Helpp!! Solve the system by graphing.

Answer:

Acute scalene triangle

On solving the provided question, we can say that - here in equation 10x + =4 = 2

An equation is a formula in mathematics that joins two statements with the equal symbol = to represent equality. The definition of an equation in algebra is a mathematical statement proving the equality of two mathematical expressions. In the equation 3x + 5 = 14, for instance, the terms 3x + 5 and 14 are separated by an equal sign. The link between two phrases on either side of a letter is expressed mathematically. There is often only one variable, which is also the symbol. instance: 2x - 4 Equals 2.

here,

the equation we have is  = 10x + =4 = 2

10x = -2

x = -1/5

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The least common multiple of 598 and 45 is 26, 910

To find the least common multiple of 598 and 45, you can use the prime factorization method. This involves finding the prime factors of both 598 and 45 and then multiplying these prime factors when they are in their highest power.

This gives:

598 prime factorization :

2 x 13 x 23 = 598

45 prime factorization :

3 x 3 x 5 = 45

The least common multiple is;

= 2 x 13 x 23 x 3 x 3 x 5

= 26, 910

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Answer:

[tex]V = 864cm^3[/tex]

Step-by-step explanation:

Given

[tex]r = 6[/tex]

[tex]\pi = 3[/tex]

Required

The volume of the sphere

This is calculated as:

[tex]V = \frac{4}{3} \pi r^3[/tex]

So, we have:

[tex]V = \frac{4}{3} *3 *6^3[/tex]

[tex]V = \frac{4}{3} *3 *216[/tex]

This gives:

[tex]V = 4 *216[/tex]

[tex]V = 864[/tex]

Answer:

[tex] \sf \: b) \: 45[/tex]

Step-by-step explanation:

The values given are,

→ u = 7

→ d = 10

→ e = 3.2

Now the expression is,

→ 15(d - u)

Evaluating the expression,

→ 15(d - u)

→ 15(10 - 7)

→ 15 × 3

→ 45

Hence, option (b) is correct.

Answer:45

Step-by-step explanation:

15(10-7)

15(3)

multiply and get 45

Answer:

4/663

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome

Since we are to draw from a pack of card, the total outcome will be 52

Since there are 4 hearts;

Pr(selecting heart) = 4/52 = 1/13

If a club is then selected without replacement, the total number of card remaining will be 51;

Pr(selecting a heart) = 4/51

probability of drawing a heart and a club in that order = 4/52 * 4/51

probability of drawing a heart and a club in that order = 16/2652

probability of drawing a heart and a club in that order = 4/663

As there are certain steps are there which describes, the definition of f x^m/n re, by  taking the mth root of a number is the same as taking the reciprocal of the exponent, and raising that reciprocality to the power of n is equivalent to raising the original number to the power of n/m.

Statements are sentences that expressage a fact, idea, or legal opinion. Statements do not ask questions, make requests or give speech act. They are also not utterances.

As there is a second step that follows,

2. This can also be written as x^(mn/m^2) = x^(n/m) which is the same as x to the power of (n/m)

3. This can also be written as x^(mn/m^2) = x^(n/m) which is the same as x to the power of (n/m)

4. The expression (x^(m/n))^(n/m) is the definition of x^mn, which is the mth root of x raised to the power of n. It makes sense because taking the mth root of a number is the same as taking the reciprocal of the exponent, and raising that reciprocal to the power of n is equivalent to raising the original number to the power of n/m.

Therefore, As a result, the complete definition of  x^m/n, are as follows in the above statement.

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The complete statement was.

The expression (x^(m/n))^(n/m) is the definition of x^mn, which is the mth root of x raised to the power of n. It makes sense because taking the mth root of a number is the same as taking the reciprocal of the exponent, and raising that reciprocal to the power of n is equivalent to raising the original number to the power of n/m.

Therefore , the solution of the given problem of equation comes out to be a.60 , b.20 and c.21.

An equation in mathematics is a representation of two equal variables, one on each side of a "equals" sign. To tackle common issues, equations can be used. We commonly seek pre algebra help to overcome obstacles in real life. Math fundamentals are covered in pre-algebra lessons.

Here,

Given : 9(x - y) = 30,

or (x-y) =30/9

To find :  

a) 18(x - y) = ?

=> 2(9(x - y))

=> 2(30)

=> 60

b)6x - 6y = ?

=> 6(x-y) = 6(30/9)

=> 2*30/3

=> 20

c) 9(x-y)-9

=> 30 -9

=>21

Therefore , the solution of the given problem of  equation comes out to be a.60 , b.20 and c.21.

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Answer: x=2.375937.... sorry I give you the wrong one but here the steps O here x=2.96423 will it can be any one of the two answer I give you now.

Step-by-step explanation: Hope this help :D

Answer:

2.4?

Step-by-step explanation:

Answer:

She spent 37.05

Step-by-step explanation:

multiply both values

Answer:

C

Step-by-step explanation:

Answer: 7.6

Use a caculator for next time so you don't have to waste your points.

