Answers
An atom is considered neutral when it has an equal number of protons (positively charged) and electrons (negatively charged).
When an atom gains or loses electrons, it becomes an ion, which is an atom with an unequal number of protons and electrons, resulting in a net positive or negative charge.
If an atom gains electrons, it becomes an anion with a negative charge. If an atom loses electrons, it becomes a cation with a positive charge.
The magnitude of the negative or positive charge of an ion is equal to the number of electrons gained or lost, respectively.
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Related Questions
A motorist travels a distance of 40 km during a 7 hour period. What was the average
speed? Round to nearest tenth.
Answers
Answer:
The average speed of the motorist was 5.7 kilometers per hour, rounded to the nearest tenth.
Explanation:
The average speed of the motorist can be calculated by dividing the distance traveled by the time taken.
[tex]\boxed{\sf Speed = \dfrac{Distance}{Time}}[/tex]
For this problem, the distance traveled is 40 km and the time taken is 7 hours.
Substitute these values into the formula:
[tex]\implies \sf Average\;speed = \dfrac{40\;km}{7\;hours}[/tex]
This simplifies to:
[tex]\implies \sf Average\;speed = 5.7\;km/h\;(nearest\;tenth)[/tex]
Therefore, the average speed of the motorist was 5.7 kilometers per hour, rounded to the nearest tenth.
Answer:
[tex] 5.7 \ km \ hr^{-1}[/tex]Explanation:
To find:-
The average speed.Answer:-
We are here given that, a motorist travels 40km in 7hrs . And we are interested in finding out the average speed of the motorist . We can find the average speed as ,
Average speed:-
It is defined as the total distance travelled divided by total time taken.Mathematically,
[tex]\longrightarrow \boxed{\rm v_{average}=\dfrac{Distance_{Total}}{Time_{Total }}} \\[/tex]
Here the total distance is 40km and the total time taken is 7hrs . So on substituting the respective values, we have;
[tex]\longrightarrow v_{average}=\dfrac{40\ km}{7\ hr} \\[/tex]
Simplify,
[tex]\longrightarrow v_{average}= 5.714 \ km \ hr^{-1} \\[/tex]
Rounding off to nearest tenth,
[tex]\longrightarrow \boxed{\boldsymbol{ v_{avg}= 5.7 \ km\ hr^{-1}}}\\[/tex]
Hence the average speed of the motorist to the nearest tenth is 5.7 km hr-¹ .
What must be the current I
in the bar for the bar to be in rotational equilibrium when it is at an angle 30.0 ∘
above the horizontal? Use the fact that τ=12IBL2
for a uniform bar of length L
carrying a current I
in a magnetic field B
.
Answers
The current required for a uniform bar to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal and carrying a current I in a magnetic field B is zero, as the torque acting on the bar is zero at this angle.
To find the current I in the bar for it to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal, we need to use the torque equation for a uniform bar carrying a current I in a magnetic field B:
τ = 1/2 IBL² sinθ
where τ is the torque, I is the current, B is the magnetic field, L is the length of the bar, and θ is the angle of the bar relative to the magnetic field.
Since we want the bar to be in rotational equilibrium, the torque must be zero, so we can set the torque equation equal to zero:
0 = 1/2 IBL² sin30°
Solving for I, we get:
I = 0 / (1/2 B L² sin30°)
I = 0
Therefore, the current required for the bar to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal is zero. This is because the torque acting on the bar is zero at this angle, which means that the bar is not experiencing any rotational force and is already in rotational equilibrium.
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How many Btus must be added to 34 lb. of ice at -32°F to change it to steam
at 416-F?
The answer should be like 48,500 something but I want to see the steps to get the answer
Answers
Based on the calculations, approximately 3,697,808 BTUs must be added to 34 lbs. of ice at -32°F to change it to steam at 416°F.
