The one critical point at (0, 0).
The critical point (0, 0) is a saddle point, and the critical point (-9, -3) is a relative minimum.
To find the critical points of the given function f(x, y) = x^2 - 6xy - 2y^3, we need to find the points where the partial derivatives with respect to x and y are equal to zero.
Calculate the partial derivative with respect to x (f_x):
f_x = 2x - 6y
Calculate the partial derivative with respect to y (f_y):
f_y = -6x - 6y^2
Set both partial derivatives equal to zero and solve the system of equations:
2x - 6y = 0 ---(1)
-6x - 6y^2 = 0 ---(2)
From equation (1), we can rearrange it to solve for x:
2x = 6y
x = 3y
Substituting x = 3y into equation (2):
-6(3y) - 6y^2 = 0
-18y - 6y^2 = 0
-6y(3 + y) = 0
Now, we have two possible cases:
a) -6y = 0
b) 3 + y = 0
a) -6y = 0
This implies y = 0
Substituting y = 0 into equation (1):
2x - 6(0) = 0
2x = 0
x = 0
So, we have one critical point at (0, 0).
b) 3 + y = 0
This implies y = -3
Substituting y = -3 into equation (1):
2x - 6(-3) = 0
2x + 18 = 0
2x = -18
x = -9
So, we have another critical point at (-9, -3).
Now, to classify each critical point as a relative maximum, relative minimum, or a saddle point, we need to analyze the second-order partial derivatives.
Calculate the second partial derivative with respect to x (f_xx):
f_xx = 2
Calculate the second partial derivative with respect to y (f_yy):
f_yy = -12y
Calculate the mixed partial derivative (f_xy):
f_xy = -6
Now, evaluate the discriminant D = f_xx * f_yy - (f_xy)^2 at each critical point:
For the critical point (0, 0):
D = f_xx * f_yy - (f_xy)^2
= 2 * (-12 * 0) - (-6)^2
= 0 - 36
= -36
For the critical point (-9, -3):
D = f_xx * f_yy - (f_xy)^2
= 2 * (-12 * -3) - (-6)^2
= 72 - 36
= 36
Analyzing the discriminant:
For the critical point (0, 0):
If D < 0, it is a saddle point. In this case, D = -36, so (0, 0) is a saddle point.
For the critical point (-9, -3):
If D > 0 and f_xx > 0, it is a relative minimum. In this case, D = 36 and f_xx = 2, so (-9, -3) is a relative minimum.
Therefore, the critical point (0, 0) is a saddle point, and the critical point (-9, -3) is a relative minimum.
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i cant do math no more
Answer:
(1, 4)
Don't worry, I feel the same way sometimes, :)
Please give me Brainliest :)Step-by-step explanation:
Substitute the bottom equation into the top.
If y=3x+1, than the first y will equal 3x+1.
3x+1 = x+3
Subtract 1 from 3
3x = x+2
Subtract x from 3x.
2x=2
Divide everything by 2.
x=1
Now substitute it in the equation.
1. y=1 + 3
y=4
2. y= 3(1) + 1
y=3+1
y=4
(1, 4)
Last year, the revenue for medical equipment companies had a mean of 70 million dollars with a standard deviation of 13 million. Find the percentage of companies with revenue between 50 million and 90 million dollars. Assume that the distribution is normal. Round your answer to the nearest hundredth
The percentage of companies with revenue between 50 million and 90 million dollar is: 87.6%
How to find the percentage from z-scores?The formula for the z-score in this type of distribution is:
z = (x' - μ)/σ
where:
x' is sample mean
μ is population mean
σ is standard deviation
We are given:
μ = 70 million dollars
σ = 13 million dollars
Thus:
When x' = 50 million dollars, we have:
z = (50 - 70)/13
z = -1.54
When x' = 90 million dollars, we have:
z = (90 - 70)/13
z = 1.54
Using probability between two z-scores calculator, we have:
z = 0.87644 = 87.6%
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Unit test unit test review active 11 12 13 a computer company wants to determine the proportion of defective computer chips from a day's production. a quality control specialist takes a random sample of 100 chips from the day's production and determines that there are 12 defective chips. assuming all conditions are met he constructs a 95% confidence interva for the true proportion of defective chips from a day's production. what are the calculations for this interval? o 12 +1.65 12(1 - 12) 100 o 12 +1.96 12(1 – 12) 100 o 0.12 +1.65, 0.12(1 – 0.12) 100 0.12 +1.96 0.12(1– 0.12) 100
The 95% confidence interval for the true proportion of defective chips is between 0.043 and 0.197.
