Find the area of the composite figure to the nearest hundredth. Find the area total area = ________ mm²

To evaluate the line integral JF.dr, where F = (-2 sin x, 2 cos y, 6zx) and C is the path given by r(t) = (3t^3, -3t^2, -3t) for 0 <= t <= 1, we first need to parameterize F and r in terms of t.

For F, we have:

F = (-2 sin x, 2 cos y, 6zx) = (-2 sin (3t^3), 2 cos (-3t^2), 6(3t^3)(-3t)) = (-2 sin (3t^3), 2 cos (3t^2), -54t^4)

For r, we already have the parameterization:

r(t) = (3t^3, -3t^2, -3t)

Now we can use the formula for the line integral:

JF.dr = ∫(F dot dr)

= ∫(-2 sin (3t^3) dx + 2 cos (3t^2) dy - 54t^4 dz)

= ∫(-18t^2 cos (3t^2) + 18t^2 cos (3t^2) - 54t^4) dt

= ∫(-54t^4) dt

= -9t^5 + C

Evaluating this expression for t = 1 and t = 0, we get:

JF.dr = (-9(1)^5 + C) - (-9(0)^5 + C)

= -9 + 9

= 0

Therefore, the line integral JF.dr evaluated along the path given by r(t) = (3t^3, -3t^2, -3t) for 0 <= t <= 1 is equal to 0.

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The composite function fg(x) is a linear function​ by the proof shown below

From the question, we have the following parameters that can be used in our computation:

f(x) = 2x - 1

g(x) = -x + 3

The above functions are linear functions

This means that the function fg(x) will also be a linear function​

To prove this, we have

f(g(x)) = 2(g(x)) - 1

substitute the known values in the above equation, so, we have the following representation

f(g(x)) = 2(-x + 3) - 1

So, we have

f(g(x)) = -2x - 7

Hence, the function is a linear function

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There are 13.5 cubic meters of water in Mr. Johnson's pool.

Volume is defined as the space occupied within the boundaries of an object in three-dimensional space.

To find the volume of water in Mr. Johnson's pool, we need to multiply the length, width, and depth of the pool. The length is 2.5 meters, the width is 4.5 meters, and the depth of water is 1.2 meters.

So, the volume of water in Mr. Johnson's pool is:

2.5 meters x 4.5 meters x 1.2 meters = 13.5 cubic meters

Therefore, there are 13.5 cubic meters of water in Mr. Johnson's pool.

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The mean of the temperatures shown is -39.4°F.

What is the mean temperature?

The average mean air temperature throughout a specific time period, typically a day, a month, or a year, as measured by a thermometer that has been properly exposed. The mean temperature is often calculated for the year and for each month in climatological tables.

Date:   Low temperature:

January 1   -42°F

January 2 -31°F

January 3  -40°F

January 4  -40°F

January 5  -44°F

Mean = Total sum of all 5 days temperature / total number of days

Mean = -42  - 31 - 40 - 40 - 44 / 5

= -197 / 5

= - 39.4°F

Hence, the mean of the temperatures shown is -39.4°F.

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Answer:

Step-by-step explanation:

The missing numbers are: box 1 = -5x and box 2 = 4sot,  A diamond problem is a type of math puzzle that involves finding two missing values in a diamond-shaped diagram.

The top and bottom numbers of the diamond represent a product, and the left and right sides represent two numbers that add up to a middle value. The goal is to find the two missing values that fit into the diamond.

To solve a diamond problem, we need to factor the product of the top and bottom numbers and look for two factors whose sum is equal to the middle value. This is because the product of two numbers can only be made up of factors that multiply together to form the product. Once we find the two factors, we can insert them into the left and right sides of the diamond.

In the given diamond problem, we have 20x? as the top and sot as the bottom. The product of these two numbers is 20x^2sot. To find the factors, we can list all the possible factor pairs of this product and check which of them adds up to -9x, which is the middle value in the diamond. We found that -5x and 4sot are the factors that add up to -9x.

Solving diamond problems can help improve factoring skills and problem-solving abilities. It requires logical thinking and an understanding of how factors and multiples work. Additionally, diamond problems can be used to introduce algebraic concepts to students in a visual and intuitive way, making them a useful tool for teaching math to learners of all ages.