To solve this problem, we need to consider the three stages of the process:
Heating the ice from -32°F to 0°F
Melting the ice at 0°F
Heating the water from 0°F to 416°F
First, we need to calculate the amount of heat required to raise the temperature of 34 lb of ice from -32°F to 0°F. We can use the specific heat of ice, which is 0.5 Btu/lb°F:
Q1 = m * c * ΔT
Q1 = 34 lb * 0.5 Btu/lb°F * (0°F - (-32°F))
Q1 = 544 Btu
Next, we need to calculate the amount of heat required to melt the ice at 0°F. We can use the heat of fusion of ice, which is 144 Btu/lb:
Q2 = m * ΔHf
Q2 = 34 lb * 144 Btu/lb
Q2 = 4896 Btu
Finally, we need to calculate the amount of heat required to raise the temperature of the water from 0°F to 416°F. We can use the specific heat of water, which is 1.0 Btu/lb°F:
Q3 = m * c * ΔT
Q3 = 34 lb * 1.0 Btu/lb°F * (416°F - 0°F)
Q3 = 14,144 Btu
The total amount of heat required is the sum of Q1, Q2, and Q3:
Q total = Q1 + Q2 + Q3
Q total = 544 Btu + 4896 Btu + 14,144 Btu
Q total = 19,584 Btu
Therefore, 19,584 Btus must be added to 34 lb of ice at -32°F to change it to steam at 416°F.
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A cylindrical glass of height h = 10 cm was covered with a piston of mass 3.5 kg and has a cross sectional area of 450 cm2.
(i) Determine the pressure that is exerted by this piston on the gas in the chamber, as shown in the figure. Assume gravitational acceleration 'g' to be 9.81 m/s2. (3)
(ii) Determine the work done when the same cylinder is heated afterwards at a constant pressure of 1 atm and its initial volume changes from Vo to 3Vo. (3)
Answers
Answer:
(i) The pressure exerted by the piston on the gas in the chamber can be calculated using the formula:
Pressure = Force / Area
The force exerted by the piston on the gas is equal to its weight, which can be calculated as:
Force = mass x gravitational acceleration
= 3.5 kg x 9.81 m/s^2
= 34.335 N
The area of the piston is 450 cm^2, which is equal to 0.045 m^2.
Therefore, the pressure exerted by the piston on the gas is:
Pressure = Force / Area
= 34.335 N / 0.045 m^2
= 763 N/m^2 or 763 Pa
(ii) The work done when the cylinder is heated at a constant pressure of 1 atm can be calculated using the formula:
Work = Pressure x Change in Volume
The initial volume of the cylinder is Vo, and the final volume is 3Vo. Therefore, the change in volume is:
Change in Volume = 3Vo - Vo
= 2Vo
The pressure is given as 1 atm, which is equal to 101,325 Pa.
Therefore, the work done is:
Work = Pressure x Change in Volume
= 101,325 Pa x 2Vo
= 202,650 Pa.Vo or 202,650 J:
A runner is sprinting at 3 m/s. But 40 seconds later they are sprinting at 3.8 m/s. What is the runner’s acceleration?
Answers
A runner is sprinting at 3 m/s. But 40 seconds later they are sprinting at 3.8 m/s. What is the runner’s acceleration?
Answer:We can use the following formula to calculate the acceleration:
a = (vf - vi) / t
where:
a = acceleration
vf = final velocity
vi = initial velocity
t = time
In this case, the initial velocity (vi) is 3 m/s, the final velocity (vf) is 3.8 m/s, and the time (t) is 40 seconds.
So, we can plug these values into the formula and solve for the acceleration:
a = (3.8 m/s - 3 m/s) / 40 s
a = 0.8 m/s^2
Therefore, the runner's acceleration is 0.8 m/s__2__.
An object has a mass of 50kg. On earth, the weight of the object is almost 500 newtons but the object floats in space. Why does an object that is so difficult to lift on earth float on space ?
Answers
The object will continue to float in a stationary position until acted upon by a force, such as a push or pull.
What is Weight?
Weight is the force with which an object is attracted towards the Earth or any other celestial body due to gravity. The weight of an object can be calculated by multiplying its mass with the acceleration due to gravity. In the SI system of units, weight is measured in Newtons (N).
An object that has a mass of 50kg has a weight of nearly 500 newtons on Earth due to gravity. However, in space, where there is no significant gravity, the object will not experience any weight or force pushing it down. The object will float because there is no force acting upon it to cause it to move in a particular direction. This is due to the absence of gravity, which is the force responsible for the weight of an object.