Answer:

1) N = 2. 2) -7/3

Step-by-step explanation:

1)

6 = 3n

6/3 = n

2 = n

n = 2

2)

-3 = 3t + 4

3t + 4 = -3

3t = -3 - 4

3t = -7

T = -7/3

here is my answer mate,

1)18

2)4

Answer:332

Step-by-step explanation:

Let x be the number

Using algebra

(x÷4)+75=158

(x÷4)=158-75

(x÷4)=83

x=83×4

x=332

Check

(332÷4)+75=158

Answer:

The probability that X is less than 5 cannot be determined.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

The distribution is right-skewed, which means that the central limit theorem can only be applied for a sample size of at least 30. Since the sample size is 9 < 30, the CLT cannot be applied, and thus the probability that X is less than 5 cannot be determined.

Answer:

x < [tex]\frac{11}{2}[/tex]

Step-by-step explanation:

=> 10x - 5 < 8x + 6

Subtract 8x from the left and right side of the inequality sign:

=> 2x - 5 < 6

Now, add 5 on both sides of the inequality:

2x < 11

now divide 2 on both sides:

x < [tex]\frac{11}{2}[/tex]

Hope this helps!

The additional expense brought on by reducing the quantity is known as the cost. An additional expense "at the margin" is another name for this. The extra income that results from raising the supply is known as the marginal revenue.

Profit is defined as the difference of revenue and cost (determined by deducting cost from revenue. when revenue exceeds operational expenses, the difference between them is called the operating profit.

The additional money "at the margin" is another name for this.The money left over after a corporation pays its bills and expenses is known as its profit. Costs are the out-of-pocket expenditures comes to making, producing, and marketing the company's goods and services.

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Answer: #4 x >l 11

Hope this helps

Step-by-step explanation:

Answer:

30 students

Step-by-step explanation:

First, we need to find exactly how many students went to school by car and how many went on the bus.

To do this, we simply multiply the fraction of students that used each transportation method by the total number of students.

[tex]\# \textrm{ of students by car} = \dfrac{3}{8} \times 240 = \dfrac{3 \times 240}{8} = \dfrac{720}{8} = 90 \textrm{ students}[/tex]

So, 90 students went to school by car.

[tex]\# \textrm{ of students on bus} = \dfrac{6}{12} \times 240 = \dfrac{1}{2} \times 240 = \dfrac{240}{2} = 120 \textrm{ students}[/tex]

So, 120 students went to school on the bus.

The number of students that walked to school is the same as the number of students who didn't go in a car or on the bus, so to find the number of students that walked to school, we can subtract the number of students that went by car and on the bus from the total number of students.

[tex]\# \textrm{ of students that walked} = 240 - 90 - 120 = 30 \textrm{ students}[/tex]

To find the cost of each pound of almonds, we need to find the difference in the cost of the almonds between the two purchases and divide it by the difference in the number of pounds of almonds. In this case, the difference in the cost of the almonds is $31 - $12 = $19 and the difference in the number of pounds of almonds is 3 - 5 = -2 pounds. Dividing the difference in the cost by the difference in the number of pounds gives us $19/-2 = $-9.50 per pound. This means that the cost of each pound of almonds is $-9.50.

To find the cost of each pound of jelly beans, we can use a similar process. In this case, the difference in the cost of the jelly beans is $31 - $12 = $19 and the difference in the number of pounds of jelly beans is 8 - 2 = 6 pounds. Dividing the difference in the cost by the difference in the number of pounds gives us $19/6 = $3.17 per pound. This means that the cost of each pound of jelly beans is $3.17.

Answer:

m=5

c=-7

Step-by-step explanation:

m is slope

c is the intercept on the y axis

Mark me brainliest pls

Answer:

<CED = 58°

Step-by-step explanation:

Let <CED = x

We can obtain the value of x as illustrated below:

<CED + 122 = 180 (angles on a straight line)

x + 122 = 180

Collect like terms

x = 180 – 122

x = 58°

<CED = x

x = 58°

Thus,

<CED = 58°

The point of intersection is (–3.5, 0.5) when the system of equations below is graphed on the coordinate plane.

The equation is defined as a mathematical statement that has a minimum of two terms containing variables or numbers that are equal.

The system of equations below

-x + y = 4,

6x + y = -3

As per the given question, the required graph has been attached below.

The point of intersection when the system of equations is graphed on the coordinate plane is (–3.5, 0.5).

This is the point where the two lines cross each other.

Hence, the correct answer would be an option (D).

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The question seems to be incomplete the correct question would be:

What is the point of intersection when the system of equations below is graphed on the coordinate plane? -x+y=4, 6x+y= -3

A. (1, –3)

B. (–1, 3)

C. (1, 3)

D. (–3.5, 0.5)

Answer:

arc AB

Step-by-step explanation:

uhhhh 48 is greater than 42

Answer:

D

Step-by-step explanation:

Edge

As a result, you are turning the entire trapezium figure 90 degrees clockwise in order to change the trapezoid LMNQ into L′M′NQ′.

In American and Canadian English, a trapezoid is a quadrilateral with at least one set of parallel sides. In British and other versions of English, the word is a trapezium. A trapezoid is always a convex quadrilateral in Euclidean geometry. The parallel sides of the trapezoid are referred to as its bases.

Given: When (-7,-2) to L, L becomes L' (-2,7)

You will often obtain a rotation of 90 degrees clockwise or 270 degrees counterclockwise around the origin (0,0), as well as a reflection across the x-axis and across the line of symmetry of the image, if you have (x,y) and it becomes (y,-x).

The entire graphic is therefore rotated 90 degrees in a clockwise orientation.

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Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 1.9842

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.