Decide which examples are Nuclear Fission reaction.
A. The reaction that is currently used in nuclear power plants.
B. Two small atoms combine together to form one larger atom.
C. A heavy atom is split when bombarded by neutrons.
D. Often involves isotopes of uranium

A) A, C, D
B) A, B, C
C) B, C, D

Answer:

The power will be "2.08 D".

Explanation:

According to the question,

The location of the image form lens,

[tex]d_i=50-2[/tex]

    [tex]=48 \ cm[/tex]

We know that,

⇒ [tex]\frac{1}{d_i} -\frac{1}{d_o} =\frac{1}{f}[/tex]

here,

[tex]d_o[/tex] = Object location

[tex]d_i[/tex] = Image location

[tex]f[/tex] = Focal length

On putting the values in the above expression, we get

⇒ [tex]\frac{1}{48} -\frac{1}{\infty} =\frac{1}{f}[/tex]

             [tex]f=48 \ cm[/tex]  

or,

             [tex]f=0.48 \ m[/tex]

hence,

The refractive power will be:

⇒ [tex]P=\frac{1}{f}[/tex]

       [tex]=\frac{1}{0.48}[/tex]

       [tex]=2.08 \ D[/tex]

Answer:

B) mass of pendulum bob

Answer: Flow rate 1670 cm³/s

Explanation:   Cross section  A =  π · (2 cm)²  = 12.56 cm²

                     V = 1000 l   , t = 10 min = 600 s

                       dV / dt = 1000 l / 600 s = 1,67 l/s = 1670 cm³ /s

                      That was not asked,

                   dV / dt = vA  and flow speed v = (dV/dt)/A = 133 cm/s

The reaction is in A in vertical direction is W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ).

In terms of psychology, "stress" and "strain" are sometimes used interchangeably in popular culture, as in the expressions "I'm feeling stressed" or "I'm under a lot of pressure."

In engineering, these phrases have specific, technical meanings. If a hook in the steel wire is attached,

If you hang the wire from the ceiling while placing a weight on the lower end, it will sag. By dividing the length change by the starting length, the strain in the wire may be computed.

Thus, as per the given scenario, W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ) will be the equation.

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The normal force on the second tier of the cake is 14N. It is the sum of the weight of the last and the second tier of the cake.

The normal force is the force which the surfaces exert to prevent solid objects from passing through each other. Normal force is a contact force. If two objects or surfaces are not in contact, they cannot exert a normal force on each other.

Fₙ = mg

Fₙ = Normal force

Fₙ on the second tier is the sum of the first and second tier of the cake is:

Fₙ = 8N + 6N

Fₙ = 14N

The normal force on the second tier is 14N.

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The horizontal distance travelled by the box is 143 m.

The horizontal distance travelled by the box is calculated by determining the time of motion of the box and the horizontal velocity of the airplane.

The time of motion of the box from the vertical height in which it was dropped is calculated as follows;

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

t = √ ( 2h / g )

t = √ ( 2 x 40 / 9.8 )

t = 2.86 seconds

The horizontal distance travelled by the box is calculated as follows;

d = Vₓ t

where

d = ( 50 m/s ) x ( 2.86 s )

d = 143 m

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The complete question is below;

A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible. Find the horizontal distance travelled by the box.

Answer:

Explanation:

KE = (1/2)mv^2 ---> m = 2KE/v^2 = 2(9.890 J)/(10.1 m/s)^2

= 0.194 kg

Note: I think there's something wrong with the energy value given. The mass value for Usain Bolt is too small. That's less than a pound!

Answer:

Explanation:

The label that identifies a rarefaction in a longitudinal wave is B.

In a longitudinal wave, such as a wave in a spring, a rarefaction is an area where the particles of the medium are farther apart than they are in the rest of the wave. This is in contrast to a compression, which is an area where the particles of the medium are closer together than they are in the rest of the wave.

In the given illustration, the area where the rings are further apart is labeled B, so B is the label that identifies a rarefaction. The area where the rings are closer together, labeled A, is a compression. The height of the spring, labeled C, does not correspond to a rarefaction or a compression, and the distance between adjacent areas where the rings are closer together, labeled D, is not related to the concept of rarefactions or compressions.

Answer:

wavelength - C

rarefractions - B

compressions - A

Explanation:

correct on EDGE 2023

Answer:

C

Explanation:

Answer:

C

Explanation:

Answer:

The power is 57.6 watts

Explanation:

We can use the Electric Power Equation to evaluate the power.

