Combine Lead (II) nitrate with Potassium Iodide solution

Answer:

A

Explanation:

Answer:

work and power increases or decreases opposite of the mass

Explanation:

This Is beacuse Work is the product of Mass, Gravity, and Height

The question is incomplete, the complete question is;

Determine whether each melting point observation corresponds to a pure sample of a single compound or to an impure sample with multiple compounds.

Experimental melting point is BELOW literature value

Experimental melting point is CLOSE to literature value

WIDE melting point range

NARROW melting point range

Answer:

narrow melting point-pure sample of a single compound

experimental melting point is close to literature value-pure sample of a single compound

wide melting point range-impure sample of multiple compounds

experimental melting point is below literature value-impure sample of multiple compounds

Explanation:

The experimental melting point of a pure single compound is sharp and extremely close to the melting point of the substance as recorded in the literature. Usually, a pure substance melts within a narrow range of temperatures.

Impure samples of multiple compounds melt over a range of temperatures. Also if the experimental melting point is well below the record in literature, then the sample is contaminated by other compounds.

Answer:

C. oxidation ..........

The given reaction is the breaking of the carbohydrate C₁₂H₂₂O₁₁ into 12 C and 11 H₂O. Hence, it is a decomposition reaction .

A decomposition reaction is a type of chemical reaction in which a compound breaks down into two or more simpler substances, either through heat, light, or an electrical current.

In a decomposition reaction, a single reactant is converted into two or more products, which can be elements or compounds.

The general equation for a decomposition reaction can be written as:

AB → A + B

where AB is the reactant and A and B are the products.

Decomposition reactions are important in many chemical processes, such as the breakdown of organic matter in soil, the production of industrial chemicals, and the functioning of biological systems.

The given  reaction is the decomposition of C₁₂H₂₂O₁₁ into 12 C and 11 H₂O.

Find more on decomposition reactions:

https://brainly.com/question/16987748

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Your complete question is follows:

C₁₂H₂₂O₁₁ ⇒ 11 H₂O + 12 C

Which type of reaction is

O synthesis

O decomposition

O oxidation

O combustion

Answer:

(A) there are 12

Explanation:

bc

Answer: Changing the number of electrons will change the overall charge on an atom.

Explanation:

An atom that loses electrons will become positively charged and an atom with added electrons will become negatively charged. ... A charged atom is called an ion.

Answer:

a particle with jagged rough ends has a high rate of deposition

Answe

Explanation:

1st Remove ( )

2nd select like terms

3rd Move the constant to the left

4th calculate

5th divided both sides

6th use quadratic formula

Answer:

Plants can split starch into it's simpler glucose units for use as energy when needed. Cellulose is known as a structural carbohydrate because of the fibers formed by it's molecules. It is the major component of plant cell walls and comprises over half of the carbon found on planets.

Explanation:

I majored in Chemistry

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

[tex]\tt \dfrac{4}{5}\times 0.5=0.4[/tex]

volume NO at 1273 K and 1 atm

[tex]\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L[/tex]

b. 15 L NH3 at STP ( 1mol = 22.4 L)

[tex]\tt \dfrac{15}{22.4}=0.67~mol[/tex]

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

[tex]\tt \dfrac{6}{4}\times 0.67=1[/tex]

mass H2O(MW = 18 g/mol) :

[tex]\tt mass=mol\times MW=1\times 18=18~g[/tex]

c. mol NO at 1273 K and 1 atm :

[tex]\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34[/tex]

mol ratio of NO : O2 = 4 : 5, so mol O2 :

[tex]\tt \dfrac{5}{4}\times 0.34=0.425[/tex]

Volume O2 at STP :

[tex]\tt 0.425\times 22.4=9.52~L[/tex]

Answer:

See explanation

Explanation:

Dalton's atomic theory furnished us with a basis to discuss the theory of atoms. However, not all his ideas holds up under the scruitiny of morden science.

He postulated that atoms were 'indivisible' the discovery of subatomic particles indeed show that there are smaller particles than atoms.

His postulation that atoms can neither be created nor destroyed does not hold water today because atoms are being created in nuclear reactors.

He said that atoms of all elements are exactly alike. Today we know there are isotopes of elements which are not exactly alike.

We can see that the Dalton's atomic theory did not take cognisance of the important role of subatomic particles in studying the structure of the atom. Modern atomic theory tries to look at the importance of these particles in the understanding the structure of the atom.

Answer:

I believe its A) Law of simple multiple proportions

Explanation:

The law of definite proportions states that a given chemical compound always contains the same elements in the exact same proportions by mass.

Answer:

A) Law of simple multiple proportions

Explanation:

Answer:

a) 2.632 kg

b) 41.36 kg

Explanation:

Given data:

Mass of CO react = ?

Mass of Fe formed = 3.50 Kg (3.50 /1000 =3500 g)

Mass of CO₂ formed = ?

