The resistance of a wire of a circular cross-section will be nine times higher when the length and diameter are both tripled.
To calculate the resistance:
So, when the length and diameter are both tripled, the resistance will be nine times higher.
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true or false? a constructor which has thrown an exception will also return a reference to its constructed object.
The given statement a constructor which has thrown an exception will also return a reference to its constructed object is false because when an exception is thrown during the construction of an object, the constructor does not complete its initialization process.
As a result, the constructed object may be in an invalid or partially constructed state, which can lead to unexpected behavior if the object is used later in the program. A constructor cannot return a value, not even a reference to its constructed object. Instead, the constructor initializes the object's data members and sets up the object's state. If a constructor throws an exception, the object is not fully constructed and is therefore not valid. The exception can be caught and handled by the caller of the constructor.
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if you accidentally grabbed the prongs of a partially plugged-in 120-v electrical plug on a day when your skin resistance was 130,000 ohms, how much current would pass through your body?
The current that would pass through the body is 0.92 A.
Current is a measure of the rate of flow of electric charge in a circuit and is measured in amperes (A). Ohm's law describes the relationship between voltage, current, and resistance in an electrical circuit.
Using Ohm's Law, the current that would pass through the body can be calculated as:
I = V/R, where V is the voltage and R is the resistance.
In this scenario,
V = 120 V
R = 130,000 ohms
Substituting these values in the formula, we get:
I = 120 V / 130,000 ohms = 0.92 A.
Therefore, approximately 0.92 amperes (or 920 milliamperes) of current would pass through the body.
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A 2 kg mass moving to the right makes an elastic head-on collision with a 4 kg mass moving to the left at 4 m/s. The 2 kg mass reverses direction after the collision and moves at 3 m/s. The 4 kg mass moves to the left at 1 m/s. What was the initial velocity of the 2 kg mass?
Answer: That's a good question
Explanation:
numerade a constant 10-n horizontal force is applied to a 20-kg cart at rest on a level floor. if friction is negligible, what is the speed of the cart when it has been pushed 8.0 m?
The speed of the cart is 4.0 m/s.
step by step explanation:
Force F is 10-N,
Distance d is 8.0-m, and
Mass m is 20-kg,
A constant 10-N horizontal force is applied to a 20-kg cart at rest on a level floor.
If friction is negligible, then the speed of the cart when it has been pushed 8.0 m can be calculated using the equation v = Fd/m,
where v is the speed of the cart,
F is the applied force,
d is the distance, and
m is the mass of the cart.
so the speed of the cart is v = (10 N × 8.0 m) / 20 kg = 4.0 m/s.
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2. how many times a minute does a boat bob up and down on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s?
The boat will bob up and down on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s once every 7.50 seconds.
To solve the given question, we must use the formula:
n= v/f
Where: v is the velocity of the wave (in m/s)f is the frequency of the wave (in Hz)n is the number of cycles per second
Therefore, the frequency of the wave (in Hz) can be calculated by using the formula:
f= v/λ
where: v is the velocity of the wave (in m/s)λ is the wavelength of the wave (in m)
The frequency of the wave is 0.1333 Hz (approx).
Now, the number of cycles per second (n) is: n = v/λ
We can solve for n by dividing the velocity of the wave by the wavelength of the wave.
Therefore,
n= v/λ= (4.80 m/s) / (36.0 m)= 0.1333 Hz
So, the boat bob up and down 0.1333 times a minute on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s.
1 Hz = 60 seconds,
0.1333 Hz = 7.50 seconds.
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what quantity describes the ability of a force to rotate an object? how does it differ from a force? on what quantities does it depend?
The quantity that describes the ability of a force to rotate an object is torque. It differs from a force in that it is a rotational force, not a linear force. Torque depends on the force applied and the distance from the point of application to the pivot point.
Torque is the measure of the ability of a force to cause rotational motion. It is defined as the product of the force and the distance between the point of application of the force and the pivot point or axis of rotation. Unlike a linear force, which produces linear motion, a torque produces rotational motion. The unit of torque is the newton-meter (N·m) in the SI system.
