For y=f(x) = x^4 - 7x + 5, find dy and Δy, given x = 5 and Δx=0.2.

Answers

Answer 1

The derivative of y=f(x) = x⁴ - 7x + 5 is dy/dx = 4x³ - 7. For x = 5 and Δx=0.2, dy = 1.986 and Δy = -54.5504.

Given the function y = f(x) = x⁴ - 7x + 5, we can find its derivative with respect to x using the power rule of differentiation:

dy/dx = d/dx(x⁴) - d/dx(7x) + d/dx(5) = 4x³ - 7

Now, we can use the given value of x = 5 and Δx = 0.2 to find the values of dy and Δy:

dy = (4x³ - 7) dx, evaluated at x = 5 and Δx = 0.2

dy = (4(5)³ - 7) (0.2) = 198.6 × 10^(-2)

This means that a small change of 0.2 in x results in a change of about 1.986 in y.

To find Δy, we use the formula:

Δy = f(x + Δx) - f(x)

Substituting x = 5 and Δx = 0.2, we get:

Δy = ((5 + 0.2)⁴ - 7(5 + 0.2) + 5) - (5⁴ - 7(5) + 5)

Simplifying this expression gives:

Δy = (122.4496 - 177) = -54.5504

This means that a small change of 0.2 in x results in a change of about -54.5504 in y.

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Related Questions

For exercise, a softball player ran around the bases 12 times in 15 minutes. At the same rate, how many times could the bases be circled in 50 minutes?

Answers

The bases could be circled 40 times in 50 minutes at the same rate.

To solve this problem

For this issue's solution, let's use unit rates.

In order to calculate the unit rate,

Considering that the player went 12 times around the bases in 15 minutes, the unit rate is 12/15, =  0.8 times per minute.

In a minute, the player would have circled the bases 0.8 times. By dividing the unit rate by the number of minutes, we can calculate how many times the bases could be circled in 50 minutes:

50 minutes x  0.8 times each minute = 40 times.

Therefore, the bases could be circled 40 times in 50 minutes at the same rate.

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Mrs. Sonora used 1/2 gallon of milk for a pudding recipe how many cups did she use for the recipe?

Answers

Answer: 8 cups

Step-by-step explanation: 16 cups in a gallon, Half of 16 is 8. (16 divided by 2 = 8)

a gambler is going to play a gambling game. in each game, the chance of winning $3 is 2/10, the chance of losing $2 is 3/10, and the chance of losing $1 is 5/10. suppose the gambler is going to play the game 5 times. (a) write down the box model for keeping track of the net gain. (you already did this in a previous lab.) (b) now write down the box model for keeping track of the number of winning plays. (c) calculate the expected value and standard error for the number of winning plays. (d) would it be appropriate to use the normal approximation for the number of winning plays? why or why not?

Answers

The  expected value and standard error for the number of winning plays is $3.1 and $ 2.21.

The population mean's likelihood to differ from a sample mean is indicated by the standard error of a mean, and simply standard error.

It reveals how much what the sample mean will change if a study were to be repeated with fresh samples drawn from a single population.

Chance of winning $3 = 2/10

chance of losing $2 = 3/10

chance of losing $1 = 5/10

Average of tickets. = - $2.50

SD of tickets = $1.80.

The box model for net gain has 2 tickets labeled $3, 3 tickets labeled $2, 5 tickets labeled

a) Expected value for the net gain.

The Expected value for net = ∑ x.p(x)

Here

can take value $1, $2 and $3

Here p(x) us the probability of winning respectively.

So, Now, Expected gain is,

(2 x 3 x 2/10) + (3 x -2 x 7/10) + (5 x -1 x 5/10)

= 12/10 - 18/10 - 25/10

= -31/10 = -$3.1.

b) Standard error of the net gain,

S.D = [tex]\sqrt{E(x^2) - [E(x)]^2}[/tex]

Now E(x²) = (2 x 3² x 2/10) + (3 x -2² x 7/10) + (5 x -1² x 5/10)

= 36/10 + 84/10 + 25/10 = 145/10

= $ 14.5

SD = [tex]\sqrt{14.5 - 3.1}\\[/tex]

SD = $ 2.21

c) Chance that the net gain is $15

P(X=15) = (z = 15-(-2.50)/1.80

= P(z=9.72) = 0.99.

