The hydrocarbon's molecular structure is [tex]C_9H_20[/tex].The hydrocarbon's empirical formula is [tex]C_9[/tex]/4H5.
To solve this problem, we need to use stoichiometry to relate the amount of [tex]CO__2[/tex] and [tex]H_2O[/tex] produced to the amount of [tex]CxHy[/tex] burned.
(a) To find the molecular formula of the hydrocarbon, we need to first calculate the number of moles of [tex]CO__2[/tex] and [tex]H_2O[/tex] produced. From the ideal gas law, we know that 1 mole of gas at STP (standard temperature and pressure) occupies 22.4 L. Therefore, 4.032 L of [tex]CO__2[/tex] at STP corresponds to:
4.032 L / 22.4 L/mol = 0.180 mol [tex]CO__2[/tex]
Similarly, the mass of H2O produced corresponds to:
3.602 g / 18.02 g/mol = 0.200 mol [tex]H_2O[/tex]
Since the hydrocarbon undergoes complete combustion, it reacts with oxygen to form [tex]CO__2[/tex] and [tex]H_2O[/tex] according to the balanced chemical equation:
[tex]CxHy[/tex] + (x + (y/4))O2 → [tex]CO__2[/tex] + (y/2)[tex]H_2O[/tex]
where x and y are the coefficients of the balanced equation. We can use the stoichiometric ratios to set up two equations:
0.180 mol [tex]CO__2[/tex] = x mol [tex]CxHy[/tex] → x = 0.180 mol / 0.0200 mol = 9
0.200 mol [tex]H_2O[/tex] = (y/2) mol [tex]CxHy[/tex] → y = 0.400 mol / 0.0200 mol = 20
Therefore, the molecular formula of the hydrocarbon is [tex]C_9H_20[/tex].
(b) To find the empirical formula of the hydrocarbon, we need to divide the subscripts by their greatest common factor. In this case, both subscripts are divisible by 4, so we get:
[tex]C_9H_20[/tex] → C9/4H5
Therefore, the empirical formula of the hydrocarbon is C9/4H5.
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Hellpppp with this question!!! THE ANSWER IS NOT 0.3 or 0.5
the answer is 2.5 according to me
1. Explain the difference in
Variation of molar conductivity
with dillusion for strong___
electrolyte and weak electrolyte
-
Explain molar Conductivity at
infinite dillusion...
Derive the expression for
dillusion law
For strong electrolytes, molar conductivity decreases as the solution is diluted because the concentration of ions decreases.
For weak electrolytes, molar conductivity increases as the solution is diluted because as the solution is diluted, the concentration of ions increases.
The expression for the dilution law is A = εcb
What is molar conductivity?The conductivity of a solution containing one mole of an electrolyte when placed between two electrodes spaced one centimeter apart is known as the molar conductivity of the electrolyte. The strength of the electrolyte affects how molar conductivity changes with dilution.
At infinite dilution, the molar conductivity of an electrolyte reaches its maximum value because the electrolyte's ions are so far apart that they no longer interact with one another.
The dilution law or Beer-Lambert law states that the absorbance of a solution is directly proportional to the concentration of the solution and the path length of the light through the solution.
A ∝ cb
Adding a proportionality constant gives:
A = εcb
where;
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Calculate the value of Kp at 227 degrees Celsius for the equilibrium: 3 A(g) ⇌ B(g) + D(g Kc=5.15
How many grams in 5 moles of water?
Answer:
90g
Explanation:
Ans. 90 gram
we know that,
n = wt/m.wt
where, n= moles
wt.= weight
m.wt = molecular weight
putting values we get
5 = wt./18 ( molecular weight of water is 18
wt.= 90
hence ans.= 90 gram
Calculate standard cell potential of an electrochemical cell powered by these half-reactions. (Write values to two decimal places. If a value is less than 1, be sure to write a 0 before the decimal.)
