Garden plots in the Portland Community Garden are rectangles limited to 45 square meters. Christopher and his friends want a plot that has a width of 7.5 meters. What length will give a plot that has the maximum area allowed?

The total length of each roll of edging in Mrs. Thomas's scale drawings will be 19.2 cm.

To find the total length of each roll of edging in her scale drawings, we need to convert the length from inches to centimeters using the given scale.

To convert the length to centimeters:

( Length in cm ) / ( Length in inches ) = ( 1  cm ) / ( 5 inches )

x / 96 inches = 1 cm / 5 inches

x 5 inches = 96 inches x 1 cm

5x = 96 cm

x = 96 cm / 5

x = 19.2 cm

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The area of the given region under the curve of a function f(x) = ax + b on the interval [0, 4] is 16 square units. So, all the options satisfy the value of a and b except (7, -9).

The area of the given region under the curve of a function f(x) = ax + b on the interval [0, 4] is 16 square units.

f(x) is a linear function, the area under the curve on the interval [0,4] is a trapezoid with a height of 4 and bases of lengths f(0) and f(4).

The area of a trapezoid is the height times the average of the bases.

a. f(x)=-2x+8  f(0)=8, f(4)=0;

  area = 4(8/2) = 16

b. f(x)=x+2; f(0)=2, f(4)=6;

  area = 4(8/2) = 16

c. f(x)=3x-2; f(0)=-2, f(4)=10;

   area = 4(8/2) = 16

d. f(x)=5x-6; f(0)=-6, f(4)=14;

   area = 4(8/2) = 16

e. f(x)=7x-9; f(0)=-9, f(4)=19;

    area = 4(10/2) = 20

Thus, The area is NOT 16 for choice e.

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The answer is B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.

To solve this problem, we are given a function h(x) and asked to find its antiderivative or indefinite integral, which is denoted by H(x) and is defined as the function whose derivative is h(x). We are also given a specific value of H(x) at x = 6 and asked to use it to find the constant of integration, denoted by C.

The given function is h(x) = 22x - 3x² - 6/x, and we want to find H(x), which is the antiderivative of h(x). Using the power rule of integration, we can integrate each term of h(x) separately:

where C is the constant of integration. Note that we need to include an absolute value sign around x in the natural logarithm term because the function is not defined for x = 0.

Next, we are given that H(6) = 31, which means that when x = 6, the value of H(x) is 31. Substituting x = 6 and H(x) = 31 into the above equation, we get:

Simplifying, we get:

Therefore, the antiderivative of h(x) is:

We can simplify the expression by using the identity ln|a/b| = ln|a| - ln|b|:

where C is the constant of integration. Thus, the final answer is:

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The equation to find the number of hours, t, until Patty and Carol are at the same location is: 70t + 50t = 300.


1. Patty and Carol start driving at the same time, towards each other on the same highway.
2. The distance between their cities is 300 miles.
3. Patty drives at an average speed of 70 mph, so in t hours she covers 70t miles.
4. Carol drives at an average speed of 50 mph, so in t hours she covers 50t miles.
5. As they drive towards each other, the sum of the distances they cover should equal the total distance between their cities.
6. Therefore, combining the distances covered by Patty and Carol, we get: 70t (Patty's distance) + 50t (Carol's distance) = 300 (total distance).

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The angle measure of the rhombus with one diagonal of a rhombus is a geometric mean of the length of the other diagonal are measured to be 75.5° .

Let d₁ and d₂ be the lengths of the diagonals of the rhombus and s as the side length. We have,

d₁ = s√2 (since the diagonal is the hypotenuse of a right triangle formed by two sides of length s)

d₁ = √d₂s

Combining these two equations, we get,

s√2 = √d₂s

Squaring both sides, we get,

2s² = d₂

Since the diagonals of a rhombus are perpendicular bisectors of each other, we have,

cosθ = (1/2) (where θ is one of the acute angles of the rhombus)

Using the law of cosines with sides s and d₂/2, we have,

(s² + (d₂/2)² - 2sd₂/2cosθ) = s²

Simplifying, we get,

d₂ = 4s cosθ

Substituting this expression for d₂ in 2s² = d₂, we get,

2s² = 4scosθ

Dividing both sides by 2s and simplifying, we get,

s = 2cosθ

Therefore, the angle measures of the rhombus are,

θ = arccos(s/2)

= arccos(cosθ/2)

= arccos(1/4)

= 75.5°

And the other acute angle has the same measure.

