Answer:
galaxies were moving away from us
Explanation:
i got 100% on my quiz
The speed of light is 300,000,000 m/s, what is the frequency of an x-ray that has a wavelength of .1 m? ____Hz?
Answer:
Explanation:
The speed of light is 300,000,000 m/s. Shat is the frequency of microwaves with a wavelength of 0.01 meter
13. What happens to the number of times you must rotate a screw in order to drive it into
an object when you increase the number of threads on the screw?
a. You must rotate the screw more times and apply a stronger force
b. You must rotate the screw more times but can apply a smaller force
c. You will rotate the screw less times but must apply a stronger force
d. You will rotate the screw less times and can apply a smaller force
14. What do you
hvor
Answer:
B
Explanation:
A scientist thinks that a certain chemical is a mutagen. She exposes plant cells to a large amount of this chemical in the laboratory.
Which statement best provides evidence that the substance is a mutagen?
MARKING BRAINLIEST
What is the zeroth law of black hole thermodynamics?
The zeroth law states that a simple, non-rotating black hole has uniform gravity at its event horizon. This is kind of like saying that such a black hole is at thermal equlibrium.
hope it helps...!!!
what kingdom are true bacteria in
Answer: Kingdom Monera
1
Lighting a match results in light and heat. Since energy was not created by the match, what transformation took place?
A.
Friction generated heat to release chemical energy.
B.
Light energy was generated from radiant energy.
C.
Sound energy generated heat energy.
Reset Next
Unit 7 - Post Test
© 2022 Edmentum. All rights reserved.
Answer:
The answer is A.
Explanation:
The friction generated heat to release chemical energy because the same same thing happens with fluorescent and sodium vapor lamps; heat causes the (low-pressure) mercury/sodium vapor gas lamp to cause a lot of heat energy resulting in the same thing happening when you strike a match.
Miguel is holding a 5 kg box.
How much force is the box exerting on him? In what direction?
How much force is he exerting on it? In what direction?
hope this answer helps...!!!
When trying to simplify and find the equivalent resistance you
should first simplify resistors in_before
simplifying those in_
Answer:When trying to simplify and find the equivalent resistance you
should first simplify resistors in PARALLEL before
simplifying those in SERIES
Explanation: hope this helps:)
Jeff's body contains about 5.12 L of blood that has a density of 1060 kg/m3. Approximately 45.0% (by mass) of the blood is cells and the rest is plasma. The density of blood cells is approximately 1125 kg/m3, and about 1% of the cells are white blood cells, the rest being red blood cells. The red blood cells are about 7.50m across (modeled as spheres).
What is the mass blood of the blood in Jeff's body?
blood=
Approximately how many blood cells (of both types) are in Jeff's blood?
Answer:Answer:
a) The mass of the blood is 5.788 kg
b) The total cells is 1.041x10¹³cells
Explanation:
Given:
V = volume of blood = 5.46 L = 0.00546 m³
ρ = density of blood = 1060 kg/m³
a) The mass of the blood is equal:
b) mc = mass of cells = 45% of mass of blood
mc = 0.45 * 5.788 = 2.6046 kg
ρc = density of cells = 1125kg/m³
The volume of the cells:
Vwc = volume of white blood cells = 1% of volume of the cells
Vwc = 0.01 * 0.0023 = 2.3x10⁻⁵m³
The radius of the cell is:
The volume of a single cell is:
The number of the red blood cells is:
The number of the white blood cells is:
The total cells is:
Tc = 1.031x10¹³ + 1.041x10¹¹ = 1.041x10¹³cells
Explanation: I just copied from another answer
Answer ASAP and only if you know its correct
this is science btw
Answer: It is brighter
Explanation: We are getting closer to the light because the earth is expanding.
the answer is it is brighter cause the light from the object is known as blueshift
Two boats - Boat A and Boat B - are anchored a
distance of 4.1 meters apart. The incoming water
waves force the boats to oscillate up and down,
making five complete cycles every 26.1 seconds.
When Boat A is at its peak, Boat B is at its low point.
There are never any waves between the two boats.
The vertical distance between Boat A and Boat B at
their extreme is 6.9 meters. Determine the wavelength
(in meters), frequency (in Hertz), and speed (in
meters/second) of the wave. (HINT: begin with a
diagram.)
Answer:
the wave length is 7.6 inches
Explanation:
PLS HELP! VERY URGENT! Choose three answers in the question below. I will give five stars the thanks and BRAINLIEST! I will give 50 point for this one! And brainly, this is only my assignment and its just one question.
