HELP PLS THIS IS DUE TOMORROW PLSSSSSSSS

Are ARST and ANSP similar? Use pencil and paper. Find the
measure of the angles in each triangle.

Which two angles must be congruent? What type of angles are they? (1 point)

Answer:

50 pages are filled with stamps.

Step-by-step explanation:

If 50% of the album is empty, then 50% of the album is filled with stamps.

So, the total number of stamps that the album holds is 500, and half of that (50%) is filled with stamps, which is:

500 * 50% = 250 stamps

Each page holds 5 stamps, so the number of pages filled with stamps is:

250 stamps / 5 stamps per page = 50 pages

Therefore, 50 pages are filled with stamps

Answer:

Step-by-step explanation:

Answer:

Cross Sections

In this task, you will use cross section flyer, an online tool, to investigate the cross sections of cones, cylinders, pyramids, and prisms by passing different planes through such objects.

For each part of this task, you will select a three-dimensional object from the list of shapes in the bottom-left corner of the screen. A three-dimensional view of the object appears on the left, and the two-dimensional cross section formed by the intersection of the object with the chosen plane appears on the right. The bottom-right controls allow you to rotate and move the plane of intersection. By varying the intersecting plane, you can change the resulting cross section.

You can also adjust the view of the three-dimensional object by clicking and dragging anywhere inside the object window. Use the coordinate X-Y-Z axes to guide you through the views. You can verify the name of a cross section by using the Click to show identification of cross section checkbox.

I think the answers 3048_&8_9_)_)_

Answer:

The new value of the portfolio would be $207,000 - $18,180 = $188,820

Step-by-step explanation:

Using the first-order partial derivatives, we can calculate the approximate change in the portfolio value due to changes in E and S using the formula:

ΔP ≈ ∂P/∂E * ΔE + ∂P/∂S * ΔS

where ΔE is the change in the price of a Euro and ΔS is the change in the TSX stock index.

Given that ∂P/∂E = 80,000 and ∂P/∂S = -20, and the changes ΔE = -0.07 and ΔS = -629, we can plug in the values and get:

ΔP ≈ 80,000 * (-0.07) + (-20) * (-629)

≈ -5,600 - 12,580

≈ -18,180

Therefore, the portfolio value is expected to decrease by approximately $18,180 if the price of a Euro goes down by $0.07 and the TSX stock index goes down by 629 points. The new value of the portfolio would be $207,000 - $18,180 = $188,820.

Answer:4x^2-4x-1

Step-by-step explanation:

The area and the circumference of the circle would be 4π square kilometers and 4π kilometers respectively.

The area of a circle with a radius r is given by:

The circumference of a circle with a radius r is given by:

Given that the radius of the circle is 2km, we can substitute r = 2 into these formulas to find the area and circumference:

In other words, the area and the circumference of the circle are 4π square kilometers and 4π kilometers respectively.

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For Bob: Mean =10.13,MAD = 2.66,Median =10.5 ,IQR = 5.5,Q1 = 8,Q3 = 13.5

for alan :Mean =7.25,Median = 7.5,IQR = 10,Q1 = 4,Q3 = 14

For Bob:

Mean = (8+15+10+10+10+15+7+8+10+9+12+11+11+13+7+8+9+9+8+10+11+14+11+10+9+12+14+14+12+13+5+13+9+11+12+13+10+8+7+8) / 38 = 10.13

MAD = 2.66 (calculated using the median of Bob's data)

To calculate the median and quartiles for Bob's data, we need to first sort the data in ascending order:

5, 7, 7, 8, 8, 8, 8, 9, 9, 9, 10, 10, 10, 10, 11, 11, 11, 11, 12, 12, 13, 13, 13, 14, 14, 15, 15

Median = (10+11) / 2 = 10.5

Q1 = median of the first half of the data = (8+8) / 2 = 8

Q3 = median of the second half of the data = (13+14) / 2 = 13.5

IQR = Q3 - Q1 = 13.5 - 8 = 5.5

Therefore, for Bob:

Median = 10.5

IQR = 5.5

Q1 = 8

Q3 = 13.5

For Alan:

Mean = (2+3+4+5+7+10+12+14+15+16) / 10 = 7.25

MAD = 2.81 (calculated using the median of Alan's data)

Median = 7.5 (calculated as the average of the 5th and 6th value in Alan's sorted data)

Q1 = 4

Q3 = 14

IQR = Q3 - Q1 = 14 - 4 = 10

Therefore, for Alan:

Median = 7.5

IQR = 10

Q1 = 4

Q3 = 14

To determine if there are any outliers, we can use the following formula:

Outliers = data points outside the range [Q1 - 1.5(IQR), Q3 + 1.5(IQR)]

For Bob:

Lower outlier bound = 8 - 1.5(5.5) = -0.25

Upper outlier bound = 13.5 + 1.5(5.5) = 24.25

There are no outliers in Bob's data.