Electric Power Equation

[tex]P=IV[/tex]

[tex]P[/tex] is the power in watts

[tex]I[/tex] is the current in amps

[tex]V[/tex] is the voltage in volts

Our lightbulb has current of 0.480 A and a voltage of 120.0 V.

[tex]I=0.480\\V=120.0[/tex]

Now we can evaluate power.

Substitute our values in for the variables.

[tex]P=0.480*120[/tex]

[tex]P=57.6[/tex]

Answer:

p/2

Explanation:

The law of motion that accounts for an apple accelerating as it falls from a tree is the law of gravity, specifically Newton's Second Law of Motion.

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In the case of an apple falling from a tree, the net force acting on it is the gravitational force pulling it toward the Earth. The acceleration of the apple is therefore determined by the strength of this gravitational force and the mass of the apple.

As the apple falls from the tree, it accelerates toward the ground due to the gravitational force acting on it. The faster the apple falls, the greater its acceleration. This acceleration is commonly referred to as acceleration due to gravity, which is a constant value of 9.81 m/s^2 near the surface of the Earth.

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The addition of two sound waves produces a new wave of higher amplitude if their compressions and refractions line up. It is also known as constructive interference.

Interference can be described as a phenomenon in which two waves combine by adding at every single point in space and time, to form a resultant wave of greater or lower amplitude.

Constructive and destructive interference occurs in the interaction of waves that are correlated with each other because they come from the same source.

When two sound waves propagate in the same direction in phase with each other, their amplitude gets added, and the resultant wave is produced from constructive interference.

When two waves interfere with each other and have a displacement in the opposite direction.  When a crest of a wave meets the trough of another wave, the waves undergo destructive interference.

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Optimal Arousal theory  focuses on finding the right level of stimulation.

William James (1842–1910), frequently referred to as the father of psychology in the United States, made significant contributions to early studies on motivation.

James proposed a number of instincts that help with survival as the driving forces behind conduct . An instinct is a species-specific pattern of behavior that is not taught, according to biology.

But there was a lot of disagreement over what exactly constitutes instinct among James's contemporaries. James postulated a number of unique human instincts, although many of his contemporaries had different lists.

Therefore, Optimal Arousal theory  focuses on finding the right level of stimulation.

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Answer:

false.

Explanation:

Since temperature and kinetic energy of molecules are proportional, the more we increase the temperature of the solvent, the faster the solute will dissolve.

This increase of kinetic energy allows the solvent molecules to more effective break apart the solvent molecules that are held together by intermolecular forces.

Answer:

An aqueous stagnant layer that overlies the apical membrane and the subepithelial blood flow are potential barriers to the absorption of drugs that readily penetrate the absorbing cell of the epithelium. The apical, basal, and basement membranes are potential barriers to the absorption of less permeable drugs.

claiming points because question is old + no keywords in title

Answer:

P V = n R T      ideal gas equation

V = k T     where k = a constant and equals k = n R / P

V is proportional to T when other factors are constant

Answer:

the answer is 2.6409.

Explanation:

i asked my teacher

So, we know that The box isn't moving at all. I'm assuming the coefficient they gave you is for static friction. We know that with static friction, the value that we calculate is a maximum value that represents the force we'd have to apply before an object starts moving!

We also know that the box isn't moving vertically. That means that its Y forces must be cancelling out, which means its weight force and its normal force must be equal to each other!

Now we can plug in these values into our static friction equation!

[tex]F_s[/tex] ≤ [tex]F_N[/tex] * μ[tex]_s[/tex]

[tex]F_s[/tex] ≤ (25N) (0.40)

[tex]F_s = 10[/tex]

Therefore your force that you'd need to apply is 10N!

The things that I will need to survive the layer of the earth called the mesosphere would be thick clothings.

The five(5) layers of the earth include the following such as:

The Mesosphere is one of the layers of the earth that is found directly above the stratosphere and then below the thermosphere.

The characteristics of the mesosphere is that the temperature rises due to reduced absorption of solar radiation and increased cooling by CO2 radiative emissions.

Therefore, for an individual to survive and live effectively at the Mesosphere layer of the earth, such needs thick clothings.

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▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

There are two forces which are being balanced :

(Ⅰ) The force of gravity which is pushing the ping-pong ball downwards.

(Ⅱ) The force of the air that's coming from hairdryer which is pushing ping-pong ball upwards.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

A horizontal force of 10.0 N is acting on a 10 kg box that is sliding to the right along the floor with velocity v.

Most people make the common assumptions of rigid body action and ignoring air resistance and friction. In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation.

The specific situation and the presumptions used will determine how many forces and moments are displayed. Most people make the common assumptions of rigid body action and ignoring air resistance and friction.

