Draw a line segment with an endpoint at 1.6 and a length of 1.2

This evaluated expression is a scalar multiple of -4, which projects that vectors CD and CE are collinear. Then, points C, D, and E lie on the same straight line.

Let us proceed by  evaluating the vector CD. Then C is the midpoint of OA, we can evaluate the vector CD by subtracting vector CO from vector OD.

Vector CO = 1/2 × Vector OA
= 1/2 × (a + b)
= 1/2a + 1/2b

Vector OD = 3/4 × Vector AD
= 3/4 × (3/4a - 1/4b)
= 9/16a - 3/16b

Vector CD = Vector OD - Vector CO
= (9/16a - 3/16b) - (1/2a + 1/2b) = 5/16a - 5/16b

Then the value of the vector CE is
OB = 2BE,
we can evaluate the vector BE by dividing vector OB by 2.

Vector BE = 1/2 × Vector OB
= 1/2 × b
= 1/2b

Vector CE = Vector CO + Vector OE

Vector OE = Vector OB - Vector OE
= b - Vector BE
= b - 1/2b
= 1/2b

Vector CE = Vector CO + Vector OE
= (1/2a + 1/2b) + (1/2b)
= 1/2a + b

Then we have to show that vectors CD and CE are collinear. Two vectors are collinear if one is a scalar multiple.

CE can be expressed in terms of CD
CE / CD
= ((1/2a + b) / (5/16a - 5/16b))

Applying simplification for this expression

CE / CD
= (-8a - 8b) / (5a - 5b)

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Answer:

The data in the table represent an exponential function.

[tex]y = 2( {3}^{x} )[/tex]

We can rewrite the integrand as follows:

1 / (2 + e^x + e^(-x))

To evaluate this integral, we use the substitution u = e^x:

du/dx = e^x

dx = du/u

Substituting u and dx in terms of u into the integral, we get:

∫ (1 / (2 + u + 1/u)) du

Multiplying the numerator and denominator by u, we get:

∫ (u / (2u + u^2 + 1)) du

Next, we complete the square in the denominator:

u^2 + 2u + 1 = (u + 1)^2

So, we can write:

∫ (u / ((u + 1)^2 + 1)) du

Now, we use the substitution v = u + 1:

dv/du = 1

du = dv

Substituting v and du in terms of v into the integral, we get:

∫ ((v - 1) / (v^2 + 1)) dv

Using partial fractions, we can write:

(v - 1) / (v^2 + 1) = A(v - i) + B(v + i)

where A and B are constants to be determined, and i = sqrt(-1).

Multiplying both sides by v^2 + 1 and simplifying, we get:

v - 1 = A(v - i)(v^2 + 1) + B(v + i)(v^2 + 1)

Substituting v = i, we get:

-i - 1 = A(0) + B(2i)

B = -(i + 1)/2i = (1 - i)/2

Substituting v = -i, we get:

i - 1 = A(-2i) + B(0)

A = (1 - i)/2i = (i - 1)/2

Therefore, we have:

(v - 1) / (v^2 + 1) = [(i - 1)/(2i)](v + i) - [(1 - i)/(2i)](v - i)

Substituting back for v, we get:

(u / ((u + 1)^2 + 1)) = [(i - 1)/(2i)][(u + 1) + ie^x] - [(1 - i)/(2i)][(u + 1) - ie^x]

Substituting this expression back into the integral and simplifying, we get:

∫ (1 / (2 + e^x + e^(-x))) dx = [(i - 1)/(2i)]*ln(e^x + e^(-x) + 2) - [(1 - i)/(2i)]*ln(e^x - i) + C

where C is the constant of integration.