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calculate the force exerted by air on a disk of radius 1.00m at the water's surface
Answers
The force exerted by air on a disk of radius 1.00m at the water's surface is approximately 318.3 N.
To calculate the force exerted by air on a disk of radius 1.00m at the water's surface, we need to know the air pressure and the surface area of the disk.
Assuming standard atmospheric pressure at sea level of 101.325 kPa and neglecting any effects due to wind, we can calculate the force exerted by air on the disk as follows:
Determine the surface area of the disk:
A = [tex]πr^2[/tex]
where r = 1.00m
A = [tex]π(1.00m)^2 = 3.14 m^2[/tex]
Calculate the force exerted by air on the disk using the formula:
F = PA
where P is the air pressure and A is the surface area of the disk.
F = [tex](101.325 kPa)(3.14 m^2)[/tex] = 318.3 N
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Amanda runs a business in a market where all firms are price takers. Bob suggests that she lower her price to attract even more customers. Should Amanda follow Bob's suggestion? Should she consider raising her price?
Answers
Amanda should carefully consider the elasticity of demand, cost of production, and competition before deciding whether to lower or raise prices. The ultimate goal is to find the right balance between attracting customers and maintaining profitability.
In a market where all firms are price takers, lowering the price may attract more customers, but it may also lead to lower profit margins. It is essential to weigh the potential benefits and costs of lowering the price before making a decision.
Amanda should consider several factors before deciding whether to follow Bob's suggestion or raise her price. These factors may include the elasticity of demand for her products, the cost of production, the pricing strategy of her competitors, and the level of competition in the market.
If the demand for Amanda's products is elastic, meaning that customers are very sensitive to price changes, lowering the price may increase the quantity sold but may not lead to higher revenues. In this case, Amanda may need to consider other strategies to increase revenue, such as expanding her product line or improving the quality of her products.
If the demand for Amanda's products is inelastic, meaning that customers are less sensitive to price changes, lowering the price may lead to increased revenue. However, Amanda should still consider the cost of production and ensure that the lower price still results in a profit.
Raising the price may be a viable option if Amanda has a unique product or a competitive advantage over her competitors. A higher price may signal higher quality or exclusivity, which can attract customers who are willing to pay a premium for the product. However, Amanda should ensure that the price increase does not lead to a significant decline in the quantity sold.
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A marble rolls off a tabletop 1.1m high and hits the floor at a point 2.1m away from the tables edge in the horizontal direction.
A. How long (in seconds) is the marble (in m/s) in the air?
B. What is the speed of the marble (in m/s) when it leaves the tables edge?
C. What is the speed (in m/s) when it hits the floor?
Answers
y = vit + (1/2)gt^2 (Equation 1)
v = vi + gt (Equation 2)
where y is the vertical displacement, vi is the initial vertical velocity (which is zero when the marble leaves the table), t is the time, and v is the final velocity.
A. To find the time the marble is in the air, we can use Equation 1 with y = 1.1 m and vi = 0:
1.1 = (1/2)gt^2
Solving for t, we get:
t = sqrt(2*1.1/g) = 0.47 seconds
Therefore, the marble is in the air for 0.47 seconds.
B. To find the speed of the marble when it leaves the table, we can use Equation 2 with vi = 0 and t = 0.47 seconds:
v = gt = 9.810.47 = 4.61 m/s
Therefore, the speed of the marble when it leaves the table is 4.61 m/s.
C. To find the speed of the marble when it hits the floor, we need to find the horizontal and vertical components of its velocity. The horizontal component is constant, since there is no horizontal acceleration. The vertical component can be found using Equation 2 with vi = 0 and t = 0.47 seconds:
vy = gt = 9.810.47 = 4.61 m/s
The horizontal component of the velocity can be found from the distance traveled in the horizontal direction (2.1 m) and the time in the air (0.47 seconds):
vx = 2.1/0.47 = 4.47 m/s
The speed of the marble when it hits the floor is the magnitude of its velocity, which can be found using the Pythagorean theorem:
v = sqrt(vx^2 + vy^2) = sqrt(4.47^2 + 4.61^2) = 6.35 m/s
Therefore, the speed of the marble when it hits the floor is 6.35 m/s.
when light strikes a green opaque object the green wavelength of light is .....