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Andrew went deep sea diving with some friends. If he descends at a rate of 4 feet per minute, what integer represents Andrews depth in ¼ of an hour?

Answers

The integer that represents Andrews depth in ¼ of an hour is 60 feet.

How to determine what integer represents Andrews depth in 1/4 of an hour?

Word problems are sentences describing a 'real-life' situation where a problem needs to be solved by way of a mathematical calculation e.g. calculation of length and depth.

If Andrew descends at a rate of 4 feet per minute and we want to find his depth in ¼ of an hour.

1/4 of an hour = (1/4 * 60) minutes = 15 minutes

Thus, the integer that represents Andrews depth in ¼ of an hour will be:

(4 feet per minute) * (15 minutes) = 60 feet

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Fred goes to Old Navy and buys two pairs of jeans for $17. 99 each, three shirts at $5. 99 each, and a pack of socks for $3. He has a coupon for 25% off his entire purchase. Sales tax is 6. 5%. What is the total cost after the discount and tax?


A: $43. 07


B: $39. 95


C: $45. 49


D: $60. 65

Answers

The total cost after discount and tax is $46.28.

To find the total cost after the discount and tax, we need to first find the subtotal before tax.

Fred bought two pairs of jeans for $17.99 each, so the cost of the jeans is $17.99 x 2 = $35.98.

He also bought three shirts at $5.99 each, so the cost of the shirts is $5.99 x 3 = $17.97.

The pack of socks costs $3.

The subtotal before discount is $35.98 + $17.97 + $3 = $57.95.

With the 25% off coupon, Fred gets a discount of $57.95 x 0.25 = $14.49.

The new subtotal after discount is $57.95 - $14.49 = $43.46.

Finally, we need to add the 6.5% sales tax.

The sales tax is $43.46 x 0.065 = $2.82.

The total cost after discount and tax is $43.46 + $2.82 = $46.28.

Therefore, the closest answer is C: $45.49.

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Laura is driving to Los Angeles. Suppose that the remaining distance to drive (in miles) is a linear function of her driving time (in minutes). When graphed, the function gives a line with a slope of -0.85. See the figure below. Laura has 52 miles remaining after 41 minutes of driving. How many miles were remaining after 33 minutes of driving?

Answers

The remaining distance after 33 minutes of driving = 58.8 miles.

Here, the slope of a linear function the remaining distance to drive (in miles) is -0.85

For this situation, we can write a linear equation as,

remaining distance = (slope)(drive time) + (intercept)

remaining distance = -0.85(drive time) + (intercept)      

y =  -0.85x + c        ..........(1)

where y represents the remaining distance

x is the drive time

and c is the y-intercept

Here, Laura has 52 miles remaining after 41 minutes of driving.

i.e., x = 41 and y = 52

Substitute these values in equation (1)

52 =  -0.85(41) + c    

c = 52 + 34.85

c = 86.85

So, equation (1) becomes,

y =  -0.85x + 86.85

Now, we need to find the remaining distance after 33 minutes of driving.

i.e., the value of y for x = 33

y =  -0.85(33) + 86.85

y =  -28.05 + 86.85        

y = 58.8

This is the remaining distance 58.8 miles.

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Q5. Compute the trapezoidal approximation for | Vx dx using a regular partition with n=6.

Answers

The trapezoidal approximation for | Vx dx using a regular partition with n=6 is approximately 0.1901.

How to find the trapezoidal approximation for a function?

To compute the trapezoidal approximation for | Vx dx using a regular partition with n=6, we can use the formula:

Tn = (b-a)/n * [f(a)/2 + f(x1) + f(x2) + ... + f(xn-1) + f(b)/2]

where Tn is the trapezoidal approximation, n=6 is the number of partitions, a and b are the limits of integration, and x1, x2, ..., xn-1 are the partition points.

In this case, we have | Vx dx as the function to integrate. Since there are no given limits of integration, we can assume them to be 0 and 1 for simplicity.

So, a=0 and b=1, and we need to find the values of f(x) at x=0, 1/6, 2/6, 3/6, 4/6, and 5/6 to use in the formula.