Pb4+ + 2e− → Pb2+
Co3+ + e− → Co2+
E°cell = V
Is the reaction spontaneous
The standard cell potential is found as +1.95 V and is a spontaneous reaction.
What is standard cell potential ?The standard cell potential (E°cell) of an electrochemical cell is given by the difference between the standard reduction potentials of the two half-cells involved.
E°cell = E°reduction (cathode) - E°reduction (anode)
The half-reactions given are:
Pb4+ + 2e− → Pb2+ (reduction)
Co3+ + e− → Co2+ (reduction)
The standard reduction potentials for these half-reactions are:
E°reduction(Pb4+/Pb2+) = -0.13 V
E°reduction(Co3+/Co2+) = +1.82 V
We then calculate as:
E°cell = E°reduction (Co3+/Co2+) - E°reduction (Pb4+/Pb2+)
E°cell = (+1.82 V) - (-0.13 V)
E°cell = +1.95 V
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8. The compound C2H4 has van der Waals constants a = 4.612 atm•L2/mol2 and b = 0.0582 L/mol. Using both the ideal gas law and van der Waals’s equation, calculate the pressure expected for 30 mol of C2H4 gas in a 6.00-L container at 20 °C.
Using the Ideal Gas Law, the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
To calculate the pressure expected for 30 mol of [tex]C_2H_4[/tex] gas in a 6.00-L container at 20 °C, we will use both the Ideal Gas Law and van der Waals equation.
Ideal Gas Law: PV = nRT
P = pressure
V = volume (6.00 L)
n = moles (30 mol)
R = ideal gas constant (0.0821 L•atm/mol•K)
T = temperature (20 °C + 273.15 = 293.15 K)
Solve for P (pressure):
P = nRT / V
P = (30 mol)(0.0821 L•atm/mol•K)(293.15 K) / 6.00 L
P = 1210.07 atm
Van der Waals equation:
(P + a(n/V)²)(V - nb) = nRT
a = 4.612 atm•L²/mol²
b = 0.0582 L/mol
Solve for P (pressure):
(P + (4.612)(30/6)²) (6 - 0.0582 * 30) = (30)(0.0821)(293.15)
P = 1179.71 atm
Using the Ideal Gas Law, the pressure is 1210.07 atm, and using the van der Waals equation, the pressure is 1179.71 atm.
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Which statement BEST describes the three enzymes? A The enzymes have different structures because they have a different sequence of amino acids. B The enzymes have the same sequence of amino acids because they are all digestive enzymes. C The enzymes perform different functions because they have the same sequence of amino acids. D The enzymes break down the same molecules because they have a different sequence of amino acids.
The best statement that describes the three enzymes is: The enzymes have different structures because they have a different sequence of amino acids. Opton A is correct.
Enzymes are biological catalysts that facilitate chemical reactions in living organisms. Enzymes are proteins, and their function is determined by their three-dimensional structure, which is determined by the sequence of amino acids that make up the protein.
In this scenario, the three enzymes have different structures, which suggests that they have a different sequence of amino acids. This difference in amino acid sequence results in different folding patterns and ultimately different shapes of the enzymes. The specific shape of an enzyme determines its ability to catalyze a particular chemical reaction. Hence, the different structures of these enzymes indicate that they may perform different functions or catalyze different chemical reactions.
Option A, "The enzymes have different structures because they have a different sequence of amino acids," is the correct answer as it aligns with the fundamental principle of protein structure and function.
Option B, "The enzymes have the same sequence of amino acids because they are all digestive enzymes," is incorrect because enzymes can have different sequences of amino acids even if they perform the same function.
Option C, "The enzymes perform different functions because they have the same sequence of amino acids," is incorrect because the sequence of amino acids determines the enzyme's structure and thus its function.
Option D, "The enzymes break down the same molecules because they have a different sequence of amino acids," is also incorrect because different amino acid sequences can result in different substrate specificity, which means that the enzymes can break down different molecules. Therefore option A is correct.