For Alan:

Lower outlier bound = 4 - 1.5(10) = -11

Upper outlier bound = 14 + 1.5(10) = 29

There are no outliers in Alan's data.

If the team needs a more consistent player with a higher median and narrower IQR, Bob might be a better choice. On the other hand, if the team needs a player who can potentially score more points, Alan might be a better choice as his mean is higher.

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The greatest common factor of 6s³t⁴ + 12s⁴t² - 15s²t³ is 3s²t², and the factored expression is 3s²t²(2st² + 4s² - 5t).

The greatest positive integer that divides two or more numbers without leaving a residual is known as the greatest common factor (GCF). In other words, the greatest number that is a factor of both (or all) of the specified numbers is chosen.

To identify the greatest common factor of 6s³t⁴ + 12s⁴t² - 15s²t³, we need to look for the largest expression that divides evenly into each term.

First, we can factor out the greatest common factor of the coefficients, which is 3: 3(2s³t⁴ + 4s⁴t² - 5s²t³)

Next, we can look for the greatest common factor of the variables. We can see that s²t² divides into each term: 3s²t²(2st² + 4s² - 5t)

Therefore, the greatest common factor of 6s³t⁴ + 12s⁴t² - 15s²t³ is 3s²t², and the factored expression is 3s²t²(2st² + 4s² - 5t).

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Step-by-step explanation:

The density of gold is given as 5×2^2 grams/cm³, which means that one cubic centimeter of gold has a mass of 5×2^2 grams.

To find the mass of 8 × 25 cm³ of gold, we need to first find the total volume of gold:

Total volume = 8 × 25 cm³ = 200 cm³

Now we can use the density of gold to find the mass:

Mass = Density × Volume

Mass = (5×2^2 grams/cm³) × 200 cm³

Mass = 5 × 4 × 200 grams

Mass = 4000 grams

Therefore, the mass of 8 × 25 cm³ of gold is 4000 grams.

The statement "cos 0° = 1, because the angles are complements" is true.

The ladder makes an angle of approximately 19.94 degrees with the wall.

We can use trigonometry to solve for the angle between the ladder and the wall.

Let's call the angle we're looking for "theta" (θ). We can use the cosine function, which is defined as the ratio of the length of the adjacent side to the length of the hypotenuse side of a right triangle, to solve for theta:

cos(θ) = opposite/adjacent

So we have:

cos(θ) = 4.7/5

We can use a calculator to solve for theta:

cos(θ) = 0.94

Take the arc cos

θ ≈ 19.94 degrees

Therefore, the ladder makes an angle of approximately 19.94 degrees with the wall.

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Question 1:

Answer:

[tex]C:25\frac{1}{3}[/tex]

Step-by-step explanation:

To find the number of pounds of milk chocolate sold, you have to multiply the amount of pounds of white chocolate sold by 4.

[tex](6+\frac{1}{3}) *4\\\\(6*\frac{3}{3}+\frac{1}{3})*4\\\\(\frac{18}{3} +\frac{1}{3} )*4\\\\\frac{19}{3} *4\\\\\frac{76}{3} \\\\25\frac{1}{3}[/tex]

Question 2:

Answer:

C: 19

Step-by-step explanation:

To find how many more pounds of milk chocolate were sold we subtract the white chocolate sold from the milk chocolate sold

[tex]25+\frac{1}{3} - 6+\frac{1}{3}\\\\25*\frac{3}{3}+\frac{1}{3}-6*\frac{3}{3}+\frac{1}{3}\\\\\frac{76}{3}-\frac{19}{3}\\\\\frac{57}{3}\\\\19[/tex]

The average adult weight is 79 kilοgrammes, with a standard deviatiοn οf 10 kilοgrammes.

We want tο find the prοbability that the sample mean οf 188 adults wοuld be greater than 80.5 kilοgrams.

An n-sample sample mean is given by: x = xi / n

where xi is the tοtal οf the sample's individual weights.

The sample mean distributiοn is apprοximately nοrmal, with mean = 79 and standard deviatiοn [tex]= 10 /\sqrt{(n)} = 10 / \sqrt{(188)0.727.}[/tex]

We can standardise the sample mean tο find the prοbability that it is greater than 80.5 kilοgrammes using the fοrmula: [tex]z = (x - ) / ( / \sqrt{(n)})[/tex]

where z is the standard nοrmal variable.

