if a gas occupies 15 l at pressure of 2.3 atm what would the volume be at 3.1 atm

Answer:

the study of Earth's magnetic field is known as isochronism

Explanation:

isochronism is having a period that is independent of oscillator amplitude in an oscillator. Like, a pendulum or balance.

Robert uses a spring scale to measure force. The unit of his measurement is newtons.

In material science, a power is an impact that can change the movement of an item. A power can make an item with mass change its speed, i.e., to speed up. Power can likewise be portrayed naturally as a push or a force. Logicians in classical times involved the idea of power in the investigation of fixed and moving articles and basic machines, yet scholars, for example, Aristotle and Archimedes held crucial mistakes in grasping power. To a limited extent this was because of a deficient comprehension of the occasionally non-clear power of erosion, and a thusly lacking perspective on the idea of normal movement.

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Answer:

Drinks are cooled more effectively by ice pieces at 00C and not by water at 00C. This is because ice takes away more heat from the drink while melting as a result of high specific latent heat capacity of ice.

Explanation:

Since the cannonball was launched horizontally (launch angle of 0) with a speed of 35m/s from a height of 15m, the time the cannonball remains in the air is for 1.75 s

A projectile is an object that moves through air in a parabolic path

Since the cannonball is a projectile and was launched horizontally (launch angle of 0) with a speed of 35m/s from a height of 15m, using the equation of motion y' - y = ut - 1/2gt² we find the time it takes the cannonball to reach the ground. or remain in the air

Since y' - y = ut - 1/2gt²  where

Substituting the values of the variables into the equation and solving for t, we have

y' - y = ut - 1/2gt²  

0 m - 15 m = 0 m/s × t - 1/2 (9.8 m/s²)t²  

- 15 m = 0 m/s - (4.9 m/s²)t²  

- 15 m = - (4.9 m/s²)t²  

t² = -15 m/- (4.9 m/s²)

t² = 3.061 s²

t = √3.061 s²

t = 1.75 s

So, the time the cannonball remains in the air is for 1.75 s

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Because according to Rutherford's atomic model electrons revolve around the nucleus and are not embedded in it just like plum in pudding. Therefore, it was J.J Thomson's model was rejected.

Rutherford disapproved the previous atomic model of J.J Thomson which suggested that electron are embedded in a positively charged nucleus like the plums in a pudding also known as plum pudding model.

He performed gold foil experiment to determine the atomic model.

However, after conducting the experiment he found that many electrons went starting without changing path.

Only few changed their path showing that atom has a dense massive structure called nucleus.

Thus, Rutherford model shows that electron are not embedded in the nucleus instead they revolve around it.

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The wavelength of the initial note is 2.34m

The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction. The distance a wave travels between its crests or troughs is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The wave's crest is its highest point, while its dip is its lowest. Because a wavelength represents a distance or length, it is expressed in length units like meters, centimeters, millimeters, nanometers, etc. Light's wavelength changes with color, or it differs for each hue. While violet has the shortest wavelength, red has the longest.

wavelength = v/f

Given:

Initial frequency, [tex]f_{initial} = 146.8 Hz[/tex]

Final frequency, [tex]f_{final} = 880\;Hz[/tex]

Sound Level, [tex]\beta = 79\;dB[/tex]

We know that,

Speed of the sound, [tex]v=343\;m/s[/tex]

Density of air, [tex]\rho=1.2\;kg/m^{3}[/tex]

Wavelength, [tex]\lambda = \frac{v}{f}[/tex]

Wavelength of initial note is,

[tex]\lambda = \frac{v}{f_{initial} }[/tex]

Substitute the known values in the above equation,

[tex]\lambda = \frac{343}{146.8}[/tex]

[tex]\lambda = 2.34\;m[/tex]

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The amount of heat the cup absorb is 1003200 J.

Given,

Mass of coffee cup = 4.00 × 100 g or 4 kg

Room temperature = 20°C

Hot water temperature = 80°C

We have to find the amount of heat the cup absorbed.

Now, by using the specific heat formula, we have

Q = mCΔT

Where m is the mass of the substance, c is the specific heat, ΔT is the change in temperature, and Q is the amount of heat received or lost.

Putting the values, we get

Q = 4 × 4180 × (80°- 20°)

Q = 1003200 J/kg K

Hence, the amount of heat absorbed by the cup is 1003200 J/kg K.

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The woman needs to climb a step of 1.05 m to work off her breakfast.

The potential energy of an object is the energy that is stored in the object due to its position above the ground level.

The potential energy of the woman can be used to determine the number of steps she needs to climb.

potential energy + heat energy = chemical energy

1 kcal = 4184 J

0.540 kcal = ?

= 2259.36 J

P.E = mgh

55 x 9.8 x h = 0.25(2259.36)

h = 1.05 m

Thus, the woman needs to climb a step of 1.05 m to work off her breakfast.

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The sign of v(O) is positive.

Recurrence is the quantity of events of a rehashing occasion for each unit of time. It is additionally once in a while alluded to as fleeting recurrence to underscore the difference to spatial recurrence, and customary recurrence to stress the differentiation to precise recurrence. Recurrence is communicated in units of hertz (Hz) which is comparable to one (occasion) each second. The comparing time frame is the time term of one cycle in a rehashing occasion, so the period is the corresponding of the recurrence. Recurrence is estimated in units called hertz (Hz). At the point when one wave passes in a single second its recurrence is 1 wave each second or 1 Hertz. Recurrence and period are really alternate extremes. While period is estimated in seconds per cycle, recurrence is estimated in cycles each second. Think about our wave with a time of 2 seconds.

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Achieving a speed of 112.25 km/h is impossible for a human.

The frequency of an event is its repetitions per unit of time. In a contrast to spatial frequency, it is also sometimes referred to as temporal frequency. Hertz (Hz), which equals one (event) per second, is the unit of frequency. The reciprocal of frequency is period, which is defined as the length of time for one cycle of a repeating occurrence.

According to the question:

Emitted frequency, f₀

Frequency heard when athlete approaches horn, f₁

Frequency heard when the athlete passes horn, f₂

Speed of the athlete (observer), v₁

Speed of sound in air = 343m/s

When an athlete approaches the horn, the frequency observed is given by,

f₁=( (v+v₁)/(v-v₂) ) ₓ f₀

f₂=( (v-v₁)/(v-v₂) ) ₓ f₀

From question,

f₂/f₁ = 5/6

5/6 = v-v₁/v+v₁

hence, v₁ = 112.25 km/h

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The acceleration of the ball while it is in contact with the wall is 4036.023 m/s²

ball strikes the wall at a speed of 17.9m/sec

after striking its goes in opposite direction with a speed of 16.0026m/sec

We have given that speed towards the wall is positive

So, u = 17.9m/sec

v = -16.0026m/sec

t = 0.0084 sec

We know that acceleration is given by

a = v-u/t

where

v = final speed

u = initial speed

t = time taken

a = v-u/t

a = 17.9 - (-16.0026) / 0.0084

a = 33.9026 / 0.0084

a = 4036.023 m/s²

So the acceleration of the ball while it is in contact with the wall is 4036.023 m/s²

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The tank that has a volume of 46575 m³ with a concentration of 65 mg/l has a total mass of mercury of: 3027.375 kg

To solve this problem the formulas and the procedures that we have to use are:

Where

Information about the problem:

Using the volume formula we get:

v=  long * wide * deep

v(solution) =  115 m * 45 m * 9 m

v(solution) = 46575 m³

By converting the volume units from m³ to liters we have:

v(solution) = 46575 m³ * 1000 l/1m³

v(solution) = 43.575*10^6 l

Applying the concentration formula and clearing the mass we get:

c= m(solute)/v(solution)

m(solute) = c * v(solution)

m(mercury) = 65 mg (mercury)/l (solution)  * 43.575*10^6 l (solution)

m(mercury) = 3.027375*10^9 mg

By converting the mass units from (mg) to (kg) we have:

m(mercury) = 3.027375*10^9 mg * 1 kg/ 1 * 10^6 mg

m(mercury) = 3027.375 kg

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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A box is at rest on an inclined surface. The last diagram correctly illustrates all forces, including any component force, therefore the correct option is D.

When two physical objects' surfaces come into contact, a force called friction acts to hinder or resist the relative motion of the items. Any two surfaces of things cannot simply slide over or across one another due to the friction force. It depends on the amount of force used on the object.

Additionally, there should be no net vertical forces acting on the inclined block. Fv=0

Therefore, the appropriate diagram is D.

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A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces?

Assume the x-axis is parallel to the surface.

The height the atmosphere would extend is 16,218.5 m.

The standard atmospheric pressure at sea level has a magnitude of 101,325 N/m².

Pa = ρgh

where;

when the density of air is half, ρ = 0.5ρ

Pa = (0.5ρ)gh

h = Pa/(0.5ρg)

h = (101,325) / (0.5 x 1.275 x 9.8)

h = 16,218.5 m

Thus, the height the atmosphere would extend is 16,218.5 m.

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0.125 mm . is the thickness of the sample.

The Hall effect is the creation of a voltage difference (the Hall voltage) across an electrical conductor, which is transverse to an applied magnetic field perpendicular to the current and an electric current in the conductor. Edwin Hall made the discovery in 1879.

We need to know the material's current, magnetic field, length, number of charge carriers, and area in order to calculate the Hall voltage. The Hall voltage is computed using the formula: v=IBlneA=(100A)(1.5T)(1.0102m)(5.91028/m3)(1.61019C)(2.0105m2)=7.9106V.

lof4

First we have to plot those point Then we can use some computer program to fit those point linearly to get slope

of that graph a and interception b. We already know, from theory, that Hall's voltage AVH and magnitude of

magnetic field B are connected as

Δ[tex]V_{H} =\frac{I}{nqt} B[/tex]

where I is current trough probe, n is concentration of charge carriers, q = 1.6 • 10¯19 C is charge of charge

carries and t is thickness of the material. We have put the data from the problem on a graph and fitted linearly and

got

a = 100 μ[tex]\frac{V}{T}[/tex]

b = —0.02  μV.

As we can see, our result are in agreement with theoretical assumptions because interception b is almost O, and a

is asked relation between Hall's voltage A VH and magnitude of magnetic field B. Then we can write

ΔVH =[tex]100X10^{-6}[/tex] V/TB

(4) Then we can use result (4) and numbers from the textbook to calculate the thickness of the sample as

[tex]a=\frac{I}{nqt} \\t=\frac{I}{anq} \\t=\frac{.200A}{100X10^{-6}X 1.6 X10^{-19}X10^{26} } \\t=0.125mm[/tex]

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The magnitude of the force is  295.54 x 10⁻³ N

Attraction betweem nucleus and electron is by electric force. Now, a positive or negative charge generates a field in the void surrounding it. We refer to this void as the electric field.

We know that , force can be found out by given formula

F = q × E where,

F = Force

q = Charge

E = Electric field

Here, the direction of Force is the same as that of the Electric field

Substituting the values, we get

F = 1.4 x 10⁻³ x 211.1

=295.54 x 10⁻³ N

Thus, the magnitude of force is 295.54 x 10⁻³ N

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Part A: Since the magnetic field is proportional to the number of turns per length (n), it follows that the magnetic field within the solenoid stays constant when both the number of turns and the length are doubled.

Answer C for portion B) is accurate; there are still the same number of turns per length.

A solenoid, to put it simply, transforms electrical energy into mechanical work. Many turns of tightly wound copper wire make up the coil. A powerful magnetic field or flux is produced when an electrical current passes through this wire.

Many turns of tightly wound copper wire make up the coil. A powerful magnetic field or flux is produced when an electrical current passes through this wire.

The housing, which is often composed of iron or steel, encloses the coil and concentrates the magnetic field it produces.

By concentrating the magnetic field, which generates the necessary mechanical force, the plunger is drawn to the stop.

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The Pressure of gas in the syringe when at an initial pressure of 60 kPa and when the volume decreased from 45 cm³ to 40 cm³ is 67.5 kPa.

Pressure can be defined as the force acting perperdicular per unit area to the surface of an object.

To calculate the pressure in the gas, we use the formula below

Formula:

Where:

Make P' the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the pressure of the gas is 67.5 kPa.

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The frequency of oscillation is [tex]\frac{1}{2\pi } \sqrt{\frac{\mu B}{I} }[/tex].

The magnetic moment is the magnetism of a magnet or other item that creates a magnetic field, as well as its orientation and strength. Electromagnets, permanent magnets, elementary particles like electrons, different compounds, and a variety of celestial objects are examples of things that have magnetic moments (such as many planets, some moons, stars, etc). The phrase "magnetic moment" typically refers to a system's magnetic dipole moment, which can be represented by an analogous magnetic dipole, which has a magnetic north and south pole that are barely separated from one another. For sufficiently small magnets or at sufficiently wide distances, the magnetic dipole component is adequate. For extended objects, additional terms may be required in addition to the dipole moment, such as the magnetic quadrupole moment.

[tex]T = \frac{ Id^{2}\theta }{dt^{2} }[/tex]

[tex]-\mu B\theta=\frac{ Id^{2}\theta }{dt^{2} }[/tex]

[tex]\frac{d^{2}\theta }{dt^{2} } = -(\frac{\mu BI}{\theta} )[/tex]

By Comparing the above equation with the SHM equation

[tex]\frac{d^2 \theta} {dt^{2} } = -\omega^{2} \theta[/tex]

[tex]\omega^{2} =\frac{ \mu B}{I}[/tex]

Frequency = [tex]\frac{\mu}{2\pi }[/tex]

=[tex]\frac{\sqrt{\frac{\mu B}{I} } }{2\pi}[/tex]

=[tex]\frac{1}{2\pi } \sqrt{\frac{\mu B}{I} }[/tex]

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Answer:

Do you have the fomular send please so I can work on it

The tension in the cord is 4.6 N

According to Newton's second law, an object's acceleration is determined by two factors: the net force acting on the object and the mass of the object.

So, if we chose the positive +x uphill for the FedEx box of mass m2= 1.0 kg and +ve axis for m1 = 3.0 kg such that their accelerations have the same magnitude.

As we apply Newton's second law to each box, we discover that:

[tex]\mathbf{F - T -m_2gsin\theta = m_2a}[/tex]

where;

Thus, the first equation can be rewritten as:

[tex]\mathbf{F-m_2gsin\theta = (m_1+m_2)a}[/tex]

Now, the acceleration moving in the same direction can be computed as:

[tex]\mathbf{a=\dfrac{12N (1.0 kg)(9.8 \ m/s^2)sin 37^0}{(1.0+3.0)kg}}[/tex]

a = 1.53 m/s²

Finally, the tension [tex]\mathbf{T=m_1a}[/tex] = (3.0 kg) (1.53 m/s²)

= 4.6 N

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No, we cannot conclude that the photoelectric effect will also occur for different metals under the same conditions.

Mathematically , we can define the photoelectric effect as:

[tex]K.E_m_a_x=E-\phi[/tex]

where  [tex]K.E_m_a_x[/tex] is the kinetic energy of the free electron, E is the energy of the incident photon, and Ф is the work function, the energy needed to release the electron from its parent atom.

