Help pls..
How many solutions does the system of linear equations represented in the graph have?

Coordinate plane with one line that passes through the points 0 comma negative 2 and 2 comma negative 1.

One solution at (−2, 0)
One solution at (0, −2)
Infinitely many solutions
No solution

Answer:

25%

Step-by-step explanation:

The total number of 7th grade students = 9 + 11 + 11 + 13 = 44

Out of the 44 students 11 play bass

Probability that a seventh grader chosen at random will play the base is:

11/44 = 1/4 = 0.25

As a percentage, this would be 0.25 x 100 = 25%

If Kayla can pay off up to $175 monthly for the purchase of a new television for $487.89, the interest she will pay at 23.5% compounded monthly is D. $18.87.

The compound interest payable on the credit card for the purchase of a new television can be computed using an online finance calculator as follows:

N (# of periods) = 3 months

I/Y (Interest per year) = 23.5%

PV (Present Value) = $487.89

PMT (Periodic Payment) = $-175

Results:

FV = $18.23

Sum of all periodic payments = $525.00

Total Interest = $18.87

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1) If Amy deposits $2,300 in an account that pays 8.5% interest, after 4 years, the future value will be $3,187.48.

2) If Andres deposits $10,000 in an account that pays 8% interest, after 4 years, the future value will be A. $13,604.89.

3) If Kara deposits $500 in an account that pays 5% interest, after 2 years, the future value will be C. $551.25.

The future values represent the present investment compounded at an interest rate.

The future values can be determined using an online finance calculator as follows:

1) N (# of periods) = 4 years

I/Y (Interest per year) = =8.5%

PV (Present Value) = $2,300

PMT (Periodic Payment) = $0

Results:

Future Value (FV) = $3,187.48

Total Interest = $887.48

2) N (# of periods) = 4 years

I/Y (Interest per year) = =8%

PV (Present Value) = $10,000

PMT (Periodic Payment) = $0

Results:

Future Value (FV) = $13,604.89

Total Interest = $3,604.89

3) N (# of periods) = 2 years

I/Y (Interest per year) = 5%

PV (Present Value) = $500

PMT (Periodic Payment) = $0

Results:

Future Value (FV) = $551.25

Total Interest = $51.25

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To move triangle KLM so that point K lies on the Y-axis, you need to apply a translation that shifts the entire triangle horizontally. By translating triangle KLM using the vector (-4, 0), point K now lies on the Y-axis.

To move the triangle so that point K lies on the Y axis, we need to perform a translation. First, we need to determine how far point K is from the Y axis. We can do this by finding the x-coordinate of point K, which is 4. This means that point K is 4 units away from the Y axis.

Next, we need to determine the direction of the translation. Since we want to move point K onto the Y axis, we need to move the triangle in the negative x direction. Therefore, the translation that will move the triangle so that point K lies on the Y axis is a horizontal translation of -4 units. We can express this translation as follows:

T(-4, 0)

This means that we need to move each point of the triangle 4 units to the left (negative x direction) to achieve the desired position of point K on the Y axis.

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The coordinates of P and Q are P(5, 5) and Q(7, 7) respectively.

Let the centres of the circles be:

P (a, r)  and

Q (b, s)

where r and s are the radii of the circles.

Since the circles are tangent to the x-axis, we know that r = a and s = b.

Also, since the circles are tangent to each other, we have

a + b = PQ = 26

Let the point of contact of circle P with the x-axis be (p, 0)

Let the point of contact of circle Q with the x-axis be (q, 0).

Then, we know that

p + q = AB = 24

Using Pythagorean theorem, we can write:

(r² - p²) + (r² - (24 - p)²) = (s²- q²) + (s² - (24 - q)²)

Expanding and simplifying, we get:

2r² - 24r + 576 = 2s² - 24s + 576

Substituting r = a and s = b, and using the fact that a + b = 26, we get:

2a² - 24a + 576 = 2b² - 24b + 576

Simplifying further, we get:

a² - 12a + 288 = b² - 12b + 288

(a - b)(a + b - 12) = 0

Since a + b = 26, we have a - b = 0 or a + b - 12 = 0. The first case gives us a = b, which is not possible since the circles are tangent to each other. Therefore, we have a + b = 12.