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None of the bills have an experimental probability of 3, as all probabilities are between 0 and 1.

Based on the table, the experimental probability for each bill being drawn from the bag next can be calculated by dividing the frequency of each bill by the total number of draws (100). Using this formula, we can calculate the experimental probabilities for each bill:

1. For the $1 bill: Experimental probability = [tex]\frac{(Frequency of  $1 bill)}{Total draws} = \frac{8}{100} = 0.28[/tex]
2. For the $10 bill: Experimental probability =[tex]\frac{(Frequency of  $10 bill)}{Total draws} = \frac{56}{100} = 0.56[/tex]
3. For the $20 bill: Experimental probability =[tex]\frac{(Frequency of  $20 bill)}{Total draws} = \frac{2}{100} = 0.02[/tex]

None of the bills have an experimental probability of 3, as all probabilities are between 0 and 1.

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The expression that represents the fee for signing up the day of the activity is x + 0.20x. This means that fee for signing up the day of the activity is original fee (x) plus an additional 20% of original fee (0.20x).

For example, if the community center charges $50 for signing up before the day of the activity, then the fee for signing up the day of the activity would be:

$50 + ($50 x 0.20) = $50 + $10 = $60

So, individuals who sign up the day of the activity are charged a higher fee than those who sign up before the day of the activity, because they are charged the original fee plus an extra 20% of the original fee. This is often used as an incentive for individuals to sign up early and to help the community center plan and prepare for the activity accordingly.

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We can use the formula for the area of a sector to find the area of sector $LMN$

The area of a sector with central angle $\theta$ in a circle with radius $r$ is given by:

$A = \frac{\theta}{360^\circ} \pi r^2$

In this case, we know that $m\angle LMN = 66^\circ$ and $LM = 19$ units, so the radius of circle M is half of the diagonal of the rectangle formed by $LM$ and $MN$. Using the Pythagorean theorem, we can find the length of $MN$:

$MN^2 = LM^2 + LN^2 = LM^2 + LM^2 = 2LM^2$

$MN = \sqrt{2} LM = \sqrt{2} \cdot 19$

So the radius of circle M is $r = \frac{1}{2}MN = \frac{1}{2}\sqrt{2} \cdot 19$

Now we can use the formula for the area of a sector to find the area of sector $LMN$:

$A = \frac{m\angle LMN}{360^\circ} \pi r^2 = \frac{66^\circ}{360^\circ} \pi \left(\frac{1}{2}\sqrt{2} \cdot 19\right)^2 \approx \boxed{90.89}$ square units (rounded to the nearest hundredth).

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Answer:

no it is not possible

Step-by-step explanation:

The minimum number of people that need to be persuaded is two. When there are 0 contributor, 1 contributor, 2 or more contributor this is a the Nash equilibria.

a. Let's first calculate the benefit to each citizen when there are n contributors. According to the problem, the benefit is n^2 dollars. So when there are 0 contributors, the benefit to each citizen is 0 dollars. When there is 1 contributor, the benefit to each citizen is 1 dollar. When there are 2 contributors, the benefit to each citizen is 4 dollars. And so on, up to 10,000 dollars per citizen when all 100 citizens contribute.

Now let's think about the incentives of each citizen to contribute. If no one contributes, everyone gets 0 dollars of benefit. If one person contributes, that person gets 1 dollar of benefit, and everyone else gets 0 dollars. So each person has an incentive to free-ride, hoping that someone else will contribute.

But if two people contribute, each person gets 4 dollars of benefit, which is more than the 1 dollar cost of contributing. So once there are at least two contributors, it becomes rational for everyone else to contribute as well.

Therefore, the minimum number of people that need to be persuaded is two. Once two people contribute, it becomes rational for everyone else to contribute as well.

b. Let's consider the Nash equilibria of the game where each citizen is deciding whether to contribute. A Nash equilibrium is a situation where no one has an incentive to change their strategy, given the strategies of all the other players.

In this case, each citizen has two strategies: contribute or free-ride. Let's consider the case where n citizens are contributing. If everyone else is contributing, then it is rational to contribute as well, since the benefit of contributing is greater than the cost.