To calculate the 95% confidence interval for the true proportion of defective computer chips, the quality control specialist would use the formula:
proportion +/- z ×√(proportion x (1-proportion)/sample size)
In this case, the proportion of defective chips is 12/100 or 0.12. The sample size is 100. To find the value of z for a 95% confidence level, we look at a standard normal distribution table or use a calculator and find that it is 1.96.
So the calculation for the confidence interval would be:
0.12 +/- 1.96 × √(0.12 × (1-0.12)/100)
Simplifying this gives us:
0.12 +/- 0.077
This means that if we repeated this sampling process many times, we would expect the true proportion of defective chips to fall within this interval 95% of the time.
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If I wanted to draw Circles X and and wanted to make sure they were congruent to Circle A, what
would be required?
To ensure that Circles X are congruent to Circle A, you need to ensure that they have the same size and shape. In other words, the radii of Circle X should be equal to the radius of Circle A.
Here are the steps you can follow to draw congruent Circles X:
Use a compass to measure the radius of Circle A.
Without changing the radius setting on your compass, place the tip of the compass at the center of where you want to draw Circle X.
Draw Circle X using the compass, making sure that the radius is the same as the radius of Circle A.
Check that Circle X and Circle A have the same size and shape. You can do this by measuring their radii with a ruler or by comparing their circumference.
By following these steps, you can ensure that Circle X is congruent to Circle A.
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A line has a slope of – 7 and passes through the point (2,7). Write its equation in slope-intercept form.
[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{7})\hspace{10em} \stackrel{slope}{m} ~=~ - 7 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{- 7}(x-\stackrel{x_1}{2}) \\\\\\ y-7=-7x+14\implies {\Large \begin{array}{llll} y=-7x+21 \end{array}}[/tex]
Suppose that a cylinder has a radius of r units, and that the height of the cylinder is also r units.The lateral area of the cylinder is 98 v square units.
Find the value of r. type your answer.....
units
Find the surface area of the cylinder to the nearest tenth. type your answer....
units
r = 4.0 units
Given that,
A cylinder has a radius of r units, and that the height of the cylinder is also r units.
The lateral area of the cylinder is 98 square units.
We need to find the value of r.
The formula for the lateral area of the cylinder is given by:
[tex]\text{A}=2\pi \text{rh}[/tex]
Put all the values,
[tex]2\pi \text{rh}=98[/tex]
[tex]\text{r}=\sqrt{\dfrac{98}{2\pi} }[/tex]
[tex]\text{r}=4.0 \ \text{units}[/tex]
So, the value of r is equal to 4.0 units.
The table shows the dimensions of four boxes.
Drag tiles to order the volumes of the boxes from least to greatest
The order of the volumes of the boxes from least to greatest is Box D, Box B, Box C, Box A. Therefore, the correct option is D.
To determine the order of the volumes of the boxes from least to greatest, we will first calculate the volume of each box using the formula:
Volume = Length × Width × Height.
Hence,
1. Box A: Volume = 2in × 4.5in × 6in = 54 cubic inches
2. Box B: Volume = 6in × 2.5in × 3in = 45 cubic inches
3. Box C: Volume = 5in × 4.5in × 2.25in = 50.625 cubic inches
4. Box D: Volume = 2.5in × 2.25in × 3in = 16.875 cubic inches
Now, arrange the volumes in ascending order:
Box D (16.875), Box B (45), Box C (50.625), Box A (54)
Thus, the correct answer is D: Box D, Box B, Box C, Box A.
Note: The question is incomplete. The complete question probably is: The table shows the dimensions of four boxes. Which is the order of the volumes of the boxes from least to greatest?
