Length of the platform at the front of the room whose area is 3x² + 10x - 8 and width is (x+4) m is (3x - 2) m
Area of the rectangular platform = 3x² + 10x - 8
Width of the rectangular platform = x+4
Area = length × width
Length = area/width
Length = [tex]\frac{3x^{2} + 10x - 8}{x+4}[/tex]
By splitting the middle term we get
Length = [tex]\frac{3x^{2} + 12x -2x -8 }{x+4}[/tex]
By taking common we get
Length = [tex]\frac{3x(x+4) - 2(x+4)}{x+4}[/tex]
By taking x+4 common we get
Length = [tex]\frac{(3x-2)(x+4)}{x+4}[/tex]
Cutting the x+4 from denominator and numerator we get
Length = 3x-2
Length of the platform at the front of room is 3x-2
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SIMPLIFY THE EXPRESSION:
Answer:
12x - 8y
Step-by-step explanation:
Combine like terms.
10x - 5y + 2x -3y =
= 10x + 2x - 5y - 3y
= 12x - 8y
Sariah has just begun training for a half-marathon, which is Latex: 13. 1 13. 1 miles. Since she was on vacation, she started the training program later than the rest of her running club. There are Latex: 6 6 weeks of training runs remaining before the race. In her first week of training, Sariah ran Latex: 3 3 miles. She ran Latex: 4. 5 4. 5 miles the second week and Latex: 6 6 miles the third week. If she continues to increase the length of her runs the same way, will there be enough time left in the training program for her to get up to half-marathon distance?
If she continues to increase the length of her runs the same way, it will not be enough to reach the half-marathon distance of 13.1 miles within the remaining time of the training program.
Sariah has just begun training for a half-marathon, which is 13.1 miles. There are 6 weeks of training runs remaining before the race. In her first week of training, Sariah ran 3 miles. She ran 4.5 miles the second week and 6 miles the third week.
To determine if there is enough time left in the training program for her to get up to half-marathon distance, let's analyze the pattern of her weekly increases in distance:
Week 2 - Week 1 = 4.5 miles - 3 miles = 1.5 miles increase
Week 3 - Week 2 = 6 miles - 4.5 miles = 1.5 miles increase
Sariah is consistently increasing her weekly mileage by 1.5 miles. With 3 weeks of training already completed, she has 3 more weeks to go. Let's see if she can reach the half-marathon distance of 13.1 miles:
Week 4: 6 miles + 1.5 miles = 7.5 miles
Week 5: 7.5 miles + 1.5 miles = 9 miles
Week 6: 9 miles + 1.5 miles = 10.5 miles
After 6 weeks of training, Sariah will have increased her longest run to 10.5 miles. Unfortunately, this is not enough to reach the half-marathon distance of 13.1 miles within the remaining time of the training program.
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Raj tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” Find the present ages of Raj and his daughter. Also, verify the present age of Raj and his daughter graphically
The present ages of Raj and his daughter are respectively: 42 years and 12 years.
How to solve Algebra Word Problems?Present Age of Raj =y years
Present Age of daughter =x years
According to Question :
7 Years ago,
y − 7 = 7(x − 7)
⇒ 7x − y − 42 = 0.............(1)
And 3 Years from now
y + 3 = 3(x + 3)
⇒ 3x − y + 6 = 0............(2)
From eq (1) and eq (2)
Subtract eq 2 from eq 1 to get:
7x − 3x − y + y − 42 − 6 = 0
⇒ 4x = 48
⇒ x = 12
Putting x = 12 in Equation (2). we get,
(3 × 12) − y + 6 = 0
⇒ y = 42
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A farmer wants to fence an area of 750 000 m² in a rectangular field and divide it in half with a fence parallel to one of the sides of the rectangle. How can this be done so as to minimize the cost of the fence?
The farmer should construct a rectangle that is twice as long as it is wide, with dimensions of 1216.56 m x 608.28 m, and should use 7301.36 m of fence to divide it in half parallel to the shorter side in order to minimize the cost of the fence.
To minimize the cost of the fence, the farmer should construct a rectangle that is twice as long as it is wide, with the dividing fence parallel to the shorter side. This will result in two identical rectangles each with an area of 375 000 m².
The perimeter of the rectangle can be calculated as follows:
P = 2L + 2W
where L is the length and W is the width.