We can calculate these values as follows:

f(0) = | V0 dx = 0

f(1/6) = | V1/6 dx = V(1/6) - V(0) = sqrt(1/6) - 0 = 0.4082

f(2/6) = | V2/6 dx = V(2/6) - V(1/6) = sqrt(2/6) - sqrt(1/6) = 0.2317

f(3/6) = | V3/6 dx = V(3/6) - V(2/6) = sqrt(3/6) - sqrt(2/6) = 0.1547

f(4/6) = | V4/6 dx = V(4/6) - V(3/6) = sqrt(4/6) - sqrt(3/6) = 0.1104

f(5/6) = | V5/6 dx = V(5/6) - V(4/6) = sqrt(5/6) - sqrt(4/6) = 0.0849

Now we can substitute these values in the formula and simplify:

T6 = (1-0)/6 * [0/2 + 0.4082 + 0.2317 + 0.1547 + 0.1104 + 0.0849/2]
   = 0.1901

Therefore, the trapezoidal approximation for | Vx dx using a regular partition with n=6 is approximately 0.1901.

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If Franco's Pizza Parlor knows that the marginal cost of the 500th pizza is $3.50 and that the average total cost of making 499 pizzas is $3.30, then
a. average total costs are falling at Q = 500.
b. average variable costs must be falling.
c. average total costs are rising at Q = 500.
d. total costs are falling at Q = 500.

Answers

If Franco's Pizza Parlor knows that the marginal cost of the 500th pizza is $3.50 and that the average total cost of making 499 pizzas is $3.30, then Average total costs are rising at Q = 500. The correct answer is (c)

The marginal cost is the additional cost of producing one more unit. In this case, the marginal cost of the 500th pizza is $3.50.

The average total cost is the total cost of producing all units up to a certain level, divided by the number of units produced. In this case, the average total cost of making 499 pizzas is $3.30.

If the marginal cost of producing the 500th pizza is greater than the average total cost of making the first 499 pizzas, then the average total cost will increase when the 500th pizza is produced.

Therefore, the correct answer is (c) average total costs are rising at Q = 500.

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if x varies directly as T and x=105 when T=400, find x when T=500​

Answers

Answerx = 131.25

Step-by-step explanation:f x varies directly as T, then we can use the formula for direct variation:

x = kT

where k is the constant of proportionality.

To find k, we can use the given values:

x = 105 when T = 400

105 = k(400)

k = 105/400

k = 0.2625

Now that we have the value of k, we can use the formula to find x when T = 500:

x = kT

x = 0.2625(500)

x = 131.25

Therefore, when T = 500, x is equal to 131.25.

Solve for x WILL MAKE BRAINLIEST QUESTION IN PHOTI ALSO

Answers

The measure of x in the intersected chord is 16.

How to find the angle in an intersected chord?

If two chords intersect in a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle.

Using the chord intersection angle theorem,

5x - 7  = 1 / 2 (119 + 27)

5x - 7 = 1 / 2 (146)

5x - 7 = 73

add 7 to both sides of the equation

5x - 7 = 73

5x - 7 + 7 = 73 + 7

5x = 80

divide both sides of the equation by  5

x = 80 / 5

x = 16

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A particle moves along the x-axis with velocity given by v(t) = 3t2 + 6t for time t ≥ 0. If the particle is at position x = 2 at time t = 0, what is the position of the particle at t = 1?

Answers

The position of the particle at time t = 1 is x = 4 units.

What is the position of a particle that moves along the x-axis with velocity v(t) = [tex]3t^2[/tex] + 6t at time t = 1 if it is at position x = 2 at time t = 0?

To find the position of the particle at time t = 1, we need to integrate the given velocity function v(t) with respect to time from 0 to 1:

x(t) = ∫v(t)dt (from t = 0 to t = 1)

= ∫([tex]3t^2[/tex]+ 6t)dt (from t = 0 to t = 1)

= ([tex]t^3 + 3t^2[/tex]) (from t = 0 to t = 1)

[tex]= (1^3 + 3(1^2)) - (0^3 + 3(0^2))[/tex]

= 4

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Find the volume of the cone to the nearest whole number. Use 3. 14


for it.


Cone


Radius Height


Volume


varrh


Worms


3in.


6in.


