If an object travels at 10 m/s constantly for 1 minute, how far will it have travelled?

The distance of the ball that would land which was launched horizontally at a speed (s) of 3.4 m/s from a table that is 7.8 m tall (d) will land is 4.29m

Consider the ball moving horizontally off the table. When it moves, gravitational force acts on it pulling the ball downwards. In addition to that objects that are falling down would accelerate quickly i.e., let’s take an object falling at the speed of x, after time t it would travel at 2x, after 2t it would be 4x.

We need to find time to calculate distance by using speed equation.

For calculating time, let’s use the freefall formula,

d = 1/2 gt²

t = √(2d) / g

t = √2 (7.8)/ 9.8

t = 1.262 s

To calculate distance, we could use speed equation as we have both Time and Velocity

s = d / t

d = s t

d = 1.262 * 3.4

d = 4.29 m

Thus, the distance of the ball that would land is 4.29 m

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The magnitude of the change in velocity is determined as 408.94 km/h.

The change in direction of the velocity is 64.4⁰ north of west.

The magnitude of the average acceleration during the trip is 0.0105 m/s².

The magnitude of change in velocity is the resultant velocity of the plane.

v² = a² + b² - 2ab cosθ

where;

v² = (192²) + (250²) - 2(192 x 250) cos(135)

v² = 167,236

v = √167,236

v = 408.94 km/h

vyi = 192 km/h

vy2 = 250 x sin(45) = 176.77 km/h

vy(total) = 192 km/h + 176.77 km/h = 368.77 km/h

vxi = 0

vx2 = - 250 km/h x cos(45) = -176.77 km/h

θ = arc tan (Vy/Vx)

θ = arc tan(368.77 / -176.77)

θ = -64.4 ⁰

θ = 64.4⁰ north of west.

a = v/t

v = 408.94 km/h = 113.6 m/s

h = 3 h = 10,800 seconds

a = (113.6 m/s) / ( 10,800 s)

a = 0.0105 m/s²

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If you were standing still on the equator of Earth you would move at nearly 1,000 miles/hour which is approximately 1,600 km/hr.

What is speed?

Speed is measured as the ratio of distance to the time in which the distance was covered.

The Earth is round and spins once every 24 hours. This spinning of the earth causes the daily motion which we feel here. If you were standing still on the equator of Earth you would move at nearly 1,600 km/hr.

Speed is a scalar quantity as it has only direction and no magnitude.

Speed is defined mathematically as distance/ time.

speed = distance/time expressed in m/s.

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The gravitational force between the two objects whose mass is reduced to one-third of its original mass is 400 N

We know that,

F = G[tex]m_{1}[/tex][tex]m_{2}[/tex] / r²

F = Gravitational force

G = Gravitational constant

[tex]m_{1}[/tex], [tex]m_{2}[/tex] = Mass of two objects

r = Distance between two objects

G = 3600 N

[tex]m_{1}'[/tex] = [tex]m_{1}[/tex] / 3

[tex]m_{2}'[/tex] = [tex]m_{2}[/tex] / 3

F' = G [tex]m_{1}'[/tex] [tex]m_{2}'[/tex] / r² = G[tex]m_{1}[/tex][tex]m_{2}[/tex] / 9 r²

F' = F / 9

F' = 3600 / 9

F' = 400 N

Gravitational force is the force of attraction between two objects due to the presence of gravity.

Therefore, the gravitational force between the two objects whose mass is reduced to one-third of its original mass is 400 N

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The frequency of a radiation that has a wavelength of 9.17 × 10-⁷m is 3.27 × 10¹⁴ Hz.

The frequency of a radiation can be calculated by dividing the velocity of the radiation by the wavelength. That is;

f = v/(λ)

According to this question, some radiation detected by a thermal imaging camera during a training exercise has a wavelength of 9.17 × 10-⁷m. The frequency can be calculated as follows:

f = 3 × 10⁸m/s ÷ 9.17 × 10-⁷m

f = 3.27 × 10¹⁴ Hz

Therefore, the frequency of a radiation that has a wavelength of 9.17 × 10-⁷m is 3.27 × 10¹⁴ Hz.

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Alexus was resting on the couch but then decided she needed some food. She ran at up to 15m/s, accelerating at 3m/s² the whole time, until she got to the fridge . The fridge will be 37.5 m far away from the couch

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Equation of kinematics  are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

given

final velocity = 15m/s

initial velocity = 0

a = 3m/s²

s = ?

a = acceleration = final - initial / time

3 = 15 - 0 / time

time = 15 /3 = 5 seconds

[tex]v^{2}[/tex] - [tex]u^{2}[/tex] = 2as

[tex]15^{2}[/tex] - 0 = 2 * 3 * s

s = 225 /6

  = 37.5 m

The fridge will be 37.5 m away from the couch

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The heigth of the cliff is 63.504 m.