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a bullet of mass 0.010 kg and speed of 100 m/s is brought to rest in a wooden block after penetrating a distance of 0.10 m. this process takes 0.02 second. the magnitude of the impulse delivered to the bullet by the block during this time is
The magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
The mass of the bullet is given as 0.010 kg and its initial speed as 100 m/s. After travelling 0.10 m, the bullet comes to rest in a wooden block. The time taken for the bullet to stop is 0.02 seconds. We need to calculate the magnitude of the impulse delivered to the bullet by the block during this time. We can use the formula for impulse, which is Impulse = Force × Time. Impulse is defined as the change in momentum. Thus, we can use the equation m₁v₁ - m₁v₂ = F×t , where m₁ is the mass of the bullet, v₁ is the initial speed of the bullet, v₂ is the final velocity of the bullet, t is the time for which the force acts, and F is the force applied on the bullet. In this case, we know the mass and initial speed of the bullet. We need to find the final velocity of the bullet to calculate the force. We can use the formula for final velocity, which is v₂ = u + at , where u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. Here, the force acting on the bullet is the force of the wooden block, and the acceleration is given by a = F/m₁ . Thus, we have v₂ = u + F/m₁ × t . The distance travelled by the bullet is given as 0.10 m. We can use the formula for distance travelled, which is s = ut + ½at² . Here, s is the distance travelled by the bullet, u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. We have u = 100 m/s, s = 0.10 m, and t = 0.02 s. We can use this equation to calculate the acceleration of the bullet. Solving for a, we get a = (2s - ut) / t² = (2 × 0.10 - 100 × 0.02) / (0.02)² = -450 m/s². Here, the negative sign indicates that the acceleration is in the opposite direction to the velocity of the bullet. Substituting this value of a in the equation for v₂, we get v₂ = 100 - 450 × 0.02 / 0.010 = 10 m/s. Thus, the change in velocity of the bullet is Δv = v₂ - v₁ = 10 - 100 = -90 m/s. The magnitude of the impulse delivered to the bullet by the block during this time is |Impulse| = m₁ × |Δv| = 0.010 × 90 = 0.90 Ns. Therefore, the magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.
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Please help me, been trying to figure it out but I cant.
what's the field strength on the loop axis at 10.0 cm from the loop center? express your answer in microtesla.
The field strength on the loop axis at 10.0 cm from the loop center is 0.01 microtesla.
The field strength on the loop axis at 10.0 cm from the loop center can be calculated using Ampere's law, which states that the integral of the magnetic field around a closed loop is equal to the total current passing through the loop. The field strength at a distance from the loop center is inversely proportional to the square of the distance from the loop center. Thus, the field strength on the loop axis at 10.0 cm from the loop center is inversely proportional to 10.0 cm^2 or 100 cm^2, which is equal to 0.01 microtesla.
To explain further, the magnetic field strength is the force per unit charge at a particular point in space. It is a vector quantity, and its direction is perpendicular to the loop plane. The strength of the magnetic field is affected by the radius of the loop, the number of turns in the loop, and the current passing through the loop. The magnetic field strength is inversely proportional to the square of the distance from the loop center, so the field strength on the loop axis at 10.0 cm from the loop center is 0.01 microtesla.
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a 75 kg skydiver is falling through air with a drag coefficient of 0.6. what is his terminal speed as he falls feet first?
The terminal speed of the skydiver as he falls feet first would be 54.9 m/s.
Terminal speed calculationTo find the terminal velocity of the skydiver, we need to balance the forces acting on him. At terminal velocity, the force of air resistance (also known as drag) is equal and opposite to the force of gravity. This means that the net force on the skydiver is zero and his velocity remains constant.
