Emily brought some homemade cookies for the school bake sale. The ingredients cost her $1.50 per cookie, but she sells them for a higher price at $3.00 per cookie. What is the percent markup per cookie?

Positive mean deviation means that the data values are on average greater than the mean, while negative mean deviation means that the data values are on average lower than the mean. This provides insight into the distribution of the data and can help identify outliers or trends in the data.

Mean deviation is a measure of dispersion that indicates how much a set of data values varies from the mean value of the data set. A positive mean deviation indicates that the data values are larger than the mean value, while a negative mean deviation indicates that the data values are smaller than the mean value.

In other words, a positive mean deviation indicates that the data set tends to be higher than the average, while a negative mean deviation indicates that the data set tends to be lower than the average.

Therefore, the sign of the mean deviation reflects the direction of deviation of the data values from the mean value, whether above or below it, and it provides important information about the distribution of the data set.

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F(x) and G(x) are polynomial functions in which the expression f(x) + g(x) is always a polynomial and f(x)/g(x) is sometimes a polynomial.

Let F(x) be a polynomial = 2x + 4

g(x) be a polynomial = 6x² + 12x

putting the value in the expression

f(x) + g(x) = 2x + 4 + 6x² + 12x

f(x) + g(x) = 6x² + 14x + 4

6x² + 14x + 4 is a polynomial

Now, putting the value in the equation

f(x)/g(x) = 2x + 4/6x² + 12x

Taking 3x common from 6x² + 12

We get 3x(3x+4)

f(x)/g(x) = 2x+4/3x(2x+4)

f(x)/g(x) = 1/3x

1/3x is not a polynomial

Hence, it sometimes a polynomial.

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(a) 1/100 (or 0.01)

(e) 0.01

This factor represents dividing the number by 100.

When Shelby multiplies 7,358.9 by a power of 10 and gets the product 73.589, we can determine the factor by comparing the two numbers.

7,358.9 → 73.589

We can see that the decimal point has moved two places to the left. Therefore, the factor is the one that will shift the decimal point two places to the left. Among the given options, the factor that does this is:

(a) 1/100 (or 0.01)

(e) 0.01

This factor represents dividing the number by 100. The other options (b, c, d, and f) do not represent the correct division by powers of 10 in this case.

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1) The discount percentage is 16.07%.

2) The discounted price of F₁, F₂ is $470,000

3) The amount that Adam had after purchasing F₁, F₂ is $530,000.

The discount percentage is a product of the discount amount divided by the original cost, multiplied by 100.

Price of item F = $280,000

Discounted price = $235,000

Discount amount = $45,000 ($280,000 - $235,000)

Discount rate = 16.07% ($45,000/$280,000 x 100)

Discounted price of F₁, F₂ = $470,000 ($235,000 x 2)

The amount that Adam had before the purchase = $1,000,000

The amount he had after purchasing F₁, F₂ = $530,000 ($1,000,000 - $470,000).

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The approximate area of the triangle is 21. 5 square units (option c).

Triangles are three-sided polygons that can have different shapes and sizes. Now, let's focus on your question about finding the area of a triangle.

To begin with, the area of a triangle is given by the formula:

Area = (base × height) ÷ 2

where the base is the length of the side that is perpendicular to the height. The height, on the other hand, is the distance between the base and the opposite vertex.

In your problem, the base of the triangle is given as 7 units, and the height is given as 6.1 units. So, we can substitute these values into the formula to get:

Area = (7 × 6.1) ÷ 2

Area = 21.35 square units

Therefore, the approximate area of the triangle is 21.35 square units. In the answer choices provided, the closest option is C, which is 21.5 square units.

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Complete Question:

What is the approximate area of the triangle when base = 7 and height = 6.1?

A. 12. 5 square units

B. 18 square units

C. 21. 5 square units

D. 31 square units

There are no other combinations to consider.

To determine the possible combinations, since Chris wants to list the thirteen states in chronological order as they continued to join the union, there is only one combination possible.

This is because the order is based on the dates the states joined, which is a fixed sequence. Here are the steps for listing the states:

1. Begin with Delaware, as it was the first state to join the union on December 17, 1787.
2. Follow with Pennsylvania, which joined on December 12.
3. Add New Jersey, which joined on December 18.
4. Continue listing the remaining ten states in the order they joined.