1. reflected
2. absorbed
3. transmitted
while all other wavelengths of visible light are......
1. reflected
2. absorbed
3. transmitted
Answers
When light strikes a green opaque object, the green wavelength of light is absorbed, while all other wavelengths of visible light are reflected.
Why does a green object appear green to our eyes?A green object appears green to our eyes because it selectively absorbs all wavelengths of visible light except for the green wavelength of light, which is reflected back to our eyes.
When light strikes a green opaque object, the green wavelength of light is absorbed by the object. This means that the green light is not reflected or transmitted, but rather it is absorbed by the object.
What happens to the energy of the absorbed light when it is absorbed by an opaque object?When light is absorbed by an opaque object, the energy of the absorbed light is converted into other forms of energy, such as thermal energy. This is because the absorbed light energy causes the atoms in the object to vibrate, which in turn generates heat energy.
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The total distance between 4 consecutive Crust of travel wave is 6m.
what is wave length of wave
3/6m=2m
Answers
The wave's wavelength is 2 metres.
What does wavelength 1 translate into?1/ denotes the number of waves in a wave train that can be found in a length of one metre when wavelength is stated in metres, or the number in wavelength is stated in centimetres, then the length is one centimetre. This value is referred to as the spectrum line's wavenumber. The frequency equation is written as f = /, where is the wave speed and is the wavelength of the wave.
If the total distance between four consecutive crests of a wave is 6 meters, then the wavelength of the wave is equal to that distance divided by the number of crests, which is three.
So the wavelength of the wave is:
6 meters / 3 = 2 meters
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A stick is resting on a concrete step with 29
of its total length
hanging over the edge. A single ladybug lands on the end of the stick hanging over the edge, and the stick begins to tip. A moment later, a second, identical ladybug lands on the other end of the stick, which results in the stick coming momentarily to rest at =62.1∘
with respect to the horizontal, as shown in the figure.
If the mass of each bug is 3.09
times the mass of the stick and the stick is 15.1 cm
long, what is the magnitude
of the angular acceleration of the stick at the instant shown? Use =9.81 m/s2.
Answers
In physics, angular acceleration refers to the time rate of change of angular velocity. the magnitude of the angular acceleration of the stick at the instant shown results in tan(θ/2) = 0.010 and θ= 1.15.
Let stand in for the angle formed by the directions of the vectors A and B. The magnitudes of A and B being equal, A, B, and R = A + B form an isosceles triangle with angles of 180, - θ/2, and θ /2. R then equals 2A cos (θ/2) to determine its magnitude. By using the fact that B=A and the isosceles triangle, the law of cosines can be used to demonstrate this.
Once more, A, -B, and D = A-B form an isosceles triangle with an angle at the top of. D = 2Asin(θ/2) is the result of using the law of cosines and the identity (1-cosθ ) = 2sin² (θ/2).
R must equal 100D for the equation to hold, hence 2A cos(θ/2) = 200A sin(θ/2).
This results in tan(θ/2) = 0.010 and θ= 1.15.
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What is the difference between a subsurface and a surface event?
Answers
A subsurface is something that is below the layer that is on the surface, whereas a surface is the topside or upward side of a flat item like a table or a liquid.
What distinguishes the top from the subsurface?Surface mining takes place on the Earth's surface and involves moving unused materials out of the way. Subsurface mining, on the other hand, does not involve moving unused sediments or rocks out of the way.
What does the rock cycle's surface occurrence entail?processes on the surface that convert rock to sediment. deposition. sediment settles on the surface away from the breeze or water that is carrying it. melting. happens as rock sinks towards the mantle of the Earth.
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Microwaves travel at the speed of light 3.00x108 m/s. When the frequency of microwaves is 9.00x109Hz, what is their wavelength?
Answers
The wavelength of microwaves with a frequency of 9.00x10^9 Hz is approximately 0.0333 meters or 33.3 millimeters.
What is the speed of microwaves and what is their frequency?Microwaves are a type of electromagnetic radiation with a frequency range of around 300 MHz to 300 GHz. They are used for various applications, including communication, cooking, and medical imaging.