Length Width Height
Box A 2in; 4.5in; 6in
Box B 6in; 2.5in; 3in
Box C 5in; 4.5in; 2.25in
Box D 2.5in; 2.25in; 3in
A) Box A Box B, Box C, Box D B) Box A, Box C, Box B, Box D C) Box B, Box D, Box A, Box C D) Box D, Box B, Box C, Box A.
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9(x) = ln (3x+11) calculate gl (x) A) 2-3x + 11)-3 B) 3(-3x + 11)-1 C) -54(-3x +11)-3 D) -9(-3x +11)-?
Using given function 9(x) = ln(3x+11), gl (x) B) 3(-3x + 11)^-1.
We are given 9(x) = ln(3x+11) and we need to find gl(x).
First, we can use the chain rule to differentiate ln(3x+11):
d/dx [ln(3x+11)] = 1/(3x+11) * d/dx [3x+11] = 3/(3x+11)
Now, we can use the given equation 9(x) = ln(3x+11) to find d/dx [9(x)]:
d/dx [9(x)] = d/dx [ln(3x+11)] = 3/(3x+11)
Therefore, gl(x) = d/dx [9(x)] / 3(x) = 3/(3x+11) * 1/3 = (3(-3x+11))^-1.
Therefore, the correct answer is B) 3(-3x+11)^-1.
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Annette drives her car 115 miles and has an average of a certain speed. If the average speed had been 8mph more, she could have traveled 138 miles in the same length of time. What was her average speed?
Annette's average speed was 40 mph if Annette drives her car 115 miles and has an average of a certain speed.
What is Average speed ?
Average speed is the total distance traveled divided by the total time taken to travel that distance. It is a measure of the overall speed of an object or person over a certain period of time.
Let's call Annette's original average speed "x". We can use the formula:
distance = speed x time
to set up two equations based on the given information.
For the first part of the trip:
115 = x * t1 (where t1 is the time it took Annette to travel 115 miles at speed x)
For the second part of the trip:
138 = (x + 8) * t2 (where t2 is the time it would have taken Annette to travel 138 miles at a speed of x + 8)
Since Annette traveled the same amount of time for both parts of the trip, we can set t1 equal to t2:
t1 = t2
We can solve for t1 in the first equation:
t1 = 115 : x
And we can solve for t2 in the second equation:
t2 = 138 : (x + 8)
Since t1 = t2, we can set the two expressions for t equal to each other:
115 : x = 138 : (x + 8)
Now we can solve for x:
115(x + 8) = 138x
115x + 920 = 138x
920 = 23x
x = 40
Therefore, Annette's average speed was 40 mph.
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There are 4 mathematics books, 5 science books and 3 english books in the library. In how many ways can you arrange these so that the books are arranged in this order: Mathematics, Science, and English, and books of the same subjects are together?
To arrange the books in the specified order (Mathematics, Science, and English), you need to determine the number of arrangements for each subject's books and then multiply them together.
For the 4 mathematics books, there are 4! (4 factorial) ways to arrange them, which is 4 × 3 × 2 × 1 = 24 ways.
For the 5 science books, there are 5! (5 factorial) ways to arrange them, which is 5 × 4 × 3 × 2 × 1 = 120 ways.
For the 3 English books, there are 3! (3 factorial) ways to arrange them, which is 3 × 2 × 1 = 6 ways.
To find the total number of ways to arrange all the books in the required order, multiply the arrangements for each subject together: 24 (Mathematics) × 120 (Science) × 6 (English) = 17,280 ways.
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There are 160 customers at Harris Teeter. 48 of them are children.What percent of the customers at Harris Teeter are adults?
PLEASE I NEED EXPLANATION
The percent of the customers at Harris Teeter that are adults is 70%
Calculating the percentage of the customers that are adultsFrom the question, we have the following parameters that can be used in our computation:
Customers = 160
Children = 48
using the above as a guide, we have the following:
Adults = Customers - Children
substitute the known values in the above equation, so, we have the following representation
Adults = 160 - 48
So, we have
Adults = 112
Next, we have
Percentage = 112/160 * 100%
Evaluate
Percentage = 70%
Hence, the percentage is 70%
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Write the equation in standard form for the circle with center (8,0) and radius 3/3.
