Answer:
The steps involved in the scientific method are;
•Draw up a research question
•Construct a hypothesis
•Test the hypothesis through experiments
•Analyse experimental results
•Draw conclusions
Science is a study of the universe from an empirical point of view. This means that scientific investigations depend onexperiments.
The first step in the scientific method of investigation is to draw up the research questions to be investigated. After this is done, subjected to experiments. The experiments may confirm or disprove the hypothesis. If the hypothesis is disproved, then it is revised in line with the results of experiments.
a research hypothesis is constructed and
Calculate the pressure amplitude of a 2.80 kHz sound wave in the air, if the
displacement amplitude is equal to 2.00 ✕ 10-8 m.
The pressure amplitude of a 2.80 kHz sound wave is mathematically given as
pm=0.14647pa
What is the pressure amplitude of a 2.80 kHz sound wave in the air?
Generally, the equation for the relation b/w pressure amplitude and displacement amplitude is mathematically given as
pm=2\pifvps
Therefore
pm=(2\pi)(2.80*10^3)(340)(1.225)(2.00*10^{-8})
pm=0.14647pa
In conclusion
pm=0.14647pa
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1 x 1015 electrons are pushed through a 10 Ω wire in one minute. What is the voltage of the power source? (e = -1.602 x 10-19 C)
The voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.
Voltage of the power source
The voltage of the power source is determined from ohm's law as shown below;
V = IR
where;
I is currentR is resistanceV is voltageBut, I = Q/t
V = (Q/t)R
[tex]V = \frac{QR}{t} \\\\V = \frac{(1\times 10^{15} \times 1.602\times 10^{-19} \ C) \times \ 10 \ ohms}{1 \times 60\ s} \\\\V = 2.67 \times 10^{-5} \ V[/tex]
Thus, the voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.
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An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
motionless (gravity force equalling electrostatic force) when the electric field is set to 370 N/C and directed
downward.
a) Determine the sign and magnitude of the charge on the oil droplet.
b) Determine the approximate number of excess electrons that are on the oil droplet.
Answer:
The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.
F = N e E where E is the value of the field and N e the charge Q
M g = N e E and M g is the weight of the drop
N = M g / (e E)
N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13
.00011 kg is a very large drop
Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs
Check: N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13 electrons
How close would you have to bring 1 C of positive chargeand 1 C of negative charge for them to exert forces of 1 N onone another?
Answer:
94,800 m
Explanation:
F = kq1 q2/r^2
1 = 9 x 10^9 x 1 / r^2
From a graph v1 = 0.4m/s, V2 = 2.35m/s, t1 = 0.5s, t2 = 10.0s. The slope obtained using the above information isSelect one:
O 0.21m/s
O 0.27m/s
O 0.25m/s
O 0.23m/s
The slope obtained using the above information is acceleration and the magnitude of the acceleration is determined as 0.21 m/s².
Slope of velocity - time graph
The slope of velocity time graph is known as acceleration. Acceleration is the rate of change of velocity with time.
a = Δv/Δt
where;
Δv is the change in velocityΔt is the change in timeChange in velocityΔv = vf - vi
Δv = 2.35 - 0.4
Δv = 1.95 m/s
Change in timeΔt = t2 - t1
Δt = 10 - 0.5
Δt = 9.5 s
Slope of the grapha = Δv/Δt
a = (1.95) / (9.5)
a = 0.21 m/s²
Thus, the slope obtained using the above information is acceleration and the magnitude of the acceleration is determined as 0.21 m/s².
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Is this circuit parallel??????
Answer:
yes it is parrell
Explanation:
Which of the following describes the renewability of utility-scale wind energy?
Replenishable but not renewable
Needs energy grid for electricity
Unlimited, clean energy plant
Sustainable lack of emissions
Unlimited, clean energy plant describes the renewability of utility-scale wind energy.
What is utility-scale wind energy?Utility-scale wind turbines are installed in large, multi-turbine wind farms connected to the nation's transmission system. These turbines produce clean and unlimited energy.
So we can conclude that Unlimited, clean energy plant describes the renewability of utility-scale wind energy.
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Answer:
Answer 3
Explanation:
I took the test
A bowl of hot soup and a glass of ice water are left in a room. Eventually
the soup and the water become the same temperature as their
surroundings. Which of the following explains the flow of heat that led to
this final outcome?
A
The heat of the soup and the cold of the water were exchanged,
cancelling each other out
B
Heat energy went from the soup to the room and from the room
into the ice water
С
Heat energy went from the ice water to the soup and from the
soup to the room.
D
The low temperature of the water was transferred to the room
and from the room to the soup.
Answer:
The answer must be B
Explanation:
Because the hot soup increases the temperature of the room it also increased the temprature of the ice water and because whatever surroundings the soup and the ice is in it transfers heat energy to the room and because most of the energy is lost in the room it eventually becomes the same tempature.