Is my 1-8 right? And if not what is the right answer and show how you got the answer. Also hat would be the answer for 9 and 10 and why because I can’t seem to figure them out.

(e) The net displacement at a point on the string is zero.

The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.

A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.

At the post, the pulses are reflected and return along the string without losing any of their amplitude.

Now, let's say the post is firmly fastened to the string.

The pulse will then be inverted upon reflection if one of the endpoints is fixed. As a result, when they collide, they cancel one another, leaving the amplitude at zero. As a result, the displacement at a string position where two pulses intersect is zero.

The correct option is (e).

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Answer:

2.9 Hrs

Explanation:

Time = Distance/velocity

6265  / 2150 ≈ 2.9 hrs

The outer gaseous giants are characterized by abundant gases like hydrogen, helium, methane, etc while the inner terrestrial planets are characterized by abundant solid elements like iron, nickel, silicon, etc.

Our solar system consists of the Sun and eight planets orbiting around it that are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

Out of the eight, the four planets closest to the sun i.e Mercury, Venus, Earth, and Mars are terrestrial, which means that their surfaces are rock solid and are composed of elements like iron, nickel, aluminum, silicon, etc.

They also have no moons or a few moons.

On the other hand, the remaining four planets i.e Jupiter, Saturn, Uranus, and Neptune are composed mainly of gases like hydrogen, helium, and methane. They are devoid of solid surfaces.

Also, they all have a large number of moons orbiting them.

Therefore, the outer gaseous giants are characterized by abundant gases like hydrogen, helium, methane, etc while the inner terrestrial planets are characterized by abundant solid elements like iron, nickel, silicon, etc.

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The ship is 354.87 km far away from its destination.

Pythagoras' Theorem states that the square of the hypotenuse side in a right-angled triangle is equal to the sum of the squares of the other two sides.

This triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse, in this case, is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.

H²=P²+B² where,

H= Hypotenuse of the triangle

P= Perpendicular of the triangle and,

B= Base of the triangle

According to the question,

The ship is 307 km due south and 178 km east due to the storm.

So, H²=P²+B²

⇒H²=(307)²+(178)²

⇒H=√125933

H=354.87 km.

Hence, the ship is 354.87 km far away from its original position.

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0.03185A current is required in the windings for that to occur.

It is given that 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T .

Putting above values in equation (1) , we get

[tex]1.00\times10^{-4}=\frac{4\pi \times10^{-7}\times1000I}{0.400} \\\\I=\frac{1.00\times10^{-4} \times0.400}{4\pi \times1000} \\\\I=0.03185A[/tex]

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The Energy flux from Star B is 16 times of the energy flux from Star A.

We have Two stars - A and B with 4900 k and 9900 k surface temperatures.

We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.

Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-

[tex]$\frac{Energy}{Area} = \sigma\times T^{4}[/tex]

Now -

Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -

[tex]$E= \sigma\times T^{4}[/tex]

Now -

For Star A →

[tex]T_{A}[/tex] = 4900 K

For Star B →

[tex]T_{B}[/tex] = 9900 K

Therefore -

[tex]$\frac{T_{B} }{T_{A} } =\frac{9900}{4900}[/tex]

[tex]\frac{T_{B} }{T_{A} }=[/tex] 2.02 = 2 (Approx.)

Now -

Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -

[tex]$\frac{E(B)}{E(A)} = \frac{\sigma\times T(B)^{4} }{\sigma \times T(A)^{2} }[/tex]

E(B) = E(A) x [tex](\frac{T(B)}{T(A)} )^{4}[/tex]

E(B) = E(A) x [tex]2^{4}[/tex]

E(B) = 16 E(A)

Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.

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Electron, photon and proton carry momentum .

Equation (1) can be written as   [tex]\lambda=\frac{h}{p}[/tex]   where λ  is known as de Broglie wavelength and p is momentum , h = Plank’s constant

For photon , the momentum is given by   [tex]p=\frac{E}{c}[/tex]   ...(2)  where c is the speed is the speed of light .

From equation (1) and (2) we can conclude that electron, photon and proton carry momentum .

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Based in the frame rate and the distance travelled by the ball, the speed of the ball is 398.6 cm/s.

