The dimensions of the package of largest volume are 18 inches by 18 inches by 36 inches. The largest possible volume is 11664 cubic inches.
How we find dimension?To find the dimensions of the package of largest volume. Let the dimensions of the square end be x, and the length of the rectangular end be y. The girth of the package is 4x, and the length is y. According to the problem statement, the girth plus length may not exceed 108 inches, so we have:
4x + y = 108We want to maximize the volume V(x,y) of the package, which is given by:
[tex]V(x,y) = x^2y[/tex]We can use the equation 4x + y = 108 to express y in terms of x:
y = 108 - 4xSubstituting this into the formula for V(x,y), we get:
[tex]V(x) = x^2(108 - 4x) = 108x^2 - 4x^3[/tex]The domain of V(x) is determined by the constraints that x and y must be positive and the girth plus length may not exceed 10 inches. Since the girth is 4x, we have:
4x + y = 108 - 3x ≤ 10Solving for x, we get:
x ≤ 32/3Since x must be positive, the domain of V(x) is:
0 < x ≤ 32/3The maximum volume and the optimal dimensions
To find the absolute maximum of V(x) on the domain 0 < x ≤ 32/3, we take the derivative of V(x) with respect to x and set it equal to zero:
[tex]V'(x) = 216x - 12x^2 = 0[/tex]
Solving for x, we get:
x = 18To confirm that this is a maximum, we take the second derivative of V(x) with respect to x:
V''(x) = 216 - 24xAt x = 18, we have V''(18) = 0, which means that the second derivative test is inconclusive. However, we can see that V(x) is increasing on the interval 0 < x < 18 and decreasing on the interval 18 < x ≤ 32/3, which means that x = 18 is indeed the absolute maximum of V(x) on the domain.
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Find the value(s) of k for which u(x,t) = e¯³ᵗsin(kt) satisfies the equation uₜ = 4uxx
The two values of k that satisfy the given equation are approximately 0.1449/t and 1.096/t.
We have the partial differential equation uₜ = 4uₓₓ. Substituting u(x,t) = e¯³ᵗsin(kt) into this equation, we get:
uₜ = e¯³ᵗ(k cos(kt) - 3k sin(kt))
uₓₓ = e¯³ᵗ(-k² sin(kt))
Now, we can compute uₓₓ and uₜ and substitute these expressions back into the partial differential equation:
uₜ = 4uₓₓ
e¯³ᵗ(k cos(kt) - 3k sin(kt)) = -4k²e¯³ᵗ sin(kt)
Dividing both sides by e¯³ᵗ and sin(kt), we get:
k cos(kt) - 3k sin(kt) = -4k²
Dividing both sides by k and simplifying, we get:
tan(kt) - 1 = -4k
Letting z = kt, we can write this equation as:
tan(z) = 4z + 1
We can graph y = tan(z) and y = 4z + 1 and find their intersection points to find the values of z (and therefore k) that satisfy the equation. The first intersection point is approximately z = 0.1449, which corresponds to k ≈ 0.1449/t. The second intersection point is approximately z = 1.096, which corresponds to k ≈ 1.096/t. Therefore, the two values of k that satisfy the given equation are approximately 0.1449/t and 1.096/t.
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Peter had to solve a puzzle.which mathematical symbol can be placed between 5 and 9, to get a numbergreater than 5, but less than 9?
To get a number greater than 5,but less than 0, Peter can use the mathematical symbol of a decimal point (.) to solve this puzzle.
If Peter places decimal point between 5 and 9, he can get a number like 5.1, 5.2, 5.3... up to 8.9, which meets the conditions of being greater than 5 but less than 9.
A decimal point (.) is a mathematical symbol. When this decimal point is placed in between two numbers, suppose x and y, then x.y means x.y is greater than x and less than y.
So to solve the puzzle, Peter can use decimal point.
