Answer:
6.12 m/s
Explanation:
In order to solve this we have two parts of this problem, first we have the time that the pizza dough spent going upwards and after that we have a free fall from there, so we will use the free fall formula after we figured out whats the final height the dough reached after being thrown from Francesco's height which is 6ft3inches or 1.90 meters
We first have to find out how much time the dough spent in the air before reaching 0 as final speed and then started the free falling:
The formula would be:
[tex]Vf=Vo-at\\0=1-(-9.81t)\\1=9.81t\\t=\frac{1}{9.81}\\t=.101[/tex]
The formula to find out final height would be:
[tex]y = \frac{ h + Vy (t-gt^{2})}{2} \\[/tex]
Now we just insert the values we know
[tex]y = h+ \frac{ Vy (t-gt^{2})}{2} \\\\y = 1.90 +\frac{ .101-(-9.81)(.101)^{2})}{2} \\\\y=1.91[/tex]
So from 1.91 meteres the free fal started we have to just calculate the final velocity with the formula for free fall and velocity:
[tex](vf)^{2} =Vo^2 +2ad[/tex]
Since Vo is 0 because we are talking about free falling we just insert the values we know:
[tex](vf)^{2} =Vo^2 +2ad\\(vf)^{2} =2ad\\(vf)^{2} =2(9.81)(1.91)\\vf=\sqrt{37.4742} \\Vf=6.12m/s[/tex]
So the final speed that the dough hit the ground with is 6.12 m/s
Electrically neutral objects become___when they or lose electrons.
Answer: positively charged
Explanation: basically when a neutral atom gets some electrons it becomes negatively charged and when a neutral atom loses elections it's positively charged Ik science is weird lol.
I hope this was the answer you were looking for.
Temperature is a measure of
Answer:
The average kinetic energy
The amount of heat a substance has or the average kinetic energy of particles in a substance
Help pls it’s urgent
list of energy changes when hydroelectricity city is made
Answer:
A turbine and generator produce the electricity
Explanation:
"A hydraulic turbine converts the energy of flowing water into mechanical energy. A hydroelectric generator converts this mechanical energy into electricity.
A 20-kg bicycle carrying a 50-kg girl is traveling with a kinetic energy of 2,290 J.
What is the velocity of the girl and bicycle?
8 m/s
16 m/s
64 m/s
4 m/s
Answer:
64 m/s
Explanation:
64m/s is the answer of question
64/m/s the answer
write .00000023 in scientific notation
Answer: 2.3 x 10^-7
Explanation:
When you move the decimal to the right, you decrease the exponent. So lets count how many spots you have to move the decimal spot to get an answer between 1 and 10. I counted seven spots.
So:
[tex]2.3 *10^-^7[/tex]
2.3 * 10 °−7
The degree indicates that the number is that small thing that floats above
3 A stationary car accelerates uniformly
for 20 s. Its velocity reaches 80
km h-1. What is the acceleration of the
car during this period?-
A 1.11 ms-2
B 2.22 ms-2
C 4.00ms-2
D 22.2ms-2
Playing with a stress ball you squeeze it as
hard as you can. How does this affect the
density of the ball?
Answer:
it dies
Explanation:
MWUAHHAHAHHA
1. Tectonic plates that move toward each other ...A Mantle
2. Layer with partially melted material that can flow easily _....B. Convergent
3. Tectonic plates that move away from each other C. Transform
4. Tectonic plates that slide past each other D. Divergent
Answer:
Its convergent
Explanation:
There areas where plates move toward each other and collide Also known as compressional pr destructive boundaries.
how far will a body move in 4sec if uniformly accelerated from rest at the rate of 2m/s2
Answer:
32m
Explanation:
v=u+at
v=0+2×4
v=8m/s
d=vt
d=8×4
d=32m
Help pls it’s urgent
Answer:
A
Explanation:
Refraction
What is the net force required to give an automobile with a mass of 2,100 kg an acceleration of 5.4 m/s^2?
Answer:
Net force = 11340 N
Explanation:
Given that,
Mass of an automobile, m = 2100 kg
Acceleration of the automobile, a = 5.4 m/s²
We need to find the net force required for the automobile. The net force is the product of mass and acceleration. It can be given by the formula as follows :
[tex]F=ma\\\\F=2100\ kg\times 5.4\ m/s^2\\\\F=11340\ N[/tex]
So, the net force is 11340 N.