As the order is determined by the joining dates, there are no other combinations to consider.

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We can conclude that Arnold's height of 4.75 feet by using tangent function is not accurate based on the calculations.

To determine whether Arnold's height is accurate, we can use trigonometry and the given information about the angle of elevation and distance to the building.

Let's start by drawing a diagram to represent the situation. We have a right triangle with the opposite side being Arnold's height (h), the adjacent side being the distance to the building (300 ft), and the angle of elevation being 22 degrees.

Using the tangent function, we can write:

tan(22) = h / 300

Solving for h, we get:

h = 300 * tan(22)

Using a calculator, we find that h is approximately 122.8 feet.

Therefore, we can conclude that Arnold's height of 4.75 feet is not accurate based on the calculations. The height we calculated is over 25 times greater than Arnold's claimed height, which is not possible.

It is important to note that this assumes that Arnold's line of sight is parallel to the ground. If Arnold is on uneven ground, this could affect the calculations. Additionally, it is possible that Arnold may have misspoken about his height or the angle of elevation. However, based on the given information and calculations, we can confidently say that Arnold's claimed height is not accurate.

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Based on the equation,  the expected average number of leaves on a tree 8 weeks after spring has started would be approximately 1966.64.

To write a linear equation that can be used to approximate the data distribution, we need to use the two given points on the scatter plot. Let's assume the first point is (0, 1700) and the second point is (6, 1900).

The slope of the line passing through these points can be calculated as:

slope = (1900 - 1700) / (6 - 0) = 200 / 6 = 33.33 (approx)

Using the point-slope form of a linear equation, we can write:

y - 1700 = 33.33(x - 0)

Simplifying, we get:

y = 33.33x + 1700

Therefore, the linear equation that can be used to approximate the data distribution is: Y = 33.33x + 1700 (Option C)

To find the expected average number of leaves on a tree 8 weeks after spring has started, we need to substitute x = 8 in the above equation and solve for Y:

Y = 33.33(8) + 1700 = 1966.64 (approx)

Therefore, the expected average number of leaves on a tree 8 weeks after spring has started would be approximately 1966.64.

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The possible set of values for a, b, and c could be: a=2, b=4, c=5.

Here is a possible set of values for a, b, and c,

- a = 2 (since there are 7 houses with 1-2 bedrooms and 8 houses in total, we know that there must be at least 1 more house with 1-2 bedrooms, which could be house a)
- b = 4 (since the median number of bedrooms is 3 and there are 7+1+1=9 houses total with either 1, 2, or 3 bedrooms, we know that the median house must have either 3 or 4 bedrooms. Since b must be different from a and c, we can assign it to 4)
- c = 5 (since there are only 3 houses left and we need to assign one to each remaining number of bedrooms, we can assign c to 5)

Therefore, a possible set of values for a, b, and c could be: a=2, b=4, c=5.

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The area of the sandbox whose base is 3.5 meter and height is 2.4 meter is 4.2 m².

Given:

Base = 3.5 m

Height = 2.4 m

First, the area of the sandbox formula:

Area = 1/2 x base x height.

Next,  substitute b = 3.5 meters and h = 2.4 meters.

Area = 1/2 * (3.5) * (2.4).

Now, simplify by multiplying 1/2, 2.4, and 3.5.

Area = 1/2 x 2.4 x 3.5

Area = 4.2 square meters.

Thus, The area of the sandbox is 4.2 m².

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The question attached here seems to be incomplete, the complete question is:

Lokota wants to build a sandbox for his little brother. Determine the amount of sand he needs by finding the area of the sandbox. Use the drop-down menus to complete the statements.

First, write the formula: A = 1/2 bh
Next, use parentheses when you substitute __ for b and __ for h.

Now, simplify by ___ 1/2, 2.4, and 3.5.

The area of the sandbox is ___ m²

Point B is not the midpoint of line AC, because angle AOB is not half of angle  AOC.

If point B is the midpoint of line AC, then angle AOB must be equal to angle  BOC.