The force of air resistance is given by:
F_drag = (1/2) * rho * v^2 * C_d * A
where:
rho is the density of air (about 1.2 kg/m^3 at sea level)
v is the velocity of the skydiver
C_d is the drag coefficient (0.6 in this case)
A is the cross-sectional area of the skydiver
The force of gravity on the skydiver is given by:
F_gravity = m * g
where:
m is the mass of the skydiver (75 kg in this case)
g is the acceleration due to gravity (9.81 m/s^2)
At terminal velocity, F_drag = F_gravity, so we can set the two equations equal to each other:
(1/2) * rho * v^2 * C_d * A = m * g
Solving for v, we get:
v = sqrt((2 * m * g) / (rho * C_d * A))
Substituting in the values given, we get:
v = sqrt((2 * 75 kg * 9.81 m/s^2) / (1.2 kg/m^3 * 0.6 * 1.5 m^2))
v = 54.9 m/s
Therefore, the terminal speed of the skydiver is about 54.9 m/s when falling feet first with a drag coefficient of 0.6.
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a cleaner pushes a 3.1-kg laundry cart in such a way that the net external force on it is 63 n. calculate the magnitude of its acceleration in m/s2.
Answer: The magnitude of the acceleration of the laundry cart is 20.32 m/s2.
The magnitude of the acceleration of the laundry cart can be calculated using the equation F = ma, where F is the force applied, m is the mass of the object and a is the acceleration.
We can rearrange the equation to solve for acceleration: a = F/m.
Plugging in the values we know, the acceleration of the laundry cart is:
a = 63N / 3.1kg = 20.32 m/s2
Therefore, the magnitude of the acceleration of the laundry cart is 20.32 m/s2.
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water travels through a 9.6 cm diameter fire hose with a speed of 1.3 m/s. at the end of the hose, the water flows out through a nozzle whose diameter is 2.5 cm. what is the speed of the water coming out of the nozzle?
The speed of the water coming out of the nozzle is 19.2 m/s. The result is obtained by using the formula for volumetric flow rate.
How to count the water flow rate in pipes of different diameters?The speed of the water coming out of the nozzle can be calculated using the flow rate equation. This equation states that the flow rate of a fluid passing through a constant cross-sectional area is constant, meaning that the water coming out of the nozzle must have the same flow rate as it did when it entered the hose.
Q₁ = Q₂
A₁v₁ = A₂v₂
We have
Determine v₂!
While A is the cross-sectional area of the hose and nozzle, it can be find by πr², where r = ½d.
Using the formula above, we get:
πr₁² × v₁ = πr₂² × v₂
(½(9.6))² × 1.3 = (½(2.5))² × v₂
23.04 × 1.3 = 1.562 × v₂
v₂ = 19.2 m/s
Hence, the speed of the water coming out of the nozzle is 19.2 m/s.
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An m= 68.0 kg person running at an initial speed of
v = 4.10 m/s jumps onto an M=136 kg cart initially at rest. The person slides on the cart's top surface and finally comes to rest relative to the cart. The coefficient of kinetic friction between the person and the cart is 0.420 . Friction between the cart and can be ignored. (Let the positive direction be to the right)
(a) Find the final velocity of the person and cart relative to the ground. (Indicate the direction with the sign of your answer.) ______ m/s
(b) Find the friction force acting on the person while he is sliding across the top surface of the cart. (Indicate the direction with the sign of your answer.)
______ N
(c) How long does the friction force act on the person? ______ s (d) Find the change in momentum of the person. (Indicate the direction with the sign of your answer.)
______ N⋅s
Find the change in momentum of the cart. (Indicate the direction with the sign of your answer.)
______ N⋅s
(e) Determine the displacement of the person relative to the ground while he is sliding on the cart. (Indicate the direction with the sign of your answer.) ______ m (f) Determine the displacement of the cart relative to the ground while the person is sliding. (Indicate the direction with the sign of your answer.) ______ m (g) Find the change in kinetic energy of the person. ______ J (h) Find the change in kinetic energy of the cart.
Explain why the answers to (g) and (h) differ. (What kind of collision is this one, and what accounts for the loss of mechanical energy?)
(a) The final velocity of the person and cart relative to the ground is 0 m/s.
(b) The friction force acting on the person while he is sliding across the top surface of the cart is -28.96 N, acting in the negative direction.
(c) The friction force acts on the person for a time of 1.50 s.
(d) The change in momentum of the person is -103.2 N⋅s, acting in the negative direction.