Answer:
sawing a board in half
dissolving sugar in water
a block of ice subliming
Explanation:
Answer: Dissolving sugar in water, burning a match, and sawing a board in half
Explanation: Dissolving sugar in water is an example of a physical change. Here's why: A chemical change produces new chemical products. In order for sugar in water to be a chemical change, something new would need to result. A chemical reaction would have to occur.
When a match burns, it undergoes a chemical change. Matches use sulfur, phosphate and a friction agent held together by a binding agent. With a match, heat ignites the phosphorous on the head of the match
cutting of wood is a physical change because only physical property of wood is changed and no new substance is formed. the properties of wood remains the same. burning of wood is a chemical change as new substances are formed that is smokes and CO2. it is different from wood.
I hope this is the correct answer im pretty sure because I've finished that quiz or test already
What happens to light when it enters a lens?
Question 9 options:
It speeds up.
It is reflected.
It is refracted.
It becomes brighter.
Answer:
It is refracted.
Explanation:
Answer:
It is refracted
Explanation:
The light changes direction when it enters and exits the prism. When white light is shone through a triangular prism, a rainbow of light is seen on the opposite side of the prism.
How do I go about this?
Hi there!
(a)
Recall that:
[tex]W = F \cdot d = Fdcos\theta[/tex]
W = Work (J)
F = Force (N)
d = Displacement (m)
Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.
[tex]W =248(56)cos(30) = 12027.36 J[/tex]
To the nearest multiple of ten:
[tex]W_A = \boxed{12030 J}[/tex]
(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.
Thus:
[tex]\boxed{W_g = 0 J}[/tex]
(c)
Similarly, the normal force is perpendicular to the displacement, so:
[tex]\boxed{W_N = 0 J}[/tex]
(d)
[tex]F_{f} =\mu_k N[/tex]
In this instance, the normal force is equivalent to the downward force of gravity and the vertical component of the applied force.
[tex]N = F_g + F_A sin(30)\\\\N = mg + F_A sin(30)\\\\N = 56(9.8) + 248sin(30) = 672.8 N[/tex]
Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
[tex]W_f = -\mu_k Nd\\W_f = - (0.1)(672.8)(56) = -3767.68J[/tex]
In multiples of ten:
[tex]\boxed{W_f = -3770 J}[/tex]
(e)
Simply add up the above values of work to find the net work.
[tex]W_{net} = W_A + W_f \\\\W_{net} = 12027.36 + (-3767.68) = 8259.68 J[/tex]
Nearest multiple of ten:
[tex]\boxed{W_{net} = 8260 J}}[/tex]
(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
[tex]F_{net} = F_{Ax} - F_f[/tex]
[tex]W = F_{net} \cdot d = (F_{Ax} - F_f)[/tex]
[tex]W = (F_Acos(30) - \mu_k N)d\\W = (248cos(30) - 0.1(672.8)) * 56 \\\\W = 8259.68 J[/tex]
Nearest multiple of ten:
[tex]\boxed{W_{net} = 8260 J}[/tex]
A disk-shaped platform has a known rotational inertia. The platform is mounted on a fixed axle and rotates in a horizontal plane, as shown above. A student wishes to determine the frictional torque exerted on the platform by the axle as the platform rotates. The student has access to equipment that would usually be found in a school physics laborator
The frictional torque exerted on the platform by the axle as the platform rotates will be;
[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]
What is torque?Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.
The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.
Work done by the frictional torque = Change in the rotational kinetic energy of the wheel
[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]
Where,
[tex]\rm T_f[/tex] is the frictional torque
[tex]\rm \omega[/tex] is the final angular velocity
[tex]\rm \omega_0[/tex] is the initial angular velocity
[tex]\rm \theta[/tex] is the angular displacement
Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;
[tex]\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2][/tex]
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A current-carrying gold wire has diameter 0.88 mm. The electric field in the wire is0.55 V/m. (Assume the resistivity ofgold is 2.44 10-8 Ω · m.)
(a) What is the current carried by thewire?
1 A
(b) What is the potential difference between two points in the wire6.3 m apart?
2 V
(c) What is the resistance of a 6.3 mlength of the same wire?
3 Ω
Hi there!
a)
We know that the resistance of the wire is equivalent to:
[tex]R = \frac{\rho L}{A}[/tex]
R = Resistance (Ω)
ρ = Resistivity (Ωm)
L = Length (m)
A = Cross-sectional area (m²)
We can relate the voltage to an electric field by:
[tex]V = Ed \\\\V = El[/tex]
V = Potential Difference (V)
E = Electric Field (V/m)
l = Length of wire (m)
And Ohm's Law:
[tex]V =iR[/tex]
i = Current (A)
V = Potential Difference (V)
R = Resistance (Ω)
We do not know the length, so we can solve using the above relationships.