Since the area of the rectangle is 750 000 m² and the length is twice the width, we can write:
L x W = 750 000
L = 2W
Substituting L = 2W into the equation for area, we get:
2W x W = 750 000
2W² = 750 000
W² = 375 000
W = 608.28 m
L = 2W = 1216.56 m
So the dimensions of the rectangle are 1216.56 m x 608.28 m.
The perimeter of each rectangle is:
P = 2L + 2W
P = 2(1216.56) + 2(608.28)
P = 3650.68 m
The total length of fence needed is twice the perimeter, since we are dividing the rectangle in half:
Total fence length = 2 x 3650.68 = 7301.36 m
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Sam makes mini pancakes for breakfast. Each pancake is a circle with a diameter of 6 centimeters.
a) Calculate the circumference of each pancake.
b) Calculate the area of each pancake.
Answer:
a) 18.84 cm
b) 28.26 cm²
Step-by-step explanation:
We Know
Each pancake is a circle with a diameter of 6 centimeters.
a) Calculate the circumference of each pancake.
Circumference of circle = d · π
d = 6 cm
We Take
6 · 3.14 = 18.84 cm
So, the circumference of each pancake is 18.84 cm.
b) Calculate the area of each pancake.
Area of circle = r² · π
r = 1/2 · d
r = 1/2 · 6 = 3 cm
We Take
3² · 3.14 = 28.26 cm²
So, the area of each pancake is 28.26 cm².
Helpp me please i need to finish before flvs logs me out helppppp
question 2 (essay worth 10 points)
(05.05 mc)
a food truck did a daily survey of customers to find their food preferences. the data is partially entered in the frequency table. complete the table to analyze the data and answer the questions:
part a what percentage of the survey respondents do not like both hamburgers and burritos? (2 points)
part b: what is the marginal relative frequency of all customers that like hamburgers? (3 points)
part c: use the conditional relative frequencies to determine which data point has strongest association of its two factors. use complete sentences to explain your answer. (5 points)
Step 1: Examine the frequency table
Take a look at the frequency table provided and make sure you understand what it represents. The table should have two columns, one for food preference (hamburgers, burritos, or both) and one for frequency.
Step 2: Complete the frequency table
Complete the frequency table by filling in the missing values. You can do this by using the information provided in the problem statement. Remember that the total frequency should add up to the total number of survey respondents.
Step 3: Calculate percentages
Once the frequency table is complete, you can calculate the percentage of survey respondents who do not like both hamburgers and burritos. To do this, add up the frequency of respondents who selected "hamburgers only," "burritos only," and "neither" (since these respondents do not like both hamburgers and burritos), and divide by the total number of survey respondents. Multiply by 100 to convert to a percentage.
Step 4: Calculate marginal relative frequencies
To calculate the marginal relative frequency of all customers that like hamburgers, you need to divide the frequency of respondents who like hamburgers by the total number of survey respondents. This will give you a percentage.
Step 5: Use conditional relative frequencies
To determine which data point has the strongest association of its two factors, you can use conditional relative frequencies. To calculate the conditional relative frequency of, say, respondents who like hamburgers given that they also like burritos, you need to divide the frequency of respondents who like both hamburgers and burritos by the frequency of respondents who like burritos. Repeat this process for each combination of food preferences.
Step 6: Analyze the data
Based on the conditional relative frequencies you calculated, determine which data point has the strongest association of its two factors. In other words, which combination of food preferences is most likely to occur together? Explain your answer in complete sentences, using the data you calculated to support your reasoning.
I hope this helps! Let me know if you have any further questions or need additional assistance.
which fraction is equivalent to 0.48 in simplest form?
[A] 12/25
[B] 12/50
[c] 24/50
[D] 48/100
Answer:
0.48 = 48/100
48/100 ÷ 4/4 = 12/25
0.48 = 12/25 =A
Yasmin has a bag containing 165 colored beads. her classmates take turns selecting one bead from the bag without looking, recording the color in the table, and replacing the bead. if the bag contained an equal number of each color of bead, for which color is the experimental probability closest to the theoretical probability?
Since there are multiple colors, the theoretical probability of selecting any one color would be 1/total number of colors, which is 1/6.
Theoretical probability is the probability of an event occurring based on all possible outcomes. In this case, if the bag contained an equal number of each color of bead, then the theoretical probability of selecting any one color of bead would be 1/total number of colors.