(e) The displacement of the person relative to the ground while he is sliding on the cart is 6.07 m, acting in the positive direction.
(f) The displacement of the cart relative to the ground while the person is sliding is 3.03 m, acting in the positive direction.
(g) The change in kinetic energy of the person is -128.8 J.
(h) The change in kinetic energy of the cart is -64.4 J.
This is an inelastic collision, meaning that the kinetic energy of the system is not conserved. This is because some of the kinetic energy is lost to friction as the person slides across the cart's surface. As the person has a greater mass than the cart, the change in kinetic energy of the person is greater than that of the cart. The total kinetic energy of the system is thus decreased, as the person and cart come to rest relative to each other.
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how much will the temperature increase if this amount of heat energy is transferred to the gas at constant volume? express your
To determine the temperature increase if a specific amount of heat energy is transferred to the gas at a constant volume, we will use the equation:
Q = nCvΔT,
where Q is the amount of heat energy transferred, n is the number of moles of gas, Cv is the heat capacity at a constant volume, and ΔT is the temperature change.
The expression to determine the temperature change is:
ΔT = Q / (nCv)
where ΔT is the change in temperature, Q is the amount of heat energy transferred, n is the number of moles of gas, Cv is the specific heat capacity at constant volume.
For this case, the formula to calculate the change in temperature if a certain amount of heat energy is transferred to the gas at constant volume is given by:
ΔT = Q / (nCv)
Where; ΔT = temperature change, n = number of moles of gas, Cv = specific heat capacity at constant volume, Q = amount of heat energy transferred.
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you have learned that in the earth-moon system, the gravitational pull of earth's tidal bulges causes the moon to spiral away from earth. since triton has a retrograde orbit, how does this affects the neptune-triton system?
You have learned that in the earth-moon system, the gravitational pull of earth's tidal bulges causes the moon to spiral away from earth. since triton has a retrograde orbit, this affects the neptune-triton system to be unstable, making it difficult for the other moons to maintain stable orbits.
Triton is a large moon of Neptune, about 1,680 miles (2,700 kilometers) in diameter. Its orbit is tilted and is also in the opposite direction of the other moons in the solar system's plane. Triton's orbit is retrograde, which means it is moving in the opposite direction to Neptune's rotation. When an object orbits in the opposite direction to the rotation of the planet it orbits, it is said to have a retrograde orbit. This is because the gravitational attraction between the two objects is weaker when they are moving in opposite directions. Because of this, Triton's retrograde orbit has a destabilizing effect on Neptune's other satellites.
The retrograde orbit of Triton causes the Neptune-Triton system to be unstable, making it difficult for the other moons to maintain stable orbits. The gravitational force of Triton is pulling away at the other moons, causing them to move erratically, some being pushed further away from Neptune and others being pulled closer. In addition to the destabilizing effect, Triton's retrograde orbit has caused it to move closer to Neptune over time, where it is thought that it will eventually break apart, forming a ring around the planet.
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Watch the Neocrystallization topic of the Metamorphic Change Animation. The protolith of the rock undergoing neocrystallization is a mudstone. As metamorphism proceeds, it is turned into a metamorphic rock called a schist. Based on what you can see in the animation, which of the following occur(s) during this transition? Choose one or more: O A. Neocrystalline garnets form. OB. Existing minerals become elongated and take on a foliation. O C. Existing minerals shrink in length. O D. Existing minerals undergo plastic deformation. E. Neocrystalline garnets are compressed.
The Neocrystallization topic of the Metamorphic Change Animation options are A (Neocrystalline garnets form), B(Existing minerals become elongated and take on a foliation), and D. (Existing minerals undergo plastic deformation. E. Neocrystalline garnets are compressed.)
Based on the information provided, during the transition of mudstone to schist through neocrystallization:
A. Neocrystalline garnets form - This occurs as new minerals, like garnets, form during the metamorphic process.
B. Existing minerals become elongated and take on a foliation - As the mudstone undergoes metamorphism, the existing minerals align and elongate, developing a foliation.
D. Existing minerals undergo plastic deformation - During metamorphism, pressure and temperature changes cause the minerals to undergo plastic deformation, changing their shape and size.
Based on the Neocrystallization topic of the Metamorphic Change Animation, the following occur during the transition of mudstone to schist: - Existing minerals become elongated and take on a foliation - Neocrystalline garnets form Therefore, options A and B are the correct answers.
So, the correct options are A, B, and D.
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(6) As the aeroplane travels away from the airport; it sends signal to the airport uslng radio waves wlth wavelength of 1,2m: When the signal Is received at the alrport; the wavelength Is 1.1 x 10"m longer than when It Is emitted by the aeroplane: Calculate the speed of the aeroplane using the formula change of wavelength speed of aeroplane wavelength speed of radlo wave [speed of radio waves = 3.0x 10" m/s] speed of aeroplane m/s (Total for Questlon 5 6 marks)
The problem involved calculating the speed of an airplane using the change in wavelength of radio waves it emits. By using the formula and substituting the given values, we found that the speed of the airplane is 2.5 x 10^5 m/s.
The given information can be summarized as:
The wavelength of the radio wave emitted by the airplane = λ_emitted = 1.2 m
The wavelength of the radio wave received at the airport = λ_received = λ_emitted + 1.1 x 10^-6 m
The speed of the radio wave = v_wave = 3.0 x 10^8 m/s
We can use the formula given in the problem to find the speed of the airplane:
change of wavelength = speed of airplane x wavelength / speed of radio wave
Substituting the given values, we get:
λ_received - λ_emitted = speed of airplane x λ_emitted / v_wave
Simplifying and solving for the speed of the airplane, we get:
speed of airplane = (λ_received - λ_emitted) x v_wave / λ_emitted
Plugging in the values, we get:
speed of airplane = (1.2 + 1.1 x 10^-6 - 1.2) x 3.0 x 10^8 / 1.2
speed of airplane = 2.5 x 10^5 m/s
Therefore, the speed of the airplane is 2.5 x 10^5 m/s.
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the time interval between flashes on a strobe light is 1/70th of a second. what is the frequency of these flashes.
(Use f=time/vibe)
Show work
The strobe light's flashes occur at a 70 Hz frequency.
What frequency does sound have?The frequency of a sound pressure wave, also known as pitch, is the quantity of times every second that it repeats. A bullfrog cry is far downward communication than a whistle, while a cricket is much downward communication than a drum beat.
To calculate the flash frequency, use the formula below.:T is the amount of time between flashes in seconds, and f is the frequency expressed in Hertz (Hz).We obtain the following value by inserting the given value: f = 1 / (1/70) f = 70 Hz.
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a 25 kg iron block that is initially at 350 c is dropped into an insulated tank that contains 100 kg of water at 18 c. no water changes phase or leaves the tank in the process. determine the total entropy change during this process. the cp,water
The total entropy change during this process is, -16.4 J/°C.
To determine the total entropy change during this process, we need to consider both the entropy change of the iron block and the entropy change of the water in the tank. We can assume that the entire process is adiabatic (i.e., no heat transfer occurs between the system and the surroundings), so the total entropy change of the system is zero.
The entropy change of the iron block can be calculated as,
ΔS_iron = m × Cp_iron × ln(T_f / T_i)
where m is the mass of the iron block, Cp_iron is the specific heat capacity of iron, T_f is the final temperature of the iron block, and T_i is the initial temperature of the iron block.
Assuming that the final temperature of the iron block is the same as the temperature of the water in the tank (i.e., 18°C), we can calculate the entropy change of the iron block as,
ΔS_iron = 25 kg × 0.45 J/g°C × ln(18°C / 350°C)
≈ -16.4 J/°C
The entropy change of the water in the tank can be calculated as,
ΔS_water = m × Cp_water × ln(T_f / T_i)
where m is the mass of the water in the tank, Cp_water is the specific heat capacity of water, T_f is the final temperature of the water, and T_i is the initial temperature of the water.
Assuming that the iron block and the water reach a final temperature of 18°C, we can calculate the entropy change of the water as,
ΔS_water = 100 kg × 4.18 J/g°C × ln(18°C / 18°C)
= 0 J/°C
Therefore, the total entropy change during this process is,
ΔS_total = ΔS_iron + ΔS_water
≈ -16.4 J/°C + 0 J/°C
≈ -16.4 J/°C
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do you think that sometimes even if all the trackers are green, they might produce the wrong camera solve/calibration?
Yes, sometimes even if all the trackers are green, they might produce the wrong camera solve/calibration.
The green tracker status indicates that the tracker is properly tracked, but it does not guarantee the accuracy of the camera solve. Various factors could lead to an incorrect camera solve.
One of the primary factors is improper tracking. In some cases, a tracker may seem to be in the right position, but the camera solver could generate an inaccurate camera solve if the tracker is not in the appropriate location on the image. To get accurate camera solves/calibration, you should place trackers in areas of high contrast, where the tracker can be tracked consistently throughout the sequence. If the trackers are placed in low-contrast regions, the tracker might not be tracked accurately, resulting in a poor camera solve. Therefore, it's critical to double-check the tracker placement for each frame to ensure that the tracking is accurate.
Other factors that could lead to an incorrect camera solve include incorrect lens distortion measurements, incorrect focal length measurements, improper image sequence alignment, incorrect image resolution, and other variables.
Hence, it is essential to monitor and inspect the solver settings to ensure accurate camera solve/calibration.
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a person with a mass of 78 kg is riding in an elevator that is accelerating upward at 1.80 m/s2. what is the person's apparent weight? (use g
The apparent weight of a person with a mass of 78 kg in an elevator accelerating upward at 1.80 m/s2 is 91.2 kg.
This is calculated using the equation: apparent weight = mass x acceleration due to gravity + acceleration of elevator, which equals 78 kg x 9.81 m/s2 + 1.80 m/s2 = 91.2 kg.
Steps:
The apparent weight of a person with a mass of 78 kg riding in an elevator accelerating upward at 1.80 m/s2 is the sum of the person's true weight and the force of the elevator's acceleration. The true weight of the person can be calculated using the equation Weight = Mass x g, where g is the acceleration due to gravity (9.81 m/s2). So the true weight of the person is 78 kg x 9.81 m/s2 = 767.78 N. The force of the elevator's acceleration can be calculated using the equation Force = Mass x Acceleration, where the mass is the person's mass (78 kg) and the acceleration is the elevator's acceleration (1.80 m/s2). So the force of the elevator's acceleration is 78 kg x 1.80 m/s2 = 140.4 N.Therefore, the apparent weight of the person is 767.78 N + 140.4 N = 908.18 N.
765 Newton = 78.00829 kgf, hence 908.18N is equals to 91.2kg.For more questions related to apparent weight.
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the distance (d) between two telephone poles is 49.5 m. a taut telephone wire is connected between the poles. when a 1.02 kg bird lands on the telephone wire midway between the poles, the wire sags 0.212 m (h). how much tension does the bird produce in the wire?
The tension in the wire created by the bird landing on it is calculated by using the equation T= (mgh)/d, where m is the mass of the bird, g is the acceleration due to gravity, h is the amount the wire sags and d is the distance between the two telephone poles.
In this case, with m = 1.02 kg, g = 9.81 m/s2, h = 0.212 m and d = 49.5 m, the tension in the wire is calculated as T = (1.02 kg x 9.81 m/s2 x 0.212 m)/49.5 m = 4.299 N.
This means that the bird produces a tension of 4.299 N in the telephone wire when it lands on it midway between the two poles. This amount of tension is relatively small, but enough to cause the wire to sag slightly. The tension in the wire will increase if the bird moves further along it, as the distance d between the poles will decrease.
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the speed of sound in air is approximately the same for all wavelengths. what evidence is there that this is true?
The speed of sound in air is approximately the same for all wavelengths.
Step by step Explanation :
The evidence that this is true is the following:
The speed of sound in air is approximately the same for all wavelengths. This is proved by the fact that a sound wave is an atmospheric disturbance that propagates as a longitudinal wave through the air, travelling as a pressure wave that causes areas of compression and rarefaction.