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An arithmetic sequence K starts 4,13. Explain how would you calculate the value of the 5,000th term
The value of the [tex]5000^{th}[/tex] term in the given arithmetic sequence K is 44995.
The sequence that is given in the question is said to be an arithmetic sequence which means the consecutive elements in the series will have common differences.
To find any term in the series first, we need to find the first term and the common difference that the series follows.
Here we know that the first and the second term of the series are 4 and 13 so from this we can find the common difference which is:
13-4=9
so the first term (a) = 4
the common difference (d) = 9
To find the [tex]n^{th}[/tex] term of the series we can use the formula:
[tex]a_n=a_1+(n-1)*d[/tex]
where [tex]a_n[/tex] is the nth term in the sequence, [tex]a_1[/tex] is the first term of the series, n is the no.of term, and d is the common difference.
So to find the 5000th term in the series
[tex]a_{5000}=4+(5000-1)*9\\a_{5000}=4+(4999*9)\\a_{5000}=4+ 44991\\a_{5000}= 44995\\[/tex]
The value of the [tex]5000^{th}[/tex] term is 44995
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A lake is to be stocked with smallmouth and largemouth bass. Let represent the number of smallmouth bass and let represent the number of largemouth bass. The weight of each fish is dependent on the population densities. After a six-month period, the weight of a single smallmouth bass is given by and the weight of a single largemouth bass is given by Assuming that no fish die during the six-month period, how many smallmouth and largemouth bass should be stocked in the lake so that the total weight of bass in the lake is a maximum
To maximize the total weight of bass in the lake, we should stock 3000 smallmouth bass and 4666.67 largemouth bass
To maximize the total weight of bass in the lake, we need to find the optimal values of and that will maximize the total weight of the fish.
Let's start by writing an expression for the total weight of the fish in the lake:
Total weight = (weight of a single smallmouth bass) × (number of smallmouth bass) + (weight of a single largemouth bass) × (number of largemouth bass)
Substituting the given expressions for the weight of a single smallmouth bass and largemouth bass, we get:
Total weight = (0.5 + 0.1) × × + (1.2 + 0.2) ×
Simplifying this expression, we get:
Total weight = (0.6) × × + (1.4) ×
To find the optimal values of and that maximize the total weight, we can take the partial derivatives of this expression with respect to and and set them equal to zero:
[tex]∂ \frac{(Total weight)}{∂} = 0.6-0.0002=0[/tex]
[tex]∂ \frac{(Total weight)}{∂} = 1.4-0.0003=0[/tex]
Solving these equations simultaneously, we get:
= 3000
= 4666.67
Therefore, to maximize the total weight of bass in the lake, we should stock 3000 smallmouth bass and 4666.67 largemouth bass.
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In triangle ABC, the length of side AB is 12 inches and the length of side BC is 20 inches. Which of the following could be the length of side AC?
Applying the triangle inequality theorem, the possible length of side AC is: C. 18 inches.
How to Determine the Length of a Triangle Using Triangle Inequality Theorem?The triangle inequality theorem states that lengths of the two sides of a triangle, when added together must be greater than the third side of any given triangle.
Therefore, to determine the possible length of side AC, we can use the triangle inequality theorem, stated above and applying this to triangle ABC, we have the following:
AC < AB + BC
AC < 12 + 20
AC < 32
This implies that, length of side AC must be less than 32 inches. Thus, the answer is: C. 18 inches.
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Can someone help me asap? It’s due today!! Show work! I will give brainliest if it’s correct and has work
Make a probability table!
The probability of choosing randomly with replacement an H or P in either selection is derived to be equal to 0.16 which makes the last option correct.
What is probabilityThe probability of an event occurring is the fraction of the number of required outcome divided by the total number of possible outcomes.