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Answer:

To find two numbers that add up to +29 and multiply to +100, you can use algebra. Let's call the two numbers "x" and "y". We know that:

x + y = 29

xy = 100

We can use the first equation to solve for one of the variables in terms of the other. For example, we can solve for "y" in terms of "x" by subtracting "x" from both sides:

y = 29 - x

Now we can substitute this expression for "y" into the second equation:

x(29 - x) = 100

Expanding the left-hand side of the equation gives:

29x - x^2 = 100

Rearranging and simplifying gives a quadratic equation:

x^2 - 29x + 100 = 0

This quadratic can be factored as:

(x - 4)(x - 25) = 0

So the two numbers that add up to +29 and multiply to +100 are +4 and +25.

Amy received 10 slices of pizza and Mr. Au received 45 slices of pizza.

Let's start by using variables to represent the unknown quantities in the problem. Let m be the number of slices of pizza Michael received, a be the number of slices Amy received, and au be the number of slices Mr. Au received.

We know that Miss Chang gave Michael 60 slices of pizza in total, so we can write:

m = 60

We also know that Amy received twice as many slices of pizza as Michael, so we can write:

a = 2m

Finally, we know that Mr. Au received three times the sum of what Miss Chang gave to Michael and Amy, so we can write:

au = 3(m + a)

We also know that Miss Chang gave 60 slices of pizza in total, so we can write:

m + a + au = 60

Now we can substitute the expressions we found for a and au into the last equation to get:

m + 2m + 3(m + 2m) = 60

Simplifying this equation, we get:

m + 2m + 3m + 6m = 60

12m = 60

m = 5

So Michael received 5 slices of pizza, and we can use the equations we found for a and au to determine how many slices Amy and Mr. Au received:

a = 2m = 2(5) = 10

au = 3(m + a) = 3(5 + 10) = 45

Therefore, Amy received 10 slices of pizza and Mr. Au received 45 slices of pizza.

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Jose drove the truck for approximately 213 miles.

Let's assume that Jose drove the truck for m miles.

We know that there was a base fee of $17.99, so the remaining amount after that base fee went towards the additional charge of 83 cents per mile.

So, the additional charge for the miles driven can be represented as 0.83m.

The total cost that Jose had to pay was $194.78. Therefore, we can write the equation:

17.99 + 0.83m = 194.78

Solving for m:

0.83m = 194.78 - 17.99

0.83m = 176.79

m = 213.072

So, Jose drove the truck for approximately 213 miles.

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Answer:

43.96 cm

Step-by-step explanation:

Given

Radius ( r ) = 7 cm

To find : Circumference of Circle

Formula

Circumference of Circle = 2πr

Note

The Value of π = 3.14

Circumference of Circle

= 2πr

= 2 × 3.14 × 7

= 43.96 cm

Answer:

Not Rounded: 43.9822971503

Rounded: 44

Step-by-step explanation:

r= radius

2[tex]\pi[/tex]r

2[tex]\pi[/tex](7)

= 43.9822971503

The total sum of all edges of the regular quadrilateral prism is 108 cm.

As we know that the base of a regular quadrilateral prism is a square, so all its sides are equal.

The edges of the base can be calculated as:

P = 4 × L

Each side of the base has a length of 8 cm. Then, put L=4,

P = 4 (8)

P = 32 cm

The edges of the top of the prism can be calculated as:

P = 4L

P = 4 (8)

P = 32 cm

The edges of the prism height can be calculated as:

P = 4h

P = 4 (11)

P = 44 cm

The total sum of all edges can be calculated as:

= 32 + 32 + 44

= 108 cm

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The probability that Jade gets the specific outcome you're interested in when rolling two dice is 1/6.

To find the probability that Jade gets a specific outcome when rolling two dice, we will use the sample space for rolling two dice, which consists of 36 possible outcomes (since there are 6 sides on each die, and we have 2 dice: 6 x 6 = 36).

Step 1: Determine the specific outcome you are interested in (for example, the sum of the numbers on the dice being 7).

Step 2: Count the number of ways this outcome can occur. For example, if we want a sum of 7, there are 6 possible outcomes: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

Step 3: Calculate the probability by dividing the number of successful outcomes by the total number of possible outcomes in the sample space.