Substituting the values, we get:

[tex]z = (80.5 - 79) / (10 / \sqrt{(188)}) \approx2.14[/tex]

Using a standard nοrmal table οr calculatοr, we can find the prοbability that z is greater than 2.14:

P(z > 2.14) ≈ 0.0161

Therefοre, the prοbability that the sample mean οf 188 adults wοuld be greater than 80.5 kilοgrams is apprοximately 0.0161, rοunded tο fοur decimal places.

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The amount of citrus juice in the combination is therefore 0.75, or 75%.

The area filled within an object's boundaries in three dimensions is referred to as its volume. It is also referred to as the object's potential.

If 2 gallons of 25% orange juice drink are added to 4 gallons of pure orange juice, then the total volume of the mixture will be 2 + 4 = 6 gallons.

Let's use the given function f(x) to calculate the concentration of orange juice in the mixture:

f(2) = (4 × 1.0 + 2 × 0.25) / (4 + 2)

= (4 + 0.5) / 6

= 4.5 / 6

= 0.75

Therefore, the concentration of orange juice in the mixture is 0.75 or 75%.

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Answer:

63

Step-by-step explanation:

we divided 18÷2=9

and we multiply 9×7=63

Answer:

[tex]p(a) = \frac{7}{100} [/tex]

Step-by-step explanation:

Given:

7 red marbles

18 blue marbles

Total number of marbles: 7 + 18 = 25

All outcomes:

[tex]n = \frac{25 \times 24}{2 \times 1} = 300[/tex]

Let's name the event A:

A - "both marbles are red"

Event's A favorable outcomes:

[tex]m(a) = \frac{7 \times 6}{2 \times 1} = 21[/tex]

[tex]p(a) = \frac{m(a)}{n} = \frac{21}{300} = \frac{7}{100} [/tex]

The average annual cοst in 2014 is $4751.6.

The definitiοn οf an equatiοn in algebra is a mathematical statement that demοnstrates the equality οf twο mathematical expressiοns. Fοr instance, the equatiοn 3x + 5 = 14 cοnsists οf the twο equatiοns 3x + 5 and 14, which are separated by the 'equal' sign.

Here the given equatiοn that represent the annual cοst in dοllars.

=> y = 83.66x+3915

Where x= number οf years

In 2004 , t = 0 years

Sο , In 2014 , t = 2014-2004 = 10 years.

Then average annual cοst in 2014 is,

=> y=83.66(10)+3915

=> y=836.6+3915

=> y = $4751.6.

Hence the average annual cοst in 2014 is $4751.6.

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The line of tangency at the point (–6, 3) is x = -6. So, the correct option is (b).

What is tangent?

In geometry, the tangent is a trigonometric function that relates to the angles and sides of a right triangle. Specifically, the tangent of an angle in a right triangle is the ratio of the length of the side opposite the angle to the length of the adjacent side.

To find the line of tangency to a circle at a given point, we need to first find the slope of the radius that passes through that point, and then take the negative reciprocal of that slope to get the slope of the tangent line.

Given the circle equation: (x + 2)² + (y - 3)²  = 16, we can see that its center is at the point (-2, 3) and its radius is 4.

To find the slope of the radius passing through the point (-6, 3), we can use the point-slope formula:

(y - y1) = m(x - x1)

where m is the slope of the radius, and (x1, y1) is the center of the circle (-2, 3). Plugging in the values, we get:

(y - 3) = m(x + 2)

Substituting the point (-6, 3) into the equation, we get:

(3 - 3) = m((-6) + 2)

0 = -4m

m = 0

So the slope of the radius is 0. To find the slope of the tangent line, we take the negative reciprocal of the slope of the radius:

slope of tangent line = -1/0 = undefined

Since the slope of the tangent line is undefined, it must be a vertical line passing through the point (-6, 3). Thus, the line of tangency at the point (-6, 3) is the vertical line x = -6.

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1 ) Finding the difference 4/9 - ⅖:

We require a common denominator to subtract fractions. The least frequent multiple of 9 and 5 in this example is 45. So we'll recast both fractions with 45 as the denominator:

[tex]\frac{4}{9} = \frac{20}{45} \\\frac{2}{5} = \frac{18}{45}[/tex]

Now we can subtract:

[tex]\frac{20}{45} - \frac{18}{45} = \frac{2}{45}[/tex]

Therefore, the difference between 4/9 and ⅖ is 2/45.