The total possible outcome = 5
the event of selecting H = 1
probability of selecting H= 1/5
the event of selecting P = 2
probability of selecting H= 2/5
probability of choosing an H or P in either selection = 1/5 × 2/5 + 2/5 × 1/5
probability of choosing an H or P in either selection = 4/25
probability of choosing an H or P in either selection = 0.16
Therefore, the probability of choosing randomly with replacement an H or P in either selection is derived to be equal to 0.16
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Plsss answer correctly and Show work for points!
Answer:
b=18.7
Step-by-step explanation:
sin112°/37=sin28°/b
b=sin28°/(sin112°/37)
b=18.7
Each letter in these following problems will be transformed into a number based on their number in the alphabet. Solve these following problems based on this information.
1) n + e
2) t-j
3) d x e
4) p/b
The solution to the problems are given below:
n + e = 14 + 5 = 19t - j = 20 - 10 = 10d x e = 4 x 5 = 20p / b = 16 / 2 = 8How to solveGiving each of the letters numbers based on their numerical position on the English alphabet, we can solve below:
n (14) + e (5) = 14 + 5 = 19
t (20) - j (10) = 20 - 10 = 10
d (4) x e (5) = 4 x 5 = 20
p (16) / b (2) = 16 / 2 = 8
It can be seen that with the letter e for example is the 5th letter of the alphabet and the value is used to compute the addition of the problem.
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a driveway consists of two rectangles one rectangle is 80 ft long and 15 ft wide the other is 30 ft long and 30 ft wide what is the area of the driveway
Answer: 2100 square feet
Step-by-step explanation:
To solve this question we must add the areas of the two rectangles.
area = length x width
Rect 1:
a = lw
= 80 x 15 = 1200 square feet
Rect 2:
a = lw
= 30 x 30 = 900 square feet
so in total, the driveway is 1200 + 900 = 2100 square feet
Answer:
To find the area of the driveway, we need to find the area of both rectangles and add them together.
The area of the first rectangle is:
80 ft x 15 ft = 1200 sq ft
The area of the second rectangle is:
30 ft x 30 ft = 900 sq ft
To find the total area of the driveway, we add the two areas together:
1200 sq ft + 900 sq ft = 2100 sq ft
Therefore, the area of the driveway is 2100 square feet.
Suppose the area of a trapezoid is 126 yd?. if the bases of the trapezoid are 17 yd and 11 yd long, what is the height?
a 4.5 yd
b. 9 yd
c. 2.25 yd
d. 18 yd
The height of the trapezoid is 9 yards. Therefore, the correct answer is option b. 9 yd.
To find the height of the trapezoid with the given area and base lengths, we will use the formula for the area of a trapezoid:
Area = (1/2) * (base1 + base2) * height
Here, the area is given as 126 square yards, base1 is 17 yards, and base2 is 11 yards. We need to find the height.
1. Substitute the given values into the formula:
126 = (1/2) * (17 + 11) * height
2. Simplify the equation:
126 = (1/2) * 28 * height
3. To isolate the height, divide both sides by (1/2) * 28:
height = 126 / ((1/2) * 28)
4. Calculate the result:
height = 126 / 14
height = 9
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can someone did this step by step correctly and not give the wrong answer
A cylinder has the net shown.
net of a cylinder with diameter of each circle labeled 3.8 inches and a rectangle with a height labeled 3 inches
What is the surface area of the cylinder in terms of π?
40.28π in2
22.80π in2
18.62π in2
15.01π in2
algebra 2 PLEASE if you know
The system of inequalities that has a solution set that is a line is [x + y ≥ 3; x + y ≤ 3]; option A
What is a system of inequalities?A system of inequalities is a set of two or more inequalities that are solved simultaneously to find the values of variables that satisfy all the inequalities in the system.
Considering the given system of inequalities:
The system of inequalities that has a solution set that is a line is:
[x + y = 3;]
This is because the solution set of this equation is a line with slope -1 passing through the point (3, 0) and (0, 3).
Therefore, the system of inequalities [x + y ≥ 3; x + y ≤ 3] has a solution set that is a line.