The speed of microwaves is the same as the speed of light, which is approximately 3.00x10^8 m/s. This means that microwaves travel at a very high speed and can cover long distances in a short amount of time.
How does the wavelength of microwaves change with their frequency?The wavelength of microwaves is inversely proportional to their frequency. This means that as the frequency of microwaves increases, their wavelength decreases.
In other words, higher frequency microwaves have shorter wavelengths, and vice versa. For example, the wavelength of microwaves with a frequency of 9.00x10^9 Hz is approximately 0.0333 meters or 33.3 millimeters.
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load=300,effort =80,load distance =4cm,effort distance =30cm,what mechanical advantage ?
Answers
ANSWER: the mechanical advantage is 3.75.
Explanation:
Given,
Load = 300
Effort = 80
Load distance = 4 cm
Effort distance = 30 cm
To calculate Load distance and Effort distance, we can use the formula:
Load x Load distance = Effort x Effort distance
300 x 4 = 80 x 30
1200 = 2400
Load distance = 4cm
Effort distance = 30cm
Now, we can calculate the mechanical advantage using the formula:
MA = Load / Effort
MA = 300 / 80
MA = 3.75
If it takes a planet 8 years to orbit the sun, how long in years will it take the plantet to go all the way around our sky once?
Answers
it would take the planet approximately 9.14 years to go all the way around our sky once.
The time it takes for a planet to go all the way around our sky once is called its sidereal period. This is the time it takes for the planet to return to the same position in the sky relative to the fixed stars.
The sidereal period of a planet is related to its orbital period around the Sun, by the following formula:
Sidereal period = Orbital period / (1 - Earth's orbital period / Planet's orbital period)
The Earth's orbital period around the Sun is approximately 1 year. Substituting the given values, we get:
Sidereal period = 8 years / (1 - 1/8)
Sidereal period = 8 years / (7/8)
Sidereal period = 9.14 years (approx)
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8. What is the natural force of attraction between any massive bodies.
a. Weight
b. Gravity
c. Friction
Answers
Answer:
Friction
Explanation:
A 75.0-kg man is riding an escalator in a shopping mall. The escalator moves the man at
a constant velocity from ground level to the floor above, a vertical height of 4.60 m. What
is the work done on the man by (a) the gravitational force and (b) the escalator?
Answers
The negative sign indicates that the work done by the escalator is in the opposite direction of the displacement, which is downward. So, the escalator is doing negative work on the man.
The gravitational force is doing positive work on the man because it is in the same direction as the displacement.
StepsWe need to use the formulas for work and gravitational potential energy:
work = force x distance x cos(theta)
gravitational potential energy = mgh
(a) The work done on the man by the gravitational force is given by:
work_gravity = mgh = (75.0 kg)(9.8 m/s^2)(4.60 m) = 3,301 J
The gravitational force is doing positive work on the man because it is in the same direction as the displacement.
(b) The work done on the man by the escalator is given by:
work_escalator = force_escalator x distance x cos(0) = force_escalator x distance
The escalator is moving the man at a constant velocity, so the net force on the man is zero (since the man is not accelerating). Therefore, the force of the escalator must be equal in magnitude and opposite in direction to the gravitational force:
force_escalator = -mg = -(75.0 kg)(9.8 m/s^2) = -735 N
Substituting this value and the distance (4.60 m) into the formula for work, we get:
work_escalator = (-735 N)(4.60 m) = -3,381 J
The negative sign indicates that the work done by the escalator is in the opposite direction of the displacement, which is downward. So, the escalator is doing negative work on the man.
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Two pure tones Cs and Gs, with frequencies from the Pythagorean diatonic scale, are sounded simultaneously. Find a) the frequencies of the three combination tones and b) the notes on the Pythagorean scale to which these tones belong.
Answers
The three combination tones have frequency that are roughly 882.33 Hz, 588.00 Hz, and 293.67 Hz. E, G, and D are the notes on the Pythagorean scale to which the combination tones correspond.
How does Pythagorean differ from simple tuning?Uniformity is provided by Pythagorean tuning, but not chords. The chords are provided via just tuning, which is based on the overtone series' simpler ratios, but it suffers from interval inequality. Even in simple music, meantone tuning produces multiple unfavourable chords despite offering equal intervals.
Sum tone frequency: F1 + F2
Difference tone frequency: F2 - F1
where F1 and F2 are the frequencies of the two pure tones.
Using the Pythagorean diatonic scale, we can find the frequencies of Cs and Gs:
Cs has a frequency ratio of 9/8 with C (fundamental frequency) and a frequency of (9/8) x 261.63 ≈ 294.33 Hz
Gs has a frequency ratio of 3/2 with G (fundamental frequency) and a frequency of (3/2) x 392.00 ≈ 588.00 Hz
Sum tone frequency: 294.33 + 588.00 = 882.33 Hz (approx.)
Difference tone frequency: 588.00 - 294.33 = 293.67 Hz (approx.)
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A glass windowpane in a home is 0.62 cm thick and has dimensions of 1.5 m × 2.3 m. On a certain day, the indoor temperature is 26°C and the outdoor temperature is 0°C.
(a) What is the rate at which energy is transferred by heat through the glass?
W
(b) How much energy is lost through the window in one day, assuming the temperatures inside and outside remain constant?
J
Answers
lass windowpane in a home is 0.62 cm thick and has dimensions of 1.5 m × 2.3 m. On a certain day, the indoor temperature is 26°C and the outdoor temperature is 0°C.the amount of energy lost through the window in one day is approximately 37.9 MJ.
We can use the formula for heat transfer through a material, which is:
Q = k * A * (T1 - T2) / d
where Q is the rate of heat transfer, k is the thermal conductivity of the material, A is the surface area of the material, d is the thickness of the material, T1 is the temperature on one side of the material, and T2 is the temperature on the other side of the material.
(a) We first need to find the thermal conductivity of glass. According to engineeringtoolbox.com, the thermal conductivity of glass is approximately 1.05 W/(m*K). We convert the temperatures to Kelvin:
T1 = 26°C + 273.15 = 299.15 K
T2 = 0°C + 273.15 = 273.15 K
Plugging in the values:
Q = (1.05 W/(m*K)) * (1.5 m * 2.3 m) * (299.15 K - 273.15 K) / (0.62 cm / 100 cm/m)
Q = 438.37 W
So the rate at which energy is transferred by heat through the glass is 438.37 W.
(b) We can convert the rate of heat transfer to energy over time by using the formula:
E = Q * t
where E is the energy, Q is the rate of heat transfer, and t is the time. Assuming 24 hours in a day:
E = 438.37 W * 24 h * 3600 s/h
E = 37,910,899.2 J
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A proton (+1.6 × 10−19 C) moves 20 cm on a path in the direction of a uniform electric field of strength 2.4 N/C. How much work is done on the proton by the electrical field?
Answers
W=Fd
F=Eq
W=Eqd
E = 2.4 N/C
q = 1.6×10⁻¹⁹ C
d = 20 cm = 0.2 m
W = 2.4(1.6×10⁻¹⁹)(0.2)
W = 7.68×10⁻²⁰ J
One litre of oxygem combines with one litre of hydrogen to produce one litre of hydrogen
peroxide.Given that the molecules of oxygen and hydrogen contain two atoms each, determine the
number of atoms in a molecule of hydrogen peroxide. Show your work.
Answers
The molecule of hydrogen peroxide contains four atoms.
Number of atoms calculation.The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is:
O2 + 2H2 → 2H2O2
This equation shows that one molecule of oxygen (O2) reacts with two molecules of hydrogen (H2) to produce two molecules of hydrogen peroxide (H2O2).
We are given that one liter of oxygen (O2) combines with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2). Since one mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters, we can assume that one mole of oxygen (O2) reacts with one mole of hydrogen (H2) to produce one mole of hydrogen peroxide (H2O2) at STP.
Using Avogadro's number (6.022 x 10^23), we can calculate the number of molecules of each substance in one mole:
Oxygen (O2): 1 mole = 6.022 x 10^23 molecules
Hydrogen (H2): 1 mole = 6.022 x 10^23 molecules
Hydrogen peroxide (H2O2): 1 mole = 6.022 x 10^23 molecules
From the balanced chemical equation, we know that two molecules of hydrogen peroxide (H2O2) are produced for every one molecule of oxygen (O2) that reacts. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of oxygen (O2) that react.
