how many days will it take to finish a 20 pound bag of rice when you use 0.4 pounds each day

Part (a)

The middle values were nitially 266 and 269, but now they are 255 and 266. Thus, the median changes from 267.5 to 260.5, meaning it decreases by 7.

Part (b)

The sum before the change is 2264, but after, it is 2120. This means the sum decreased by 144, and thus the mean decreased by 16.

To get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

Given that we have to get 1 by dividing 60 by something and multiply 60 by something to get 25.

We are required to find those numbers.

Take first result:

Suppose the number which divides 60 be x.

So,

60/x=1

x=60

Number will be 60.

Take second result:

Suppose the number which multiplied with 60 to get 25 be y.

So,

60*y=25

y=25/60

y=0.41

Number will be 0.41.

Hence to get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

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Answer:

120

Step-by-step explanation:

the difference = 24×41-864=120

Answer:

  5.2 g/cm³

Step-by-step explanation:

Given a sculpture consisting of 2 cm³ at 4 g/cm³, 7 cm³ at 5 g/cm³, and 5 cm³ at 6 g/cm³, you want its average density.

The total mass of the sculpture is the sum of the masses of the components. Each of those is the product of its volume and density.

  red sand: (2 cm³)(4 g/cm³) = 8 g

  yellow sand: (7 cm³)(5 g/cm³) = 35 g

  brown sand: (5 cm³)(6 g/cm³) = 30 g

The total mass of the sculpture is ...

  total mass = 8 g + 35 g + 30 g = 73 g

The total volume of the sculpture is the sum of the volumes of its parts:

  total volume = 2 cm³ +7 cm³ +5 cm³ = 14 cm³

The density is the ratio of mass to volume:

  ρ = (total mass)/(total volume) = (73 g)/(14 cm³) = 73/14 g/cm³

  = 5 3/14 g/cm³ ≈ 5.2 g/cm³

The average density of the sculpture is about 5.2 g/cm³.

The possible values of x will belong to the set A = [9, ∞).

We have the following inequality -

1 - 2x/3 ≤ -3

We have to determine all values of x.

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

According to the question, we have the following inequality -

1 - 2x/3 ≤ -3

Subtract 1 from both sides -

-2x/3 ≤ -4

Multiply by -1 on both sides -

2x/3 ≥ 4

Multiply by 3/2 on both sides -

x ≥ 9

Hence, the possible values of x will belong to the set A = [9, ∞).

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Answer:

GA =34

Y = 61

Step-by-step explanation:

GA= GENERAL ADMISSION =$10

Y= YOUTH =$8

GA+Y= 95

GA=95-Y

10GA+8Y=828

10(95-Y)+8Y=828

950-10Y+8Y=828

-2Y= 122 MULTIPLY BY (-1)

2Y= 122

Y= 61

GA= 34

There were 61 youth tickets sold and 34 general admission tickets

Answer:

450g

450,000mg

450,000,000,000ng

Explaination:

Kg to g (x1,000)

Kg to mg (x1,000,000)

kg to ng (x1,000,000,000,000)

Answer:

-7

Step-by-step explanation:

The number located at point D is 7, And the opposite of 7 is -7.

Answer:

$1

Step-by-step explanation:

If you have x dimes, you have 8x nickels.

So, this means x + 8x = 18.

This means you have 2 dimes and 16 nickels, which have a combined value of 2(0.10)+16(0.05)=$1.

Answer:

[tex] \sf \large \: 4m+52[/tex]

Step-by-step explanation:

4(m−2+15)

=(4)(m+−2+15)

=(4)(m)+(4)(−2)+(4)(15)

=4m−8+60

=4m+52

Answer:

4m+52

Step-by-step explanation:

Answer:

[tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

Step-by-step explanation:

Here, m is the slope and b is the y-intercept.

( -1, 3) ;  x₁ = -1  & y₁ = 3

(7, -8) ; x₂ = 7 & y₂ = -8

Slope can be obtained by the formula:

    [tex]\sf \boxed{\bf Slope = \dfrac{y_2-y_1}{x_2-x_1}}[/tex]

                [tex]\sf =\dfrac{-8-3}{7-[-1]}\\\\\\=\dfrac{-8-3}{7+1}\\\\\\=\dfrac{-11}{8}[/tex]

Now, we can find the y-intercept,

[tex]\sf y = \dfrac{-11}{8}x + b\\\\Substitute \ any \ one \ of \ the \ point \ in \ the \ above \ equation.\\\\\text{Here, we are substituting (-1 ,3)}\\\\3 = \dfrac{-11}{8}*(-1) + b\\\\3 = \dfrac{11}{8}+b\\\\b = 3 - \dfrac{11}{8}\\\\b = \dfrac{3*8}{1*8}-\dfrac{11}{8}\\\\b= \dfrac{24-11}{8}\\\\b= \dfrac{13}{8}[/tex]

Slope-intercept form:

          [tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

The value of x and y is y=29, X=21.