Height is the vertical distance  between two points.

To calculate the height of the cliff, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the heigth of the cliff is 63.504 m.

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Answer:

Explanation:

The correct option will be the option (d) that is 1.09 A.

According to the equation given in the question:

That is; P=i^2R                  where I= current, R= resistance

           P=30 W

           R=25 ohm

            30=i^2*25

              I^2=30/25

             I^2=1.2

             I=1.09A

So, the correct answer of the given question will be 1.09A

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Proper vector notations are V = 42i  km/hr, r = 6.5j m, and a = -1.9j m/s².

In physics, a vector is a quantity with both magnitude and direction. It is typically represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.

A) Let us assume that the west direction is the positive X-axis.

In vector notation, the X-axis is denoted by "i". So, the westward velocity of 42 km/hr  will be written as

V = 42i  km/hr

B) Let us assume that the North direction is the positive Y- axis.

In vector notation, the  Y-axis is denoted by "j". Also, the position vector is represented by the letter 'r'. So position 6.5 measured in m, that is North of the reference point will be written as

r = 6.5j m

C) Let us assmue thaat the downward direction is negative  Y-axis.

In vector notation, the  Y- axis is denoted by "j". so, the downward acceleration measured in m/s2 that has a magnitude of 1.9 will be written as

a = 1.9 × (-j) m/s²

a = -1.9j m/s²

So, proper vector notations are V = 42i  km/hr, r = 6.5j m, and a = -1.9j m/s².

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The height of the 2nd spot is 3 times the height of the 1st spot (Option A)

We'll begin by obtaining the height of the first spot. This can be obtained as follow:

v = 2x / t

343 = 2x / 4

Cross multiply

2x = 343 × 4

2x = 1372

Divide by 2

x = 1372 / 2

Height of first spot = 686 m

v = 2x / t

343 = 2x / 12

Cross multiply

2x = 343 × 12

2x = 4116

Divide by 2

x = 4116 / 2

Height of second spot = 2058 m

Comparison = Height of 2nd spot / Height of 1st spot

Height of 2nd spot / Height of 1st spot = 2058 / 686

Height of 2nd spot / Height of 1st spot = 3

Cross multiply

Height of 2nd spot = 3 × Height of 1st spot

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Answer: Vx is changing  and  Vx is greatest near the beginning of the launch.

Explanation: Think of Vx as a bullet fired from a gun. As soon as it is fired it starts to slow down so Vx is changing and at the beginning Vx has its greatest velocity because it can only go slower from there.

answers are B and C. horizontal velocity never changes so A cannot be the answer. that makes B one of the answers. I would also say that the horizontal velocity is greatest near the beginning of the launch as it just starts, since it stays at a constant pace after, so D is not an answer. hope this helps ^_^

The distance to the destination is 18,000 meters or 18 kilometers. the formula for calculating the distance is speed × Time.

Using the formula:

Distance = Speed × Time

Speed = 15 m/s (meters per second)

Time = 20 minutes

First, we need to convert the time from minutes to seconds, as the speed is given in meters per second.

1 minute = 60 seconds

Time in seconds = 20 minutes × 60 seconds/minute = 1200 seconds

Now, we can calculate the distance:

Distance = 15 m/s × 1200 seconds

Distance = 18,000 meters

So, the distance to the destination is 18,000 meters, or 18 kilometers (since 1 kilometer = 1000 meters).

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Work done on the book is 10.595 Joules .

Work done on the book would be equal to the Potential Energy

Work Done = Potential Energy

W = m g h

where ,  ' m ' represents mass of the book

' g ' stands for  Acceleration due to gravity

' h ' represents the height to which the book is raised

So, according to the given question ,

m = 5.1 kg

g = 9.8 m / s ²

h = 21.2 cm

  =  0.212 m

W = m g h

    = 5.1 kg x 9.8 m / s ² x 0.212 m

    = 10 . 595 Joules

Hence, Work done on the book is 10.595 Joules .

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Answer:

A battery

Explanation:

A battery is the biggest conductor. I think.

Answer: 1 > 3 > 2

Explanation: The range will increase with the velocity. If they are all launched at the same time the ones that are launched the hardest or with the most velocity will go the furthest horizontally. But because they are all launched from the same height and the force of gravity on all three projectiles is constant (the same for all three) they will all hit the ground at the same time but different distances from the starting point.

Answer: I believe that the answer to your question is "Inertia", or A

Explanation:

If a bat hits a ball with 85 N of force the bat will also exert the same force

85N.

You are probably already aware of the force the ball applies to the wall when it is thrown against it. Similar to how the wall exerts a force on the ball, the ball bounces off the wall. Similar to how the earth drags you down with gravity. You might not be aware of it, but you are also pushing the planet with the same amount of power. The third law of Newton is a result of this amazing event.

