longrightarrow \: (AC)^2 = (AB)^2 + (BC)^2[/tex]

[tex] \sf \longrightarrow \: ( \sqrt{80} )^2 = (x)^2 + (8)^2[/tex]

[tex] \sf \longrightarrow \: 80 = (x)^2 + (8)^2[/tex]

[tex] \sf \longrightarrow \: 80 \: = x^2 \: + \: 8^2[/tex]

[tex] \sf \longrightarrow \: 80 \: = x^2 \: + \: 64[/tex]

[tex] \sf \longrightarrow \: 80 \: - 64 = x^2 \:[/tex]

[tex] \sf \longrightarrow \: 16 = x^2 \:[/tex]

[tex] \sf \longrightarrow \: x^2 \: = 16[/tex]

[tex] \sf \longrightarrow \: x \: = \sqrt{16} [/tex]

[tex] \sf \longrightarrow \: x \: = 4 \: units [/tex]

The new coordinate of the vertex after dilation is (-5, -3).

To find the new coordinate, you'll need to use the given scale factor of 1/3 and apply it to the original vertex coordinates (-15, -9). Here's a step-by-step explanation:

1. Identify the original vertex coordinates: (-15, -9).
2. Identify the scale factor for dilation: 1/3.
3. Apply the scale factor to the x-coordinate: (-15) * (1/3) = -5.
4. Apply the scale factor to the y-coordinate: (-9) * (1/3) = -3.
5. The new coordinates after dilation are (-5, -3).

By following these steps, you can find the new coordinates of the vertex after dilation at the origin using the given scale factor.

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The value is calculated by dividing the total number of occurrences by 200 favourable examples that do not possess a college degree is 0.33 is the determined probability value.

The favourable number of cases is 200.

The total number of cases is 600.

The calculation of the required probability is,

Probability = Favourable cases Total number of cases 200 600 = 0.33

Occurrences refer to events or incidents that happen in a particular time or place. These events can be both positive and negative and can occur in various contexts, such as personal experiences, historical events, natural phenomena, and scientific observations.

Occurrences can be significant or insignificant, depending on their impact on individuals or society as a whole. Some occurrences may be routine and expected, while others may be unexpected and unpredictable. The study of occurrences is important in many fields, including history, sociology, psychology, and environmental science. By analyzing past occurrences, researchers can gain insights into patterns of behavior and trends that can inform future decisions and policies.

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Complete Question:-

The employees of a company were surveyed on questions regarding their educational background (college degree or no college degree) and marital status (single or married). Of the 600 employees, 400 had college degrees, 100 were single, and 60 were single college graduates. The probability that an employee of the company does not have a college degree is:

_______________________________

_______________________________

The derivative of the given function is f'(x) = 2(sec x * tan x) + sec^2 x. b) The critical numbers for the function are x = 0 and x = π.of the given function is f'(x) = 2(sec x * tan x) + sec^2 x.

The critical numbers for the function are x = 0 and x = π.

Derivative and critical numbers,

a) Find the derivative: We're given the function f(x) = 2 sec x + tan x.

To find its derivative, we need to find the derivatives of the individual terms (sec x and tan x) and then add them together.

The derivative of sec x is sec x * tan x. So, for the term 2 sec x, the derivative is 2 * (sec x * tan x).

The derivative of tan x is sec^2 x.

Now, we add both derivatives to find the derivative of f(x): f'(x) = 2(sec x * tan x) + sec^2 x

b) Find the critical numbers: Critical numbers are the points where the derivative of the function is either 0 or undefined.

To find the critical numbers, we'll set f'(x) equal to 0 and solve for x, as well as identify where the derivative is undefined.

First, let's set f'(x) to 0: 0 = 2(sec x * tan x) + sec^2 x

We need to solve this equation for x. It's a bit tricky, so let's rewrite the equation in terms of sin and cos: 0 = 2((1/cos x) * (sin x/cos x)) + (1/cos x)^2

Now let's simplify the equation: 0 = 2(sin x/cos^2 x) + 1/cos^2 x

To eliminate the denominators, we'll multiply through by cos^2 x: 0 = 2(sin x) + cos x

Now, we can use the unit circle to find the values of x in the interval 0 ≤ x ≤ 2π that satisfy this equation: For sin x = 0, x = 0, π For cos x = -2, there's no solution in the given interval because the range of cosine is -1 ≤ cos x ≤ 1.

Therefore, the critical numbers are x = 0 and x = π. Your answer:

a) The derivative of the given function is f'(x) = 2(sec x * tan x) + sec^2 x.

b) The critical numbers for the function are x = 0 and x = π.

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The length of the base is 16 inches.

To find the length of the base of the triangular pane of glass, we can use the formula for the area of a triangle which is:

Area = (1/2) x base x height

We are given that the height of the pane is 32 inches and the area is 256 square inches. Substituting these values into the formula, we get:

256 = (1/2) x base x 32

To isolate the base, we can divide both sides by (1/2) x 32, which simplifies to 16. This gives us:

256 ÷ 16 = base

Simplifying the left side of the equation, we get:

16 = base

Therefore, the length of the base of the pane is 16 inches.

In summary, the triangular pane of glass has a height of 32 inches and an area of 256 square inches. To find the length of the base, we use the formula for the area of a triangle and solve for the base.

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The arc measure of minor BC is 155°

An arc is a segment of a circle is defined by two endpoints and the set of points on the curve between them.

The length of an arc is a fraction of the circumference of the circle, and can be calculated using the angle between the two endpoints and the radius of the circle.