For example if we take a light of  2eV that is incident on cesium, which has a work function of 1.26 eV. In this case, since the photon energy is greater than the work function, an electron can be emitted.

but if we hit this light of 2eV on the platinum which has a work function of 3.65eV . Apparently, this time the light doesn't have enough energy to free loosely bound electrons from their parent atoms.

Thus ,the emission of photoelectrons and the kinetic energy of the emitted photoelectrons depend on the frequency of light  incident on the metal surface.

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An object which has a mass of 70 kg is sitting on a cliff 10 m high. the object's potential energy is 7,000 J

Given: m = 70 kg in mass Height h = 10 m and acceleration g = 10 m/s2

Required. Potential Energy of Gravitation, or P.E

Equation: P.E = mgh

= (70 Kg)(10 m/s²) ( 10 m)

P.E. equals 7,000 kg/m2 or

P.E = 7,000 J

Scottish physicist William Rankine initially used the word "potential energy" in the 19th century, and it has since become a cornerstone of the science. Because of their location, which makes them position relative, items that have this energy stored in them have the capacity to unleash it.

Our knowledge of the cosmos and how we fit into it depends on potential energy. In fact, potential energy and the labour necessary to move an item are determined by the position of the object in the universe.

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The force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity is known as weight.

Weight is the force of gravity acting on a body.

The formula is :

                                W =mg

Here,

W is the weight or force acting on the body. m is the mass of the body, and g is the gravitational acceleration.

Since weight is also a force, so its SI unit is also newton. The value of weight varies from place to place depending on the gravity. Its value can also be equal to zero.

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If a wave has a wavelength of 2.5 m and a frequency of 150 Hz, then the speed of the wave would be

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

As given in the problem If a wave has a wavelength of 2.5 m and a frequency of 150 Hz, then we have to find the speed of the wave,

The speed of the wave = frequency of the wave ×  wavelength

                                       = 150 × 2.5

                                       =375 meters / seconds

Thus, the speed of the wave would be 375 meters / seconds.

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The car that would have the acceleration of 3m/s^2 would be of mass 4 kg.

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20855 turns of wire are on the coil.

A substance or thing that creates a magnetic field is called a magnet. The most noteworthy characteristic of a magnet—a force that pulls on other ferromagnetic elements, such as iron, steel, nickel, cobalt, etc.—as well as the ability to attract or repel other magnets—is caused by this invisible magnetic field. An object made of a substance that has been magnetized and produces its own persistent magnetic field is referred to as a permanent magnet. A common example is a refrigerator magnet used to keep notes on the door of the refrigerator. Ferromagnetic materials are those that can be magnetized and are also those that are powerfully drawn to a magnet (or ferrimagnetic).

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Answer:

true

Explanation:

correct me if i'm wrong

Answer:

False

Explanation:

A convenient definition of temperature is that it is a measure of the average translation kinetic energy associated with the disordered microscopic motion of atoms and molecules. The flow of heat is from a high temperature region towards a lower temperature region.What is the microscopic energy?

Microscopic Energy. This energy is defined as the energy associated with the random, disordered motion of molecules and due to intermolecular forces.Is temperature a direct measure of the amount of energy in an object?

Temperature is a direct measurement of thermal energy, meaning that the hotter an object is, the more thermal energy it has. Heat is a measure of how much thermal energy is transferred between two systems. It is easy to turn mechanical energy into thermal energy, for example using friction.

A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. The physical field of a system of charged particles can also be referred to as the electric field.

In a uniform electric field E, a particle with electric charge q moves in a straight line. The speed of the particle is u.

The electric force exerted in the charge is qE.

The electric field and the velocity of the particle are both in the x direction.

For a small speed u when compared to the speed of light c, the relativistic equation reduces to the classical acceleration:

a = qE / m

Now, as u approaches c, the acceleration will tend to zero, so that the object can or will never reach the speed of light.

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