Find cos B. a. Cosine B = StartFraction 41 Over 40 EndFraction c. Cosine B = StartFraction 40 Over 41 EndFraction b. Cosine B = StartFraction 9 Over 41 EndFraction d. Cosine B = StartFraction 9 Over 40 EndFraction

By making the financially irresponsible decision of maxing out your credit card limit, you might not have money for an emergency situation.

As, There is no foolproof technique to determine how much you can spend in excess of your credit limit, but you can go over it.

When determining the risk of accepting an over-the-limit transaction, card issuers may take into account a number of criteria, including your prior payment history.

Now, maxing out credit card leads to negative results.

So, either not have money for an emergency situation or not be able to buy the things you need.

But we can still spend after maxing out the limit.

Thus, not have money for an emergency situation is correct option.

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Answer:

Positive Association

Complementary Angles

Negative Association

Clusters in Data

Supplementary Angle

Non-linear Association

Step-by-step explanation:

Match the boxes on the left to the answers:

Positive Association

Complementary Angles

Negative Association

Clusters in Data

Supplementary Angle

Non-linear Association

Answer:

  [tex]x=-\dfrac{\sqrt{51}}{10}[/tex]

Step-by-step explanation:

You want the value of x in the third quadrant of a unit circle where y = -7/10.

The radius of a unit circle is 1, so the Pythagorean theorem tells you the magnitude of the value of x is ...

  1² = x² +(7/10)²

  x = -√(1 -49/100) = -√(51/100) . . . . . . x < 0 in the third quadrant

  x = (-√51)/10

Answer: i gotchu

Step-by-step explanation:

1) Since the base of this function is greater than 1, this means its increasing exponentially (increases from left to right).  So as x approaches positive infinity, y approaches positive infinity as well.

Domain (-∞,∞)   Range (0,∞)

2) If the base changes to 1/9 the function would decrease. So as x approaches positive infinity, y approaches 0 (Check attached screenshot)

3) The "+5" raises the horizontal asymptote up 5 units. So the new equation for the horizontal asymptote is y=5.

The "x-2" shifts the x values to the right by 2 units.

u dont have to pay me, i literally just learned this like a month ago :)

The sum expression [tex][2(4 + \frac9n)^4](\frac9n) + ... + [2(4 + \frac{9n}n)^4](\frac9n)[/tex] using the sigma notation is [tex]\sum\limits^{n}_{i=1} [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

From the question, we have the following parameters that can be used in our computation:

[tex][2(4 + \frac9n)^4](\frac9n) + ... + [2(4 + \frac{9n}n)^4](\frac9n)[/tex]

From the above expression, we can see that the different expression in each term is

9/n

So, we introduce a variable

Assuming the variable is i, the i-th term of the expression would be[tex]t(i) = [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

When represented using the sigma notation, we have

[tex]\sum\limits^{n}_{i=1} [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

Hence, the sum expression using the sigma notation is [tex]\sum\limits^{n}_{i=1} [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

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The probability that the first roll is a total of at least 5 and the second roll is a total of at least 4  is 0.764 or 76.4%.

The probability is the chance that an expected event occurs out of many possible events.

For two independent events happening, we use the rule of multiplication of independent events based on dice probabilities.

The event that the first roll is a total of at least 5 = A

In the event that the second roll is a total of at least 4 = B

The number of faces on each die, n = 6

The probability of event A = ³⁰/₆ = ⁵/₆

The probability of event B = ³³/₃₆ = ¹¹/₁₂

Multiplying the two probabilities, P(A) and P(B) = ⁵/₆ ​× ¹¹/₁₂

= ⁵⁵/₇₂ = 0.764

Thus, there is a ⁵⁵/₇₂ or 0.764 chance that the first roll is at least 5 and the second roll is at least 4.

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Answer: A

Step-by-step explanation:

A dilation is not a rigid transformation, which means it has to scale the object into a different measure. So, enlarging or reducing the size of an object is a dilation.

The tangent secant exterior angle measure theorem indicates that the measure of the arc DG, m[tex]\widehat{DG}[/tex] is 85°, the correct option is the option B.

B. m[tex]\widehat{DG}[/tex] = 85°

The tangent secant exterior angles theorem states that if two secant or tangent or a secant and tangent intersect on the exterior to a circle, the measure of the angle formed is half the difference of the arcs they intercept.

The possible options in the question indicates that the possible drawing in the consists of a tangent and a secant, with the angle m∠DBG, being external to the circle.

