Find the exact perimeter.

Step-by-step explanation:

11 cm, 6 cm, 17 cm

Answer::

11cm, 6cm, 17cm

step by step explanation:

the correct answer is 11cm 6cm and 17cm

because in a right angled triangle, the square of the hypothenus is equal to the square of the sum of the other two sides

hypothenus= 17cm other two sides=11cm and 6cm

Angles ABC and CBD are complementary - they add up to 90°. This means

(4x + 52°) + (8x - 10°) = 90°

Solve for x :

12x + 42° = 90°

12x = 48°

x = 4°

It follows that angle CBD has measure

4 • 4° + 52° = 16° + 52° = 68°

Answer...

Ok done. Thank to me >:3

Answer:

No because Temperature is measured in Kelvins

Step-by-step explanation:

Answer:

D. 25.12 feet

Step-by-step explanation: C= r(pi)^2

Answer:

-5x+12

Step-by-step explanation:

12 -5x

We can use the communitive property of addition to change the order.

The minus sign stays with the 5x

-5x+12

The Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]

We're given:

Plug these measurements into the Pythagorean theorem:

[tex]a^2+b^2=c^2\\9^2+12^2=c^2[/tex]

⇒ Combine like terms:

[tex]81+144=c^2\\c^2=225[/tex]

[tex]c^2=225[/tex]

Answer:

2.

Step-by-step explanation:

it's the reciprocal

so it's gonna reflect

Answer:

[tex]derivative \: of \: y = 6 {x}^{2} + 2x + 4[/tex]

Step-by-step explanation:

we know that

[tex] \frac{d}{dx} {x}^{n} = n {x}^{n - 1} [/tex]

Now the derivative of y=2x³+x²+4x

[tex] \frac{dy}{dx} = \frac{d}{dx} (2 {x}^{3} + {x}^{2} + 4x)[/tex]

[tex] \frac{dy}{dx} = \frac{d}{dx} (2 {x}^{3} ) + \frac{d}{dx}( {x}^{2} ) + \frac{d}{dx} (4x)[/tex]

[tex]\frac{dy}{dx} = 2(\frac{d}{dx} {x}^{3} ) + \frac{d}{dx} {x}^{2} + 4(\frac{d}{dx} x)[/tex]

here

[tex]\frac{d}{dx} {x}^{3} = 3 {x}^{2} [/tex]

[tex]\frac{d}{dx} {x}^{2} = 2x[/tex]

[tex]\frac{d}{dx} x = 1[/tex]

Now

[tex]\frac{dy}{dx} = 2(3 {x}^{2} ) + 2x + 4(1)[/tex]

[tex]\frac{dy}{dx} = 6 {x}^{2} + 2x + 4[/tex]

I hope it helped you

Answer:

195 cubic inches

Step-by-step explanation:

A fishing tackle box is 13 inches long, 6 inches wide, and inches high. What is the volume of the tackle box? SOLUTION: The volume of the tackle box is 195 cubic inches.

Answer:

$53.33

Step-by-step explanation:

40/1 - .25

40/.75 = $53.33

Answer:

the answer is A because if the interest is equal to 624×5×3÷100 which would give us 93.60

but for the rest the when you solve it you won't get the same answer below it

Answer:

x is 36

Step-by-step explanation:

the way to find out is 1/4 multiplied by what gives you 9. 9 divided by 1/4 is 36. 36 1/4's gives you 9.

Answer: 2

Step-by-step explanation:first u subtract 1-9=8then u divide 4/8=2 tell me if wrong

Answer:

x = 9

Step-by-step explanation:

using Pythagoras' identity in the right triangle

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

x² + 6² = ([tex]\sqrt{117}[/tex] )²

x² + 36 = 117 ( subtract 36 from both sides )

x² = 81 ( take square root of both sides )

x = [tex]\sqrt{81}[/tex] = 9

Answer:

Given:

[tex]\begin{aligned} \textsf{Perimeter} & =\textsf{shorter leg + longer leg + hypotenuse}\\ & = (x+5)+[3(x+5)-1]+[2(x+5)+13]\\ & = x+5+3x+15-1+2x+10+13\\ & = 6x+42\end{aligned}[/tex]

[tex]\begin{aligned} \textsf{Area} & =\dfrac12\textsf{(shorter leg)(longer leg)}\\ & =\dfrac12(x+5)[3(x+5)-1]}\\ & =\dfrac12(x+5)(3x+14)\\ & = \dfrac12(3x^2+29x+70)\\ & = \dfrac32x^2+\dfrac{29}{2}x+35 \end{aligned}[/tex]