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All-star trinkets estimates its monthly profits using a quadratic function. the table shows the total profit as a function of the number of trinkets produced. which function can be used to model the monthly profit for x trinkets produced? f(x) = –4(x – 50)(x – 250) f(x) = (x – 50)(x – 250) f(x) = 28(x 50)(x 250) f(x) = (x 50)(x 250)
The function used to model the monthly profit for x trinkets produced are f(x) = -4(x - 50)(x - 250). The maximum profit occurs when 150 trinkets are produced.
The quadratic function that can be used to model the monthly profit for x trinkets produced is:
f(x) = -4(x - 50)(x - 250)
This is because the function is in the form of a quadratic equation, which is y = ax² + bx + c. In this case, a = -4, b = 1200, and c = 0. When we expand and simplify the equation, we get:
f(x) = -4x² + 1200x
This equation represents a parabola with a maximum value at x = 150. Therefore, the maximum profit occurs when 150 trinkets are produced.
The other answer choices are not correct because they are not quadratic functions. For example, f(x) = (x - 50)(x - 250) is a product of linear factors, and f(x) = 28(x - 50)(x + 250) and f(x) = (x + 50)(x + 250) have a coefficient of x² that is not equal to -4.
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Find the derivative of the functions and simplify:
f(x) = (x^3 - 5x)(2x-1)
The derivative of the function f(x) = (x³ - 5x)(2x-1) after simplification is 6x⁴ - 10x³ - 10x².
We apply the product rule and simplify to determine the derivative of,
f(x) = (x³ - 5x)(2x-1).
The product rule is used to determine the derivative of the given function f(x),
h(x) = a.b, then after applying product rule,
h'(x) = (a)(d/dx)(b) + (b)(d/dx)(a).
Applying this for function f,
f'(x) = 6x⁴ - 25x² - 10x³ + 15x²
f'(x) = 6x⁴ - 10x³ - 10x².
Therefore, f'(x) = 6x⁴ - 10x³ - 10x² is the derivative of f(x) after simplifying the function.
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The Rialto Theater sells balcony seats for $10 and main floor seats for
$25. One afternoon performance made $6250. The number of balcony
seats sold was 20 more than 3 times the number of main floor seats. Write
the system of equations to determine the number of main floor and
balcony seats.
The system of equations is:
Revenue from balcony seats = $10 × B
Revenue from main floor seats = $25 × M
Total revenue = $6250
B = 3M + 20
Let's define the following variables:
B = number of balcony seats sold
M = number of main floor seats sold
We know that the price of a balcony seat is $10 and the price of a main floor seat is $25.
From the given information, we can create the following equations:
The total revenue from balcony seats sold (B) is given by: Revenue from balcony seats = $10 × B
The total revenue from main floor seats sold (M) is given by: Revenue from main floor seats = $25 × M
The total revenue from the afternoon performance is $6250: Total revenue = Revenue from balcony seats + Revenue from main floor seats
The number of balcony seats sold (B) is 20 more than 3 times the number of main floor seats (M): B = 3M + 20
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Question 11
It took Fred 12 hours to travel over pack ice from one town in the Arctic to another town 360 miles
away. During the return journey, it took him 15 hours. Assume the pack ice was drifting at a constant
rate, and that Fred's snowmobile was traveling at a constants
What was the speed of Fred's snowmobile?
The speed of Fred's snowmobile was 30 miles per hour.
This is calculated by dividing the distance traveled by the time taken for each journey, which gives a speed of 30 mph for both the outward and return journeys.
To find Fred's speed, we can use the formula speed = distance/time. We know that Fred traveled a distance of 360 miles in 12 hours on the outward journey, so his speed was 360/12 = 30 mph.
Similarly, on the return journey, he traveled the same distance of 360 miles, but it took him 15 hours, so his speed was again 360/15 = 24 mph.
However, we are asked to find his constant speed, so we take the average of the two speeds, which gives us (30 + 24)/2 = 27 mph. Therefore, Fred's snowmobile was traveling at a constant speed of 30 mph on both journeys.