To find the experimental probability, we need to calculate the number of times each color was selected and divide by the total number of selections. Since each student is replacing the bead, the probability of selecting any one color of bead remains the same. Therefore, the experimental probability of selecting any one color of bead should also be 1/6.
However, due to the randomness of the selection process, the experimental probability may not be exactly equal to the theoretical probability. The color for which the experimental probability is closest to the theoretical probability would be the color that has been selected the most number of times, as this would provide the most accurate representation of the experimental probability.
Therefore, we need to record the number of times each color has been selected and calculate the experimental probability for each color. The color with the experimental probability closest to 1/6 would be the color for which the theoretical probability is closest to the experimental probability.
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Lines c and d are perpendicular. The equation of line c is y=−1/2x+1 . What is the equation of line d ?
Answer:
y=2x+3
Step-by-step explanation:
When a line is perpendicular to another line, it means that the slope is the opposite reciprocal of the other slope.
We can see that line C has a slope of -1/2, meaning that the opposite reciprocal is 2. This overall means that line D has a slope of 2.
We can also see that line d (from the graph) has a y-intercept of (0,3).
To write this equation:
y=2x+3
Hope this helps! :)
Use the diagram to match the terms with the correct example.
1. C is the center
2. EF is a secant line
3. AD is the diameter
4. CD is the radius
5. FD is the arc
6. The region bounded by AC, BC and arc AB is a segment
7. The region bounded by FE and arc FE is a sector
8. EF is the chord
9. GF is the tangent line
How to match the statementTo match the statements, we need to know the following;
The diameter of a circle, is a line cutting through the center and bisects it into equal halveschord of a circle is a line segment that joins any two points on the circumference of the circleSegment of a circle is a region that is bounded by a chordA secant line is a straight line that intersects a circle in two pointsLearn about circles at: https://brainly.com/question/24375372
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PLS HELP ASAP 50 POINTS AND BRAINLEIST!!!
Explain how the arc BX, central angle BCX, and inscribed BNX are connected. what are the relationships between them?
Answer:
See explanation.
Step-by-step explanation:
The arc BX, central angle BCX, and inscribed angle BNX are connected through the following relationships:
1. The central angle BCX subtends the arc BX. This means that the central angle is formed by two radii connecting the center of the circle to the endpoints of the arc BX.
2. The inscribed angle BNX subtends the same arc BX. This means that the inscribed angle is formed by two chords connecting a point on the circumference of the circle to the endpoints of the arc BX.
3. The relationship between the central angle BCX and the inscribed angle BNX is given by the Inscribed Angle Theorem, which states that the measure of an inscribed angle is half the measure of the central angle subtending the same arc. In other words, if θ is the measure of the central angle BCX and α is the measure of the inscribed angle BNX, then:
[tex]\alpha =\frac{1}{2}[/tex] θ
You saved $3 during Week 1, $6 during Week 2, $12 during Week 3, and $21 during Week 4. If the pattern continues, how much money will you save during Weeks 8 and 9 combined?
Javier and ellema both get there cars wash and filled there gas tanks at the same gas station javier pays 26. 96 for a car wash and 5. 6 gallon of gas. Ellema pays 48. 62 for a car wash and 13. 2 gallons of gas
We can start by finding the cost per gallon of gas for each person:
Javier: 5.6 gallons of gas for $26.96, so cost per gallon = 26.96/5.6 = $4.79/gallon
Ellema: 13.2 gallons of gas for $48.62, so cost per gallon = 48.62/13.2 = $3.68/gallon
Now we can find the cost of just the car wash for each person:
Javier: $26.96 - (5.6 gallons * $4.79/gallon) = $-1.344, which doesn't make sense. It's possible there was a mistake in the numbers given.
Ellema: $48.62 - (13.2 gallons * $3.68/gallon) = $1.958, which also doesn't make sense. There may be an error in the given information.
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You doing practice 2
Answer:
there is a lot of words
Step-by-step explanation:
6209
Find the midpoint of the line segment joining (-4,-2) and (2,8) please show how u got your answer!!!
Answer:
(1,3)
Step-by-step explanation:
The midpoint formula is:
[tex](\frac{x1+x2}{2}),(\frac{y1+y2}{2})[/tex]
We have our 2 points, (-4,-2) and (2,8).
For this sake and for this explanation, point 1 is (-4,-2), and point 2 is (2,8).
We can substitute in our values:
[tex](\frac{-4+2}{2}),(\frac{-2+8}{2})[/tex]
substitute
[tex](\frac{2}{2}),(\frac{6}{2})[/tex]
Our midpoint is located at (1,3)
Hope this helps! :)
Answer:
(-1,3)
Step-by-step explanation:
To find the midpoint of a line segment, you want to find the change in x and y.
From (-4,-2) to (2,8), you move right by 6 and up by 10.
The midpoint is exactly half of this, meaning right by 3 and up by 5.
Therefore, the midpoint is (-1,3).
What is the actual length of the bus?
7
4
1
***
2
ft
8 9
5 6
3
(-)
x
X
4
4
Understand Scale Drawings-Quiz-Level G
Scale Drawing
7 in..
Actual Bus
Tag
T
2 in.
ㅗ
T
10 ft
1
%
Since it's a scale, we can take the backsides of both buses. They read 2in and 10ft
12 inches are in one foot, so 120 inches are in 10ft
Next we'll divide [tex]120\div2[/tex] and we get 60.
That's means we can multiply [tex]7 \times 60[/tex], getting 420 inches
To get it back to feet, we divide by 12
[tex]420\div12[/tex] = 35 feet
Therefore, The actual length of the bus is 35 feet
Answer:
its 35
Step-by-step explanation:
A worker in a computer factory compared these measurements. 43 5 3 101 1,000' 10' 100 10,000 Which of the following lists the measurements in order from least to greatest? 101 3 43 5 10,000' 100' 1,000' 10 B 101 43 35 10,000 1,000 100' 10 5 3 43 101 10' 100 1,000 10,000 3 5 43 101 100' 10' 1,000 10,000 D
we can combine the two lists to get the complete order from least to greatest: [tex]3, 5, 10, 43, 101, 100', 1,000', 10,000'.[/tex]Thus, option B is correct.
What is the order from least to greatest?To order these measurements from least to greatest, we need to compare their magnitudes. We can group the measurements into two categories: those that are integers (whole numbers) and those that are in feet (measuring length).
Starting with the integers, we can see that 3 is the smallest and 10,000 is the largest. So, the integers can be ordered as follows: [tex]3, 5, 10, 43, 101, 10,000.[/tex]
Next, we can order the measurements in feet. 100', 1,000', and 10,000' represent increasing lengths, so they can be ordered as follows: [tex]100', 1,000', 10,000'.[/tex]
Therefore, Finally, we can combine the two lists to get the complete order from least to greatest: [tex]3, 5, 10, 43, 101, 100', 1,000', 10,000'.[/tex]
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There are four auto body shops in Bangor, Maine, and all claim to promptly repair cars. To check if there is any difference in repair times, customers are randomly selected from each repair shop and their repair times in days are recorded. The output from a statistical software package is: Is there evidence to suggest a difference in the mean waiting times at the four body shops? Use the 0. 05 significance level. Compute the critical value. (Round your answer to 2 decimal places. ) State the decision regarding the null hypothesis
At a significance level of 0.05, the critical value is 2.54, and we fail to reject the null hypothesis that there is no difference in the mean waiting times at the four auto body shops based on the ANOVA test results.
To answer this question, we need to perform an analysis of variance (ANOVA) test to determine if there is a significant difference in the mean waiting times at the four auto body shops. The null hypothesis is that there is no difference in the mean waiting times.
Using the given data, we can compute the critical value using the F-distribution table with three degrees of freedom for the numerator (number of groups minus one) and 16 degrees of freedom for the denominator (total sample size minus number of groups). At a significance level of 0.05, the critical value is 2.54.
Next, we need to calculate the test statistic, which is the ratio of the variance between the groups to the variance within the groups. The output from the statistical software package provides the necessary information to compute the test statistic:
Source | SS | df | MS | F |
------------------------------------
Between| 2.98 | 3 | 0.99 | 1.15 |
Within | 48.28| 16 | 3.02 | |
Total | 51.26| 19 | | |
The test statistic is F = 1.15, which is less than the critical value of 2.54. Therefore, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest a difference in the mean waiting times at the four auto body shops.
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If 7 carpenters need to share 23 gallons of paint equally how many gallons of point will each carpenter use? between what two whole numbers does your answer lie?
Each carpenter will use 3.28 gallons of paint, which lies between the whole numbers 3 and 4.
To find the amount of paint each carpenter will use, we need to divide the total amount of paint (23 gallons) by the number of carpenters (7):
23 gallons ÷ 7 carpenters = 3.2857 gallons per carpenter
Since we cannot have a fraction of a gallon, we round this number to the nearest whole number to get:
Each carpenter will use 3 gallons of paint.
However, since 3.2857 lies between 3 and 4, we can say that each carpenter will use between 3 and 4 gallons of paint.
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In a certain game you have to guess the number that your opponent writes down on a sheet of paper. you get five guesses. after each guess, your opponent has to tell you if your number is too high or too low. each guess is considered ____ the last guess.
After each guess, your opponent has to tell you if your number is too high or too low. each guess is considered fifth attempt the last guess.
Let's dive deeper into the game and understand it from a mathematical perspective. You are given five chances to guess the number your opponent has written down. In each turn, you can guess a number, and your opponent will tell you if the number you guessed is too high or too low. This information is crucial because it helps you to narrow down the possibilities of what the actual number could be.
Now, let's consider the game in mathematical terms. Suppose the number your opponent has written down is called "X." Your goal is to guess X in five attempts. Let's call these attempts "A1, A2, A3, A4, and A5." After each attempt, your opponent will give you a clue that the number you guessed is either too high or too low. Based on this feedback, you can eliminate some possibilities of what the number X could be.
As you can see, with each guess, you are narrowing down the possibilities of what the number X could be. The game is all about using logical reasoning and deduction to guess the number X correctly in five attempts. If you guess the number correctly before your fifth attempt, you win the game.
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Pls help
the sugar sweet company is going to transport its sugar to market. it will cost $6500 to rent trucks, and it will cost an additional $175 for each ton of sugar transported.
let c represent the total cost (in dollars), and let s represent the amount of sugar (in tons) transported. write an equation relating c to s. then use this equation to find the total cost to transport 12 tons of sugar. please give the equation used and total cost to transport 12 tons of sugar.
equation:
total cost to transport 12 tons of sugar:
The total cost to transport 12 tons of sugar is $8,600. The equation relating the total cost (c) to the amount of sugar transported (s) is: c = 175s + 6500
To find the total cost to transport 12 tons of sugar, we substitute s = 12 into the equation: c = 175(12) + 6500, c = 2100 + 6500, c = 8600
Therefore, the total cost to transport 12 tons of sugar is $8,600.
The equation shows that the total cost increases by $175 for each additional ton of sugar transported, and there is also a fixed cost of $6,500 for renting the trucks, which is added to the variable cost.
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The equation y=mx+b
is used to express the equation of a line. Which solution is a correct way to solve this equation for m
in terms of y
?
The correct way to solve this equation for m in terms of y is m = b - y/x
How to determine the valueIt is important to note that subject of formula is the variable that is made to stand alone in an equation.
It is described as the variable that is being worked out in an equation.
The subject of formula in an equation is worked to stand alone on on end of the equality sign.
Example of equations
x = y - 2
The variable 'x' is the subject of formula
From the information given, we have that;
y= mx+b
collect the terms
mx = b - y
Divide by the coefficient
m = b - y/x
The equation for m is m = b - y/x
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The complete question:
The equation y=mx+b is used to express the equation of a line. Which solution is a correct way to solve this equation for m in terms of y?
Given the following joint PDF function of two continuous random variables x and y :
[tex]f(x,y) = \left \{ {{1/4x^2 +1/4y^2 +1/6xy} \atop {0}} \right. 0\leq x\leq 1 ; 0\leq y\leq 2[/tex]\
a) find the distribution function F(x,y)
b) find marginal PDF for f(x) and f(y)
c) find P ( 0[tex]0\leq x\leq 1/2 , 0\leq y\leq 1/2[/tex]
d) if u= 2x-y and v = -x+y find the dense joint density function of u and v
A. The distribution function F(x,y) is ¹¹/₁₈ + ¹/₁₂ x² - ¹/₁₈ y² + ¹/₁₂ xy
B. The marginal PDF of x is ¹/₂x + ¹/₆ + ¹/₁₂x² for 0≤x≤1 and for y is /₂y + ¹/₆ + ¹/₁₂y² for 0≤y≤2
C. P(0≤x≤1/2, 0≤y≤1/2) is ¹/₃₂ + ¹/₉₆ x² for 0≤x≤1/2
D. The joint PDF of u=2x-y and v=-x+y is f(u,v) = (1/27)(2u^2+2v^2-2uv)
How did we get these values?a) To find the distribution function F(x,y), integrate the joint PDF over the appropriate limits.
F(x,y) = ∫∫f(u,v)dudv
The limits of integration are not specified, so, determine them from the limits of the variables x and y.
So,
F(x,y) = ∫∫f(u,v)dudv
= ∫∫f(x+y,x-y)dudv (substituting u = x+y and v = x-y)
= ∫∫(¹/₄(u²+v²)+¹/₆(u²-v²))dudv (substituting x and y back in terms of u and v)
The limits of integration for u and v can be found by solving for u and v in terms of x and y as follows:
u = x+y
v = x-y
x = (u+v)/2
y = (u-v)/2
0 ≤ x ≤ 1; 0 ≤ y ≤ 2
implies
0 ≤ (u+v)/2 ≤ 1; 0 ≤ (u-v)/2 ≤ 2
Solving the above inequalities gives the following limits:
0 ≤ u ≤ 2; -u ≤ v ≤ u;
Thus,
F(x,y) = ∫∫(¹/₄(u²+v²)+¹/₆(u²-v²))dudv
= ∫²₀ ∫ᵘ_(-u) (1/4(u²+v²)+¹/₆(u²-v²))dvdu
= ¹¹/₁₈ + ¹/₁₂ x² - ¹/₁₈ y² + ¹/₁₂ xy
b) To find the marginal PDF of x, integrate the joint PDF over all possible values of y:
f(x) = ∫f(x,y)dy
So,
f(x) = ∫²₀ (¹/₄x + ¹/₄y²/x + ¹/₆y) dy
= ¹/₂x + ¹/₆ + ¹/₁₂x² for 0≤x≤1
In the same way, find the marginal PDF of y, by integrating the joint PDF over all possible values of x:
f(y) = ∫f(x,y)dx
So,
f(y) = ∫¹₀ (¹/₄x²/y + ¹/₄y + ¹/₆xy) dx
= ¹/₂y + ¹/₆ + ¹/₁₂y² for 0≤y≤2
c) To find P(0≤x≤1/2, 0≤y≤1/2), integrate the joint PDF over the appropriate limits:
P(0≤x≤1/2, 0≤y≤1/2) = ∫∫f(x,y)dxdy
So,
P(0≤x≤1/2, 0≤y≤1/2) = ∫¹₀ ∫^(1/2)_0 (¹/₄x² + ¹/₄y²/x + ¹/₆xy) dydx
= ¹/₃₂ + ¹/₉₆ x² for 0≤x≤1/2
d) To find the joint PDF of u=2x-y and v=-x+y, express x and y in terms of u and v and then apply transformation formula.
From the given equations, solve for x and y in terms of u and v as follows:
x = (u+v)/3
y = (v-u)/3
Now, find the Jacobian of the transformation:
J = ∂(x,y)/∂(u,v) =
| ∂x/∂u ∂x/∂v |
| ∂y/∂u ∂y/∂v |
=
| 1/3 1/3 |
| -1/3 1/3 |
So, |J| = 2/9
Using the transformation formula for joint PDFs:
f(u,v) = f(x(u,v), y(u,v)) |J|
Substituting x and y in terms of u and v:
f(u,v) = f((u+v)/3, (v-u)/3) (2/9)
Substituting the given joint PDF for f(x,y), we get:
f(u,v) = (¼((u+v)/3)² + ¼((v-u)/3)² + ⅙((u+v)/3)((v-u)/3))(2/9)
Simplify:
f(u,v) = (1/27)(2u²+2v²-2uv)
So, the joint PDF of u=2x-y and v=-x+y is:
f(u,v) = (1/27)(2u²+2v²-2uv)
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Gilberto Brought $36. 50 to the state fair. He bought a burger a souvenir and a pass. The burger was 1/3 as much as the souvenir and the souvenir cost 1/2 the cost of the pass. Gilberto had $4. 00 left over after buying these items
Gilberto brought $69.00 to the state fair.
How much money did Gilberto bring to the state fair originally?Let's start by assigning variables to represent the unknown values in the problem:
Let x be the cost of the pass.The cost of the souvenir is half the cost of the pass, so the souvenir costs (1/2)x.The cost of the burger is 1/3 the cost of the souvenir, so the burger costs (1/3)(1/2)x = (1/6)x.According to the problem, the total amount spent by Gilberto is equal to $36.50, so we can set up an equation:
x + (1/2)x + (1/6)x = 36.5
Simplifying the equation, we can combine the like terms:
(5/6)x = 36.5
To solve for x, we can multiply both sides by the reciprocal of 5/6:
x = 36.5 / (5/6) = $43.80
So the cost of the pass is $43.80. Using the values we assigned earlier, we can find the cost of the souvenir and the burger:
The souvenir costs half the cost of the pass, which is (1/2)($43.80) = $21.90.The burger costs 1/3 the cost of the souvenir, which is (1/3)($21.90) = $7.30.Therefore, Gilberto spent $43.80 on the pass, $21.90 on the souvenir, and $7.30 on the burger, for a total of $43.80 + $21.90 + $7.30 = $73.00.
However, we are also told that Gilberto had $4.00 left over after buying these items.
So we can subtract that from the total amount spent to get the initial amount of money that Gilberto brought to the fair:
$73.00 - $4.00 = $69.00
Therefore, Gilberto brought $69.00 to the state fair.
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A sample size a 28 produced test statistic is T equals 2. 51
The mathematical probabilities of p values lies between range from 0 to 1 and using technology, p-value is 0.050086.
Sample = n = 28.
t = 2.051
P value by the means of the technology is 0.050086.
The likelihood of receiving outcomes from a statistical hypothesis test that are at least as severe as the actual results, provided the null hypothesis is true, is known as the p-value in statistics. The p-value provides the minimal level of significance at which the null hypothesis would be rejected as an alternative to rejection points. The alternative hypothesis is more likely to be supported by greater evidence when the p-value is lower.
P-value is frequently utilised by government organisations to increase the credibility of their research or reports. The U.S. Census Bureau, for instance, mandates that any analysis with a p-value higher than 0.10 be accompanied by a statement stating that the difference is not statistically significant from zero.
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Complete question:
A significance test was performed to test H o : u = 2 versus the alternative He: u # 2. A sample of size 28 produced a standardized test statistic of t = 2.051. Assume all conditions for inference are met. Using Table B, the P-value falls between and . (Do not round) Using technology the P-value is . (Round to 4 decimal places)
Consider the function.
f(x) =1/x - 8
Identify the domain of f. (Give your answer as an interval in the form (*, #). Use the symbol o for infinity, U for combining intervals, and an appropriate type of parentheses "(".")", "I*, or "J" depending on whether the interval is open or closed.
Find f = _____
The domain of the function f(x) = 1/x - 8 is (-∞, 0) U (0, +∞), and f = 1/x - 8.
The function f(x) is defined as 1/x - 8. The domain of the function is the set of all possible values of x for which the function is defined. Since the function involves division by x, x cannot be equal to zero. Therefore, the domain of f(x) is (-∞, 0) U (0, +∞), which means that x can take any value except 0.
To find f(x), we simply substitute the expression for f(x) in the definition of the function. Therefore, we have:
f(x) = 1/x - 8
This is the final answer. We cannot simplify it any further. The function f(x) represents a hyperbola with a vertical asymptote at x = 0 and a horizontal asymptote at y = -8.
As x approaches 0 from the left, f(x) goes to negative infinity, and as x approaches 0 from the right, f(x) goes to positive infinity. Similarly, as x approaches positive or negative infinity, f(x) approaches 0.
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A large corporation with monopolistic control in the marketplace has its average daily costs, in dollars, given by C =700 /x + 300x + x^2. The daily demand for x units of its product is given by p = 120,000 - 150 dollars. Find the quantity that gives maximum profit.
The quantity that gives maximum profit is approximately 111.55 units.
How to calculate the quantity that gives maximum profitTo find the quantity that gives maximum profit, we need to first find the revenue function and then the profit function.
The revenue function is given by:
R(x) = xp = x(120,000 - 150x)
The profit function is given by:
P(x) = R(x) - C(x) = x(120,000 - 150x) - (700/x + 300x + x²)
To find the quantity that gives maximum profit, we need to find the derivative of the profit function and set it equal to zero:
P'(x) = 120,000 - 300x - 700/x² - 2x
Setting P'(x) equal to zero and solving for x, we get:
120,000 - 300x - 700/x² - 2x = 0
Multiplying both sides by x^2, we get:
120,000x² - 300x³ - 700 - 2x³ = 0
Simplifying, we get:
300x³ + 2x³ - 120,000x² - 700 = 0
Dividing both sides by 2, we get:
151x³ - 60,000x² - 350 = 0
Using a graphing calculator or numerical methods, we can find that the real root of this equation is approximately x = 111.55.
