Answers
For this workout I did squats. Squats may aid in weight loss because they burn calories. Moreover, they reduce the possibility of knee and ankle injuries.
How did the squat exercise make you feel?When performing squats, your legs should feel fatigued. Lower back ache is a sign that you're likely doing the workout wrong. This shows that your lower back muscles are working harder than your glutes and quadriceps since they are taking the load. Pay attention to how you squat.
Squats are possible everywhere?It doesn't matter where it is—a living room, office, stairwell, park, or closet—as long as there are a few feet available. The only thing you need is your body weight.
Is it acceptable to squat without a spotter?In some instances, it is acceptable to squat without a spotter. The environment and resources you have at your disposal, though, are everything. The safest choice is to use a power rack or squat stand with adjustable safety pins, arms, or straps.
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Related Questions
Starting from rest, a wheel of radius 0.25 m accelerates counterclockwise at 6 rad/s2 in 2 seconds. Approximately many revolutions does the wheel complete during its 2 seconds of acceleration?
Starting from rest, a wheel of radius 0.25 m accelerates counterclockwise at 6 rad/s2 in 2 seconds. Approximately many revolutions does the wheel complete during its 2 seconds of acceleration?
Answers
The wheel completes approximately 1.91 revolutions during its 2 seconds of acceleration.
How can I determine how many revolutions a wheel takes when moving quickly?The car's uniform acceleration, a = v/t, is provided. The distance it moves in the given amount of time, t, can be calculated using the kinematic equations for linear motion. By multiplying this distance by the tyre's diameter, we can calculate the number of revolutions. The formula f = vf/rtire yields the ultimate angular speed.
To resolve this issue, we can use the kinetic equation shown below:
θ = 1/2 α t²
To begin with, we can use the following method to determine the wheel's ultimate angular velocity:
ωf = ωi + αt
where i represents the starting angular speed. (which is zero in this case).
ωf = ωi + αt
ωf = 0 + 6 rad/s² × 2 s
ωf = 12 rad/s
Next, we can calculate the number of rotations made during the two seconds of acceleration using the formula for the angle the wheel made:
θ = 1/2 α t²
θ = 1/2 × 6 rad/s^2 × (2 s)²
θ = 12 rad
We can divide this by 2 (the number of radians in a rotation) to get the number of revolutions:
of revolutions = θ / 2π
of revolutions = 12 rad / 2π
of revolutions ≈ 1.91 revolutions.
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We perform an experiment with a 28 cm rod with a mass of .07 kg swinging from its endpoint. The pendulum is allowed to move freely. The pendulum system is then placed on a cart. From rest of both the cart and the pendulum, the cart is push and the acceleration (a) of the cart and the angle of the pendulum is measured. (1): Justify based on theory the maximum displacement angle observed. (2): Do the same, but what if the rod is hung 8 cm from its endpoint?
Answers
For a given length of the pendulum and acceleration of the cart, the maximum displacement angle can be determined using the above formulas.
What is Acceleration?
Acceleration can be positive or negative depending on the direction of the change in velocity. If an object is speeding up, the acceleration is positive, while if it is slowing down, the acceleration is negative.
(1) The maximum displacement angle observed in a pendulum experiment can be determined by the length of the pendulum and the acceleration due to gravity. According to the theory of simple harmonic motion, the period of a pendulum is directly proportional to the square root of its length and inversely proportional to the square root of the acceleration due to gravity.
The formula for the period of a pendulum is:
T = 2π * sqrt(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.8 m/[tex]s^{2}[/tex]).
For a given length of the pendulum, the maximum displacement angle occurs when the pendulum is at the highest point in its swing (i.e., when its velocity is momentarily zero). At this point, all of the energy of the pendulum is potential energy (i.e., gravitational potential energy), and the angle is known as the maximum displacement angle or the amplitude.
The maximum displacement angle (θ) can be calculated using the formula:
θ = [tex]sin^{^-1(a/g)}[/tex]
where a is the acceleration of the cart.
Therefore, for a given length of the pendulum and acceleration of the cart, the maximum displacement angle can be determined using the above formulas.
(2) If the rod is hung 8 cm from its endpoint instead of 28 cm, the length of the pendulum (L) would be 20 cm. Using the same formula as above, the period of the pendulum would be:
T = 2π * sqrt(0.2/9.8) = 0.898 seconds
The maximum displacement angle can be calculated using the same formula as above:
θ = sin^[tex]sin^{^-1(a/g)}[/tex]
where a is the acceleration of the cart.