The tangent secant exterior angle measure theorem indicates that we get;

m∠DBG = (1/2) × (m[tex]\widehat{GFE}[/tex] - m[tex]\widehat{DG}[/tex])

The question indicates; m[tex]\widehat{GFE}[/tex] = 149°

m∠DBG = 32°

Therefore;

32 = (1/2) × (149° - m[tex]\widehat{DG}[/tex])

149° - m[tex]\widehat{DG}[/tex] = 2 × 32° = 64°

m[tex]\widehat{DG}[/tex] = 149° - 64° = 85°

The measure of the arc DG, m[tex]\widehat{DG}[/tex] is 85°

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Sum

Mean = (4.1 + 3.2 + 2.8 + 2.6 + 3.7 + 3.1 + 9.4 + 2.5 + 3.5 + 3.8) / 10

Mean = 36.7 / 10

Mean = 3.67

To find the median, we need to put the values in order:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4

The middle number is the median, which is 3.35 in this case (3.2+3.5)/2.

To find the mode, we look for the value that appears most often. In this case, there is no mode as no value appears more than once.

To find the first quartile (Q1), we need to find the value that separates the bottom 25% of the data from the top 75%. We can do this by finding the median of the lower half of the data:

2.5, 2.6, 2.8, 3.1, 3.2

The median of this lower half is 2.8, so Q1 = 2.8.

To find the third quartile (Q3), we need to find the value that separates the bottom 75% of the data from the top 25%. We can do this by finding the median of the upper half of the data:

3.7, 3.8, 4.1, 9.4

The median of this upper half is 3.95, so Q3 = 3.95.

To find the outlier, we can use the rule that any value more than 1.5 times the interquartile range (IQR) away from the nearest quartile is considered an outlier. The IQR is the difference between Q3 and Q1:

IQR = Q3 - Q1

IQR = 3.95 - 2.8

IQR = 1.15

1.5 times the IQR is 1.5 * 1.15 = 1.725.

The only value that is more than 1.725 away from either Q1 or Q3 is 9.4. Therefore, 9.4 is the outlier in this data set.

Answer:

Step-by-step explanation:

Mean is the average of the data vales : 38.7 (sum of all values) divided by 10 (the number of values).  Mean = 38.7/10 = 3.87

Median is the "middle" number" = put the date in order and find the middle value:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4, since there is no middle data value, find the average of the 2 in the middle.

3.2 + 3.5/2 = 6.7 ÷ 2 = 3.35 - median

All values appear once so there is no mode.

First quartile is the middle of the lower set of data = 2.8

Third quartile is the middle of the upper set = 3.8

The outlier is 9.4.

How to calculate the outlier:

First you need the IQR which is the diffence of Q3 - Q1,

so the IQR is 3.8- 2.8 = 1

Outliers are the quartile + or - (1.5)(IQR)

Q1 -(1.5)(1) = 2.8 - 1.5 = 1.3

Q3 - (1.5)(1)= 3.8 + 1.5 =4.5

So anything below 1.3 or above 4.5 is an outlier.

There is one 9.4

Step-by-step explanation:

This is a right triangle , so the Pythagorean theorem applies

c^2 = a ^2 + b^2        c  is the hypotenuse   a and b are the legs

15^2 = 9^2 + x^2

15^2 - 9^2 = X^2

x  = 12 ft

Answer:

[tex]sec(-\theta)=-3.1[/tex]

[tex]sin(-\theta)=-0.62[/tex]

Step-by-step explanation:

Part a.

[tex]sec(\theta)[/tex] is related to [tex]cos(\theta)[/tex] through a reciprocal relationship [tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex].

Since [tex]cos(\theta)[/tex] is an even function (reflecting left-right across the y-axis doesn't change the graph), then [tex]sec(\theta)[/tex] is also an even function.

For any input in the domain, even functions produce the same output if the opposite of the input is used.  In other words, if "f" is an even function, for all x in the domain of f, [tex]f(x)=f(-x)[/tex].

Thus, for the secant function, if a mystery value "x" is used as an input, and -3.1 is obtained as an output, then if the opposite of x, or -x, is input into the secant function, the output will also be -3.1.

[tex]sec(-\theta)=-3.1[/tex]

Part b.

The [tex]sin(\theta)[/tex] function does not reflect left-right across the y-axis to produce the same graph, so the sine function is not even.

However, the sine function can be rotated 180 degree about the origin, sometimes thought of as reflecting through the origin, to produce the same graph.  Visually, this is an "odd" function.

For any input in the domain, if the opposite of the input is used, odd functions produce the opposite of the original output.  In other words, if "g" is an odd function, for all x in the domain of g, [tex]-g(x)=g(-x)[/tex].

Thus, for the sine function, if a mystery value "x" is used as an input, and 0.62 is obtained as an output, then if the opposite of x, or -x, is input into the sine function, the output will be the opposite of 0.62, meaning -0.62.

[tex]sin(-\theta)=-0.62[/tex]

Answer:

Let the width of the rectangle be w. Then the length of the rectangle is 5w.

The perimeter of a rectangle is the sum of all four sides. So, the perimeter of the rectangle is 2w+2(5w)=108 cm.

Simplifying the right side of the equation, we get 12w=108 cm.

Dividing both sides of the equation by 12, we get w=9 cm.

Since the width is 9 cm, the length of the rectangle is 5w=5(9)=45 cm.

Therefore, the length of the rectangle is 45 cm and the width is 9 cm.

We can conclude that there is significant evidence that the number of complaints received by Lara music store is different from number of complaints received by music stores in general.

Here, we have,

H0 : μ ≥ 6

H1 : μ < 6

Test statistic :

n = 20

Sample Mean, x = 3

σ = 1.5

Test statistic = (x - μ) ÷ σ/sqrt(n)

Test statistic = (3 - 6) ÷ 1.5/sqrt(20)

Test statistic = - 3 / 0.3354101

Test statistic = −8.944271

Since, sample size is < 30 ;

Obtaining the Critical value using the from T;

Tcritical at 0.05, df = 19 = - 1.729

Tstatistic < Tcritical

−8.944271 < - 1.729

Hence, we reject the Null:

We can conclude that there is significant evidence that the number of complaints received by Lara music store is different from number of complaints received by music stores in general.

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Here is the data collected as a result of the experiment.
1) Numerical order is: 0.20, 0.20, 0.46, 0.46, 2.10, 2.10, 5.50, 11.80, 12.20, 12.20, 13.22, 14.65, 16.07, 17.49, 18.91, 20.33, 20.50, 20.50, 21.75, 23.18

2)  The data represents rainfall in millimeters over a 20-day period.

3) Mean = 11.69 mm.

4) The minimum rainfall is 0.20 mm ;

the maximum is 23.18 mm.

1) The data is listed as follows.

2) The data represents the amount of rainfall in millimeters over a 20 day period.

3) The mean rainfall over the 20 day period is 11.69 mm.

= (0.20 + 0.20 + 0.46 + 0.46 + 2.10 + 2.10 + 5.50 + 11.80 + 12.20 + 12.20 + 13.22 + 14.65 + 16.07 + 17.49 + 18.91 + 20.33 + 20.50 + 20.50 + 21.75 + 23.18) /20

Mean (x)  = 11.69 mm.

3) The minimum rainfall is 0.20 mm and the maximum is 23.18 mm.

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The calculated value of the length RP is 107 units

From the question, we have the following parameters that can be used in our computation:

The circles and the tangent lines

Start by calculating the segment PQ using the following Pythagoras theorem

PQ² = (50 + 11)² + 11²

Evaluate

PQ² = 3842

So, we have

PQ = 62

The value of the length RP is then calculated as

RP = PQ + TU

So, we hav

RP = 62 + 45

Evaluate

RP = 107

Hence, the value of the length RP is 107 units

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The correct numbers for Derrek and Thomas' football teams are :

According to the information given, Thomas's football team lost 3 yards in their first drive, which means they moved backward 3 yards from the line of scrimmage. This can be represented as -3 on the number line.

On the other hand, Derrek's football team gained 5 yards in their first drive, which means they moved forward 5 yards from the line of scrimmage. This can be represented as +5 on the number line.

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Step-by-step explanation:

The constant of proportionality is just the slope of the line

using 0,0   and  3,2   points

slope = (y1-y2 ) / ( x1-x2) = (0-3) / ( 0-2) = 3/2 = constant of proportionality

The area of the shaded region is 51.75 in².

From the figure

Radius of semicircle = √25² - 20²

                                  =√625-  400 = 15 inch

Now, Area of Trapezium = 1/02 ( a +b ) h

= 1/2 (17 + 37) x 15

= 1/2 (54) x 15

= 27 x 15

= 405 in²

Then, Area of Shaded region

= Area of Trapezium -  Area of semicircle

= (405 - πr²)

= 405 - 353.25

= 51.75 in²

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The weights of the debt, preferred stock, and common equity financing are 28.6%, 30.4%, and 41.0%, respectively.

To calculate the weighted cost of capital (WACC), the proportion of each component of capital structure is needed. The weight of each component of the capital structure is determined by dividing the market value of the component by the total market value of all the components of the capital structure.

In this case, the total market value of the company's capital structure is the sum of the market value of debt, preferred stock, and common equity.

The weights for each component are calculated as follows:

Weight of debt = Market value of debt / Total market value of capital structure

= $3.3 million / ($3.3 million + $3.5 million + $4.3 million)

= 0.286 or 28.6%

Weight of preferred stock = Market value of preferred stock / Total market value of capital structure

= $3.5 million / ($3.3 million + $3.5 million + $4.3 million)

= 0.304 or 30.4%

Weight of common equity = Market value of common equity / Total market value of capital structure

= $4.3 million / ($3.3 million + $3.5 million + $4.3 million)

= 0.410 or 41.0%

These weights can be used to calculate the weighted cost of capital for Romero Company.

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Answer: First, let's convert the room's dimensions from feet to yards, since the carpet cost is given per square yard:

17 feet = 5.67 yards (rounded to two decimal places)

16 feet = 5.33 yards (rounded to two decimal places)

Next, we can calculate the area of the room in square yards by multiplying these values:

Area = 5.67 yards × 5.33 yards = 30.23 square yards (rounded to two decimal places)

Finally, we can multiply the area by the cost per square yard to get the total cost:

Total cost = 30.23 square yards × $101/square yard = $3,056.23 (rounded to two decimal places)

Therefore, it will cost $3,056.23 to carpet the room.

The function shows that the chairs and sofas the manufacturer should produce to earn that profit is C. (6, 12) P= 1,260

The profit function is P = 50x + 80y.

In order to find the optimal production quantities that will maximize the profit function, we need to determine which vertex yields the highest profit.

From the given vertices, we can see that the profit at (0,0) is 0. The profit at (0,15) is 1,200, and the profit at (6,12) is 1,260.

Therefore, the manufacturer should produce 6 chairs and 12 sofas to earn a profit of 1,260.

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Answer:

the temperature at 7 am was -36.7 degrees.

Step-by-step explanation:

Let's denote the temperature at 7 am by "x". Since the temperature increased by 8.4 C between 7 am and 11 am, we can set up the equation:

x + 8.4 = -28.3

Subtracting 8.4 from both sides, we get:

x = -36.7

Therefore, the temperature at 7 am was -36.7 degrees.

Answer:

C

Step-by-step explanation:

if the mean and median are the same, the graph will be symmetrical

The graph of the piecewise function is given by the image presented at the end of the answer.

A piece-wise function is a function that has different definitions, depending on the input of the function.

All the five definitions of the function in this problem are constant, hence the graph will be composed by horizontal lines.

The definitions are given as follows:

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Answer:10.66 years. Punch again to double check

Step-by-step explanation:

A=Pe^(rt)

11700=5850e^(.065t)

isolate the variable expression

2=e^(.065t) divide by 5850

ln2=lne^(.065t) take the natural log of both sides

ln2=.065t. Bring down the power, lne equals

t is about 10.66 years. Divide ln2 by .065

Answer:

It is called as triangular numbers

Step-by-step explanation:

these numbers can be represented as a triangle of dots

The sales 12 weeks after release is $586,000 . Option A is the correct answer.

To create a table of values, we can plug in different values of t and find the corresponding values of s:

t s

0 10

1 19.882

2 26.248

3 31.177

4 35.064

5 38.185

6 40.731

7 42.837

8 44.6

9 46.095

10 47.384

11 48.508

12 49.498

To graph the function, we can plot the values from the table on a coordinate plane. The horizontal axis represents time in weeks, and the vertical axis represents sales in thousands of units. The resulting graph is a curve that starts at (0,10) and increases as t increases.

To estimate the sales 12 weeks after release, we can look at the graph and see that the corresponding value of s is around 49.5 thousand units. Therefore, the answer is about $586,000 (49.5 x 1000 x 12). Option A is the correct answer.

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Answer:

c=12.04

Explanation:

You can use the formula given: c=√a^2+b^2

c=√8^2+9^2=√64+81=√145=12.04

The minimum grade you need to get a B in the course is given as follows:

x = 80.625.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations, which is also called the cardinality of the data-set.

The grades and their percentages are given as follows:

You want a grade of 80, hence the minimum test average is obtained as follows:

0.15 x 73 + 0.2 x 79 + 0.25 x 84 + 0.4x = 80

47.75 + 0.4x = 80

x = (80 - 47.75)/0.4

x = 80.625.

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The length of the third side is 8units

Pythagoras theorem states that : the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.

If a and b are the legs of the triangle and c is the hypotenuse,then

c² = a²+b²

For example , if a = 3 and b = 4 , then

c = √3²+4²

c = √ 9+16

c = √25

c = 5units.

Similarly, c = 10, a= 6, and b is unknown

therefore

10²= 6²+b²

b² = 10²-6²

b² = 100-36

b² = 64

b = √64

b = 8units

therefore the length of the third leg is 8units.

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