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In the titration between hcl and naoh what’s the medium at the end point and why ?
In the titration between HCl and NaOH, the medium is neutral at the end point because of complete neutralization of a strong acid by a strong base.
Neutralization is a chemical reaction in which acid and base react to form salt and water. Hydrogen (H⁺) ions and hydroxide (OH⁻ ions) react with each other to form water.
The strong acid and strong base neutralization have a pH value of 7.
The beaker gets warm which indicates that the reaction between acid and base is an exothermic reaction releasing heat energy into the surroundings.
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Isoprenol (C₅H₁₀O) can be produced from isobutene (C₄H₈) and formaldehyde (CH₂O) via the following reaction scheme. What is the change in enthalpy in kJ associated with the production of 155.3 g C₅H₁₀O (isoprenol)?
C₄H₈(g) + CH₂O(g) → C₅H₁₀O(l) ∆H = -191.3 kJ
To determine the change in enthalpy associated with the generation of 155.3 g of [tex]C_5H_1_0O[/tex] we must first calculate the moles of [tex]C_5H_1_0O[/tex] produced using its molar mass.
The molar mass of C₅H₁₀O is:
5(12.01 g/mol) + 10(1.01 g/mol) + 16.00 g/mol = 88.15 g/mol
Moles of C₅H₁₀O produced:
155.3 g / 88.15 g/mol = 1.763 mol C₅H₁₀O
The balanced chemical equation states that the formation of 1 mol of C₅H₁₀O results in an enthalpy change of -191.3 kJ.
As a result, the enthalpy change during the formation of 1.763 mol of C₅H₁₀O is: -191.3 kJ/mol x 1.763 mol = -337.8 kJ
The enthalpy change for the production of 155.3 g of C5H10O is -337.8 kJ.
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What is the number of molecules of NO, which contains 16 gm of oxygen. 14
please help asap!
3. A double replacement reaction occurs between two solutions of lead (II) nitrate and potassium bromide. Write a
balanced equation for this reaction-identifying the product that will precipitate, and the product that will remain in
solution.
a) Write the balanced equation for this double replacement reaction.
b) If this reaction starts with 32.5 g lead (II) nitrate and 38.75 g potassium bromide, how many grams of the
precipitate will be produced? Remember to use the limiting reactant to calculate the amount of precipitate
formed.
c) How many grams of the excess reactant will remain?
Answer:
Explanation:
a) The balanced equation for the double replacement reaction between lead (II) nitrate and potassium bromide is:
Pb(NO₃)₂(aq) + 2KBr(aq) → PbBr₂(s) + 2KNO₃(aq)
In this reaction, lead (II) bromide (PbBr₂) will precipitate, while potassium nitrate (KNO₃) will remain in solution.
b) To determine the amount of precipitate produced, we need to first determine the limiting reactant. We can do this by calculating the number of moles of each reactant and comparing it to the stoichiometry of the balanced equation.
The molar mass of lead (II) nitrate is 331.21 g/mol and the molar mass of potassium bromide is 119.00 g/mol.
The number of moles of lead (II) nitrate is 32.5 g / 331.21 g/mol = 0.0981 mol The number of moles of potassium bromide is 38.75 g / 119.00 g/mol = 0.3256 mol
According to the balanced equation, one mole of lead (II) nitrate reacts with two moles of potassium bromide to produce one mole of lead (II) bromide. This means that if all the lead (II) nitrate were to react, it would require 0.0981 mol * 2 = 0.1962 mol of potassium bromide.
Since we have more than enough potassium bromide (0.3256 mol > 0.1962 mol), lead (II) nitrate is the limiting reactant.
The number of moles of lead (II) bromide produced will be equal to the number of moles of lead (II) nitrate consumed, which is 0.0981 mol.
The molar mass of lead (II) bromide is 367.01 g/mol, so the mass of lead (II) bromide produced will be 0.0981 mol * 367.01 g/mol = 36.0 g.
c) To determine the amount of excess reactant remaining, we need to subtract the amount consumed from the initial amount.
The number of moles of potassium bromide consumed is half the number of moles of lead (II) nitrate consumed, which is 0.0981 mol / 2 = 0.04905 mol.
The mass of potassium bromide consumed is 0.04905 mol * 119.00 g/mol = 5.84 g.
The mass of potassium bromide remaining is 38.75 g - 5.84 g = 32.91 g.
Which
thermochemical
equation
corresponds to
the graph?
Answer: C
Explanation:
Answer: C
Explanation:
Write the electronic configuration of all the metal ions in the d-blocks (3d series)
The electronic configuration of the d-block metal ions in the 3d series is represented by electronic configuration of Argon (Ar), 3d and 4s sub orbitals.
What is the electronic configuration of all d block?The electronic configuration of the d-block metal ions in the 3d series is as follows:
Scandium (Sc): [Ar] 3d¹ 4s²
Titanium (Ti): [Ar] 3d² 4s²
Vanadium (V): [Ar] 3d³ 4s²
Chromium (Cr): [Ar] 3d⁵ 4s¹
Manganese (Mn): [Ar] 3d⁵ 4s²
Iron (Fe): [Ar] 3d⁶ 4s²
Cobalt (Co): [Ar] 3d⁷ 4s²
Nickel (Ni): [Ar] 3d⁸ 4s²
Copper (Cu): [Ar] 3d¹⁰ 4s¹
Zinc (Zn): [Ar] 3d¹⁰ 4s²
Thus, the above illustration shows the electronic configuration of all the metal ions in the d-blocks (3d series).
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Given the following reaction:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g) ∆H = -2511.6 kJ
What is the energy change when 7.76 g of C₂H₂ react with excess O₂?
Chemical reactions nearly always include a change in energy between the products and reactants.
Thus, Energy is released when chemical bonds are created and is released when chemical bonds are destroyed.
The overall energy of a system, however, must remain constant according to the Law of Conservation of Energy, and chemical reactions frequently absorb or release energy in the form of heat, light, or both.
The difference in the amounts of chemical energy that are stored in the products and reactants accounts for the energy change in a chemical reaction. Enthalpy refers to the system's heat content or stored chemical energy.
Thus, Chemical reactions nearly always include a change in energy between the products and reactants.
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Question 8 of 21
Which nucleus completes the following equation?
The nucleus completing the following equation is option C: ₂₄⁵⁰Cr.
This reaction is a type of radioactive nuclei decay.
What is radioactive decay?Radioactive decay is the process by which unstable atomic nuclei undergo spontaneous transformations in order to achieve a more stable state. This is accomplished by the emission of particles and/or electromagnetic radiation from the nucleus. The decay may occur by several mechanisms, including alpha decay, beta decay, gamma decay, and electron capture.
In alpha decay, the nucleus emits an alpha particle, which consists of two protons and two neutrons, resulting in a daughter nucleus that has two fewer protons and two fewer neutrons than the original nucleus.
In beta decay, a neutron in the nucleus is converted into a proton and an electron, and the electron is then emitted from the nucleus as a beta particle. This results in the daughter nucleus having one more proton and one fewer neutron than the original nucleus.
In gamma decay, the nucleus emits a gamma ray, which is a high-energy electromagnetic radiation, without changing the number of protons or neutrons in the nucleus.
In electron capture, an electron from the inner shell of the atom is captured by the nucleus, and a proton in the nucleus is converted into a neutron. This results in the daughter nucleus having one fewer proton and one more neutron than the original nucleus.
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Calculate the volume of C2H2 that is collected over water at 23 ∘C by a reaction of 1.52 g of CaC2 if the total pressure of the gas is 751 torr. (The vapor pressure of water is 21.07 torr .)
