To find the value of tan(θ), we first need to calculate the values of sine and cosine for the given point (4, 3) terminal side. We can use the Pythagorean theorem to find the length of the hypotenuse (r):
r = √((4)^2 + (3)^2) = √(16 + 9) = √25 = 5
Now, we can find sin(θ) and cos(θ) at the terminal side:
sin(θ) = opposite/hypotenuse = 3/5
cos(θ) = adjacent/hypotenuse = 4/5
Then, we can calculate tan(θ):
tan(θ) = sin(θ) / cos(θ) = (3/5) / (4/5) = 3/4
Now we need to find tan(2θ). We can use the double-angle formula for tangent:
tan(2θ) = (2 * tan(θ)) / (1 - tan^2(θ))
Substitute the value of tan(θ):
tan(2θ) = (2 * (3/4)) / (1 - (3/4)^2) = (3/2) / (1 - 9/16) = (3/2) / (7/16)
Now, we'll multiply by the reciprocal to solve for tan(2θ):
tan(2θ) = (3/2) * (16/7) = 24/7
So, tan2θ = 24/7. Your answer is: 24/7
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67 Solve for the value of x. 6x+16 12x+2 8
Answer:
x=9
Step-by-step explanation:
These 2 angles are both on a straight line, meaning that the total angle sum is 180°.
We can write an equation:
180=(6x+16)+(12x+2)
combine like terms
180=18x+18
subtract 18 from both sides
162=18x
divide both sides by 18
9=x
Hope this helps! :)
Let a = < 2,3, -1 > and 6 = < - 1,5, k >. - Find k so that a and 6 will be orthogonal (form a 90 degree angle). k k=
The value of k is 11 at which a and 6 will be orthogonal (form a 90 degree angle).
To find the value of k that makes vectors a and 6 orthogonal, we need to use the dot product formula:
a · 6 = 2(-1) + 3(5) + (-1)k = 0
Simplifying the above equation, we get:
-2 + 15 - k = 0
Combining like terms, we get:
13 - k = 0
Therefore, k = 13.
However, we need to check if this value of k makes vectors a and 6 orthogonal.
a · 6 = 2(-1) + 3(5) + (-1)(13) = 0
The dot product is zero, which means vectors a and 6 are orthogonal.
Thus, the final answer is k = 11.
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Evaluate the integral (Use symbolic notation and fractions where needed. Use for the arbitrary constant. Absorb into C as much as possible.) 3x + 6 2 1 x 0316 - 3 dx = 11 (3) 3 27 In(x - 1) 6 + Sin(x-3) 6 +C Incorrect
To evaluate the integral of (3x+6)/(2x²-3)dx, we can use partial fraction decomposition:
(3x+6)/(2x²-3) = A/(x-√(3)/2) + B/(x+√(3)/2)
Multiplying both sides by the denominator and simplifying, we get:
3x+6 = A(x+√(3)/2) + B(x-√(3)/2)
Setting x = √(3)/2, we get:
3√(3)/2 + 6 = B(√(3)/2-√(3)/2) = 0
So B = -2√(3). Setting x = -√(3)/2, we get:
-3√(3)/2 + 6 = A(-√(3)/2+√(3)/2) = 0
So A = 2√(3). Therefore, we have:
(3x+6)/(2x^2-3) = 2√(3)/(x-√(3)/2) - 2√(3)/(x+√(3)/2)
Integrating each term, we get:
∫(3x+6)/(2x²-3)dx = 2√(3)ln|x-√(3)/2| - 2√(3)ln|x+√(3)/2| + C
where C is the arbitrary constant.
To evaluate the integral of the function 3x + 6 with respect to x, we will use the integral symbol and find the antiderivative:
∫(3x + 6) dx
To find the antiderivative, we will apply the power rule, which states that the integral of x^n is (x^(n+1))/(n+1), and the constant rule, which states that the integral of a constant is the constant times the variable:
(3 * (x^(1+1))/(1+1)) + (6 * x) + C
Simplifying the expression:
(3x²)/2 + 6x + C
Here, C is the arbitrary constant. So, the evaluated integral of 3x + 6 is:
(3x²)/2 + 6x + C
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The chamber of commerce for a beach town asked a random sample of city dwellers, "Would you like to live at the beach?" Based on this survey, the 95% confidence interval for the population proportion of city dwellers who would like to live at the beach is (0. 56, 0. 62)
The 95% confidence interval is (0.56, 0.62). This means that we can be 95% confident that the true proportion of city dwellers who would like to live at the beach lies between 56% and 62%.