Newton's Third Law states that if object A exerts a force on object B, then object B must apply a force on object A that is equal in magnitude and directed in the opposite direction.

An object interacts with another object when a push or pull is applied to it. A product of interaction is force. Frictional force, for example, falls into the category of contact force. Non-contact force, on the other hand, includes gravitational force. Newton's third rule of motion explains that when two bodies contact, they exert force on one another. This force is referred to as an action and reaction pair.

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The impulse is equal to the rate of change of momentum.

The term impulse refers to the product of force and time. Let us recall that from Newton's law, impulse is proportional to the change in the momentum of the ball.

We can write from Newtons law;

F. t = Mv - Mu

F = force

t = time

M = mass

v = final velocity

u = initial velocity

Thus, the impulse is equal to the rate of change of momentum.

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The distance travelled by Ann before she begins to slow down is 11.65 m

First, we shall enlighten ourselves on what speed is. This is given below.

Speed is the distance an object travelled per unit time. It can be expressed as:

Speed = distance / time

Finally, we can obtain the distance Ann travelled as illustrated below.

From the question given above, the following data were obtained:

Speed = distance / time

15.56 = distance / 0.749

Cross multiply

Distance = 15.56 × 0.749

Distance = 11.65 m

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Answer:

58.8 metres

Explanation:

using the formula

h=ut+½gt

U=0

g=9.8m/s²

t=12.0a

Hence, h= 0.5 × 9.8 × 144

h = 58.8 metres

The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash, therefore the correct answer is option A.

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem, a test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.

Thus, the initial acceleration vector will point in the direction of the wall and be smaller than the crash's acceleration vector, therefore the correct answer is option A.

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Answer:

100

Explanation:

3-2=1

100/1=100

Answer:

A)  4.95 m

B)  1.48225 m

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

[tex]u=9.00\quad v=9.00 \quad a=0\quad t=0.550[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = \left(\dfrac{u+v}{2}\right)t:\\\\s&= \left(\dfrac{9+9}{2}\right)(0.550)\\s&= (9)(0.550)\\ \implies s&= 4.95\:\sf m\\\end{aligned}[/tex]

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

[tex]u=0\quad a=9.8\quad t=0.550[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\s&= (0)(0.550)+\dfrac{1}{2}(9.8)(0.550)^2\\s&= 0+(4.9)(0.3025)\\\implies s&= 1.48225\:\sf m\\\end{aligned}[/tex]

(a) The current drawn is 5A.

(b) The resistance of the filament is 48Ω.

(a) The formula for power is:

P = VI

therefore, current drawn is;

[tex]I = \frac{P}{V}[/tex]

[tex]I = \frac{1200}{240}[/tex]

I = 5A

Therefore, the current drawn is 5A.

(b) Using, ohm's law:

V = IR

therefore, resistance of the filament is:

[tex]R = \frac{V}{I}[/tex]

[tex]R = \frac{240}{5}[/tex]

R = 48Ω

Therefore, the resistance of the filament is 48Ω.

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The electric force on one of the masses is 0.6 N.

The acceleration of the mass is 0.35 m/s².

The electric force between the masses is calculated as follows;

F = kq²/r²

where;

F = (9 x 10⁹ x (9.8 x 10⁻⁶)²)/(1.2²)

F = 0.6 N

The acceleration of the mass is calculated as follows;

F = ma

a = F/m

a = (0.6 N) / (1.7 kg)

a = 0.35 m/s²

Thus, the electric force on one of the masses is 0.6 N.

The acceleration of the mass is 0.35 m/s².

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The vertical speed of the ball increases and its horizontal speed remains constant as usual because air friction is being neglected.

By definition, air resistance refers to the forces that work against an object's relative motion as it travels through the atmosphere. These drag forces cause the object to move more slowly by acting in opposition to the speed of the incoming flow. Since drag is the part of the net aerodynamic force operating in the opposite direction to the direction of the movement, it differs from other resistance forces in that it directly depends on velocity.

Fluid friction includes friction in the air. These friction forces differ from the conventional model of surface friction in that they rely on velocity. Only rare examples can be dealt with analytically since the velocity dependence may be extremely intricate. Air resistance is roughly proportional to velocity and can be represented in the form of very low speeds for microscopic particles.

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We consider an elementary mass located at this point to be in a stable equilibrium.

An equilibrium is said to be stable if small, externally induced displacements from that state produce forces that tend to oppose the displacement and return the body or particle to the equilibrium state.

Also a body is said to be in a stable equilibrium, if the opposing forces acting on a body are equal.

Thus, along the line through the centers of the Moon and the Earth, there is a point where the gravitational forces exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point to be in a stable equilibrium.

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