Tree


Gum

Answers

The volume of the cone is 57 cubic inches. To find the volume of the cone, we use the formula: V = (1/3)π[tex]r^{2}[/tex]h, where r is the radius of the cone, h is the height of the cone, and π is approximately 3.14.

Given that the radius of the cone is 3 inches and the height is 6 inches, we can substitute these values into the formula and solve for V: V = (1/3)π([tex]3^{2}[/tex])(6), V = (1/3)π(9)(6), V = (1/3)(3.14)(54), V = 56.52 cubic inches

Rounding to the nearest whole number, the volume of the cone is 57 cubic inches.

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A. Directions:translate each problem into algebraic expression or equation and identify the variable/s.

1. Julie weighs c kilogram. After going to gym for six months, she lost 2. 5 kilograms. Express her weight algebraically.

2. Peter is m centimeter tall. Jhon's height is 5 more than twice the height of Peter. How tall is Jhon?

3. Ador is thrice older than Emy. If Emy is d years old less than 9,how old is ador?

4. Jupiter is n years old now. How old is Jupiter 7 years from now?

5. Anna's sister is p years old. Anna is 4 years older than thrice the age of her sister. How old is Anna?

guys please help me please

Answers

lets assume.

Algebraic expression: c - 2.5. The variable is c, which represents Julie's initial weight in kilograms.

Algebraic equation: Jhon's height = 2m + 5. The variables are m, which represents Peter's height in centimeters, and the height of Jhon, which is represented by the equation.

Algebraic equation: Ador's age = 3(Emy's age - d). The variables are Ador's age and Emy's age, which is d years less than 9.

Algebraic expression: n + 7. The variable is n, which represents Jupiter's current age in years.

Algebraic equation: Anna's age = 3p + 4. The variables are p, which represents Anna's sister's age in years, and Anna's age, which is represented by the equation.

SO ANNA  current age is P=3+4

and p=7

Anna's age = 3p + 4, where p is the age of Anna's sister in years, and Anna is 4 years older than thrice the age of her sister.

If Anna's sister is 10 years old, how old is Anna according to the equation?Algebraic expression: c - 2.5, where c is the weight of Julie in kilograms, and 2.5 is the weight she lost after six months of going to the gym.

Algebraic equation: Jhon's height = 2m + 5, where m is the height of Peter in centimeters, and Jhon's height is 5 more than twice the height of Peter.

Algebraic equation: Ador's age = 3(Emy's age - d), where Emy is d years less than 9, and Ador is thrice older than Emy.

Algebraic equation: Jupiter's age 7 years from now = n + 7, where n is Jupiter's current age in years.

Algebraic equation: Anna's age = 3p + 4, where p is the age of Anna's sister in years, and Anna is 4 years older than thrice the age of her sister.

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Use matrices A, B, C and D. A = Find CD a. 2 3 0 -5 b. 27 -29 -7 31.0 -384-1 2 6 -6 -6 4 -2 -27 18 -9 -12 8 -4 2 Mark this and return C = 9 and D= [-3 2 -1] C. Please select the best answer from the choices provided | ** - 16 24 -8 0 -40 32 Save and Evil​

Answers

The product of matrices C and D is:

[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]

The best answer is option b.

How to find the product of two matrices?

A matrix (plural matrices) is a set of numbers arranged in rows and columns so as to form a rectangular array.

The number of rows of a matrix can be determined by counting from top to bottom and the number of columns can be determined by counting from left to right.

The product (multiplication) of matrices C and D is:

CD = C * D

[tex]CD = \left[\begin{array}{ccc}2\\9\\4\end{array}\right] * \left[\begin{array}{ccc}-3&2&-1\\\end{array}\right][/tex]

To get the product, multiply each row by the column. That is:

2 * (-3) = -6

9 * 2 = 18

4 * (-1) = -4

[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]

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a fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. they want to construct a 85% confidence interval with an error of no more than 0.06 . a consultant has informed them that a previous study found the mean to be 4.9 fast food meals per week and found the standard deviation to be 0.9 . what is the minimum sample size required to create the specified confidence interval? round your answer up to the next integer.

Answers

The minimum sample size which is need to to create the given confidence interval is equal to 467.

Sample size n

z = z-score for the desired confidence level

From attached table,

For 85% confidence level, which corresponds to a z-score of 1.44.