Why is it important for scientists to find better ways to store solar and wind energy?
Answer:
Energy storage plays an important role in this balancing act and helps to create a more flexible and reliable grid system. For example, when there is more supply than demand, such as during the night when low-cost power plants continue to operate, the excess electricity generation can be used to power storage devices.
Explanation:
I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)
It important for scientists to find better ways to store solar and wind energy because solar and wind energy have variable outputs.
Lately, the world have begun to gradually gravitate away from non renewable energy sources such as fossil fuels and research efforts have been concentrated on renewable energy sources such as solar and wind energy.
However, the energy output from these sources are variable. Therefore, it is necessary to device ways to store energy from these sources in order to improve overall energy supply.
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How many atoms of each element are in 4Na3PO4?
A.) 3 sodium, 1 phosphorus, 4 oxygen
B.) 4 sodium, 4 phosphorus, 4 oxygen
C.) 12 sodium, 1 phosphorus, 4 oxygen
D.) 12 sodium, 4 phosphorus, 16 oxygen
Answer:
D) 12 sodium, 4 phosphorus. 16 oxygen
Explanation:
there is a four in front of the full formula, so you multiply all of the sub numbers by 4
Newton
10. Your mass on Earth is 50kg. Planet Xenon has half the gravitational force of Earth. What
are your weight and mass on Planet Xenon?
Given parameters:
Mass on earth = 50kg
Unknown:
Mass on planet Xenon = ?
Weight on planet Xenon = ?
Mass is the amount of matter contained in a particular substance.
Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.
Weight = mass x acceleration due to gravity
Planet Xenon has half the gravitational force of Earth.
This translated gives [tex]\frac{9.8}{2}[/tex] = 4.9m/s²
Now, mass is always the same every where if the amount of matter in a substance does not change.
In this problem, mass = 50kg on planet xenon.
Weight = mass x acceleration due to gravity = 50 x 4.9 = 245N
The weight on Xenon is 245N and the mass is 50kg
Please help in 5 mintues
A piece of chess game called master
a. king
b. queen
c. rook
d. bishop
1
A truck increases its speed from 15 m/s to 60 m/s in 15 s. Its acceleration is
a driver travels 4.25 km in two minutes. if the driver's initial velocity is 20m/s, what is the acceleration
Recall the definition of average velocity:
average v = ∆x / ∆t
The driver moves a distance of ∆x = 4.25 km = 4250 m in 2 min = 120 s, so the average velocity is
average v = (4250 m) / (120 s) ≈ 35.4 m/s
Under constant acceleration, the average velocity can also be computed by taking the average of the initial and final velocities:
average v = (initial v + final v) / 2
Solve for (final v) :
35.4 m/s = (20 m/s + final v)/2
final v ≈ 50.83 m/s
Recall the definition of average acceleration:
average a = ∆v / ∆t
Solve for a :
a = (50.83 m/s - 20 m/s) / (120 s)
a ≈ 0.257 m/s²
A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a scale. Write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the variables in the problem statement.
Answer:
W_net = mg + 2mgh/r
Explanation:
The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.
Now, gravitational force is; F_g = mg
While centripetal force is; F_c = mv²/r
Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.
Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.
Thus;
F_c = 2mgh/r
Where;
m is ball mass
r is tube radius
h is fall height
Thus, the net force will be;
F_net = F_g + F_c
Now, Net force would be equal to the net weight that will be read on the scale.
Thus;
W_net = F_net = F_g + F_c
W_net = mg + 2mgh/r
At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]
Given the following data:
Mass, m = 1.7 kg.Height, h = 14.2 meters.Radius, r = 6.2 meters.To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:
The forces acting on the ball.In this scenario, there are two (2) forces acting on the bowling ball and these include:
Centripetal forceGravitational forceMathematically, centripetal force is given by this formula:
[tex]F_c = \frac{mv^2}{r}[/tex] .....equation 1.
Mathematically, gravitational force is given by this formula:
[tex]F_g= mg[/tex] ....equation 2.
Where:
m is the mass.g is the acceleration due to gravity.v is the velocity.Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:
[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.
