if f(x)=√2x+3/6x-5, then f(-1/2)=

Answer:

imagine she doesn't find him

*grins with werid intantions*

Answer:

1=15?

Step-by-step explanation:

5*4=15 becuz lower angle=top 1 angle and stuff i hope this helps. im just a helpless 6th grader :)

Answer:

11 elevenths equal a whole meatloaf

11/11=1

Answer:

11 11ths

Step-by-step explanation:

11/11 = 1 whole

Answer:

y = 28.1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Set Up Equation

"Difference" is subtraction

"y" is y

"8.1" is 8.1

"is" is equal

"20" is 20

y - 8.1 = 20

Step 2: Solve for y

Given:

[tex]\dfrac{1}{4}x+\dfrac{3}{8}[/tex]

To find:

The factor form of given expression by the GCF.

Solution:

First we need to find the GCF of [tex]\dfrac{1}{4}[/tex] and [tex]\dfrac{3}{8}[/tex].

So, make denominators same.

[tex]\dfrac{1}{4}=\dfrac{1\times 2}{4\times 2}=\dfrac{2}{8}[/tex]

Now,

[tex]GCF\left(\dfrac{2}{8},\dfrac{3}{8}\right)=\dfrac{1}{8}[/tex]

[tex]GCF\left(\dfrac{1}{4},\dfrac{3}{8}\right)=\dfrac{1}{8}[/tex]

We have,

[tex]\dfrac{1}{4}x+\dfrac{3}{8}[/tex]

It can be written as

[tex]=\dfrac{2}{8}x+\dfrac{3}{8}[/tex]

Taking out the GCF [tex]\dfrac{1}{8}[/tex], we get

[tex]=\dfrac{1}{8}(2x+3)[/tex]

Therefore, the required factor form is [tex]\dfrac{1}{8}(2x+3)[/tex].

Given:

The graph of the function [tex]f(x)=\dfrac{1}{x}[/tex].

To find:

The value of the function f(x), when x is close to zero.

Solution:

From the given graph it is clear that, f(x) approaches towards infinity and negative infinity as x approaches towards 0.

[tex]f(x)\to \infty[/tex] as [tex]x\to 0^+[/tex]

[tex]f(x)\to -\infty[/tex] as [tex]x\to 0^-[/tex]

In means, the value of must be very large positive value or very large negative if x is close to zero.

From the given options -10,000 is very large negative value.

So, the possible value of f(x) could be -10000 if x is close to 0.

Therefore, the correct option is A.

Answer:

15 centimeters

Step-by-step explanation:

Ratio of Mr. Thompson rectangle = length : width

= 5 : 2

Audrey plans to draw a rectangle with a width of 6 centimeters.

Ratio of Audrey rectangle = length : width

= x centimeters : 6 centimeters

Equate the two ratios to find the value of x

5 : 2 = x : 6

Cross product

5 * 6 = 2 * x

30 = 2x

Divide both sides by 2

x = 30 / 2

= 15

x = 15 centimeters

Audrey's rectangle should have a length of 15 centimeters

Answer:

15

Step-by-step explanation:

Here are the steps, hope it helps!

Answer:

$12.23

Step-by-step explanation:

75/100 = 0.75

0.75 x 6.99 = 5.2425

6.99 + 5.2425 = 12.2325

Answer:

He would need to walk the dog 6 more times because 8 times 11 is 88 and if he has already walked the dog 5 times you would subtract that from 11 to get 6. So the answer would be 6

Step-by-step explanation:

8·11= 88

11-5= 6

Answer: {(-5, 6), (-3, 13), (-14, 30)} is a function

{(12, 12), (12, 13), (12, 14)} and {(1, 3), (4, 5), (4, 9), (6, 19)} are not a function

Answer:

the second set

Step-by-step explanation:

You cannot have the same number in your domain twice.

Answer:

What do you mean? It could be both, in different ways.

Answer: 1)2x=4 -> 4/2 = 2 so x=2

2) y=0

3) x=3

4) 2y + (3*3y) = -15

11y=-15

y = -15/11

5) 4x + 7x + 63 = 19

11x = -44

x = -4

Step-by-step explanation:

Answer:

1. polynomial

2. equation

I hope it will be useful.

Given:

The expressions are

[tex]-6a^2b^{-1}[/tex]

[tex]\dfrac{5}{y^{-3}}[/tex]

To find:

The simplified form of each expression.

Solution:

We have,

[tex]-6a^2b^{-1}[/tex]

[tex]=-6a^2(\dfrac{1}{b})[/tex]      [tex][\because x^{-n}=\dfrac{1}{x^n}][/tex]

[tex]=-\dfrac{6a^2}{b}[/tex]

Therefore, the simplified form of [tex]-6a^2b^{-1}[/tex] is [tex]-\dfrac{6a^2}{b}[/tex].