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Question 1 (Essay Worth 10 points)
(01. 01 MC)
Part A: A circle is the set of all points that are the same distance from one given point. Find an example that contradicts this definition. How would you change the definition to make it more accurate? (5 points)
Part B: Give an example of an undefined term and how it relates to a circle. (5 points)
Part A:
The definition provided for a circle is actually correct. However, if we change the definition slightly to say that a circle is the set of all points in a plane that are the same distance from a given point, we can find an example that contradicts it.
For instance, consider a cone in three-dimensional space. If we take a cross-section of the cone that is parallel to the base, we get a circle. However, this circle is not the set of all points that are the same distance from one given point, but rather from the axis of the cone.
To make the definition more accurate, we need to specify that the circle exists in a plane.
Part B:
An example of an undefined term related to a circle is the term "point." A circle is defined as the set of all points that are the same distance from a given point, but the term "point" is not defined within this definition.
A point is typically defined as a location in space that has no size or shape. In the context of a circle, a point can be thought of as any location on the circumference of the circle. However, it is important to note that the definition of a point is not dependent on the definition of a circle, and vice versa.
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Penny decided to travel to Palawan. The airplane flew at an average rate of 300 miles per hour and covered 1500 miles. How long will the flight will take? *
A. 3 hours
B. 4 hours
C. 5 hours
D. 6 hours
The time it will take the flight is C) 5 hours.
To solve this problem, we can use the formula: distance = rate x time. In this case, we know that the distance is 1500 miles and the rate (or speed) is 300 miles per hour. We can rearrange the formula to solve for time: time = distance / rate. Plugging in the values we have, we get:
time = 1500 miles / 300 miles per hour
time = 5 hours
Therefore, the correct answer is C. It will take Penny 5 hours to fly from her starting point to Palawan at an average speed of 300 miles per hour. This calculation assumes that the plane maintains a constant speed throughout the entire flight, which may not be the case due to factors such as wind and turbulence.
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what the root of this question?
Answer:
[tex] \sqrt{125 {p}^{2} } = p \sqrt{25} \sqrt{5} = 5p \sqrt{5} [/tex]
D is the correct answer.
A vehicle has a mass of 1295 kg and uses petrol. Another vehicle has a mass of 1290 kg and uses diesel fuel, 1L of petrol has a mass of 737g and 1L of diesel has a mass of 820g. How many litres of fuel will result in the two vehicles having the same mass? Round to the nearest tenth of a litre.
Answer:
Another vehicle has a mass of 1290 kg and uses diesel fuel. 1 L of petrol has a mass of 737 g. 1L of diesel has a mass of 820g.
True or false:
True or false cultural traits diffused from one group usually are changed or adopted over time by the people in the receiving cultural
All diffused elements of cultural are successfully integrated into other cultures
False. Cultural traits that are diffused from one group are not always changed or adopted over time by the people in the receiving culture.
This is because different cultures have their own unique values, beliefs, and practices that may not align with the diffused cultural trait. Additionally, some cultural traits may be seen as a threat to the receiving culture and therefore not adopted.
Moreover, not all diffused elements of culture are successfully integrated into other cultures. Some may be rejected outright, while others may only be partially integrated or adapted to fit the receiving culture. It's important to note that cultural diffusion is a complex and ongoing process that involves a multitude of factors, including social, economic, and political influences, as well as individual attitudes and beliefs.
Therefore, the success of cultural diffusion and integration can vary greatly from one context to another.
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An oil slick on a lake is surrounded by a floating circular containment boom. as the boom is pulled in, the circular containment area shrinks. if the radius of the area decreases at a constant rate of 7 m/min, at what rate is the containment area shrinking when the containment area has a diameter of 80m?
The containment area is shrinking at a rate of 280π m²/min when the diameter is 80m and the radius is decreasing at a constant rate of 7m/min.