Maximum error or margin of error E = 0.06

Population standard deviation σ = 0.9

Minimum sample size required to construct a 85% confidence interval with an error of no more than 0.06,

Use the formula,

n = (z / E)^2 × σ^2

Plugging in the values, we get,

⇒ n = (1.44 / 0.06)^2 × 0.9^2

⇒ n = 466.56

Rounding up to the next integer, we get a minimum sample size of 467.

Therefore, the minimum sample size required to construct a 85% confidence interval with an error of no more than 0.06 is 467.

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A license plate is made of three letters and three numbers, how many different license plates are possible?

Answers

There are 17,576,000 different license plates possible, considering 26 letters (A-Z) and 10 numbers (0-9).

There are 26 options for each of the three letters and 10 options for each of the three numbers. Therefore, using the multiplication principle, the total number of possible license plates is 26 x 26 x 26 x 10 x 10 x 10 = 17,576,000.

Alternatively, we can use the permutation formula to calculate the number of arrangements: P(26,3) x P(10,3) = 15,600 x 720 = 11,251,200.

However, since order does not matter in a license plate, we need to divide by the number of permutations of three letters and three numbers, which is 3! x 3! = 36, resulting in 11,251,200 / 36 = 17,576,000 possible license plates.

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A company manufactures to types of cabinets, type 1 and type 2. It produces 110 total cabinet’s each week.

Last week, the number of type 2 cabinets produced exceeded twice the number of type 1 cabinets produced by 20. If x is the number of type 1 cabinets produced and y is the number of type 2 cabinets produced, the system of equations that represent this situation is x + y = 110 and y = 2x+20

The number of type 2 cabinets produced last week is ____. This number exceeds the number of type 1 cabinets produced durin the week by ______.

Answers

The number of type 2 cabinets produced last week is 80. The number of type 2 cabinets produced last week exceeded the number of type 1 cabinets produced during the week by 50.

Using the system of equations given, we can solve for the number of type 1 and type 2 cabinets produced.

x + y = 110 represents the total number of cabinets produced, where x is the number of type 1 cabinets and y is the number of type 2 cabinets produced.

y = 2x + 20 represents the relationship between the number of type 1 and type 2 cabinets produced. This equation tells us that the number of type 2 cabinets produced exceeds twice the number of type 1 cabinets produced by 20.

To solve for y, we substitute the value of y from the second equation into the first equation:

x + (2x + 20) = 110

Simplifying this equation:

3x + 20 = 110

3x = 90

x = 30

Therefore, the number of type 1 cabinets produced last week is 30.

To find the number of type 2 cabinets produced, we substitute x = 30 into the second equation:

y = 2x + 20 = 2(30) + 20 = 80

The number of type 2 cabinets produced last week exceeds the number of type 1 cabinets produced during the week by:

80 - 30 = 50.

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Find f'(4) for f(x) = ln (2x^3"). Answer as an exact fraction or round to at least 2 decimal places.

Answers

To find f'(4) for the function f(x) = ln(2x^3), we first need to find the derivative f'(x) using the chain rule.

The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.

For f(x) = ln(2x^3), the outer function is ln(u) and the inner function is u = 2x^3.

The derivative of the outer function, ln(u), is 1/u.
The derivative of the inner function, 2x^3, is 6x^2 (using the power rule).

Now, apply the chain rule: f'(x) = (1/u) * 6x^2 = (1/(2x^3)) * 6x^2.

Simplify f'(x): f'(x) = 6x^2 / (2x^3) = 3/x.

Now, find f'(4): f'(4) = 3/4.

So, f'(4) for f(x) = ln(2x^3) is 3/4 or 0.75 when rounded to 2 decimal places.

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In ΔVWX, w = 4.7 inches, v = 2.4 inches and ∠V=8°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answers

The value of W to the nearest tenth of degree is 15.8°

What is sine rule?

The sine rule states that if a, b and c are the lengths of the sides of a triangle, and A, B and C are the angles in the triangle; with A opposite a, etc., then a/sinA=b/sinB=c/sinC.

Sine rule can be used to find unknown side or angle In a triangle.

w/sinW = v/sinV

4.7/sinW = 2.4 / sin8

2.4sinW = 4.7 sin8

2.4sinW = 0.654

sinW = 0.654/2.4

sinW = 0.273

W = sin^-1( 0.273)

W = 15.8° ( nearest tenth)

therefore the value of W is 15.8°

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Every line segment used to make this hospital logo is 3 meters long. What is the total area of the logo in square meters?