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Yes, there is a relationship like a straight line between the raises administrators at State University receive and their performance on the job

To obtain this interpretation, we consider the equation of the regression line, which relates the predicted raise amount (y hat) to the job performance rating (x). The y-intercept term in this equation is the value of y hat when x equals zero. Therefore, the estimated y-intercept of $14,000 represents the predicted raise amount for an administrator whose job performance rating is zero, which corresponds to the base raise amount at State University.

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The limit of sec(y sec²y - tan²y - 1) as y approaches 1 is undefined. The function is not continuous at the point being approached.

Explanation: To evaluate the limit, we can first simplify the expression inside the secant function using the trigonometric identity:sec²θ - tan²θ = 1/cos²θ - sin²θ/cos²θ = (1 - sin²θ)/cos²θ = cos²θ / cos²θ = 1Substituting this expression back into the limit, we get:lim sec(y sec²y - tan²y - 1)y→1= lim sec(y - 1)y→1As y approaches 1, the argument of the secant function approaches 0, which means that the secant function approaches infinity. Therefore, the limit is undefined.Since the limit is not defined, the function is not continuous at the point being approached. A function is continuous at a point if and only if the limit of the function as x approaches that point exists and is equal to the value of the function at that point. In this case, since the limit does not exist, the function is not continuous at y = 1.

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The number of solutions that are there for the pair of equations for lines Q and S is zero solution (no solution) because the lines are parallel with no point of intersection.

In Mathematics and Geometry, no solution is sometimes referred to as zero solution, and an equation is said to have no solution when the left hand side and right hand side of the equation are not the same or equal.

This ultimately implies that, a system of equations would have no solution when the line representing each of the equations are parallel lines and have the same slope i.e both sides of the equal sign are the same and the variables cancel out.

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The critical numbers of f are x = -5 and x = 5.

(A) To find the derivative f'(x), we differentiate f(x) = x³ - 75x - 2 with respect to x:
f'(x) = 3x² - 75

(B) There are no partition numbers for f' as partition numbers are related to integer partitions, which are not applicable in this context.

(C) To find the critical numbers of f, we set f'(x) equal to 0 and solve for x:
3x² - 75 = 0
x² = 25
x = ±5

So the critical numbers of f are x = -5 and x = 5.

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Answer:

-4 = 5

0 = -1

2 = -4

4 = -7

(-4, 5)

(0, -1)

(2, -4)

(4, -7)

Step-by-step explanation:

First, let's identify what each term represents.

y-intercept: -1

slope: 3/2

Then, fill out the table.

x = -4

-1 - (3/2 · -4)

-1 - (-12/2)

-1 - (-6)

-1 + 6

y = 5

x = 0

-1 - (3/2 · 0)

-1 - 0

y = -1

x = 2

-1 - (3/2 · 2)

-1 - (6/2)

-1 - (3)

y = -4

x = 4

-1 - (3/2 · 4)

-1 - (12/2)

-1 - (6)

y = -7

Then, plot the points in the function on the graph.

(-4, 5)

(0, -1)

(2, -4)

(4, -7)

Answer:

Step-by-step explanation:

It's given that, The height of three basketball players is 210 cm, 220 cm and 191 cm.

h₁ = 210 cm

h₂ = 220 cm

h₃ = 191 cm

Total number of observations = 3.

Average = Sum of all observations/Total number of observations.

↠ Average = h₁ + h₂ + h₃/3

↠ Average = 210 +220 + 191 /3

↠ Average = 430 + 191/3

↠ Average = 621/3

↠ Average = 207

Therefore, The required average height is 207 cm.

Answer: x(squared) + (y + 2)(squared) = 36

Step-by-step explanation:

The center of the circle is at (0 , -2), so we will eliminate the x value by just writing x(squared), and then we will write the y value as (y + 2)(squared) because the standard form for a circle is

(x - h)(squared) + (y + 2)(squared) = r(squared)

And if we count from the center to the top point of the circle, the number would be 6, so we would square 6 which would be 36.

Answer:

1

1

1

2

2

2

2

Step-by-step explanation:

Optimize crate cost by expressing material cost in terms of x and y, calculating cost of all four sides, and finding minimum cost. Optimal dimensions: x = 16 ft, y = 48 ft. Minimum cost: $8704.

To find the dimensions of the crate that will minimize the total cost of material, we need to use optimization techniques, we need to express the cost of materials in terms of x and y then calculate the cost of all four sides, then find the minimum cost.
Let's start by defining the variables we need to work with:

Let x be the length of one side of the square base (in feet),  Let y be the height of the crate (in feet).
From the given volume, we know that:
V = x^2 * y = 12288 ft^3
We can use this equation to solve for one of the variables in terms of the other:
y = 12288 / (x^2)
Now we need to express the cost of materials in terms of x and y.
The area of the bottom is x^2, so the cost of the bottom is:
[tex]C_b = 10 * x^2[/tex]
The area of each side is x * y, and there are four sides, so the cost of the sides is:
[tex]C_s = 4 * 2 * x * y = 8xy[/tex]
The area of the top is also x^2, so the cost of the top is:
[tex]C_t = 2 * x^2[/tex]
The total cost of materials is the sum of these three costs:
[tex]C = C_b + C_s + C_t = 10x^2 + 8xy + 2x^2[/tex]
Now we can substitute y = 12288 / (x^2) into this equation:
[tex]C = 10x^2 + 8x * (12288 / x^2) + 2x^2[/tex]
Simplifying this expression, we get:
[tex]C = 12x^2 + 98304 / x[/tex]
To find the minimum cost, we need to find the value of x that minimizes this expression. We can do this by taking the derivative of C with respect to x and setting it equal to zero:
C' = 24x - 98304 / x^2 = 0
Solving for x, we get:
x = 16 ft
Now we can use this value of x to find y:
y = 12288 / (16^2) = 48 ft
Therefore, the dimensions of the crate that will minimize the total cost of material are:
- Length of one side of the square base = x = 16 ft
- Height of the crate = y = 48 ft
To check that this is indeed the minimum cost, we can plug these values back into the expression for C and calculate the cost:
C = 10 * 16^2 + 8 * 16 * 48 + 2 * 16^2 = 8704
Therefore, the minimum cost of material for the crate is $8704.

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The area of the quadrilateral can be found by dividing it into two triangles and finding the sum of their areas. The line connecting points B and D divides the quadrilateral into two triangles ABD and BCD. The area of triangle ABD is 1/2 * base * height = 1/2 * 6 * 6 = 18 square units. The area of triangle BCD is 1/2 * base * height = 1/2 * 3 * 8 = 12 square units. Therefore, the area of the quadrilateral is 18 + 12 = 30 square units.

The estimated quantity of the substance at t = 1.9 is approximately 35.3 units.

To estimate the quantity of the substance at t = 1.9 using linear approximation, we can use the formula:

ΔR ≈ dR/dt * Δt

Given the point R(2) = 35 and the differential equation dR/dt = -1/5(R – 20), we can first find the value of dR/dt at t = 2.

dR/dt(2) = -1/5(R(2) – 20) = -1/5(35 – 20) = -1/5(15) = -3

Now, we can calculate Δt, which is the difference between the given t-value (2) and the desired t-value (1.9):

Δt = 1.9 - 2 = -0.1

Next, we can calculate ΔR using the linear approximation formula:

ΔR ≈ dR/dt * Δt ≈ -3 * (-0.1) = 0.3

Finally, we can estimate the quantity of the substance at t = 1.9 by adding ΔR to the given value of R(2):

R(1.9) ≈ R(2) + ΔR ≈ 35 + 0.3 = 35.3

Therefore, the estimated quantity of the substance at t = 1.9 is approximately 35.3 units.

