in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?

(a) The magnitude of force vector B at the given resultant force is 120 N.

(b) The direction of  force vector A is 142.46°

The resultant forces is calculated as follows;

Acosθ + Bcosθ = 0 --- (1)

Asinθ + Bsinθ = 150 ---- (2)

Acosθ + Bcos60 = 0    

-60 + Bsin60 = 0     (Acosθ = x-component of A = Ax)

Bcos60 = 60

B = 60/cos(60)

B = 120 N

Asinθ + Bsinθ = 150

Ay + Bsinθ = 150

Ay + 120sin60 = 150

Ay = 150 - 120sin60

Ay = 46.1 N

[tex]tan \theta = \frac{A_y}{A_x} \\\\\theta = tan^{-1} (\frac{A_y}{A_x})\\\\\theta = tan^{-1} (\frac{46.1}{-60})\\\\\theta = -37.53^0\\\\\theta = -37.53^0 + 180 = 142.46^0[/tex]

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Answer:

The answer would be 25kg.

Explanation:

Because the force is 50 N and the acceleration is 2 meters per second squared and the Newton's Law Triangle is F = m x a or Force = Mass x Acceleration so we have to solve the equation 50 divided by 2 or 50/2 which results in 25kg.

Answer:

с The handle will turn anticlockwise (to the left).

Explanation:

The actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.

The wavelength of the light is determined using the following formulas;

[tex]\lambda = d(\frac{y}{D} )[/tex]

where;

y = (λD) / (d)

Thus, the actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.

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The magnetic field is weak in both A and C but strong in B since magnetic field strength increases with number of turns and quantity of current.

The strength of the magnetic field in a solenoid is affected by the following factors:

The strength of the magnetic field of a solenoid ncreases when:

Therefore, the magnetic field is weak in both A and C but strong in B.

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Researching information

Explanation: Edge 2020

hope this helps :3. pls mark me brainiest Brainliest

Answer:

It is C.

Explanation:

Got it right on edge.

Answer:

See below ~

Explanation:

Assume the bodies have the same acceleration

Divide the RHS of equation 2 by equation 1.

Therefore, the body of 6 kg accelerates more by 3 times

Answer:

The property of light going in a straight lines in a homogenous straightforward medium is known as rectilinear engendering of light.

Answer:

the property of light travelling in a straight lines in a homogenous transparent medium

Explanation:

Answer:

(b) from left to right (→)

Explanation:

Frictional Force

When the surface of one object comes into touch with the surface of another, friction is the force that resists motion. Friction reduces a machine’s mechanical advantage, or, to put it another way, friction reduces the output-to-input ratio. Frictional force refers to the force generated by two surfaces that contact and slide against each other.

Friction is caused due to the irregularities on the two surfaces in contact. So, when one object moved over the other, these irregularities on the surface get entangled, giving rise to friction.

The more the roughness, the more irregularities and more significant will be the friction.

Friction always acts in the opposite direction to the motion, hence the force of friction will be from left to right.

Hi there!

Recall that the amplitude of an oscillating system occurs at a point of maximum potential energy.

For a spring system, potential energy is given as:
[tex]U = \frac{1}{2}kx^2[/tex]

U = Potential Energy (J)

k = Spring constant (N/m)
x = amplitude (m)

We can rearrange the equation to solve for amplitude more easily.

[tex]U = \frac{1}{2}kx^2\\\\2U = kx^2\\\\x^2 = \frac{2U}{k}\\\\x = \sqrt{\frac{2U}{k}}[/tex]

If we double 'U':
[tex]x' = \sqrt{\frac{2(2U)}{k}} = \sqrt{2}*\sqrt{\frac{2U}{k}}\\\\x' = \sqrt{2} * x[/tex]

Thus, the new amplitude would be √2 times greater, so:
[tex]20 cm \cdot \sqrt{2} = \boxed{28.284 cm}[/tex]

The type of mental function that is the strongest and most obvious is feeling. That is option A.

Mental function can be defined as those activities that are performed by individuals such as thinking, sensing, or reasoning that involves the cognitive use of the brain.

The four basic cognitive functions include:

The magnitude of each basic cognitive functions depends on the personality of the individual.

An extrovert is an individual that is active, outgoing, and has an expressive pattern of behaviour. Therefore extrovert feeling would be the strongest and most obvious.

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Changes in daily routine or lifestyle like traveling can lead to constipation

However, other causes of constipation include the following:

This is a health condition in whereby there is difficulty in emptying the bowels.

This makes defecation very difficult.

So therefore, changes in daily routine or lifestyle like traveling can lead to constipation

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Charge is neither generated nor destroyed, according to the rule of conservation of charge. Charge is merely transferred from one item to another in the form of electrons.