The value of angle AOC is calculated as follows;

let angle AOC = θ

cos θ = 100 yds / 500 yds

cos θ = 0.2

θ = cos⁻¹ (0.2)

θ = 78.5⁰

The value of length AC is calculated as follows;

AC = √ (500² - 100²)

AC = 489.9

If point B is the midpoint, then AB = BC = 489.9/2 = 244.95

The value of angle AOB is calculated as follows;

tan β = AB/AO

tan β = 244.95/100
tan β = 2.4495

β = arc tan (2.4495)

β = 67.8⁰

Half of angle AOC = 78.5⁰/2 = 39.25⁰

β  ≠ 39.25⁰

So point B is not midpoint of line AC, since angle AOB is not half of angle  AOC.

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The measurement of the two shorter sides in Monica's wrapping paper is 17 inches.

We can use proportions to solve this problem. Since Francisco's piece of paper is similar to Monica's piece of paper, the ratios of the corresponding sides will be equal. Specifically, we have:

17 / x = 34 / y

where x is the length of one of Francisco's shorter sides, and y is the length of one of Monica's shorter sides.

To solve for y, we can cross-multiply and simplify:

17y = 34x

y = 2x

So the length of one of Monica's shorter sides is half the length of one of her longer sides, or:

y = 1/2 * 34 = 17

Therefore, the measurement of the two shorter sides in Monica's wrapping paper is 17 inches. Answer: a. inches.

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The probability that she will select the two pink bean bags from the box on her first two attempts is approximately 2.2%.

To calculate the probability that she will select the two pink bean bags from the box on her first two attempts, we need to;
1. Determine the total number of bean bags in the box. There is one yellow, four blue, three red, and two pink bean bags, which makes a total of 1 + 4 + 3 + 2 = 10 bean bags.
2. Calculate the probability of selecting a pink bean bag on the first attempt. There are two pink bean bags out of 10, so the probability is 2/10 or 1/5.

3. After selecting one pink bean bag, there are now nine bean bags left in the box. Calculate the probability of selecting the second pink bean bag on the second attempt. Since there is only one pink bean bag left, the probability is 1/9.
4. To find the overall probability of selecting two pink bean bags in the first two attempts, multiply the probabilities from steps 2 and 3. So, the probability is (1/5) * (1/9) = 1/45.
5. Convert the fraction to a percentage by dividing the numerator by the denominator and multiplying by 100. (1/45) * 100 = 2.22% (rounded to the nearest tenth of a percent).

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The image coordinates of N′M′O′ if the preimage is translated 7 units to the left is D- N′(−11, −2), M′(−8, −1), O′ (−11, −5)

A triangle is seen as a closed, two-dimensional geometric figure that has three straight sides and three angles.

To get the image coordinates of the preimage translated 7 units to the left, we simply subtract 7 from the x-coordinates of each vertex:

N' = (Nx - 7, Ny) = (−4 - 7, −2) = (−11, −2)

M' = (Mx - 7, My) = (−1 - 7, −1) = (−8, −1)

O' = (Ox - 7, Oy) = (−4 - 7, −5) = (−11, −5)

Therefore, the image coordinates of NMO after the translation 7 are: N′(−11, −2), M′(−8, −1), O′ (−11, −5)

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The associations rhat are shown by the graph are

A graph depicting a negative linear association appears as points on the chart are concomitantly placed around a straight line that confidently descends from left to right. In simpler terms, there is a notable inverse correlation between the x and y variables, which can be best comprehended with the help of an illustration.

For instance, if one were to consider a dataset representing the age of an automobile (x) and its fuel efficiency in miles per gallon (y), a graph displaying a rigorous negative linear association implies that with an increase in the age of the car, its energy proficiency has an inclination to decrease.

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The equation of the tangent line is y = x - 1.

To find the equation of the tangent line of y=xlog(x) at the point (1,0), we will first need to find the derivative of the function y=xlog(x) with respect to x.

Step 1: Find the derivative of y=xlog(x) with respect to x.
Using the product rule, (uv)' = u'v + uv', where u=x and v=log(x).

u' = derivative of x with respect to x = 1
v' = derivative of log(x) with respect to x = 1/x

Now, apply the product rule:
y' = u'v + uv' = 1*log(x) + x*(1/x) = log(x) + 1

Step 2: Find the slope of the tangent line at the point (1,0).
Evaluate y' at x=1:
y'(1) = log(1) + 1 = 0 + 1 = 1

The slope of the tangent line at (1,0) is 1.

