A student uses the right-hand rule as shown. an illustration with a right hand with fingers curled and thumb pointed up. what is the direction of the magnetic field in front of the wire closest to the student? up right down left
The direction of the magnetic field in front of the wire closest to the student is on the left. The direction is found by the right-hand rule.
What is the right-hand rule?The right-hand rule is a popular mnemonic for remembering how axes in three-dimensional space are oriented.
The fact that the three axes of three-dimensional space have two different orientations gives birth to the majority of the many left-hand and right-hand rules.
Using the right-hand rule, we can recall this diagram. Your thumb points in the direction of the magnetic force pushing on the moving charge
If you point your pointer finger in the direction of the positive charge and then your middle finger in the direction of the magnetic field.
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Answer:
left
Explanation:
edge 2022
Question :- If a spring of spring constant ‘m’ is divided into 5:3 ratio, then what will be the spring constant of the larger piece of spring?
Answer :- 8m/5
I need explanation!
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Here we go ~
As we have been given, The spring of spring constant " m " was cut to form 2 new springs in ratio of 5 : 3.
we have to find out the spring constant of the longer spring which was formed, and it's given that spring constant of the main spring was " m "
Now, let the length of main spring be " l "
So, lengths of the resultant springs will be :
[tex]\qquad \cal \dashrightarrow \: \dfrac{5l}{8} \: \: and \: \: \dfrac{3l}{8} \: \: \: \: respectively[/tex]
And we know that spring constant is inversely proportional to length of spring so, we infer that :
[tex]\qquad \cal \dashrightarrow \: m\propto \dfrac{1}{l} m \: \: \: \: \: - (1)[/tex]
where, m is spring constant of main spring and l is its length.
[tex]\qquad \cal\dashrightarrow \: m_1 \propto \dfrac{8}{5l} \: \: \: \: \: \: \: - (2)[/tex]
where, m1 is spring constant of longer spring, and 5l/8 is its length.
let's divide (2) by (1), we will get ~
[tex]\qquad \cal \dashrightarrow \: \dfrac{m_1}{m} = \dfrac{8}{5l} \div \dfrac{1}{l} [/tex]
[tex]\qquad \cal \dashrightarrow \: \dfrac{m_1}{m} = \dfrac{8}{5l} \times \dfrac{l}{1} [/tex]
[tex]\qquad \cal \dashrightarrow \: \dfrac{m_1}{m} = \dfrac{8}{5} [/tex]
[tex]\qquad \cal \dashrightarrow \: {m_1}{} = \dfrac{8}{5} m [/tex]
So, the spring constant of equivalent longer strong formed will be 8/5 m
prove:
[tex]m_2 = \frac{8m}{5} [/tex]
Explanation:
Given:
Spring constant of spring= m
The ratio of spring = 5:3
To find:
spring constant of the larger piece of spring?
Solution:
Let the length of larger piece L2 be 5x and smaller piece L1 be 3x with spring constant m2 and m1 respectively.
now,
spring constant (m) inversely proportional to the length of spring i.e.
[tex]m \propto \: \frac{1}{l} {,}\: m_1 \propto \: \frac{1}{l_1} {,}\: m_2 \propto \: \frac{1}{l_2}[/tex]
Also,
The spring is connected in series hence,
[tex] \frac{1}{m} = \frac{1}{m_1} + \frac{1}{m_2} [/tex]
and
[tex] \frac{m_1}{m_2} = \frac{l_2}{l_1} \\ {m_1} = {m_2} \cdot \frac{l_2}{l_1} \\ {m_1} = {m_2} \cdot \frac{5}{3} \\ [/tex]
Substituting above value in,
[tex] \frac{1}{m} = \frac{1}{m_1} + \frac{1}{m_2} \\ \frac{1}{m} = \frac{1}{{m_2} \cdot \frac{5}{3}} + \frac{1}{m_2} \\ \frac{1}{m} = \frac{3}{5m_2} + \frac{1}{m_2} \\ \frac{1}{m} = \frac{3m_2 + 5m_2}{5 {m_2}^{2} } \\ \frac{1}{m} = \frac{8m_2}{5 {m_2}^{2} } \\ \frac{1}{m} = \frac{8 \cancel {m_2}}{5 \cancel{m_2}^{2} } \\ \frac{1}{m} = \frac{8}{5m_2} \\ m_2 = \frac{8m}{5} [/tex]
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A wave along a guitar string has a frequency of 440 hz and the wavelength of 1. 25m. What is the speed of the wave?