The equation in standard form for the circle with center (8,0) and radius 3/3 is (x - 8)² + y² = 1
To write the equation in standard form for the circle with center (8,0) and radius 3/3, we can use the following formula for a circle in standard form:
(x - h)² + (y - k)² = r²
Where (h, k) is the center of the circle and r is the radius. In this case, the center is (8,0) and the radius is 3/3, which simplifies to 1. Now, we can substitute the values of h, k, and r into the equation:
(x - 8)² + (y - 0)² = 1²
Since (y - 0) is just y, we can simplify the equation to:
(x - 8)² + y² = 1
So, the equation in standard form for the circle with center (8,0) and radius 3/3 is:
(x - 8)² + y² = 1
In summary, we used the standard form equation for a circle, substituted the given values for the center and radius, and simplified the equation to obtain the final answer.
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Mortgage payments Principal : $ 180,000.00 Interest Rate Monthly Payment How much money will be spent in interest alone over the course of the 3.5 % 30 - year mortgage described in the table ? 3.5% 5% $808 $966 $ 1079 6% A. $110,880 B. $6,300 C. $180,000 D. $ 290,880
Answer:
To calculate the amount of money spent in interest alone over the course of a 30-year mortgage, we can use the formula:
Total Interest = (Monthly Payment x Number of Payments) - Principal
For a 3.5% 30-year mortgage with a principal of $180,000, the monthly payment can be calculated using the formula:
Monthly Payment = (Principal x Monthly Interest Rate) / (1 - (1 + Monthly Interest Rate)^(-Number of Payments))
where Monthly Interest Rate = Annual Interest Rate / 12, and Number of Payments = 30 years x 12 months per year = 360.
Plugging in the values, we get:
Monthly Payment = (180,000 x 0.0035) / (1 - (1 + 0.0035)^(-360)) = $808.28
Using this monthly payment, we can calculate the total interest over the 30-year period:
Total Interest = ($808.28 x 360) - $180,000 = $101,020.80
Therefore, the correct answer is A. $110,880 (which is not one of the options given).
On a standard dice, the sum of the numbers of dots on opposite faces is always 7. Four standard dice are glued together, as shown. What is the minimum number of dots that could lie on the whole surface?
The minimum number of dots that could lie on the whole surface of four standard dice glued together is 56.
This can be achieved by placing the faces with 1 dot opposite the faces with 6 dots, the faces with 2 dots opposite the faces with 5 dots, and the faces with 3 dots opposite the faces with 4 dots on all four dice. Since the sum of the numbers on opposite faces of each individual die is always 7, the sum of the numbers on opposite faces of the four glued-together dice is also always 7. Therefore, the minimum number of dots on the whole surface is 7 times the number of faces, which is 7 x 8 = 56.
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A quantity with an initial value of 8200 grows continuously at a rate of 0. 55% per decade. What is the value of the quantity after 97 years, to the nearest hundredth?
Answer: 4000. 4
As per the growth function, the value of the quantity after 97 years would be $67,458.85.
In your problem, you have a quantity with an initial value of 8200 that grows continuously at a rate of 0.55% per decade. To find the value of the quantity after 97 years, we can use the following growth function:
A(t) = A₀[tex]e^{kt}[/tex]
In this formula, A(t) represents the value of the quantity after time t, A₀ represents the initial value of the quantity (in this case, 8200), e represents Euler's number (a mathematical constant equal to approximately 2.718), k represents the growth rate (in this case, 0.0055 per decade), and t represents the time elapsed (in this case, 97 years).
To solve for the value of the quantity after 97 years, we simply plug in the values we know and solve for A(t):
A(t) = 8200[tex]e^{(0.0055/10\times97)}[/tex]
= 8200[tex]e^{0.5285}[/tex]
≈ 67,458.85
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Create a story context for the following expressions ( 5 1/4 - 2 1/8) divided by 4 and 4 x ( 4. 8/0. 8)
To create a story context for the given expressions, which are (5 1/4 - 2 1/8) divided by 4 and 4 x (4.8/0.8).
Imagine there is a fruit store where you have to prepare fruit baskets for a local charity event. The first expression (5 1/4 - 2 1/8) divided by 4 can be a story about the number of apples to be distributed equally among four baskets.