180-60=120

4y+4=120 get y by itself and remember that what ever you do to one side you do to the other.

Alternate interior angles are congruent so 3x-3=60

What is an angle ?

Angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. Angles formed by two rays lie in the plane that contains the rays. Angles are also formed by the intersection of two planes. These are called dihedral angles.

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Answer: The car was not speeding. It went 27.6 mi/h.

Step-by-step explanation: The equation v=2/5L is given where v is measured in mi/h. L is measured in ft. Since we have the value 69 for L, we sub it into the equation. We end up getting 27.6 mi/h after evaluating.

Answer:

=sqrt of 30

Step-by-step explanation:

=sqrt of 3×2×5

=sqrt 30

Answer:

A

Step-by-step explanation:

that should be an equal sign

Step-by-step explanation:

[tex](3 \sqrt{3 - 2 \sqrt{2)(3 \sqrt{3 - 2 \sqrt{2)} } } } [/tex]

The sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

A sequence is defined as an arrangement of numbers in a particular order.

The most common sequence are the arithmetic and the geometric sequence.

The sequence starts with 0 but each number is two times three less than the previous number.

This means the first term of the sequence is 3.

Hence,

2 times 3 less than the previous number means:

Aₙ = Aₙ₋₁ - 2(3)

where,

Let's use the formula to find the other numbers in the sequence,

A₂ = A₂₋₁ - 2(3) = 0 - 6 = -6

A₃ = A₃₋₁ - 2(3) = -6 - 6 = -12

A₄ = A₄₋₁ - 2(3) = -12 - 6 = - 18

A₅ = A₅₋₁ - 2(3) = -18 - 6 = - 22

Therefore, the sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

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An equation to answer the question of how many people must attend the third show to have an average attendance of 3,000 when the other show attendance numbers are 2580, and 2920 is 9,000 = 2,580 + 2,920 + x.

An equation is a mathematical expression or statement that shows that two values are equal.

An equation uses the equation mark (=).

To have an average attendance per show of 3,000 for three shows, a total of 9,000 people must attend the three shows (3,000 x 3).

Attendance for the first show = 2,580

Attendance for the second show = 2,920

Total attendance for the two shows = 5,500

Required attendance for the third show, x = 9,000 = 2,580 + 2,920 + x

x = 9,000 - 5,500

x - 3,500

Thus, the equation for the third show attendance is 9,000 = 2,580 + 2,920 + x where x = 3,500.

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And the other show attendance numbers are 2580 and 2920.

The length and width is 32 inches and 10 inches.

Let us assume the width of rectangle be w. So, length of rectangle = 3w + 2. As per the known fact, the length and width of rectangle for perimeter is related as - Perimeter = 2 (length + width)

Keep the values in formula to find the value of width

84 = 2 (3w + 2 + w)

Performing addition in bracket

84 = 2 (4w + 2)

Performing multiplication

84 = 8w + 4

8w = 84 - 4

Performing subtraction

8w = 80

w = 80 ÷ 8

Performing division

w = 10 inches

Finding length now -

Length = 3×10 + 2

Length = 30 + 2

Length = 32 inches

Hence, the length and width is 32 inches and 10 inches.

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Answer:

3k

Step-by-step explanation:

k+(k-1)+(k+1)=3k

The equation of circle is [tex]x^2+y^2=100[/tex]

The standard equation of a circle with center (h, k) and radius r is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex] ........(1)

This is the equation needed for the circle with a center at A(h, k) and a radius equal to r since it describes the relationship between the coordinates of any point on the circumference.

Now according to the question, it is given that the circle has the center at origin and length of its radius is 10.

Center = (h, k)=(0, 0)

Radius(r) = 10 units

Now, substituting the given values in (1) we get;

⇒[tex]x^2+y^2=100[/tex]

Therefore, the equation of circle centered at origin with radius 10 is [tex]x^2+y^2=100[/tex]

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Answer: 1. {a, b, c, d, e}

2. {a, b, d}

3. {c, f, g, h}

4. {a, c}

Step-by-step explanation:

1. AUC ==> Means take all parameters from A and C.

A+C=

{a, b, c, d}+{a, e}={a, b, c, d, e}

2. B∩A ==> Means take the common parameters from B and A

B: {b, e, a, d}

A: {a, b, c, d}

Both B and A have a, b, and d.

So answer is {a, b, d}.

3. B' is every parameter that isn't in B

Reminder: B={b, e, a, d}.

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(B'): {c, f, g, h}

4. A-B∩C'

First, let's find C'.

C' is every parameter that isn't in C.