In our example, there are 6 successful outcomes, and there are 36 possible outcomes in the sample space:

Probability = (Number of successful outcomes) / (Total number of possible outcomes) = 6/36

Step 4: Express the probability in its simplest form by reducing the fraction. In our example, 6/36 can be reduced to 1/6.

So, the probability that Jade gets the specific outcome you're interested in when rolling two dice is 1/6.

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The data gathering technique used by Dr. Jackson in her study of the daily activities of 4th graders is an example of a quantitative approach. This approach involves the collection of numerical data that can be analyzed using statistical methods to identify patterns and relationships.

By asking the children to indicate the amount of time they spend on different activities, Dr. Jackson is collecting quantitative data that can be used to compare and contrast the daily routines of different children. This approach is particularly useful for identifying trends and patterns in the data, such as the amount of time spent watching television or playing video games.

Quantitative data gathering techniques are commonly used in social sciences research, including education, psychology, and sociology. They are useful for identifying patterns and trends in large data sets, and can be used to make predictions about future behavior or outcomes.

Overall, Dr. Jackson's study of the daily activities of 4th graders is an example of the quantitative approach to data gathering. By collecting numerical data on the amount of time spent on different activities, Dr. Jackson can analyze the data using statistical methods to identify patterns and trends, and make predictions about future behavior or outcomes.

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Answer:

A≈166.28

Step-by-step explanation:

Answer:

A≈166.28

Step-by-step explanation:

The primary reason many present-day African nations struggled to unite their people is F. Because many African peoples have strong tribal ties.

The strong tribal identities and loyalties that exist among various ethnic groups inside African states today are one of the main causes of the effort to bring people together. Through colonisation, many African nations were developed, and many of them contained numerous groups with various cultural, linguistic, and ethnic origins.

Therefore, as a result, it has been challenging to forge a strong sense of national identity among many individuals who still identify primarily with their own tribe or ethnic group. This has occasionally resulted in disputes and hostilities amongst various diverse groups, impeding efforts to create a community that is more unified.

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Area of sector = 161.1 square inches

Activity 1:

The radius of the pizza is half of its diameter, which is 16/2 = 8 inches.

The central angle of the sector is 80%, which is 0.8 times 360 degrees = 288 degrees.

To find the area of the sector, we use the formula:

Area of sector = (central angle / 360) x πr^2

Area of sector = (288 / 360) x π x 8^2

Area of sector = (0.8) x π x 64

Area of sector = 161.1 square inches (rounded to the nearest tenth)

Activity 2:

The unit of measurement for the area of the sector is square inches (in²).

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An American in the middle 70% of cheese consumption consumes between 23.1 lbs and 41.5 lbs of cheese per year.

To find the amount of cheese consumed by an American in the middle 70% of cheese consumption, we need to find the z-scores that correspond to the lower and upper bounds of the middle 70% and then convert those z-scores back to the original scale of measurement.

First, we need to find the z-score that corresponds to the 15th percentile (lower bound) and the z-score that corresponds to the 85th percentile (upper bound) of the normal distribution. We can use a standard normal table or a calculator to find these values. Using a calculator, we get:

z_15 = invNorm(0.15) = -1.036

z_85 = invNorm(0.85) = 1.036

Next, we can use the formula:

z = (x - mu) / sigma

where x is the amount of cheese consumed by an American, mu is the mean amount of cheese consumed (32.3 lbs), and sigma is the standard deviation (8.7 lbs), to convert the z-scores back to the original scale of measurement:

For the lower bound:

-1.036 = (x - 32.3) / 8.7

x = -1.036 * 8.7 + 32.3 = 23.1 lbs

For the upper bound:

1.036 = (x - 32.3) / 8.7

x = 1.036 * 8.7 + 32.3 = 41.5 lbs

Therefore, an American in the middle 70% of cheese consumption consumes between 23.1 lbs and 41.5 lbs of cheese per year.

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The parametric equations to plot points. The sixth point is (0, 1).

The parametric equations given are:

x = sin t

y = 1 − cos t

To plot points for these equations, we can choose some values of t and substitute them in the equations to get the corresponding values of x and y. Here are some points we can plot:

When t = 0, x = sin 0 = 0 and y = 1 − cos 0 = 1.

So the first point is (0, 1).

When t = π/4, x = sin (π/4) = √2/2 and y = 1 − cos (π/4) = 1 − √2/2.

So the second point is (√2/2, 1 − √2/2).

When t = π/2, x = sin (π/2) = 1 and y = 1 − cos (π/2) = 0.

So the third point is (1, 0).

When t = π, x = sin π = 0 and y = 1 − cos π = 2.

So the fourth point is (0, 2).

When t = 3π/2, x = sin (3π/2) = −1 and y = 1 − cos (3π/2) = 0.

So the fifth point is (−1, 0).

When t = 2π, x = sin 2π = 0 and y = 1 − cos 2π = 1.

So the sixth point is (0, 1).

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The largest two digit number that is divisible by both 6 and 8 that is Dexter's number is equals to the ninty-six.

Two digit numbers : 2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99. They cannot start from zero. We have specify that Mr. Phil asks his students to determine the largest 2 -digit number that is divisible by both 6 and 8. Let the dexter's two digit number be 'x'.

From the above list of 11 numbers the largest number that is multiple of 2 and 3 both. That is 96. So, the students answer is 91. The answer of one of his student is less than 5 the correct number. Hence, required value is 96.

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To find the rate of change of the temperature difference between the two spacecraft, we need to first find the temperature at each spacecraft's position at time t=4.

For the first spacecraft, rt sin(t) = r4sin(4) and t=4, so its position is (4sin(4), 4, 0). Using the temperature function, we have T(4sin(4), 4, 0) = (4sin(4))(4)(5-2) = 48.08.

For the second spacecraft, rz cos(t) = r3cos(4) and t=-4/3, so its position is (3cos(4), -4/3, 7). Using the temperature function, we have T(3cos(4), -4/3, 7) = (3cos(4))(-4/3)(5-2) = -9.09.

Therefore, the temperature difference D between the two spacecraft at time t=4 is D = 48.08 - (-9.09) = 57.17.

To find the rate of change of D with respect to time, we use the Chain Rule. Let x = 4sin(t) and y = 4, so D = T(x, y, 0) - T(3cos(t), -4/3, 7). Then,

dD/dt = dD/dx * dx/dt + dD/dy * dy/dt

We already know that D = 48.08 - 9.09 = 57.17, so dD/dx = dT/dx = y(5-2x) = 4(5-2(4sin(4))) = -31.64.

We also have dx/dt = 4cos(4) and dy/dt = 0, since y is constant.

To find dD/dy, we take the partial derivative of T with respect to y, holding x and z constant: dT/dy = x(5-2y) = (4sin(4))(5-2(4)) = -28.16.

Putting it all together, we get:

dD/dt = dD/dx * dx/dt + dD/dy * dy/dt
= (-31.64)(4cos(4)) + (-28.16)(0)
= -126.56

Therefore, the rate of change of the temperature difference between the two spacecraft at time t=4 is -126.56.
Given the paths of the two spacecraft: r1(t) = (t sin(t), t, 0) and r2(t) = (t cos(t), -t, 7), and the temperature function T(x, y, z) = x * y * z^2, we want to determine the rate of change of the temperature difference D at time t=4 using the Chain Rule.

