The values of distance and orbital periods of planets Mercury is 0.39AU and 0.242yrs,Venus 0.72AU distance and 0.616yrs,Earth 1AU distance and 1yrs,Mars 1.52AUdistance and 1.88,Jupiter 5.2AUdistance and 1.88 ,Saturn N/Adistance and NA years as infromation is not provided,Uranus 19.18AUdistance and 84yrs,Neptune 30.06AUdistance and165yrs.
Based on the given information, here are some key facts about the planets in our solar system:
- Mercury is the closest planet to the Sun, with a distance from the Sun of 0.39 astronomical units (AU). It has an orbital period of 0.242 years.
- Venus is the second planet from the Sun, with a distance of 0.72 AU. Its orbital period is 0.616 years.
- Earth is the third planet from the Sun, with a distance of 1 AU. Its orbital period is 1 year.
- Mars is the fourth planet from the Sun, with a distance of 1.52 AU. Its orbital period is 1.88 years.
- Jupiter is the fifth planet from the Sun, with a distance of 5.2 AU. Its orbital period is 11.86 years.
- Saturn is the sixth planet from the Sun, with a distance of N/A AU. Its orbital period is N/A.
- Uranus is the seventh planet from the Sun, with a distance of 19.18 AU. Its orbital period is 84 years.
- Neptune is the eighth planet from the Sun, with a distance of 30.06 AU. Its orbital period is 165 years.
Therefore the the distance and orbital periods are in increasing arrangement mercury, venus, earth, mars, jupiter, saturn ,uranus, neptune distance from the sun.
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The distance between two cities is 180 kilometers. There are approximately 8 kilometers in 5 miles.
Which measurement is closest to the number of miles between these two cities?
The measurement which is closest to the number of miles between these two cities is 113 miles.
Given the distance between two cities is 180 kilometers.
If there are approximately 8 kilometers in 5 miles, we can use this conversion factor to convert 180 kilometers to miles, then one kilometer is approximately equal to 5/8 miles (0.625 miles).
To find the number of miles between the two cities, we can convert 180 kilometers to miles by multiplying by the conversion factor:
180 kilometers × (5/8 miles per kilometer) ≈ 112.5 miles = approximately 113 miles
Therefore, the closest measurement to the number of miles between these two cities is approximately 113 miles.
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A 5 m long car is overtaking a 19 m long bus. The bus is travelling at a constant speed of 25 m/s. The car takes 3 s to overtake the bus. We assume that overtaking starts when the frontmost part of the car crosses the backmost part of the bus and ends when the backmost part of the car crosses the frontmost part of the bus. So at what constant speed (in m/s) is the car driving?
Answer:
Length of a car is 5m
Length of bus is 19m
Velocity of bus is 25ms-¹
Step-by-step explanation:
Assuming that overtaking start from front most part to back most part
Distance travel by car is 19m+5m=24m
Let velocity of bus be Vc and of car be Vb
Now
Velocity of car is 32ms-¹
A sphere has a radius of 12 cm. a cylinder has the same radius and has a height of 12 cm. what is the difference in their volumes in cubic cm? record your answer to the nearest hundredth. use 3.14
The difference in volumes between the sphere and the cylinder is approximately 3619.14 cubic cm.
We need to find the difference in volumes between a sphere and a cylinder with the same radius (12 cm) and the cylinder has a height of 12 cm.
Step 1: Find the volume of the sphere.
The formula for the volume of a sphere is V_sphere = (4/3)πr³.
V_sphere = (4/3) × 3.14 × (12 cm)³
V_sphere = (4/3) × 3.14 × 1728 cm³
V_sphere ≈ 9047.78 cm³
Step 2: Find the volume of the cylinder.
The formula for the volume of a cylinder is V_cylinder = πr²h.
V_cylinder = 3.14 × (12 cm)² × 12 cm
V_cylinder = 3.14 × 144 cm² × 12 cm
V_cylinder ≈ 5428.64 cm³
Step 3: Find the difference in volumes.
Difference = V_sphere - V_cylinder
Difference = 9047.78 cm³ - 5428.64 cm³
Difference ≈ 3619.14 cm³
The difference in volumes between the sphere and the cylinder is approximately 3619.14 cubic cm.