Using substitution method to solve  the simultaneous equations:

a + b = 12

a + b = 26

We get a = 7 and b = 5.

Therefore, the centres of the circles P and Q are (7, 7) and (5, 5) respectively.

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The minimum surface area of fabric needed for the sleeve is approximately 628.32 cm².

Based on the given model arm, a right circular cylinder would best represent the model for the sleeve.

To calculate the minimum surface area of fabric needed for the sleeve, we need to find the lateral surface area of the right circular cylinder.

The lateral surface area of a right circular cylinder is given by the formula:

Lateral surface area = 2πrh

where r is the radius of the cylinder, h is the height of the cylinder.

In this case, the height of the cylinder needs to be 20 cm (to cover the distance from the shoulder to the elbow), and the radius can vary depending on the desired fit. Let's assume a radius of 5 cm for the purposes of this calculation.

Plugging in the values, we get:

Lateral surface area = 2π(5 cm)(20 cm)

= 628.32 cm²

Therefore, the minimum surface area of fabric needed for the sleeve is approximately 628.32 cm².

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If Sam needs 2/5 pound turkey to make one sandwich, then to make 7 sandwiches, he will need:

(2/5) x 7 = (2 x 7)/5 = 14/5 = 2.8 pounds of turkey

Therefore, Sam needs 2.8 pounds of turkey to make 7 sandwiches.

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The training program with the least rate of change is Rachel's, with an increase of 3 minutes per day.

Rachel:
Starting minutes: 30
Increase in rate: 3 minutes per day
Equation: f(x) = 3x + 30

Nicole:
Starting minutes: 30 (since f(0) = 5(0) + 30 = 30)
Increase in rate: 5 minutes per day
Equation: f(x) = 5x + 30

To find the training program with the least rate of change, we need to find the derivative of each equation and set it equal to zero:

f'(x) = 3 for Rachel's equation
f'(x) = 5 for Nicole's equation

Since 3 is less than 5, Rachel's training program has the least rate of change. Therefore, the rate of change in minutes per day for Rachel's training program that has the least rate of change is 3 minutes per day.

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The area of sector is 14π/3 square inches for a circle having a radius of 7 inches and measures an angle of 4π/15 radians.

Radius of circle =  7 inches

Angle of circle =  4π/15 radians

The area of a sector of a circle can be calculated by using the formula:

A = (θ/2) × [tex]r^2[/tex]

A =  The area of the sector

θ = central angle in radians

r = radius of the circle.

Substituting the given values in the formula:

Area = (θ/2) × [tex]r^2[/tex]

Area = (4π/15 × 1/2) × [tex]7^2[/tex]

Area= (2π/15) × 49

Area = 14π/3

Therefore, we can conclude that the area of the sector is 14π/3 square inches.

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Answer:

50, positive

Step-by-step explanation:

(-5) * (-10) = 50

When a negative multiplies by another negative, the answer is positive

So, the answer is 50 and the sign is positive

The probability of a bulb lasting for at most 624 hours is 0.9861, rounded to four decimal places.

The standard deviation of the lifetime is a measure of how spread out the lifetimes are. In other words, it tells us how much the lifetimes of bulbs vary from the mean. In this case, the standard deviation of the lifetime is 20 hours.

Now, let's get to the question at hand. We want to find the probability of a bulb lasting for at most 624 hours. To do this, we need to use the properties of the normal distribution.

First, we need to calculate the z-score, which tells us how many standard deviations a value is from the mean. We can use the formula z = (x - mu) / sigma, where x is the value we are interested in, mu is the mean, and sigma is the standard deviation. In this case, x = 624, mu = 580, and sigma = 20.

Plugging these values into the formula, we get z = (624 - 580) / 20 = 2.2.

Next, we need to find the probability of a bulb lasting for at most 624 hours, which is the same as finding the area under the normal curve to the left of z = 2.2. We can use a standard normal distribution table or a calculator to find this probability.