Answer:
550 m/s
Explanation:
Speed of wave = wl * f wl = 1,25 m f = 440 Hz (given)
1.25 m * 440 = 550 m/s
A cosmic ray electron moves at 7.50 × 106 m/s perpendicular to the Earth’s
magnetic field at an altitude where field strength is 1.00 × 10−5 T. What is the radius
of the circular path the electron follows?
Answer:
4.27m
Explanation:
force on moving charge= qvBsin$
centripetal force=mv^2/r
since the forces are equal
mv^2/r=qvBsin$
r= (mv^2)/(qvBsin$) = mv/qBsin$
r-radius
m-mass of an electron
q-charge on electron
v-velocity of the electron
B-field strength
$ - angle
r= ((9.1093837 ×10^-31)kg × 7.50 × 10^6 m/s)/(1.6×10^-19C×10^-5T×sin90) = 4.27m
What direction would the north pole of a bar magnet point if you were to hang the bar magnet from a thin string?.
Answer:
TOWARD the North pole.
Explanation:
. The net force F acting on an object that moves along a straight line is given as a function of time t by 2 F t( ) = κt + τ , where 2 κ = 1 N s and τ = 1 N . What is the change in momentum of the object from t = 0 s to t = 3 s?
The change in the momentum of the object moving along a straight line is determined as 3 Ns.
Change in momentum of the object
The change in the momentum of the object is equal to impulse received by the object.
The impulse received by the object is determined from the product of force and time of action.
J = Ft
Ft() = kt + τ
at time 0 s
Ft(0) = 1(0) + 1
Ft(0) = 1 Ns
at time , t = 3 s
Ft(3) = 1(3) + 1
Ft(3) = 4 Ns
Change in momentum from 0 s to 3 s, = 4 Ns - 1 s = 3 Ns
Thus, the change in the momentum of the object moving along a straight line is determined as 3 Ns.
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A glass slides across a bar and slows down due to a kinetic friction of 0. 175N. If the glass weighs 0. 500N, what is the coefficient of kinetic friction between the glass and the bar?
Answer:
F = M a = Ff force of friction
Ff = μ M g = μ W where M g = weight of glass
The problem gives the kinetic friction as a force (Ff) in Newtons
μ = Ff / W = .175 / .500 = .35
Light enters air from water. The angle of refraction will be.
Answer:
90 degrees...
Explanation:
Hope this helps you!!!
Lesson 18, Physical Science
Please help!! I'll mark you as Brainlest
Q1. Describe how the skater's kinetic and potential energy change as the skater descends. Explain what happens to the total energy (potential energy + kinetic energy) in terms of the Law of Conservation of Energy.
Change the skater with the "Choose Skater" button.
Q2. Describe any changes to the bar graphs you see when you change skaters. Is the Law of Conservation of Energy still obeyed?
Reset the half-pipe and click on the "Show Grid" check box. Grab the track (drag the track with a right-click) and set the bottom of the track at "zero" height.
Select the default, 75 kg, PhET skater and set him at 5.0 meters above the zero and allow him to skate.
Q3. How much potential energy does the skater have at 5.0 meters? How much kinetic energy does the skater have at 0.0 meters?
Q4. If a 20.0 kg skater started his skate at 10 meters height (on Earth):
How much potential energy would the skater have at the start of skating?
How much kinetic energy would the skater have at the start of skating?
How much potential energy would the skater have at zero height?
How much kinetic energy would the skater have at zero height?
Create this skate path:
Start the skater on the left side and observe. Then answer the following question:
Q5. Does the skater have enough energy to make it all the way to the right side? Explain why or why not.
If the skater starts on the left on the following path:
Q6. Answer the parts of this question based upon the above skater path. If the skater starts at point "A":
Where does the skater have the maximum potential energy?
