Find the zeros of each quadratic equation below by graphing.
Pls I need help

Step-by-step explanation:

-5x - 4y = 10

Intercept-y (x = 0)

-5 (0) - 4y = 10

-4y = 10

y = - 5/2

(0, -5/2)

Intercept-x (y = 0)

-5x - 4 (0) = 10

-5x = 10

x = -2

(-2, 0)

The number of bacteria contained in the human body is 40 times as great as the number of genes contained in the human body.

To find out how many times greater the number of bacteria in the human body is than the number of genes, we need to divide the number of bacteria by the number of genes:

4 × 10^13 (number of bacteria) ÷ 1 × 10^12 (number of genes)

= 40

Therefore, the number of bacteria contained in the human body is 40 times as great as the number of genes contained in the human body.

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Maria jumped 6 inches farther than Nate.

To see why, we can subtract Nate's jump height from Maria's jump height:

32 - 26 = 6

So Maria jumped 6 inches farther than Nate did.

To represent this problem mathematically, we can use the equation:

Maria's jump height - Nate's jump height = the difference in their jump heights

Or, using variables:

M - N = D

Where M represents Maria's jump height, N represents Nate's jump height, and D represents the difference between their jump heights. Plugging in the numbers from the problem, we get:

32 - 26 = D

Simplifying, we get:

6 = D

So D, the difference between their jump heights, is 6 inches.

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A BASE jumper will fall 324 feet in 4.5 seconds.

What are velocity ?

velocity is a unit of measurement for the Distance an object travels in a

the predetermined period of time. Here is a word equation that illustrates the connection between space, speed, and time: velocity is calculated by dividing the total Distance traveled by the journey time.

We can use the given function to find out how far a BASE jumper will fall in 4.5 seconds:

d = 16t²

where d is the distance (in feet) and t is the time (in seconds).

Substitute t = 4.5 into the formula:

d = 16(4.5)²

d = 324

Therefore, a BASE jumper will fall 324 feet in 4.5 seconds.

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The length of the minor arc GD is approximately 0.196π units.

To get the length of the minor arc GD, we need to subtract the measure of the major arc mDUG from the circumference of the circle, and then divide by 360° to find the length of one degree of arc.
First, we need to find the circumference of the circle. Since GA = 29, we know that the radius of the circle is also 29. The formula for the circumference of a circle is C = 2πr, so for this circle we have: C = 2π(29) = 58π
Next, we need to subtract the measure of the major arc mDUG from the circumference of the circle. Since mDUG = 185°, we have:
58π - (185/360)(58π) = (175/360)(58π)
Simplifying this expression, we get: (175/360)(58π) = 29(175/72)π ≈ 70.48π
Finally, we divide this value by 360° to find the length of one degree of arc:
(70.48π)/360 ≈ 0.196π
Therefore, the length of the minor arc GD is approximately 0.196π units.

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If the CPI was 305 in 1995, the price of jeans that cost $14.99 in 1973 would be approximately $47.05 in 1995 after adjusting for inflation.

To find the price of jeans in 1995, we first need to adjust the 1973 price for inflation using the Consumer Price Index (CPI). CPI measures the average change in prices of goods and services over time, so it can help us compare prices from different years.

First, we need to calculate the inflation rate between 1973 and 1995. We can do this by dividing the CPI in 1995 (305) by the CPI in 1973 (135):

Inflation rate = (305 / 135) * 100% = 226.67%

This means that prices in 1995 were about 2.27 times higher than in 1973. Now, we can apply this inflation rate to the price of jeans in 1973:

Price in 1995 = Price in 1973 * (1 + inflation rate)

Price in 1995 = $14.99 * (1 + 2.2667) = $47.05

Therefore, if the CPI was 305 in 1995, the price of jeans that cost $14.99 in 1973 would be approximately $47.05 in 1995 after adjusting for inflation. This calculation helps to compare the cost of goods across different time periods by taking inflation into account, thus giving a better understanding of the changes in purchasing power over time.

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To find the total volume of the silo, we need to add the volume of the hemisphere on top to the volume of the cylinder at the bottom.

The volume of a hemisphere is given by:

V_hemi = (2/3)πr^3

where r is the radius of the hemisphere.

Substituting r = 9ft, we get:

V_hemi = (2/3)π(9ft)^3

= 1521π ft^3

The volume of a cylinder is given by:

V_cyl = πr^2h

where r is the radius of the cylinder and h is its height.

Substituting r = 9ft and h = 35ft, we get:

V_cyl = π(9ft)^2(35ft)

= 2673π ft^3

Therefore, the total volume of the silo is:

V_silo = V_hemi + V_cyl

= 1521π + 2673π

= 4194π ft^3

≈ 13160 ft^3

Rounding to the nearest cubic foot, the silo can hold approximately 13160 cubic feet of grain.

Answer:

55%

Step-by-step explanation:

Chances it wont land on red = chances of blue + chances of yellow

                                                = 55%

If Kai spent 55$ all together then each pack of gum cost $4.

To solve this question follow the steps given below:

Calculate the total cost of Gatorade.
Since there are 5 bags and each bag has a bottle of Gatorade that costs $3, the total cost for Gatorade is 5 * $3 = $15.

Calculate the total cost of gum.
Since Kai spent $55 in total, we need to subtract the cost of Gatorade to find the total cost of gum. $55 - $15 = $40.

Calculate the total number of gum packs.
Each bag contains 2 packs of gum, and there are 5 bags. So, there are    2 * 5 = 10 packs of gum.

Calculate the cost of each pack of gum.
To find the cost of each pack of gum, divide the total cost of gum by the number of gum packs. $40 / 10 = $4.

So, each pack of gum cost $4.

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The exact value of sin⁻¹(−1/2) is -π/6.

Given, sin⁻¹(-1/2)

The inverse sine function, sin⁻¹, or arcsin, returns the angle whose sine is equal to the given value. In this case, we are looking for the angle whose sine is -1/2.

Let y = sin⁻¹(-1/2)

sin (y) = -1/2

sin (y) = - sin (π/6)

sin (y) =  sin (- π/6)

y = - π/6

sin⁻¹(-1/2) = - π/6

To understand why the answer is -π/6, we can consider the unit circle. On the unit circle, the sine function represents the y-coordinate of a point corresponding to an angle. For -1/2, we need to find the angle where the y-coordinate is -1/2.

One such angle is -π/6, where the point on the unit circle is located in the fourth quadrant. At this angle, the y-coordinate is -1/2. Hence, sin⁻¹(−1/2) is -π/6.

Therefore, the exact value of sin⁻¹(−1/2) is -π/6.

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The equation of the line representing that best fit the given scatterplot is given by option d. y = -0.005x + 22.5.

Consider the two points from the attached scatterplot.

Let the coordinates of the two point be ( x₁ , y₁) = ( 1500 , 12.5 )

And other point be ( x₂ , y₂) = ( 2000 , 10 )

Slope of the line 'm'  = ( y₂ - y₁ ) / ( x₂ - x₁ )

                                  = ( 10 - 12.5) / ( 2000 - 1500 )

                                  = -2.5 / 500

                                  = -0.005

From the attached scatterplot we have,

y-intercept 'c' where x = 0 is equals to 22.5.

The equation best which represents the line of best fit for the scatterplot is equals to,

y = mx + c

Substitute the value we have,

y = -0.005x + 22.5

Therefore, the equation of the line representing scatterplot is equals to option d. y = -0.005x + 22.5.

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The above question is incomplete, the complete question is:

Which equation best represents the line of best fit for the scatterplot?

a) y = 2.5x + 25 b) y = −2.5x + 20 c) y = −0.05x + 20 d) y = −0.005x + 22.5

Attached scatterplot.

The integral  ∫(8x/2 + 2/x^3)dx evaluates to 4x^2 - 2/x^2 + C, where C is the constant of integration.

The given integral ∫(8x/2 + 2/x^3)dx is definite integral without any integration limits. To evaluate this integral, we can split it into two parts

∫8x/2 dx + ∫2/x^3 dx

We made use of the power rule of integration to simplify the first term, and the inverse power rule to simplify the second term.

Simplifying each integral, we get

4x^2 - 2/x^2 + C

where C is the constant of integration.

Therefore, the final answer to the integral is

∫(8x/2 + 2/x^3)dx = 4x^2 - 2/x^2 + C

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--The given question is incomplete, the complete question is given

" Evaluate. Assume that x>0. ∫(8x/2 + 2/x^3)dx"--

The critical points and their classifications are: (0, kπ/2), local minimum for all k.

To find the critical points of f(x, y), we need to find where the partial derivatives of f with respect to x and y are equal to zero:

∂f/∂x = 6x = 0

∂f/∂y = 2sin(2y) = 0

From the first equation, we get x = 0, and from the second equation, we get sin(2y) = 0, which has solutions y = kπ/2 for any integer k.

So the critical points are (0, kπ/2) for all integers k.

To classify these critical points, we need to use the second derivative test. The Hessian matrix of f is:

H = [6 0]

[0 -4sin(2y)]

At the critical point (0, kπ/2), the Hessian becomes:

H = [6 0]

[0 0]

The determinant of the Hessian is 0, so we can't use the second derivative test to classify the critical points. Instead, we need to look at the behavior of f in the neighborhood of each critical point.

For any k, we have:

f(0, kπ/2) = 1 + 3(0)² - cos(2kπ) = 2

So all the critical points have the same function value of 2.

To see whether each critical point is a maximum, minimum, or saddle point, we can look at the behavior of f along two perpendicular lines passing through each critical point.

Along the x-axis, we have y = kπ/2, so:

f(x, kπ/2) = 1 + 3x² - cos(2kπ) = 1 + 3x²

This is a parabola opening upwards, so each critical point (0, kπ/2) is a local minimum.

Along the y-axis, we have x = 0, so:

f(0, y) = 1 + 3(0)² - cos(2y) = 2 - cos(2y)

This is a periodic function with period π, and it oscillates between 1 and 3. So for each k, the critical point (0, kπ/2) is neither a maximum nor a minimum, but a saddle point.

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The diagram to create a similar triangle has been attached.

Similar triangles are defined as triangles that possess the same shape, but then their sizes will likely vary. We can also say that two triangles are referred to as similar if they possess the same ratio of its' corresponding sides and also an equal pair of corresponding angles

The two different triangles can be formed by placing the 90° angle adjacent to, or opposite the given side.

In the diagram below attached, we see that the two triangles are ABC and ABD. Thus, the right angles are located at vertex C and vertex B, respectively.

Thus, it has been created with the given measurements

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Answer:

The polar form of the rectangular coordinates (0, 6√3) with a positive value of r, over the interval 0 ≤ θo < 27 and in terms of radians, is (6√3, 1.58).

Step-by-step explanation:

To convert the rectangular coordinates (0, 6√3) to polar form, we can use the following formulas:

r = √(x^2 + y^2)

θ = tan^(-1)(y/x)

Substituting the given values, we get:

r = √(0^2 + (6√3)^2) = 6√3

θ = tan^(-1)((6√3)/0) = π/2

However, note that the angle θ is not well-defined since x=0. We can specify that the point lies on the positive y-axis, which corresponds to θ = π/2 radians.

Thus, the polar form of the rectangular coordinates (0, 6√3) is:

r = 6√3

θ = π/2

To express the angle θ in terms of θo, where 0 ≤ θo < 27 and in radians, we can write:

θ = π/2 = (π/54) × 54 ≈ (0.0292) × 54 ≈ 1.58 radians

Therefore, the polar form of the rectangular coordinates (0, 6√3) with a positive value of r, over the interval 0 ≤ θo < 27 and in terms of radians, is (6√3, 1.58).

√6a + 3 < a + 2,  we have proven that √6a + 3 < a + 2 for all a > 1 using the Mean Value Theorem.

To use the Mean Value Theorem to prove √6a + 3 < a + 2 for all a > 1, we first note that the function f(x) = √6x + 3 is continuous on the interval [1,a].

Next, we need to find a point c in the interval (1,a) such that the slope of the line connecting (1,f(1)) and (a,f(a)) is equal to the slope of the tangent line to f(x) at c.

The slope of the line connecting (1,f(1)) and (a,f(a)) is given by:

(f(a) - f(1)) / (a - 1) = (√6a + 3 - √9) / (a - 1) = (√6a) / (a - 1)

To find the slope of the tangent line to f(x) at c, we first find the derivative of f(x):

f'(x) = (1/2) * (6x + 3)^(-1/2) * 6 = 3 / √(6x + 3)

Then, we evaluate f'(c) to get the slope of the tangent line at c:

f'(c) = 3 / √(6c + 3)

Now, by the Mean Value Theorem, there exists a point c in (1,a) such that:

f'(c) = (√6a) / (a - 1)

Setting these two expressions for f'(c) equal to each other, we get:

3 / √(6c + 3) = (√6a) / (a - 1)

Solving for c, we get:

c = (a + 2) / 6

(Note that c is indeed in (1,a) since a > 1.)

Now, we can evaluate f(a) and f(1) and use the Mean Value Theorem to show that:

√6a + 3 - √9 < (√6a) / (a - 1) * (a - 1)

Simplifying, we get:

√6a + 3 < a + 2

as desired.

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To find the linearization L(x) of the function f(x) = 7cos(x) at a = 3.14159265359, we'll use the formula:

L(x) = f(a) + f'(a)(x - a)

where f'(x) is the derivative of f(x) with respect to x.

First, let's find the value of f(a) at a = 3.14159265359:

f(a) = 7cos(a)
f(3.14159265359) = 7cos(3.14159265359) ≈ -7

Next, let's find the value of f'(a) at a = 3.14159265359:

f'(x) = -7sin(x)
f'(a) = -7sin(a)
f'(3.14159265359) = -7sin(3.14159265359) ≈ 0

Now we have all the pieces we need to plug into the formula for L(x):

L(x) = f(a) + f'(a)(x - a)
L(x) = -7 + 0(x - 3.14159265359)
L(x) = -7

So the linearization of the function f(x) = 7cos(x) at a = 3.14159265359 is:

L(x) = -7

To find the linearization L(x) of the function f(x) = 7cos(x) at a specific point a, we'll use the formula:

L(x) = f(a) + f'(a)(x - a)

Given that a = 3.14159265359 (approximating π), first we need to find f(a) and f'(a).

1. f(a) = 7cos(a) = 7cos(3.14159265359) ≈ -7
2. To find f'(x), we take the derivative of f(x):
f'(x) = -7sin(x)

Now, we can find f'(a):
f'(a) = -7sin(3.14159265359) ≈ 0

Finally, we can plug these values into the linearization formula:
L(x) = -7 + 0(x - 3.14159265359)

Simplifying, we get:

L(x) = -7

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3) The expression In(4x^5) - In(x^3) - In 4 can be simplified using the properties of logarithms. We know that ln(a) - ln(b) = ln(a/b) and ln(a^n) = n ln(a), so we can write:In(4x^5) - In(x^3) - In 4 = In[(4x^5)/(x^3)] - In 4= In(4x^2) - In 4= In(4x^2/4)= In(x^2)Thus, the simplified expression is In(x^2).4) To solve this problem, we need to use the formula for compound interest:A = P(1 + r/n)^(nt)where A is the final amount, P is the initial amount, r is the interest rate (as a decimal), n is the number of times interest is compounded per year, and t is the number of years.We want to find t when A = 3P and r = 0.02 (since the price of beef has inflated by 2%). We are told that interest is compounded biannually, so n = 2. Plugging in these values and solving for t, we get:3P = P(1 + 0.02/2)^(2t)3 = (1.01)^2tln(3) = ln(1.01^2t)ln(3) = 2t ln(1.01)t = ln(3) / (2 ln(1.01))Using a calculator, we find t ≈ 34.64 years. Therefore, it will take about 34.64 years for the price of beef to triple at a 2% biannual inflation rate.

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It will take approximately 110 years for the price of beef to triple when inflating 2% compounded biannually.

3) To simplify the expression In(4x^5) - In(x^3) - In(4), we will use the properties of logarithms:

- In(a) - In(b) = In(a/b)
- In(a^b) = b * In(a)

So, we can rewrite the expression as:

In(4x^5 / (x^3 * 4))

Now, we can simplify the expression inside the natural logarithm:

(4x^5) / (4x^3) = x^(5-3) = x^2

Thus, the simplified expression is:

In(x^2)

4) To find how long it will take for the price of beef to triple when inflating 2% compounded biannually, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

where A is the final amount, P is the initial amount, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the time in years. In this case, we want the final amount to be triple the initial amount:

3P = P(1 + 0.02/2)^(2t)

To solve for t, we can divide both sides by P:

3 = (1 + 0.01)^(2t)

Now, take the natural logarithm of both sides and use the properties of logarithms:

ln(3) = ln((1 + 0.01)^(2t))
ln(3) = 2t * ln(1 + 0.01)

Finally, isolate t:

t = ln(3) / (2 * ln(1 + 0.01))

t ≈ 109.96

It will take approximately 110 years for the price of beef to triple when inflating 2% compounded biannually.

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The measure of angle x of the ninja star is given by x = 56°

Given data ,

Let the ninja star be represented as an isosceles triangle

Now , it is constructed using four congruent isosceles triangles that are placed along the sides of a square

And , the vertex angle of the triangle is x

In an isosceles triangle, the two equal sides are called legs, and the remaining side is called the base. The angle opposite the base is called the vertex angle

So , the measure of x = 180° - ( 62° + 62° )

On simplifying , we get

x = 56°

Hence , the angle of triangle is x = 56°

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Answer:

Step-by-step explanation:

To find the solution set to the inequality w - 10 < 16, we can solve for w by adding 10 to both sides of the inequality:

w - 10 + 10 < 16 + 10 w < 26

This means that any number less than 26 is part of the solution set to the inequality. So, out of the given options, the number that is not part of the solution set is D. 27 because it is greater than 26.

Answer:

Step-by-step explanation:

Of means to multiply

So to find .3 of the 10.38 pounds up apples:

.3 x 10.38

=3.114 pounds of apples were used

5.) The dimensions of the banner whose perimeter is given is listed below:

length = 134in

width = -59in

To calculate the dimensions of the rectangular banner, the formula for the perimeter of rectangle should be used and it's given below;

Perimeter of rectangle = 2(length+width)

length = 16-2a

width = a

perimeter = 160in

That is;

160 = 2(16-2a+a)

160 = 32-4a+2a

160 = 42-2a

2a = 42-160

2a = -118

a = 118/2

= -59

Length = 16-2(-59)

= 16+118

= 134in

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The greatest number of teams the director could make is 4, and there will be 3 girls on each team.

Since the director wants to make teams with an equal number of boys and girls, the number of teams must be a factor of both 16 and 12. The common factors of 16 and 12 are 1, 2, 4, and 8. Since the director wants to make as many teams as possible, the greatest number of teams is 4.

Each team will have 4 boys and 3 girls, so the total number of girls needed is 4 x 3 = 12. Since there are 12 girls in the camp, there will be 12/4 = 3 girls on each team. Therefore, the greatest number of teams the director could make is 4, and there will be 3 girls on each team.

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The explict formula, in slope intercept form is an = n/5

The given sequence is 1/5, 2/5, 3/5.

We can observe that this is an arithmetic sequence, where the first term is 1/5, the common difference is 1/5

To find the explicit formula for an arithmetic sequence, we can use the formula:

an = a1 + (n-1)d

Substituting the values we know for this sequence, we get:

an = 1/5 + (n - 1)*(1/5)

Evaluate

an = n/5

Thus, the nth term of this sequence can be found by substituting the value of n in the formula an = n/5

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Complete question

1/5 2/5 3/5

What is the explicit formula in slope intercept form

Answer:

C

Step-by-step explanation:

The lowest point on the graph on the y-axis is -4

The number of possible outcomes of the compound event of selecting a card, spinning the spinner, and tossing a coin is B. 72 outcomes.

To determine the number of possible outcomes for the compound event, we need to multiply the number of outcomes for each individual event.

There are 12 cards labeled 1 through 12, so there are 12 possible outcomes for selecting a card. The spinner is divided into three equal-sized portions, so there are 3 possible outcomes for spinning the spinner. There are 2 possible outcomes for tossing a coin (heads or tails).

the total number of possible outcomes for the compound event:

12 (selecting a card) x 3 (spinning the spinner) x 2 (tossing a coin) = 72

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Answer:

Step-by-step explanation:

The distance between the two cruise liners is approximately 3.6 km.

We can use the Pythagorean theorem to find the distances between Liam and the two cruise liners, and then use the distance formula to find the distance between the two cruise liners. Let's call the distance between Liam and the first cruise liner "d1" and the distance between Liam and the second cruise liner "d2". Then:

d1 = sqrt(5² - 2²) = sqrt(21) km

d2 = sqrt(6.8² - 2²) = sqrt(44.44) km

To find the distance between the two cruise liners, we can use the distance formula:

distance = sqrt((d2 - d1)² + (6.8 - 5)²) km

Plugging in the values, we get:

distance = sqrt((sqrt(44.44) - sqrt(21))² + 1.8²) km

Simplifying this expression gives:

distance = sqrt(44.44) - sqrt(21) km

So the distance between the two cruise liners is approximately 3.9 km.

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To find the revenue function, we need to multiply the price (p) by the quantity (x):

R(x) = xp = (2220 - x^2) x

Expanding this expression, we get:

R(x) = 2220x - x^3

To find the cost function, we can simply use the given formula:

C(x) = 900 + 14x + x^2

To find the profit function, we subtract the cost from the revenue:

P(x) = R(x) - C(x)

= (2220x - x^3) - (900 + 14x + x^2)

= -x^3 + 2206x - 900

To find P'(x), the derivative of P(x) with respect to x, we take the derivative of the expression for P(x):

P'(x) = -3x^2 + 2206

Setting P'(x) equal to zero and solving for x, we get:

-3x^2 + 2206 = 0

x^2 = 735.333...

x ≈ 27.104

We can't produce a fraction of a hundred units, so we round down to the nearest hundredth unit, giving x = 27.

To confirm that this value gives a maximum profit, we can check the sign of P''(x), the second derivative of P(x) with respect to x:

P''(x) = -6x

When x = 27, P''(x) is negative, which means that P(x) has a local maximum at x = 27.

Therefore, the quantity that will give the maximum profit is 2700 units (27 x 100).

To find the maximum profit, we evaluate P(x) at x = 27:

P(27) = -(27)^3 + 2206(27) - 900

= 53,955 dollars

Therefore, the maximum profit is $53,955.

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