In a student survey, forty part-time students were asked how many courses they were taking this term. The (incomplete) results are shown below: Please round your answers to 4 decimal places.


# of Courses Frequency Relative Frequency Cumulative Frequency

1 11 ? 11

2 ? 0.425 28

3 12 0.3 ?

What percent of students take exactly two courses?

%

Answers

Answer 1

Answer:

42.5%

Step-by-step explanation:

First we have to complete the table. We know that there are forty part time students so sum(f)=n=40. So, for two courses frequency is 40-11-12=17.

The relative frequency is the proportion of respective frequency and the sum of frequency. So, the missing relative frequency for 1st course is 11/40=0.275.

The missing relative frequency can also be computed as by subtracting given relative frequencies from 1 as sum of relative frequencies is 1. So, 1-0.425-0.3=0.275.

The cumulative frequency of respective class is the sum of frequency of previous classes and frequency of respective class. The missing cumulative frequency is 11+17+12 or 28+12= 40.

So, the complete table is

# of Courses Frequency Relative Frequency Cumulative Frequency

1                        11                   0.275                    11

2                        17                  0.425                    28

3                         12                  0.3                        40

The percent of students takes exactly two courses=0.425*100=42.5%


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Answers

Answer:

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                                         [tex]\huge\boxed{(-2)^2x^3y^2}[/tex]

___________________________________________________________

                                              [tex]\boxed{Explanation}[/tex]

[tex](-2)\;*(-2)=(-2)^2\\x*x*x=x^3\\y*y=y^2\\\\Add\;them\;all\;together\;and\;you\;get\;(-2)^2x^3y^2.[/tex]

Hope it helps!

May i have brainliest?

[tex]\huge\boxed{Thanks,\;Plip.}[/tex]

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Answers

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