Answers

Without an image I can’t really tell the exact area of the logo but if I had to use this I formation only I would say maybe 13.5 square meters.

There were three ant hills in Mrs. Brown's yard. The first ant hill had 4,867,190 ants. The second ant hill had 6,256,304 ants, and the third ant hill had 3,993,102 ants. Choose the best estimate of the number of ants in Mrs. Brown's yard

Answers

The best estimate of the number of ants in Mrs. Brown's yard is 15,116,596.

What is arithmetic sequence?

An arithmetic sequence is a sequence of numbers in which each term after the first is found by adding a fixed constant number, called the common difference, to the preceding term.

Mrs. Brown's yard has three ant hills, each with a different number of ants. To estimate the total number of ants in the yard, we simply add up the number of ants in each hill.

The first hill has 4,867,190 ants, the second has 6,256,304, and the third has 3,993,102. When we add these numbers together, we get a total of 15,116,596 ants in Mrs. Brown's yard. Of course, this is just an estimate, as there may be other ant hills or individual ants scattered around the yard.

However, this calculation gives us a good approximation of the number of ants in the yard based on the information given.

To estimate the total number of ants in Mrs. Brown's yard, we can add up the number of ants in each of the three ant hills:4,867,190 + 6,256,304 + 3,993,102 = 15,116,596.

Therefore, the best estimate of the number of ants in Mrs. Brown's yard is 15,116,596.

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Find an angle \thetaθ coterminal to -497^{\circ}−497 ∘

, where 0^{\circ}\le\theta<360^{\circ}0 ∘

≤θ<360 ∘

Answers

The correct answer for an angle coterminal to -497° within the interval 0°≤θ≤360° is 223°.

What are Coterminal angles?

Coterminal angles are angles that share the same initial and terminal sides when drawn in the standard position (starting from the positive x-axis) on the coordinate plane. In other words, coterminal angles are angles that differ by an integer multiple of 360° or 2π radians.

To find an angle coterminal to within the interval use the fact that to add or subtract a multiple of to an angle does not change its position on the unit circle.

To make the angle positive, add  360°  repeatedly until an angle within the desired interval is obtained:

= -497° +360°

= -137°

adjust this angle to be within the interval 0°≤θ≤360°, and add another 360°:

= -137° + 360°

= 223°

The required angle is 223°.

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An angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.

Given that; the angle is, -497 degrees.

Now, for an angle coterminal to -497 degrees within the range 0≤θ<360 degrees, add or subtract multiples of 360 degrees until we get an angle within the desired range.

Now, add multiples of 360 degrees until we get a positive angle:

-497 + 360 = -137

Now we have an angle of - 137 degrees, but it is still not within the desired range of 0 ≤ θ < 360 degrees.

To adjust the angle, add 360 degrees to it:

-137 + 360 = 223

Now an angle of 223 degrees, which is within the desired range.

Therefore, an angle θ coterminal to -497 degrees, where 0 ≤ θ < 360 degrees, is 223 degrees.

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Describe the end behavior of
f(x)= -x² -1

show steps

Answers

As the x-values go to either positive or negative infinity, the function decreases towards negative infinity.

Step 1: Identify the degree and leading coefficient.
In f(x) = -x² - 1, the degree is 2 (the highest power of x), and the leading coefficient is -1.
Step 2: Determine the end behavior based on the degree and leading coefficient.
Since the degree is even (2) and the leading coefficient is negative (-1), we know that both ends of the graph will point in the same direction.

Step 3: Identify the specific end behavior.
Because the leading coefficient is negative, the graph of the function will open downward. As x approaches positive infinity, f(x) will decrease towards negative infinity. Similarly, as x approaches negative infinity, f(x) will also decrease towards negative infinity.

Step 4: Write the end behavior in a concise format.
The end behavior of f(x) = -x² - 1 can be written as:
As x → ±∞, f(x) → -∞.
In summary, the function f(x) = -x² - 1 has a downward-opening parabola due to its even degree and negative leading coefficient.