In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation. The resultant forces and moments in dynamics can have non-zero values.

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At separation  of 1470 meters, the two charges exert a force of 0.70 N on each other.

Electric force is the interaction between any two charged objects that can be either attractive or repelling. Newton's rules of motion, which apply to all forces, explain how each one affects the target body and how it does so. The electric force is one of the many forces that operate on objects.

We know that electric force can be mathematically defined as:

F = kQq/r²

0.70 = 9.0 × 10⁹ × (6.0×10⁻⁹)²/r²

r = 1.47 meter.

Hence, the separation between two charges is 1.47 meters.

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Answer:

e. none of the above

Explanation:

The frequency of an oscillating pendulum is the number of oscillation per unit time.

Mathematically, the frequency of an oscillating pendulum is given by the formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Hence, none of the changes mentioned will increase the frequency of an oscillating pendulum.

Answer:

[tex]\frac{T_2}{T_1} = 1[/tex]

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

[tex]v = \sqrt{\frac{3RT}{M} }[/tex]

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

[tex]v = \sqrt{\frac{3RT_1}{M} }[/tex]

For T = T₂ :

[tex]v = \sqrt{\frac{3RT_2}{M} }[/tex]

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

[tex]\sqrt{\frac{3RT_1}{M} }=\sqrt{\frac{3RT_2}{M} }\\\\\frac{T_2}{T_1} = 1[/tex]

The points in order of increasing value of the velocity can be ranked as:

B < C < A ≡ F < E < D.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

According to the figure:

The points in order of increasing value of the velocity can be written as:

B < C < A ≡ F < E < D.

As the displacement becomes from positive to negative near point B, it has the lowest velocity and  as the displacement becomes from negative to positive near point D, it has the highest velocity

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The number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

Electrons are particles of matter that carry a negative electrical charge. Electrons are the smallest particles in the atom and are responsible for most of the atom's mass. Electrons orbit around the nucleus of the atom and are held together by the electromagnetic force. Electrons have a property called spin, which can have a value of either +1/2 or -1/2. Electrons are found in all elements and are important in chemical reactions as they are able to move around and form bonds with other atoms. Electrons are also important in electricity and magnetism.

The number of excess electrons on the balloon is equal to the charge of the balloon divided by the charge of an electron. Since the charge of an electron is 1.60 x 10-19 Coulombs, the number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.

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Answer:

a. The final speed , v' when it returns is the same speed, u as when it was released. v' = u

b. The time of flight T equals twice the time taken to reach the highest point, t. T = 2t

Explanation:

(a) As long as you can neglect the effects of the air, if you throw anything vertically upward, it will have the same speed when it returns to the release point as when it was released.

Using v² = u² - 2gh, we find the maximum height the object reaches. With u = initial vertical velocity, v = velocity at maximum height = 0 m/s (since it momentarily stops), g = acceleration due to gravity and h = maximum height

So, v² = u² - 2gh

0² = u² - 2gh

0 = u² - 2gh

-u² = -2gh

h = -u²/-2g

h = u²/2g

On its return trip to the point where it is released, the distance covered is h and its initial velocity u' = 0

With v' as the final velocity, we use

v'² = u'² + 2gh

substituting the values of the variables into the equation, we have

v'² = 0² + 2g(u²/2g)

v'² = 0² + u²

v'² = u²

taking square-root of both sides, we have

√v'² = √u²

v' = u

So, the final speed , v' when it returns is the same speed u as when it was released. v' = u

(b) The time of flight will be twice the time it takes to get to its highest point.

At the highest point, its velocity is zero.

Using v = u - gt where u = initial velocity, v = final velocity(velocity at highest point) = 0 (since it is momentarily at rest), g = acceleration due to gravity and t = time taken to reach the highest point.

So, substituting the values of the variables into the equation, we have

v = u - gt

0 = u - gt

-u = -gt

t = u/g

On its return trip, since we know its final velocity = u and its initial velocity is  0 m/s, again, using

v' = u' + gt' where u' = initial velocity = 0 (since it is at its highest point), v' = final velocity = u (velocity on return to release point), g = acceleration due to gravity and t' = time taken to reach release point from highest point

So, substituting the values of the variables into the equation, we have

v' = u' + gt'

u = 0 + gt'

u = gt'

t' = u/g = t

So, the time of flight, T = time taken to reach highest point + time taken to return to release point

T = t + t'

T = u/g +u/g

T = 2u/g

T = 2t

So, the time of flight T equals twice the time taken to reach the highest point, t. T = 2t