Solution:

Chemical equation;

Fe₂O₃ + 3CO     →   2Fe + 3CO₂

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles =  3500 g/55.85 g/mol

Number of moles = 62.67 mol

now we will compare the moles of iron with CO.

            Fe         :       CO

             2          :       3

          62.67     :        3/2×62.67 = 94 mol

Mass of CO:

Mass = number of moles × molar mass

Mass = 94 mol × 28 g/mol

Mass = 2632 g

In kilogram:

2632g × 1 Kg /1000 g

2.632 kg

Now we will compare the moles of Fe with CO₂

                 Fe         :           CO₂

                  2          :           3

               62.67     :        3/2×62.67 = 94 mol

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 94 mol × 44 g/mol

Mass = 4136 g

In kilogram:

4136g × 1 Kg /1000 g

41.36 kg

Answer:

[tex]\boxed {\boxed {\sf 50.1 \ kJ}}[/tex]

Explanation:

When water changes from ice (solid) to water (liquid), it is melting or fusion. Therefore, we can use the following formula to find energy:

[tex]q=mH_f[/tex]

where q is the energy, m is the mass, and Hf is the heat of fusion.

1. Define Values

The mass is 150 grams. The heat of fusion for water is 334 Joules per gram.

[tex]m= 150 \ g \\H_f=334 \ J/g[/tex]

2. Calculate Energy

Substitute the values into the formula.

[tex]q=150 \ g * 334 \ J/g[/tex]

Multiply. Note that the grams (g) will cancel each other out and leave Joules as our units.

[tex]q=150 *334 \ J[/tex]

[tex]q=50100 \ J[/tex]

3. Convert Units

We found the answer in joules, but the question asks for kilojoules, so we must convert.

There are 1000 Joules in 1 kilojoule. Therefore, we can divide the joules calculated by 1000.

[tex]50100 \ J *\frac{1 \ kJ}{1000 \ J}[/tex]

[tex]\frac{50100 \ kJ}{1000 \ }[/tex]

[tex]50.1 \ kJ[/tex]

50.1 kilojoules are needed to change 150 grams of ice to water.

Answer:

1. The graph where x axis and y axis are present is called coordinate.

4. 18

Answer: The resultant pressure is 3.22 atm

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

[tex]P\propto T[/tex]     (At constant volume and number of moles)

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas  = 2.79 atm

[tex]P_2[/tex] = final pressure of gas  = ?

[tex]T_1[/tex] = initial temperature of gas  = 273K

[tex]T_2[/tex] = final temperature of gas = 315 K

[tex]\frac{2.79}{273}=\frac{P_2}{315}[/tex]

[tex]P_2=3.22atm[/tex]

Thus the resultant pressure is 3.22 atm

Answer:

ok!

Explanation:

Answer:

Don't travel by air if you can avoid it because air travel uses up large amounts of fossil fuels and creates greenhouse gases. Dispose of any rubbish responsibly - it can be hazardous to wildlife. Use public transport, cycle or walk instead of using a car. Use facilities and trips run by local people whenever possible.

Answer:

Practicing recycling and green computing

Answer:

propyl

1-propylmethane or 2-methylpropane

Answer:

Rb

Alkali Metals are Group 1 so

Rb it isnt Hydrogen because it is a gas

Explanation:

Answer:

1s²2s²p⁶3s²p⁴

Explanation:

An atom that is in the ground state has not lost or gained electrons. If we look at the Periodic Table, we can see that the electron configuration of the sulfur atom (S) is [Ne]3s²p⁴. Since the electron configuration of Ne is 1s²2s²p⁶, the complete electron configuration is 1s²2s²p⁶3s²p⁴.

Answer: XCl2(aq) + 2 AgNO3(aq) ---> X(NO3)2(aq) + 2 AgCl(s)

Explanation:

Hehe I remembered how...

the equilibrium of the system will be upset

Explanation:

Answer:

Dissolving?

Explanation:

Answer:

B. Dissovling

Explanation:

Im a smart boy G.

Answer:

14.351

Explanation:

Answer:

It would be able to function because the ph of the environment is similar to that of intestine.

Explanation:

The pH of the small intestine is eight. The enzyme would be able to function because enzyme C functions best at a Ph range around 8.

Answer:

MgF₂

Explanation:

Fluorine only has a 1- charge, so to satisfy the 2+ charge on magnesium–– you need 2 fluorine atoms to balance out the charges.

Answer:

10000 g BaNO₃

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

3.02 × 10²⁵ formulas units BaNO₃

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of BaNO₃ - 137.33 + 14.01 + 3(16.00) = 199.34 g/mol

Step 3: Convert

[tex]3.02 \cdot 10^{25} \ formula \ units \ BaNO_3(\frac{1 \ mol \ BaNO_3}{6.022 \cdot 10^{23} \ formula \ units \ BaNO_3} )(\frac{199.34 \ g \ BaNO_3}{1 \ mol \ BaNO_3} )[/tex] = 9996.79 g BaNO₃

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

9996.79 g BaNO₃ ≈ 10000 g BaNO₃