Is 34/18 greater or less than or equal to 1 5/6

In what context? Do you mean calculus If you are talking about graphing on a graph plane it would be the two accelerates on the x axis so (left or right) and then the 1.5 accelerates on the y axis so 1.5 on the y axis would be one and halfway to the 2 mark on the y axis so in the middle of 1 to 2 on the y axis the y axis goes (up and down)

Answer:

$1.33

Step-by-step explanation:

32-20 = 12

12/9 = $1.33

[tex]\begin{cases} \stackrel{apples}{10^3}\\ \stackrel{grapes}{10^2}\\ \stackrel{oranges}{10^1} \end{cases}\qquad \begin{cases} \stackrel{lbs}{32}\\ \stackrel{lbs}{25}\\ \stackrel{lbs}{42} \end{cases}\qquad \begin{array}{rllll} 10^3\cdot 32\\ 10^2\cdot 25\\ +\qquad 10\cdot 42\\\cline{1-1} 34920&lbs \end{array}[/tex]

Answer:

Step-by-step explanation:

The number of black pieces is 5 more than 3 times the white pieces:

Let the number of rounds is x.

Initial number of white nd black pieces:

Substitute the values of b and w into first equation and find the value of x:

Find the number of pieces:

Correct choice is D

Answer:

A game consists of black and white pieces. The number of black pieces is 5 more than 3 times the white pieces. Seven white and 15 black pieces are removed each round. After several rounds, there are 3 white and 56 black pieces left. How many pieces were there in the beginning?

A. 52

B. 158

C. 210

D. 213

E. 218

Answer:

(2,5)

(3,8)

(4,13)

(5,12)

(6,18)

(7,20)

Plug those into the scatter plot graph

Step-by-step explanation:

The left side is the x axis and the right side is the y axis

Answer:

160

Step-by-step explanation:

We know that [tex]\left \{ {{t=2.5} \atop {v=64}} \right.[/tex]

Formulate and substitute: [tex]d=2.5[/tex]×[tex]64[/tex]

Calculate the product or quotient: [tex]160[/tex]

Answer: [tex]160[/tex]

Step-by-step explanation:

Avg = 20 + 14 + 28 + 18 /4

Avg = 80/4 = 20

Answer:

1/4 to the 0 power is equal to 1. Therefore, it is not bigger than 1

Answer:

Area= 18 x 18=324 sq.cm

Step-by-step explanation:

p=36 x2=72 (as it is twice that of the original paper)

since it is a square, length of 1 side = 72/4= 18

so, the area = l x l= 18 x 18= 324 sq.cm

Answer:

Area= 18 x 18=324 sq.cm

Step-by-step explanation:

p=36 x2=72 (as it is twice that of the original paper)

Since it is a square, length of 1 side = 72/4= 18

Therefore, the area = l x l= 18 x 18= 324 sq.cm

Hope this helps :)

Answer:

4,0 is the right ok I am a professor

Answer:

See attached

Expressions matching the properties

The associative property:

The commutative property:

Distributive property:

Answer:

160000

Step-by-step explanation:

HCF (2x, x) = x.

Factors of 2x = 2 × x × 1

Factors of x = x × 1

Common factors = x, 1

HCF = x × 1 = x

See the attachment too.

________

Hope it helps ⚜

Answer:

Add 6 to both sides

Step-by-step explanation:

The (usual) first thing to do when solving any equation is to simplify both sides of the equation. However, since we have nothing to simplify, we move onto the next step that'll be the first step: isolating the variable, x. To do so, we must do the inverse of subtracting 6 (which is adding 6).

Answer: B.

Step-by-step explanation:

brainliest me

Answer:

The equation of a straight line is always

[tex]y=mx+b[/tex]

The constant m always refers to the slope, and the constant b always refers to the y-intercept.

Simply substitute the numbers in:

[tex]y=-\frac{1}{2}x+3[/tex]

There's your equation!

[tex]0.18[/tex]

is the decimal point

Answer:

(3, 9)

Step-by-step explanation:

Set 3x and 2x+3 equal to each other forming an equation in x.