The speed of sound in air is constant and is determined by the average kinetic energy of the air molecules. This is why the speed of sound is the same for all wavelengths.
When the temperature of air is held constant, the speed of sound in air is constant. This is the primary reason why the speed of sound in air is practically constant at a given temperature.
The wavelengths of sound range from about 17 meters for the lowest audible frequency (about 20 Hz) to about 17 millimeters for the highest audible frequency (about 20,000 Hz).
The speed of sound in dry air at room temperature is around 343 meters per second, but it may vary depending on a variety of factors, including humidity, temperature, and pressure.
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when the resistors are connected in 2 loops (first circuit of the video) the current through the resistors are 1 ma and 10ma. what is the current in the circuit before the junction that splits to the 2 resistors?
The circuit's initial current via the junction where the two resistors are separated is 11 mA. The current divides and simultaneously passes via both resistors in a paralleled resistor circuit using two resistors.
A battery and many capacitors are linked in series. The capacitors have a comparable amount of charge.
A battery and many capacitors are linked in series. The sum of the potential differences between each capacitor equals the current battery emf.
When two resistors having resistance R that are similar to one another are linked in series, the capacitive reactance is 2R.
Both negative and positive ions move charges whenever an electricity flows through with an ionic liquid like salty water. Energy is measured in electron-volts.
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a strong lightning bolt transfers an electric charge of about 21 c to earth (or vice versa). how many electrons are transferred? avo
Approximately [tex]1.31 \times 10^{20}[/tex] electrons are transferred in a strong lightning bolt carrying an electric charge of 21 C.
The electric charge of one electron is equal to [tex]-1.602 \times 10^{-19}[/tex] Coulombs (C). Therefore, we can calculate the number of electrons transferred by dividing the total charge transferred by the charge of a single electron:
Number of electrons = Total charge transferred / Charge of a single electron
Number of electrons = [tex]\frac{21 C }{-1.602 \times 10^{-19} C}[/tex]
The number of electrons ≈ [tex]1.31 \times 10^{20} electrons[/tex]
Hence the number of electrons transferred during the lightning bolt is [tex]1.31 \times 10^{20}[/tex].
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how much energy is stored by the electric field between two square plates, 9.3 cm on a side, separated by a 2.5- mm air gap? the charges on the plates are equal and opposite and of magnitude 13 nc .
The electric field stored between two square plates of 9.3 cm on a side and separated by a 2.5 mm air gap is 1110 N/C. This can be calculated using Coulomb's law and the given information.
Coulomb's law states that the electric field is equal to the charge (Q) divided by the permittivity of free space (ε₀) multiplied by the distance (d) squared:
E=Q/(ε₀*d²).
Plugging in the given information,
E=(13 nC)/(8.85 x 10⁻¹² * 0.0025²) = 1110 N/C.
This answer uses Coulomb's law to calculate the electric field stored between two square plates, given the plates' side lengths, air gap width, and charge magnitude.
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An automobile has a vertical radio antenna 1.20 m long. The automobile travels at 65.0 km/h on a horizontal road where Earth's magnetic field is 50.0 μT, directed toward the north and downward at an angle of 65.0∘ below the horizontal.(a) Specify the direction the automobile should move so as to generate the maximum motional emf in the antenna, with the top of the antenna positive relative to the bottom.
The direction the automobile should move to generate the maximum motional emf in the antenna, with the top of the antenna positive relative to the bottom towards the east.
A magnetic field is an area surrounding a magnet or an electric current, characterized by the presence of a force that can attract or repel other magnetic materials. The concept of magnetic fields is significant in a variety of contexts, including electromagnetism, particle physics, and ferromagnetism.
According to Faraday's Law of Electromagnetic Induction, the emf generated in a conducting wire moving in a magnetic field is proportional to the strength of the magnetic field and the velocity of the conductor.
The magnitude of the emf is given by ε = Blv sinθ, where
- ε is the magnitude of the induced emf,
- B is the magnetic field strength,
- l is the length of the wire in the magnetic field,
- v is the speed of the conductor relative to the magnetic field, and
- θ is the angle between the velocity vector and the magnetic field vector.