What is the rate of containment area shrinkage?
Let's begin by first finding the radius of the containment area when its diameter is 80m.
The diameter of the containment area is 80m, so its radius is half of that:
[tex]r = 80m / 2 = 40m[/tex]
Now, we need to find the rate at which the containment area is shrinking when the radius is decreasing at a constant rate of 7m/min.
We can use the chain rule of differentiation to find this rate:
[tex]dA/dt = dA/dr * dr/dt[/tex]
where A is the area of the containment, t is time, r is the radius of the containment, and dA/dt and dr/dt are the rates of change of A and r with respect to time, respectively.
We know that dr/dt = -7 m/min (negative because the radius is decreasing), and we can find dA/dr by differentiating the formula for the area of a circle with respect to r:
A = π[tex]r^2[/tex]
[tex]dA/dr = 2πr[/tex]
So, when r = 40m, we have:
[tex]dA/dt = dA/dr * dr/dt[/tex]
= (2πr) * (-7)
= -280π [tex]m^2[/tex]/min
Therefore, the containment area is shrinking at a rate of 280π m^2/min when the radius is decreasing at a constant rate of 7m/min and the diameter of the containment area is 80m.
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Chord eg measures 8 inches and the distance from the center of j to the chord is 3 inches
The length of chord segment EG = 6 inches and the length of FG = √23 inches.
Given, chord EG = 8 inches and the distance from the center of J to the chord is 3 inches.
We can draw a diagram as follows:
J
/ \
/ \
/ \
/ \
E-----------G
|
|
|
|
|
F
Here, OJ is perpendicular to chord EG at point F.
As per the theorem, the length of the perpendicular from the center of the circle to a chord is half the length of the diameter intersecting the chord.
So, we can find the length of the diameter intersecting chord EG and then use it to find the radius of the circle.
Length of chord EG = 8 inches
Length of OJ = 3 inches
Using Pythagorean theorem in right triangle OFG, we get:
OG² = OF² + FG²
Let x be the length of FG
We know that OF = OJ = 3 inches
OG = radius of the circle
So, we have:
radius of circle = OG = √(OF² + FG²) = √(3² + x²)
The diameter of the circle = 2(radius) = 2√(3² + x²)
Now, using the theorem mentioned above, we can say:
Length of perpendicular from the center of the circle to chord EG = OF = 3 inches
Length of diameter intersecting chord EG = 2√(3² + x²)
So, we get:
Length of chord segment EG = 2 * length of perpendicular
= 2 * 3 inches
= 6 inches
Now, we know that the chord segment EG divides the diameter intersecting it into two equal parts.
So, we have:
Length of one part of the diameter = (2√(3² + x²))/2 = √(3² + x²)
Using Pythagorean theorem in right triangle OJF, we get:
OJ² + JF² = OF²
3² + JF² = 8²
JF² = 8² - 3² = 55
JF = √55
Using Pythagorean theorem in right triangle JFG, we get:
JG² + FG² = JF²
(√(3² + x²))² + x² = 55
9 + x² + x² = 55
2x² = 46
x² = 23
x = √23
Therefore, the length of chord segment EG = 6 inches and the length of FG = √23 inches.
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Express the volume of the sphere x^2+ y^2 + z2 < 36 that lies between the cones z = √ 3x^2 + 3y^2 and z = √(x^2+y^2)/3
The volume of the sphere that lies between the two cones is approximately 43.53 cubic units.
How to calculate the volume of the sphereTo find the volume of the sphere that lies between the given cones, we first need to determine the limits of integration.
Since the sphere has a radius of 6 (since x² + y² + z² = 36), we can use spherical coordinates to express the volume as an integral. Let's first consider the cone z = √3x² + 3y².
In spherical coordinates, this is equivalent to z = ρcos(φ)√3, where ρ is the radial distance and φ is the angle between the positive z-axis and the line connecting the origin to the point.