Since we are given that one liter of oxygen (O2) reacts with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2), we can say that the volumes of the gases are proportional to their number of molecules. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is also equal to the number of molecules of hydrogen (H2) that react.
So, we can start with one mole of hydrogen (H2) and use the balanced chemical equation to find the number of moles of hydrogen peroxide (H2O2) produced:
1 mole H2 → 2 moles H2O2
Since one molecule of hydrogen peroxide (H2O2) contains two hydrogen atoms and two oxygen atoms, we can find the total number of atoms in a molecule of hydrogen peroxide:
2 hydrogen atoms + 2 oxygen atoms = 4 atoms
Therefore, a molecule of hydrogen peroxide contains four atoms.
In summary:
The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is: O2 + 2H2 → 2H2O2
One mole of oxygen (O2) reacts with two moles of hydrogen (H2) to produce two moles of hydrogen peroxide (H2O2).One liter of oxygen (O2) reacts with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2).Using Avogadro's number, we can calculate the number of molecules of each substance in one mole.Since the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of hydrogen (H2) that react, we can find the number of atoms in a molecule of hydrogen peroxide by considering the atoms in a molecule of hydrogen. Therefore, a molecule of hydrogen peroxide contains four atoms (two hydrogen atoms and two oxygen atoms).
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What is one way that light waves differ from sound?
Answers
Answer:
The direction of vibration in the waves is at 90° to the direction that the light travels. Light travels in straight lines, so if you have to represent a ray of light in a drawing, always use a ruler. Unlike sound waves, light waves can travel through a vacuum (empty space).
Explanation:
A student trying to calculate the
parameters of a satellite orbit obtained
a quantity Q which is related with the
orbital radius R., radius of the earth
R and acceleration due to gravity, g
½
2
by the formula Q
(SR²)
gR
dimensional analysis, find out what Q
represents.
Select one:
Tangential force
O Orbital speed
.
Centripetal acceleration
O Torque on the satellite
Using
Answers
Orbital speed is defined as Fg=GmM(R+h)2, where m is the satellite's mass and h is its height above the planet's surface.
How do you determine a satellite's orbital velocity?The orbital mobility is given by the formula g(R+h) = gr. Orbital velocity refers to the velocity needed to counteract the gravitational pull on the moon with its inertia, or propensity to continue moving.
What factors affect a satellite's orbital velocity?The planetary velocity of a satellite that orbits the Earth is determined by the height of the satellite above the planet. The needed orbital velocity increases with the distance from the Earth. At lower altitudes, a satellite encounters traces of Upper orbit, which causes drag.
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A driver holds his hands on opposite sides of the 35-cm -diameter steering wheel in a modern sports car. A torque of 4.5 N⋅m is required to turn the wheel. If the driver applies an equal force on each side of the wheel, what is the minimum force each hand must supply?
Answers
Therefore, each hand must supply a minimum force of 12.86 N to turn the steering wheel.
How hard must you move the steering wheel?Although you can use any amount of power, modern cars all have assistance, so you don't need to use much force. You can add up to 200 N (20 kg), but any more weight may damage your steering rod ends, which could lead to increased steering vibration or even failure.
The formulas below provide the torque needed to move the steering wheel.
τ = Fr
where r is the steering wheel's radius and F is the power being applied to it.
Given that the steering wheel's diameter in this instance is 35 centimeters, the radius is as follows:
r = 35 cm / 2 = 17.5 cm = 0.175 m
The torque required is given as 4.5 N⋅m.
Therefore:
4.5 N⋅m = F * 0.175 m
Solving for F, we get:
F = 4.5 N⋅m / 0.175 m
F = 25.71 N
The minimal force that each hand must exert is as follows because the driver exerts equal force on each side of the wheel:
F/2 = 25.71 N / 2 = 12.86 N.
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Suppose an alien civilization has a space station in circular orbit around its home planet. The station's orbital radius is four times the planet's radius.(a)if an alien astronaut has weight wsurface just before launch from the surface, will she be weightless when she reaches the station and floats inside of it?(b) If not, what will be the ratio of her weight in orbit to her weight on the planet's surface? (If she is weightless, enter 0.)