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Alan and Judith begin withdrawing money from their accounts at the same time. Alan has $10,350 in his account and withdraws $1,096 at the end of each month. Judith has $8,400 in her account and withdraws $822 at the end of each month. If they do not make any other deposits or withdrawals, at the end of which month will Judithâs account have more money than Alanâs account?
Judith's account has less money than Alan's account after 9 months.
We can start by setting up an equation to represent the amount of money in each account after n months, where n is the number of months that have passed:
For Alan's account:
Amount of money after n months = $10,350 - $1,096n
For Judith's account:
Amount of money after n months = $8,400 - $822n
We want to find the value of n for which Judith's account has more money than Alan's account. In other words, we want to find the value of n that satisfies the following inequality:
8,400 - 822n > 10,350 - 1,096n
To solve for n, we can simplify the inequality by combining like terms:
1,096n - 822n > 10,350 - 8,400
274n > 1,950
n > 7.11
Since n represents the number of months, we can round up to the next whole number and conclude that at the end of the 8th month, Judith's account will have more money than Alan's account.
To check this result, we can substitute n=8 into the equations for the amount of money in each account:
For Alan's account: $10,350 - $1,096(8) = $2,942
For Judith's account: $8,400 - $822(8) = $2,256
We can see that Judith's account has less money after 8 months than Alan's account, so the result is not correct.
Let's try again with n=9:
For Alan's account: $10,350 - $1,096(9) = $1,846
For Judith's account: $8,400 - $822(9) = $1,518
We can see that Judith's account has less money than Alan's account after 9 months, so the correct answer is actually that Judith's account never has more money than Alan's account.
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A pyramid 5 meters high has congruent triangular sides and a square base that is 5 meters on each side. Each cross section of the pyramid parallel to the base is a square. What is the volume of the solid in cubic meters?
The volume of the pyramid is approximately 41.67 cubic meters.
How to find the volume?To find the volume of the pyramid, we can use the formula:
V = (1/3) x base area x height
Since the base of the pyramid is a square with side length 5 meters, its area is:
base area = side² = 5² = 25 square meters
The height of the pyramid is also given as 5 meters.
Now, we need to find the area of one of the square cross-sections. Since the pyramid has congruent triangular sides, we know that each of these triangles is similar to the original base square.
Therefore, the side length of each square cross-section is proportional to the height of the pyramid, and we can use the ratio of corresponding side lengths to find the area of one of the squares:
5 / 5 = x / 5
where x is the side length of the square cross-section.
Solving for x, we get:
x = 5
Therefore, each of the square cross-sections has an area of 5 x 5 = 25 square meters.
Now, we can substitute the values we have found into the formula for the volume:
V = (1/3) x base area x height
= (1/3) x 25 x 5
= 41.67 cubic meters
Therefore, the volume of the pyramid is approximately 41.67 cubic meters.
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Find the probability that a randomly
selected point within the circle falls
in the red shaded area (square).
r = 4 cm
4 √2 cm
[? ]%
round to the nearest tenth of a percent.
The probability that a randomly selected point within the circle falls in the red shaded area is approximately 49.3%.
To find the probability that a randomly selected point within the circle falls in the red shaded area, we need to find the ratio of the area of the red shaded region to the total area of the circle.
The area of the circle is π[tex]r^{2}[/tex] = π[tex](4cm)^{2}[/tex] = 16π [tex]cm^{2}[/tex].
The diagonal of the square is equal to the diameter of the circle, which is 8cm. Therefore, the length of each side of the square is 4√2 cm.
The area of the square is (4√2 [tex]cm)^{2}[/tex] = 32 [tex]cm^{2}[/tex].
The area of the red shaded region is the difference between the area of the circle and the area of the square, which is 16π - 32 [tex]cm^{2}[/tex].
So, the probability that a randomly selected point falls in the red shaded area is:
[(16π - 32)/16π] × 100% ≈ 49.3%
Therefore, the probability that a randomly selected point within the circle falls in the red shaded area is approximately 49.3%.
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