You initially have 5 1/4 dozen apples, but you realize that 2 1/8 dozen of them are not suitable for the baskets.
To find out how many dozens of apples should be put into each basket, you need to subtract the unsuitable apples and divide the result by 4:
(5 1/4 - 2 1/8) / 4
Now, let's move on to the second expression, 4 x (4.8/0.8). This can be a story about the number of oranges you need to purchase for the fruit baskets. You already have 4.8 dozen oranges, but you need to add more to reach the desired ratio of oranges to apples.
Your friend suggests that for every 0.8 dozen oranges you currently have, you should add 4 more dozen oranges. To find out how many dozens of oranges you need to buy, you can use this formula:
4 x (4.8/0.8)
By creating these story contexts, you can use the given expressions to solve real-life problems, such as distributing fruits among charity baskets.
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Find the area of the composite figure to the nearest hundredth. Find the area total area = ________ mm²
The total area of the composite figure is 1650 mm
To find the area of a composite figure, you need to break it down into simpler shapes whose areas you can calculate and then add up the individual areas. In this case, the composite figure consists of two shapes: a rectangle and a trapezoid.
To find the area of the rectangle, you multiply its length by its width. From the given dimensions, the length of the rectangle is 40 mm and the width is 30 mm. So the area of the rectangle is 40 x 30 = 1200 mm².
To find the area of the trapezoid, you use the formula for the area of a trapezoid: (base1 + base2) x height / 2. From the given dimensions, the two bases of the trapezoid are 25 mm and 35 mm, and the height is 15 mm. So the area of the trapezoid is (25 + 35) x 15 / 2 = 450 mm².
Now you add the areas of the two shapes together to get the total area of the composite figure: 1200 + 450 = 1650 mm².
Therefore, the total area of the composite figure is 1650 mm², rounded to the nearest hundredth.
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Jose reads his book at an average rate of
2. 5
2. 5 pages every four minutes. If Jose continues to read at exactly the same rate what method could be used to determine how long it would take him to read
20
20 pages?
It would take Jose approximately 3232 minutes (or about 53.87 hours) to read 2020 pages at the same rate of 2.5 pages every four minutes.
To determine how long it would take Jose to read 2020 runners at the same rate of2.5 runners every four twinkles, we can use a proportion. Let x be the number of twinkles it would take Jose to read 2020 runners. also, we can set up the following proportion:
2.5 pages / 4 minutes = 2020 pages / x minutes
To solve for x, we can cross-multiply and simplify:
2.5 pages * x minutes = 4 minutes * 2020 pages
2.5x = 8080
x = 8080 / 2.5
x = 3232
Therefore, it would take Jose approximately 3232 minutes to read 2020 pages at the same rate of 2.5 pages every four minutes.
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A 5-minute international call costs $2.15 and a 12-minute call costs $3.06. The work shows how to write an equation where x represents the number of minutes, and y represents the total cost of an international call. Analyze the steps of the work to determine if the equation is correct.
1. Point 1: (5, 2.15). Point 2: (12, 3.06). 2. m = StartFraction 12 minus 5 Over 3.06 minus 2.15 EndFraction = StartFraction 7 Over 0.91 EndFraction = 7.69. 3. 5 = 2.15 (7.69) + b. b = negative 11.54. 4. y = 7.69 x minus 11.54.
In which step did Emilia make an error?
In step 2, she substituted the x values for y and the y values for x.
In step 3, she didn’t use an x and y from the same coordinate pair.
In step 4, Emilia solved for the wrong variable.
Emilia did not make an error.
Emilia make an error in step 3 she didn't use an x and y from the same coordinate pair.
In step 1 : point 1 : (5, 2.15) point 2 : (12, 3.06)
In step 2 : m = [tex]\frac{12-5}{3.06-2.15}[/tex]
m = 7/0.91
m = 7.69
In Step 3 : y = mx + b
m = slope
Point used by Emilia (2.15 , 5)
But the point should be used be Emilia is (5, 2.15)
2.15 = 5(7.69) + b
b = y intercept
b = -36.3
step 3 is wrong she didn't use right coordinates of x and y
In step 4 : y = mx +b
y = 7.69x -36.3
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Alexandre has two brothers: Hugo and Romain. Every day Romain draws a name out of a hat to randomly select one of the three brothers to wash the dishes. Alexandre suspected that Romain is cheating, so he kept track of the draws, and found that out of
12
1212 draws, Romain didn't get picked even once.
