Julissa is printing out copies for a work training. It takes 4 minutes to print a color copy, and it takes 2 minutes to print a grayscale copy. She needs to print no fewer than 8 copies within 25 minutes. Which system of inequalities represents the number of color copies, x, and grayscale copies, y, that Julissa can print to meet her goal?.

Answers

Answer 1

The system of inequalities for Julissa can be given as 4x + 2y ≤ 25

and x + y ≥ 8.

 

What is a system of inequalities?

The system of inequalities is given with the use of the more than inequalities for the correspondence to one variable.

In the given system, the inequalities lies with the grayscale copies, and color copies with the time limit of 25 minutes and minimum number of 8 copies.

Let the number of color copies = x

The time taken to print each color copy = 4 minutes

Thus, the time taken to print x color copies = 4x

Let the number of gray scale copies = y

The time taken to print each gray scale copy = 2 minutes

Thus, the time taken to print y gray scale copy = 2y

Total copies printed = x + y

Maximum time taken to print x color copies and y grayscale copies = 25 minutes

So,

4x + 2y ≤ 25

and x + y ≥ 8  

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Answers

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[tex]N=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\Where\ N\ is\ the \ amount \ of\ substance\ remaining\ after\ t\ years,\\N_o\ is\ the\ original\ amount, t_\frac{1}{2} \ is\ half\ life.\\\\\\Given\ N_o=5\ \mu g,t=1\ year,t_\frac{1}{2} =433\ years. Hence:\\\\N=5*10^{-6}(\frac{1}{2} )^\frac{1}{433} =4.992\ \mu g[/tex]

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