First, let's find the temperature for each spacecraft at time t:

T1(t) = T(r1(t)) = (t sin(t)) * t * 0^2
T1(t) = 0

T2(t) = T(r2(t)) = (t cos(t)) * (-t) * 7^2
T2(t) = -49t^2 cos(t)

Now, find the temperature difference D(t) = T2(t) - T1(t) = -49t^2 cos(t)

Next, find the derivative of D(t) with respect to t:

dD/dt = -98t cos(t) + 49t^2 sin(t)

Now, we need to evaluate dD/dt at t=4:

dD/dt(4) = -98(4) cos(4) + 49(4)^2 sin(4) ≈ -104.32

Thus, the rate of change of the temperature difference D at time t=4 is approximately -104.32 (in decimal notation, rounded to two decimal places).

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The agent should sample at least 109 two-bedroom homes to estimate the mean selling price within $10,000 with an 89.9% level of confidence.

To estimate the required sample size, we need to use the formula:

n = (Zα/2 * σ / E)²

where Zα/2 = the critical value of the standard normal distribution for the given confidence level. For an 89.9% level of confidence, the value of Zα/2 is 1.645.

σ = the population standard deviation (unknown)

E = the margin of error (maximum distance between the sample mean and the true population mean)

To estimate σ, we can use the range method, which assumes that the population standard deviation is approximately equal to the range divided by 4:

σ ≈ (highest value - lowest value) / 4

In this case, σ ≈ ($1,000,000 - $50,000) / 4 = $237,500

Substituting the values into the formula,

n = (Zα/2 * σ / E)²

n = (1.645 * $237,500 / $10,000)²

n ≈ 109

Therefore, the agent should sample at least 109 two-bedroom homes to estimate the mean selling price within $10,000 with an 89.9% level of confidence.

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The answer is reasonable because it is positive and also the equation is true . it would take Lara about 5.3 hours to clean the tank by herself.

Let's denote the time it takes for Lara to clean the tank alone as "L". We can use the formula for the combined work rate of two people, which is:

(1/7) + (1/L) = (1/3)

Multiplying both sides by the least common denominator, 21L, gives:

3L + 21 = 7L

Subtracting 3L from both sides, we get:

21 = 4L

Dividing both sides by 4, we get:

L = 5.25 hours (to the nearest tenth)

The answer is reasonable because it is positive, and it is also less than 7 hours, which is Kevin's time. When substituted back into the original equation, we get:

(1/7) + (1/5.25) = (1/3)

0.1429 + 0.1905 = 0.3333

0.3334 ≈ 0.3333

The equation is true, so the answer is reasonable. Therefore, it would take Lara about 5.3 hours to clean.

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Tricia has a total of $6.35. The answer is D.

Tricia has 10 quarters, which is equivalent to $2.50 (since 1 quarter is $0.25).

She also has 17 dimes, which is equivalent to $1.70 (since 1 dime is $0.10).

Tricia has 40 nickels, which is equivalent to $2.00 (since 1 nickel is $0.05).

Finally, she has 15 pennies, which is equivalent to $0.15 (since 1 penny is $0.01).

To find the total amount of money Tricia has, we can add up the values of each coin:

$2.50 + $1.70 + $2.00 + $0.15 = $6.35

Therefore, Tricia has a total of $6.35. The answer is option D.

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If Ali took 6 pencils from a new box of pencils and there are 18 pencils left in the box, then there were 24 pencils in the brand new box.

To see why, you can add the number of pencils Ali took to the number of pencils left in the box:

6 + 18 = 24

Therefore, there were 24 pencils in the brand new box before Ali took 6 of them.

The correct expression is 4,000 times. 1. 4 to the sixth power.

The formula for the future value of an investment with annual compounding interest is:

A = P(1 + r)ⁿ

A = future value

P = principal amount

r = annual interest rate expressed as a decimal

n = number of years.

In this case, Jaleesa deposited $4,000 at an annual interest rate of 4% (0.04 as a decimal) and the investment is compounded annually for 6 years. So the expression that can be used to find the value of her investment at the end of 6 years is:

A = 4,000(1 + 0.04)⁶

Simplifying the expression, we get:

A = 4,000(1.04)⁶

Therefore, the correct expression is 4,000 times. 1. 4 to the sixth power.