The speed of an object or a moving body is the ratio of the distance covered by the moving body or object and the time taken to cover that distance.

Mathematically:

The speed of the ball in the diagram is determined as follows:

Total distance covered by the ball will the product of the distance between the points and the number of point covered by the ball after the original point.

Distance between points = 19 cm

number of points = 6

Total distance covered by the ball = 6 *19 cm

Total distance covered by the ball = 114 cm

Time taken = 1/frame rate * number of points

Time taken = 1/22 * 6

Time taken = 0.286 s

Speed = 114 cm/0.286 s

Speed = 398.6 cm/s

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If the troughs of the atomic orbitals overlap with each other and indicate out-of-phase combinations then they interact destructively.

However, (+), and (-) pair of atomic orbitals interact destructively.

In Chemistry, molecular orbital theory(MOT) indicates that atoms merge together to form atomic orbitals in a molecule. Atomic orbitals overlap to form molecular orbitals.

In a molecule, there are two types of orbitals: bonding orbitals (BO) and anti-bonding orbitals(ABO).

According to MOT theory, when atoms join together through atomic wavefunction then the electrons display wave-like nature.

The presence of electrons in the bonding orbitals increases the molecular stability increases as compared to their presence in anti-bonding orbitals.

To put it simply, when only the crusts of waves overlap in molecule orbitals they form constructive interference while overlapping of troughs causes destructive interference.

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The answer is τ is proportional to θ

A motion in which the restoring force is directly proportional to the body's displacement from its mean position is known as a simple harmonic motion, or SHM. This restoring force always moves in the direction of the mean position. The French mathematician Joseph Fourier made the discovery that any regularly recurring motion or wave, regardless of how complex its shape, may be thought of as the sum of a collection of straightforward harmonic motions or waves in 1822.

Consider a magnetic dipole that has been liberated from its equilibrium orientation in a homogeneous magnetic field.  Let the angle between the magnetic moment and the magnetic field be θ. The torque on the dipole due

to the external field is, τ=μXB

and magnitude of,     τ=μB sinθ

if the angle is small, then,    τ=μBθ

or,                                          τproportionalθ

which is the equation for a restoring torque, so the dipole tends to turn the dipole toward its equilibrium

orientation if displaced from its original position. So a magnetic dipole in a uniform magnetic field can oscillate as

a torsional pendulum in SHM if displaced from its equilibrium position.

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Answer:

It's all in the Explanation.

Explanation:

You round the number of the IP address and boom. You have your answer.

The wavelength of the final note is 0.389m

The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction. The distance a wave travels between its crests or troughs is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The wave's crest is its highest point, while its dip is its lowest. Because a wavelength represents a distance or length, it is expressed in length units like meters, centimeters, millimeters, nanometers, etc. Light's wavelength changes with color, or it differs for each hue. While violet has the shortest wavelength, red has the longest.

wavelength = v/f

wavelength = 343/800 m = 0.389m

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The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 125 m * (2 * 9.8 m/s²))

v₀ = √( 125 m * 19.6 m/s²)

v₀ = √2450 m²/s²

v₀ = 49.497 m/s

Applying the maximum time formula we get:

t max= v₀ / g

t max= 49.497 m/s / 9.8 m/s²

t max = 5.050 s

Applying  the time of flight formula, we get:

t(of) =2 * t max

t(of) =2 * 5.050 s

t(of) = 10.1 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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The time spent in the air by the ball is 10.01 seconds.

The total time spent in the air by the ball is the sum of the time it spends moving up and the time it spends falling down.

The time spent by the ball moving up - time spent by the ball travelling down.

Time spent by the ball traveling down a distance of 125 meters is calculated using the formula given as follows:

t = √2h/g

Total time spent = 2 * √2h/g

where:

h = 125 m

g = 9.81 m/s²

T = 2 * √(2 * 125/9.81)

T = 10.01 s

Therefore, the time spent in the air by the ball is the sum of the time spent moving up and the time it spends falling down which are both equal.

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The length of the rod as a function is  379.57 Δt

(b) The speed of a wave in metal=3560 m/s

Let L be the length of the rod.

