find the value of x in the Triangle shown below
x=?​

Answer:

Explain more

Step-by-step explanation:

You need to explain more like add an image or tell us how much much money is a rope.

Answer:

Anupam ask me where l live

hope it's help you (^0^)

Answer:

1/64

Step-by-step explanation:

P(pick 3 consecutive spades with replacement of drawn cards) =

(13/52)(13/52)(13/52) =

(1/4)(1/4)(1/4) =

1/64

Here we have $400 originally and it is invested at an interest rate of 0.015 for 4 years.

Therefore we can say that the interest rate is 0.015 * 4 * 100 = 6% for the 4 years.

Simple interest is 6% / 4 = 1.5%.

And the principal is $400.

Answer:

B

Step-by-step explanation:

number of adults=a

number of children=1

cost of adult tickets=$9 per adult

cost of children's tickets=$6 per child

Total cost=$78

9(a)+6(1)=78

9a+6=78 B

do have a great day ahead...

Answer:

137.8

when round of:138

Answer:

137.8

Step-by-step explanation:

Can't really break it down further than this.

9514 1404 393

Answer:

  D: 21

Step-by-step explanation:

The first term is (a1). The third term is (a1)r². The product of these terms is ...

  (a1)(a1)r² = ((a1)r)², the square of the second term.

The missing term is √(7·63) = √441 = 21.

_____

Additional comment

In consideration of the above, you can also see that the common ratio can be found from ...

  a3/a1 = ((a1)r²)/(a1) = r² = 63/7 = 9

Then the common ratio is r = √9 = 3, and the second term is 7·3 = 21.

Answer:

hope i helped...if anythng not understood please write in the comments

Answer:

90

Step-by-step explanation:

you can multiply anything here in any order.

you could first do 5 times -9

5 * -9 = -45

and then multiply the -2 to the -45

-2 * -45 = 90

Answer:

The answer is 86° Fahrenheit.

Step-by-step explanation:

The equation for converting between Fahrenheit and Celsius is °F = 1.8 x °C + 32. So you would just plug 30 in for the °C.

°F = 1.8 x 30° + 32.

°F = 54 + 32

°F = 86°

Answer:

30ºC = 86ºF

Step-by-step explanation:

The temperature T in degrees Fahrenheit (ºF) is equal to 30 degrees Celsius (ºC) times 9/5 plus 32:

T(ºF) = 30ºC × 9/5 + 32 = 86ºF

Answer:-16

Step-by-step explanation:

add all the temperature together =-112

then you divide by the number of temperatures given which is 7 which gives you -16

Answer:

-16 degrees C.

Step-by-step explanation:

When they say mean, they mean the average. You add the numbers together and divide them on how many numbers there are.

Answer:

5. yes It still has the same density because it is the same thing.

6. a. float   less than one

b. Float less than one

C. Sink   greater than one

7. 1652.4 This is because the density equation is mass/volume. We have the density and mass but no volume. do get it we need to re arrange the equation. mass x density = volume.

Step-by-step explanation:

Answer:

-12

Step-by-step explanation:

-3 + -9 = 12

hope this helps

Answer:

-12

Step-by-step explanation:

-3 + -9

turns into

-3 - 9

Which means on the number line, we start at -3 and move to the left 9 units.

When we move to left on the number line by 9, we are at -12.

Which means -3 - 9 (-3 + -9) = -12

its right because

6 x 5 is the area of the leftmost rectangle

4 x 5 is the area of the bottom rectangle

3 x 5 is the area of the rightmost rectangle

5 x 5 is the area of the slanted square on the top

the last term is the area of the trapezoid, which is (base1 + base2) x height /2

they split the trapezoid thing into a square and a triangle, which gets you the same answer

they multiplied it by 2 because there are 2 trapezoids

9514 1404 393

Answer:

Step-by-step explanation:

Jarvis is paid for 1 1/2 times the number of hours he worked on Saturday. So, for the 5 hours he worked, he is paid for ...

  5 × 1 1/2 = 7 1/2 hours . . . . paid on Saturday

Jarvis is paid for 1 3/4 times the number of hours he worked on Sunday, So, for the 2 hours he worked, he is paid for ...

  2 × 1 3/4 = 3 1/2 hours . . . . paid on Sunday

The total of hours for which Jarvis is paid is ...

  7 1/2 + 3 1/2 = 11 hours . . . . paid for the weekend

At $9 per hour, the amount Jarvis is paid for the weekend is ...

  $9 × 11 = $99.00 . . . . weekend pay

Answer: 4

pls give brainliest

Answer: a

Step-by-step explanation:

Answer:

A robot can complete tasks in

hour. Each task takes the same amount of time.

a. How long does it take the robot to complete one task?

It takes one hour to complete one task.

b. How many tasks can the robot complete in one hour?

It complete only one task in one hour.

y=mx+b

-3=3(3)+b

-3=9+b

-12=b

Answer: A

Step-by-step explanation:

It is the definition of independent and dependent events

can you help me this 4^x x ^8^x^+^1 = 2⁴

Answer:

12 passengers can travel in Rs. 900.

Step-by-step explanation:

see the above attachment.

if you face any problem comment me, I am there for help.

hope this helps you.

Answer:

Define:

Domain is the set of values that you can input in a function

Range is the set of values that corresponds to the output of a function, the set of values corresponding to its results

The vertical line test is a simple test you can do with a graph to know if this graph correspond to a function or not: you have to draw a vertical line, parallel to the y-axis and if that line touch the graph in just one point, it is a function

What is the domain and range of each function?

Domain = {3, 5, 7, 8, 11}

Range = {6, 7, 9, 14}

Is each relation a function?