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The current ratio of length to width for US paper money is approximately 2.61 to 6.14 inches. This means that US paper money is roughly rectangular in shape, with a length that is about 2.61 times greater than its width.

The current size of US paper money is standardized by the Bureau of Engraving and Printing (BEP). According to the BEP, the current size of a US paper bill is 2.61 inches wide and 6.14 inches long. This size has remained the same since the 1920s, although earlier bills were larger.

The rectangular shape of US paper money makes it easy to handle and store, and the standardized size ensures that it can be easily recognized and processed by vending machines, bank machines, and other automated devices.

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The conclusion is YEN ≈ 63.43°.and  YN = 4√5 cm.

We can begin by drawing a diagram of the triangle LNM with the given measurements:

     N

     |\

     | \

    y|  \ x

     |   \

     |____\

     L  8cm M

Since X is the midpoint of MN, we know that MX = NX = 6/2 = 3cm. Similarly, Y is the midpoint of LN, so LY = NY = 8/2 = 4cm.

To find YN, we can use the Pythagorean theorem:

 Y________N

  |\     |

  | \    |

  |  \   | 6cm

  |   \  |

  |    \ |

 L|_____Y\|

     4cm

YN² = YL² + LN²

YN² = 4² + 8²

YN² = 80

YN = √80 = 4√5 cm

Therefore, YN = 4√5 cm.

To find YẼN, we need to find the angle YLN. Since Y is the midpoint of LN, YL is half the length of LN, which is 8cm. So YL = 4cm. We can use trigonometry to find the angle YLN:

tan(YLN) = opposite/adjacent

tan(YLN) = YL/LN

tan(YLN) = 4/8

tan(YLN) = 0.5

YLN ≈ 26.57°

Since LÑN = 90°, we know that YEN is the complement of YLN:

YEN = 90° - YLN

YEN ≈ 63.43°

Therefore, YEN ≈ 63.43°.

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The direction of fastest increase in temperature at the point (1, 3, 1) is given by the unit vector (-5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10)).

To find the direction of fastest increase in temperature at the point (1, 3, 1), we need to find the gradient of the temperature function T(x, y, z) at that point.

The gradient of a function is a vector that points in the direction of steepest increase, and its magnitude is the rate of change in that direction. So, we can find the gradient vector ∇T(x, y, z) as follows:

∇T(x, y, z) = ( ∂T/∂x , ∂T/∂y , ∂T/∂z )

=[tex]( -20xe^(-2x^2-y^2-3z^2) , -2ye^(-2x^2-y^2-3z^2) , -6ze^(-2x^2-y^2-3z^2) )[/tex]

Therefore, at the point (1, 3, 1), the gradient of T(x, y, z) is:

∇T(1, 3, 1) = [tex]( -20e^(-8) , -6e^(-8) , -18e^(-8) )[/tex]

To find the direction of fastest increase, we need to normalize this vector to a unit vector. The magnitude of the gradient vector is:

|∇T(1, 3, 1)| = sqrt( (-[tex]20e^(-8))^2 + (-6e^(-8))^2 + (-18e^(-8))^2 )[/tex]

= sqrt( 640e^(-16) )

= 8e^(-8) sqrt(10)

So, the unit vector in the direction of fastest increase is:

( -20e^(-8) / (8e^(-8) sqrt(10)) , -6e^(-8) / (8e^(-8) sqrt(10)) , -18e^(-8) / (8e^(-8) sqrt(10)) )

= ( -5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10) )

Therefore, the direction of fastest increase in temperature at the point (1, 3, 1) is given by the unit vector (-5/sqrt(10) , -3/sqrt(10) , -9/sqrt(10)).

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Answer:

f(x) = x² - 10x + 22

Step-by-step explanation:

Let's assume the quadratic polynomial as:

f(x) = ax² + bx + c

Now we know that if one of the zeroes is 5 + √3, then the other zero must be 5 - √3 (because complex roots always come in conjugate pairs).

So the sum of the zeroes will be:

(5 + √3) + (5 - √3) = 10

10 = 2 * 5

The product of the zeroes will be:

(5 + √3) * (5 - √3) = 25 - 3 = 22

Now, using the sum and product of zeroes, we can write:

b/a = 10

c/a = 22

Solving for b and c, we get:

b = -10a

c = 22a

Substituting these values in f(x), we get:

f(x) = a(x - 5 - √3)(x - 5 + √3)

Expanding the right-hand side:

f(x) = a[(x - 5)² - (√3)²]

f(x) = a(x² - 10x + 22)

Comparing the coefficients of f(x) with ax² + bx + c, we get:

a = 1, b = -10, c = 22

Therefore, the quadratic polynomial is:

f(x) = x² - 10x + 22

The equation of the line is P = 2(1.0048)ᵗ and the population in 30 years is 2.31

The equation is represented as

y = abᵗ

Where

a = y when t = 0

The points on the line are

(0, 2) and (20, 2.2)

This means that

a = 2

So, we have

y = 2bᵗ

Using the points, we have

2b²⁰ = 2.2

b²⁰ = 1.1

So, we have

b = 1.0048

This means that the equation is

P = 2(1.0048)ᵗ

Above, we have

a = 2

So, the meaning of the interpretation is that the initial population of the endangered colony is 2

Also, we have

b = 1.0048

So, the meaning of the interpretation is that the endangered colony increases by a factor of 1.0048 every year

Recall that

P = 2(1.0048)ᵗ

Here, we have

t = 30

So, the equation becomes

P = 2(1.0048)³⁰

Evaluate

P = 2.31

Hence, the population in 30 years is 2.31

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The surface area of the cylinder is 96cm²

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

Surface area of the cylinder = The area around the cylinder + 2 * The area of the top

Substitute the known values in the above equation, so, we have the following representation

Surface area of the cylinder = 64 + 2 * 16

Evaluate

Surface area of the cylinder = 96

Hence, the surface area of the cylinder is 96cm²

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The relationship between the squares formed by the sides of a right triangle is defined by Pythagorean Theorem, which states that the square on the hypotenuse side is the sum of the squares on the other two sides.

According to Pythagorean Theorem, the square formed by the side length of the hypotenuse side of right triangle is equivalent to the sum of the squares formed by the lengths of the other two sides

Let a, b, and c represent the lengths of the sides of the right triangle, where;

a = The length of the hypotenuse side

b = The length of a leg of the right triangle

c = The length of the other leg of the right triangle

The area of each squares are therefore;

Area of the square formed by the hypotenuse side = a²

Area of the square formed by the legs = b² and c²

Therefore; a² = b² + c²

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Answer:

To make the polynomial 9x^10 + ax^b + 100 a perfect square trinomial, we need to add a constant term to it such that it becomes a square of a binomial.

Let's first write the square of a binomial in general form:

(a + b)^2 = a^2 + 2ab + b^2

If we compare this general form with our polynomial, we can see that the first term, 9x^10, is equal to (3x^5)^2, which means that we can write our polynomial as:

(3x^5)^2 + ax^b + 100 = (3x^5 + c)^2

Expanding the right-hand side of this equation, we get:

(3x^5 + c)^2 = 9x^10 + 6cx^15 + c^2

Comparing the coefficient of x^15 on both sides, we get:

6c = 0

Since c cannot be zero (otherwise we would end up with the original polynomial), this means that we must have:

c = 0

Therefore, we can write our polynomial as:

(3x^5)^2 + ax^b + 100 = (3x^5)^2

Expanding the right-hand side, we get:

(3x^5)^2 = 9x^10

Therefore, we must have:

a = 0

b = 10

So the values of a and b that make the polynomial 9x^10 + ax^b + 100 a perfect square trinomial are a = 0 and b = 10.