[tex]\begin{aligned} \textsf{Area} & =2.5 \sf (Perimeter)\\ \implies \dfrac32x^2+\dfrac{29}{2}x+35 & =\dfrac52(6x+42)\\ 3x^2+29x+70 & =5(6x+42)\\ 3x^2+29x+70 & =30x+210\\ 3x^2 -x-140 & =0\\ 3x^2-21x+20x-140 & =0\\ 3x(x-7)+20(x-7) &=0\\ (x-7)(3x+20)& =0\end{aligned}[/tex]

Therefore:

[tex](x-7)=0 \implies x=7[/tex]

[tex](3x+20)=0 \implies x=-\dfrac{20}{3}[/tex]

[tex]x=-\dfrac{20}{3}[/tex] is not a viable solution as when inputting this into the formula for the shorter leg, it gives a negative value:

[tex]\textsf{Shorter leg}=-\dfrac{20}{3}+5=-\dfrac53[/tex]

As distance cannot be negative, this is not a viable solution.

When x = 7:

[tex]\textsf{Shorter leg}=7+5=12[/tex]

[tex]\textsf{Longer leg}=3(7+5)-1=35[/tex]

[tex]\textsf{Hypotenuse}=2(x+5)+13=37[/tex]

[tex]\textsf{Perimeter}=6(7)+42=84[/tex]

[tex]\textsf{Area} & =\dfrac32(7)^2+\dfrac{29}{2}(7)+35=210[/tex]

Therefore, there is one viable solution.  This solution in the form (x, A) is  (7, 210)

Answer:

4.9 × [tex]10^3[/tex]

Step-by-step explanation:

Start by doing what is in the paranthesis from right to left.

[tex]9 * 10^2 = 900[/tex]

and

[tex]4 * 10^3 = 4000[/tex]

So if we add them we get:

[tex]900 + 4000 = 4900[/tex]

Now to put it into standard form we just put a decimal to the right of the first number and see how many times we need to move right in order to make the number. In this case it's 3 times so we tack on × [tex]10^3[/tex]

So our answer is:

[tex]4.9[/tex] × [tex]10^3[/tex]

Answer:

The value of a is 7.

Step-by-step explanation:

To calculate mean, add all of the numbers in the set and divide by the number of terms in said set. There are 7 numbers in this set, so the equation can be set up as follows.

(4 + 10 + 3 + 6 + a + 9 + 10)/7 = 7

Simplify the terms on the top.

(42 + a)/7 = 7

Multiply both sides by 7.

42 + a = 49

Subtract both sides by 42.

a = 7.

Proof:

(4 + 10 + 3 + 6 + a + 9 + 10)/7 = 7

Substitute variable.

(4 + 10 + 3 + 6 + 7 + 9 + 10)/7 = 7

Add in the parenthesis.

49/7 = 7

Divide.

7 = 7.

Answer:

250

Step-by-step explanation:

Answer:  [tex]C=31.4[/tex]

Step-by-step explanation: When you are finding the circumference of a circle you use the formula

[tex]C=2\pi r[/tex]

[tex]C=2*3.14 *5[/tex]

[tex]C=31.4[/tex]

hi the awnser us defiantly going to be that I 56

Step-by-step explanation:

edge

Answer:

Step-by-step explanation:

I don't see any information on dimensions of the cans or box, so I'll assume the question wants a general solution.

Three steps will result in the volume of sand required to fill the remaining space in the box.

1.  Calculate the volume of a can using the equation for the volume of a cylinder:  Vol = πr²h

2.  Multiply the can volume by 12.  This will give the total volume of the 12 cans in the box.

3.  Calculate the volume of the box:  Volume = (Base)(Width)(Height)

[Make sure the units are the same as those used in calculating the can volume.  E.g., if the can is calculated with cm as the measue, the box dimensions must also be cm]

4.  Subtract the volume of the12 cans (from step 2) from the volume of the box.

The result from 4 will be the volume of sand required to fill the box containing 12 cans.  

I'm not clear why filling the box with sand is important, but perhaps it will absorb any soda released from cans broken when the heavy box is dropped by the person shocked that 12 cans of pop could be so heavy.

Answer:

50.3

Set A to the value of pi times the radius squared.

[tex]4^2 = 4 * 4 = 16\\\\A = \pi *r^2(4^2) = 50.26548245...[/tex]

Answer:

[tex]x=\frac{3}{2}[/tex]

Step-by-step explanation:

Step 1.  Put each term in [tex]3x-\frac{1}{2}[/tex] over the common denominator 2.