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(a) Find the frequency ratio between the two frequencies fi = 256 Hz and f2=320 Hz.
(b) Add the interval of a fifth to f2 to obtain fs, and find the frequency ratio falfi.
(c) Find the frequency of fs.
Answers
The frequency ratio between fi = 256 Hz and f2 = 320 Hz is 4:5.Adding the interval of a fifth to f2 (320 Hz) results in fs (400 Hz). The frequency ratio falfi is 5:8.The frequency of fs is 400 Hz.
What is the interval of a fifth in music theory?The interval of a fifth in music theory is the distance between two notes that are five notes apart in a diatonic scale. For example, the distance between C and G is a fifth.
How are frequency and pitch related in music?Frequency and pitch are related in music because the pitch of a note is determined by its frequency. Lower frequencies result in lower pitches, whereas higher frequencies result in higher pitches.
The relationship between frequency and pitch is logarithmic, meaning that a doubling of frequency results in an increase of one octave (a doubling of pitch).
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Evaluate the formula x² =
(n-1)s²
0²
when o = 2.94, n=39, and s=3.15.
x² = (Round to three decimal places as needed.)
Answers
Answer:
x² = ((n-1)s²)/o²
x² = (39 - 1) * (3.15)² / (2.94)²
x² = 38 * 9.9225 / 8.6436
x² = 43.7598
Rounding to three decimal places, x² = 43.760. Therefore, the value of x² is 43.760 when o = 2.94, n = 39, and s = 3.15.
Explanation:
Math
Easy physics.
if the ball in the following image continues to accelerate at a rate of 10m/s after it reaches the peak height and begins to move back down, what velocity should the ball 3 seconds after reaching the peak height.
Answers
The velocity of the ball 3 seconds after reaching the peak height is 30 m/s. And the right option is D. 30 m/s
What is velocity?Velocity is the rate of change of displacement.
To calculate the velocity the ball will travel after reaching the peak height, we use the formula below
Formula:
v = u+at...................... Equation 1Where:
v = velocity at which the ball travels after reaching the peak heightu = Initial velocitya = Accelerationt = TimeFrom the question,
Given:
a = 10 m/s²u = 0 m/s (At the peak height)t = 3 secondsSubstitute these values into equation 1
v = 0+(3×10)v = 30 m/sHence, the velocity is 30 m/s.
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A 28 g block of ice is cooled to −78 ◦C. It
is added to 562 g of water in an 80 g copper
calorimeter at a temperature of 21◦C.
Find the final temperature. The specific
heat of copper is 387 J/kg ·
◦C and of ice is
2090 J/kg ·
◦C . The latent heat of fusion of
water is 3.33 × 105
J/kg and its specific heat
is 4186 J/kg ·
◦C .
Answer in units of ◦C
Answers
Answer:
14.46°C
Explanation:
Given:
Mass of ice = 28 g = 0.028 kgMass of water = 562 g = 0.562 kgMass of copper calorimeter = 80 g = 0.08 kgSpecific heat of copper = 387 J/(kg°C)Specific heat of water = 4186 J/(kg°C)Specific heat of ice = 2090 J/(kg°C)Latent heat of fusion of water = 3.33 x 10^5 J/kgInitial temperature of ice = -78°CMelting point of ice = 0°CInitial temperature of water and copper calorimeter = 21°CFind:
The final temperature of the mixtureSolution:
1. Calculate the heat required to warm the ice from its initial temperature to its melting point: Heat to warm ice = Mass of ice * Specific heat of ice * (Melting point of ice - Initial temperature of ice) Heat to warm ice = 0.028 kg * 2090 J/(kg*°C) * (0°C - (-78°C)) = 4579.44 J
2. Calculate the heat required to melt the ice at its melting point: Heat to melt ice = Mass of ice * Latent heat of fusion of water Heat to melt ice = 0.028 kg * 3.33e5 J/kg = 9324 J
3. Calculate the heat lost by the water and calorimeter as they cool down to the final temperature: Heat lost by water and calorimeter = Mass of water * Specific heat of water * (Initial temperature of water and copper calorimeter - Final temperature) + Mass of copper calorimeter * Specific heat of copper * (Initial temperature of water and copper calorimeter - Final temperature)
4. The total heat gained by the ice must be equal to the total heat lost by the water and calorimeter: Heat to warm ice + Heat to melt ice + Mass of ice * Specific heat of water * (Final temperature - Melting point of ice) = Heat lost by water and calorimeter 4579.44 J + 9324 J + 0.028 kg * 4186 J/(kg°C) * (Final temperature - 0°C) = [0.562 kg * 4186 J/(kg°C) + 0.080 kg * 387 J/(kg*°C)] * (21°C - Final temperature)
Solving for the final temperature, we get: Final temperature ≈ 14.46°C
So, the final temperature of the system is approximately 14.46°C
A 10,000 kg railroad car is rolling at 4.00 m/s when a 4000 kg load of gravel is suddenly dropped in.
What is the car's speed just after the gravel is loaded?
Answers
The speed of the car just after the gravel is loaded is 2.8m/s.
An isolated system experiences a change in momentum to zero when the starting and final velocities are equal. The reactions between the particles are separated from the surroundings. Momentum is conserved, so we use the rule of conservation of momentum, which is expressed by the equation
[tex]P_{f}[/tex]=[tex]P_{i}[/tex](1)
Railway is frictionless due to isolated mechanism. The thing travels at a momentum p-based speed while having mass. m
An object's bulk and velocity v are combined to form a vector.Equation of the form gives the velocity.
[tex]p=mv[/tex]
Using expression p into equation (1)
[tex]m_{f}v_{f}[/tex]=[tex]m_{i}v_{i}[/tex](2)
The final mass of a car is its original mass plus the mass of the gravel added. A car has an initial mass of.10000Kg preliminary pace is
[tex]m_{f}[/tex]=10000Kg+4000Kg=14000Kg
initial speed 4m/s
the final speed should be found after solving the equation(2) for [tex]v_{f}[/tex]
[tex]v_{f}[/tex]=[tex]\frac{m_{i}v_{i} }{m_f} }[/tex]=[tex]\frac{10000Kg(4m/s)}{1400Kg}[/tex]=2.8m/s
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If the entire mass of the Milky Way was due to gas and stars, how would you expect the rotational speed of a star near the edge of the galaxy to compare to the rotational speed of a star near the center?
Answers
Observations of a Milky Way have brought out that stars close to the galaxy's edge rotate rather quickly, which implies that there is more solar masses that we are unable to perceive.
What is a star of mass 1 solar?The Sun-like star is known as a 1-solar mass star. At the rightmost to the bottom left in the stars, the primary structure region is where this type of star begins. Nearing the end its main-sequence existence, the star transforms into a red giant as it keeps burning its fuel.
The eight solar masses are known as.As far as I'm aware, "massive stars" are defined as having masses equal or greater than to eight solar masses.
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The food calorie is equivalent to 4190 J . How many food calories does the cyclist burn if he rides over level ground at 7.3 m/s for 1.5 h ?
Answers
Answer:
To solve this problem, we need to use the formula: calories burned = (power expended in watts x time in seconds) / 4.184 First, we need to find the power expended in watts. We can use the formula: power = force x velocity Assuming the cyclist weighs 75 kg, the force required to maintain a speed of 7.3 m/s on level ground is: force = mass x acceleration force = 75 kg x 0 m/s^2 (since the cyclist is not accelerating) force = 0 N Therefore, the power expended by the cyclist is: power = force x velocity power = 0 N x 7.3 m/s power = 0 W Now we can plug in the values into the calories burned formula: calories burned = (power expended in watts x time in seconds) /
Tobias has set a goal to reduce the number of errors on his timed typing tests by three each week. How can he track his progress on this goal?
Question 3 options:
plot the change in his WPM on a chart
purchase a fee-based typing program
track the hours he practices each week
edit each test document and write down the number of errors
Answers
Answer: D, Edit each test document and write down the number of errors
Explanation: I did the test and got 5/5 gl! :D
what is the speed of a water wave that has a wavelength of 2 m and a frequency of 0.025 Hz?
Answers
Explanation:
speed = wavelength * frequency
= 2 m * .0025/s = .005 m/s
4. An ice skater is spinning on the ice at 4.00 rev/s. If the skater’s nose is 0.120 m from the axis of rotation, what is the centripetal acceleration of his nose?