Substituting eqn. 3 into eqn. 2, we have:
[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]
At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:
[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]
Read more on net force here: https://brainly.com/question/14361879
A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil with a density of 800 kg/m3 and capped at both ends with tight-fitting pistons. The wider arm of the U-tube has a radius of 18.0 cm and the narrower arm has a radius of 5.00 cm. The car rests on the piston on the wider arm of the U-tube. The pistons are initially at the same level. What is the force that must be applied to the smaller piston in order to lift the car after it has been raised 1.20 m
Answer:
The answer is below
Explanation:
Pascal's law states that pressure is exerted in all parts of a static fluid equally.
The area of the narrower arm with a radius of 0.05 m (5 cm) is given as:
Area of narrow arm = π(0.05)²
The area of the wider arm with a radius of 0.18 m (18 cm) is given as:
Area of narrow arm = π(0.18)²
The ratio if the wider arm area to the narrow arm area = π(0.18)² / π(0.05)² = 12.96
To move the 12000 N car, the amount of force needed = 12000/12.96 = 926 N
If a car moves at a velocity of 1.45 x102 m/s for 1.8 x103
seconds. How far does the car go?
Answer:
The answer is
[tex]2.61 \times {10}^{5} \: \: m[/tex]Explanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × timeFrom the question
velocity = 1.45 × 10² m/s
time = 1.8 × 10³ s
We have
distance = 1.45 × 10² × 1.8 × 10³
We have the final answer as
[tex]2.61 \times {10}^{5} \: \: m[/tex]
Hope this helps you
PLEASE HELP GIVING BRAINLIEST!!
What is magnetic poles always come in pair
3 Points
The half-value layer for lead for g rays from 60Co is 12.8 mm. An electrometer gave a count rate of 35 pulses per second when at a
certain distance from a source, with no lead between source and detector. If 6 mm of lead were then inserted between source and
detector, the count rate (in pulses per second) would be nearest to:
A. 16
OB. 8
OC. 20
D. 25
OE. 75
Answer:
D. 25
Explanation:
The number of pulses per second (p) for x mm of lead can be modeled by the exponential equation ...
p = 35(0.5^(x/12.8))
Then for x=6, the value of p is ...
p = 35·0.5^(6/12.8) ≈ 25.29
The expected count rate would be nearest 25 pps.
Change in Energy Quick Check
1 of 5
Which change occurs as an object falls toward the surface of Earth? (1 point)
The force of gravity on the object decreases.
The potential energy of the object decreases.
The acceleration due to gravity decreases.
The kinetic energy of the object decreases
IF SOMEONE GETS THE ANSWERS TO 1-5 of quick check pls post them here
Answer:
The force of gravity on the object decreases. (FALSE)
The potential energy of the object decreases. (TRUE)
The acceleration due to gravity decreases. (FALSE)
The kinetic energy of the object decrease (FALSE)
Explanation:
FORCE OF GRAVITY:
Force of gravity on the object is the weight of object, which depends upon the mass and value of acceleration due to gravity (W = mg). Since, the value mass is constant on Earth and acceleration due to gravity is also constant on earth.
Therefore, force of gravity remains same on the object. The statement is false.
POTENTIAL ENERGY:
Potential energy of object depends upon the mass, value of acceleration due to gravity, and change in height of object (P.E = mgΔh). Since, the value mass is constant on Earth and acceleration due to gravity increases as the object moves towards the surface of earth. But, the height of object is decreasing.
Therefore, potential energy of object decreases. The statement is true.
ACCELERATION DUE TO GRAVITY:
Acceleration due to gravity depends upon the altitude (gh = g[1 - 2h/Re]). Since, the height of object is decreasing.
Therefore, acceleration due to gravity increases. The statement is false.
But, this change is not significant.
KINETIC ENERGY:
Kinetic Energy of object, which depends upon the mass and velocity of the object (K.E = mv²/2). Since, the value mass is constant on Earth and velocity increases as the object moves towards the surface of earth.
Therefore, kinetic energy of the object also increases. The statement is false.
As the object falls towards the surface of the earth, the potential energy of the object decreases.
The earth is a large gravitational field. The potential energy of an object is dependent on its height. As a body falls through a height, its mass remains constant but its height decreases therefore its potential energy decreases also.