Examine the prime factors of the denominator when the fraction is in its simplest elementary form to determine if it will have a terminating or repeating decimal. The decimal will end if they are made up of 2s and/or 5s.

2) calculating the quotient 2/9 / ⅚:

Fractions are divided by multiplying the first fraction by the reciprocal of the second fraction. So:

2/9 ÷ ⅚ = 2/9 x 6/5

Before multiplying, we can simplify:

2/9 x 6/5 = 12/45

And here's another example:

12/45 = 4/15

As a result, the quotient of 2/9 56 is 4/15.

3) Writing each terminating decimal as an integer quotient:

(a) 0.437 = 437/1000

(b) 8.2 = 82/10 = 41/5

4) Choosing whether each rational number will result in a repeated or terminating decimal:

(a) 8/15

Yes, the fraction is simplified.

The simplified denominator contains factors 2 0r 5.

It is a terminating decimal.

(b) 13/125

Yes, the fraction is simplified.

The simplified denominator contains factors other than 2 or 5.

It is a repeating decimal.

(c) 8/35

Yes, the fraction is simplified.

The simplified denominator contains factors other than 2 or 5.

It is a repeating decimal.

(d) 3/24

Yes, the fraction is simplified.

The simplified denominator contains factors other than 2 or 5.

It is a repeating decimal.

(e) 22/55

Yes, the fraction is simplified.

The simplified denominator contains factors other than 2 or 5.

It is a repeating decimal.

(f) 24/75

No, the fraction is not simplified.

The simplified fraction is = 8/25

The simplified denominator contains factors 2 or 5.

It is a terminating decimal.

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The probability that none of the four unrelated Caucasian people in the U.S. have AB- blood is approximately 0.9606 or 96.06%.

The problem states that the probability that a Caucasian person in the U.S. has AB- blood is 1%. This means that the probability of a Caucasian person not having AB- blood is 1 - 0.01 = 0.99.

The problem asks to find the probability that none of the four unrelated Caucasian people have AB- blood. Since we are assuming that the blood types of the four people are independent, we can multiply the probabilities of each person not having AB- blood to find the probability that none of them have AB- blood.

Using the multiplication rule of probability, we can calculate the probability of no AB- blood as:

P(No AB- in 4) = P(Not AB-) * P(Not AB-) * P(Not AB-) * P(Not AB-)

P(No AB- in 4) = 0.99 * 0.99 * 0.99 * 0.99

P(No AB- in 4) = 0.9606

Therefore, the probability that none of the four unrelated Caucasian people in the U.S. have AB- blood is approximately 0.9606 or 96.06%. This means that there is a high likelihood that none of the four people have AB- blood.

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Answer:

m∠1 = 41°

m∠2 = 139°

Step-by-step explanation:

Set variables:

  1. ∠1 = x

  2. ∠2 = y

Make first equation:

It says "m∠2 is 16 more than 3 times m∠1."

So let's convert that into an equation:

y = 16° + 3x

Now, by looking at the photo, we can tell that its a straight line, which is equal to 180°

Derived from that, we can get m∠1 + m∠2 = 180°, which in other "words" is x + y = 180°.

Great, now we have our 2 equations, and we just have to solve.

Equations:

  1. y = 16° + 3x

  2. x + y = 180°

Let's substitute what we have for y into the second equation:

x + (16° + 3x) = 180°

Solve:

(We can take out parentheses because it's a "+" sign)

Combine like terms:

4x + 16° = 180°

Subtract 16° from both sides

4x = 164°

Isolate x by dividing both sides by 4

x = 41°

Substitute:

Now that we have x = 41°, we can substitute that in for the equation - "y = 16° + 3x"

New Equation:

y = 16° + 3(41°)

Solve:

Multiply 3 and 41°, which is 123°

y = 16° + 123°

Simplify:

y = 139°

Reminder:

m∠1 = x

m∠2 = y

Therefore,

m∠1 = 41°

&

m∠2 = 139°

Hopefully this helps!

(If you want, please mark me brainliest tomorrow)

Answer:

Basically, a straight line is equal to 180 degrees. If angle 2 is 16 more than 3 times angle 1, we get the equation of y = 16 + 3x. Put them together and you get x + 16 + 3x = 180. Then you just solve, and get x = 41. Then you put x in for the other equation and get y = 139.