Reminder: C={a, e}

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(C'): {b, c, d, f, g, h}

Then lets find B∩C'

B: {b, e, a, d}

C': {b, c, d, f, g, h}

Both B and C' have b and d, so B∩C' is {b, d}

A-{b, d}=

{a, b, c, d}-{b, d}={a, c} ==> Answer for 4

Answer:

[tex]\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}[/tex]

[tex]\sf 2) \quad B \cap A = \{a, b, d\}[/tex]

[tex]\sf 3) \quad B' = \{c, f, g, h \}[/tex]

[tex]\sf 4) \quad A -(B \cap C') = \{a, c \}[/tex]

Step-by-step explanation:

Set Notation

[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]

Given sets:

Therefore:

Question 1

[tex]\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}[/tex]

Question 2

[tex]\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}[/tex]

Question 3

[tex]\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}[/tex]

Question 4

[tex]\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}[/tex]

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The value of x associated with the point P on a number line is 0.5.

In accordance with the statement, the condition SP = PT means that the locations of points S, T and P on the number line are 0, 1, x, so that S < P < T and that point P is equidistant of points S and T. Then, the location of the missing point is determined by the midpoint formula:

P = 0.5 · S + 0.5 · T

P = 0.5 · 0 + 0.5 · 1

P = x = 0.5

The value of x associated with the point P on a number line is 0.5.

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Answer: See attached

Step-by-step explanation:

See attached

Answer:

So what you have to do is go back to you lesson and read till you find an answer just like this one and read how to do it when u do that go back and to the quick check and find an answer that is similar. the reason why I'm telling you this is cause I cant calculate it right. or what you can do is calculate it right on here.

Step-by-step explanation:

https://www.inchcalculator.com/cubic-footage-calculator/

Answer:

(−∞, 31/5) or x <31/5 (the graph will start a little bit past 6 and will be a open circle and head to the left)

Answer:

x< 6[tex]\frac{1}{5}[/tex]

Step-by-step explanation:

7<-5(x -8) - 2  Distribute the 5

7<-5x + 40 - 2

7<-5x +38  Subtract 38 from both sides

-31<-5x  Divide both sides by -5

[tex]\frac{31}{5}[/tex] >x  When you divide both sides by a negative number, you must flip the sign.

or

x < 6 [tex]\frac{1}{5}[/tex]

Answer:

6(5)3(5)² + (3)³

Step-by-step explanation:

Put this into your calculator just like this

Answer is 140

According to the question,

Given that,

111 + 10 + 25 - 2 × 3

calculate the term

121 + 25 - 6

121 + 19

140

Una solicitud de licencia de manejar comercial

(DL 44C). Al firmar este formulario significa

que usted se compromete a hacerse un análisis

químico para determinar el contenido de alcohol

o drogas en su sangre. Si se niega a firmarlo, el

Departmento de Vehículos Motorizados (DMV)

no expedirá o renovará su licencia de manejar.

• Su nombre verdadero y completo.

• Un reporte de examen médico aprobado Medical Examination Report (MER). El formulario

federal válido (orginal o copia) del reporte del

examen médico Medical Examination Report

(MER) (MCSA-5875) y el formulario del certificado del examinador médico Medical Examiner’s Certificate Form (MEC) MCSA-5876

al solicitar la licencia de manejar o el permiso;

tal reporte debe ser expedido por un doctor en

los Estados Unidos que esté licenciado en medicina (M.D.), un doctor licenciado en osteopatía

(D.O.), un médico asistente con licencia (P.A.),

un enfermero practicante avanzado y registrado

(APN) o un doctor quiropráctico autorizado. Los

conductores que tengan certificados para manejar autobuses escolares, autobuses de actividades

estudiantiles School Pupil Activity Bus Certificate (SPAB), autobuses de jóvenes, vehículos

paratránsito para el público en general General

Public Paratransit Vehicle (GPPV) o co certificados para manejar vehículos de labores agrícolas

deben tener un examen médico expedido por

un doctor en medicina, un médico asistente con

licencia, un enfermero practicante avanzado y

registrado o un quiropráctico que esté autorizado en el registro nacional de examinadores médicos certificados National Registry of Certified

Medical Examiners (§12517.2 del CVC).

Se requiere un reporte médico fechado en los 2

últimos años para cualquier tipo de solicitud de

licencia CDL y luego cada 2 años.

Nota: No envíe por correo su reporte médico

a la patrulla de caminos California Highway

Patrol (CHP). El formulario MER y el formulario

del certificado MEC pueden presentarse en una

oficina del DMV o ser enviados por correo directamente al DMV para actualizarlos. Envíe por

correo sus formularios MER y MEC a la siguientedirección por lo menos 4 semanas antes que se

venza su reporte médico anterior o su privilegio

para manejar vehículos CMV puede invalidarse.

Envíe el reporte médico a:

Department of Motor Vehicles

CDL/PDPS Unit, MS G204

PO Box 942890

Sacramento, CA 94290-0001

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