We have,

[tex]\dfrac{5}{y^{-3}}[/tex]

[tex]=\dfrac{5}{\dfrac{1}{y^3}}[/tex]      [tex][\because x^{-n}=\dfrac{1}{x^n}][/tex]

[tex]=5\times \dfrac{y^3}{1}[/tex]

[tex]=5y^3[/tex]

Therefore, the simplified form of [tex]\dfrac{5}{y^{-3}}[/tex] is [tex]5y^3[/tex].

Answer:

The inverse of f(x) is [tex]f^{-1}[/tex](x) =  ± [tex]\sqrt{\frac{x+\frac{11}{4}}{3}}[/tex] + [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

To find the inverse of the quadratic function f(x) = ax² + bx + c, you should put it in the vertex form f(x) = a(x - h)² + k, where

∵ f(x) = 3x² - 3x - 2

→ Compare it with the 1st form above to find a and b

∴ a = 3 and b = -3

→ Use the rule of h to find it

∵ h = [tex]\frac{-(-3)}{2(3)}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]

∴ h =  [tex]\frac{1}{2}[/tex]

→ Substitute x by the value of h in f to find k

∵ k = 3( [tex]\frac{1}{2}[/tex])² - 3( [tex]\frac{1}{2}[/tex]) - 2

∴ k = [tex]-\frac{11}{4}[/tex]

→ Substitute the values of a, h, and k in the vertex form above

∵ f(x) = 3(x -  [tex]\frac{1}{2}[/tex])² + [tex]-\frac{11}{4}[/tex]

∴ f(x) = 3(x -  [tex]\frac{1}{2}[/tex])² - [tex]\frac{11}{4}[/tex]

Now let us find the inverse of f(x)

∵ f(x) = y

∴ y = 3(x -  [tex]\frac{1}{2}[/tex])² - [tex]\frac{11}{4}[/tex]

→ Switch x and y

∵ x = 3(y -  [tex]\frac{1}{2}[/tex])² - [tex]\frac{11}{4}[/tex]

→ Add [tex]\frac{11}{4}[/tex] to both sides

∴ x + [tex]\frac{11}{4}[/tex] = 3(y - [tex]\frac{1}{2}[/tex])²

→ Divide both sides by 3

∵ [tex]\frac{x+\frac{11}{4}}{3}[/tex] = (y - [tex]\frac{1}{2}[/tex])²

→ Take √ for both sides

∴ ± [tex]\sqrt{\frac{x+\frac{11}{4}}{3}}[/tex] = y - [tex]\frac{1}{2}[/tex]

→ Add  [tex]\frac{1}{2}[/tex] to both sides

∴ ± [tex]\sqrt{\frac{x+\frac{11}{4}}{3}}[/tex] + [tex]\frac{1}{2}[/tex] = y

→ Replace y by [tex]f^{-1}[/tex](x)

∴ [tex]f^{-1}[/tex](x) =  ± [tex]\sqrt{\frac{x+\frac{11}{4}}{3}}[/tex] + [tex]\frac{1}{2}[/tex]

∴ The inverse of f(x) is [tex]f^{-1}[/tex](x) =  ± [tex]\sqrt{\frac{x+\frac{11}{4}}{3}}[/tex] + [tex]\frac{1}{2}[/tex]

Answer:

The standard notation would be 141.7

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

sin= opposite/hypotenuse

Given:

The length of a rectangle is one unit more than its width.

Area of rectangle = 56 units

To find:

The dimensions of the rectangle​.

Solution:

Let, width of the rectangle be x.

Then, length of the rectangle = x+1

Area of a rectangle is

[tex]Area=length\times width[/tex]

[tex]56=(x+1)\times x[/tex]

[tex]56=x^2+x[/tex]

[tex]0=x^2+x-56[/tex]

By splitting the middle term, we get

[tex]x^2+8x-7x-56=0[/tex]

[tex]x(x+8)-7(x+8)=0[/tex]

[tex](x-7)(x+8)=0[/tex]

Using zero product property, we get

[tex]x-7=0[/tex] and [tex]x+8=0[/tex]

[tex]x=7[/tex] and [tex]x=-8[/tex]

Width cannot be negative. So, x=7.

Now,

Width = 7 units

Length = 7+1

            = 8 units

Therefore, the length of the rectangle is 8 units and width is 7 units.