Let's test the hypothesis that each brother has an equal chance of
1
3
3
1
start fraction, 1, divided by, 3, end fraction of getting picked in each draw versus the alternative that Romain's probability is lower.
Assuming the hypothesis is correct, what is the probability of Romain not getting picked even once out of
12
1212 times? Round your answer, if necessary, to the nearest tenth of a percent.
Based on the observed outcome, it is therefore very or highly unlikely that Romain's probability is equal to that of the other brothers, and thus it is possible that Romain is cheating.
What is the probability?Beneath the assumption that each brother has an break even with chance of getting picked in each draw, the likelihood of Romain not getting picked indeed once out of 12 times is:
P(Romain not picked) = (2/3)¹²
= 0.0077
This is one that is less than 1%, which suggests that the observed result is made up of a likelihood less than 1% beneath the given speculation. Therefore, we need to reject the hypothesis that each brother has an equal chance of getting picked in all of the draw.
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See text below
Alexandre has two brothers: Hugo and Romain. Every day Romain draws a name out of a hat to randomly select one of the three brothers to wash the dishes. Alexandre suspected that Romain is cheating, so he kept track of the draws, and found that out of 12 draws, Romain didn't get picked even once. 1 Let's test the hypothesis that each brother has an equal chance of of getting picked in each draw versus 3 the alternative that Romain's probability is lower. Assuming the hypothesis is correct, what is the probability of Romain not getting picked even once out of 12 times? Round your answer, if necessary, to the nearest tenth of a percent. Let's agree that if the observed outcome has a probability less than 1% under the tested hypothesis, we will reject the hypothesis. What should we conclude regarding the hypothesis? Choose 1 answer: We cannot reject the hypothesis. B We should reject the hypothesis.
En un viaje en mula hacia el pico duarte el jinete observa en un poste 1, 290 m sobre el nivel del mar , luego de 5 horas de camino presta atencion a otro poste que indica , 2, 480 m sobre el nivel de mar. ¿ cual ha sido su desplazamiento en direccion vertical?
The vertical displacement of the mule comes out to be the difference between the final and the initial position which is 1190 m.
The displacement refers to the distance between the final and the initial position of an object. It is the shortest distance between these points is the displacement of the object. It is a vector quantity.
Vector quantity refers to the measurement in which both magnitude and direction are considered.
Starting point = 1290 m
Final point = 2480 m
Displacement = 2480 - 1920
= 1190 m
1190 m is the vertical displacement of the mule when traveling from one post to another.
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The question is in Spanish and when translated to English, it is:
On a mule trip to Duarte Peak, the rider observes a post 1,290 m above sea level, after 5 hours of walking he pays attention to another post that indicates 2,480 m above sea level. What has been its displacement in the vertical direction?
Brainliest for the one who answers first!
The measure of an angle is 90.4°. What is the measure of its supplementary angle?
Answer:
89.6°
Step-by-step explanation:
180-90.4=89.6°
Answer: 89.6
Step-by-step explanation:
Supplementary means angles adding up to 180
180-90.4 = x
x=89.6 this is your supplemental angle
Among american adults, 42. 5 percent are considered: multiple choice question. Obese. Athletic. Anorexic. Underweight
Answer:
Obese
Step by Step Explanation:
looked it up :)
Evaluate the definite integral:
∫(e^z) + 8/ (e^z+8z)^2
The definite integral
[tex]-e^(2z)/u + 16e^z/u - 64ln(u)/u + C[/tex]
To evaluate this definite integral, we need to find the antiderivative of the integrand and evaluate it at the limits of
integration.
Let's start by using u-substitution:
Let [tex]u = e^z+8z[/tex]
Then [tex]du/dz = e^z+8[/tex]
And [tex]dz = 1/e^z+8 du[/tex]
Substituting this into the integral, we get:
[tex]∫(e^z) + 8/ (e^z+8z)^2 dz[/tex]
= [tex]∫(1/u^2)(e^z+8)^2 du[/tex]
= [tex]∫(1/u^2)(e^(2z)+16e^z+64) du[/tex]
= [tex]-e^(2z)/u + 16e^z/u - 64ln(u)/u + C[/tex]
Now we need to evaluate this antiderivative at the limits of integration.