If everyone else is free-riding, then it is rational to free-ride as well, since the cost of contributing is greater than the benefit. However, if some people are contributing and some people are free-riding, then it may be rational to contribute, since the benefit of contributing may outweigh the cost, depending on the number of contributors.

Therefore, there are multiple Nash equilibria in this game, depending on the number of contributors. When there are 0 contributors, everyone is free-riding and this is a Nash equilibrium. When there is 1 contributor, that person is contributing and everyone else is free-riding, and this is a Nash equilibrium. When there are 2 or more contributors, everyone is contributing, and this is a Nash equilibrium.

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The solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.

To solve this system of linear equations, we can use Gaussian elimination, which involves adding and subtracting equations to eliminate variables. Here are the steps:

x - 3y - 2z = 6

2x - 4y - 3z = 8

-3x + 6y + 8z = -5

Step 1: Add twice the first equation to the second equation to eliminate x:

x - 3y - 2z = 6

4y + z = 20

-3x + 6y + 8z = -5

Step 2: Add three times the first equation to the third equation to eliminate x:

x - 3y - 2z = 6

4y + z = 20

9y + 2z = 13

Step 3: Solve for z in the second equation:

4y + z = 20

z = 20 - 4y

Step 4: Substitute z into the third equation and solve for y:

9y + 2z = 13

9y + 2(20 - 4y) = 13

y = -3

Step 5: Substitute y into the second equation and solve for z:

4y + z = 20

4(-3) + z = 20

z = 8

Step 6: Substitute y and z into the first equation and solve for x:

x - 3y - 2z = 6

x - 3(-3) - 2(8) = 6

x = 1

Therefore, the solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.

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The text format of the question in the picture:

15. The solution the system of linear equation of

x-3y-2z = 6

2x-4y-3z = 8

(-3x+6y+8z = -5 is

A) X=-1,y=-3, z=-2 B) X=-1,y=-3, z=2 C) X=1,y=-3, z=2 D) X = 1, y = 3, z=-2

Sea "l" la medida del largo del terreno y "a" la medida del ancho del terreno.

De acuerdo con el problema, el ancho es la mitad del largo, es decir, a = l/2.

El perímetro de un rectángulo se calcula sumando las longitudes de sus cuatro lados, por lo que en este caso:

Perímetro = 2l + 2a = 2l + 2(l/2) = 3l

Sabemos que el perímetro es de 105 metros, entonces:

3l = 105

l = 105/3 = 35

Por lo tanto, el largo del terreno es 35 metros. Y, como el ancho es la mitad del largo, entonces:

a = l/2 = 35/2 = 17.5

Por lo tanto, el ancho del terreno es de 17.5 metros.

En resumen, las medidas del terreno son 35 metros de largo y 17.5 metros de ancho.

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Answer:

Volume = 288695.6 in³

Step-by-step explanation:

Volume of a sphere is given by

v=4/3πr^3

Where r is the radius of the sphere

From the question

radius = 41 in

Substitute the value into the above formula

We have

v=4/3 x 41^3π

=275684/3 π

= 288695.6097

We have the final answer as

Volume = 288695.6 in³ to the nearest tenth

Volume = 288695.6 in³ to the nearest tenth

Hope this helps you

PLS MARK BRAINLIEST

The coordinate matrix of the linear transformation with respect to the second ordered basis is found by multiplying the change of basis matrix by the coordinate matrix of the linear transformation with respect to the first ordered basis is [tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]

Let V be a vector space with two ordered bases B and B', and let T be a linear transformation from V to V. Suppose that the change of basis matrix from B to B' is P, and the coordinate matrix of T with respect to B is A.

To find the coordinate matrix of T with respect to B', we can use the formula

A' = P⁻¹AP

where A' is the coordinate matrix of T with respect to B'.

To use this formula, we need to find the inverse of P. If P is invertible, then we have

P⁻¹ = 1/det(P) * adj(P)

where det(P) is the determinant of P and adj(P) is the adjugate of P.

