Answers
Answer:
[tex]\sqrt{x^2+2}\left(x^2+x+2\right)^2[/tex]
Step-by-step explanation:
Given equation:
[tex](x^2+2)^{\frac{5}{2}}+2x(x^2+2)^{\frac{3}{2}}+x^2\sqrt{x^2+2}[/tex]
[tex]\textsf{Rewrite the exponents }\frac{5}{2} \textsf{ as } \left(\frac{1}{2} \cdot 5\right)\textsf{ and }\frac{3}{2} \textsf{ as }\left(\frac{1}{2} \cdot 3\right):[/tex]
[tex]\implies (x^2+2)^{\frac{1}{2} \cdot 5}+2x(x^2+2)^{\frac{1}{2}\cdot 3}+x^2\sqrt{x^2+2}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{bc}=(a^b)^c:[/tex]
[tex]\implies \left((x^2+2)^{\frac{1}{2}}\right)^5+2x\left((x^2+2)^{\frac{1}{2}}\right)^3+x^2\sqrt{x^2+2}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{\frac{1}{2}}=\sqrt{a}:[/tex]
[tex]\implies \left(\sqrt{x^2+2}\right)^5+2x\left(\sqrt{x^2+2}\right)^3+x^2\sqrt{x^2+2}[/tex]
Factor out [tex]\sqrt{x^2+2}[/tex] from each of the three terms:
[tex]\implies \sqrt{x^2+2}\left[\left(\sqrt{x^2+2}\right)^4+2x\left(\sqrt{x^2+2}\right)^2+x^2\right][/tex]
[tex]\textsf{Factor the expression in the parentheses using} \quad a^2+2ab+b^2=(a+b)^2.[/tex]
[tex]\textsf{Let }a=\left(\sqrt{x^2+2}\right)^2 \textsf {and }b=x:[/tex]
[tex]\implies \sqrt{x^2+2}\left(\left(\sqrt{x^2+2}\right)^2+x\right)^2[/tex]
[tex]\textsf{Apply exponent rule} \quad \sqrt{a^2}=a:[/tex]
[tex]\implies \sqrt{x^2+2}\left(x^2+2+x\right)^2[/tex]
[tex]\implies \sqrt{x^2+2}\left(x^2+x+2\right)^2[/tex]
Related Questions
A loptop and 3 tablets cost $810. A laptop and 1 tablet cost $630. How much does one laptop cost? How much does one tablet cost?
Answers
Answer: Tablet costs $225
Laptop costs $135
Step-by-step explanation:
Laptop is = x
Tablet = T
x + 3t = 810
x + t = 360
x = 360 - t
360 - t + 3t =810
2t = 450
t = 225
x + 225 = 360
x = 135
30 ones, 2 thousands, 4 hundred thousands, 60 tens and 100 hundreds what number am I?
Answers
Answer:
602,630
Step-by-step explanation:
Reduce answers to lowest terms 5/9 + 1/10
Answers
The answer for the given question is 59/90
A fraction is said to be in lowest terms when the greatest common factor (GCF) of the numerator and denominator is 1. Now that this is in mind, let's continue to solve.
Given, 5/9+1/10 and we have to convert or reduce it into the lowest terms.
So, let's proceed to solve this question
First add 5/9 and 1/10 i.e.,
= 5/9+1/10
Taken LCM of 9 and 10 which comes out to be 90.
Then, adding, we get
= 50+9/90
= 59/90
59/90 is already in its lowest form because the numerator and denominator have no common factor other than 1. So it's already at its most basic level.
Therefore, 59/90 is the required answer.
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through: (1,-1), slope = -3/5
Answers
Answer:
equation : 3x + 5y + 2 = 0
Step-by-step explanation:
y - y1 = m (x - x1)
y - (-1) = -3/5 ( x - 1 )
5(y + 1) = -3(x - 1)
5y + 5 = -3x + 3
3x + 5y + 2 = 0
Hi everyoneeee i just need one thing done
solve this in word form
1,900
Answers
There are two ways to say 1900 in word form.