[tex]V = iR\\\\V = i\frac{\rho L}{A}\\\\\frac{V}{L} = E = i\frac{\rho}{A}\\\\i = \frac{EA}{\rho} = \frac{.55 \times \pi (0.00044^2)}{(2.44 \times 10^{-8})}} = \boxed{13.71 A}[/tex]
b)
We know that V = Ed (Electric field × distance), so:
[tex]V = 0.55 \times 6.3 = \boxed{3.465 V}[/tex]
c)
Calculate the resistance using the above equation.
[tex]R = \frac{\rho L}{A}\\\\R = \frac{(2.44\times 10^{-8})(6.3)}{\pi(0.044^2)} = \boxed{2.527 \times 10^{-5} \Omega}[/tex]
4. What type of assessments are based on repeatable, measurable data?
Objective assessment is the type which is based on repeatable, measurable data.
What is Objective assessment?This involves the use of unbiased and balanced observation based on verified facts.
This is verified by the use of repeatable and measurable data so as to ensure the accuracy is high in this scenario.
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List two similarities between combustion and fission
Answer:
Explanation:
Bot produce heat both produce end products that are different than the beginning products
Help me balance ittt
Answer:
CH4 + 2O2 -> CO2+2H20 Here we add 2 in front of H2O and 2 in front of O2
How to calculate Density of tetragonal unit cell by formula?
Answer:
[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
The formula of Density for a random unit cell is as follows -
[tex]Density = \frac{ Z _{effective} \times M }{N _{a} \times a {}^{3} } \\ [/tex]
where ,
★ [tex]Z _{effective}[/tex] = number of atoms in a unit cell
★ M = molar mass
★ [tex] N _{a} = Avogadro's \: Number = 6 × 10^{23}[/tex]
★ a = edge length
now ,
In a tetragonal unit cell ,
the atoms are present over the corners as well as the at the body centre.
Therefore ,
[tex]Z _{effective} = contribution \: by \: the \: 8 \: corners \: + contribution \: by \: the \: body \: centre[/tex]
[tex]\implies \: (\frac{1}{8} \times 8) \: + \: 1 \\ \\ \implies \: 1 + 1 \\ \\ \implies2[/tex]
And ,
[tex]N _{a} = 6 \times 10 {}^{23} [/tex]
Substituting the values of the following in the formula of Density , we get
[tex]\bold\purple{Density = \frac{2 \times M}{6 \times 10 {}^{23} \times a {}^{3} }} \\[/tex]
hope helpful :D
Answer ASAP and only if you know its correct
this is science btw also, brainliest to the correct answer
Answer:
the answer is B
Explanation:
its b
B. A 20kg wagon is pulled up a 30° incline at an acceleration of 2.5ms?. The force pulling the wagon is parallel to the incline and its value is 182N. Determine the value of the co-efficient of kinetic friction. [5]
The value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.
Coefficient of the kinetic frictionThe value of coefficient of kinetic friction is calculated as follows;
F - Ff = ma
F - μmgcosθ = ma
where;
F is applied forceμ is coefficient of kinetic frictionm is mass of the wagona is acceleration of the wagon182 - μ(20 x 9.8 x cos30) = 20(2.5)
182 - 169.74μ = 50
182 - 50 = 169.74μ
132 = 169.74μ
μ = 132/169.74
μ = 0.78
Thus, the value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.
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Objects in space are moving at a constant velocity in a straight line.
Which phrase tells what they do?
O always move in an orbit
O stop on their own when they run out of energy
o keep moving at a constant velocity until some force acts on them
O require constant energy to keep moving in one or more directions
Answer:
C
Explanation:
An object in motion will stay in motion unless acted on by a net positive or negative force.
For answer A. If the object were to be in an orbit, it would inevitably accelerate due to it being acted on by the gravitational force from the object it is orbiting. At different points in the orbit, the object will move at different speeds and continuously transfer between kinetic and potential energy.
For answer B. The object would would not stop their motion. In order for the object to lose energy, it would have to transfer it through friction or through its interaction with a gravitational field.
For answer D. No energy is "required" to maintain constant motion unless the object is willingly fighting against a resistive force like friction or a graviational well.
Answer ASAP and only if you know its correct
this is science btw
Answer:
jupiter
Explanation:
from the list, Jupiter is closest to the sun.