Step 3: Find the equation of the tangent line.
We will use the point-slope form of a linear equation: y - y1 = m(x - x1), where (x1, y1) is the point (1,0) and m is the slope (1).

y - 0 = 1(x - 1)
y = x - 1

The equation of the tangent line of y=xlog(x) at the point (1,0) is y = x - 1.

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Hence, 7 + 24 = 25 is a valid equation, and C is the correct response as the right triangle with sides of 7 inches, 25 inches, and 24 inches.

A right quadrilateral relationship between its sides is described by the Pythagorean Theorem, a fundamental theorem of geometry. According to this rule, the hypotenuse's square value, which is the side that forms the right angle, is the same as the total of the squared that compose the other two sides. In other words, the following is how the theorem can be expressed for a quadrilateral with leg of length a, b, and c and a hypotenuse of length c: [tex]a^2 + b^2 = c^2[/tex] . Although it's believed that the Greeks and romans and Indians knew about this theorem before the ancient Greek philosopher Plato, who is recognized with discovering it, gave it its name.

given

The Pythagorean Theorem's equation setup for a right triangle is as follows: [tex]a^2 + b^2 = c^2[/tex]

where c is the length of the hypotenuse and a, b, and c are the lengths of the right triangle's legs.

Right triangle with sides of 7 inches, 25 inches, and 24 inches is shown. Its legs are 7 inches and 24 inches, and its hypotenuse is 25 inches. Hence, we may construct the equation as follows:

[tex]7^2 + 24^2 = 25^2[/tex]

When we simplify this equation, we obtain:

49 + 576 = 625

625 = 625

Hence, 7 + 24 = 25 is a valid equation, and C is the correct response as the right triangle with sides of 7 inches, 25 inches, and 24 inches.

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The value of dt/dN when N = 15 is -0.00509.

We are given the equation t = 7,286.9 - 1,252 ln(N/IV) which relates the number of years t that must pass before N grams of a radioactive element remain. We want to find the rate of change of t with respect to N, i.e., dt/dN when N = 15.

We can start by taking the derivative of both sides of the equation with respect to N:

dt/dN = -1252 / (N*ln(2))

Now we can substitute N = 15 into this equation to get:

dt/dN = -1252 / (15*ln(2))

Evaluating this expression, we get dt/dN ≈ -0.00509 (rounded to 2 decimal places). Therefore, the rate of change of t with respect to N when N = 15 is approximately -0.00509 years per gram.

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The equation of the tangent line to f(x) is y = -4x + 4

The equation of the tangent line to f(x) = 1/x at a point x = a is given by:

y - f(a) = f'(a) * (x - a)

where f'(x) is the derivative of f(x) with respect to x.

We can find a "nice" point near 0.504 by choosing a = 0.5, which is close to 0.504 and makes the calculation easy.

The derivative of f(x) = 1/x is given by:

[tex]f'(x) = -1/x^2[/tex]

At x = 0.5, we have:

f(0.5) = 1/0.5 = 2

[tex]f'(0.5) = -1/(0.5)^2 = -4[/tex]

Plugging these values into the equation of the tangent line, we get:

y - 2 = -4 * (x - 0.5)

Simplifying, we get:

y = -4x + 4

Now we can use this tangent line to approximate (1/0.504) as follows:

(1/0.504) ≈ y(0.504)

Plugging x = 0.504 into the equation of the tangent line, we get:

y(0.504) = -4(0.504) + 4 = 1.784

Therefore, (1/0.504) ≈ 1.784

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The cost of each item, obtained from the equation for the sum of the costs of the item are;

A brush costs $3.5

A sketchbook costs $10.5

A paint set costs $21

An equation is a mathematical statement that expresses equivalence between two expression joined by an '=' sign.