Hence, the true statement is that as the object falls towards the surface of the earth, the potential energy of the object decreases.
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When an object remains stationary, any forces acting on it must be balanced.
Choose 1 answer:
True
False
Based on what you learn about gravity describe why objects float in outer space
Answer:
Objects float in outer space because there is no gravitational force. The farther you get from earth, the less gravity.
Explanation:
Answer:
they float do to gravity
Explanation:
here if you tossed a ball in the air it would come back down fast in space however it would only float up and stay do to gravity
______ is a disease in which the body does not produce or probory use inslin
Answer:
Diabetes
Explanation:
Insulin is an important hormone that helps the body convert sugar, starches, and other foods into energy.
Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west end of the corridor, a woman walks a short distance east along the corridor and stops before reaching the water fountain. The distance from her to the fountain is twice the distance she has walked. She then continues walking east, passes the water fountain, and stops 60 m from her first stop. Now the distance from her to the fountain is twice the distance from her to the east end of the corridor. How long is the corridor
Answer:
The corridor's distance is "90 m".
Explanation:
She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1. Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled. Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop. The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.Now,
⇒ [tex]2x + 2y = 60[/tex]
⇒ [tex]x + y = 30[/tex]
The total distance of the corridor will be:
= [tex]x + 2x + 2y + y[/tex]
= [tex]3\times (x + y)[/tex]
= [tex]3\times 30[/tex]
= [tex]90 \ m[/tex]
A block of mass 12.2 kg is sliding at an initial velocity of 6.65 m/s in the positive x-direction. The surface has a coefficient of kinetic friction of 0.253. (Indicate the direction with the signs of your answers.)
a.) What is the force of kinetic friction (in N) acting on the block?
(b What is the block's acceleration (in m/s2)?
(c) How far will it slide (in m) before coming to rest?
Explanation:
Given that,
Mass of the block, m = 12.2 kg
Initial velocity of the block, u = 6.65 m/s
The coefficient of kinetic friction, [tex]\mu_k=0.253[/tex]
(a)The force of kinetic friction is given by :
[tex]f=\mu_k mg[/tex]
mg is the normal force
So,
[tex]f=0.253\times 12.2\times 9.8\\\\f=30.24\ N[/tex]
(b) Net force acting on the block in the horizontal direction,
f = ma
a is the acceleration of the block
[tex]a=\dfrac{f}{m}\\\\a=\dfrac{30.24}{12.2}\\\\a=2.47\ m/s^2[/tex]
(c) Let d is the distance covered by the block before coming to the rest. Using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(6.65)^2}{2\times 2.47}\\\\d=-8.95\ m[/tex]
Hence, this is the required solution.
This question involves the concepts of the frictional force, Newton's second law of motion, and the equations of motion.
a) The force of kinetic friction acting on the block is "-30.28 N".
b) The acceleration of the block is "-2.48 m/s²".
c) The block will slide "8.9 m" before coming to rest.
a)
The kinetic friction force is given by the following formula:
[tex]F=\mu_k mg[/tex]
where,
F = frictional force = ?
[tex]\mu_k[/tex] = coefficient of kinetic friction = 0.253
m = mass of block = 12.2 kg
g = acceleration dueto gravity = 9.81 m/s²
Therefore,
[tex]F=(0.253)(12.2\ kg)(9.81\ m/s^2)[/tex]
F = - 30.28 N (negative sign due to resistive force)
b)
According to Newton's Second Law of Motion:
F = ma
[tex]a=\frac{F}{m} = \frac{-30.28\ N}{12.2\ kg}\\\\[/tex]
a = -2.48 m/s² (negative sign due to deceleration)
c)
Using the third equation of motion to calculate the distance:
[tex]2as=v_f^2-v_i^2[/tex]
where,
s = distance = ?
vf = final speed = 0 m/s
vi = initial speed = 6.65 m/s
Therefore,
[tex]2(-2.48\ m/s^2)s=(0\ m/s)^2-(6.65\ m/s)^2\\\\s=\frac{-(6.65\ m/s)^2}{2(-2.48\ m/s^2)}[/tex]
s = 8.9 m
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The attached picture shows Newton's Second Law of Motion.