Answer:

7

Step-by-step explanation: POV: I got it right

Answer:

1/49

Step-by-step explanation:

multiplying two of these, as long as the bases are the same, which is true here, you can add the exponents

so the exponents would be

-5/6 + (-7/6)=-5/6-7/6=-12/6=-2

7^-2=1/49

Answer:

Step-by-step explanation:

1/49

Answer:

see explanation

Step-by-step explanation:

Using the rule of exponents

[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex] , then

[tex]1.5^{-2}[/tex]

= [tex]\frac{1}{1.5^{2} }[/tex]

= [tex]\frac{1}{2.25}[/tex]

= 0.4444.....

Answer:

First tanks

Step-by-step explanation:

Rate for the first tank

One tank is filling at a rate of 5/8 gallon per 7/10 hour.

= 5/8 gallon ÷ 7/10 hour

= 5/8 ×10/7 (gallon/hour)

= 25/28 gallon/hour

= 0.8928571429 gallon /hour

Rate for the second tank

A second tank is filling at a rate of 5/9 gallon per 2/3 hour.

5/9 gallon ÷ 2/3 hour

5/9 × 3/2 (gallon per hour)

= 5/6 (gallon per hour)

= 0.8333333333 gallon/hoir

The tank that is filling faster the first tank at the rate of 0.8928571429 gallon /hour

60°

take (43.4-1.4)m to get the remaining height which Wii be you height ie.42m

base is the distance that the man stands away from the pole

using tan rule will be opposite/adjacent

Answer:

The slope of the parallel line to the given line is [tex]-\frac{1}{4}[/tex]

The equation of the parallel line to the given line and passes through the given point is y + 4 =  [tex]-\frac{1}{4}[/tex] (x + 2)

The y-intercept of the parallel line to the given line and passes through the given point is  [tex]-\frac{9}{2}[/tex]

Step-by-step explanation:

In the given figure

∵ The given line passes through points (2, 6) and (-6, 8)

∴ x1 = 2 and y1 = 6

∴ x2 = -6 and y2 = 8

→ Substitute them in the rule of the slope above to find it

∵ m = [tex]\frac{8-6}{-6-2}[/tex] = [tex]\frac{2}{-8}[/tex] = [tex]-\frac{1}{4}[/tex]

∴ The slope of the given line is [tex]-\frac{1}{4}[/tex]  

∵ Parallel lines have the same slopes

∴ The slope of the parallel line to the given line is [tex]-\frac{1}{4}[/tex]

∵ The parallel line passes through the point (-2, -4)

∴ x1 = -2 and y1 = -4

∵ m = [tex]-\frac{1}{4}[/tex]

→ Substitute them in the point-slope form above

∵ y - (-4) = [tex]-\frac{1}{4}[/tex] (x - (-2))

∴ y + 4 =  [tex]-\frac{1}{4}[/tex] (x + 2)

∴ The equation of the parallel line to the given line and passes through

   the given point is y + 4 =  [tex]-\frac{1}{4}[/tex] (x + 2)

∵ m = [tex]-\frac{1}{4}[/tex]

→ Substitute it in the slope-intercept form above

∴ y =  [tex]-\frac{1}{4}[/tex] x + b

→ To find b substitute x by -2 and y by -4 (coordinates the given point)

∵ -4 = [tex]-\frac{1}{4}[/tex](-2) + b

∴ -4 = [tex]\frac{1}{2}[/tex] + b

→ Subtract  [tex]\frac{1}{2}[/tex]  from both sides

∴ [tex]-\frac{9}{2}[/tex] = b

∵ b is the y-intercept

∴ The y-intercept of the parallel line to the given line and passes

   through the given point is  [tex]-\frac{9}{2}[/tex]

Answer:

What is the slope of the line that is parallel to the given line and passes through the given point?

✔ –1/4

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the given point?

✔ y + 4 = –1/4(x + 2)

What is the y-intercept of the line that is parallel to the given line and passes through the given point?

✔ –9/2

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

hope you have a wonderful new year

Answer:

245

Step-by-step explanation:

What is 70 percent (calculated percentage %) of number 350? Answer: 245.

Answer:

[tex]6^{30}[/tex]

Step-by-step explanation:

Using the rules of exponents

[tex](a^m)^{n}[/tex] ⇔ [tex]a^{mn}[/tex]

[tex]\frac{a^{m} }{a^{n} }[/tex] ⇔ [tex]a^{(m-n)}[/tex]

Given

[tex]\frac{(6^-4)^{-9} }{6^6}[/tex]

= [tex]\frac{6^{36} }{6^{6} }[/tex]

= [tex]6^{(36-6)}[/tex]

= [tex]6^{30}[/tex]

Answer:

Step-by-step explanation:

The Answer is 10