1900 = nineteen hundred
1900 = one thousand, nine hundred
Both are equally valid.
Answer: one thousand nine hundred
Step-by-step explanation:
Does anyone understand this?
Answers
Answer: B.
Step-by-step explanation:
the goal of the question is to make <AZB ≈ (around) <AYB. Answer b is the only one that makes sense because in the first answer triangle AYB is obtuse and much wider than triangle AZB. While in answer c, triangle AYB is acute and way too small to be around triangle AZB. In answer b, the angles are around the same even though one triangle is slightly larger than the other.
What is the sum of the polynomials? Need help.
Answers
Answer:
(d) 9x² -12y² -11x
Step-by-step explanation:
The sum of polynomials (8x² -9y² -4x) and (x² -3y² -7x) is found by combining like terms.
Polynomial additionWhen simplifying the sum of polynomials, the distributive property comes into play. It lets you add and remove parentheses, recognizing that factors outside parentheses multiply each term inside parentheses.
(8x² -9y² -4x) + (x² -3y² -7x)
= 8x² -9y² -4x + x² -3y² -7x . . . . . eliminate parentheses
= (8 +1)x² +(-9 -3)y² +(-4 -7)x
= 9x² -12y² -11x
Ordered: 100mg. Available: 0.1g. How many tablets should be given? ________
Answers
Answer:
1 TABLET
Step-by-step explanation:
1 tablet should be given. The aim is to ensure that the amount of medicine you give matches what was prescribed. In order to do that, we must change either the amount we ordered or the amount that is available so that they are both measured in the same unit.
How many tablets should be given?To decide the number of tablets that ought to be given, we have to be change over the accessible sum from grams to milligrams.
Given:
Ordered: 100 mg
Available: 0.1 g
1 g = 1000 mg
Converting the available sum to milligrams:
0.1 g * 1000 mg/g = 100 mg
Since the available amount is equal to the ordered sum, you'd have to be give 1 tablet.
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Use the phrase below to answer the following questions.
The sum of -15y and 16y is −4.
Translate the phrase into an algebraic equation.
Now, use your equation to solve for y.
y =
Answers
The translation of the phrase The sum of -15y and 16y is −4 is
-15y + 16y = -4 and the value of y is -4.
What is an algebraic equation?An algebraic equation is written in the form of variables and constants and we combine these variables and constants with arithmetic operations.
In the given question there is a statement The sum of -15y and 16y is −4 and we have to express it in form of numerical and solve for y or find the value of y.
∴ The sum of -15y and 16y is −4 can be expressed numerically as,
-15y + 16y = -4.
y = -4.
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Mrs. Lin asked her students to
write a sequence with a common
ratio of 5 where a₁ is negative. Who
correctly completed the task?
KORY
-1, 5, -25, 125,
REID
-3, -15, -75,-375,..
KEISHA
-10,-5, 0, 5, 10,
ALLIE
2, 10, 50, 250,
Answers
Answer:
REID: -3, -15, -75,-375,..Step-by-step explanation:
If a GP has a positive common ratio and negative first term, it means all its terms are negative since formed by a product of positive and negative numbers.
We can only see one sequence with all negative terms and common ratio of 5, this is REID's.
Determine the amplitude or period as requested.
Amplitude of y = negative one-third sine x
a.
Negative one-third
b.
StartFraction pi Over 3 EndFraction
c.
One-third
d.
3
Answers
The amplitude of the function is 1/3
How to determine the amplitude of the function?The function is given as:
y = negative one-third sine x
Rewrite properly as
y = -1/3sin(x)
A sine function is represented as:
y = Asin(x)
And the amplitude is
Amplitude = |A|
In y = -1/3sin(x), we have
A = -1/3
So, we have
Amplitude = |-1/3|
Evaluate
Amplitude = 1/3
Hence, the amplitude of the function is 1/3
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A rectangular room is 2 times as long as it is wide, and its perimeter is 32 meters. Find the
dimension of the room.
L=?
W=?
Answers
Answer: l=32/3 meters
w=16/3 meters
Step-by-step explanation:
P=perimeter, l=length, w=width
P=2l+2w
32=2(2w)+2w
32=4w+2w
6w=32
w=32/6
w=16/3 meters
32=2l+2(16/3)
32=2l+32/3
(32=2l+32/3)*3
96=6l+32
6l=64
l=64/6
l=32/3 meters
7(4x-5) - 4(6x+5) = -91
Answers
Answer:
x = -9Step-by-step explanation:
7(4x-5) - 4(6x+5) = -91
28x - 35 - 24x -20 = -91
28x - 24x = -91 + 35 + 20
4x = -36
x = -36 : 4
x = -9
---------------
10.79 less then the product of 26 and x
Answers
Answer:
I believe it's 15.21x
Step-by-step explanation:
10.79 - 26 * x
10.79 - 26x =
15.21x
XZ is the perpendicular bisector of segment WY. Solve for k. Enter a NUMBER only.
Answers
=====================================================
Explanation:
"bisect" means to "divide in half"
So segment WY is split into two smaller equal pieces.
Segments WX and XY are the same length
WX = XY
6k+8 = 11k-12
6k-11k = -12-8
-5k = -20
k = -20/(-5)
k = 4
Distributive property 3(2x+7)
Answers
[tex] \rm\sum_{n = 0}^ \infty \bigg( - \frac{1}2 \bigg)^{n} \frac{ \Gamma ( \frac{1 + n}{2} )}{ \Gamma(1 + \frac{n}2) } \\ [/tex]
Answers
Let [tex]S[/tex] be the sum. Introduce a factor of [tex]\Gamma\left(\frac12\right)=\sqrt\pi[/tex] to rewrite the summand as a beta function integral. Then in the sum, interchange it with the integral, and [tex]S[/tex] reduces to a simple integral.
[tex]\displaystyle S = \sum_{n=0}^\infty \left(-\frac12\right)^n \frac{\Gamma\left(\frac{n+1}2\right)}{\Gamma\left(\frac n2+1\right)}[/tex]
[tex]\displaystyle . ~~ = \frac1{\sqrt\pi} \sum_{n=0}^\infty \left(-\frac12\right)^n \, \mathrm{B}\left(\frac n2+\frac12, \frac12\right) \\\\ ~~~~ = \frac1{\sqrt\pi} \sum_{n=0}^\infty \left(-\frac12\right)^n \int_0^1 \frac{t^{n/2}}{\sqrt t \sqrt{1-t}} \, dt \\\\ ~~~~ = \frac1{\sqrt\pi} \int_0^1 \frac{dt}{\sqrt t \sqrt{1-t}} \sum_{n=0}^\infty \left(-\frac{\sqrt t}2\right)^n \\\\ ~~~~ = \frac2{\sqrt\pi} \int_0^1 \frac{dt}{\sqrt t\sqrt{1-t}\left(\sqrt t+2\right)}[/tex]
Substitute [tex]u=\sqrt t+2[/tex] and [tex]du=\frac{dt}{2\sqrt t}[/tex].
[tex]\displaystyle S = \frac4{\sqrt\pi} \int_2^3 \frac{du}{u\sqrt{-(u-1)(u-3)}}[/tex]
Now substitute [tex]u=1+\frac2{1+t^2}[/tex] and [tex]du=-\frac{4t}{(1+t^2)^2}\,dt[/tex] - this comes from an Euler substitution of the form [tex]\sqrt{a(x-\alpha)(x-\beta)}=(x-\alpha)t[/tex]. [tex]S[/tex] reduces drastically to a trivial arctangent integral.
[tex]\displaystyle S = \frac8{\sqrt\pi} \int_0^1 \frac{dt}{t^2+3} \\\\ ~~~~ = \frac8{\sqrt\pi} \cdot \frac\pi{6\sqrt3} = \boxed{\frac43\sqrt{\frac\pi3}}[/tex]
One machine can seal 360 packages per hour, and an older machine can seal 140 packages per hour. How many MINUTES will the two machines working together take to seal a total of 700 packages?
Answers
Answer:
84 minutes
Step-by-step explanation:
360 per hour = 6 per min
140 per hour = 2 1/3 per min
Both together do 8 1/3 per min.
In 3 minutes, both machines together do 25 packages.
700/25 = 28.
In 3*28 minutes, which is 84 minutes, both machines together seal 700 packages.
Thanks!
change the subject. make x the subject
Answers
When the subject is changed for x, the equation is x = 1 - 1/(1 - (1/(1 - y)^2)))
How to change the subject and make x the subject?The equation is given as
x = 1 - 1/(1 - (1/(1 - y)^2)))
The question implies that we change the subject and make x the subject
However, in the equation;
The subject of the equation is x
This means that when the subject is changed for x, the equation is x = 1 - 1/(1 - (1/(1 - y)^2)))
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Find an equation of the line perpendicular to 3y=x+3 that passes through the point (5,8). Write the answer in slope-intercept form, y=mx+b, with all fractions written in the lowest terms.
Answers
Let the equation of the line perpendicular to line 3x+2y=16 is:-
2x - 3y = C. ………………(1)
Line (1) passes through the point (9,-2), therefore
2×9 - 3×(-2)= C
or, C = 24.
Thus, the required equation is:-
2x - 3y = 24.
or, 3y = 2y - 24.
or, y = (2/3).x + (-8). Answer.
3. Ages of Accountants. The average age of the accountants at Three Rivers Corp. is 25 years,
with a standard deviation of 4 years; the average salary of the accountants is $30,500, with a
standard deviation of $4500. Compare the variations of age and income.
Answers
The age of accountant is more variable than salary.
What is standard deviation ?Standard deviation is the square of difference between the sets of data and mean.
Comparison for variation of data can be determined by coefficient of variation (C.V).
We know C.V = [tex]\frac{\sigma}{|\overline{x|}}[/tex] × 100.
First we are determining C.V for ages.
Where [tex]\sigma[/tex] = standard deviation and [tex]|\overline{x}|[/tex] = arithmetic mean or average.
∴ C.V for ages, where [tex]\sigma[/tex] = 4 and [tex]|\overline{x}|[/tex] = 25 years is
C.V = [tex]\frac{4}{25}[/tex] × 100.
C.V = 16.
[tex]C.V_a_g_e[/tex] = 16%.
Now C.V for salary,
where [tex]\sigma[/tex] = 4500 and [tex]|\overline{x}|[/tex] = 30500.
C.V = [tex]\frac{4500}{30500}[/tex] × 100.
C.V = [tex]\frac{4500}{305}[/tex].
[tex]C.V_s_a_l_a_r_y =[/tex] 14.75 %.
So, the coefficient of variation of age is more than that of salary.
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I had 7 bottles and 3 friends how much will be left
Answers
The number of bottles that would be left is 1
How to determine the number of bottles that would be left?The given parameters are
Number of Bottles = 7
Number of Friends = 3
Assume that the bottles are to be shared among the friends only
The number of bottles that would be left is
Bottles left = Number of Bottles % Number of Friends
This gives
Bottles left = 7%3
Evaluate the modulo operation
Bottles left = 1
Hence, the number of bottles that would be left is 1
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A car pulls forward 35 feet in 7 seconds, and then stops and sits still for 4 seconds, and then pulls backward 21 feet in 5 seconds. a) What is the distance that the car moved in the full 16 seconds? b) What is the total displacement of the car in the full 16 seconds? c) What are the average speeds in the first, second, and third parts of the car’s motion? d) What is the car’s average speed during the full 16 seconds? e) What is the car’s average velocity during the full 16 seconds?
Answers
a) The total distance covered is 56 feet
b) The total displacement is 14 feet
c) The average speed in the first, second, and third parts of the car’s motion are; 5 feet/sec, 0 feet/sec and 4.2 feet/sec
d) The average speed of the car is 3.5 feet/sec
e) The average velocity of the car is 0.875 feet/sec
What is the displacement?We must understand that the distance is the difference between two points but the displacement is the distance between two points in a definite direction. This implies that the distance is a scalar quantity while the distance is a vector quantity. Being a vector quantity means that when we are computing the displacement that we must take into account the direction of the motion and this also applies to the calculation of the velocity of the car.