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Help me please first correct answer get branliest and please no essay

Answers

Answer:

6cm

Step-by-step explanation:

all the sides of a square are identical so we can assume the missing side as x

since all four sides are the same and the perimeter is the sum of all sides, we can write

x+x+x+x=24cm

4x=24cm

x=24/4

x=6cm

What is the area of the shaded part of the circle?

And also, I am so confused about how to do it so can someone help me pls?

Answers

The required area of the shaded part of the circle is 50.24 sq. cm

What is area of a circle?

A circle of radius r has an area of r2 in geometry. Here, the Greek letter  denotes the constant ratio of a circle's diameter to circumference, which is roughly equivalent to 3.14159.

According to question:

Given data:

Radius of small circle = 6/2 = 3 cm

Radius of big circle = 10/2 = 5 cm

then.

Area of shaded part = area of big circle - area of small circle

Area of shaded part = π(5)² -  π(3)²

Area of shaded part = 25π - 9π

Area of shaded part = 16π

Area of shaded part = 50.24 sq. cm

Thus, required area of the shaded part of the circle is 50.24 sq. cm

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A volleyball player’s serving percentage is 75%. Six of her serves are randomly selected. Using the table, what is the probability that at most 4 of them were successes?




A 2-column table with 7 rows. Column 1 is labeled number of serves with entries 0, 1, 2, 3, 4, 5, 6. Column 2 is labeled probability with entries 0. 0002, 0. 004, 0. 033, 0. 132, 0. 297, 0. 356, question mark.




0. 297



0. 466



0. 534



0. 822

Answers

To solve this problem, we first need to understand what "at most 4 of them were successes" means. This includes the cases where there are 0, 1, 2, 3, or 4 successful serves out of the 6 selected.

We can use the table to find the probabilities for each of these cases.

For 0 successful serves, the probability is 0.0002.

For 1 successful serve, the probability is 0.004.

For 2 successful serves, the probability is 0.033.

For 3 successful serves, the probability is 0.132.

For 4 successful serves, the probability is 0.297.

To find the probability of at most 4 successful serves, we add up these probabilities:
[tex]0.0002 + 0.004 + 0.033 + 0.132 + 0.297 = 0.466[/tex]

So the probability of at most 4 successful serves is 0.466.

Therefore, the answer is 0.466 and it is found by adding up the probabilities for the cases where there are 0, 1, 2, 3, or 4 successful serves out of the 6 selected from the table.

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Prove that the value of the expression: (36^5−6^9)(38^9−38^8) is divisible by 30 and 37.


_x30x37

Don't answer if you don't know

Answers

To prove that the expression (36^5−6^9)(38^9−38^8) is divisible by 30, we need to show that it is divisible by both 2 and 3.

First, we can factor out a 6^9 from the first term:

(36^5−6^9)(38^9−38^8) = 6^9(6^10-36^5)(38^9-38^8)

Notice that 6^10 can be written as (2*3)^10, which is clearly divisible by both 2 and 3. Also, 36 is divisible by 3, so 36^5 is divisible by 3^5. Thus, we can write:

6^9(6^10-36^5) = 6^9(2^10*3^10 - 3^5*2^10) = 6^9*2^10*(3^10 - 3^5)

Since 2^10 is divisible by 2, and 3^10 - 3^5 is clearly divisible by 3, the whole expression is divisible by both 2 and 3, and therefore divisible by 30.

To prove that the expression is divisible by 37, we can use Fermat's Little Theorem. Fermat's Little Theorem states that if p is a prime number and a is any positive integer not divisible by p, then a^(p-1) is congruent to 1 modulo p, which can be written as a^(p-1) ≡ 1 (mod p).

In this case, p = 37, and 36 is not divisible by 37. Therefore, by Fermat's Little Theorem:

36^(37-1) ≡ 1 (mod 37)

Simplifying the exponent gives:

36^36 ≡ 1 (mod 37)

Similarly, 38 is not divisible by 37, so:

38^(37-1) ≡ 1 (mod 37)

Simplifying the exponent gives:

38^36 ≡ 1 (mod 37)

Now we can use these congruences to simplify our expression:

(36^5−6^9)(38^9−38^8) ≡ (-6^9)(-1) ≡ 6^9 (mod 37)

We know that 6^9 is divisible by 3, so we can write:

6^9 = 2^9*3^9

Since 2 and 37 are relatively prime, we can use Euler's Totient Theorem to simplify 2^9 (mod 37):

2^φ(37) ≡ 2^36 ≡ 1 (mod 37)

Therefore:

2^9 ≡ 2^9*1 ≡ 2^9*2^36 ≡ 2^(9+36) ≡ 2^45 (mod 37)

Now we can simplify our expression further:

6^9 ≡ 2^45*3^9 ≡ (2^5)^9*3^9 ≡ 32^9*3^9 (mod 37)

Notice that 32 is congruent to -5 modulo 37, since 32+5 = 37. Therefore:

32^9 ≡ (-5)^9 ≡ -5^9 ≡ -1953125 ≡ 2 (mod 37)

So:

6^9 ≡ 2*3^9 ≡ 2*19683 ≡ 39366 ≡ 0 (mod 37)

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Let a,b,c and d be distinct real numbers. Show that the equation (x-b)(x-c) (x-d) + (x-a)(x-c)(x - d) + (x-a) (x-b)(x-d) + (x - a)(x-b)(x-c) has exactly 3 distinct roul solutions (Hint: Let p(x)= (x-a)(x-b)(x-c)(x-d). Then p(x) = 0 has how many distinct real solutions? Then use logarithmic differentiation to show that p'(x) is given by the expression on the left hand side of (1). Now, apply Rolle's theorem. )

Answers

There exists at least one c in the open interval (a, b) such that f'(c) = 0.

There are 3 distinct points where p'(x) = 0, which corresponds to the 3 distinct real solutions of the given equation.

To prove that the given equation has exactly 3 distinct real solutions, let's follow the steps mentioned in the question.

First, consider the polynomial p(x) = (x-a)(x-b)(x-c)(x-d). Since a, b, c, and d are distinct real numbers, p(x) has 4 distinct real roots, namely a, b, c, and d.

Now, let's find the derivative p'(x) using logarithmic differentiation. Taking the natural logarithm of both sides, we have:

[tex]ln(p(x)) = ln((x-a)(x-b)(x-c)(x-d))[/tex]

Differentiating both sides with respect to x, we get:

[tex]p'(x)/p(x) = 1/(x-a) + 1/(x-b) + 1/(x-c) + 1/(x-d)[/tex]

Multiplying both sides by p(x) and simplifying, we have:

[tex]p'(x) = (x-b)(x-c)(x-d) + (x-a)(x-c)(x-d) + (x-a)(x-b)(x-d) + (x-a)(x-b)(x-c)[/tex]

Now, we apply Rolle's Theorem, which states that if a function is continuous on the closed interval [a, b], differentiable on the open interval (a, b), and f(a) = f(b), then there exists at least one c in the open interval (a, b) such that f'(c) = 0.

Since p(x) has 4 distinct real roots, there must be 3 intervals between these roots where the function p(x) satisfies the conditions of Rolle's Theorem. Therefore, there are 3 distinct points where p'(x) = 0, which corresponds to the 3 distinct real solutions of the given equation.

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A right triangle has legs that are 17 centimeters and 28 centimeters long.

What is the length of the hypotenuse?

Enter your answer as a decimal, Round your answer to the nearest hundredth.

Answers

Answer: 4.5

Step-by-step explanation:

Frank keeps his pet iguana in a glass tank that is shaped like a rectangular prism.the height of the tank is 11 inches, the width is 34.5 inches, and the length is 25 inches.what is the best estimate for the volume of the tank in cubic feet?remember 12 inches = 1 foot.

Answers

The best estimate for the volume of the tank in cubic feet is 5.5 cubic feet.

The volume of the tank is:

V = l x w x h

where l is the length, w is the width, and h is the height.

Substituting the given values, we get:

V = 25 x 34.5 x 11 = 9547.5 cubic inches

To convert cubic inches to cubic feet, we divide by (12 x 12 x 12), since there are 12 inches in a foot and 12 x 12 x 12 cubic inches in a cubic foot:

V = 9547.5 / (12 x 12 x 12) cubic feet

V ≈ 5.5 cubic feet

Therefore, 5.5 cubic feet is the best estimate for the tank's cubic foot capacity.

Hence , the volume of the rectangular glass tank is 5.490 feet³

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