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how many vertices has a cuboid
Answer: 8
Step-by-step explanation:
Use the Picard-Lindeloef iteration to find the first few elements of a sequence {yn}n=0 of approximate solutions to the initial value problem y(t) = 5y(t)+1, y(0) = 0
To use the Picard-Lindelöf iteration to find a sequence of approximate solutions to the initial value problem y'(t) = 5y(t) + 1, y(0) = 0, we start with the initial approximation y_0(t) = 0. Then, for each n ≥ 0, we define y_{n+1}(t) to be the solution to the initial value problem y'(t) = 5y_n(t) + 1, y_n(0) = 0. In other words, we plug the previous approximation y_n into the right-hand side of the differential equation and solve for y_{n+1}.Using this procedure, we can find the first few elements of the sequence {y_n} as follows:y_0(t) = 0y_1(t) = ∫ (5y_0(t) + 1) dt = ∫ 1 dt = ty_2(t) = ∫ (5y_1(t) + 1) dt = ∫ (5t + 1) dt = (5/2)t^2 + ty_3(t) = ∫ (5y_2(t) + 1) dt = ∫ (5(5/2)t^2 + 5t + 1) dt = (25/6)t^3 + (5/2)t^2 + tTherefore, the first few elements of the sequence {y_n} are y_0(t) = 0, y_1(t) = t, y_2(t) = (5/2)t^2 + t, and y_3(t) = (25/6)t^3 + (5/2)t^2 + t.
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To use the Picard-Lindelöf iteration method to find the first few elements of a sequence {y_n} of approximate solutions to the initial value problem y'(t) = 5y(t) + 1, y(0) = 0, we first set up the integral equation for the iteration:
y_n+1(t) = y(0) + ∫[5y_n(s) + 1] ds from 0 to t
Since y(0) = 0, the equation becomes:
y_n+1(t) = ∫[5y_n(s) + 1] ds from 0 to t
Now, let's calculate the first few approximations:
1. For n = 0, we start with y_0(t) = 0:
y_1(t) = ∫[5(0) + 1] ds from 0 to t = ∫1 ds from 0 to t = s evaluated from 0 to t = t
2. For n = 1, use y_1(t) = t:
y_2(t) = ∫[5t + 1] ds from 0 to t = 5/2 s^2 + s evaluated from 0 to t = 5/2 t^2 + t
3. For n = 2, use y_2(t) = 5/2 t^2 + t:
y_3(t) = ∫[5(5/2 t^2 + t) + 1] ds from 0 to t = ∫(25/2 t^2 + 5t + 1) ds from 0 to t = 25/6 t^3 + 5/2 t^2 + t
These are the first few elements of the sequence {y_n} of approximate solutions to the initial value problem using the Picard-Lindelöf iteration method.
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How can I get the answer for
A=
Vertex for y=
Answer:
1) a = 14
2) -4 (x - 2)² - 5
Step-by-step explanation:
To obtain a vertex, you take h and k in a equation.
So a(x-h)²+k = a(x-2)² -5
For the point (1, - 9),
a[(1)-2]² - 5 = - 9
a(1) = -9+5
a = -4
so the final equation is
-4(x-2)² - 5
I'm not 100% sure about this but I tried. Let me know if it makes sense
D(x) is the price, in dollar per unit, that the consumers are willing to pay for x units of an item, and S(x) is the price, in dollars per unit, that producers are willing to accept for x units. Find (a) the equilibrium point, (b) the consumer surplus at the equilibrium point, and (c) the producer surplus at the equilibrium point.
D(x)=(x-7)^2, S(x)=x^2+2x+33
Find:
A) The equilibrium point
B) The consumer surplus at the equilibrium point
C) The producer surplus at the equilibrium point
32/9
So the producer surplus at the equilibrium point is 32/9 dollars.
To find the equilibrium point, we need to set D(x) equal to S(x) and solve for x:
(x-7)^2 = x^2 + 2x + 33
Expanding and simplifying:
x^2 - 14x + 49 = x^2 + 2x + 33
12x = 16
x = 4/3
So the equilibrium point is x = 4/3.
To find the consumer surplus at the equilibrium point, we need to find the difference between the maximum price consumers are willing to pay (D(4/3)) and the equilibrium price (S(4/3)) and multiply by the quantity sold (4/3):
Consumer surplus = (D(4/3) - S(4/3)) * (4/3)
= [(4/3 - 7)^2 - (4/3)^2 - 2(4/3) - 33] * (4/3)
= [49/9 - 16/9 - 8/3 - 33] * (4/3)
= -224/27
So the consumer surplus at the equilibrium point is -224/27 dollars.
To find the producer surplus at the equilibrium point, we need to find the difference between the equilibrium price (S(4/3)) and the minimum price producers are willing to accept (S(0)) and multiply by the quantity sold (4/3):
Producer surplus = (S(4/3) - S(0)) * (4/3)
= [(4/3)^2 + 2(4/3) + 33 - 33] * (4/3)
= 32/9
So the producer surplus at the equilibrium point is 32/9 dollars.
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Consider the graph of the linear function h(x) = –x + 5. Which could you change to move the graph down 3 units?
the value of b to –3
the value of m to –3
the value of b to 2
the value of m to 2
The change to move the graph down 3 units is given as follows:
the value of b to 2.
How to define a linear function?The slope-intercept representation of a linear function is given by the equation presented as follows:
y = mx + b
The coefficients of the function and their meaning are described as follows:
m is the slope of the function, representing the change in the output variable y when the input variable x is increased by one.b is the y-intercept of the function, which is the initial value of the function, i.e., the numeric value of the function when the input variable x assumes a value of 0. On a graph, it is the value of y when the graph of the function crosses the y-axis.The function in this problem is given as follows:
y = -x + 5.
Moving the graph down 3 units, we subtract by three, hence:
y = -x + 5 - 3
y = -x + 2.
Meaning that the value of b is of b = 2.
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The force on a particle is described by 8x^3-5 at a point s along the z-axis. Find the work done in moving the particle from the origin to x = 4.
The work done in moving the particle from the origin to x = 4 under the influence of the force F (x) = 8[tex]x^3[/tex]-5 is 492 units of work.
The work done in moving a particle along a path under the influence of a force, we use the work-energy principle.
This principle states that the work done on a particle by a force is equal to the change in the particle's kinetic energy.
Mathematically this can be expressed as:
W = ΔK
Where
W is the work done,
ΔK is the change in kinetic energy and
Both are scalar quantities.
The work done by a force on a particle along a path is given by the line integral:
W = ∫ C F · ds
Where,
C is the path,
F is the force,
ds is the differential displacement along the path and denotes the dot product.
In the case where the force is a function of position only (i.e., F = F(x,y,z)), we can evaluate the line integral using the parametric equations for the path.
If the path is given by the parameterization r(t) = <x(t), y(t), z(t)>, then we have:
W = ∫ [tex]a^b[/tex] F(r(t)) · r'(t) dt
The work done in moving the particle from the origin to a final position at x = 4. We can evaluate the work done using the definite integral of the force from x = 0 to x = 4, as shown in the solution.
The initial kinetic energy is zero.
The work done by the force in moving the particle from x = 0 to x = 4 is given by the definite integral:
W = ∫ F(x) dx
Substituting the given expression for the force, we have:
W = ∫0 (8x - 5) dx
Integrating with respect to x, we have:
W = [(2x - 5x)]_0
W = (2(4) - 5(4)) - (2(0) - 5(0))
W = 512 - 20
W = 492
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Find the measure of ZB b 60⁰
Answer: b = 30°
Step-by-step explanation:
The little square represents a 90-degree angle.
90° - 60° = b
30° = b
b = 30°
Multiply (x-4)(x+5) Show your work in the box and enter your answer in the spot below: (No work loses points)
The solution to the expression is x² + x - 20
How to calculate the expression?(x-4)(x+5)
open the bracket
x² + 5x - 4x - 20
x² + x - 20
Hence the solution to the expression leads to quadratic equation which is written is x² + x -20
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What is the interquartile range of 58,55,54,61,56,54,61,55,53,53?
The interquartile range of 58,55,54,61,56,54,61,55,53,53 is 6.
To find the interquartile range (IQR), we first need to find the first and third quartiles of the data set. The first quartile (Q1) is the median of the lower half of the data set, and the third quartile (Q3) is the median of the upper half of the data set. The IQR is then the difference between Q3 and Q1.
To find Q1 and Q3, we first need to put the data set in order from lowest to highest:
53, 53, 54, 54, 55, 55, 56, 58, 61, 61
The median of the entire data set is the average of the two middle numbers, which in this case is (55 + 56) / 2 = 55.5.
To find Q1, we need to find the median of the lower half of the data set, which includes the numbers 53, 53, 54, 54, 55. The median of this lower half is the average of the two middle numbers, which is (53 + 54) / 2 = 53.5.
To find Q3, we need to find the median of the upper half of the data set, which includes the numbers 56, 58, 61, 61. The median of this upper half is the average of the two middle numbers, which is (58 + 61) / 2 = 59.5.
Now that we have Q1 and Q3, we can calculate the IQR as:
IQR = Q3 - Q1 = 59.5 - 53.5 = 6
Therefore, the interquartile range of the given data set is 6.
The IQR is a useful measure of variability because it is not influenced by outliers or extreme values in the data set, unlike the range or standard deviation. The IQR gives us an idea of the spread of the "middle" 50% of the data, which can help us understand the distribution of the data and identify any potential skewness or outliers.
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ignore the 94 don’t really understand this problem pls help (giving brainliest)
Answer:
measure of angle GHJ = 1/2 the measure of arc GJ = (1/2)(86°) = 43°
measure of angle JIG = 1/2 the measure of arc GJ = (1/2)(86°) = 43°
Lines ab and cd are parallel. if 6 measures (4x - 31)°, and 5 measures 95°, what is the value of x? a. x = 19 b. x = 95 c. x = 265 d. x = 29
Answer: x=29
Step-by-step explanation:
To find the value of x, we can set the two angles equal to each other and solve for x, which gives x = 19.
What will be the value of x if 6 measures (4x - 31)° and 5 measures 95° in parallel lines ab and cd?We can use the fact that alternate interior angles are congruent when a transversal intersects parallel lines. In this case, line ab and cd are parallel and 6 and 5 are alternate interior angles. So we can set up an equation:
4x - 31 = 95
Solving for x:
4x = 126
x = 31.5
So the value of x is not one of the answer choices given. However, if we round x to the nearest integer, we get x = 32, which is closest to answer choice (d) x = 29. Therefore, the closest answer choice is (d) x = 29.
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the following table shows the number of miles a hiker walked on a trail each day for 6 days. day 1 2 3 4 5 6 number of miles 8 5 7 2 9 8 what was the mean number of miles the hiker walked for the 6 days? responses 3.5 3.5 4.5 4.5 6.5 6.5 7.5 7.5 8
The mean number of miles the hiker walked for the 6 days was 6.5 miles.
To calculate the mean or average of a set of numbers, we add up all the numbers and then divide the sum by the number of items in the set. In this case, we have the number of miles the hiker walked on each of the six days. To find the total number of miles the hiker walked, we simply add up all the numbers
8 + 5 + 7 + 2 + 9 + 8 = 39
Next, we divide the total number of miles by the number of days (which is 6) to get the average or mean number of miles the hiker walked per day:
Mean number of miles = Total number of miles / Number of days
= 39 / 6
= 6.5
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Pls help me with this! I need to finish today
Answer:
T=64
Step-by-step explanation:
Multiply both sides by 4
t/4=16
t/4×4=16×4 Cancel out the 4
t=64
What is the area of a 125 degree sector for a circle with a radius of 12 m, rounded to the nearest whole number
The area of the 125 degree sector for a circle with a radius of 12 m is approximately 158 square meters.
To find the area of a 125 degree sector of a circle with a radius of 12 m, we need to use the formula for the area of a sector:
Area of sector = (θ/360) x πr², where θ is the central angle of the sector, r is the radius of the circle, and π is a constant equal to approximately 3.14.
Substituting the given values, we get: Area of sector = (125/360) x π x 12² = (0.3472) x π x 144 = 158.03
Rounding to the nearest whole number, we get the area of the sector as 158 square meters. Therefore, the area of the 125 degree sector for a circle with a radius of 12 m is approximately 158 square meters.
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Javier's deli packs lunches for a school field trip by randomly selecting sandwich, side, and drink options. each lunch includes a sandwich (pb&j, turkey or ham and cheese), a side (cheese stick or chips), and a drink (water or apple juice)
1. what is the probability that a student gets a lunch that includes chips and apple juice?
2. what is the probability that a student gets a lunch that does not include chips?
Answer is: Probability of a student getting a lunch that does not include chips is 6/12 or 0.5.
1. To find the probability of a student getting a lunch that includes chips and apple juice, we need to first find the total number of possible lunch combinations. There are 3 options for sandwiches, 2 options for sides, and 2 options for drinks, so there are a total of 3 x 2 x 2 = 12 possible lunch combinations.
Out of those 12 combinations, there is only 1 combination that includes chips and apple juice: ham and cheese sandwich, chips, and apple juice.
Therefore, the probability of a student getting a lunch that includes chips and apple juice is 1/12 or approximately 0.083.
2. To find the probability of a student getting a lunch that does not include chips, we can count the number of possible lunch combinations that do not include chips and divide by the total number of lunch combinations.
There are 3 sandwich options and 2 drink options, so there are a total of 3 x 2 = 6 possible lunch combinations without chips.
Out of the total of 12 possible lunch combinations, 6 do not include chips, so the probability of a student getting a lunch that does not include chips is 6/12 or 0.5.
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Stephen has a counter that is orange on one side and brown on the other. The counter is shown below: A circular counter is shown. The top surface of the counter is shaded in a lighter shade of gray and Orange is written across this section. The bottom section of the counter is shaded in darker shade of gray and Brown is written across it. Stephen flips this counter 24 times. What is the probability that the 25th flip will result in the counter landing on orange side up? fraction 24 over 25 fraction 1 over 24 fraction 1 over 4 fraction 1 over 2
The probability that the 25th flip will result in the counter landing on orange side up is fraction 1 over 2. The correct answer is D.
The probability of an event occurring is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In this case, Stephen has flipped the counter 24 times and he wants to know the probability of getting an orange side up on the 25th flip.
Since the counter has two sides - orange and brown, the probability of landing on the orange side is 1/2 or 0.5.
Each flip of the counter is independent of the others, so the previous flips do not affect the outcome of the 25th flip. Therefore, the probability of the 25th flip landing on the orange side up is still 1/2 or 0.5. The correct answer is D.
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Ralph has a cylindrical container of parmesan cheese. The diameter of the base of the container is 2. 75 inches, and the height is 6 inches. What is the area of a horizontal cross section of the cylinder to the nearest tenth of a square inch? Use 3. 14 for π
The area of a horizontal cross-section of the cylinder whose diameter is 2.75 inches and height is 6 inches is 5.9 inch².
Diameter of the base of the container = 2.75 inch
Height of the cylinder = 6 inch
Area of a horizontal cross-section of the cylinder = πr²
Here, r = radius of the container
Radius = Diameter/2
Radius = 2.75/2
Radius = 1.375
Area of the horizontal cross-section of the cylinder = 3.14 × 1.375 × 1.375
Area = 5.9365625
Area of the horizontal cross- section of the cylinder to the nearest tenth is 5.9
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A doctor saw 8 patients a day for 7 days. How many patiencents did he see altogether
The doctor saw 56 patients altogether during the 7 days.
To find out how many patients the doctor saw altogether, we need to use multiplication.
Identify the number of patients seen per day (8 patients).
Identify the number of days the doctor worked (7 days).
Multiply the number of patients per day by the number of days worked.
8 patients/day × 7 days = 56 patients.
The doctor saw 8 patients per day for 7 days, so the total number of patients he saw in a week is
Therefore, the doctor saw a total of 56 patients in 1 week.
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Write the standard form of the equation of the circle with the given characteristics. Endpoints of a diameter: (0, 0), (8, 6)
The standard form of the equation of the circle with the given characteristics is[tex] {(x - 4)}^{2} + {(y - 3)}^{2} = 25[/tex]
To get the equation of the circle using the endpoints of a diameter, we have to use the standard form :
[tex](x - h) ^{2} + (y - k)^{2} = {r}^{2} [/tex]
In which (h, k) represents the middle point of the circle and r as the radius. so, we need to find the midpoint of the diameter using the endpoints (0, 0) and (8, 6).
Midpoint = ((0+8)/2, (0+6)/2) = (4, 3)
Next, we need to calculate the radius by using the distance formula to calculate the distance between the center and one of the diameter endpoints.
[tex] {r}^{2} = {(8 - 4)}^{2} + {(6 - 3)}^{2} = {4}^{2} + {3}^{2} = 16 + 9 = 25[/tex]
Now, substituting the values of (h, k) and
[tex] {r}^{2} [/tex] into the standard form equation to get the equation:
[tex] {(x - 4)}^{2} + {(y - 3)}^{2} = 25[/tex]
Therefore, the standard form equation of the circle with the given characteristics is
[tex] {(x - 4)}^{2} + {(y - 3)}^{2} = 25[/tex]
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The standard form of the given question is (x - 4)² + (y - 3)² = 25, under the condition endpoints of a diameter: (0, 0), (8, 6).
In order To write the standard form of the equation of a circle with endpoints of a diameter (0, 0), (8, 6), we first need to find the center and radius of the circle.
The diameter comprises the midpoints of the center of the circle. The midpoint of (0, 0) and (8, 6) is ((0+8)/2, (0+6)/2) = (4,3). Center point of the circle is (4,3).
Diameter = 2× radius
. The distance between (0, 0) and (8, 6) is √((8-0)² + (6-0)²)
= √(64+36)
= √100
= 10.
Then, the radius of the circle is 10/2 = 5.
Then,
(x - h)² + (y - k)² = r²
here
(h,k) = center of the circle
r = radius.
Staging in this equation
h=4,
k=3
r=5
(x - 4)²+ (y - 3)² = 25
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A pack of 24 crayons costs the manufacturer $0.05 to make and is sold to the stores for $0.25. the stores sell the crayons for $0.50 during back to school week.
1.an equation that represents the mark up cost by the manufacturer is
a.p(c)=2c
b.p(c)=5c
c.p(c)=10c
2.an equation that represents the store mark up cost is
a.s(p)=2p
b.s(p)=5p
c.s(p)=10p
3.a composition of these two functions is
a.s(p(c))=2c
b.s(p(c))=10c
c.s(p(c))=5c
4.it represents
a.the total markup from cost to sales price
b.how much the store profits from the sale
c.how much money the manufacturer makes
a. s(p)=2p b. p(c)=5c c. s(p(c))=5c a. The total markup from cost to sales price.
How are the mark-up costs and profits determined in the pricing of the crayons?The equation that represents the mark-up cost by the manufacturer is c. p(c) = 10c. This equation implies that the manufacturer adds a mark-up of 10 times the cost to determine the selling price of the crayons.The equation that represents the store mark-up cost is b. s(p) = 5p. This equation implies that the store adds a mark-up of 5 times the cost price (or the price they purchase from the manufacturer) to determine the selling price during back-to-school week.The composition of these two functions is c. s(p(c)) = 5c. This equation represents that the store applies their mark-up (5 times the cost) to the manufacturer's selling price (10 times the cost) to determine the final selling price of the crayons.It represents a. the total mark-up from cost to sales price. This composition equation shows how both the manufacturer and the store contribute to the mark-up, resulting in the final selling price of the crayons. It accounts for the mark-up at each stage of the distribution process, from the manufacturer to the store.Learn more about manufacturer
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3/4+(1/3 divided by 1/6) - (-1/2)
3/4 + (1/3 divided by 1/6) - (-1/2) when simplified give 3 1/4
How to determine this
3/4 + (1/3 divided by 1/6) - (-1/2)
3/4 + (1/3 ÷ 1/6) - (-1/2)
Using the rule of BODMAS
Whee B = Bracket
O = Order
D = Division
M = Multiplication
A = Addition
S = Subtraction
By removing the bracket
3/4 + 1/3 ÷ 1/6 + 1/2
By dividing
3/4 + 1/3 * 6/1 + 1/2
3/4 + 6/3 + 1/2
3/4 +2 + 1/2
By finding the LCM
The LCM is lowest common factor of the denominator which is 4
= [tex]\frac{3+8+2}{4}[/tex]
= 13/4
= 3 1/4
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The weekly demand for wireless mice manufactured by Insignia Consumer Electronic
Products group is given by
p(x) = -0.005x + 60, where p denotes the unit price in dollars and x denotes the quantity demanded. The weekly cost
function associated with producing these wireless mice is given by
C(x) = -0.001x^2 + 18x + 4000
Where C(x) denotes the total cost in dollars incurred in pressing x wireless mice (a) Find the production level that will yield a maximum revenue for the manufacturer. What will
be maximum revenue? What price the company needs to charge at that level? (b) Find the production level that will yield a maximum profit for the manufacturer. What will be
maximum profit? What price the company needs to charge at that level?
The production level that will yield maximum revenue is 6000 units, the maximum revenue is $180,000, and the price the company needs to charge at that level is $30. The production level that will yield maximum profit is 5250 units, the maximum profit is $59,250, and the price the company needs to charge at that level is $37.25.
To find the production level that will yield maximum revenue, we need to determine the quantity demanded that maximizes the revenue. The revenue function is given by
R(x) = xp(x) = x(-0.005x + 60) = -0.005x^2 + 60x
To find the maximum value of R(x), we need to take the derivative of R(x) and set it equal to zero
R'(x) = -0.01x + 60 = 0
x = 6000
So the production level that will yield maximum revenue is 6000 units.
To find the maximum revenue, we can plug this value into the revenue function
R(6000) = -0.005(6000)^2 + 60(6000) = $180,000
To find the price the company needs to charge at that level, we can plug the production level into the demand function
p(6000) = -0.005(6000) + 60 = $30
To find the production level that will yield maximum profit, we need to determine the quantity that maximizes the profit function. The profit function is given by
P(x) = R(x) - C(x) = -0.005x^2 + 60x - (-0.001x^2 + 18x + 4000) = -0.004x^2 + 42x - 4000
To find the maximum value of P(x), we need to take the derivative of P(x) and set it equal to zero
P'(x) = -0.008x + 42 = 0
x = 5250
So the production level that will yield maximum profit is 5250 units.
To find the maximum profit, we can plug this value into the profit function
P(5250) = -0.004(5250)^2 + 42(5250) - 4000 = $59,250
To find the price the company needs to charge at that level, we can plug the production level into the demand function
p(5250) = -0.005(5250) + 60 = $37.25
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PLEASE HELP I NEED HELP QUICK!!!
There are 720 different arrangements of the six children possible when Ben can't sit next to Dan.
There are 720 different arrangements of the six children possible.
The key to solving this problem is to recognize the fact that there are six children and six chairs, so each child has one and only one chair. This means that for each position in the row, one child must be placed in the chair.
To solve this problem we can use the permutation formula for "n objects taken r at a time without repetition," which is: n!/(n-r)!
In this case, n is 6 (the number of children) and r is 6 (the number of chairs). So, 6!/(6-6)! = 6!/(0!) = 6!/1 = 6! = 720.
Therefore, there are 720 different arrangements of the six children possible when Ben can't sit next to Dan.
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Cam put 4 12/25 pounds of rice in bags that each weigh 7/25 pound. She uses 1/8 of the bags of rice. How many bags of rice are left?
Answer:
14
Step-by-step explanation:
Cam put a total of 4 12/25 pounds of rice in bags, which is equivalent to 112/25 pounds of rice.
Each bag weighs 7/25 pound, so the total number of bags of rice is:
(112/25) ÷ (7/25) = 16
Cam uses 1/8 of the bags of rice, which is:
(1/8) x 16 = 2
So Cam uses 2 bags of rice.
The number of bags of rice left is the total number of bags (16) minus the number of bags used (2):
16 - 2 = 14
Therefore, 14 bags of rice are left.
suppose you own a restaurant and have a cook whose ability and attitude you are suspicious of. one of the dishes on the menu is duck cassoulet, which uses duck legs that have been slow fried over a couple of hours in oil that does not exceed a temperature of 175 degrees. this is a time consuming and monotonous process, but one that results in excellent meat that you sell for a large mark-up. you suspect your cook is lazy and doesn't properly monitor and maintain the oil temperature. you take a random sample of 12 duck legs and take them to a forensics lab where you are able to discover the maximum temperature the meat has reached. within your sample the mean maximum temperature of the duck legs is 182 degrees with a standard deviation of 5 degrees. meat cooked precisely to 175 degrees is what your cook is supposed to do. test the claim that your employee is capable (meaning he doesn't over-fry the meat) at the 90% confidence level. what is your conclusion? group of answer choices reject the null hypothesis, accept the alternative hypothesis fail to reject the null hypothesis reject the null hypothesis, reject the alternative hypothesis fail to reject the null hypothesis, fail to reject the null hypothesis fail to reject the null hypothesis, reject the alternative hypothesis
The claim of cooking duck legs at given temperature with mean , standard deviation represents reject the null hypothesis, accept the alternative hypothesis.
Confidence level = 90%
Sample mean maximum temperature x = 182 degrees
Hypothesized population mean μ =175 degrees
Sample standard deviation s = 5 degrees)
Sample size n =12
To test the claim that employee is capable of cooking the duck legs within the required temperature range.
Set up the following hypotheses,
Null hypothesis,
The mean maximum temperature of the duck legs is equal to or greater than 175 degrees (μ ≥ 175).
Alternative hypothesis,
The mean maximum temperature of the duck legs is less than 175 degrees (μ < 175).
Testing whether the mean is less than a specific value (175 degrees), this is a one-tailed test.
To reject or fail to reject the null hypothesis,
Use a one-sample t-test with a significance level of 0.1 .
T-test statistic is ,
t = (x - μ) / (s / √n)
Plugging in the values, we get,
t = (182 - 175) / (5 / √(12))
= 4.85
The degrees of freedom for this test is n-1 = 11.
Using a t-distribution table ( attached table) ,
Critical value for a one-tailed test with 11 degrees of freedom and a significance level of 0.1.
The critical value is 1.363.
Since the calculated t-value 4.85 is greater than the critical value (1.363).
Reject the null hypothesis at the 90% confidence level.
⇒Sufficient evidence to conclude that the mean maximum temperature of the duck legs cooked by your cook is less than 175 degrees.
Employee is not capable of cooking the duck legs within the required temperature range.
Therefore, for the given situation of confidence level of 90% reject the null hypothesis, accept the alternative hypothesis.
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If November 30 falls on a Sunday, then December 25 of that same year falls on which day of the week? (November has 30 days)
Step-by-step explanation:
Three weeks would be the 21st and would be Sunday too, then
22 Mon
23 Tues
24 Wed
25 Thur
Find the positive solution, to the nearest tenth, of f(x)
g(x) = -2x + 25.
X≈
Submit
= g(x), where f(x) = 3* - 2 and
The result will be the x value when the difference between the values of f(x) and g(x) is less than 0.1, which will be the positive solution to the nearest tenth of f(x)=g(x).
To find the positive solution, to the nearest tenth, of f(x)=g(x) using Cora's process, the steps are as follows:
Input the initial value of x,if x=0.
Calculate f(x) and g(x):
f(x) = x² - 8 = 0 - 8 = -8
g(x) = 2x - 4 = 0 - 4 = -4
If f(x) is less than g(x), then x should be increased and vice versa.
Increase or decrease x accordingly and calculate the new values of f(x) and g(x).
Keep repeating steps 3 and 4 until the difference between the values of f(x) and g(x) is less than 0.1.
Hence, the result will be the x value when the difference between the values of f(x) and g(x) is less than 0.1, which will be the positive solution to the nearest tenth of f(x)=g(x).
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Cora is using successive approximations to estimate a positive solution to f(x) = g(x), where f(x)=x2 - 8 and g(x)=2x - 4. The table shows her results for different input values of x. Use Cora's process to find the positive solution, to the nearest tenth, of f(x) = g(x)