Where does the skater have the minimum potential energy?
Where does the skater have the minimum kinetic energy?
Where does the skater have the maximum kinetic energy?
At which two points would the skater have about the same kinetic energy?
Q7. Based upon the equation for potential energy, how do you expect the potential energy to change when the gravity is lower than it is on Earth (for example, gravity on the moon is 1.6 m/s2 )?
Use the option boxes to move the skater to Jupiter, where acceleration due to gravity is 26 m/s2.
Q8. Describe any differences you see in potential and kinetic energy between the Earth and Jupiter.
Use the option boxes to move the skater to the moon where the acceleration from gravity is 1.6 m/s2.
Q9. Describe any differences you see in potential and kinetic energy between the Earth and the moon.
Q10. Does this agree with the prediction you made in Q7?
Q11. How high must a 20 kg skater start at to have a kinetic energy of 360 joules at a height of 0 meters?
Q12. What is the total energy of the 60.0 kg skater before she starts her ride, 12 meters above the ground?
Q13. If you throw a 2.0 kg basketball straight up in the air, at what height will the basketball have 160 J of potential energy?
Q14. Describe what happens to the bar graphs when you change the amount of friction. Is the Law of Conservation of Energy still obeyed?
The kinetic energy of the skater would increase while his potential energy would decrease as he descends from top to bottom.
What is the law of conservation of energy?The law of conservation of energy states that the energy possessed by a physical body can neither be created nor destroyed, but it can only be converted (transformed) from one form of energy to another.
Based on the law of conservation of energy, the total energy (potential energy + kinetic energy) would always remain constant because it is conserved.
The potential energy of this skater at a height of 5.0 meters is given by:
PE = mgh
PE = 75 × 9.8 × 5.0
PE = 3,675 Joules.
Also, the kinetic energy of this skater at a height of 0.0 meters would be equal to zero assuming it is at rest.
In conclusion, the potential energy possessed by a physical body is highly dependent on its height while kinetic energy depends only on motion, regardless of height.
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The spacecraft that really gave scientists their first good close-up look at the planet Mercury was:
Answer:
Mariner 10 in 1974 and 1975
Explanation:
The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and round answer to the nearest whole number.)
53....................................
Explanation:
True or False
1. Conduction occurs only when molecules are in contact with each other.
2. Fast moving particles will take heat from slow moving particles.
3. Energy is carried in waves during conduction.
4. Conduction can transfer heat through space.
5. Warmer particles will give heat to cool particles.
6. During conduction, the movement of the molecules is important.
7. Light is a form of conduction heat transfer.
8. A carrier is needed for conduction to occur - something must carry the heat.
9. Fast moving particles will speed up slow moving particles.
#1
True#2
No it happens opposite as heat transfers from high to low
False#3
True#4
No it can't be happened in vaccum
False#5
True(Stated in no 2)#6
TrueFaster the movement faster the heat transfer
#7
Light particles get transferred from low to high (sun light)
True#8
True#9
FalseThe shared attitudes, values, goals, and practices that characterize groups is defined as
A. family
B. parenting
C. genetics
D. culture
Please select the best answer from the choices provided
Ο Α.
OB
Ос
OD
A boy throws a ball vertically up. It returns the ground after seconds. Find the maximum height reached by the ball.
Answer:
If he throws the ball with speed V then (vertical speed)
V / g is the time to reach maximum height (V2 - V1) / a
The total time to again reach the ground is then
T = 2 V / g
H = 1/2 g t^2 where t = V / g
H = 1/2 g (V / g)^2 = V^2 / (2 g)
This is the familiar formula
V = (2 g H)^1/2 for the initial upwards speed
Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum that has a wavelength of 725 nm and a peak electric field magnitude of 2. 9 V/m. (Use the following as necessary: t and x. Assume that E is in volts per meter, B is in teslas, t is in seconds, and x is in meters. Do not include units in your answer. Assume that E
The peak magnetic field of the electromagnetic wave in the red part of the visible spectrum is 9.67 x 10⁻¹⁰ T.