[tex]\frac{6x}{2}-\frac{1}{2}[/tex]

Therefore we have [tex](\frac{6x}{2}-\frac{1}{2})=4[/tex]

Step 2.

Combine [tex]\frac{6x}{2}-\frac{1}{2}[/tex] into a single fraction.

[tex]\frac{6x-1}{2}[/tex]  

Therefore we have [tex](\frac{1}{2}(6x-1))=4[/tex]  or [tex]\frac{6x-1}{2}=4[/tex]

Step 3.

Multiply both sides by a constant to simplify the equation.

Multiply both sides of [tex]\frac{6x-1}{2}=4[/tex]  by 2:

[tex]\frac{2*(6x-1)}{2}=4*2[/tex]

Step 4.

Cancel the common terms in the numerator and denominator of   [tex]\frac{2*(6x-1)}{2}[/tex]

Then we get [tex]\frac{2}{2}*(6x-1)[/tex]  which simplifies to [tex](6x-1)[/tex]

So all together we have [tex](6x-1)=2*4[/tex]

Step 5.

Multiply 2 and 4 together and remove the parenthesis.

[tex]6x-1=8[/tex]

Step 6.

Isolate terms with the variable x to the left hand side.

So add 1 to both sides:

[tex]6x+(1-1)=8+1[/tex]

Evaluate   [tex]1-1=0[/tex]  which cancels out

Step 7.

Add the like terms on the right side:

[tex]6x=9[/tex]

Step 8.

Divide both sides by a constant to simplify the equation.

Divide both sides of [tex]6x=9[/tex]  by 6.

[tex]\frac{6x}{6} =\frac{9}{6}[/tex]

Any non-zero number divided by itself is 1.

[tex]x=\frac{9}{6}[/tex]  which simplifies to [tex]x=\frac{3}{2}[/tex]

Problem 25

Point P has the x coordinate x = -5, while point Z has the x coordinate x = 5. This is a distance of 10 units on the number line. Segment PZ is 10 units long which is the base of the triangle.

The height of the triangle is 8 units because it's the vertical distance from R to segment PZ. Notice we go from x = 4 to x = -4. The base and height are always perpendicular to one another.

Area = (base*height)/2

Area = (10*8)/2

Area = 80/2

Area = 40

==========================================================

Problem 26

I'm not sure about this one because the instructions mention a grid, but I don't see any grid lines here. I'm not sure if the grid lines are just really faint or if your teacher forgot to put them in.

[tex]\text{Larger angle} =x\\\\\text{Smaller angle} =y\\ \\\text{According to the condition,}\\\\x=10y+15\\\\\text{The two angles are supplementary, so their sum is}~ 180^{\circ} \\\\x+y=180\\\\\implies 10y+15 +y = 180\\\\\implies 11y = 180-15\\\\\implies 11y=165\\\\\implies y = \dfrac{165}{11}\\\\\implies y = 15\\\\\text{So,} ~x =180-15 = 165\\\\\text{Hence the larger angle is}~ 165^{\circ}~ \text{and the smaller angle is }15^{\circ}[/tex]

Answer:

0.2

Step-by-step explanation:

the sum of 5 times 0.2 and 7 equals 8

Answer:

144 is the surface area

Step-by-step explanation:

Multiply 5 x 8 for the 3 rectangles. You will get an answer of 40. 40 x 3 is 120. For the 2 triangles you multiply 6 x 4 divided by 2 times 2 which is 24 lol. 120 + 24 = 144.

Answer:

A = 6400 m²

Step-by-step explanation:

the sides s of a square are congruent , then

s = 320 ÷ 4 = 80 m

tahe area (A) of a square is calculated as

A = s² = 80² = 6400 m²

The required area of square, having side 80 meters, is 6400 square meters.

A square is a quadrilateral with four equal sides and four equal angles that is a regular quadrilateral. The square's angles are at a straight angle or 90 degrees.

Given that,

The length of fencing enclosure a square = 320 meters,

Let the side of the square is a meter,

According to given condition, perimeter of square,

4a = 320  

a = 80

Since, the area of square having side a, is a²

Area = a²

Area = (80²)

Area = 6400 square meters.

The area of square, having side 80, is 6400 square meters.

To learn more about Square on:

https://brainly.com/question/28776767

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Answer:

Point d's corrdinates are (-7, -3). You can use the coordinate grid to find it out by graphing the others first and then find the missing one based on the sides

Step-by-step explanation: