The given statement "A change in the concentration of the reactant or the product do not change keq" will be false. Because a change in the concentration of a reactant or product will change the value of Keq.
According to Le Chatelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that partially counteracts the stress and reestablishes equilibrium. Changes in the concentration of a reactant or product will alter the concentrations of all species present in the reaction, and thus will disturb the equilibrium.
For example, if the concentration of a reactant is increased, the reaction will shift towards the product side to partially counteract the increase in the concentration of the reactant. This will result in an increase in the concentration of products and a decrease in the concentration of reactants. As a result, the value of Keq will change to reflect the new equilibrium concentrations of reactants and products.
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a solution is prepared at that is initially in trimethylamine , a weak base with , and in trimethylammonium chloride . calculate the ph of the solution. round your answer to decimal places.
The pH of the solution prepared in trimethylamine, a weak base, with trimethylammonium chloride is 11.10 (rounded to the nearest decimal place).
The pH of the solution, the concentration of each ion and the pKa of the acid must be determined.
Trimethylamine + H₂O ⇌ Trimethylammonium ion + OH⁻ the acid-base equilibrium can be expressed as follows: Trimethylamine + H₂O ⇌ Trimethylammonium ion + OH⁻Ka = Kw / Kb = 1.00 × 10⁻¹⁴ / 6.3 × 10⁻⁴ = 1.58 × 10⁻¹¹
The initial concentration of the weak base (Trimethylamine) is determined using the molarity equation. Molarity = number of moles / liters of solution0.125 M Trimethylamine (CH₃)₃N
The concentration of the Trimethylammonium ion (conjugate acid) can be calculated using the mass balance equation. Molarity = number of moles / liters of solution0.125 M Trimethylamine (CH₃)₃N
The hydroxide ion concentration. OH⁻ concentration = Kb x [A] = 6.3 × 10⁻⁴ x 0.125 = 7.87 × 10⁻⁵ M
pH is calculated using the hydroxide ion concentration.
The pH of a solution is determined using the formula:pH = 14 - pOH= 14 - log[OH⁻]= 14 - log(7.87 × 10⁻⁵)= 11.10. Therefore, the pH of the solution is 11.10 (rounded to the nearest decimal place).
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How much concentrated 18 M sulfuric acid is needed to prepare 250 ml of 6.0M solution?
we need to measure 83.33 ml of 18 M sulfuric acid and dilute it to 250 ml with water to prepare a 6.0 M solution of sulfuric acid.
we can use the formula:
M1V1 = M2V2
Where:
M1 is the initial concentration of the sulfuric acid solution
V1 is the volume of the sulfuric acid solution needed
M2 is the final concentration of the sulfuric acid solution
V2 is the final volume of the sulfuric acid solution
In this case, we want to prepare a 6.0 M solution of sulfuric acid with a final volume of 250 ml. We need to find out how much concentrated 18 M sulfuric acid solution is needed.
Using the formula above, we can rearrange it to solve for V1:
V1 = (M2 x V2) / M1
Substituting the values we have:
V1 = (6.0 M x 250 ml) / 18 M
V1 = 83.33 ml
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unscramble the capitalized words in the definition to complete the sentence
1. Motion energy is properly called kinetic energy. It is proportional to the mass of the moving object and grows with the square of its speed.
2. When an object is raised, energy is released when the object is lowered or falls. This demonstrates the gravitational relationship between Earth and objects in motion.
3. The faster an object moves, the more energy it has; a ball rolling across the floor at five meters per second has less energy than a ball rolling down a steep ramp at twenty meters per second, even though they are the same
object.
Hope this helps!
What is the amount of heat required to boil 145 g of water?
Answer:
78,300 cals.
Explanation:
540 cals of heat reqd to convert1 gm of water at 100 deg C so 540 x 145 = 78,300 cals.
Answer:
The answer is 78,300 calories.
540 calories of heat are required to transform one gram of water at 100 degrees Celsius, so 540 x 145 = 78,300 cal
Explanation:
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calculate the ph of a solution prepared by adding 20.0 ml of 0.100 m hcl to 80.0 ml of a buffer that is comprised of 0.25 m nh3 and 0.25 m nh4cl. kb of nh3
The pH of the solution prepared by adding 20.0 mL of 0.100 M HCl to 80.0 mL of a buffer that is comprised of 0.25 M NH₃ and 0.25 M NH₄Cl is 3.79.
The balanced chemical equation for the reaction between NH₃ and HCl is:
NH₃ (aq) + HCl (aq) → NH₄⁺ (aq) + Cl⁻ (aq)
Before any HCl is added, the solution contains 80.0 mL of a buffer solution that is comprised of 0.25 M NH₃ and 0.25 M NH₄Cl. NH₃ is a weak base, and its dissociation in water can be represented as follows:
NH₃ (aq) + H₂O (l) ⇌ NH₄⁺ (aq) + OH⁻ (aq)
The base dissociation constant (Kb) for NH₃ is 1.8 x 10⁻⁵ at 25°C.
After adding 20.0 mL of 0.100 M HCl to the buffer solution, the amount of NH₃ remaining in the solution will react with the HCl to form NH₄⁺ and Cl⁻. The amount of HCl added to the solution is:
moles of HCl = M x V = 0.100 mol/L x 0.020 L
= 0.002 mol
Since NH₃ is a weak base, the buffer will resist changes in pH upon addition of HCl. The added HCl will react with NH₃ in the buffer solution to form NH₄⁺ and Cl⁻ ions. The NH₄⁺ ion is the conjugate acid of NH₃ and will slightly increase the acidity of the solution.
The amount of NH₃ that reacts with the HCl is:
Moles of NH₃ = moles of HCl
= 0.002 mol
The remaining amount of NH₃ in the solution is:
Initial moles of NH₃ - moles of NH₃ that reacted = (0.25 mol/L x 0.080 L) - 0.002 mol = 0.018 mol
The amount of NH₄⁺ that forms is equal to the amount of NH₃ that reacted:
0.002 mol of NH₃ = 0.002 mol of NH₄⁺
The concentration of NH₃ in the final solution is:
[ NH₃ ] = moles of NH₃ / total volume of solution
= 0.018 mol / 0.100 L = 0.18 M
The concentration of NH₄⁺ in the final solution is:
[ NH₄⁺ ] = moles of NH₄⁺ / total volume of solution
= 0.002 mol / 0.100 L = 0.02 M
The concentration of H⁺ in the final solution can be calculated using the equilibrium constant expression for NH₃:
Kb = [ NH₃ ][ OH⁻ ] / [ NH₃ ]
[ H⁺ ] = Kb x [ NH₃ ] / [ NH₃ ] = (1.8 x 10⁻⁵) x (0.18 mol) / (0.02 mol) = 0.000162 M
The pH of the final solution can be calculated as:
pH = -㏒[H⁺] = -log(0.000162) = 3.79
Therefore, the pH of the solution obtained by adding 20.0 mL of 0.100 M HCl to 80.0 mL of a buffer containing 0.25 M NH₃ and 0.25 M NH₄Cl is 3.79.
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of the following, which does NOT explain why the products are obtained in equal amounts? Backside attack on the radical intermediate leads to two diastereomers. The reaction generates a new chiral center. O A racemic mixture is formed. Attack on either face of planar radical intermediate is equally likely.
The term that does NOT explain why the products are obtained in equal amounts is "A racemic mixture is formed." The correct answer is option C.
According to the given question, a backside attack on the radical intermediate leads to two diastereomers. This means that two diastereomers are obtained in equal amounts.
The reaction generates a new chiral center, which also contributes to the production of equal amounts of products. Attack on either face of planar radical intermediate is equally likely, which means that both faces are attacked equally, leading to the formation of equal amounts of products.
However, the term "A racemic mixture is formed" cannot explain why the products are obtained in equal amounts.
A racemic mixture is a mixture that contains equal amounts of enantiomers, but it does not necessarily explain why equal amounts of products are obtained in a chemical reaction. Therefore, the correct answer is option C.
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Complete question
Of the following, which does NOT explain why the products are obtained in equal amounts?
a. Backside attack on the radical intermediate leads to two diastereomers.
b. The reaction generates a new chiral centre.
c. A racemic mixture is formed.
d. Attack on either face of planar radical intermediate is equally likely.
How do I solve this?
There is 21.77 g of excess SO₂ left over after the reaction is complete.
What is meant by reagent?Reagents are substances used in laboratory tests and can be used in a chemical process to find, quantify, or create other substances.
2SO₂ + O₂ → 2SO₃
Molar mass of SO₂ = 32.06 g/mol
Molar mass of O₂ = 31.9988 g/mol
Number of moles of SO₂ = 21.71 g / 32.06 g/mol = 0.677 mol
Number of moles of O₂ = 21.71 g / 31.9988 g/mol = 0.678 mol
2 moles of SO₂ : 1 mole of O₂
0.678 mol O₂ × (2 mol SO₂ / 1 mol O₂) = 1.356 mol SO₂
Therefore, 1.356 mol of SO₂ are required to react completely with 0.678 mol of O₂. However, we only have 0.677 mol of SO₂, so there is an excess of:
Excess SO₂ = 1.356 mol – 0.677 mol = 0.679 mol
Molar mass of SO₂ = 32.06 g/mol
Excess SO₂ = 0.679 mol × 32.06 g/mol = 21.77 g
Therefore, there is 21.77 g of excess SO₂ left over after the reaction is complete.
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A can of hairspray has an initial temperature of22 °C and a pressure of 18.5 psi, what is the temperature of the gas if the pressure decreased to 17.35 psi?
These rules described by specific cases of an ideal gas law, which states PV = nRT. When temperature rises, molecules become more energised, and lose their attraction to one another, causing pressure to fall.
How are pressure and temperature related?As long as the volume remains constant, the pressure of a given quantity of petrol is precisely proportional towards its absolute temperature (Amontons' law). Under constant pressure, the volume of the a given gas is proportional to its exact temperature.
What is the formula for pressure and temperature?Now, let's review PV = nRT, our ideal petrol law. In this equation, P denotes pressure in atmospheres, V denotes volume in litres, n denotes moles of particles, T denotes temperature in Kelvin, and R denotes the ideal gas constant.
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now that we have used tables and graphs to work out radioactive decay. lets try a problem without those aides. given the ur/pb system, if we proceed through 4 half-lives how many parents(ur) and daughters(pb) will we have left. this assumes that we begin with 100,000 atms of ur. if the half life is 1.6 ga how many years will it take to get through these 4 half lives?
To solve this problem, we can use the formula for radioactive decay and after 4 half-lives, there will be 6,250 atoms of uranium remaining for Parents and 93,750 atoms of lead produced for daughters.
The formula is [tex]N = N0 * (1/2)^{(t/t1/2)} ^[/tex]
where N is the final amount, N0 is the initial amount, t is the time elapsed, and t1/2 is the half-life of the radioactive isotope.
Given that the half-life of the uranium-lead (U-Pb) system is 1.6 billion years, the time required for 4 half-lives to occur is:
t = 4 * t1/2 = 4 * 1.6 billion years = 6.4 billion years
Therefore, it would take 6.4 billion years to get through these 4 half-lives.
Using the formula for radioactive decay, we can calculate the amount of uranium and lead remaining after 4 half-lives have occurred, starting with 100,000 atoms of uranium:
For the parents (uranium):
[tex]N = N0 * (1/2)^{(t/t1/2)} ^ = 100,000 * (1/2)^4 = 6,250[/tex]atoms
Therefore, after 4 half-lives, there will be 6,250 atoms of uranium remaining.
For the daughters (lead):
[tex]N = N0 - (N0 * (1/2)^{(t/t1/2)} = 100,000 - 6,250 = 93,750[/tex] atoms
Therefore, after 4 half-lives, there will be 93,750 atoms of lead produced.
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a water sample requires 5.28 ml of 0.0200 n h2so4 to lower the ph of 50.00 ml of sample to ph 4.3. the original ph of the sample was 6.7. a. what is the total alkalinity [alk] in eq/l in the original sample? what is most likely the dominant form contributing to the alkalinity at this ph? b. what is ct in the original sample? c. assuming this sample was originally open to the atmosphere (418 ppmv co2) and was in a closed system from the point of collection (meaning no additional gas exchange), can all the dissolved carbonate species be attributed to atmospheric co2, or must another source of carbonate be present as well? justify your decision using numbers as needed
The total alkalinity [Alk] in eq/L of the original sample is 0.00211 eq/L, the carbonate concentration (Ct) in the original sample is approximately 2.51 × 10⁻³ M, and the dissolved carbonate species in the original sample cannot be attributed solely to atmospheric CO₂, and another source of carbonate must be present as well.
To determine the total alkalinity [Alk] in eq/L of the original sample, we can use the following equation;
[Alk] = (Vb × Nb - Va × Na) / V
Where, Vb = volume of acid added (mL), Nb = normality of acid, Va = volume of sample (mL), Na = normality of sample (in this case, assumed to be zero), V = total volume (mL)
Substituting the given values, we get;
Vb = 5.28 mL
Nb = 0.0200 N
Va = 50.00 mL
Na = 0
V = 50.00 mL
[Alk] = (5.28 mL × 0.0200 N - 50.00 mL × 0) / 50.00 mL = 0.00211 eq/L
Therefore, the total alkalinity [Alk] in eq/L of the original sample will be 0.00211 eq/L.
At pH 6.7, the dominant form of alkalinity is likely bicarbonate (HCO₃⁻).
To determine the carbonate concentration (Ct) in the original sample, we can use the following equation;
pH = pKa + log([HCO₃⁻] + 2[CO₃²⁻] / [H₂CO₃])
At pH 6.7, we can assume that [HCO₃⁻] is much greater than [CO₃²⁻] and [H₂CO₃]. Therefore, we can simplify the equation to;
pH ≈ pKa + log([HCO₃⁻])
pKa for the bicarbonate system is 6.35.
Rearranging the equation, we get;
[HCO₃⁻] = [tex]10^{(pH-pKa)}[/tex] = [tex]10^{(6.7-6.35)}[/tex] = 2.51 × 10⁻³ M
[CO₃²⁻] = (Kw / K₂) × [HCO₃⁻] = (10⁻¹⁴ / 4.45 × 10⁻⁷) × 2.51 × 10⁻³ = 5.66 × 10⁻¹² M
Ct = [HCO₃⁻] + [CO₃²⁻] = 2.51 × 10⁻³ M + 5.66 × 10⁻¹² M ≈ 2.51 × 10⁻³ M
Therefore, the carbonate concentration (Ct) in the original sample is approximately 2.51 × 10⁻³ M.
At atmospheric pressure and temperature, the partial pressure of CO₂ in air is approximately 0.0004 atm, which corresponds to a dissolved CO₂ concentration of about 10 ppm. The dissolved CO₂ concentration in the original sample is much higher than this (418 ppm), which suggests that there must be another source of carbonate in the sample besides atmospheric CO₂.
In addition, the calculated Ct in the original sample is higher than the dissolved CO₂ concentration, further supporting the conclusion that there must be another source of carbonate in the sample.
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Calculate the weight 22.4L of NO2 at STP.
Answer:
46g
Explanation:
22.4L of NO2 at STP = 1mol of NO2 = atomic mass of NO2 = 46g
a gas sample with a mass of 2.50 g is collected at 20.0oc and 732.5 mmhg. the volume is 1.28 l. what is the molar mass of the gas?
We can use the ideal gas law, PV = nRT, to solve for the number of moles of gas present:
P = 732.5 mmHg = 0.963 atm (converting to atm)
V = 1.28 L
T = 293.15 K (20.0°C = 293.15 K)
R = 0.08206 L·atm/(mol·K)
PV = nRT
n = PV/RT = (0.963 atm)(1.28 L)/(0.08206 L·atm/mol·K)(293.15 K) = 0.0557 mol
Next, we can use the formula for molar mass, M = m/n, where m is the mass of the gas, to solve for the molar mass of the gas:
M = m/n = 2.50 g/0.0557 mol = 44.9 g/mol
Therefore, the molar mass of the gas is 44.9 g/mol.
The molar mass of the gas is 34.75 g mol^-1. To find the molar mass of the gas, the formula for the ideal gas law can be used.
The ideal gas law is given as
PV = nRT
Where,
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = gas constant
T = temperature of the gas
The given values of pressure, volume, and temperature are
P = 732.5 mmHg
V = 1.28 L
R = 62.36 L mmHg mol^-1
KT = 20°C = 20 + 273.15 = 293.15 K
Substituting these values in the ideal gas law equation and solving for n will give us the number of moles of the gas in the sample.
n = (PV) / (RT)
n = (732.5 mmHg × 1.28 L) / (62.36 L mmHg mol^-1 K × 293.15 K)
n = 0.07195 mol
To find the molar mass of the gas, we can use the formula
m = (mass of gas) / (number of moles of gas)
m = 2.50 g / 0.07195 mol
m = 34.75 g mol^-1.
Therefore, the molar mass of the gas is 34.75 g mol^-1.
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A balloon that can hold 35 L of air is inflated with 2.5 moles of gas at a pressure of 2.5
atmosphere. What is the temperature in °C of the balloon?
Answer:
The temperature of the balloon is approximately 153.4°C.
Explanation:
To find the temperature in Celsius of the balloon, we can use the ideal gas law.
Ideal Gas Law[tex]\boxed{\sf PV=nRT}[/tex]
where:
P is the pressure measured in atmospheres (atm).V is the volume measured in liters (L).n is the number of moles.R is the ideal gas constant (0.08206 L atm mol⁻¹ K⁻¹).T is the temperature measured in kelvin (K).Given values:
P = 2.5 atmV = 35 Ln = 2.5 molR = 0.08206 L atm mol⁻¹ K⁻¹Substitute the values into the formula and solve for T:
[tex]\implies \sf 2.5 \cdot 35 = 2.5 \cdot 0.08206 \cdot T[/tex]
[tex]\implies \sf T=\dfrac{2.5 \cdot 35}{2.5 \cdot 0.08206}[/tex]
[tex]\implies \sf T=\dfrac{87.5}{0.20515}[/tex]
[tex]\implies \sf T=426.5178...\;K[/tex]
As the temperature should be in Celsius, we need to convert from kelvin to Celsius by subtracting 273.15:
[tex]\implies \sf T=426.5178...\;K-273.15=153.4^{\circ}C[/tex]
Therefore, the temperature of the balloon is approximately 153.4°C.
if 10.0 ml of 0.050 m hcl is added to a 20.0 ml solution of 0.10 m nano 2 and 0.10 m hno 2 , what will be the ph of the resultant solution? ka for hno 2
The pH of the resultant solution is 3.16.
To determine the pH of the resultant solution after mixing the two solutions, we need to calculate the concentrations of all the ions present in the final solution.
First, let's calculate the moles of HCl added;
moles of HCl = concentration x volume = 0.050 M x 0.010 L = 0.00050 moles
Next, we need to calculate the moles of NaNO₂ and HNO₂ in the 20.0 mL solution;
moles of NaNO₂ = concentration x volume = 0.10 M x 0.020 L = 0.0020 moles
moles of HNO₂ = concentration x volume = 0.10 M x 0.020 L = 0.0020 moles
Since NaNO₂ is a salt and dissociates completely in water, it will provide Na⁺ and NO₂⁻ ions in solution. HNO₂, on the other hand, is a weak acid that will partially dissociate into H⁺ and NO₂⁻ ions. The equilibrium reaction for the dissociation of HNO₂ is;
HNO₂ + H₂O ⇌ H₃O⁺ + NO₂⁻
The acid dissociation constant, Ka, for HNO₂ is 4.5 x 10⁻⁴.
Let's assume x is the concentration of H⁺ ions produced by the dissociation of HNO₂. The NO₂⁻ concentration will be equal to the initial concentration of HNO₂ (0.10 M) minus the H+ ion concentration (x). Therefore, [NO₂⁻] = [HNO₂] - [H⁺]
[NO₂⁻] = 0.10 M - x
The equilibrium expression for the dissociation of HNO₂ can be written as;
Ka = [H⁺][NO₂⁻] / [HNO₂]
Substituting the expressions we found for [NO₂⁻] and [HNO₂]:
4.5 x 10⁻⁴ = x(0.10 M - x) / 0.0020 M
Solving for x using the quadratic formula;
x = 1.4 x 10⁻⁴ M
Now we can calculate the concentration of H⁺ ions in the final solution:
[H⁺] = [HCl] + [HNO₂]
[H⁺] = 0.00050 M + 1.4 x 10⁻⁴ M
[H⁺] = 6.9 x 10⁻⁴ M
Finally, we calculate the pH of solution by using the formula; pH = -log[H⁺]
pH = -log(6.9 x 10⁻⁴)
pH = 3.16
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calculate the ph 4.79 ml beyond the equivalence point. unrounded rounded to reach the equivalence point, what volume (in ml) of h c l hcl must be added?
The pH before any HCl is added will be; 12.91, and the pH after the addition of 4.00 mL HCl is 1.17.
To solve this problem, we need to use the balanced chemical equation for the reaction between M(OH)₂ and HCl;
M(OH)₂ + 2HCl → 2H₂O + MCl₂
The balanced chemical equation shows that the reaction between M(OH)₂ and HCl is a 1:2 reaction. Therefore, the number of moles of HCl needed to react with the M(OH)₂ is twice the number of moles of M(OH)₂.
Before any HCl is added, the solution contains only M(OH)₂. The concentration of M(OH)₂ is 0.0811 M. We will use the following equation to calculate the pOH:
pOH = -log[OH⁻]
Since M(OH)₂ is a strong base, it completely dissociates in water, so [OH⁻] = [M(OH)₂]. Therefore;
[OH⁻] = 0.0811 M
pOH = -log(0.0811) = 1.09
The pH can be calculated using the following equation;
pH + pOH = 14
pH = 14 - pOH = 14 - 1.09 = 12.91
After the addition of 4.00 mL of HCl, the total volume of the solution is 5.00 mL + 4.00 mL = 9.00 mL. The number of moles of M(OH)₂ in the solution is;
moles M(OH)₂ = concentration x volume = 0.0811 M x 5.00 mL = 0.0004055 moles
The number of moles of HCl added to the solution is
moles HCl = concentration x volume = 0.0512 M x 4.00 mL = 0.0002048 moles
Since the reaction is a 1:2 reaction, the number of moles of HCl required to react with all of the M(OH)₂ is:
moles HCl required = 2 x moles M(OH)₂ = 2 x 0.0004055 = 0.000811 moles
The remaining moles of HCl in the solution after the reaction is;
moles HCl remaining = moles HCl added - moles HCl required = 0.0002048 - 0.000811 = -0.0006062 moles
Since the remaining moles of HCl is negative, it means that all of the M(OH)₂ has reacted and there is an excess of HCl in the solution. Therefore, the pH of the solution is determined by the concentration of the excess H⁺ ions. The concentration of excess H⁺ ions can be calculated using the following equation;
[H⁺] = concentration of HCl remaining / total volume of solution
[H⁺] = (-0.0006062 moles / 9.00 mL) x (1000 mL / 1 L) = -0.0674 M
The pH can be calculated using the following equation:
pH = -log[H⁺] = -log(-0.0674)
= 1.17 (Note: The negative sign indicates that the solution is acidic.)
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--The given question is incorrect, the correct question is
"Using the concentration values determined in this investigation for M(OH)₂ and HCl, calculate the pH for a strong acid + strong base titration in which 5.00 mL of the M(OH)₂ was transferred via pipet to a beaker and HCl was added from the burret. Calculate the pH: a) before any HCl is added, b) after the addition of 4.00 mL HCl. Concentration of HCl = 0.0512 M, Concentration of M(OH)₂ = 0.0811 M."--
Bill nye the science guy phases of matter video, 10 things you learn in that video
Bill Nye is an American scientific educator, engineer, and television host who goes by the moniker "Bill Nye the Science Man. "Children were the target audience for the program, which used humor, experiments, and demonstrations to teach scientific principles in a fun and approachable way.
What is phases of matter?Phases of matter are the various phases that matter can take on depending on its physical characteristics as well as the ambient temperature and pressure. Matter exists in three basic states: solid, liquid, and gas.
The "Phases of Matter" video by Bill Nye the Science Man teaches you the following 10 things:
There are three basic phases of matter: solid, liquid, and gas. Matter is everything that has mass and occupies space.
Because their molecules are closely packed together and immobile, solids have a definite shape and volume.
Because their molecules can move and slide past one another, liquids have a constant volume but adopt the shape of the container.
Because their molecules are spaced far apart and are free to flow in any direction, gases don't have a set shape or volume.
By adding or subtracting heat energy, a substance can transition from one phase to another.
A substance's melting point is the temperature at which it turns from a solid to a liquid, and its boiling point is the temperature at which it turns from a liquid to a gas.
Because water has a higher melting and boiling point than other molecules of a similar size, it is a unique substance.
Moreover, a change in pressure or a chemical reaction can cause a substance to transition from one phase to another.
In extremely high temperatures and pressures, matter can exist in other states like plasma and Bose-Einstein condensate.
For the purpose of comprehending the behavior of materials and creating new technologies, the study of matter and its phases is crucial.
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155.7 grams of xenon gas is collected from the air. How many moles of xenon gas will be in the sample?
Inferring from this, the sample contains roughly 1.186 moles of xenon gas.
The STP uses what formula to determine moles?Number of moles = Molar volume at STP litres/V o l u m e ITP litres is the formula to calculate the number of moles at STP.
We need to utilise the molar mass of xenon, which is roughly 131.3 g/mol, to calculate the amount of xenon gas in the sample. The number of moles is then determined by dividing the gas's mass, which is given, by its molar mass:
Number of moles = Mass of gas / Molar mass of gas
Number of moles = 155.7 g / 131.3 g/mol
Number of moles = 1.186 moles (rounded to three decimal places)
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What concentration do you get when you dissolve 3 g NaCl in 100ml of water?
The NaCl solution has a 30 g/L concentration.
What is NaCl?Sodium chloride, or NaCl, is a chemical compound that is frequently referred to as table salt. It is an ionic compound comprised of chloride anions and sodium cations (Na+) (Cl-). At room temperature, NaCl is a white, crystalline solid that is very soluble in water.
How do you determine it?Let's start by converting the solution's volume from milliliters to liters:
100 ml = 100/1000 L = 0.1 L
Then, we can use the following formula to determine the solution's concentration:
concentration = amount of solute / volume of solution
replacing the specified values:
concentration = 3 g / 0.1 L = 30 g/L
As a result, the NaCl solution has a 30 g/L concentration.
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how many moles of a monoprotic acid would be needed to react completely with 25 ml of a 1.10 m naoh solution
One mole of a monoprotic acid would be needed to react completely with 25 ml of a 1.10 M NaOH solution.
An acid is a compound that releases a proton (H+) when dissolved in water, whereas a base is a compound that accepts a proton when dissolved in water. When an acid and a base combine, a neutralization reaction occurs. The products of this reaction are water and a salt (ionic compound).
Neutralization is a chemical reaction that occurs between an acid and a base, resulting in a salt and water. This reaction entails the transfer of electrons from the base to the acid, forming water molecules and an ionic compound known as a salt. This reaction can be categorized into five types, depending on the combination of acid and base used.
The general formula for the neutralization reaction is:
HA + BOH → BA + H2O , where HA represents an acid, BOH represents a base, BA represents a salt, and H2O represents water. To react completely with 25 mL of a 1.10 M NaOH solution, you would need 0.0275 moles of a monoprotic acid.
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How do I solve these?
The pressure exerted by the female's stiletto heel on the hard maple floor is approximately 76.1 psi.
The force that the woman is applying to the door = 300 N/m² * 0.0200 m²
Force is 6 N
How is the pressure determined?First, we need to convert the weight of the female from pounds to pounds-force.
Since weight is a force that is due to gravity, we can use the equation:
force = mass x acceleration due to gravity
The acceleration due to gravity is approximately 32.2 feet per second squared, so we can calculate the force as:
force = mass x acceleration due to gravity
force = 120 lbs x (1 lb-force/32.2 ft/s^2)
force = 3.73 lb-force
Next, we need to calculate the area of the heel in contact with the floor. We can use the formula for the area of a circle:
area = π x (diameter/2)^2
Plugging in the values given, we get:
area = π x (0.25 in/2)^2 = 0.049 in^2
Now we can calculate the pressure as the force divided by the area:
pressure = force/area = 3.73 lb-force / 0.049 in^2
pressure = 76.1 psi
2. Force = Pressure * area
The force that the woman is applying to the door = 300 N/m² * 0.0200 m²
Force = 6 N
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___C2H2 + ___O2 ---> ____CO2 + ____H2O
1. during proper cool-down activities, the aerobic energy system helps remove lactic acid by converting it to fuel. a. true b. false
False. During proper cool-down activities, the body's aerobic energy system can help remove lactic acid from the muscles, but it does not convert it into fuel.
Lactic acid is converted into lactate, which is then transported to the liver where it is converted back into glucose through a process called gluconeogenesis. This glucose can then be used as fuel by the body. During intense exercise, the body relies heavily on the aerobic energy system to produce energy quickly. This results in the production of lactic acid, which can lead to muscle fatigue and soreness.
During the cool-down period, the body's aerobic energy system takes over to restore energy stores and remove waste products, including lactic acid. However, instead of converting lactic acid to fuel, it is actually converted into pyruvate, which then enters the mitochondria of the cell and undergoes aerobic respiration to produce ATP (adenosine triphosphate) – the primary source of energy for the body. The aerobic energy system helps remove lactic acid by converting it into pyruvate, which is then used as fuel for the production of ATP through aerobic respiration.
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a 25.0 ml sample of a saturated caoh2 solution is tritrated with and the equiavence what is the concentration of the hydroxide ion
The concentration of the hydroxide ion in the saturated Ca(OH)₂ solution is 0.080 M.
To calculate the concentration of hydroxide ion in the saturated Ca(OH)₂ solution, we need to use the results of the titration.
Assuming that the titrant is a strong acid, the balanced chemical equation for the reaction is; H⁺ + OH⁻ → H₂O
The equivalence point of the titration is reached when all of the hydroxide ions in the saturated Ca(OH)₂ solution have reacted with the acid. At this point, the moles of H⁺ added equals the moles of OH⁻ in the original solution. Therefore, we can use the volume and concentration of the titrant, along with the volume of the saturated Ca(OH)₂ solution, to calculate the concentration of OH⁻.
Let's assume that the titrant used is 0.1 M HCl, and that it took 20.0 ml of HCl to reach the equivalence point. This means that 20.0 ml of HCl contains 0.002 moles of H⁺ ions. Since the reaction is 1:1, there are also 0.002 moles of OH⁻ ions in the original 25.0 ml of saturated Ca(OH)₂ solution.
To calculate the concentration of OH⁻ in the saturated Ca(OH)₂ solution, we can use the following equation.
OH⁻ concentration = moles of OH⁻ /volume of solution
OH⁻ concentration = 0.002 moles / 0.025 L
OH⁻ concentration = 0.080 M
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5. Balance each equation.
a. FeCl3 + NaOH →→ Fe(OH)3 + NaCl
b. CS₂ + Cl₂- → CCl4 + S₂Cl₂
c. KI + Pb(NO3)2 Pbl₂+ KNO3
d. C₂H₂ + O₂ CO₂ + H₂O
Answer:
a. FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
b. CS₂ + 3Cl₂ → CCl₄ + S₂Cl₂
c. 2KI + Pb(NO₃)₂ → PbI₂ + 2KNO₃
d. C₂H₂ + 2.5O₂ → 2CO₂ + H₂O
Note: In equation d, the coefficients have to be balanced using fractional numbers.
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which substance would not work as a grignard reagent? select one: phenylmagnesium chloride isopropylmagnesium chloride ethylmagnesium bromide methylcalcium bromide
phenylmagnesium chloride isopropylmagnesium chloride ethylmagnesium bromide methylcalcium bromide. It is not a Grignard reagent.
A Grignard reagent is made up of an organomagnesium halide that has a general formula of RMgX, where R is an organic group, and X is a halogen (most often chlorine, bromine, or iodine). A Grignard reagent can be used to make carbon-carbon bonds with various alkyl, vinyl, and aryl halides, ketones, and aldehydes.
Methylcalcium bromide is the substance that would not work as a Grignard reagent. A Grignard reagent, as previously stated, is an organomagnesium halide. When calcium is added to the solution, it precipitates. When the solution is diluted or extracted, calcium is commonly seen as a white, fluffy solid. Calcium has a lower electronegativity than magnesium, which means it will not create a Grignard reagent as magnesium does.
As a result, methylcalcium bromide is not a Grignard reagent. Phenylmagnesium chloride, isopropylmagnesium chloride, and ethylmagnesium bromide are examples of Grignard reagents. Grignard reagents are mostly used in organic synthesis, especially in the formation of carbon-carbon bonds.
Therefore phenylmagnesium chloride isopropylmagnesium chloride ethylmagnesium bromide methylcalcium bromide is not a Grignard reagent.
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tar sand (oil sand) is group of answer choices the result of biodegradation by plant material in the bottom of swamps. easy to extract and therefore a lucrative unconventional reserve. the residue of larger molecules left behind after microbes attack existing underground oil reserves. sand or sandstone that contains high concentrations of macerals (complicated carbon molecules).
Tar is not a lucrative unconventional reserve as it is not easy to extract tar sands.
The given statement is referring to tar sands (oil sands) which is a group of sedimentary rocks containing sand, clay, water, and a thick, molasses-like substance called bitumen (tar). Tar sand is the residue of larger molecules left behind after microbes attack existing underground oil reserves. Tar sand is found in sand or sandstone that contains high concentrations of macerals (complicated carbon molecules). It is not easy to extract tar sands as it requires expensive extraction methods that are not yet viable due to low oil prices. Therefore, it is not a lucrative unconventional reserve.
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liam needs to complete parts b and c of the lab. how should he decide which salts to test when investigating the effects of anions on ph? group of answer choices liam should choose salts that have both cations and anions liam should choose salts that have neutral cations liam should choose salts that have acidic or basic cations liam should choose salts that have acidic or basic anions liam should choose salts that have neutral anions
To investigate the effects of anions on pH, option d- Liam should choose salts that have acidic or basic anions.
This is because the anions in a salt can react with water to produce either an acidic or basic solution. The choice of cation is not as important, as neutral cations will not affect the pH of the solution. Therefore, option (d) is the most appropriate choice for Liam.
To elaborate further, when a salt is dissolved in water, it dissociates into its respective cation and anion. The anion, in particular, can interact with water to form either an acidic or basic solution. For example, chloride ions (Cl-) do not have any acidic or basic properties, and therefore, will not affect the pH of a solution.
However, nitrate ions (NO) are basic anions and can hydrolyze to form hydroxide ions (OH-) and increase the pH of the solution.
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Determine the mass, in grams, of 0.485 moles of Mn with correct sig figs When copper is heated with an excess of sulfur, copper(I) sulfide is formed. In a given experiment, 0.0970 moles of copper was heated with excess sulfur to yield 5.13 g copper(I) sulfide. What is the percent yield
The mass of 0.485 moles of Mn is 26.7 g, and the percent yield of copper(I) sulfide in the given experiment is 66.3%.
What is the mass of 0.485 moles of Mn and the percent yield of copper(I) sulfide in a given experiment?
To determine the mass of 0.485 moles of Mn, we need to use the molar mass of Mn, which is 54.94 g/mol:
Mass = moles x molar mass
Mass = 0.485 mol x 54.94 g/mol
Mass = 26.7 g (with 3 significant figures)
Therefore, the mass of 0.485 moles of Mn is 26.7 g (with 3 significant figures).
Now, to calculate the percent yield of copper(I) sulfide in the given experiment:
The balanced chemical-
equation for the reaction is:
2 Cu + S → Cu2S
We can see from the equation that 2 moles of Cu react with 1 mole of S to generate 1 mole of Cu2S.
Given that 0.0970 moles of Cu-
was used in the reaction, we can calculate the theoretical yield of Cu2S:
2 moles of Cu react to form 1 mole of Cu2S
0.0970 moles of Cu reacts to form (0.0970/2) moles of Cu2S
= 0.0485 moles of Cu2S
Using the molar mass of Cu2S (159.17 g/mol), we can calculate the theoretical mass of Cu2S:
Mass = moles x molar mass
Mass = 0.0485 mol x 159.17 g/mol
Mass = 7.73 g
Therefore, the theoretical yield of Cu2S is 7.73 g.
The percent yield is calculated as follows:
Percent Yield =
(Actual Yield / Theoretical Yield) x 100%
Actual Yield = 5.13 g (given)
Theoretical Yield = 7.73 g
Percent Yield = (5.13 g / 7.73 g) x 100%
Percent Yield = 66.3%
Therefore, the percent yield of copper(I) sulfide in the given experiment is 66.3%.
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(17 points)
A chemical equation is given below. How would you classify this reaction?
2AgNO3 + Mg(OH)2 ------ 2AgOH + Mg(NO3)2
A. single replacement
B. double replacement
C. decomposition
D. combustion
Answer:
The chemical equation 2AgNO3 + Mg(OH)2 → 2AgOH + Mg(NO3)2 represents a double replacement reaction. In this type of reaction, the cations and anions of two different compounds exchange places with each other to form two new compounds. In the given equation, silver nitrate (AgNO3) reacts with magnesium hydroxide (Mg(OH)2) to form silver hydroxide (AgOH) and magnesium nitrate (Mg(NO3)2).
Answer:
double replacement
Explanation:
the equilibrium constant, kc, at 500oc is 3.8 x 10-4. which is present in the larger amount: reactants or products?
At equilibrium, reactants will be present in the larger amount compared to the products.
The equilibrium constant (Kc) is a measure of the relative concentrations of products and reactants at equilibrium. Kc is defined as the product of the concentrations of the products raised to their stoichiometric coefficients, divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.
In this case, Kc = 3.8 x 10^-4 at 500°C. This value of Kc tells us that the concentration of products at equilibrium is relatively low compared to the concentration of reactants. In other words, the reaction strongly favors the formation of reactants over products.
Therefore, at equilibrium, reactants will be present in the larger amount compared to the products.
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