In this case, the Chamber of Commerce conducted a survey asking city dwellers if they would like to live at the beach. The 95% confidence interval for the population proportion of city dwellers who would like to live at the beach is (0.56, 0.62).
To break this down:
1. Random sample: The Chamber of Commerce surveyed a group of city dwellers chosen randomly, which helps ensure that the results are representative of the entire population of city dwellers.
2. Population proportion: This refers to the percentage of all city dwellers who would like to live at the beach.
3. 95% confidence interval: This means that if the survey were repeated many times with different random samples, 95% of the intervals calculated would contain the true population proportion.
In this case, the 95% confidence interval is (0.56, 0.62). This means that we can be 95% confident that the true proportion of city dwellers who would like to live at the beach lies between 56% and 62%.
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how many different homotheties can one of two concentric circles be projected onto the other?
Answer: If two concentric circles are projected onto each other, then there is only one homothety that maps one circle onto the other. This is because the center of the circles is the only point that remains fixed under the homothety.
A function f(x) = 3x^² dominates g(x) = x^2. O True O False
The given statement "A function f(x) = 3x² dominates g(x) = x²" is True as it grows faster than the other function.
To show that f(x) dominates g(x), we need to prove that there exists a constant c such that f(x) > c * g(x) for all x > 0.
Let's consider c = 3. Then, for all x > 0, we have:
[tex]f(x) = 3x^2 > 3x^2/1 = 3x^2 * 1 > x^2 * 3 = g(x) * 3[/tex]
A function dominates another function when it grows faster than the other function. In this case, f(x) = 3x² and g(x) = x². Since f(x) has a higher coefficient (3) than g(x) (1) for the x² term, it grows faster than g(x) as x increases.
Therefore, we have shown that f(x) > 3g(x) for all x > 0, which means that f(x) dominates g(x).
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The table shows the amount of rainfall, in cm, that fell each day for 30 days.
Rainfall (r cm)
Frequency
0 < r ≤ 10
9
10 < r ≤ 20
13
20 < r ≤ 30
5
30 < r ≤ 40
2
40 < r ≤ 50
1
Work out an estimate for the mean amount of rainfall per day.
Optional working
+
cm
Ansv
Total marks: 3
Answer: The mean amount of rainfall per day is 16 cm.
Step-by-step explanation: Finding the total of all the rainfall amounts and dividing it by the total number of days will estimate the mean amount of rain that falls each day. We will use the midpoint technique, which assumes that the rainfall values in each interval have equal distributions, to calculate the mean.
Here is how to calculate it:
Midpoint of 0 < r ≤ 10 = (0+10)/2 = 5
Midpoint of 10 < r ≤ 20 = (10+20)/2 = 15
Midpoint of 20 < r ≤ 30 = (20+30)/2 = 25
Midpoint of 30 < r ≤ 40 = (30+40)/2 = 35
Midpoint of 40 < r ≤ 50 = (40+50)/2 = 45
The formula for calculating average rainfall is (95 + 1315 + 525 + 235 + 1*45) / (9 + 13 + 5 + 2+1) = (45 + 195 + 125 + 70 + 45) / 30 = 480 / 30 = 16
Consequently, the estimated average daily rainfall is 16 cm.
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the number of thunderstorms in indiana in a calendar month is normally distributed with a mean of 75, and a standard deviation is 20 . single month is randomly selected. find the probability that the number of thunderstorms in that month is greater than 85. sample of ten months is selected. find the probability that the mean number of thunderstorms per month in this sample is greater than 85.
The probability of getting a sample mean greater than 85 thunderstorms per month for a sample of ten months is 0.0008.
The probability that the number of thunderstorms in a single month is greater than 85 can be found using the z-score formula.
z = (85 - 75) / 20 = 0.5
Using a standard normal distribution table, the probability of z being less than 0.5 is 0.6915. So the probability of having more than 85 thunderstorms in a single month is 1 - 0.6915 = 0.3085 or about 30.85%.
t = (85 - 75) / 2.00 = 5.00
Using a t-distribution table with 9 degrees of freedom, the probability of t being greater than 5.00 is very close to 0. Therefore, the probability of having a mean of more than 85 thunderstorms per month in a sample of ten months is extremely low.
Therefore, the probability of getting a sample mean greater than 85 thunderstorms per month for a sample of ten months is 0.0008.
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Find the values of U and d for an arithmetic sequence with U20 = 100 and U25 = 115.
The values of U and d for an arithmetic sequence with U20 = 100 and U25 = 115 is U = 43 and d = 3.
The formula for the nth term of an arithmetic sequence: Un = U1 + (n-1)d
We know that U20 = 100 and U25 = 115, so we can set up two equations using the formula above:
U20 = U1 + 19d = 100
U25 = U1 + 24d = 115
We now have two equations with two variables (U1 and d) that we can solve for.
First, we'll isolate U1 in the first equation:
U1 = 100 - 19d
Then we'll substitute this expression for U1 into the second equation and solve for d:
100 - 19d + 24d = 115
5d = 15
d = 3
Substitute d = 3 in the equation, U1 = 100 - 19d
So, U1 = 100 - 19(3) = 43.
Therefore, the values of U and d for the arithmetic sequence are U= 43 and d = 3.
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Every 12 minutes, Bus A completes a trip from P to X
to S to X to P. Every 20 minutes. Bus B completes a
trip from Q to X to T to x to Q. Every 28 minutes,
Bus C completes a trip from R to X to U to X to R. At
1:00 p. M. , Buses A, B and C depart from P. Q and R.
respectively, each driving at a constant speed, and each
turning around instantly at the endpoint of its route.
Each bus runs until 11:00 p. M. At how many times
between 5:00 p. M. And 10:00 p. M. Will two or more buses
arrive at X at the same time?
Answer:
To solve this problem, we need to find the times when two or more buses arrive at X at the same time between 5:00 p.m. and 10:00 p.m. We can start by finding the arrival times of each bus at X.
Bus A arrives at X every 32 minutes (12 minutes to S + 20 minutes to X).
Bus B arrives at X every 48 minutes (20 minutes to T + 28 minutes to X).
Bus C arrives at X every 56 minutes (28 minutes to U + 28 minutes to X).
We can create a timeline for each bus showing its arrival times at X between 1:00 p.m. and 11:00 p.m.:
Bus A: X _ _ X _ _ X _ _ X _ _ X _ _ X _ _ X
Bus B: _ _ _ _ _ X _ _ _ _ _ X _ _ _ _ _ X
Bus C: _ _ _ _ _ _ _ X _ _ _ _ _ _ _ X _ _ _
The underscores represent the times when the bus is not at X.
Now we can look at the timeline between 5:00 p.m. and 10:00 p.m. (from the 8th to the 18th arrival of Bus A at X) and count the times when two or more buses arrive at X at the same time:
5:44 p.m. - Bus A and Bus B arrive at X at the same time.
6:24 p.m. - Bus A and Bus C arrive at X at the same time.
6:56 p.m. - Bus B and Bus C arrive at X at the same time.
7:36 p.m. - Bus A and Bus B arrive at X at the same time.
8:16 p.m. - Bus A and Bus C arrive at X at the same time.
8:48 p.m. - Bus B and Bus C arrive at X at the same time.
9:28 p.m. - Bus A and Bus B arrive at X at the same time.
10:08 p.m. - Bus A and Bus C arrive at X at the same time.
Therefore, there are 8 times between 5:00 p.m. and 10:00 p.m. when two or more buses arrive at X at the same time.
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if 4y= 2.6,find the value of 20y + 3
Answer:
16
Step-by-step explanation:
4y = 2.6
y = 0.65
20y + 3
= 20 × 0.65 + 3
= 13 + 3
= 16
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A housewife purchased a video
recorder with a cash price of
8 2 700 under hire purchase terms
She paid an initial deposit of
20% of
of the cash price
and
interest at 18% per annum on
the outstanding balance is
Charged. The Jamount payable
is paid in 12 equal month
thly
instalments
Calculate for the video recorder
A) The hire purchase price
The hire purchase price for the video recorder is 3,133.20.
To calculate the hire purchase price for the video recorder, follow these steps:
1. Calculate the initial deposit: 20% of the cash price (2,700) is (0.20 * 2,700) = 540.
2. Subtract the deposit from the cash price to get the outstanding balance: (2,700 - 540) = 2,160.
3. Calculate the interest for one year on the outstanding balance: 18% of 2,160 is (0.18 * 2,160) = 388.80.
4. Divide the interest by 12 to find the interest per month: (388.80 / 12) = 32.40.
5. Add the interest per month to the outstanding balance: (2,160 + 32.40 * 12) = 3,133.20.
6. The hire purchase price is 3,133.20, which is the total amount payable in 12 equal monthly instalments.
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Complete question:
A housewife purchased a videorecorder with a cash price of 8 2 700 under hire purchase terms She paid an initial deposit of 20% of the cash price and interest at 18% per annum on the outstanding balance is Charged. The Jamount payable is paid in 12 equal monththly instalments Calculate for the video recorder The hire purchase price
(1 point) Consider a piece of wire with uniform density. It is the quarter of a circle in the first quadrant. The circle is centered at the origin and has radius 5. Find the centroid (cy) of the wire. =y= (1 point) Compute the total mass of a wire bent in a quarter circle with parametric equations: 2 = 9 cost, y=9 sint, 0
The total mass of the wire is [tex]M = 9\rho * (\pi/2).[/tex]
How to find the total mass of the wire?Using the formula for finding the centroid of a two-dimensional object with uniform density:
cy = (1/Area) * ∫(y*dA)
The equation of the circle is [tex]x^2 + y^2 = 25[/tex]. Solving for y, we get:
[tex]y = \sqrt(25 - x^2)[/tex]
Since the wire is in the first quadrant, the limits of integration are 0 ≤ x ≤ 5 and 0 ≤ y ≤ [tex]\sqrt(25 - x^2).[/tex]
To find the area of the wire, we integrate:
[tex]Area = \int \int dA = \int 0^5 \int 0^{\sqrt(25-x^2)}dy dx[/tex]
[tex]= \int 0^{5 (sqrt(25-x^2))}dx[/tex]
[tex]= (1/2) * [25sin^{(-1)(x/5)} + x\sqrt(25-x^2)] from 0 to 5[/tex]
[tex]= (1/2) * [25\pi/2] = 25\pi/4[/tex]
To find the centroid (cy), we integrate:
[tex]cy = (1/Area) * \int(ydA) = (1/(25\pi/4)) * \int0^5 \int0^{\sqrt(25-x^2)} y dy dx[/tex]
[tex]= (4/25*\pi) * \int0^5 [(1/2)*y^2]_0^{\sqrt(25-x^2)} dx[/tex]
[tex]= (4/25\pi) * \int 0^5 [(1/2)(25-x^2)] dx[/tex]
[tex]= (4/25\pi) * [(25x - (1/3)*x^3)/2]_0^5[/tex]
[tex]= (4/25\pi) * [(255 - (1/3)*5^3)/2][/tex]
[tex]= 50/3[/tex]
Therefore, the centroid of the wire is cy = 50/3.
Now use the formula for the mass of a thin wire for total mass:
M = ∫ρ ds
Since the wire has uniform density, the linear density is constant and can be factored out of the integral:
M = ρ * ∫ds
The differential element of arc length is:
[tex]ds = \sqrt(dx^2 + dy^2) = \sqrt((-9sin t)^2 + (9cos t)^2) dt[/tex]
[tex]= 9\sqrt(sin^2 t + cos^2 t) dt = 9 dt[/tex]
Integrating from 0 to pi/2, we get:
[tex]M = \rho * \int ds = \rho * \int 0^{(\pi/2)} 9 dt[/tex]
[tex]= 9\rho * [t]_0^{(\pi/2)} = 9\rho * (\pi/2)[/tex]
Therefore, the total mass of the wire is [tex]M = 9\rho * (\pi/2).[/tex]
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Write the absolute value in the form x-b=c where b is a number and c can be either number or expression
The absolute value of x can be written in the form
x-(1/2)x=0 or |x| = (1/2)x
To write the absolute value in the form x-b=c where b is a number and c can be either a number or expression, you can use the following steps:
1. Start with the absolute value expression: |x|
2. Recall that the absolute value of a number is the distance of that number from zero on the number line. So, we can rewrite |x| as the distance between x and 0 on the number line.
3. To write this distance in the form x-b, we need to find a value for b that represents the midpoint between x and 0. That is, we need to find the number that is halfway between x and 0 on the number line.
4. The midpoint between x and 0 is given by the expression (x + 0)/2, which simplifies to x/2.
5. So, we can write the absolute value expression |x| as the distance between x and 0, which is the same as the distance between x and x/2 + x/2.
6. Simplifying this expression, we get:
|x| = |x - x/2 - x/2|
7. Rearranging terms, we get:
|x| = |(1/2)x - (1/2)x|
8. Finally, we can write the absolute value in the form x-b=c by setting b = (1/2)x and c = 0, which gives us:
|x| = |x - (1/2)x - 0| = |(1/2)x - 0|
So, the absolute value of x can be written in the form x-(1/2)x=0, or in other words:
|x| = (1/2)x
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21. How many times larger is the volume of a cone if the height is multiplied by 3?
Answer:
If the height is tripled and the radius remains constant, then the volume will be tripled or multiplied by 3.
Step-by-step explanation:
An example proving this:
Fill the cones with water and empty out one cone at a time. Each cone fills the cylinder to one-third quantity. Hence, such three cones will fill the cylinder. Thus, the volume of a cone is one-third of the volume of the cylinder.
So, the height is divided by three in the volume formula. Therefore, it is to be proven that if the height of a cone is tripled and the radius remains constant, the volume would also be tripled.
Lily's age is 2 years and 4 months.
Hugo's age is 1 year and 8 months.
Write Lily's age in months as a fraction of Hugo's age in months.
Give your answer in it's simplest form.
Answer:
7/5
Step-by-step explanation:
Lily's age in months: 2×12+4=28mo
Hugo's age in months=12+8=20
Lily's age over Hugo's age: 28/20
Simplify:
28/20=14/10=7/5
According to "7-Year-Old Girl Gets New Hand from 3-D Printer," which is the best explanation of why Faith needs a prosthetic hand?
She needs extra help holding onto paper, bicycle handlebars, and other objects.
She has been waiting for the opportunity to design her own hand.
The waiting list was too long for other types of treatment.
She lost her left hand due to a condition at birth
Faith needs a prosthetic hand because she lost her left hand at birth and requires assistance holding objects.
Why does Faith need a prosthetic hand in "7-Year-Old Girl Gets New Hand from 3-D Printer"?According to the article "7-Year-Old Girl Gets New Hand from 3-D Printer," Faith is a young girl who was born with a condition that caused her to lose her left hand. As a result, she has difficulty holding onto objects such as paper and bicycle handlebars. Faith had been waiting for an opportunity to design her own prosthetic hand, but the waiting list for other types of treatment was too long. Fortunately, a team of students and educators at a local university were able to create a prosthetic hand for her using a 3-D printer. The new hand will allow Faith to have greater independence and mobility, and she is excited to be able to participate in activities she was previously unable to do. This story is an example of how technology can be used to improve the lives of individuals with disabilities and provide them with greater opportunities to participate fully in everyday life.
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8-40.
For the triangle at right, write each of the following trigonometric ratios. The first one is done for you.
Answer:
tan A: BC/AB
cos A: AB/AC
sin C: AB/AC
cos C: BC/AC
sin A: BC/AC
Step-by-step explanation:
sin of an angle: opposite/hypotenuse
cosine of an angle: adjacent/hypotenuse
tangent of an angle: opposite/adjacent
Select the correct answer.
In a sequence described by a function, what does the notation f(3) = 1 mean?
O A.
The third term in the sequence has a value of 1.
OB.
The first term in the sequence has a value of 3.
OC. The common difference of the sequence is 3.
OD. The common ratio of the sequence is 3.
The third term in the sequence has a value of 1.
Here, we have,
Sequence
Given:
f(3) = 1
Let f(x) b a function.
Here x is replaced by "3", f(3) represents the value of the 3rd term of the function, which is 1.
In this case f(3) = 1 means the value of a member of the sequence when x = 3 is 1.
For example, if the sequence is the values of x^2-8 from 1 to infinity, then f(1) would have a value 1-8 = -7 and f(3) would be 9- 8 = 1
The third term in the sequence has a value of 1.
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Pls help me with this!! 5 pts and brainliest included for the one who answers first!
Answer:
Step-by-step explanation:
Take the natural logarithm of both sides of the equation to remove the variable from the exponent. ln(e−6w)=ln(952) ln ( e - 6 w ) = ln ( 95 2 ).
I Need help with these please answer someone omg
Step-by-step explanation:
suppose 2 more variable y and z
12. [0/1 Points] DETAILS PREVIOUS ANSWERS LARCALC9 11.7. Convert the point from rectangular coordinates to spherical coordinates. (7,7, 2/7) (0, 0, 4) = ( 3V 14, 7,61.87 ). x Submit Answer
The spherical coordinates for the given rectangular coordinates (7, 7, 2/7) are (ρ, θ, φ) = (10, 45°, 88.57°) or (10, π/4, 1.545) in radians.
We'll need to find ρ (rho), θ (theta), and φ (phi) using the given rectangular coordinates (x, y, z). Here's the step-by-step process:
1. Calculate ρ (rho): ρ is the distance from the origin to the point in 3D space. You can find it using the formula: ρ = √(x² + y² + z²)
In this case, x = 7, y = 7, and z = 2/7.
Plugging these values into the formula: ρ = √(7² + 7² + (2/7)²) ρ = √(49 + 49 + 4/49) ρ = √(98 + 4/49) ρ = √(4900/49) ρ = 10
2. Calculate θ (theta): θ is the angle in the xy-plane, measured from the positive x-axis. You can find it using the formula: θ = arctan(y/x)
In this case, x = 7 and y = 7.
Plugging these values into the formula: θ = arctan(7/7) θ = arctan(1) θ = 45° (in degrees) or π/4 (in radians)
3. Calculate φ (phi): φ is the angle between the positive z-axis and the line connecting the origin to the point. You can find it using the formula: φ = arccos(z/ρ)
In this case, z = 2/7 and ρ = 10.
Plugging these values into the formula: φ = arccos((2/7)/10) φ = arccos(1/35) φ ≈ 88.57° (in degrees) or ≈ 1.545 (in radians)
So, the spherical coordinates for the given rectangular coordinates (7, 7, 2/7) are (ρ, θ, φ) = (10, 45°, 88.57°) or (10, π/4, 1.545) in radians.
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Ello beautiful people how are you doing today and wyd this weekend
Hello beautiful people! I hope you're all doing well today. As for me, I'm feeling great and ready for the weekend! I plan on spending some quality time with my loved ones, exploring new places, and trying out new activities.
I believe that weekends are meant for rest, relaxation, and rejuvenation, so I'm looking forward to taking a break from my busy work schedule.
One of the things I love about weekends is the opportunity to disconnect from the stresses of everyday life and focus on things that bring me joy. Whether it's going for a hike, trying out a new recipe, or catching up with friends over a cup of coffee, there's always something to look forward to.
this weekend I plan on making the most of my free time by doing things that make me happy and help me recharge. I hope you all have a great weekend as well, and that you find time to do the things you love with the people you care about. Remember, life is short, so let's make the most of every moment we have!