Using a calculator, we can use the normal cdf function with the values -9999 (a very large negative number) and 2.2 to find the probability. This gives us a probability of 0.9861.

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a. The initial height of the bouncing ball is 15 feet.

b. The percent rate of change is 85%.

c. The height of the bouncing ball after 5 seconds is approximately 6.79 feet (rounded to the nearest hundredth).

In mathematics, a function is a rule that assigns each element in a set (the domain) to a unique element in another set (the range). The domain and range can be any sets, but they are typically sets of real numbers.

The function f(x) = 15 (0.85)ˣ models the height, in feet, of a bouncing ball after x seconds.

a. The initial height of the bouncing ball is given by f(0). Plugging in x = 0, we get:

f(0) = 15*1

f(0) = 15(1)

f(0) = 15

Therefore, the initial height of the bouncing ball is 15 feet.

b. The percent rate of change is given by the coefficient of the base, which is 0.85 in this case. To convert this decimal to a percentage, we can multiply by 100:

0.85 × 100 = 85

Therefore, the percent rate of change is 85%.

c. The height of the bouncing ball after 5 seconds is given by f(5). Plugging in x = 5, we get:

f(5) = 15

f(5) ≈ 6.79

Therefore, the height of the bouncing ball after 5 seconds is approximately 6.79 feet (rounded to the nearest hundredth).

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The expression 0.85(1.4s) represents the final selling price of the jacket after two price changes: an initial 15% decrease in price, followed by another 15% decrease in price.

The expression 0.85(1.4s) represents the final selling price of the jacket after two price changes. We can break it down into its constituent parts to understand what happened to the price.

Factor 1.4s represents the original selling price of the jacket. This means that the store owner started with a price of 1.4s dollars.

The factor 0.85 represents the first price change. When the store owner lowered the price by 15%, the new price became 0.85 times the original price.

The second factor of 0.85 represents the second price change. After the first price change, the new price was 0.85(1.4s) dollars. When the store owner lowered the price again by 15%, the final selling price became 0.85 times the price after the first price change.

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The interest accrued after one month at a rate of 15.5% on a principal amount of $1,000 is $12.92.

To use the formula I=Prt to calculate the interest accrued after one month at a rate of 15.5%, we need to know the principal amount (P) and the time period (t) in years.

Assuming that the principal amount is $1,000, and the time period is one month, which is equivalent to 1/12 of a year, we can calculate the interest as follows:

[tex]I = Prt[/tex]

[tex]I[/tex] [tex]= 1000 x 0.155 x (1/12)[/tex]

[tex]I = $12.92[/tex]

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Answer:

let x be the no.

So, 5 less than the square of a number in an algebraic expression is:

x^2 - 5

A store has 25 VCRs in stock, but 2 of these are defective he answer is the probability that the second person to buy a VCR gets a defective one and the first customer's VCR was not defective is .077.

The probability that the first customer's VCR is not defective is 23/25, as there are 23 working VCRs out of the total 25.

Since one VCR has already been sold, there are 24 VCRs left and 1 defective VCR. Thus, the probability that the second customer gets a defective VCR is 1/24.

To find the probability that both events occur, we multiply the individual probabilities:

P = (23/25) x (1/24)

P = 0.077 or 0.0778 when rounded to the nearest thousandth.

Therefore, A store has 25 VCRs in stock, but 2 of these are defective he answer is the probability that the second person to buy a VCR gets a defective one and the first customer's VCR was not defective is .077.

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In this scenario, the dependent variable is "how many jumps I can do," while the independent variable is "how long I am jumping (2 minutes)."

The relationship between these variables can be described as follows: The number of jumps completed depends on the duration of time spent jumping, with a specific focus on a 2-minute interval.

When we say the dependent variable is "how many jumps I can do," it means that the number of jumps completed is determined by or depends on the independent variable, which is the duration of time spent jumping.

This suggests that as the duration of time increases or decreases, it will likely have an impact on the number of jumps performed.

In this particular case, you have specified a 2-minute interval as the focus. It suggests that you are examining the relationship between the number of jumps completed and the specific duration of 2 minutes.