Yes

Answer:

my butt

Step-by-step explanation:

why well because when were dinosaurs created in 1957 and when they were alive they drove cars to school to learn about extra chromosomes and and then the meatore hit and created my butt.

I hope that helps if you need anymore help let me know :)

Answer:

increasing

Step-by-step explanation:

it's increasing because throughout the days you can see that the plants growth is slowly progressing in this case going up on the grpah.

(1)

(a) Use the fact that [tex]\sqrt{x^2} = |x|[/tex] for all [tex]x[/tex]. Since [tex]x\to+\infty[/tex], we have [tex]x>0[/tex] and [tex]|x| = x[/tex].

[tex]\displaystyle \lim_{x\to\infty} \frac{\sqrt{9x^2 - 2}}{x + 4} = \lim_{x\to\infty} \frac{\sqrt{x^2} \sqrt{9 - \frac2{x^2}}}{x + 4} \\\\= \lim_{x\to\infty} \frac{ x \sqrt{9 - \frac2{x^2}}}{x+4} \\\\= \lim_{x\to\infty} \frac{\sqrt{9 - \frac2{x^2}}}{1 + \frac4x} \\\\= \frac{\sqrt9}1 = \boxed{3}[/tex]

(b) This time [tex]x\to-\infty[/tex], so [tex]x < 0[/tex] and [tex]|x| = -x[/tex].

[tex]\displaystyle \lim_{x\to\infty} \frac{\sqrt{9x^2 - 2}}{x + 4} = \lim_{x\to\infty} \frac{\sqrt{x^2} \sqrt{9 - \frac2{x^2}}}{x + 4} \\\\= \lim_{x\to\infty} \frac{ \boxed{-x} \sqrt{9 - \frac2{x^2}}}{x+4} \\\\= (-1) \times \lim_{x\to\infty} \frac{\sqrt{9 - \frac2{x^2}}}{1 + \frac4x} \\\\= -\frac{\sqrt9}1 = \boxed{-3}[/tex]

(c) We immediately have

[tex]\displaystyle \lim_{x\to\infty} (x - \sqrt x) = \boxed{\infty}[/tex]

since [tex]x > \sqrt x[/tex] for all [tex]x > 1[/tex].

(d) Introduce a difference of squares by factoring in the limand's conjugate. The rest mirrors what we did in (a)/(b).

[tex]\displaystyle \lim_{x\to\infty} \left(\sqrt{x^2 + 12x} - x\right) = \lim_{x\to\infty} \frac{\left(\sqrt{x^2+12x} - x\right) \left(\sqrt{x^2+12x} + x\right)}{\sqrt{x^2 + 12x} + x} \\\\ = \lim_{x\to\infty} \frac{\left(\sqrt{x^2+12x}\right)^2 - x^2}{\sqrt{x^2+12x}+x} \\\\ = \lim_{x\to\infty} \frac{12x}{\sqrt{x^2+12x}+x} \\\\ = \lim_{x\to\infty} \frac{12}{\sqrt{1 + \frac{12}x} + 1} = \frac{12}{\sqrt1 + 1} = \boxed{6}[/tex]

(e) Divide through by the highest-degree exponential term.

[tex]\displaystyle \lim_{x\to\infty} \frac{12e^{2x} - 3e^{3x}}{2e^{2x} + 4e^{3x}} = \lim_{x\to\infty} \frac{12e^{-x} - 3}{2e^{-x} + 4} = \frac{0 - 3}{0 + 4} = \boxed{-\frac34}[/tex]

(2) By definition of the derivative, we have

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{f(x+h) - f(x)}h[/tex]

For [tex]f(x) = \sqrt{x^2+1}[/tex], the limit becomes

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\sqrt{(x+h)^2+1} - \sqrt{x^2+1}}h[/tex]

Factor in the conjugate.

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\left(\sqrt{(x+h)^2+1} - \sqrt{x^2+1}\right) \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\left(\sqrt{(x+h)^2+1}\right)^2 - \left(\sqrt{x^2+1}\right)^2}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\bigg((x+h)^2+1\bigg) - (x^2+1)}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{2xh + h^2}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{2x + h}{\sqrt{(x+h)^2+1} + \sqrt{x^2+1}}[/tex]

[tex]\implies \boxed{f'(x) = \displaystyle \lim_{h\to0} \frac{x}{\sqrt{x^2+1}}}[/tex]

(3) The tangent line to

[tex]y = \frac1{x^2+1}[/tex]

at the point (2, 1/5) has slope equal to the derivative [tex]\frac{dy}{dx}[/tex] when [tex]x = 2[/tex]. Compute the derivative; since [tex]y = \frac1{f(x)^2}[/tex] where [tex]f(x)[/tex] is the function from the previous problem, using the chain rule gives

[tex]y = \dfrac1{f(x)^2} \implies \dfrac{dy}{dx} = -\dfrac{2f'(x)}{f(x)^3} = -\dfrac{2 \times \frac{x}{\sqrt{x^2+1}}}{\left(\sqrt{x^2+1}\right)^3} \\\\ \implies \dfrac{dy}{dx} = -\dfrac{2x}{(x^2+1)^2}[/tex]

The tangent line at (2, 1/5) then has slope

[tex]\dfrac{dy}{dx}\bigg|_{x=2} = -\dfrac{2\times2}{(2^2+1)^2} = -\dfrac4{25}[/tex]

Using the point-slope formula, the equation of the tangent line is

[tex]y - \dfrac15 = -\dfrac4{25} (x - 2) \implies \boxed{y = -\dfrac{4x - 13}{25}}[/tex]