Let's assume the limits are a and b:
= [tex][-e^(2b)/(e^b+8b) + 16e^b/(e^b+8b) - 64ln(e^b+8b)/(e^b+8b)] - [-e^(2a)/(e^a+8a) + 16e^a/(e^a+8a) - 64ln(e^a+8a)/(e^a+8a)][/tex]
Simplifying this expression is not easy, but it can be done with some algebraic manipulation.
Therefore, The definite integral
[tex]-e^(2z)/u + 16e^z/u - 64ln(u)/u + C[/tex]
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b) In a certain group of 200 persons, 110 can speak Nepali, 85 can speak Maithili and 60 can speak both the languages. Find, (i) how many of them can talk in either of these languages? (ii) how many of them can talk in neither of these languages?
Answer:
(i) 135, (ii) 65-----------------------
Given:
Total number in the group - 200 persons,Nepali speakers - 110,Maithili speakers - 85,Both - 60.(i) We know 60 out of 110 can speak both languages, so as 60 out of 85. The number 60 is counted twice if we add them together.
Find the number of those speak either language:
Either = sum of each - bothEither = 110 + 85 - 60 = 135(ii) Find the number of thise who can talk neither of these languages:
Neither = total - eitherNeither = 200 - 135 = 65If a side of a square is doubled and an adjacent side is diminished by 3, a rectangle is formed whose area is numerically greater than the area of the square by twice the original side of the square. Find the dimensions of the original square
The dimensions of the original square is 8 by 8.
Let x be the original side length of the square. The area of the square is x². When one side is doubled and the adjacent side is diminished by 3, the rectangle's dimensions become 2x and (x-3). The area of the rectangle is (2x)(x-3) = 2x² - 6x.
According to the problem, the area of the rectangle is greater than the area of the square by twice the original side of the square, which is 2x. So we can set up the equation:
2x² - 6x = x² + 2x
Now, solve for x:
2x² - x² = 6x + 2x
x² = 8x
x = 8
So the dimensions of the original square are 8 by 8.
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1. For the solid bounded by the panes 2 = 1 - x and z=1-y in the first octant (which is the same as being bounded by x = 0, y = 0, 2 = 0), one triple integral that describes the volume of the solid is: 1- SL | 1 d:dyds + C5 .** 1 dzdyudar 0 lo z , Z=1-4 ។ Z=1- х Find three other orders of integration that describe this solid. You need not find the volume. 2. Compute by switching the order of integration: dyd.x 3. Write the following integral in polar coordinates, then solve. arctan ( dyda ", 1.
1. For the solid bounded by the panes 2 = 1 - x and z=1-y in the first octant, one triple integral that describes the volume of the solid. The region is bounded by the x-axis and the curve y = √(2x-x^2), which is the top half of a circle centered at (1,0) with radius 1.
One possible order of integration is:
∫0^1 ∫0^(1-x) ∫0^(1-y) dzdydx
This means we integrate over z first, then y, then x. Another order of integration could be:
∫0^1 ∫0^x ∫0^(1-x-y) dzdydx
Here we integrate over z first, then x, then y.
Another possible order of integration is:
∫0^1 ∫0^1-x ∫0^1-y dzdxdy
Here we integrate over z first, then x, then y. This order of integration can also be rewritten in polar coordinates as:
∫0^(π/4) ∫0^(secθ-1) ∫0^(cscθ-1) r dzdrdθ
2. Compute by switching the order of integration:
∫0^2 ∫0^√(2x-x^2) dydx
First, let's sketch the region of integration. The region is bounded by the x-axis and the curve y = √(2x-x^2), which is the top half of a circle centered at (1,0) with radius 1.