The volume of C₂H₂ that is collected over water at 23 ∘C by the reaction of 1.52 g of CaC₂ is 0.61 L
How do i determine the volume of C₂H₂ collected?First, we shall determine the mole of CaC₂ that reacted. Details below:
Mass of CaC₂ = 1.52 g Molar mass of CaC₂ = 64 g/mol Mole of CaC₂ =?Mole = mass / molar mass
Mole of CaC₂ = 1.52 / 64
Mole of CaC₂ = 0.024 mole
Next, we shall determine the mole of C₂H₂. obtained. Details below:
CaC₂ + 2H₂O -> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ reacted to produced 1 mole of C₂H₂
Therefore,
0.024 mole of CaC₂ will also react to produce 0.024 mole of C₂H₂
Finally, we shall determine the volume of C₂H₂ collected. This is shown below:
Temperature (T) = 23 °C = 23 + 273 = 296 KVapor pressure = 21.07 torrPressure of dry gas (P) = 751 - 21.07 = 729.93 torrGas constant (R) = 62.36 torr.L/mol KNumber of mole (n) = 0.024 moleVolume of gas (V) =?PV = nRT
729.93 × V = 0.024 × 62.36 × 296
Divide both sides by 729.93
V = (0.024 × 62.36 × 296) / 729.93
V = 0.61 L
Thus, the volume of the C₂H₂ gas collected is 0.61 L
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Calculate the mass of Kr
in a 9.95 L
cylinder at 91.2 ∘C
and 4.50 bar
.
Please help I appreciate it thanks!!!!!!!!!!!!!!!!!!!!!!
The correct molar mass for nickel chloride is 94.14 g/mol (option C).
How to calculate molar mass?Molar mass is the mass of a given substance divided by its amount, measured in moles. It is commonly expressed in grams (sometimes kilograms) per mole.
The molar mass of a substance can be calculated by summing up the atomic masses of the element components.
According to this question, the atomic mass of nickel is 58.693 amu while that of chlorine gas is 35.45 amu. The molar mass of nickel chloride can be calculated as follows;
molar mass = 35.45 amu + 58.693 amu = 94.14 g/mol
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A sample of an ideal gas has a volume of 2.31 L
at 279 K
and 1.01 atm.
Calculate the pressure when the volume is 1.09 L
and the temperature is 308 K.
We can use the combined gas law to determine the pressure of the gas at the final state. The combined gas law relates the pressure, volume, and temperature of a gas:
(P1 x V1) / T1 = (P2 x V2) / T2
where P1, V1, and T1 are the pressure, volume, and temperature of the gas at the initial state, and P2, V2, and T2 are the pressure, volume, and temperature of the gas at the final state.
We are given the initial pressure (P1 = 1.01 atm), volume (V1 = 2.31 L), and temperature (T1 = 279 K) of the gas, and the final volume (V2 = 1.09 L), and temperature (T2 = 308 K) of the gas. We can solve for P2, the final pressure of the gas:
(P1 x V1) / T1 = (P2 x V2) / T2
P2 = (P1 x V1 x T2) / (V2 x T1)
P2 = (1.01 atm x 2.31 L x 308 K) / (1.09 L x 279 K)
P2 = 2.41 atm (rounded to three significant figures)
Therefore, the pressure of the gas when the volume is 1.09 L and the temperature is 308 K is approximately 2.41 atm.
The following equations represent chemical
reactions.
Chemical Reactions
1) 2Na+2H₂O →NaOH + H₂
2) H₂+O₂ H₂O
3) MgCl₂ → MgCl₂
4) NaOH+MgCh→ NaCl + MgOH
Which equation shows that the total mass during a chemical reaction stays the same?
The equation that shows that the total mass during a chemical reaction stays the same is 2) H₂ + O₂ → H₂O.
This is an example of a balanced chemical equation where the number of atoms of each element on both the reactant and product side is equal. In other words, the total number of atoms of each element is conserved, and therefore the total mass is conserved. In the other reactions, either the number of atoms on the product side is different from the reactant side or there is no reaction at all.