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Classify the following expression by degree and term: (2 points)x2y − 7xy + xyz + x2nd degree polynomial7th degree polynomial2nd degree trinomial3rd degree polynomial
The given expression x²y − 7xy + xyz is a 3rd degree polynomial.
To classify it by degree and term, let's first determine the degree of each term:
1. x²y: The degree is the sum of the exponents of the variables (x and y). Here, the degree is 2 (from x²) + 1 (from y) = 3.
2. 7xy: The degree is 1 (from x) + 1 (from y) = 2.
3. xyz: The degree is 1 (from x) + 1 (from y) + 1 (from z) = 3.
Now, we can classify the expression:
- Degree: Since the highest degree among the terms is 3, the expression is a 3rd-degree polynomial.
- Term: There are three terms in the expression, so it is a trinomial.
In summary, the given expression, x²y − 7xy + xyz, is a 3rd-degree trinomial.
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Joseph measures the ropes to tie boats to a dock. He records the lengths of the ropes in feet and then makes a line plot. Joseph concludes that the difference between the longest and shortest lengths is 2 1/2 feet. Martha disagrees and says that the difference is only 1 foot who is correct? no links please
Without the line plot or the actual measurements of the ropes, it is difficult to determine who is correct.
Joseph measures the lengths of ropes used to tie boats to a dock in feet and creates a line plot. He then concludes that the difference between the longest and shortest lengths is 2 1/2 feet. Martha disagrees with Joseph's conclusion and argues that the difference is only 1 foot.
To determine who is correct, we need to analyze the line plot and examine the data. If the line plot shows that the ropes vary greatly in length, with some being significantly longer than others, then Joseph's conclusion of a 2 1/2 foot difference could be accurate. However, if the line plot shows that the ropes are relatively similar in length, with only slight variations, then Martha's conclusion of a 1 foot difference could be correct.
Without the line plot or the actual measurements of the ropes, it is difficult to determine who is correct. Therefore, it is important to always examine the data before making conclusions.
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: Ben practises playing the Oboe daily.
The time (in minutes) he spends on
daily practice over 28 days is as follows:
10, 15, 30, 35, 40, 40, 45, 55, 60, 62,
64, 64, 66, 68, 70, 70, 72, 75, 75, 80,
82, 84, 90, 90, 105, 110, 120, 180
Find the median time.
Find the lower quartile.
Find the upper quartile.
Find the range.
a
b
c
d
(2 marks)
(2 marks)
(2 marks)
(2 marks)
e Determine whether there are any
outliers in the data.
(4 marks)
f Draw a box-and-whisker
the above data.
diagram for
(3 marks)
The values of given conditions are:
1. median=70
2. Lower quartile=40
3. Upper quartile=87
4. Range=170
5. IQR=47
6. Lower outlier threshold=-20.5
7. Upper outlier threshold=160.5
What is median?In statistics, the median is the value separating the higher half from the lower half of a dataset. In other words, it is the middle value of a dataset when it is ordered in ascending or descending order.
Here,
To find the median time, we need to arrange the data in order from least to greatest and find the middle value.
10, 15, 30, 35, 40, 40, 45, 55, 60, 62, 64, 64, 66, 68, 70, 70, 72, 75, 75, 80, 82, 84, 90, 90, 105, 110, 120, 180
There are 28 values in the data set, so the median is the average of the 14th and 15th values:
Median = (70 + 70)/2
= 70
To find the lower quartile, we need to find the median of the lower half of the data set:
10, 15, 30, 35, 40, 40, 45, 55, 60, 62, 64, 64, 66, 68
There are 14 values in the lower half, so the lower quartile is the median of these values:
Lower quartile = (40 + 40)/2
= 40
To find the upper quartile, we need to find the median of the upper half of the data set:
72, 75, 75, 80, 82, 84, 90, 90, 105, 110, 120, 180
There are 14 values in the upper half, so the upper quartile is the median of these values:
Upper quartile = (84 + 90)/2
= 87
To find the range, we subtract the smallest value from the largest value:
Range = 180 - 10
= 170
To determine if there are any outliers in the data set, we need to calculate the interquartile range (IQR):
IQR = Upper quartile - Lower quartile
= 87 - 40
= 47
Any value that is more than 1.5 times the IQR below the lower quartile or above the upper quartile is considered an outlier.