We can switch the order of integration to integrate over x first, then y:
∫0^1 ∫0^(2-2y^2) dxdy
To find the limits of integration for x, we set y = √(2x-x^2) and solve for x:
y^2 = 2x - x^2
x^2 - 2x + y^2 = 0
(x-1)^2 = 1 - y^2
x = 1 ± √(1-y^2)
Since the curve is the top half of the circle, we take the positive square root:
x = 1 + √(1-y^2)
So the limits of integration for x are 0 to 2-2y^2. Integrating with respect to x first gives:
∫0^1 ∫0^(2-2y^2) dxdy = ∫0^1 (2-2y^2)dy = 4/3
3. Write the following integral in polar coordinates, then solve:
arctan (dy/dx)
We can write dy/dx in terms of polar coordinates using the chain rule:
dy/dx = (dy/dr)(dr/dθ)(1/dx/dθ)
Using the relationships x = rcosθ and y = rsinθ, we have:
dx/dθ = -rsinθ
dy/dθ = rcosθ, So
dy/dx = (dy/dr)(dr/dθ)(1/dx/dθ) = (cosθ)/(sinθ) = cotθ
Therefore, the integral becomes:
∫arctan(cotθ) dθ
To solve this integral, we use the identity arctan(x) + arctan(1/x) = π/2 for x > 0:
arctan(cotθ) = π/2 - arctan(tanθ)
So the integral becomes:
∫(π/2 - arctan(tanθ)) dθ
Integrating, we get:
(π/2)θ - ln|cosθ| + C
Where C is the constant of integration.
1. To find three other orders of integration for the solid bounded by the planes z = 1 - x, z = 1 - y, x = 0, y = 0, and z = 0 in the first octant, we can rearrange the given triple integral, which is given as:
∫∫∫_D dz dy dx
Now, we can find three other orders of integration:
a) ∫∫∫_D dx dz dy
b) ∫∫∫_D dy dx dz
c) ∫∫∫_D dy dz dx
2. To compute the volume of the solid by switching the order of integration, we can rewrite the given integral ∫∫ dy dx as: ∫∫ dx dy
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The tables represent hat sizes measured in inches for two softball teams.
Pelicans
21.5 25 22
21 22 23
22.5 24 21.5
22 23.5 22
23.5 22 24.5
Falcons
22.5 20 23.5
21 24 22
20.5 21.5 23
23 22.5 21
24 22 24.5
Which team has the largest overall size hat for their playersThe tables represent hat sizes measured in inches for two softball teams.
Pelicans
21.5 25 22
21 22 23
22.5 24 21.5
22 23.5 22
23.5 22 24.5
Falcons
22.5 20 23.5
21 24 22
20.5 21.5 23
23 22.5 21
24 22 24.5
Which team has the largest overall size hat for their players? Determine the best measure of center to compare and explain your answer.
Falcons; they have a larger median value of 22.5 inches
Pelicans; they have a larger median value of 22 inches
Falcons; they have a larger mean value of about 22 inches
Pelicans; they have a larger mean value of about 23 inches? Determine the best measure of center to compare and explain your answer.
Falcons; they have a larger median value of 22.5 inches
Pelicans; they have a larger median value of 22 inches
Falcons; they have a larger mean value of about 22 inches
Pelicans; they have a larger mean value of about 23 inches
Marsha threw her math book off a 30 foot building. The equation of the book can be represented by the equation h=-16[tex]x^{2}[/tex]+24x+30. What is the maximum height
of Marsha's math book?
The maximum height of Marsha's math book is 36 feet.
To find the maximum height of Marsha's math book, we need to find the vertex of the parabolic equation h = [tex]-16x^2 + 24x + 30[/tex]. The vertex of a parabola is the highest or lowest point on the curve, depending on whether the parabola opens upward or downward.
To find the x-coordinate of the vertex, we can use the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic equation [tex]ax^2 + bx + c[/tex]. In this case, a = -16 and b = 24, so we have:
x = -b/2a = -24/(2*(-16)) = 0.75
To find the y-coordinate of the vertex, we can substitute x = 0.75 into the equation h = [tex]-16x^2 + 24x + 30[/tex], which gives us:
h = [tex]-16(0.75)^2 + 24(0.75) + 30 = 36[/tex]
Therefore, the maximum height of Marsha's math book is 36 feet.
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Can someone please answer numbers 12, 13, 14, and 15?