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Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.
Answer:
Explanation:
The chemical equation for the production of manganese from manganese (II) carbonate, oxygen, and aluminium can be represented as follows:
3MnCO3(s) + 3O2(g) + 4Al(s) → 3Mn(s) + 3CO2(g) + 2Al2O3(s)
In this equation, manganese (II) carbonate (MnCO3) reacts with oxygen (O2) and aluminium (Al) to produce manganese (Mn), carbon dioxide (CO2), and aluminium oxide (Al2O3). The equation is balanced with three molecules of manganese carbonate, three molecules of oxygen, and four molecules of aluminium reacting to produce three molecules of manganese, three molecules of carbon dioxide, and two molecules of aluminium oxide.
PLS MARK ME BRAINLIEST
Help please! I'll give brainliest and 5 stars if you show work!
To solve this problem, we can use the formula:
q = m × c × ΔT
where q is the heat absorbed or released, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.
First, let's calculate the mass of water:
m = 225.0 g
Next, let's calculate the heat absorbed by the water:
q_water = m × c × ΔT
q_water = 225.0 g × 4.184 J/(g·°C) × (24.60°C - 20.53°C)
q_water = 3749.8 J
Since the metal released 4274 J of heat, the heat absorbed by the calorimeter can be calculated by subtracting the heat absorbed by the water from the total heat released by the metal:
q_calorimeter = - (q_water + q_metal)
q_calorimeter = - (3749.8 J + 4274 J)
q_calorimeter = - 8023.8 J
Therefore, the heat absorbed by the calorimeter is -8023.8 J, which is approximately equal to -8000 J or -8.0 kJ. The answer is (c) -339 J, since it is the closest to the calculated value when rounded to the nearest integer. Note that the negative sign indicates that the calorimeter absorbed the heat, which is expected since the reaction involved a release of heat.
WHEN SOME PEOPLE HAVE AN UPSET STOMACH, THEY TAKE A SODA TABLET LIKE
TUMS TO NEUTRALIZE THEIR STOMACH ACID.
THE REACTION IS HYDROCHLORIC ACID PLUS SODIUM BICARBONATE MAKES SALT,
CARBON DIOXIDE (THAT'S WHY SOME PEOPLE BURP) AND WATER.
HOW MUCH CARBON DIOXIDE AND SALT (IN GRAMS) ARE PRODUCED IF A 2 GRAM
TABLET OF SODIUM BICARBONATE IS TAKEN TO REACT WITH 18 GRAMS OF
HYDROCHLORIC ACID?
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium bicarbonate [tex](NaHCO_3)[/tex] is:
[tex]HCl + NaHCO_3\ - > NaCl + CO_2 + H_2O[/tex]
The coefficients in the balanced equation show that 1 mole of HCl reacts with 1 mole of [tex]NaHCO_3[/tex] to produce 1 mole of NaCl, 1 mole of [tex]CO_2[/tex], and 1 mole of [tex]H_2O[/tex]. We need to find the number of moles of [tex](NaHCO_3)[/tex] present in the tablet.
2 grams of [tex]NaHCO_3[/tex] is equivalent to 0.02 moles, and 18 grams of HCl is equivalent to 0.45 moles. Since [tex](NaHCO_3)[/tex] is limiting reagent, only 0.02 moles of NaCl and [tex]CO_2[/tex] will be produced. The molar mass of [tex]CO_2[/tex] is 44 g/mol, so the mass of [tex]CO_2[/tex] produced is 0.88 g. The molar mass of NaCl is 58.44 g/mol, mass of NaCl produced is 1.17 g.
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A 210.00 g sample of water with an initial temperature of 29.0°C absorbs 7,000.0 J of heat. What is the final temperature of the water?
Note: Use C (capital C) for degrees Celsius when typing units. So it might look like 35C or 2.03 J/gC. Give your answer in 3 sig figs.