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The correct options are:

Option B:  The football is thrown from 6 feet off the ground.

when t = 0

h(t) = 6 * 75 * 0 + 16 * 0

= 6 feet

Option C : - 16t² represents the effect of gravity

we have

[tex]h = ut - \frac{1}{2}gt^2[/tex]

[tex]\frac{1}{2}gt^2=-16t^2[/tex]

F. The vertex of the graph of h gives the maximum height of the foot

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The values of the variables x and y area 42 and 12 respectively

We can see that the quadrilateral that is inscribed in the circle is a parallelogram.

The properties of a parallelogram includes;

Then, from the information given, we have that;

x + 35 = 77

Now. collect the like terms, we get;

x = 77 - 35

subtract the values, we have;

x = 42

Also,

4y + 46 = 94

collect the like terms

4y = 94 - 46

4y = 48

Divide by the coefficient of y, we have;

y = 12

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Answer:p(x)=3x+5

Step-by-step explanation:

f(x)=2x+3

g(x)=x+2

p(x)=(2x+2)+(x+2)= 3x+5

Answer:

p(x)=ax + b

Step-by-step explanation:

Answer:

x = 30 , y = 54

Step-by-step explanation:

the figure is a trapezium

each lower base angle is supplementary to the upper base angle on the same side, then

4x + y + 6 = 180 ( subtract 6 from both sides )

4x + y = 174 ( subtract 4x from both sides )

y = 174 - 4x → (1)

and

2x + 12 + 2y = 180 → (2)

substitute y = 174 - 4x into (2)

2x + 12 + 2(174 - 4x) = 180

2x + 12 + 348 - 8x = 180

- 6x + 360 = 180 ( subtract 360 from both sides )

- 6x = - 180 ( divide both sides by - 6 )

x = 30

substitute x = 30 into (1)

y = 174 - 4(30) = 174 - 120 = 54

thus x = 30 and y = 54

Answer: Box and whisker plots are plots on number lines with a box and two lines off the edges, called whiskers. The box has a line at the upper quartile(1), one at the lower quartile(2), and one in the center of the box at the median(3). The two lines go to the ends of the data, one at the minimum(4) and one at the maximum(5).

  4     2     3       1             5

   |-----[___|____]-----------|

₀__₁__₂__₃__₄__₅__₆__₇__₈

I hope this helps.

The profit is maximized at $16,400 when the ticket price is $12.

To find the ticket price that maximizes the profit, we used the fact that the maximum or minimum value of a quadratic function occurs at its vertex. For a quadratic function in the form of P(x) = ax^2 + bx + c, the x-coordinate of the vertex can be found using the formula x = -b / 2a.

In this case, we were given the function [tex]P(x) = -100x^2 + 2400x - 8000,[/tex]where x represents the price per ticket. The coefficient of [tex]x^2[/tex] is negative, which tells us that the graph of this function is a downward-facing parabola. The vertex of this parabola represents the maximum value of the function.

Using the formula x = -b / 2a, we found the x-coordinate of the vertex to be x = -2400 / 2(-100) = 12. This means that a ticket price of $12 will maximize the profit.

To verify that this is indeed the maximum profit, we substituted x = 12 into the profit function P(x):

[tex]P(12) = -100(12)^2 + 2400(12) - 8000 = 16,400[/tex]

We can see that the profit is maximized at $16,400 when the ticket price is $12.

In summary, to find the ticket price that maximizes the profit, we used the formula x = -b / 2a to find the x-coordinate of the vertex of the quadratic function representing the profit from selling tickets to a musical. The maximum profit occurs at the ticket price that corresponds to the x-coordinate of the vertex.