[tex]-\frac{l}{3560}+\frac{l}{343}=\Delta t \\&l=\Delta t\left(\frac{1}{-\frac{1}{3560}+\frac{1}{343}}\right)[/tex]

[tex]\\&l=379.571 \Delta t \\&\text[/tex]

As a result, the rod's length as a function is 379.57 Δt.

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Fundamental frequency will be [tex]\frac{1}{{2} }[/tex] times that of original frequency on doubling the length of the string which is option (e) .

From equation (1)  it can be seen clearly that fundamental frequency in inversely proportional to the length of the string.

On putting double the length of the string in equation (1) keeping the all factor same , we get

               [tex]f'=\frac{1}{2\times2l} \sqrt{\frac{T}{u} }\\\\f'=\frac{1}2 } f[/tex]

Where f ' is the new frequency and f is the original frequency .

Thus, If the length of the string is doubled, with all other factors held constant, then the fundamental frequency will reduce to half.

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Answer:

IV: Sail shape

DV: Travel distance

Explanation:

The independent variable is the variable we are changing to see its effects. If we are seeing how the shape of a sail affects travelling distance, the independent variable will be the shape of the sail. This could be achieved by using different dimensions or different geometric shapes.

The dependent variable is the one we are measuring in response to the independent variable. In this case it will be the distance that the boat travels. This could be measured using a ruler or distance meter.

Hope this helped!

Reid runs away from Jarharri after an intense political debate. The average acceleration of Reid will be 0.69 m/s².

Acceleration is like the angry, fire-breathing dragon of motion variables in comparison to displacement and velocity. It can be dangerous, some people find it frightening, and if it's large, it makes you pay attention. You can feel yourself accelerating in scenarios like sitting in a plane during takeoff, slamming on the brakes in a car, or speeding around a corner in a go-kart.

Acceleration is of various types :

According to the question, the given values are :

Initial velocity, u = 0 km/hr,

Final Velocity, v = 25 km/hr

v = 25 × (5/18) = 6.9 m/s and,

Time, t = 10 seconds

Now, use the Equation of motion :

v = u+at

6.9 m/s = 0 + a (10 sec)

a = 6.9/10

a = 0.69 m/s²

Hence, the acceleration that we get here is 0.69 m/s².

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Yes, electromagnetic can travel without medium.

Mechanical waves and electromagnetic waves are two important ways that energy is transported in the world around us.

Waves in water and sound waves in air are two examples of mechanical waves.

Mechanical waves are caused by a disturbance or vibration in matter, whether solid, gas, liquid, or plasma.

Matter that waves are traveling through is called a medium.

These mechanical waves travel through a medium by causing the molecules to bump into each other, like falling dominoes transferring energy from one to the next.

Sound waves cannot travel in the vacuum of space because there is no medium to transmit these mechanical waves.

On the other hand electromagnetic waves don't require medium for its propagation.

An easy example would be light which is an EM wave reaches earth even though space has no medium.

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Consider east-west direction along x-axis and north-south direction along y-axis, x = x- component of the displacement vector = - 4580 Sin32.4 = - 2454.1 m

y = y- component of the displacement vector = 4580 Cos32.4 = 3867.02 m

z = z-component of the displacement vector = 2450 m

magnitude of displacement vector is given as

magnitude = sqrt(x² + y² + z²) = sqrt((- 2454.1)² + (3867.02)² + (2450)²) = 5194.13 m

Work is the result of displacement and a part of force acting in the displacement direction. 2. The result of force and displacement is work. 3. Work is a result of force and a part of displacement that moves in the force's direction.

When examining a force's geometric representation or its algebraic equivalent, the components of a force can be viewed as horizontal and vertical changes. The vertical and horizontal forces that combine to create the resulting force are represented by a force's components.

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Answer: All that seems to be needed to be done, is for you to subtract 57m from 70m and that equals: 13m displacement! hope this is helpful! good luck!

The magnitude and direction of the plane's total displacement will be 7.66 km, 26.20° to the ground.

It should be noted that displacement is a vector quantity which explains the change in the distance to the overall change in position of the object.

The sine and cosine function can be used to solve for the resultant x and y components.

Resultant x = 2.5 cos 35 + 5.2 cos 22

= 6.87 km

Resultant y = 2.5 sin 35 + 5.2 sin 22

= 3.38 km

The resultant displacement is calculated using hypotenuse equation:

displacement = ✓(6.87² + 3.38²)

displacement = 7.66 km

The resultant angle will be:

θ = tan^-1 (3.38 / 6.87)

θ = 26.20°

Therefore the magnitude and direction will be 7.66 km, 26.20° to the ground.

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The resultant velocity of the boat with respect to the North is 17 m/s North-West.

Resultant velocity is the single velocity obtained when two or more velocities are are combined.

To calculate the resultant velocity of the boat, we use the formula below.

Formula:

From the question,

Given:

Substitute these values into equation 1

Hence, the resultant velocity of the boat with respect to the North is 17 m/s North-West.

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Answer:

.587 s

Explanation:

d = 1/2 a t^2

1.69 m  = 1/2 ( 9.81 m/s^2) (t^2)

  t = .587 s

(a) No, it is not possible if one attract other two then it means rest of two have some sign of charge which repel to each other.

(b)Yes, similarly & it is not possible

(c) Yes, Two current carrying having same direction current, it

attract, If one attract others two it means all have same direction. Hence it is true

(d) (Not possible) Because of one repel other two it means other two have same direction which attract to each other.

Gravity is an invisible force that pulls things toward Earth. Actually, there are other places with gravity than our planet. Every thing in the universe possesses gravity, including you and the stars, planets, and moons. All objects are attracted to one another by gravity.

Every thing on Earth experiences weight, or a gravitational pull produced by the mass of the planet that is proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience.

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Answer: velocity

Explanation: Acceleration = change in velocity / time interval

5m/s to 25 m/s, in 2 seconds. So 25m/s - 5 m/s, then divide by time =

10m/s squared

E = 1.024 10⁻⁷ N/C is the size of an electric field where a proton experiences an electric force that is equal to its weight.

The term "electric field" refers to the physical field that surrounds electrically charged particles and pulls or attracts all other charged particles nearby. Additionally, it describes the physical environment of a system of charged particles.

The answer to the question is that the electric force's strength is proportional to its weight.

F(q) = Weight.

F(q) = E × q

where;

E = electric field magnitude

q = charge on an electron.

Therefore;

E × q = m × g

E = (1.67 × 10^-27 × 9.81)/1.60× 10^-19

E = 1.024 × 10^-7 N/C

Therefore, the magnitude of the electric field is E = 1.024 10⁻⁷ N/C.

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The result will be E1=E2>E4>E3

When the plane of the armature of an a.c. dynamo is parallel to the lines of force of the magnetic field, the amplitude of the induced e.m.f. is at its greatest. Additionally, the rate of change of the magnetic flux associated with the armature is at its greatest. As a result, in this orientation, the e.m.f. induced in the armature is greatest.

The EMF's amplitude is equal to Nr2B. N is the number of turns, and r is the square's half-side.

In example 3, the axis is perpendicular to the magnetic field, hence the flux is zero and the amplitude is zero as a result.

Case 4 has an axis that falls between types 1, 2, and 3.

Here, we must consider the angular velocity's x and y components.

Component in the x direction will be zero.

Additionally, the new angular velocity will be 2w because it is exactly halfway between x and y.

So now put these numbers in actual formula. The result will be E1=E2>E4>E3

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The total energy of the proton is 2882.31 MeV.

We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by

Eo = m₀ . c²

where Eo is rest energy, m₀ is rest mass and c is speed of light (3 x 10⁸ m/s).

The total energy of object can be described as

E = Eo / √(1 - v²/c²)

where E is total energy, v is the object speed.

From the question above, we know that :

m₀ = 1.6 x 10¯²⁷ kg

c = 3 x 10⁸ m/s

v = 0.95c

Find the rest energy

Eo = m₀ . c²

Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²

Eo = 1.44 x 10¯¹⁰ joule

Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV

Eo = 900 x 10⁶ eV

Eo = 900 MeV

Determine the total energy

E = Eo / √(1 - v²/c²)

E = 900 / √(1 - (0.95c)²/c²)

E = 900 / 0.31

E = 2882.31 MeV

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