Assuming that P is invertible, we can compute its inverse as follows

det(P) = 1*(-2) - 2*2 = -5

adj(P) =[tex]\left[\begin{array}{cc}-2&2\\-2&1\end{array}\right][/tex]

So, P⁻¹ = (-1/5)*[tex]\left[\begin{array}{cc}-2&2\\-2&1\end{array}\right][/tex] = [tex]\left[\begin{array}{cc}2/5&-2/5\\2/5&-1/5\end{array}\right][/tex]

Now, we can use the formula to find the coordinate matrix of T with respect to B'

A' = P⁻¹AP =  *[tex]\left[\begin{array}{cc}-2&1\\-1&0\end{array}\right][/tex]*[tex]\left[\begin{array}{cc}-1&2\\2&1\end{array}\right][/tex]= [tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]

Therefore, the coordinate matrix of T with respect to B' is

[tex]\left[\begin{array}{cc}0&2/5\\1&-1/5\end{array}\right][/tex]

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--The given question is incomplete, the complete question is given

"  Using change of base matrices to find coordinate matrices of linear transformations Let B and C be two ordered bases of R2, and consider a linear transformation T: R2 + R2. Suppose that the change of base matrix Ic, B is given by [0 -2 3 3] and the coordinate matrix Tc,c of T with respect to C is given by [ -1 -1 2 -1] Use this to determine coordinate matrix TB,B of T with respect to B. TB,B ? "--

Answer:

36/49.

Step-by-step explanation:

Probability if rains on one day = (6/7)

Probabiilty it rains the next day  also

= 6/7 * 6/7

= 36/49.

Around $441 million worth of food is wasted in the US each day.

According to the United States Department of Agriculture (USDA), about 30-40 percent of the food supply in the United States goes to waste. In terms of dollars, that translates to approximately $161 billion worth of food being wasted each year in the United States.

Dividing that number by 365, we can estimate that around $441 million worth of food is wasted in the US each day.

It's difficult to estimate how many people could be fed with the food that is thrown away, as food waste can take many forms, such as uneaten meals at restaurants, spoiled produce at grocery stores, and expired food in households. However, according to Feeding America, a national food bank network, approximately 42 million Americans, including 13 million children, are food insecure, which means they lack reliable access to affordable, nutritious food.

If we assume that all the food that is currently being wasted in the US could be redistributed to those who are food insecure, it could potentially feed a significant number of people. However, in reality, the logistics of collecting, storing, and distributing food waste can be complex, and some food waste may not be safe or nutritious to eat. Additionally, addressing food waste is just one piece of the puzzle in addressing food insecurity, which is a complex issue with many underlying factors.

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The area of the outer circle and of the inner circle is :  πr² and,  πx².

Then subtract the area of the inner circle from the outer circle is :

π (r - x) (r+x)

Here, we have,

Given:

Let the radius of outer circle i.e CA be r

Let the radius of inner circle i.e CB be x

The diagram is given below as attachment.

We know that,

area of circle = πR²

Then subtract the area of the inner circle from the outer circle is:

The area of the outer circle - area of the inner circle

= πr² -  πx²

= π (r² - x²)

=π (r - x) (r+x)

So, we get

Then subtract the area of the inner circle from the outer circle is:

π (r - x) (r+x)

Hence, The area of the outer circle and of the inner circle is :  πr² and,  πx².

Then subtract the area of the inner circle from the outer circle is :

π (r - x) (r+x)

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The total surface area of the prism is 282

From the question, we have the following parameters that can be used in our computation:

The net of a triangle prism.

The total surface area of the prism is the sum of the individual shapes

So, we have

Surface area = 2 * 1/2 * 6 * 5 + 3 * 6 * 14

Evaluate

Surface area = 282

Hence. the total surface area of the prism is 282

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Answer:

The total surface area is 282

It will take the rock 1.5 seconds  to hit the ground

Since the situation is modeled by the equation h = -16t² + 16t + 12

The rock will hit the ground when height is zero i.e. h = 0. Thus, we have:

-16t² + 16t + 12 = 0 and we can then solve for the time (t) .

-16t² + 16t + 12 = 0  (divide through by -16)

t² - t - 3/4 = 0

Using factorization method:

(t + 1/2) (t - 3/2) = 0

t = -1/2 or 3/2

Since t cannot be negative. Thus, t = 3/2 = 1.5.

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For a random sample of 155 observations results in 62 successes.

a) A 90% confidence interval for the population proportion of successes is equals to the (0.335 , 0.465).

b) A 90% confidence interval for the population proportion of failure is equals to the (0.535 , 0.665).