This implies that you are interested in understanding how the number of jumps varies within this fixed time frame.

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The volume of the given shape is 125 unit³ if the length is 5 unit, breadth is 5 unit, and height is 5 unit.

A cube is a three-dimensional geometric shape that has six identical square faces, where each face meets at a right angle with the adjacent faces. It is a regular polyhedron, meaning that all of its faces are congruent (identical) and its edges are of equal length.

Volume of cube = length × breadth × height

length = 5 unit

breadth = 5 unit

height = 5 unit

Volume = 5 × 5 × 5

= 125 unit³

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Answer:

(2,-4)

Step-by-step explanation:

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

2x+3y=−8,3x+y=2

To make 2x and 3x equal, multiply all terms on each side of the first equation by 3 and all terms on each side of the second by 2. Then simplify

6x+9y=−24,6x+2y=4

Add 6x to −6x. Terms 6x and −6x cancel out, leaving an equation with only one variable that can be solved, add 9y to −2y, add −24 to −4, and divide both sides by 7.

y=−4

Substitute −4 for y in 3x+y=2. Because the resulting equation contains only one variable, you can solve for x directly. Add 4 to both sides of the equation and divide both sides by 3.

x=2

Using the straight-line method, we can find the depreciation expense per year by dividing the depreciable value (cost - residual value) by the estimated life:

Depreciable Value = Cost - Residual Value

Depreciable Value = $40000 - $10000

Depreciable Value = $30000

Annual Depreciation Expense = Depreciable Value / Estimated Life

Annual Depreciation Expense = $30000 / 6

Annual Depreciation Expense = $5000

To create a depreciation schedule, we can subtract the annual depreciation expense from the cost each year until we reach the residual value:

| Year | Cost |   Depreciation | Accumulated Depreciation | Book Value |

|------|---------------|-----------------  |----------------------------------------|------------|

| 1     | $40000  | $5000                | $5000                             | $35000     |

| 2    | $35000  | $5000                 | $10000                           | $30000     |

| 3    | $30000  | $5000                  | $15000                           | $25000     |

| 4    | $25000  | $5000                  | $20000                          | $20000     |

| 5    | $20000  | $5000                  | $25000                         | $15000     |

| 6    | $15000  | $5000                    | $30000                        | $10000     |

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BD = CA is proved using the Pythagorean theorem.

It is a quadrilateral that has one pair of parallel sides and a height.

The area is calculated as 1/2 x the sum of the parallel sides x height.

Examples:

Area of a trapezium that has the parallel sides as 3 cm and 4 cm and a heght o 5 cm.

Area = 1/2 x (3 + 4) x 5

Area = 1/2 x 7 x 5

Area = 35/2 = 17.5 cm^2

We have,

From the trapezium ABCD,

BA = CD ______(A)

Now,

We can have two triangles:

ΔABD and ΔACD

Using the Pythagorean theorem.

BD² = AB² + AD² _____(1)

And,

CA² = CD² + AD² ______(2)

From (1), (2), and (A).

BD² = BA² + AD²

CA² = BA² + AD²

This means,

BD² = CA²

BD = CA

Proved

Thus,

BD = CA can be Proven as above.

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Answer:

Step-by-step explanation:

Answer:

C. The distributive property

By using factoring and the zero product property the two numbers that multiply to make -14 and add to make -3 are -7 and 4.

The zero product property is a fundamental property of algebra that states that if the product of two or more factors is zero, then at least one of the factors must be zero. In other words, if a × b = 0, then either a = 0 or b = 0 or both a and b are zero. This property is often used to solve equations and factor polynomials. For example, if we have the equation (x - 3)(x + 5) = 0, we know that the only way the product can be zero is if one of the factors is zero, so we set each factor equal to zero and solve for x:

(x - 3)(x + 5) = 0

x - 3 = 0 or x + 5 = 0

x = 3 or x = -5

Thus, the solutions to the equation are x = 3 and x = -5.

We can solve this problem by using factoring and the zero product property.