Saturn is moving with uniform angular speed of 2πf along the circumference of it's orbit around the sun with radius R, having centre O. At any time, the angular position of Saturn is (2πf)t and the displacement in SHM at that time t is given by x(t)=Rcos(2πf)t. Find it's acceleration.
Answer:Sir haymo knows
Explanation:
he gave as homework
The acceleration of the Saturn is - (2πf)²x(t).
What is Simple harmonic motion?A motion in which the restoring force is directly proportional to the body's displacement from its mean position is known as a simple harmonic motion, or SHM. This restoring force always moves in the direction of the mean position. A particle moving in simple harmonic motion accelerates as a(t) = - ω² x (t). Here, ω denotes the particle's angular velocity.
The acceleration of the particle at any position is directly proportional to the displacement from the mean position in simple harmonic motion, which is an oscillatory motion.
Given that:
at any time, the angular position of Saturn is (2πf)t.
the displacement in SHM at that time t is given by x(t)=R cos(2πf)t.
Hence, speed in SHM at that time t is given by
[tex]v(t) = \frac{dx(t)}{dt} =R \frac{d }{dt} cos(2\pi f)t = -(2\pi f) sin(2\pi f)t[/tex]
it's acceleration is
[tex]a(t) = \frac{dv(t)}{dt} =-(2\pi f) R \frac{d }{dt} sin(2\pi f)t = -(2\pi f)^2 Rcos(2\pi f)t = -(2\pi f)^2 x(t)[/tex]
hence, at any time t, the acceleration of the Saturn is - (2πf)²x(t).
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what is the time right now and why.
Answer:
Its 11:21 AM where i am
Explanation:
I d k cuz the sun is up? XD i d k
What is the voltage of the following circuit?
Answer:
v = 48
Explanation:
follow the formula v = i x r add up all the resistors an multiply it by the current
2. Anna mixes 200 g of hot coffee at 90 °C with 50 g of cold water at 3 °C to bring down the temperature of the coffee. Explain what happens to the mixture using kinetic molecular model. (3 marks)
The average kinetic energy of the molecules of the coffee will decrease and the speed of the individual molecules will also reduce.
Temperature of resultant mixtureThe temperature of the resultant mixture will be higher than the cold water temperature and lower than the hot coffee temperature.
Based on the decrease of the resulting temperature (equilibrium temperature) of the mixture, the average kinetic energy of the molecules of the coffee will decrease and the speed of the individual molecules of the hot coffee mixture will reduce, leading to a resultant cold mixture of coffee.
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a. The flow of energy from Earth's interior to the surface is about 50 terawatt (1 terawatt = 1e12 joule/sec). This is the energy that gives Earth an active surface geology (hot springs, volcanoes, plate tectonics, etc). Roughly half of this geothermal is from the energy produced by radioactive decay, and roughly half is from the energy left from the formation of the hot Earth.
Estimate how much geothermal energy reaches Earth’s surface in one day (in Joule).
b. Estimate humanity’s current consumption of energy in one day (in Joule).
c.Assuming 100% efficiency of extracting geothermal energy, estimate the ratio of geothermal energy to human's current annual world consumption of energy.
A) The amount of geothermal energy that reaches Earth's surface in one day is : 43.2 * 10¹⁷ joules
B) Humanity's current consumption of energy is; 71.4 GJ per individual.
C) Ratiois ; 60.5 * 10⁶ Joules
Given data :
Amount of energy flow = 50 terawatt = 50*10¹² joule/sec.
Determine the geothermal energy that reaches the earthSince the geothermal energy reaches the earth in a single day
Energy = power * time
Time = 24 hours ( 1 day ) = 86400 secs.
Energy = 50*10¹² joule/sec * 86400 secs
= 43.2 * 10¹⁷ joules
B) Estimating humanity's current consumption of energy in one day.Humanity's current consumption of energy in one day is estimated to be 71.4 GJ per individual.
C) Determine the ratio of geothermal energy to human's current annual consumptionGeothermal energy / human current annual consumption
= 43.2 * 10¹⁷ Joules / 71.4 * 10⁹ Jolues
= 60.5 * 10⁶ Joules
Hence we can conclude that A) The amount of geothermal energy that reaches Earth's surface in one day is : 43.2 * 10¹⁷ joules
B) Humanity's current consumption of energy is; 71.4 GJ per individual.
C) Ratiois ; 60.5 * 10⁶ Joules
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a ballon holds 24L at 45 k . find the volume if the temperature is increased to 911 k