Relationship between electric and magnetic field
The relationship between electric and magnetic field at a given peak electric field is given as;
c = (E₀) / (B₀)
where;
c is speed of lightE₀ is the peak electric fieldB₀ is the peak magnetic fieldB₀ = E₀ / c
B₀ = (2.9) / (3 x 10⁹)
B₀ = 9.67 x 10⁻¹⁰ T
Thus, the peak magnetic field of the electromagnetic wave in the red part of the visible spectrum is 9.67 x 10⁻¹⁰ T.
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if a plane is flying in the air and it crashes on the border of america and canada where do u bury the survivors
Answer:
Why would you bury the survivors? LOL
Answer:
you dont bury the surviors because they are alive.
Explanation:
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What type of corrective lenses would an eye doctor most likely prescribe for a patient with astigmatism?.
What is a mutation? *
A) a type of molecule that genes and chromosomes are made of
B) a random change to a gene that sometimes results in a new trait
C)the process in which two parents pass on their genes to create offspring
D)a characteristic that all members of a species have
If an asteroid with a diameter of 1 km strikes the earth, how big of a crater will it make?.
An asteroid with diameter of 1 km will have a crater of 5.236 x 10⁸ m³ volume when it strikes the earth.
Volume of crater made by the asteroidThe impact created by an asteroid when it strikes the earth depends on several factors such as the size of the asteroid.
The bigger the diameter of the asteroid the bigger the crater volume it will make when it strikes the earth.
Assuming the asteroid to be spherical, volume of the crater is calculated as follows;
V = 4/3πr³
Where;
r is radius of the sphere = 500 mV = 4/3π(500)³
V = 5.236 x 10⁸ m³
Thus, an asteroid with diameter of 1 km will have a crater of 5.236 x 10⁸ m³ volume when it strikes the earth.
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The signs of cognitive (mental) stress include all of the following except: a. loss of memory b. loss of concentration c. poor judgment d. isolation please select the best answer from the choices provided. a b c d
All of the above-mentioned symptoms of cognitive stress except for isolation. Option d is correct.
What is cognitive mental stress?Mental (cognitive) stress is an emotional/physical strain that causes a person to feel irritated, depressed, angry, anxious, and so on.
Cognitive stress is marked by a variety of moods and/or emotions linked to excessive anxiety about money, overall health, job loss, and so on.
All of the above-mentioned symptoms are markers of cognitive stress. In some circumstances, this condition may exacerbate stress.
Loss of memory, loss of concentration, and poor judgment are symptoms that are markers of cognitive stress.
Social isolation has been linked to a variety of mental illnesses, including increased stress, despair, and anxiety.
Hence all of the above-mentioned symptoms of cognitive stress except isolation. Option d is correct.
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Answer:
D
Explanation:
Three liquids are at temperatures of 13 ◦C, 19◦C, and 40◦C, respectively. Equal masses of the first two liquids are mixed, and the equilibrium temperature is 15◦C. Equal masses of the second and third are then mixed, and the equilibrium temperature is 36.9 ◦C. Find the equilibrium temperature when equal masses of the first and third are mixed. Answer in units of ◦C.
Answer:
2 C1 = 4 C2 heat loss = heat gain
C1 = 2 C2
17.9 C2 = 3.1 C3 mixing second and third
17.9 / 2 C1 = 3.1 C3 C1 for C2
17.9 C1 = 6.2 C3
C3 = 2.89 C1
C1 (T - 13) = C3 (40 - T) heat loss = heat gain
T - 13 = 2.89 (40 - T) = 115.5 - 2.89 T
3.89 T = 128.5
T = 33 deg C
When liquids A and D is added the temperature of the mixture will be θ= 36.71°C.
What is Temperature ?
Temperature is a physical quantity which measures hotness and coldness of a body. Temperature measures the degree of vibration of molecule in a body. Temperature is measured in centigrade (°C), Fahrenheit (°F) and Kelvin (K) in which Kelvin (K) is a SI unit of temperature. Absolute scale of temperature means Kelvin scale of temperature. relation between Kelvin(K) and centigrade (°C), °C= K - 273.15 from equation, 273.15 K means 0 °C, which is freezing point of water (ice).