We have a random sample of 155 observations results in 62 successes. So,

Observed value, x = 62

Sample size,n = 155

Population Proportion, p = x/n

= 62/155

= 0.4

a) We have to determine 90% confidence interval for the population proportion of successes. Using the distribution table, for 90% confidence interval, z-score value is equals to 1.6. Consider Confidence interval formula with proportion, CI [tex]= p ± z×\sqrt\frac{p(1-p)}{n}[/tex]

substitute all known values in above formula, [tex]= 0.4 ± 1.64\sqrt\frac{0.4(1- 0.4)}{155}[/tex]

= 0.4 ± 0.0645

= (0.4 - 0.0645 , 0.4 + 0.0645)

= (0.335 , 0.465)

b) Now, we have to determine a 90% confidence interval for the population proportion of failures.

Now consider, here failure observed values, x = 155 - 62

= 93

proportion, p = x/n

= 93/155 = 0.6

Consider the confidence interval formula, CI [tex]= p ± z×\sqrt\frac{p(1-p)}{n}[/tex]

substitute values, [tex]= 0.6 ±1.64×\sqrt\frac{0.6(1-0.6)}{155}[/tex]

= 0.6 ± 0.0645

= (0.6 - 0.0645 , 0.6 + 0.0645)

= (0.535 , 0.665)

Hence, required value is (0.535 , 0.665).

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Answer:

  36 units

Step-by-step explanation:

You want to know the perimeter of the right triangle with leg lengths 9 units and 12 units.

The perimeter of the triangle is the sum of the lengths of its sides. We can count squares to find the lengths of the horizontal and vertical legs. The length of the hypotenuse can be found using the Pythagorean theorem:

  c² = a² +b²

  c² = 9² +12² = 81 +144 = 225

  c = √225 = 15 . . . . length of the hypotenuse

Then the perimeter is ...

  P = a +b +c = 9 +12 +15 = 36 . . . units

The perimeter of the triangle is 36 units.

__

Additional comment

The leg lengths have the ratio 9:12 = 3:4, telling you this is a 3:4:5 right triangle. This means you know the side lengths are 3:4:5 = 9:12:15, and their sum is 9+12+15 = 36.

It is handy to memorize a few of the Pythagorean triples that often show up in algebra, trig, and geometry problems: {3, 4, 5}, {5, 12, 13}, {7, 24, 25}, {8, 15, 17}.

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The crop sizes for first 4 years without using fertilisers are:

The size of the potato crop for each of the first four years is computed as follows:

For Year 1:

= 15 tonnes * 1

= 15 tonnes

For Year 2:

= 15 tonnes x 0.8

= 12 tonnes

For Year 3:

= 12 tonnes x 0.8

= 9.6 tonnes

For Year 4:

= 9.6 tonnes x 0.8

= 7.68 tonnes

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Coordinates of vertex y are (-12,-1).

To find the coordinates of vertex y in parallelogram WXYZ, we can use the fact that opposite sides of a parallelogram are parallel. We can use this property to find the coordinates of y by first finding the vector between points X and Z, and then adding that vector to the coordinates of point W.

The vector between points X and Z is (-7-2,-3-4)=(-9,-7). Adding this vector to the coordinates of point W gives (-5-9, 2-7)=(-14,-5). Therefore, the coordinates of vertex Y are (-14,-5).

Hence, the coordinates of vertex Y in the parallelogram WXYZ are (-14, -5).

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I think it might be C

The choice which best describes the measure of center of these data is (d) Rome data center is "best-described" by median and  data center of "New-York" is "best-described" by mean.

In the table provided below, we see that the "IQR" for Rome is relatively large compared to the IQR for New York, which suggests that that there may be some skewness in the distribution of the Rome data. So, the median would be a better-measure of center than the mean.

On the other hand, the IQR for "New-York" is relatively small, which indicates that the data is more symmetric and the mean would be a better measure of center.

Therefore, the correct answer is (d).

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The given question is incomplete, the complete question is

The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either from Rome, Italy, or New York, New York:

                    High   Low    Q1     Q3    IQR    Median    Mean    σ

Rome              18       1         3       7        4         6.5          6.4    4.3

New York       14       1        4.5    8.5     4          5.5          6.1     3.2

Which of the choices below best describes how to measure the center of these data?