For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as

du=0.2512J

Generally, the equation for the initial velocity  is mathematically given as

v0=-iAB

Therefore

-2*\pi(0.2)(0.5))

v0=-0.1256J

for  180

theta=0180=-iABcos180

V180=0.1256J

Therefore

du=v180-v0

0.1258-(-0.1256

du=0.2512J

In conclusion,  potential energy

du=0.2512J

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Answer:

D

Explanation:

Cellular respiration is a set of metabolic reactions and processes that take place in the cells of organisms to convert chemical energy from oxygen molecules or nutrients into adenosine triphosphate, and then release waste products.

Answer:

18.51 J

Explanation:

First, we need to find the Kinetic energy of the disk. Since the disk travels in a straight line, we can use the formula [tex]K=\frac{1}{2}mv^2[/tex]:

[tex]Kdisk=\frac{1}{2} 0.033*33.5^2\\Kdisk=18.51 J[/tex]

Since no other force is present, no friction, sound, or vibration, energy must be conserved. Therefore, the answer for both is 18.51 J.

Answer: If you are adding heat to a sample at a constant rate , you plot the temperature against time.

Explanation:

The velocity of 1kg and 2 kg mass when separation becomes 5m is 1.334 x 10⁻¹¹ m/s and 6.67 x 10⁻¹² m/s respectively.

The gravitational force between the masses is determined as follows;

[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11}) (1)(2)}{10^2} \\\\F = 1.334 \times 10^{-12} \ N[/tex]

a = F/m

a₁ = (1.334 x 10⁻¹²) / (1)

a₁ = 1.334 x 10⁻¹² m/s²

a₂ = (1.334 x 10⁻¹²) / (2)

a₂ = 6.67 x 10⁻¹³ m/s²

v = u + 2ad

v₁ = u₁ + 2a₁d

v₁ = 0 + 2( 1.334 x 10⁻¹² )(5)

v₁ = 1.334 x 10⁻¹¹ m/s

v₂ = u₂ + 2a₂d

v₂ = (0) + 2(6.67 x 10⁻¹³)(5)

v₂ = 6.67 x 10⁻¹² m/s

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For a velocity selector for ions using perpendicular electric and magnetic fields is mathematically given as

B= 0.225 T

Generally, the equation for the magnetic field is mathematically given as

B = E/v

Therefore

B = 900/4000

B= 0.225 T

In conclusion. the magnetic field is

B= 0.225 T

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The speed of the waves will be 100 cm/s. The speed of a wave is the product of the frequency and wavelength.

When an object vibrates, a pressure wave is created, which produces sound. The particles in the surrounding medium (air, water, or solid) vibrate as a result of the pressure wave.

For one node distance is [tex]\lambda[/tex]

The distance between 4 nodes;

[tex]=\rm \lambda+ \frac{\lambda}{2} \\\\ = \frac{3 \lambda}{2} \\\\[/tex]

The distance between 4 nodes = 15.0 cm.

[tex]\frac{3\lambda}{2} = 15 \times 10^{-2} \\\\ \lambda= \frac{2 \times 15 \times 10^{-2}}{3} \\\\\ \lambda= 10 \times 10^{-2}[/tex]

The given frequency of the source is;

f = 10 Hz

The speed of wave is found as;

[tex]\rm v = f \lambda \\\\ v= 10 \times 10^{-2} \\\\ v=1 \ m \\\\\ v = 10^2 \ cm/sec[/tex]

Hence,  the speed of the waves will be 100 cm/s

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Answer:

15 267 times per second

Explanation:

1 / ( 6.55 x 10 ^-5) = 15 267 Hz

Answer:

1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.

solution

element

mixture

compound

2.

Which of the following materials is a substance?

air

gasoline

stainless steel

silver

3.

The first figure in a properly written chemical symbol always is _____.

boldfaced

capitalized

italicized

underlined

4.

Which of the following represents a compound?

H

H-3

H2O

O-16

5. What do chemical symbols and formulas represent, respectively?

elements and compounds

atoms and mixtures

compounds and mixtures

elements and ions

Explanation:

The rocket plane will travel 800 meters before coming to rest.

initial speed= 80 m/s

kinetic friction= 0.6

Net force action on the plane:

  F- kinetic friction = mass * acceleration

 mass*g - 0.6*mass*g=mass*acceleration     (take g=10m/s)

              acceleration=4m/s

calculation of stopping distance:-

   V²=U²-2as

   0+2as=U²

   S=U²/2a

   S=(80*80)2*4

   S=800 meter.

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[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Here,

Here, we have

We have to find the time of flight

We know that,

Time of flight

[tex]\sf{ = }{\sf{\dfrac{ 2uSin{\theta}}{g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ 2{\times}100{\times}Sin30{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 200{\times}{\frac{1}{2}}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 100}{9.8}}}[/tex]

[tex]\bold{ = 10.20 \: s }[/tex]

Hence, The time of flight is 10.20 sec .

Here, We have

We have to find the maximum height attained by the body

We know that,

Maximum height

[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin^{2}{\theta}}{2g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin^{2}30{\degree}}{2{\times} 9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{1}{2}}{\times}{\frac{1}{2}}}{19.6}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}{\frac{1}{2}}}{19.6}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 2500}{19.6}}}[/tex]

[tex]\sf{ = 127.5 \: m}[/tex]

Hence, The maximum height attained by the body is 127.5 .

Here, we have

We have to find the horizontal range

We know that,

Horizontal range

[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin2{\theta}}{g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin2{\times}30{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}Sin{\times}60{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{\sqrt{3}}{2}}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}\sqrt{3}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}1.732}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 8660}{9.8}}}[/tex]

[tex]\sf{ = 883.67 \: or 883.7 m}[/tex]

Hence, The range of the body is 883.67 or 883.7 m.

Answer:

(a) 10.20 s (nearest hundredth)

(b) 127.55 m (nearest hundredth)

(c) 883.70 m (nearest hundredth)

Explanation:

Part (a)

At the end of the projectile's flight, its vertical displacement will be zero.

Resolving vertically, taking up as positive:

[tex]s=0\quad u=100 \sin30^{\circ} \quad v=v, \quad a=-9.8, \quad t=t[/tex]

[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2:\\ 0 & =100 \sin 30^{\circ}t+\dfrac12(-9.8)t^2\\ 0 & = 50t-4.9t^2\\ 4.9t^2 & = 50t\\ 4.9t & = 50\\ t & = \dfrac{50}{4.9}\\ t & = 10.20\:\sf s\:(nearest\:hundredth)\end{aligned}[/tex]

Part (b)

At the maximum height, vertical velocity will be zero.

Resolving vertically, taking up as positive:

[tex]s=0\quad u=100 \sin30^{\circ} \quad v=0, \quad a=-9.8, \quad t=t[/tex]

[tex]\begin{aligned}\textsf{Using }\:v^2 & = u^2+2as :\\ 0^2 & = (100 \sin 30^{\circ})^2+2(-9.8)s\\ 0 & = 2500-19.6s\\ 19.6s & = 2500\\ s & = \dfrac{2500}{19.6}\\ s & = 127.55\: \sf m\:(nearest\:hundredth) \end{aligned}[/tex]

Part (c)

The horizontal velocity of a projectile is always constant, so u = v.

The horizontal component of acceleration is zero.

Resolving horizontally, taking right as positive (and using the value for t we found in part a):

[tex]s=s\quad u=100 \cos30^{\circ} \quad v=100 \cos30^{\circ} , \quad a=0, \quad t=\dfrac{50}{4.9}[/tex]

[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2 : \\ s & =(100 \cos 30^{\circ})\left(\dfrac{50}{4.9}\right)+\dfrac12(0)\left(\dfrac{50}{4.9}\right)^2\\ s & =50\sqrt{3}\left(\dfrac{50}{4.9}\right)+0\\ s & =883.70\: \sf m\:(nearest\:hundredth)\end{aligned}[/tex]

The current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

The current in the series circuit is determined by applying ohms law as shown below;

V = IR

where;

R = 12 Ω  + 15 Ω  = 27 Ω

I = V/R

I = 9/27

I = 0.333 A

Thus, the current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

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For an aluminum disk of radius 8.7 cm and thickness 3.0 mm spinning around,  moment of inertia   is mathematically given as

I=16268.20gcm^2

Generally, the equation for the volume  is mathematically given as

v=\pir^2t

Therefore

v=\pi(8.7)^2*0.32

v=76.09cm^3

In conclusion, The inertia

I=136.83*8.7^2/2

I=16268.20gcm^2

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Answer:

See below ~

Explanation:

Total Resistance

Total Current Drawn

Answer:

You should probably try following the instructions and you will be able to find the answer to the question :>

Explanation:

but mostly the technology's using us

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

Let's use the given expression :

[tex]\qquad \tt \dashrightarrow \:a = v \dfrac{dv}{ds} [/tex]

[tex]\qquad \tt \dashrightarrow \:v \:dv= a \: {}{ds} [/tex]

Now, integrate both sides

[tex]\qquad \tt \dashrightarrow \: \int_{u}^v (v )\: dv= {\int _{0 }^{s} }{}^{} (a) \: {}{ds} [/tex]

[tex]\qquad \tt \dashrightarrow \: {\bigg[\dfrac{v {}^{2} }{2} \bigg]}_{u }^{v} \: = {\bigg[{a{s}^{} }{} \bigg]}_{0}^{s}[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{1}{2} {\bigg[{v {}^{2} - {u}^{2} }{} \bigg]}_{}^{} \: = a{\bigg[{{s - 0}^{} }{} \bigg]}_{}^{}[/tex]

[tex]\qquad \tt \dashrightarrow \: v {}^{2} - {u}^{2} =2 as[/tex]

[tex]\qquad \tt \: \therefore v {}^{2} =u {}^{2} + 2as[/tex]

I hope you understood ~