3x=2x+3

Solve for x.

x=3

Substitute the given value of x into the equation y=3x.

y=3x3

Solve for y.

y=9

(x, y) = (3, 9)

Hope this helps :)

Answer:

Step-by-step explanation:

Answer:

Ms. April will not have enough students.

Step-by-step explanation:

This is because 180 days of the year divided by 3 students per day = 60 students per year. The class only has 20 students, therefore, there is not enough students needed to collect milk.

Answer:

Ms. April will not have enough students.

Step-by-step explanation:

This is because 180 days of the year divided by 3 students per day = 60 students per year. The class only has 20 students, therefore, there is not enough students needed to collect milk.

Answer:

800

Step-by-step explanation:

800+799=1599

Answer:

Unsure but it might be -8/3

Step-by-step explanation:

Answer:

He must get a 96% on the fourth test to raise his average to an 87

Step-by-step explanation:

I'm not sure if I'm using substitution method but I guess it's x = 12.4

Cost is 65x + 3500 where x is = 326.

65(326) + 3500

21,190 + 3500 = $24,690 is the cost.

Revenue is 365x where x is 326.

365(326) = $118,990

Now we subtract the two:

118,990 - 24,690 = $94,300

This means that the answer is C) $94,300.

I hope this helps! :)

Answer: D. 16.33

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

35-3×9=35-27

=8

Hope this helps!!!

Answer:

(a) [tex]\log_72 \approx 0.3562[/tex]

(b) [tex]\log_7(\frac{147}{16} ) = 2[/tex]

Step-by-step explanation:

For the point a:

For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex]

16 can be re-write as [tex]2^4[/tex]. Then you have:

[tex]\log_72^4[/tex]

Using the power property of the logarithm we have:

[tex]\log_ba^c = c\log_ba[/tex]

[tex]\log_72^4 = 4\log_72[/tex]

And this expression is equal to:

[tex]4\log_72 \approx 1.4248\\\log_72\approx \frac{1.4248}{4} \approx 0.3562\\[/tex]

For the point b:

For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex] and [tex]\log_73 \approx 0.5646[/tex]

The first is use the quotient property in the given log.

[tex]\log_c\frac{a}{b} = \log_ca-\log_cb[/tex]

[tex]\log_7\frac{147}{16} = \log_7147 -\log_716[/tex]

We already know the value of [tex]\log_716[/tex] then we have to calculate the value of [tex]\log_7147[/tex].

So we factorize the number 147 in [tex]3 \cdot 7 \cdot 7[/tex] (for factorize the number start with the smaller prime and check if the remainder is 0, it is then is a primer factor of the number).

Now re-write [tex]\log_7147[/tex] as [tex]\log_73 \cdot 7^2[/tex] and by the product property get:

[tex]\log_bmn = \log_b m +\log_b n\\\log_73 \cdot 49 = \log_7 3 +\log_7 49 = 0.5646 + 2 = 2.5646[/tex]

Know replace each value in the subtraction and get the result:

[tex]\log_7147 -\log_716 = 2.5646 - 0.5646 = 2[/tex]

[tex]\\ \sf\longmapsto (5x^3+5x^2+5)-(6x^3-6x^2+8x-5)[/tex]

[tex]\\ \sf\longmapsto 5x^3+5x^2+5-6x^3+6x^2-8x+5[/tex]

[tex]\\ \sf\longmapsto 5x^3-6x^3+5x^2+6x^2-8x+5+5[/tex]

[tex]\\ \sf\longmapsto -x^3+11x^2-8x+10[/tex]

[tex]\\ \sf\longmapsto x^3-11x^2+8x-10[/tex]

[tex]\large \boldsymbol{} \longmapsto (5x^3+5x^2+5) -(6x^3-6x^2+8x-5 ) \\\\\\ \longmapsto5x^3+5x^2+5-6x^3+6x^2-8x+5 \\\\\\ \longmapsto 5x^3-6x^3+5x^2+6x^2-8x+5+5 \\\\\\ \longmapsto \boxed{ - x^3+11x^2-8x+10}[/tex]