(a) Both centers are best described by the mean.

(b) Both centers are best described by the median.

(c) The Rome data center is best described by the mean. The New York data center is best described by the median.

(d) The Rome data center is best described by the median. The New York data center is best described by the mean.

We can expect  4 giant swallowtails to visit Ellie's garden.

In total, there were 96 butterfly visits (32 monarchs + 56 gulf fritillaries + 8 giant swallowtails).

Now, we can calculate the probability of a giant swallowtail visit:
Probability

= (number of giant swallowtails) / (total butterfly visits)

= 8/96

= 1/12

Given that 48 butterflies visit her garden, we can expect the number of giant swallowtails to be:
Expected giant swallowtails

= (total butterflies) × (probability of giant swallowtails)

= 48 × (1/12)

= 4

So, we can expect approximately 4 giant swallowtails to visit Ellie's garden out of the 48 butterflies.

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For the function "h(x) = |2x| - 8", the domain is (-∞, ∞) and the range is  [-8, ∞).

The function h(x) = |2x| - 8 is defined for all real numbers x, so the domain of h(x) is the set of all real-numbers, or (-∞, ∞).

To find the range of the function, we determine set of all possible output values of function. Since the function involves the absolute value of 2x, the output can never be less than -8.

When "2x" is positive, |2x| = 2x. When 2x is negative, |2x| = -2x. This means that the function h(x) will have two branches depending on whether 2x is positive or negative.

⇒ When 2x is positive, h(x) = |2x| - 8 = 2x - 8. This branch of the function will have all non-negative values.

⇒ When 2x is negative, h(x) = |2x| - 8 = -2x - 8. This branch of the function will have all non-positive values.

Combining the two , we get the range of the function h(x) as [-8, ∞).

Therefore, the domain of h(x) is (-∞, ∞) and the range of h(x) is [-8, ∞).

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To compute Bu(1.-3) - 88 - (1, -3), we need to substitute the values of u and v into the expression for w.

First, we need to find the values of u and v. Since u = 1.-3 and v = (1, -3), we have:

u = 1.-3 = 1 - 0.3 = 0.7
v = (1, -3)

Next, we can substitute these values into the expression for w:

w = 2xy + y^2 - 4x^2
 = 2(1)(-3) + (-3)^2 - 4(1)^2  (substituting x = 1 and y = -3)
 = -6 + 9 - 4
 = -1

Finally, we can compute Bu(1.-3) - 88 - (1, -3) by multiplying the gradient of w by the vector (1, -3) and subtracting 88:

Bu(1.-3) - 88 - (1, -3) = (-8x + 2y, 2x + 2y)  (1, -3) - 88
                        = (-8(1) + 2(-3), 2(1) + 2(-3))  (1, -3) - 88
                        = (-14, -4)  (1, -3) - 88
                        = (-14)(1) + (-4)(-3) - 88
                        = -14 + 12 - 88
                        = -90

Therefore, Bu(1.-3) - 88 - (1, -3) = -90.

Since the question seems to have some typos or missing information, I'll assume you want to find the partial derivatives of w with respect to x and y, and evaluate them at the point (1, -3).

Given w = 2xy + y² - 4x², let's compute the partial derivatives:

∂w/∂x = 2y - 8x
∂w/∂y = 2x + 2y

Now, let's evaluate these partial derivatives at the point (1, -3):

∂w/∂x(1, -3) = 2(-3) - 8(1) = -6 - 8 = -14
∂w/∂y(1, -3) = 2(1) + 2(-3) = 2 - 6 = -4

Thus, the evaluated partial derivatives are ∂w/∂x(1, -3) = -14 and ∂w/∂y(1, -3) = -4.

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In a regular tiling, if there are six polygons meeting at a vertex, then the angles at the vertex are 120 degrees.

This is because each regular polygon has interior angles that are multiples of 180 degrees divided by the number of sides. For a regular hexagon, which has six sides, each interior angle measures 120 degrees. When six regular hexagons meet at a vertex in a regular tiling, the total angle sum at the vertex is 720 degrees (6 times 120 degrees).

Since the angles must be divided equally among the six hexagons, each angle at the vertex is 120 degrees.

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