help pls !! ♡
6. In the diagram of circle O, tangent PB is drawn as is secant PAC. We wish to prove the Secant/Tangent Length Theorem, i.e. PA·PC = PB2. (a) Explain why APAB is similar to APBC (i.e. explain which two angles pairs must be congruent and why). O® A P B (6) Set up a proportion involving PA, PB, and PC based on the similar triangles and rewrite it in product form. Draw the two similar triangles separately and in the same orientation to help. COMMON CORE GEOMETRY, UNIT #8 - CIRCLE GEOMETRY - LESSON #8 eMATHINSTRUCTION, RED HOOK, NY 12571, © 2018​

Answer: y=5x+100

Step-by-step explanation:

the y intercept is the 100$ invested into the account, and the rate of change is 5

Answer:

IQR = 5

Step-by-step explanation:

the IQR is the difference between the upper quartile Q₃ and the lower quartile Q₁

Q₃ is the value at the right side of the box plot , that is

Q₃ = 51

Q₁ is the value at the left side of the box plot , that is

Q₁ = 46

then

IQR = Q₃ - Q₁ = 51 - 46 = 5

Answer:

where is the prism? did u attach a photo of it

The value of the constant of variation is one-fourth. Then the correct option is A.

The term "constant of variation" refers to the fact that the relationship between variables remains constant.

The formula will be

y = kx

where k is the variation constant.

When f = 2 and g = 8, n = 4. if n varies jointly with f and g, then the equation will be

n = kgf

Then the value of k will be

4 = (2)(8)k

k = 1/4

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Answer:

Keep it simple. Answer: A

Step-by-step explanation:

Answer:

The correct option is a.

The given expression is,Use property of logarithm

The value of log(0.5) is -0.30103.

The value of given expression is -4.81648.

If the final answer appromatted to preceding integer, then the correct option is -4.00.Step-by-step explanation:

The value of the [tex]log_{0.5}[/tex] (16) will be -4.00 so the correct option will be (A).

The exponent indicates the power to which a base number is raised to produce a given number called a logarithm.

A logarithm is a power to which a number must be raised in order to get some other number.

A logarithm is useful to find out the values on which power has a variable.

In another word, a logarithm is a different way to denote any number.

If you want to write 1 in logarithm then it will be log(base).

[tex]log_{a}[/tex] (x) = b ⇒ [tex]a^{b}[/tex] = x.

Let's say the given number is x then

x = [tex]log_{0.5}[/tex] (16)

[tex]0.5^{x}[/tex] = 16

Take log by both sides

Log[tex]0.5^{x}[/tex] = log 16

By log property

x log 0.5 = log 16

x = -4.00 hence, the correct answer to the given question will be -4.00.

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Answer:

1. true 2. false 3. false 4. true 5. false 6. false or true

Step-by-step explanation:

you're welcome

Answer:

x=1.082682

Step-by-step explanation:

Answer:

what do you need help with

Step-by-step explanation:

Answer:

SAME

Step-by-step explanation:

I am so happy someone else goes through this! I'm SO happy I'm not alone.

Since, the fundraiser only have three prices for books($2, $5 and $10), the number of $5 book that was sold is 12.

The fundraiser only have 3 prices for books which are $2, $5 and $10.

There were 6 more $5 books sold than $10 books sold.

Let

x = number of $10 book sold

Therefore,

number of  $5 books sold = x + 6

There are 8 more $2 book sold than $10 book sold. Therefore,

number of  $2 books sold = x + 8

A total of $250 was raised.

Therefore, the total amount sold forms the following equation:

10x + 5(x + 6) + 2(x + 8) = 250

10x + 5x + 30 + 2x + 16 = 250

17x = 250 - 30 - 16

17x  = 204

x = 204 / 17

x = 12

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Answer:

60%

Step-by-step explanation:

(4-2.5):2.5*100 =

(4:2.5-1)*100 =

160-100 = 60

The given quadratic equation has no real solutions.

Given quadratic equation is:

[tex]ax^2+bx+c=0[/tex]

The discriminant(D) of a quadratic equation tells about the nature of roots.

If [tex]D > 0[/tex], the roots of the quadratic equation will be real and distinct.

If [tex]D=0[/tex], the roots of the quadratic equation will be real and equal.

If [tex]D < 0[/tex],  the roots of the quadratic equation will be imaginary.

Given that the quadratic [tex]ax^2+bx+c=0[/tex] has a discriminant value of -16.

[tex]D=-16 < 0[/tex]

So, the roots of the given quadratic equation will be imaginary.

So, the given quadratic equation has zero real solutions.

Hence, the given quadratic equation has no real solutions.

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Answer:

A

Step-by-step explanation:

A)(m+8)(2 ÷3)

Because 2/3 is just 2 divided by 3

Brainliest please?

