L 4.4.2 Test (CST): Electricity and Energy Resources
Question 11 of 25
What happens to the field lines of two positive charges as the charges are
brought close together?
A. The field lines are attracted to the other charge.
B. The field lines cross together.
C. It would depend on what kind of positive charges they are.
D. The field lines bend away from the other charge.
SUBMIT

Answer: The smallest whole-number ratio of the atoms in a compound represents the molar ratio of the elements in which they are combined. For example, Water is a compound. The chemical formula of water is H2O H 2 O . In water, H and O elements are combined in the molar ratio of 2:1.Explanation:

Answer:

[tex]emperical \: formula[/tex]

The mass(in grams) of iron, Fe produced from the 92.5g of iron (ii) oxide, FeO is 71.9 grams

The mass of Fe produced from the 92.5g of iron (ii) oxide, FeO can be obtained as follow:

2FeO → 2Fe + O₂

From the balanced equation above,

143.7 g of FeO reacted to produce 111.7 g of Fe

Therefore,

92.5 g of Fe will react to produce = (92.5 × 111.7) / 143.7 = 71.9 g of Fe

Thus, the mass of Fe produced from the reaction is 71.9 grams

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Complete question:

How many grams of Fe are produced from 92.5 g of FeO given the following reaction 2FeO → 2Fe + O₂

Answer:

3 moles H2 x (molecules / 1 mol H2)

Explanation:

3 moles H2 x (molecules / 1 mol H2)

Answer:

0.275M

Explanation:

First, we need to determine the number of moles of oxalic acid dihydrate used in the titration:

moles of H2C2O4 • 2H2O = (0.284 g) / (126.07 g/mol) = 0.00225 mol

Since oxalic acid dihydrate is diprotic, it can react with two moles of NaOH per mole of H2C2O4 • 2H2O. Therefore, to determine the molarity of the NaOH solution, we need to divide the number of moles of NaOH used in the titration by the volume of NaOH solution used:

moles of NaOH = (0.00225 mol H2C2O4 • 2H2O) x (2 mol NaOH / 1 mol H2C2O4 • 2H2O) = 0.0045 mol

molarity of NaOH = (0.0045 mol) / (0.01637 L) = 0.275 M

Therefore, the molarity of the NaOH solution is 0.275 M.

Answer:

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Explanation:

A. The hydronium ion concentration, [H₃O⁺] of the solution is 4.57×10⁻⁸ M

B. The hydroxide ion concentration, [OH⁻] of the solution is 1.28×10⁻⁶ M

C. The hydroxide ion concentration, [OH⁻] of the solution is 1.80×10⁻¹¹ M

We can determine the [H₃O⁺] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

[H₃O⁺] × 2.19×10⁻⁷ = 10¯¹⁴

Divide both side by 2.19×10⁻⁷

[H₃O⁺] = 10¯¹⁴ / 2.19×10⁻⁷

[H₃O⁺] = 4.57×10⁻⁸ M

We can determine the [OH⁻] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

7.81×10⁻⁹ × [OH⁻] = 10¯¹⁴

Divide both side by 7.81×10⁻⁹

[OH⁻] = 10¯¹⁴ / 7.81×10⁻⁹

[OH⁻] = 1.28×10⁻⁶ M

We can determine the [OH⁻] of the solution as shown below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

5.57×10⁻⁴ × [OH⁻] = 10¯¹⁴

Divide both side by 5.57×10⁻⁴

[OH⁻] = 10¯¹⁴ / 5.57×10⁻⁴

[OH⁻] = 1.80×10⁻¹¹ M

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The most suitable separation technique for this mixture is a combination of magnetic separation and filtration.

First, a magnet can be used to separate the iron fillings from the sand and salt mixture. This is because iron is magnetic and will be attracted to the magnet, leaving the sand and salt behind.

Next, the sand and salt mixture can be dissolved in water. Since salt is soluble in water but sand is not, the salt will dissolve while the sand remains behind. The mixture can then be filtered to separate the sand from the saltwater solution.

Finally, the saltwater solution can be heated to evaporate the water and obtain the salt as a solid residue.

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Answer:

Explanation:

% comp is g element / g cpd x 100%  get the grams from the periodic table

1) 77.78%Fe & 22.22 % O

2) 40.68 % Mg & 59.32 % Cl

3) 75 % C & 25% H

4) 15.79% C & 84.21 % S

5) 30.43 % N & 69.57 % 0

6) 92.63%Hg & 7.37 % )

7) 18.98 % Sn &  81.02 %I

8) 88.89 % Cu & 11.11 % O

9) 82.35 & N & 17.65 % H

10) 40% C & 6.67% H & 53.33 % O

Answer:2.115 L

Explanation:

4.5 x .47 = 2.115 L

4.5 pints are approximately equal to 2.129292 liters. The answer closes to the result is 2.215 liters.

This question is concerned with conversion between pints and liters. 1 pint is equal to approximately 0.473176 liters. Therefore, to find out how many liters that 4.5 pints is equal to, we multiply 4.5 by 0.473176.

The calculation is as follows: 4.5 pints * 0.473176 liters/pint = 2.129292 liters

Considering the options that was given, the closest answer is 2.215 liters.

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According to the kinetic molecular theory, gases are described by the following statement:

This statement highlights that gases are made up of particles that are in constant motion, moving in straight lines until they collide with another particle or the walls of the container.

The motion of gas particles is random, and their energy increases as the temperature of the gas increases. The kinetic molecular theory also suggests that the particles in a gas are far apart from each other and do not attract or repel each other, except during collisions.

Additionally, the kinetic molecular theory states that the pressure of a gas is caused by the collisions of gas particles with the walls of the container. The higher the concentration of gas particles or the faster they are moving, the greater the pressure of the gas.

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Answer:

many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?

volume: 16 mL

First, we need to calculate the number of moles of Zn:

m(Zn) = 5.05 g

M(Zn) = 65.38 g/mol (molar mass of Zn)

n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol

According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:

n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol

Now we can use the molarity of the HCl solution to calculate the volume needed:

M(HCl) = 1.50 mol/L

n(HCl) = V(HCl) × M(HCl)

V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL

Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).

Answer:

Solubility.

Explanation:

Solubility is the maximum concentration of a solute that can dissolve in a solvent at a given temperature. At the maximum concentration of solute, the solution is said to be saturated. The units of solubility can be provided in mol/L or g/L.