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Answer:

D

Step-by-step explanation:

A rhombus with a diagonal of 26.4 cm and an area of 204.6 square cm has another diagonal of length 15.5 cm

Rhombus is a 2-Dimensional shape. It is a quadrilateral. It is a specialized form of a parallelogram. All sides of a rhombus are equal in length.

Similar to a parallelogram, it has opposite sides parallel to each other and opposite angles of equal magnitude.

The area of a rhombus is expressed as half of the product of diagonals.

A = 0.5pq

A is the area

p is the length of one diagonal

q is the length of another diagonal

A = 204.6 square cm

p = 26.4 cm

204.6 = 0.5 * 26.4 * q

q = 15.5 cm

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To use logarithmic differentiation to find the derivative of the function y = x²/x, we first take the natural logarithm of both sides:

ln(y) = ln(x²/x)

Using the properties of logarithms, we can simplify this to:

ln(y) = 2 ln(x) - ln(x)

Now we differentiate both sides with respect to x using the chain rule:

1/y * y' = 2/x - 1/x

Simplifying this expression, we get:

y' = y * (2/x - 1/x²)

Substituting back in the original expression for y, we have:

y' = x²/x * (2/x - 1/x²)

Simplifying further, we get: y' = 2x - 1/x

Therefore, the derivative of the function y = x²/x using logarithmic differentiation is y' = 2x - 1/x.

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The volume of the resulting solid is estimated 4,128.38 cubic units.

The volume of the ball isgitten as:

V_ball = (4/3)πr^3

r is the radius of the ball. In this scenario

r = 11, so:

V_ball = (4/3)π(11)^3

V_ball = (4/3)π(1331)

V_ball = 4,396.46 cubic units

The volume of the hole is gotten as :

V_hole = (4/3)πr^3

r is the radius of the hole.

In thisscenario, r = 4, so:

V_hole = (4/3)π(4)^3

V_hole = (4/3)π(64)

V_hole = 268.08 cubic units

In conclusion, the volume of the resulting solid is:

V_resulting_solid = V_ball - V_hole

V_resulting_solid = 4,396.46 - 268.08

V_resulting_solid = 4,128.38 cubic units

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If a large airline wants to estimate its average number of unoccupied seats per flight over the past year Then a 92% confidence interval for the population mean number of unoccupied seats per flight is (10.334, 12.266) seats.

To construct a confidence interval for the population mean number of unoccupied seats per flight, we will use the following formula CI = X ± z*(σ/√n)

Where:

X = sample mean = 11.3 seats

σ = sample standard deviation = 4.3 seats

n = sample size = 300

z = z-score corresponding to the desired confidence level of 92%, which we can look up in a standard normal distribution table or use a calculator. For a 92% confidence level, the z-score is 1.75.

Plugging in the values, we get:

CI = 11.3 ± 1.75*(4.3/√300)

CI = 11.3 ± 0.966

Therefore, the 92% confidence interval for the population mean number of unoccupied seats per flight is (10.334, 12.266) seats. This means we can be 92% confident that the true population means a number of unoccupied seats per flight falls within this interval.

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After solving the word problem, the large bag contains enough sugar to make 40 cakes

Since the large bag is 2.5 times larger than the small bag, and the small bag contains enough sugar to make 9 cakes, the large bag contains enough sugar to make:

2.5 * 9 = 22.5 cakes

However, since there are only 30 cups of sugar in the large bag, and we don't know how much sugar is needed to make a single cake, we cannot determine the exact number of cakes that can be made with a large bag of sugar.

As for the small bag, if it had enough sugar to make 9 cakes and there are 0.75 cups of sugar remaining, then each cake requires:

(sugar in bag - remaining sugar) / number of cakes

= (9 - 0.75) / 9

= 0.75 cups of sugar

Therefore, the large bag contains enough sugar to make:

30 cups / 0.75 cups per cake

= 40 cakes

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