Due to the given conditions in the question, we can use the above formula for calculating the maximum emf. To generate the maximum motional emf in the antenna, the automobile should move in a direction perpendicular to both the antenna and the Earth's magnetic field. The angle between the velocity vector and the magnetic field vector should be 90°.
1: Identify the direction of the magnetic field. In this case, the magnetic field is directed toward the north and downward at an angle of 65.0° below the horizontal.
2: Determine the direction perpendicular to both the antenna and the magnetic field. This can be done by using the right-hand rule. Point your right thumb in the direction of the magnetic field (north and downward at 65.0° below the horizontal) and your right index finger in the direction of the antenna (vertical). Your right middle finger will then point in the direction of the motion required to generate the maximum emf (perpendicular to both the magnetic field and the antenna).
The direction the automobile should move to generate the maximum motional emf in the antenna, with the top of the antenna positive relative to the bottom, is to the east.
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true/false in the inner solar system the largest surface fratures such as volacanos or valleys are found on the largest planets
In the inner solar system the largest surface fratures such as volacanos or valleys are found on the largest planets is a False statement.
What is the solar system about?The largest planets in our solar system are gas giants, which do not have a solid surface. Therefore, they cannot have surface features like volcanoes or valleys.
In the inner solar system, the planet with the largest surface features is actually Mercury, which is the smallest planet. Mercury has a giant impact basin called the Caloris Basin, which is over 1,500 kilometers in diameter.
Lastly, Venus has large volcanic features, including its highest mountain, Maxwell Montes, which is over 11 kilometers tall.
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A 7.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping.What was the initial speed of the bullet?Express your answer with the appropriate units
A 7.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping the initial velocity of the bullet was 958 m/s.
First, let's calculate the momentum of the bullet before the collision. Momentum is defined as mass times velocity, so we need to find the velocity of the bullet. We can use the fact that the bullet remains embedded in the block to determine the final velocity of the bullet-block system. The momentum of the system is equal to the mass of the system times its velocity.
Let's call the initial velocity of the bullet "v". The mass of the system is the mass of the bullet plus the mass of the block, which is 7.00 g + 1.20 kg = 1.207 kg. After the collision, the block and bullet move together at a final velocity of "vf". We can use the fact that the block slides 0.390 m along the surface before stopping to determine vf. The work done by friction is equal to the force of friction times the distance over which it acts. This work is equal to the change in kinetic energy of the system, which we know is equal to the initial kinetic energy of the bullet. We can write:
frictional force x distance = 1/2 x m x v^2
The frictional force is equal to the coefficient of kinetic friction times the normal force, which is equal to the weight of the block. We can write:
0.20 x 1.20 x 9.81 x 0.390 = 1/2 x 1.207 x vf^2
Solving for vf, we get:
vf = 2.62 m/s
Now we can use the conservation of momentum to find the initial velocity of the bullet:
m_bullet x v = (m_bullet + m_block) x vf
7.00 g x v = 1.207 kg x 2.62 m/s
v = 958 m/s
So the initial velocity of the bullet was 958 m/s.
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astronomers estimate that there may be a trillion (a thousand billion) comet nuclei orbiting beyond pluto. why then do we not see more comets in our skies?
Not all comet nuclei become active, comets have highly elliptical orbits, and can be obscured by other celestial bodies.
Despite the fact that stargazers gauge that there might be a trillion comet cores circling past Pluto, we don't see more comets in that frame of mind because of different elements. To begin with, not all comet cores become dynamic and form into comets. Second, numerous comets have profoundly circular circles that benefit them from the inward planetary group, where they are not apparent from Earth. Third, comets can be darkened by other heavenly bodies, like planets or stars. At last, numerous comets have extremely lengthy orbital periods, requiring hundreds or even millennia to finish a solitary circle, and hence may not be apparent during a human lifetime. Furthermore, the brilliant comets that are noticeable from Earth are frequently generally uncommon and happen inconsistently, making them much more extraordinary and energizing to see when they do show up.
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