Answers
The centripetal acceleration of the ice skater spinning on the ice at 4.00 rev/s whose nose is 0.120 m from the axis of rotation is [tex]75.78m/s^2[/tex]
Given the rate of revolutions of a skater = 4rev/s
The distance of nose from skater = 0.120m
Let the centripetal acceleration of his nose = ac
The centripetal acceleration of an object moving in a circular path can be calculated using the equation:
[tex]ac = (v^2)/r[/tex]
where v is the velocity of the object, and r is the radius of the circle.
In this case, the angular velocity of the skater is 4.00 rev/s.
Since 1 revolution is = 2π radians,
the skater's angular velocity can be expressed as:
v = rω such that
[tex]\omega = (4.00 rev/s) * (2\pi radians/1rev) = 8\pi rad/s = 25.13rad/s[/tex]
Using the equation above, the centripetal acceleration of the skater's nose can be calculated as:
[tex]ac = \omega^2r^2/r = \omega^2r[/tex]
[tex]ac = (25.13 radians/s)^2*0.120 m[/tex]
[tex]ac = 75.78m/s^2[/tex]
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In your design, how would you change the mass of Car A to minimize (make less) the change in motion of Car A due to the collision? Explain your idea using Newton's Third Law and support it with evidence from the system model in this activity
Answers
to minimize the change in motion of Car A due to the collision, we should decrease the mass of Car A relative to the mass of Car B.
Newton's Third Law states that for every action, there is an equal and opposite reaction. This means that in a collision between two objects, the force that Car A exerts on Car B is equal and opposite to the force that Car B exerts on Car A.
To minimize the change in motion of Car A due to the collision, we need to minimize the force that Car B exerts on Car A. This can be achieved by decreasing the mass of Car A relative to the mass of Car B.
We can see evidence of this from the system model in the activity. When Car A and Car B have equal masses, they experience equal and opposite forces during the collision, and their velocities are both affected to the same degree. However, when Car A has less mass than Car B, Car B experiences a greater force during the collision, but Car A experiences a smaller force. As a result, Car A experiences less of a change in velocity than it would if the masses were equal.
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which patterns do you notice about the intensities of the reflected and the refracted rays? What can you conclude from this pattern?
Answers
The angle on incidence and the characteristics of the objects involved determine how intense the reflected & refracted rays are. But generally speaking, there are some trends that may be seen.
Where is the ray being reflected?The incident & surface normal planes specify the plane in which light that Reflects always falls. The rules of reflection applies to images created by both curved and planar mirrors.
What do reflection and refracted light mean?Reflection is the act of light simply returning when it strikes a material on a plane. Refraction is the process by which light passes through a medium and undergoes a change that causes it to bend. The medium returns the light that it received.
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Easy physics.
if the ball in the following image continues to accelerate at a rate of 10m/s after it reaches the peak height and begins to move back down, what velocity should the ball 3 seconds after reaching the peak height.
Answers
The velocity of the ball 3 seconds after reaching the peak height is 30 m/s.
What is Velocity?
Velocity is a vector quantity that describes the speed and direction of motion of an object. It is defined as the rate of change of displacement of an object over time. In other words, velocity tells us how fast an object is moving and in what direction.
Assuming that air resistance is negligible, we can use the kinematic equations of motion to solve for the velocity of the ball 3 seconds after reaching the peak height.
Let's use the following variables:
a = acceleration = 10 m/[tex]s^{2}[/tex] (since the ball is continuing to accelerate downwards)
t = time = 3 seconds (since we want to find the velocity 3 seconds after reaching the peak)
v₀ = initial velocity = 0 m/s (since the ball has zero velocity at the peak)
v = final velocity (what we want to find)
Using the kinematic equation for velocity with constant acceleration:
v = v₀ + at
Substituting the given values:
v = 0 + 10 m/[tex]s^{2}[/tex] × 3 s
v = 30 m/s
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when is the angular momentum of asystem constant
Answers
The angular momentum of a system is conserved when there is no external torque acting on the system.
This is known as the law of conservation of angular momentum. Mathematically, it can be expressed as:
L = Iω
where L is the angular momentum of the system, I is the moment of inertia, and ω is the angular velocity. If the net external torque acting on the system is zero, then the angular momentum of the system remains constant.
This law has many applications in physics, including in rotational motion, celestial mechanics, and quantum mechanics. For example, the conservation of angular momentum explains why a spinning ice skater speeds up when they bring their arms inwards, and why the Earth's rotation remains constant over long periods of time.
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A sound wave has a frequency of 668 Hz in air
and a wavelength of 0.5 m.
What is the temperature of the air?
Relate the speed of sound in air to temper-
ature in units of Kelvin, but answer in units
of Celsius.
Assume the velocity of sound at 0°C is
334 m/s.
Answer in units of degC.
Answers
The temperature of the air would be 6.3 °C.
Sound wave and air temperatureThe speed of sound in air depends on the temperature of the air according to the equation:
v = 331.5 m/s * sqrt(T/273.15 K)
where v is the speed of sound, T is the temperature of the air in Kelvin, and 273.15 K is the temperature at which the speed of sound is 331.5 m/s.
We know the frequency and wavelength of the sound wave, which are:
f = 668 Hz
λ = 0.5 m
The speed of sound can be calculated from the formula:
v = fλv = (668 Hz) * (0.5 m) = 334 m/sSubstituting this value for v and the given value for the speed of sound at 0°C into the equation above and solving for T gives:
v = 331.5 m/s * sqrt(T/273.15 K)(T/273.15 K) = (v/331.5 m/s)^2(T/273.15 K) = (334 m/s / 331.5 m/s)^2(T/273.15 K) = 1.022T = 1.022 * 273.15 KT = 279.4 KThe temperature of the air is 279.4 K, which is equivalent to 6.3 °C, rounded to 1 decimal place.
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Suppose a double-slit interference pattern has its third minimum at an angle of 0.283° with slits that are separated by 292 μm.
Answers
Consequently, the light's wavelength that caused the multiply-slit interference pattern was around 546 nm.
Why do interference patterns exist?Solution and Justification: Interference patterns are produced when waves of identical (or what very similar) frequencies collide. The amplitudes of these waves may then either be raised (via constructive interference) or lowered.
Which interference pattern does the equation have?Fringes are the light lines that alternate with the black lines in the interference pattern. The following equation can be used to calculate the wavelength for the double-slit experiment: dissipates ≈ xd / L.
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The correct question is
Problem 4: Suppose a double-slit interference pattern has its third minimum at an angle of 0.256° with slits that are separated by 293 μm.
Randomized Variables
0 = 0.256°
d=293 μm
Calculate the wavelength of the light in nm.
Gra
Ded
Pote
What is Newton's law of cooling
Answers
Answer:
Q = h . A . (T (t) - T env)
the rate of loss of heat from a body is directly proportional to the difference in the temperature of the body and its surroundings.
Explanation:
Q = rate of heat transfered out of the body
h = heat transfers coefficient
A = heat transfer to surface area
T = temperature of the objects surface
T env = temperature of the environment
T (t) = time dependent temperature
A proton traveling due east in a region that contains only a magnetic field experiences a vertically upward force (away from the surface of the earth). What is the direction of the magnetic field with respect to your screen? Question 4 options: a) into your screen b) to the right c) out of your screen d) to the left
Answers
The direction of the magnetic field with respect to your screen is d) to the left.
The upward force experienced by the proton indicates that the magnetic field is acting perpendicular to both the motion of the proton (due east) and the force it experiences. According to the right-hand rule for magnetic forces, if you point your thumb in the direction of the velocity of the charged particle (due east in this case) and your fingers in the direction of the force (vertically upward), then the direction your palm faces represents the direction of the magnetic field.
In this scenario, if you extend your left hand and point your thumb to the right (due east) and your fingers vertically upward, your palm will face to the left, indicating that the magnetic field is directed to the left. Therefore, option d) to the left is the correct answer. The magnetic field is perpendicular to the plane of the screen and points into the screen.
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a block of mass 300kg is sliding down a ramp of 4 m from a height of 3 m .calculate the coefficient of kinetic friction,mechanical advantage ,va
Answers
the coefficient of kinetic friction is approximately 0.689, the mechanical advantage is 4/3, and the velocity ratio is 1.22.
the coefficient of kinetic friction, mechanical advantage, and velocity at the bottom of the ramp, we need to use the conservation of energy principle. At the top of the ramp, the block has potential energy given by mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the ramp. At the bottom of the ramp, the block has kinetic energy given by (1/2)m[tex]v^2[/tex], where v is its velocity. Assuming there is no energy loss due to friction, we can equate the potential energy at the top of the ramp to the kinetic energy at the bottom of the ramp.