Answer:

Step-by-step explanation:

The given sequence can be written as:

a_1 = 8

a_2 = 10

a_3 = 12.5

a_4 = 15.625

To find the recursive formula, we need to find the common ratio (r) between consecutive terms:

r = a_2 / a_1 = 10 / 8 = 1.25

r = a_3 / a_2 = 12.5 / 10 = 1.25

r = a_4 / a_3 = 15.625 / 12.5 = 1.25

Since the common ratio is constant, we can use the formula for a geometric sequence to find the recursive formula:

a_n = r * a_{n-1}

Substituting r = 1.25 and a_1 = 8, we get:

a_n = 1.25 * a_{n-1}

Therefore, the recursive formula for the given sequence is:

a_n = 1.25 * a_{n-1}, with a_1 = 8.

Value of m and b of the straight line in the graph is 0 and 2 respectively.

In mathematics, slope refers to the steepness or inclination of a line, and is defined as the ratio of the change in the y-coordinate to the change in the x-coordinate between any two points on the line. It is often represented by the letter m. The slope of a line can be positive, negative, zero, or undefined.

Let us assume that the equation of line be y=mx+b.

where m is the slope

and b is the intercept

The line in the graph is parallel to x axis

so, slope is 0

m=0

the line passes through(0,2)

Putting the value in the equation, we get

b=2

Hence, the equation of line be y=2

Therefore, value of m=0 and b=2.

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The complete question is:

The graph is showing the equation of straight line y=mx+b, find the value of m and b.

Image is attached below:

Answer: You're answer is 3

or exactly 3.464.

[tex]\sqrt{100}[/tex]Answer:

10

Step-by-step explanation:

You have to reverse the square root [tex]3\sqrt{12}[/tex]

what perfect square makes 3? 9.

what is [tex]\sqrt{9} \sqrt{12}[/tex]

[tex]\sqrt{108}[/tex]

what is the perfect square between 108? 100 and 121.

what is the different between them?

108-100=8

121-108=13

obviously, 8 is closer than 13, so now find the square root of the closer perfect square.

[tex]\sqrt{100}[/tex]=10

Answer:

43.20 = 18x + 25.20

x = $1.00

Step-by-step explanation:

43.20 - 18x = 25.20

or

43.20 = 25.20 + 18x

Solve for x:

18x = 43.20 - 25.20

18x = 18

x = 18/18 = $1.00

Answer:

−x2−6x+8

Step-by-step explanation:

1,Rearrange terms

2.Distribute

3.Add the numbers

4.combine like terms

hope this helps i lfet some steps for you!!!<3333

Answer: X = 1, Y = 2

Step-by-step explanation:

X - Y = -1

X = Y - 1

2(Y - 1) - Y = 0

2Y - 2 - Y = 0

Y - 2 = 0

Y = 2

X - (2) = -1

X - 2 = -1

X = 2 - 1

X = 1

The height of the box must be at least 2.9111 feet.

The volume of the cylinder is given by the formula V = πr²h, where r is the radius of the cylinder and h is its height.

Since the width of the cylinder is 3 feet, the radius is 1.5 feet.

The volume of the oil is 15 gallons, which is equivalent to 0.2 cubic feet. We know that this volume of oil takes up 75% of the space between the cylinder and the box, so the total space between the cylinder and the box is 0.2 / 0.75 = 0.2667 cubic feet.

Since the cylinder fits perfectly inside the box, the volume of the box is equal to the volume of the cylinder plus the space between the cylinder and the box. Therefore, we have:

Volume of box = Volume of cylinder + Volume of oil

Volume of box  = πr²h + 0.2667

Substituting the values we have:

Volume of box = π(1.5)²h + 0.2667

Volume of box = 7.0686h + 0.2667

To find the height of the box, we need to isolate h. We know that the volume of the box must be greater than or equal to the volume of the cylinder, so we can set up the inequality:

Volume of box  ≥ Volume of cylinder

πr²h + 0.2667 ≥ πr²(3)

h + 0.0889 ≥ 3

h ≥ 2.9111

Therefore, the height of the box must be at least 2.9111 feet.

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The stem and leaves display the image and distribute information continuously. These charts are similar to histograms, but instead of using lines, they show numbers. It is a useful tool, especially when searching for statistical information.

The stem and leaf diagram, also known as the stem and leaf diagram, is a method of organizing data in a way that makes it easy to observe the frequency of importance of different species. A chart that shows numerical data arranged in a series. Each data value or number is divided into stems and leaves.

Rows and sheets are represented in the form of a special table in which each first digit or digit of the document value is divided by the stem and the last digit of the document in sheets. The letter is used to represent the stem and leaf, called stem and leaf values.

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