Lower outlier threshold = Lower quartile - 1.5IQR
= 40 - 1.547
= -20.5
Upper outlier threshold = Upper quartile + 1.5IQR
= 87 + 1.547
= 160.5
To draw a box-and-whisker plot, we need to plot a box from the lower quartile to the upper quartile, with a line inside the box representing the median. We then draw whiskers extending from the box to the smallest and largest values that are not outliers. The box extends from 40 to 87, with a line at 70 representing the median. The whisker on the left extends to the smallest non-outlier value of 10, and the whisker on the right extends to the largest non-outlier value of 120.
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A cube is cut into two pieces by a single slice that passes through the points A, B, and C.
What shape is the cross section.
1. Rectangle
2. Triangle
3. Square
4. Trapezoid
The correct option is (2) triangle, because the slice intersects the cube face at three non-collinear points.
How many edges does a cube have?When a cube is cut by a single slice passing through three non-collinear points on a face, the shape of the cross section will be the intersection of the slice with the cube face. In this case, the slice passes through points A, B, and C, which are non-collinear, and thus the shape of the cross section will be a triangle.
This is because a triangle is the only shape that can be formed by the intersection of a plane with three non-collinear points on a flat surface, such as the face of a cube. The other options of rectangle, square, and trapezoid are not possible since they cannot be formed by the intersection of a plane with three non-collinear points on a flat surface.
A rectangle can only be formed by the intersection of a plane with four points that form a right angle, a square can only be formed by the intersection of a plane with four points that form a right angle and are equidistant from each other, and a trapezoid can only be formed by the intersection of a plane with four points that are not collinear, but only two of which are parallel.
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Sarah has a solid wooden cube with a length of 4/5 cm. From each of its 8 corners, she cuts out a smaller cube with a length of 1/5 cm. What is the volume of the block after cutting out the smaller cubes?
The volume of the block after cutting out the smaller cubes is 56/125 cubic centimeters.
The initial volume of the solid wooden cube is given by:
V_initial = (4/5 cm)³ = 64/125 cm³
To find the volume of each of the 8 smaller cubes cut out from the corners, we can use the formula:
V_small cube = (1/5 cm)³= 1/125 cm³
Since we cut out 8 smaller cubes, the total volume of the smaller cubes is:
V_small cubes = 8 x (1/125 cm³) = 8/125 cm³
To find the final volume of the block after cutting out the smaller cubes, we can subtract the volume of the smaller cubes from the initial volume of the block:
V_final = V_initial - V_small cubes
Substituting the values we obtained earlier, we get:
V_final = (64/125 cm³) - (8/125 cm³) = 56/125 cm³
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Randomly meeting a -child family with either exactly one or exactly two children
Considering the function f(x) = x(x-4), if the point (2+c, y) is on the graph of f(x), then the following point will also be on the graph of f(x): (2-c, y). Explanation: Since f(x) is symmetric with respect to the vertical line x = 2 (due to the fact that f(x) = x(x-4) = (x-2+2)(x-2) = (x-2)^2 - 2^2), if the point (2+c, y) is on the graph, then its symmetric counterpart, (2-c, y), will also be on the graph.
About functionThe definition of a function in mathematics can also be interpreted as a relation that connects each member of x in a set called the domain with a single value f(x) from a second set called the codomain.
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(a) Find the size of angle PQR. Reason (b) Find the size of angle PRQ. Reason (c) Find the size of angle POQ.. Reason
Answer:
a) Angle PQR=90 degrees
b) Angle PRQ=56 degrees
c) Angle POQ=112 degrees
Step-by-step explanation:
a) Angle PQR=90 degrees
reason: the angle in a semicircle is 90°
b) Angle PRQ=56 degrees
reason: angles in same segment of a circle are equal, so far, the segment PQ is common for angles PSQ and PRQ. Therefore, PRQ is 56 degrees.
c) Angle POQ=112 degrees
Reason: isosceles triangle