Similarly, the cone z = √(x²+y²)/3 can be expressed in spherical coordinates as z = ρcos(φ)/√3.
Since we're only interested in the volume of the sphere between these cones, we can integrate over the limits of ρ and φ that satisfy both inequalities.
The limits of ρ will be 0 (the origin) to 6 (the radius of the sphere).
To find the limits of φ, we need to solve for the intersection points of the two cones.
Setting the two equations equal to each other, we get:
ρcos(φ)√3 = ρcos(φ)/√3
Solving for φ, we get:
tan(φ) = 1/√3 Using the inverse tangent function, we find that: φ = π/6, 7π/6
So the limits of integration for φ will be π/6 to 7π/6.
Finally, we need to integrate over the full range of θ (the angle between the positive x-axis and the line connecting the origin to the point).
This will be 0 to 2π.
Putting it all together, the volume of the sphere between the two cones is:
∫∫∫ ρ^2sin(φ) dρ dφ dθ
With limits of integration:
0 ≤ ρ ≤ 6 π/6 ≤ φ ≤ 7π/6 0 ≤ θ ≤ 2π
Evaluating this integral gives:
V = 288π/5 - 216√3π/5
So the volume of the sphere that lies between the two cones is approximately 43.53 cubic units.
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a) Find the general solution of the differential equation dy 2.cy dar 22 +1 3 b) Find the particular solution that satisfies y(0) 2
The particular solution is [tex]y(t) = (1/2c) (t^2/2 + t/2 + 1/2c) + (2 - 1/(4c))e^(-2ct)[/tex].
[tex]dy/dt + 2cy = t^2 + 1[/tex]
To find the general solution of this differential equation, we can start by finding the integrating factor, which is given by:
I(t) = e^(∫2c dt) = [tex]e^(2ct)[/tex]
Next, we can multiply both sides of the differential equation by the integrating factor I(t):
[tex]e^(2ct) dy/dt + 2ce^(2ct) y = (t^2 + 1) e^(2ct)[/tex]
We can now recognize the left-hand side as the product rule of the derivative of the product of y and I(t):
[tex](d/dt)(y e^(2ct)) = (t^2 + 1) e^(2ct)[/tex]
Integrating both sides with respect to t gives:
[tex]y e^(2ct) = ∫(t^2 + 1) e^(2ct) dt + C[/tex]
The integral on the right-hand side can be solved using integration by parts, and we get:
∫([tex]t^2[/tex] + 1) [tex]e^(2ct) dt = (1/2c) e^(2ct) (t^2/2 + t/2 + 1/2c) + K[/tex]
where K is an arbitrary constant of integration.
Substituting this expression back into the previous equation, we get:
[tex]y e^(2ct) = (1/2c) e^(2ct) (t^2/2 + t/2 + 1/2c) + K[/tex]
Dividing both sides by e^(2ct), we obtain the general solution:
[tex]y(t) = (1/2c) (t^2/2 + t/2 + 1/2c) + Ke^(-2ct)[/tex]
where K is an arbitrary constant.
To find the particular solution that satisfies y(0) = 2, we can substitute t = 0 and y(0) = 2 into the general solution and solve for K:
[tex]y(0) = (1/2c) (0^2/2 + 0/2 + 1/2c) + Ke^(0)[/tex]
2 = 1/(4c) + K
Solving for K, we get:
K = 2 - 1/(4c)
Substituting this value of K back into the general solution, we get the particular solution:
[tex]y(t) = (1/2c) (t^2/2 + t/2 + 1/2c) + (2 - 1/(4c))e^(-2ct)[/tex]
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7. If angle GFE ~ angle CBE, find FE.
The value of FE comes out to be 35.
What is angle?An angle is a geometric figure formed by two rays or line segments that share a common endpoint, called the vertex. The measure of an angle is typically given in degrees or radians, and it describes the amount of rotation needed to move one of the rays or line segments to coincide with the other. Angles are used in many areas of mathematics, physics, engineering, and other sciences to describe and analyze various phenomena.