The 210.00 g sample of the water with the initial temperature of the 29.0°C absorbs the 7,000.0 J of heat. The final temperature of the water is the 36.9 °C .
The mass of the water = 210 g
The initial temperature = 29.0 °C
The final temperature = ?
The heat energy = 7000 J
The specific heat capacity = 4.184 J/g °C
The heat energy is expressed as :
Q = m c ΔT
Where,
The m is mass of water = 210 g
The c is specific heat of water = 4.184 J/g °C
The ΔT is change in temperature = final temperature - initial temperature
The ΔT is change in temperature = T - 29.0 °C
7000 = 210 × 4.184 ( T - 29.0 )
7000 = 878.64 ( T - 29.0 )
( T - 29.0 ) = 7.966
T = 36.9 °C
The final temperature is 36.9 °C .
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Write the complete equation for neutralization reactions for LiOh + HNO2
The complete equation for the neutralization reactions for the LiOH + HNO₂ is as :
LiOH + HNO₂ ----> LiNO₂ + H₂O
The Neutralization reaction is the reaction as in the chemical reaction in which the acid will reacts with the base and to produce the salt and the water molecule. The general equation of the chemical reaction is as :
HX + BOH --> BX + H₂O
The reaction with the LiOH and the HNO₂ is :
LiOH + HNO₂ ----> LiNO₂ + H₂O
There is the combination of the H⁺ ions and OH⁻ ions that will form the water.
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Joan wrote a science fiction story where the people only texted each other, and never talked. They still had vocal chords, but they could no
longer make sounds. Their vocal chords were
Answer:
Vestigial
Explanation:
The retention of genetically determined traits or structures that have partially or completely lost their ancestral purpose in a specific species is known as vestigiality. In most cases, evaluating the vestigality requires comparison with comparable traits in closely related species.
Arrange the following ions in order of increasing ionic radius: selenide ion, rubidium ion, bromide ion, strontium ion.
Answer:
Br, Se, Sr, Rb
Explanation:
Atomic radius increases as you move to the left and down the periodic table. The increase in radius as you move left is due to decreasing effective nuclear charge (the pull an electron feels from the nucleus) since the number of protons decrease. The increase in radius as you move down is due to a higher number of principle energy levels (orbital in which the electron is located relative to the atom's nucleus), causing the electrons to be farther from the nucleus.
I2 + N2H4==> HI + N2 according to the reaction ,How many grams of HI are obtained if 115.7 g of N2H4 reacts with
an excess of iodine?
The mass of the HI that is produced is 1843 g
What is stoichiometry?Stoichiometry is a branch of chemistry that focuses on the quantitative relationships in chemical reactions between reactants and products.
What is the number of moles?
Number of moles of [tex]N_{2} H_{4}[/tex] = 115.7 g/32 g/mol
= 3.6 moles
Now we have that the balanced reaction equation is;
[tex]N_{2} H_{4} + 2I_{2} --- > N_{2} + 4 HI[/tex]
If 1 mole of [tex]N_{2} H_{4}[/tex] produces 4 moles of HI
3.6 moles of [tex]N_{2} H_{4}[/tex] will produce 3.6 * 4/1
= 14.4 moles of HI
Mass of HI produced = 14.4 moles * 128 g/mol
= 1843 g
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What is the molarity of a solution that has 2.0 moles of solute in 3.0 L of solution?
The molarity of the solution that has 2.0 moles of solute in 3.0 L of solution is 0.67 mol/L
What is molarity?Molarity is described as a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.
Molarity = moles of solute / liters of solution
we then substitute the given values, and have
Molarity = 2.0 moles / 3.0 L
Molarity = 0.67 mol/L
Molarity is very important because the ration used to express the concentration of any solution.
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2ch4 and c2h8 how are they different
Answer:
Explanation:
Both 2CH4 and C2H8 have the same number and kind of elements. But practically, 2CH4 will be existing but C2H8 cannot exist.