Let m be the mass of each liquid and C₁,C₂,C₃ Be specific heat of liquid A,B,C Respective. When A and B are mixed. The final temperature is 15°C
∴ Heat gained by A= heat lost by B
i.e. mC₁(15−13)=mC₂(19-15)
5C₁ = 4C₂
C₂ = 5/4 C₁ ________1)
When B and C are mixed. The final temperature is 36.9°C
∴ Heat gained by B= heat lost by C
i.e. mC₂(36.9−19)=mC₃(40-36.9)
C₂17.9 = C₃3.1
C₃=5.77C₂_____2)
from equa. 1) and 2)
We get,
C₃=5.77(5/4 C₁)
C₃ = 7.21 C₁
When A and C is mixed let the final temperature be θ.
C₁(θ-13) = C₃(40-θ)
C₁(θ-13)=7.21 C₁(40-θ)
(θ-13)=7.21 (40-θ)
θ-13= 288.4-7.21θ
8.21 θ=288.4+13
8.21 θ= 301.4
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Evelynn is measuring the pitch of a piano note. What unit of measurement is she most likely recording her value
in?
O hertz
decibels
Ofrequency
amplitude
Answer:
hertz
Explanation: play piano
In a parallel circuit the ________ resistance is always less than the resistance of any individual resistor.
Answer:
"total" resistance
The current will have the option of going thru more than 1 resistor so the total resistance of the circuit will be less than any resistance in the circuit.
A collision is elastic only when kinetic energy and momentum are conserved through the collision. Group of answer choices True False
Answer:
Both momentum and kinetic energy are conserved quantities in elastic collisions.
Explanation:
An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.
What is the position of the earth, moon, and sun during a new moon?
Earth is between the sun and the moon
sun is between Earth and the moon
moon is to the side of Earth and the sun
moon is between the sun and Earth
Answer: The first option
Explanation: common sense
The Moon always rotates about the Earth in its orbit. The position of the Earth, moon and sun during a new moon is Earth is in between Sun and Moon.
What is new moon?When moon has travelled for 14 days, it starts its journey again for the next 14 days. The journey starts from the new moon to the full moon. The position of new and full moon is the same. At this time, the Earth is in between the Sun and the Moon.
Thus, the position of the Earth, moon and sun during a new moon is Earth is in between Sun and Moon.
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Explanations based on supernatural forces, values or ethics can never be disproved and thus do not fall under the realm of science.
options:
True
False
Answer:
true, since science does not believe and agree to the supernatural.
This property of matter describes
a substance's ability to be
stretched thin?
Answer:
Ductility
Explanation:
is the physical property of a material associated with the ability to be hammered thin or stretched into wire without breaking. A ductile substance can be drawn into a wire.
How many years does it take for pluto to orbit the sun.
Answer:
248 years
Explanation:
The last time this happened was from 1979 to 1999. It won't happen again until 2227.
A boy holds a toy soldier in from of a concave mirror. The focal length of the mirror is 0.45 m and the boy holds the toy soldier at a distance of 0.25m from the mirror. Find the image distance.
Once the merry-go-round travels at this new angular speed, with what force does the person need to hold on?.
For a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s is mathematically given as
F= 618.9 N
What is the centripetal force?Generally, the equation for the angular speed is mathematically given as
w = v/R
Therefore
w= 4.7/1.8
w= 2.611 rad/s
Where total momentum
Tm= 642.96 + 272.32
Tm= 915.28
and total inertia
Ti= 184 + 246.24
Ti= 430.24
In conclusion, centripetal force
F= mrw^2
F = m*R*w2^2
F = 76*1.8*2.127^2
F= 618.9 N
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CQ
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a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s in the counter clockwise direction when viewed from above a person with mass m=76 kg and velocity v=4.7 m/s runs on a path tangent to the merry go round once at the merry go round the person jumps on and holds on to the rim of the merry go round angular speed of the merry go round after the person jumps on 2.127 rad/s Once the merry go round travels at this new angular speed with what force does the person need to hold on?