First, we need to find two numbers that multiply to make -14. The factors of -14 are (-1, 14) and (1, -14), so the two numbers could be -1 and 14, or 1 and -14.

Next, we need to find which pair of numbers adds up to -3. The only pair of numbers that works is -7 and 4 because (-7) + 4 = -3.

Therefore, the two numbers that multiply to make -14 and add to make -3 are -7 and 4.

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An exponential function in terms of x is [tex]P(x) = 140,000(1.05)^x[/tex]

The population would be 291049.95 after 15 years.

In Mathematics, a population that increases at a specific period of time represent an exponential growth. This ultimately implies that, a mathematical model for any population that increases by r percent per unit of time is an exponential function of this form:

[tex]P(x) = I(1 + r)^x[/tex]

Where:

By substituting given parameters, we have the following:

[tex]P(x) = 140,000(1 + 0.05)^x\\\\P(x) = 140,000(1.05)^x[/tex]

After 15 years, we have:

[tex]P(15) = 140,000(1.05)^{15}[/tex]

P(15) = 291049.95 units.

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Applying the inscribed angle theorem, the measure of the size of angle ∅ = 85 degrees.

If an inscribed angle in a circle is subtended by an arc, the inscribed angle theorem states that the measure of the intercepted arc would be twice the measure of the inscribed angle.

Therefore, we have:

measure of arc DF = 2(31) = 62 degrees [inscribed angle theorem]

measure of arc BD = 2(54) = 108 degrees.[inscribed angle theorem]

∅ = 1/2(measure of arc BDF) [inscribed angle theorem]

∅ = 1/2(m(DF) + m(BD))

Substitute:

∅ = 1/2(62 + 108)

∅ = 1/2(170)

∅ = 85 degrees.

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The maximum height of the arrow is 105 feet. To find the maximum height of the arrow, we need to determine the vertex of the quadratic function h = -16[tex]t^{2}[/tex] + 80t + 25.

The vertex is the highest point on the graph of the function, which represents the maximum height of the arrow.

To find the t-value at the vertex, we use the formula t = -b/2a, where a = -16 and b = 80. Plugging these values into the formula gives us t = -80/(2(-16)) = 2.5 seconds.

To find the maximum height, we plug t = 2.5 into the equation to get h = -16[tex](2.5)^{2}[/tex] + 80(2.5) + 25 = 105 feet. Therefore, the maximum height of the arrow is 105 feet.

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a) To find y for the given x and Δx values, first calculate x + Δx:
x + Δx = 3 + 0.03 = 3.03

Now, use the function y = f(x) = 9x to find the y values:
y = 9(3) = 27 (for x = 3)
y = 9(3.03) = 27.27 (for x = 3.03)

b) To find dy, we first need to find the derivative of the function (f'(x)). The function is y = f(x) = 9x, and its derivative (using differentiation) is:
f'(x) = 9

c) To find dy for the given x and Δx values, we can now use the formula dy = f'(x)dx:
dy = f'(x)dx = 9(0.03) = 0.27

So, for the given x and Δx values, a) y is 27 and 27.27, b) dy is equal to 9, and c) dy for the given x and Δx values is 0.27.

Answer:

Step-by-step explanation:

Given cos(θ) = 5/9, you want the six trig functions of θ.

The relevant identities are ...

The sine of θ is ...

  sin(θ) = √(1 -(5/9)²) = √(81 -25)/9 = (√56)/9

  sin(θ) = (2/9)√14

Then the cosecant is ...

  csc(θ) = 1/sin(θ) = (9/2)/√14

  csc(θ) = (9√14)/28

The tangent of θ is ...

  tan(θ) = sin(θ)/cos(θ) = ((2/9)√14)/(5/9)

  tan(θ) = (2/5)√14

Then the cotangent is ...

  cot(θ) = 1/tan(θ) = (5/2)/√14

  cot(θ) = (5√14)/28

The secant of θ is ...

  sec(θ) = 1/cos(θ) = 1/(5/9)

  sec(θ) = 9/5

The cosine is given in the problem statement.

Answer:

60

Step-by-step explanation:

((sum of frequency of even numbers)/(total number of tries))(150)