The amount Camille brought to the art supply = $39.50

The cost of the brush = (1/3) × The cost of the sketchbook

Cost of the sketchbook = (1/2) × Cost of the paint set

Amunt Camille had left over = $4.50

The cost of the items Camille bought = $39.50 - $4.5 = $35

Let x represent the cost of the brush, let y represent the cost of the sketchbook and let z represent the cost of the paint set

Therefore, we get the following equation; x + y + z = 35

x = (1/3)·y

y = (1/2)·z

Which indicates;

x = (1/3) × (1/2)·z = (1/6)·z

From which we get; (1/6)·z + (1/2)·z + z = 35

(5/3)·z = 3

z = 35 × 3/5 = 21

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The arc length (s) for a circle with radius 4.27 meters and central angle 2.16 radians is approximately 9.22 meters.

To find the arc length (s) for a circle with radius (r) and central angle (θ), you can use the formula:

s = r * θ

In this case, the radius (r) is 4.27 meters, and the central angle (θ) is 2.16 radians. Plug these values into the formula:

s = 4.27 * 2.16

Now, multiply the values:

s ≈ 9.2232

Round the answer to two decimal places:

s ≈ 9.22 meters

So, the arc length (s) for a circle with radius 4.27 meters and central angle 2.16 radians is approximately 9.22 meters.

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The first derivative is dy/dx = [tex]-20x^3[/tex], and the second derivative is d^2y/dx^2 = -60x^2.

The function you provided is: y =[tex]-5x^4 + 1[/tex]

To find the first derivative (dy/dx), we'll use the power rule which states that if y = x^n, then dy/dx =[tex]n * x^(n-1)[/tex].

Applying this rule to each term, we get: dy/dx = [tex]d(-5x^4)/dx + d(1)/dx[/tex]dy/dx =[tex]-5(4x^(4-1)) + 0[/tex] (since the derivative of a constant is 0) dy/dx = [tex]-20x^3[/tex]

Now, to find the second derivative [tex](d^2y/dx^2)[/tex], we'll differentiate the first derivative again using the power rule: [tex]d^2y/dx^2 = d(-20x^3)/dx d^2y/dx^2 = -20(3x^(3-1)) d^2y/dx^2 = -60x^2[/tex]

So, the first derivative is dy/dx = [tex]-20x^3[/tex], and the second derivative is [tex]d^2y/dx^2 = -60x^2.[/tex]

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The testimonies of Nazi officials at the Nuremberg Trials were incredibly important because they provided valuable insight into the atrocities committed by the Nazi regime.

Their testimonies helped to dispel any claims of denial that the events of the Holocaust had occurred. The confessions given by the Nazi officials gave detailed accounts of the crimes committed by the regime, and helped to hold those responsible accountable for their actions. It is important to note that while some Nazis did receive lighter sentences because of their confessions, the vast majority of those involved were held fully responsible for their crimes. Overall, the testimonies of Nazi officials played a crucial role in bringing justice to the victims of the Holocaust and shedding light on the horrific actions of the Nazi regime.

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The derivative of y = ln[tex](9x^2-7x+4)[/tex] is y' = (18x-7) / [tex](9x^2-7x+4)[/tex].

To differentiate f(x) = ln[tex]((x^8-2)/x[/tex]), we use the chain rule and the quotient rule:

f'(x) = [[tex](x^8[/tex]-2)/x]' / (x^8-2)/x + ln[tex]((x^8-2[/tex])/x)'

[tex]= [((x^8-2)'x - (x^8-2)x') / x^2] / (x^8-2)/x + [(1/x)'(x^8-2) - (1)'x(x^8-2)/x^2][/tex]

[tex]= [(8x^7)(x) - (x^8-2)] / x^2(x^8-2)/x + [(1/x)(x^8-2)/x^2] - (1)(x^8-2)/x^2[/tex]

[tex]= [(8x^8-2-x^8+2)] / x(x^8-2) + [(x^8-2)/x^2(-x)][/tex]

[tex]= (7x^8-4) / (x^2(x^8-2)) - (x^8-2) / (x^3(x^8-2))[/tex]

Simplify to get:

[tex]f'(x) = (6x^8-4) / (x^3(x^8-2))[/tex]

Therefore, the derivative of f(x) = ln[tex]((x^8-2)/x) is f'(x) = (6x^8-4) / (x^3(x^8-2)).[/tex]