1-Ep = Ek + Wf
mgh = 1/2 * m[tex]v^2[/tex]+ μk * mg * d
Solving for the coefficient of kinetic friction, we get:
μk = (mgh - 1/2 * m[tex]v^2[/tex]) / (mgd)
μk = (2gh - [tex]v^2[/tex]) / (2gd)
μk = (2 * 9.81 m/[tex]s^2[/tex] * 3 m - [tex]v^2[/tex]) / (2 * 4 m)
μk = 0.689
2-The mechanical advantage of the ramp is given by the ratio of the length of the ramp to the height from which the block falls:
MA = d / h = 4 m / 3 m = 4/3
3-VR = v / sqrt(2gh)
Ep = Ek + Wf
mgh = 1/2 * m[tex]v^2[/tex] + μk * mg * d
Solving for v, we get:
v = sqrt(2gh - 2μkgd) = 5.77 m/s
So the velocity ratio is:
VR = 5.77 m/s / sqrt(2 * 9.81 m/[tex]s^2[/tex] * 3 m) = 1.22
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the function f(x) = -x^2 - 9x+36 shows the relationship between the vertical distance of a diver from a pool's surface f(x), in feet, and the horizontal distance x, in feet, of a diver from the diving board. What is a zero of f(x), and what does it represent?
Answers
The zeros of the function f(x) are x = 3 and x = -12.
To find the zeros of a function, we need to solve the equation f(x) = 0. In this case, we have:
f(x) = -x^2 - 9x + 36
Setting f(x) = 0, we get:
-x^2 - 9x + 36 = 0
We can solve this quadratic equation by factoring or by using the quadratic formula. Factoring, we get:
-(x - 3)(x + 12) = 0
Setting each factor equal to zero, we get:
x - 3 = 0 or x + 12 = 0
Solving for x, we get:
x = 3 or x = -12
These zeros represent the horizontal distances from the diving board where the vertical distance of the diver from the pool's surface is zero. In other words, they represent the points where the diver enters the water. The zero x = 3 represents the point where the diver enters the water at a distance of 3 feet from the diving board, while the zero x = -12 represents the point where the diver enters the water at a distance of 12 feet behind the diving board. However, the negative solution x = -12 is not meaningful in this context since it represents a point that is behind the diving board, so we discard it. Therefore, the zero x = 3 is the meaningful solution, which represents the point where the diver enters the water at a distance of 3 feet from the diving board.
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The sound level produced by one singer is
82.1 dB.
What would be the sound level produced
by a chorus of 43 such singers (all singing at
the same intensity at approximately the same
distance as the original singer)?
Answer in units of dB.
Answers
Answer: The sound level produced by a chorus of 43 singers will be 97.66 dB.
Explanation:
Let I, the intensity of a sound produced by a singer, therefore, the intensity of the sound produced by 43 singers is equal to 43I. Therefore, the intensity is:
x = 10log(43I/Io)
x = 10log(43) + 10log(I/Io)
The second term in the equation is the sound intensity produced by a single singer. We calculate that the sound intensity of 36:
x = 10log(36) + 82.1 = 97.66 dB
A jar of tea is placed in sunlight until it
reaches an equilibrium temperature of 33.3
◦C .
In an attempt to cool the liquid, which has a
mass of 187 g , 133 g of ice at 0.0
◦C is added.
At the time at which the temperature of the
tea is 31.8
◦C , find the mass of the remaining
ice in the jar. The specific heat of water
is 4186 J/kg ·
◦ C . Assume the specific heat
capacity of the tea to be that of pure liquid
water.
Answer in units of g.
(2 significant digits)
Answers
Answer: The mass of the remaining ice in the jar is 1.3e+2 g.
Explanation: Let’s denote the mass of the remaining ice as m_ice. The heat gained by the ice is equal to the heat lost by the tea. The heat gained by the ice is given by m_ice * L_f, where L_f is the latent heat of fusion of water (334000 J/kg). The heat lost by the tea is given by m_tea * c_w * (T_initial - T_final), where m_tea is the mass of tea (0.187 kg), c_w is the specific heat capacity of water (4186 J/kg·°C), T_initial is the initial temperature of the tea (33.3°C), and T_final is the final temperature of the tea (31.8°C).