Let us now carry pout the calculations;
a) Total distance = 35 feet + 21 feet = 56 feet
b) Total displacement = 35 feet - 21 feet = 14 feet
c) Average speed of the first, second, and third parts of the car’s motion;
i) 35 feet / 7 seconds = 5 feet/sec
ii) 0 feet/sec ( it sat still)
iii) 21 feet/5 seconds = 4.2 feet/sec
d) The cars average speed = 56 feet/16 seconds = 3.5 feet/sec
e) Average velocity = 14 feet/ 16 seconds = 0.875 feet/sec
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Katherine buys eggs and apples at the store.
. She pays a total of $47.45.
. She pays a total of $6.77 for the eggs.
She buys 6 bags of apples that each cost the same amount.
Write and solve an equation which can be used to determine x, how much each bag
of apples costs.
Answers
Answer:
x = 5.94
Step-by-step explanation:
6 3/7 + 7 5/7 as a mixed number in simplest form
Answers
Answer: 14 1/7
Step-by-step explanation:
An object is moving at a speed of 360 kilometers per hour. Express this speed in miles per day. Round your answer to the nearest whole number.
Answers
We get the speed of the object as 5365 miles / day after rounding off.
We are given that an object is moving at a speed of 360 kilometers per hour.
We know that:
1 km = 0.621 miles.
So, 360 km will be:
360 km = 223.56 miles.
Also, we know that:
we have 24 hours in 1 day.
1 day = 24 hours.
1 hour = 1 / 24 day.
Re-writing the speed of the object, we get that:
223.56 miles in 1 / 24 day
That is:
5365.44 miles / day.
Rounding off:
= 5365 miles / day.
Therefore, we get the speed of the object as 5365 miles / day after rounding off.
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Someone answer this riddle in the photo
Answers
They still loose 100 dollars
Answer:
The store lost $100....
how many cubic feet water will aquarium A hold 16ft and 8ft
Answers
Answer:
128 feet
Step-by-step explanation:
8*16 is 128 feet
factor out the greatest common factor (5r-6)(r+3) - (2r-1)(r+3)
Answers
The factor (r + 3) is common. Then the greatest common factor will be (r + 3).
What is the greatest common factor?Simply said, it is the biggest common element. The highest consistent element in the above example is 15, making 15 the greatest common factor amongst 15, 30, and 105. The biggest chunk of the common factors is called the "Greatest Common Factor" (of two or more numbers).
The expression is given below.
⇒ (5r - 6)(r + 3) - (2r - 1)(r + 3)
In both terms, the factor (r + 3) is common. Then the greatest common factor will be (r + 3). Then the expression will be
⇒ (5r - 6)(r + 3) - (2r - 1)(r + 3)
⇒ [(5r - 6) - (2r - 1)](r + 3)
⇒ (3r - 5)(r + 3)
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Suppose you received a score of 91 out of 100 on exam 1. The mean was 79 and the standard deviation was 8. What score do you need on exam 2 to do equally well, if the mean is 60 and the standard deviation is 12?
Answers
You require the score of 78 to do equally well in exam 2.
To compare both the scores, we need to compute the z scores of both exams and then compare the values. The formula for z-score is:
Z = (X - μ)/σ
Where X = score obtained
μ = mean score
σ = standard deviation
For Exam 1:
Z = (91 - 79)/8
= 12/8
Z = 3/2
To perform similarly well on the second exam, let x equal z 3/2.
For Exam 2:
Z = (x - 60)/12
3/2 = (x - 60)/12
By cross multiplying we get
2(x - 60) = 12 * 3
x - 60 = 36 /2
x - 60 = 18
x = 18 + 60
x = 78
Therefore, Consequently, you must achieve a score of 78 to perform equally well in Exam 2.
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