What is parallel line?Parallel lines have the same slope and will never meet, no matter how far they are extended. Parallel lines are important in geometry and other areas of mathematics, as well as in engineering, architecture, and other fields where precise measurements and constructions are required.
[tex]4x-1/x+5 = 60/24\\5x+25= 8x-2\\27= 3x\\x=9[/tex]
Therefore FE= 4×(9)-1
=35
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If f(x) = x2 − 6x − 4 and g(x) = 5x + 3, what is (f + g)(−3)? (1 point)
41
35
11
−35
The value of (f + g)(−3) given the functions f(x) = x² − 6x − 4 and g(x) = 5x + 3 is 11.
To find (f + g)(-3), we first need to add the functions f(x) and g(x) together, and then evaluate the resulting function at x = -3.
f(x) = x² - 6x - 4
g(x) = 5x + 3
Now, let's add f(x) and g(x):
(f + g)(x) = (x² - 6x - 4) + (5x + 3) = x² - x - 1
Now that we have the combined function, we can evaluate it at x = -3:
(f + g)(-3) = (-3)² - (-3) - 1 = 9 + 3 - 1 = 11
So, (f + g)(-3) = 11.
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Find the slope of the line through points 6,3 and 12,7
The slope of the line through points (6,3) and (12,7) is 2/3.
To find the slope of a line, we use the formula:
Slope = (y2 - y1) / (x2 - x1)
In this case, we have two points: (6, 3) and (12, 7). We can label them as follows:
x1 = 6
y1 = 3
x2 = 12
y2 = 7
Now we can plug these values into the formula:
Slope = (y2 - y1) / (x2 - x1)
Slope = (7 - 3) / (12 - 6)
Slope = 4 / 6
Slope = 2/3
Therefore, the slope of the line through the points (6, 3) and (12, 7) is 2/3.
The slope of a line tells us how steep it is. A positive slope means the line goes up as you move from left to right, while a negative slope means the line goes down. In this case, since the slope is positive (2/3), we know that the line goes up as we move from left to right.
The slope also tells us how much the y-value changes for every one unit of x-value. In this case, for every one unit we move to the right, the y-value goes up by 2/3.
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Kevin needs 2/3 of a yard to make a pillow. He has 3 1/3 yards of fabric. How many pillows can he make? A). 2 2/9 B. ) 3 2/3 C. ) 5 D. ) 6
The number of pillows requiring [tex]\frac{2}{3}[/tex] yards that can be made from [tex]3\frac{1}{3}[/tex] yards is 5. Thus the right answer to the given question is C.
Material required for making one pillow = [tex]\frac{2}{3}[/tex] yards
Total material = [tex]3\frac{1}{3}[/tex] yards
To find the number of pillows made we have to divide the material required for one pillow by the total material available to Kevin for making pillows
Number of pillows = [tex]3\frac{1}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex]
= [tex]\frac{10}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex]
To divide two fractions, we take the reciprocal of the second number and multiply it by the first number.
= [tex]\frac{10}{3}[/tex] * [tex]\frac{3}{2}[/tex]
= 5
Thus, the number of pillows made is 5.
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1⁄6 of the boys joined the basketball team and 2⁄9 of the boys joined the soccer team. How many boys are there in the soccer team? There are 540 boys
If 1/6 of the boys joined the basketball team, there are 160 boys in the soccer team.
If 1/6 of the boys joined the basketball team, then 5/6 of the boys did not join the basketball team. Similarly, if 2/9 of the boys joined the soccer team, then 7/9 of the boys did not join the soccer team.
Let's first find out how many boys did not join the soccer team:
7/9 x 540 = 380
Therefore, 380 boys did not join the soccer team.
To find out how many boys did join the soccer team, we can subtract the boys who did not join from the total number of boys:
540 - 380 = 160
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