Equating the heat gained by the ice to the heat lost by the tea, we get:
m_ice * L_f = m_tea * c_w * (T_initial - T_final)
Substituting in the values, we get:
m_ice * 334000 = 0.187 * 4186 * (33.3 - 31.8)
Solving for m_ice, we get:
m_ice = 0.187 * 4186 * (33.3 - 31.8) / 334000
m_ice ≈ 0.130 kg
Converting to grams and rounding to two significant figures, we get:
m_ice ≈ 130 g
Hope this helps, and have a great day! =)
If a transverse wave passes from a flexible spring into a heavier stiffer spring where the wave has a greater speed, what will happen to the
reflected wave in the flexible spring?
Answers
When a transverse wave passes from a flexible spring into a heavier stiffer spring, the wave will have a greater speed in the stiffer spring due to the increased stiffness of the material. As a result, when the wave reaches the end of the stiffer spring, some of the energy from the wave will be reflected back towards the flexible spring.
The reflected wave in the flexible spring will be inverted, meaning that it will be flipped upside down. Additionally, the amplitude of the reflected wave will depend on the amount of energy that was transmitted into the stiffer spring.
If a large amount of energy was transmitted, then the reflected wave will have a higher amplitude. Conversely, if only a small amount of energy was transmitted, then the reflected wave will have a lower amplitude.
Overall, the reflected wave in the flexible spring will experience a change in both its orientation and amplitude due to the transmission and reflection of the initial wave in the stiffer spring.
When a transverse wave passes from a flexible spring into a heavier, stiffer spring where the wave has a greater speed, the reflected wave in the flexible spring will have a reduced amplitude and undergo a phase change of 180 degrees, resulting in an inverted waveform.
This occurs due to the impedance mismatch between the two springs, causing part of the wave energy to be reflected and part to be transmitted.
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In an air standard diesel cycle, the compression ratio is 16 and at the beginning of isentropic compression, the temperature is 15c and the pressure is 0.1 j\.1pa. Heat is added until the t:mperature at constant process is 1480c. Calculate cut off ratio, heat supplied per kg of arr, cycle efficiency and mean effective pressure
Answers
If Cv reduces by 2%, calculate the percentage gain in efficiency of the a diesel cycle with a bit rate of 16 and a cut-off ratio of 10% of a swept volume. Taking Cv = 0.717 & 1.4; the answer is 1.23%.
Where can I find the volume?In cubic units, the volume answer is displayed. Volume is determined by multiplying the length, breadth, and height.
What does measuring of volume entail?The 3-dimensional space that is occupied by matter or surrounded by a surface is measured in volume, which is expressed in cubic units. A derived measure called a cubic meter (m3) serves as the SI volume measurement unit.
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in a car lift in a service station, compressed air exerts a force on a small piston that has a circular cross section of radius 5.00cm. This pressure is transmitted by a liquid to a piston that has a radius of 15.0 cm. (b) What air pressure will produce a force of that magnitude?
Answers
The air pressure that will produce a force of the given magnitude is 135 times the pressure transmitted by the liquid. The value of P2, the pressure transmitted by the liquid, is not given in the problem, so we cannot determine the exact value of P1.
How is atmospheric pressure produced?The planet's gravitational pull on the gases above its surface produces atmospheric pressure, which depends on the planet's mass, the radius of its surface, the quantity, makeup, and vertical distribution of the gases in the atmosphere.
The following equations describe the force that compressed air exerts on a tiny piston:
F1 = P1 * A1
The larger piston, which has a larger area A2, receives the power via the liquid. The larger piston's power is determined by:
F2 = P2 * A2
Pascal's rule states that the larger piston receives the same amount of pressure P1 as the smaller piston, so we have:
P1 = P2
Since the forces F1 and F2 are equal, we have:
F1 = F2
Therefore:
P1 * A1 = P2 * A2
P1 * (pi * (5.00 cm)²) = P2 * (pi * (15.0 cm)²)
Simplifying and solving for P1, we get:
P1 = (P2 * A2 * (5.00 cm)²)/ (A1 * (15.0 cm)²)
Substituting A1 = pi * (5.00 cm)² and A2 = pi * (15.0 cm)², we get:
P1 = (P2 * 15.0²) / 5.00²
P1 = 135 * P2.