To differentiate y = ln[tex](9x^2-7x+4)[/tex], we use the chain rule:

y' =[tex][(9x^2-7x+4)' / (9x^2-7x+4)][/tex]

[tex]= [(18x-7) / (9x^2-7x+4)][/tex]

Simplify to get:

[tex]y' = (18x-7) / (9x^2-7x+4)[/tex]

Therefore, the derivative of y = [tex]ln(9x^2-7x+4) is y' = (18x-7) / (9x^2-7x+4).[/tex]

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Se puede utilizar el teorema de Pitágoras para resolver este problema. Si se considera que la altura del árbol es la hipotenusa del triángulo rectángulo,

entonces la parte superior de la parte rota del árbol es uno de los catetos, y la distancia medida sobre el piso hasta la cúspide del árbol es el otro cateto.

Por lo tanto, se tiene que:

[tex]altura^2 = cateto1^2 + cateto2^2[/tex]

Reemplazando los valores conocidos, se tiene:

[tex]altura^2 = 10^2 + 6^2[/tex]

[tex]altura^2 = 136[/tex]

Tomando la raíz altura^2 = 136, se obtiene:

[tex]altura = √136[/tex]

altura ≈ 11.66 m

Por lo tanto, la altura que tenía el árbol antes de ser roto por el viento es de aproximadamente 11.66 metros.

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The shape of the distribution  in histogram is skewed left and mean=43.071429 and standard deviation= 15.886445 are used together to measure the center and spread of the data.

What is histogram?

A grouped frequency distribution with continuous classes is graphically represented by a histogram. It is an area diagram, and its size is proportional to the frequencies in the associated classes. Due to the base's coverage of the spaces between class boundaries, all of the rectangles in such representations are contiguous.

We can make a sideways histogram. (makes it easier if typing text, but if you are writing on paper then you don't have to make it sideways) Each row will represent a range of 10 (1st row is 10 to 19, 2nd row is 20 to 29, etc)

=> 13 23 28 33 34 38 44 45 49 50 55 59 65 67

The data looks like it is slightly skewed left (hump towards the right [down]). The mean and the standard deviation are used together to measure the center and spread of the data.

Mean = [tex]\frac{ 13+23+28+33+34+38+44+45+49+50+55+59+65+67}{14}=\frac{603}{14}[/tex] = 43.071429

Standard deviation = 15.886445

Hence the shape of the distribution  in histogram is skewed left and mean=43.071429 and standard deviation= 15.886445 are used together to measure the center and spread of the data.

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The lowest possible number of balls blind man need to pick to ensure that he picked two different colors balls is equal to 48.

Number of green balls = 44

Number of blue balls = 65

Number of yellow balls = 14

Number of red balls = 2

To ensure the blind man picks two balls of different colors.

Maximum number of balls he can pick of a single color before he is guaranteed to have picked two of different colors.

All the blue and red balls have a rough surface.

All the green and yellow balls have a smooth surface.

Treat them as two distinct groups.

Let us consider the worst-case scenario,

where the blind man picks all the balls of one group before picking any ball of the other group.

Here, he could pick all 44 green balls or all 14 yellow balls before picking any blue or red ball.

Similarly, he could pick both red balls before picking any blue ball.

To ensure he has picked two balls of different colors, he needs to pick at least,

(44 green balls + 1 yellow ball) or 3 balls (2 red balls + 1 blue ball)

= 48 balls whichever is higher.

Therefore, the lowest possible number of balls he needs to pick to ensure he has picked two balls of different colors is 48.

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(A) There is only one term in the expression:[tex]-112y^2.[/tex]

(B) There are four terms in the expression[tex]: 7x^2, 5y, -9xy, and 3.[/tex]

In A option, There is only one term within the algebraic expression [tex]-112y^2.[/tex]A term is a single numerical or variable expression this is separated from other expressions through addition or subtraction.

In B option, There are 4 terms within the algebraic expression[tex]7x^2 + 5y - 9xy +[/tex] 3. A time period is a single numerical or variable expression that is separated from other expressions through addition or subtraction.

In this situation, the primary term is[tex]7x^2[/tex], the second time period is 5y, the 0.33 time period is -9xy, and the fourth term is 3.

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