Answer: y = -1.3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: 37.5

Explanation: find the surface area of one side, which is 2.5*2.5=6.25 then multiply that product by six, since there’s six sides in a square, and you’ll get 37.5

Answer:

do you have a picture so I can see more information

Answer:

AD = 44 and angle CAB = 90 degrees

Step-by-step explanation:

since the shape is a rectangle, all corner angles must be 90 degrees. so CAB is also 90 degrees.

the length of half of BC is 22, so the full length of BC is 44. using symmetry, AD should also be 44.

byebye!<3

Answer:

see below

Step-by-step explanation:

7x-12=30

7x=30-+12

x=42/7

x=6

5x-18=77

5x=77+18

x=95/5

x=19

8x+12=36

8x=36-12

x=24/8

x=3

x+45=72

x=72-45

x=27

x+27=82

x=82-27

x=55

x-13=66

x=66+13

x=79

Answer:

0.64

Step-by-step explanation:

...........................

Answer:

0.64

Step-by-step explanation:

3.20 divided by 5 is 0.64.

The answer is: (1, –1)

Answer:

B

Step-by-step explanation:

[tex]\frac{2}{3}[/tex] + [tex]\frac{x}{3}[/tex] > 1 ( multiply through by 3 to clear the fractions )

2 + x > 3 ( subtract 2 from both sides )

x > 1

Answer:

Step-by-step explanation:

In the question we are given with ,

And we are asked to find the perimeter of rectangle . As we know that ,

[tex] \red {\boxed{\rm{Perimeter \: of \: rectangle = 2 ( L + W ) }}}[/tex]

Where ,

Substituting values of length and width in formula :

[tex] \longmapsto \: 2(28 + 9)[/tex]

Step 1 : Solving the parenthesis :

[tex] \longmapsto \: 2(37)[/tex]

Step 2 : Multiplying 2 and 37 :

[tex] \longmapsto \: \red{ \boxed{74 \: cm}}[/tex]

Answer:

69.5 if C and D both add up to 90, M=90 if both angles C and D were complementary to combine to a supplementary.

Step-by-step explanation:

You're trying to find m which is a variable for measurement for the "D" angle.

Info Given:

20.5 for angle C

Unknown for angle D

Both angles are Complementary.

_____________________________________________

I have 2 answers for this (The question was stated unclearly so I have 2 interpretations of this)

1st Answer:

If you're asking to solve for M but the C and D angles add up to 90 then do

90 - 20.5 = 69.5

2nd Answer:

We know that both angles are complementary which are 90-degree angles.

If we combine them then the angles add up to 180.

So C and D add up to form a Supplementary Angle.

20.5+69.5 + m = 180

Then M could possibly be 90.

The total cost of tuition, books, and fees for Jose if he eventually chooses to attend this college for four years is $58,000.

Multipiciation is the process of combining numbers or vectors together in order to determine their product. Multiplication is represented with this sign: x.

The total cost of attending the college for four years = cost per year x total number of years

$14,500 x 4 = $58,000

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Answer:

3.90 sq cm

Step-by-step explanation:

[tex]A_{equilateral\: \triangle} = \frac{ \sqrt{3} }{4} \times {(side)}^{2} \\ \\ = \frac{ \sqrt{3} }{4} \times {(3)}^{2} \\ \\ = \frac{9 \sqrt{3} }{4} \\ \\ = 3.89711432 \: {cm}^{2} \\ \\ \approx \: 3.90 \: {cm}^{2} [/tex]

Answer:

A

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

2.25/.5

We will see that the system of equations has infinite solutions, each of the form:

y = (3/2)*(x + 1)

Here we have the system:

3x - 2y = -3

-9x + 6y = 9

Notice that if we add 3 times the first equation to the second one, we get zero.

3*(3x - 2y) + -9x + 6y  = 3*(-3) + 9

9x - 6y - 9x + 6y = -9 + 9

0 = 0

This actually means that both equations represent the same line, then, the "two" lines intersect in infinite points, meaning that the system of equations has infinite solutions, which are of the form:

3x - 2y = -3

2y = 3 + 3x

y = (3/2)*(x + 1)

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The sketch of the function on the set of axes is given below:

The zero of any real-, complex-, or generally vector-valued function f, is a member x of the domain of function such that f(x)=0 at x; x is the solution to the equation f(x) = 0.

As we have the zeros 2,-2,4,-4

The function can be:

[tex]f(x)=(x-2)(x+2)(x-4)(x+4)\\f(x)=(x^2-4)(x^2-16)\\f(x)=x^4-20x^2+64[/tex]

The sketch using a graphing calculator:

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The expression which is equivalent to the given ratio of the two provided binary fraction is startfraction 3 (6) minus 1 over 2 (6) 1 endfraction.

Equivalent expressions are the expression whose result is equal to the original expression, but the way of representation is different.

The given binary functions are.

[tex]r(x) = 3x - 1[/tex]

[tex]s(x) = 2x +1[/tex]

The expression which has to be found out is,

[tex]\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{3(6)-1}{2(6)+1}\right)\\\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{18-1}{12+1}\right)\\\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{17}{13}\right)[/tex]

Thus, the expression which is equivalent to the given ratio of the two provided binary fraction is startfraction 3 (6) minus 1 over 2 (6) 1 endfraction.

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