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A uniformly charged semicircle (radius= 4.46 cm, charge= 7.5 μC). What is the magnitude of the electric field at the center of the semicircle?
Answers
Answer:
A uniformly charge d insulating rod of length 14.0cm is bent into the shape of a semicircle as shown in Figure. The rod has a total charge of −7.50μC. Find (a) the magnitude and (b) the direction of the electric field at O, the center of the semicircle.
1859579
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Medium
Solution
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Verified by Toppr
Due to symmetry, E
y
=∫dE
y
=0, and E
x
=−∫dEsinθ=−k
e
∫
r
2
dqsinθ
where dq=λds=λrdθ; the component E
x
is negative because charge q=−750μC, causing the net electric field to be directed to the left.
E
x
=−
r
k
e
λ
0
∫
π
sinθdθ=−
r
k
e
λ
(−cosθ)∣
0
π
=−
r
2k
e
λ
where λ=
and r=
π
L
. Thus,
E
x
=−
L
2
2k
e
∣q∣π
=−
(0.140m)
2
2(8.99×10
9
N⋅m
2
/C
2
)(7.50×10
−6
C)π
E
x
=−2.16×10
7
N/C
(a) magnitude E=
2.16×10
7
N/C
The two formulas above give the Schwarzschild radius, R, of a black hole in terms of its mass, M. From Equation 1, verify Equation 2, which gives R in meters and M in kilograms, using c = 3x108 m/s for the speed of light, and G = 6.67x10-11 Newtons m2/kg2 for the gravitational constant.
Problem 2: Calculate the Schwarzschild radius, in meters, for Earth where M = 5.7 x 1024 kilograms.
Problem 3: Calculate the Schwarzschild radius, in kilometers, for the sun, where M = 1.9 x 1030 kilograms.
Problem 4: Calculate the Schwarzschild radius, in kilometers, for the entire Milky Way, with a mass of 250 billion suns.
Problem 5: Calculate the Schwarzschild radius, in meters, for a black hole with the mass of an average human being with M = 60 kilograms.
Answers
Using the formula given, the Schwarzschild radius are calculated below;
What is the Schwarzschild radius?Problem 1:
Given: R = 2GM/c² and R = 1.48 × 10⁻²⁷M
Using c = 3x10^8 m/s and G = 6.67x10^-11 Nm^2/kg^2
G = gravitational constant, c = speed of light
Substituting the values, we get:
1.48 × 10⁻²⁷M = 2GM/c²
R = 2GM/c² = (2 x 6.67x10^-11 x M)/(9x10^16)
R = 1.48 x 10^-27 M
The radius is 1.48 * 10^-27M
Problem 2:
To calculate the Schwarzschild radius, we simply need to substitute the values into the equation
Given: M = 5.7 x 10^24 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x M)/(9x10^16)
R = 8.45 * 10^-3m
Problem 3:
Given: M = 1.9 x 10^30 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x M)/(9x10^16)
R = 2816.2 kilometers
Problem 4:
Given: M = 250 billion suns = 250 x 10^9 x 1.9 x 10^30 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x 2.5 x 10^11 x 1.9 x 10^30)/(9x10^16)
R = 7.04 x 10^14 kilometers
Problem 5:
Given: M = 60 kg
Using R = 2GM/c² = (2 x 6.67x10^-11 x 60)/(9x10^16)
R = 8.9 x 10^-26 meters
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Below are some properties of candle wax (paraffin wax). Candle wax Melting point (mp)=68°C Specific heat capacity (c)=29j/g°C Specific latent heat of fusion (L) = 220j/g .Calculate the energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C.
Answers
To calculate the energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C, we need to consider two processes:
(1) raising the temperature of the wax from 20°C to 68°C
(2) melting the wax at its melting point of 68°C.
The first process requires an energy input of Q1 = mcΔT, where m is the mass of the wax (100 g), c is the specific heat capacity of the wax (29 J/g°C), and ΔT is the change in temperature (68°C - 20°C = 48°C). Thus, Q1 = (100 g)(29 J/g°C)(48°C) = 139,200 J.
The second process requires an energy input of Q2 = mL, where L is the specific latent heat of fusion of the wax (220 J/g). Thus, Q2 = (100 g)(220 J/g) = 22,000 J.
Therefore, the total energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C is Q = Q1 + Q2 = 139,200 J + 22,000 J = 161,200 J.
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