Answers
the astronaut's weight in orbit will be 1/16th of her weight on the planet's surface.
(a) Yes, the astronaut will be weightless when she reaches the station and floats inside it. This is because the space station is in freefall around the planet, and the astronaut will be in the same state of freefall as the station.
(b) The ratio of the astronaut's weight in orbit to her weight on the planet's surface can be found using the equation:
w_orbit/w_surface = [tex](R_surface / R_orbit)^2[/tex]
where w_surface is the astronaut's weight on the planet's surface, w_orbit is her weight in orbit, R_surface is the planet's radius, and R_orbit is the radius of the station's orbit.
Substituting R_orbit = 4R_surface and simplifying, we get:
w_orbit/w_surface = (1/16)
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Neglecting air resistance, firing a projectile at an angle of ____
degrees will allow it to have the greatest horizontal displacement or ____
First blank answers :
45
60
90
Second blank answer choices:
Height
Trajectory
Range
Answers
Neglecting air resistance, firing a projectile at an angle of 45
degrees will allow it to have the greatest horizontal displacement or range.
We can prove this by using the range formula, which is...
[tex]R=\frac{v^2sin(2 \theta)}{g}[/tex]
In order to maximize the value R, [tex]sin(2 \theta)[/tex] has to be equal to 1. What values of theta make sine equal 1? In degrees, that would be 90. So if we let θ equal 45 we get....
[tex]R=\frac{v^2sin(2 (45))}{g} \Longrightarrow R=\frac{v^2sin(90)}{g} \Longrightarrow R=\frac{v^2(1)}{g}[/tex]
Thus, the value of R is maximized.
An object R leaves a platform XY with a horizontal velocity of 7ms1 and lands at Q. If it takes the same object 0.3s to fall freely from Y to P, calculate the distance PQ. (Take g = l0m−2 ) A. 7.30m B.2.55m C.2.l0m D. 1.65m E.0.45m
Answers
With a 7ms1 horizontal velocity, an object R departs from a platform XY and lands at Q. The length PQ is 0.45m if the identical object falls freely from Xy to P in 0.3 seconds.
Is the initial velocity constant across all angles?There is no possible for the items to have the same start y-component velocity unless they're shot with distinct initial speeds given that each is launched at a various perspectives. The objects must have been shot at different speeds if they had the same maximum height.
Why is a launch angle of 45 degrees ideal?We can observe that over the longest-range the signal reaches its maximum output value, 1, at an output data angle of 90 degrees Punts 2 are at a 90-degree angle, so is at a 45-degree angle. In other words, a projectile moves and furthest when it is fired at a 45-degree angle.
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A standing wave formed on a rope that is 7.5 meters long. The fundamental harmonic forms at 14 Hz Speed
If the rope is being shaken to form a standing wave pattern displaying five "bumps", then the wave pattern would be called the harmonic. Complete the chart using the information from above.
Pic attached below
Answers
A standing wave formed on a rope that is 7.5 meters long. The fundamental harmonic forms at 14 Hz.
If the rope is being shaken to form a standing wave pattern displaying five "bumps", then the wave pattern would be called the fifth harmonic.
Complete the chart using the information from above:
( chart is attached below the answer )
To calculate the wavelength, we can use the formula: wavelength = speed / frequency.
For the fifth harmonic, the frequency is 70 Hz, and the speed is 7.5 m/s (given in the problem). Therefore, the wavelength is:
wavelength = speed / frequency = 7.5 / 70 = 0.107 meters.
We can also calculate the period using the formula: period = 1 / frequency. For the fifth harmonic, the period is:
period = 1 / frequency = 1 / 70 = 0.0143 seconds.
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An ice cube has a mass of 64 g and is initially at a temperature of 0°C . The ice cube is heated until 56.6 g has become water at 100°C and 7.4 g has become steam at 100°C. How much energy (in kJ) was transferred to the ice cube to accomplish the transformation?
Answers
Answer:
An ice cube has a mass of 64 g and is initially at a temperature of 0°C . The ice cube is heated until 56.6 g has become water at 100°C and 7.4 g has become steam at 100°C. How much energy (in kJ) was transferred to the ice cube to accomplish the transformation?