We can say that measure of arc BC is m∠ BPC. Also, arc AD is m∠ APD

By Vertical Angles Theorem. That is:

Provided AC and BD are diameters,

m∠ BPC = m∠ APD

m∠ BPC = 155°

Since m∠ BPC = 155°

Therefore, the arc measure of minor BC is 155°

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Complete Question

See attached image

The lateral surface area of a cylinder is the area of the sides of the cylinder, not including the top or bottom. In the case of a can of beans, the label that wraps around the can represents this lateral surface area.

To find the lateral surface area of the can, we need to use the formula for the lateral surface area of a cylinder: LSA = 2πr*h, where r is the radius of the base of the cylinder and h is the height of the cylinder.

Since we are given the diameter of the can (7 cm), we need to divide it by 2 to get the radius: r = 7/2 = 3.5 cm. The height of the can is given as 11 cm.

Now we can plug these values into the formula to find the lateral surface area of the can: LSA = 2π(3.5)(11) ≈ 242.95 cm².

So the lateral surface area of the can of beans is approximately 242.95 cm². This is the area of the sides of the can that the label would wrap around.

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Spencer will be on the phone for 56 minutes in total if he routes 28 calls.

Using unit rates, we can calculate how long Spencer will spend on the phone when routing 28 calls if he spent 10 minutes on the phone while routing 5 calls.

The amount of time spent on each phone call is the unit rate. In this instance, the unit fee is 10 minutes / 5 phone calls = 2 minutes each call.

In order to determine how much time Spencer will spend on the phone when routing 28 calls, we can use this unit rate as follows:

Therefore, Spencer will be on the phone for 56 minutes in total if he routes 28 calls.

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The ladder reaches up 20ft the side of the house.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

This theorem can be used to solve problems involving right triangles, such as finding the length of the sides or the height of an object.

In this problem, we are given the length of the ladder and the height up the side of the house that it reaches.

We can use the Pythagorean theorem to find the distance from the base of the ladder to the side of the house.

We can then use this distance and the height up the side of the house that the ladder reaches to find the length of the ladder using the Pythagorean theorem again.

Let's call the distance from the base of the ladder to the side of the house "x". We can then use the Pythagorean theorem to find the height that the ladder reaches up the side of the house.

According to the Pythagorean theorem, the length of the ladder (which is the hypotenuse of the right triangle formed by the ladder, the ground, and the side of the house) is equal to the square root of the sum of the squares of the other two sides.

So, if we let "h" be the height up the side of the house that the ladder reaches, we have:

ladder length = √(x^2 + h^2)

We know that the ladder is 20ft long and reaches up 16ft, so we can set up the equation:

20 = √(x^2 + 16^2)

Squaring both sides of the equation, we get:

400 = x^2 + 256

Subtracting 256 from both sides, we get:

144 = x^2

Taking the square root of both sides, we get:

x = 12

So the ladder is leaning against the house 12ft away from the base, and we can use the Pythagorean theorem to find the height up the side of the house that the ladder reaches:

ladder length = √(12^2 + 16^2) = √(144 + 256) = √400 = 20

Therefore, the ladder reaches up 20ft the side of the house.

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Using trigonometry, we can solve for the missing angles to find them as 18.43°, 45°, 45°, and 18.43°.

The sign is mounted on a sloped surface, which means that we'll need to use some trigonometry to find the missing angles.

Let's concentrate on the sign's upper right corner, where the letters x and y are absent from two perspectives. The magnitude of angle x may be determined using trigonometry.

Let's begin by sketching a right triangle that has an angle x. The triangle's two sides may be represented by the sign's vertical and horizontal lines, with the addition of a third side to join the top right corner of the sign to the sloping area below.

Since the sign is an octagon, we know that each interior angle is 135°. Therefore, the measure of angle y must be:

y = 180 - 135 = 45°

Now, let's look at the right triangle that includes angle x. We know that the hypotenuse of the triangle is the sloped surface of the sign, which has a length of 4.5 meters. We also know that the opposite side of the triangle is the height of the sign above the ground, which has a length of 1.5 meters.

Using trigonometry, we can find the measure of angle x by taking the inverse tangent of the opposite side over the adjacent side:

tan(x) = opposite/adjacent = 1.5/4.5 = 1/3

x = tan⁻¹(1/3) ≈ 18.43°

Therefore, the measure of angle x is approximately 18.43 degrees.

Hence, using trigonometry, we can solve for the missing angles to find them as 18.43°, 45°, 45°, and 18.43°.

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After 2 hours, approximately 4.38 grams of Francium remain from the 480-gram sample.

What is Algebraic expression ?

An algebraic expression is a combination of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. It may contain one or more terms, with each term separated by a plus or minus sign. Algebraic expressions are used in algebra to represent mathematical relationships and formulas.

a) To write an exponential function that models the mass of Francium remaining after t minutes, we can use the formula:

N = N0 * [tex](1/2)^{(t / t1/2)}[/tex]

where N is the amount remaining after time t, N0 is the initial amount, t1/2 is the half-life, and (t/t1/2) means raised to the power of t/t1/2.

In this case, the initial amount is 480 grams, the half-life is 22 minutes, and we want to find the amount remaining after t minutes. Therefore, the exponential function that models the mass of Francium remaining after t minutes is:

N = 480 * [tex](1/2)^{t/22}[/tex]

b) 2 hours is equal to 120 minutes. To find how many grams of Francium remain after 2 hours, we can substitute t = 120 into the exponential function we found in part a):

N = 480 *[tex](1/2)^{ (120 / 22) }[/tex] ≈ 4.38 grams

Therefore, after 2 hours, approximately 4.38 grams of Francium remain from the 480-gram sample.

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Answer:

156 bundles

Step-by-step explanation:

Total area of the roof = 2(70 x 30) = 4200 sf  

(4200 sf) / (27sf/bundle) = 155.56 ≈ 156 bundles