Option 4. The effects of the simplifications are often relatively small, the computations may become too complex if all factors are included, or it isn’t possible to know the initial values of all factors well enough to include them
Computational models often make our derivations and complex studies get simplified. However these models ignores some factors which can only be determines practically.Hence, the statement in 4th option better indicates the need of simplifications.
What is computational model?A computational model is used to predict som complex structures or performing complex derivations and calculations using computer programmes and simulations.
For instance, there are various computational softwares such Gaussian to study the structural and electronic properties of molecules such as bond parameters, enthalpies etc. Similarly, the Hartree method for the calculation of energy levels can be performed using computational models.
These models simplifies and make more easier to understand a parameter or any structure or equation. However some factors which cannot included in these computations make a chance of inaccuracy in them.
In fact they cannot predicted by computations but can only be determined practically. But to make the study simpler adn near perfection we use these models without too much complex factors. Hence, option 4 is correct.
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An example of conservation of angular momentum is jumping on a Merry-Go-Round. Watch this video (it starts part way through but the only thing you miss is the people pushing the Merry-Go-Round) to see someone jumping on a Merry-Gr-Round in motion like this problem. You can model the Merry-Go-Round as a solid disk with a radius of 2.70 m and a mass of 77.0 kg. Initially the Merry-Go-Round has an angular velocity 7.40 radians / second. Then the person jumps on and change the Moment of Inertia of the system. The person lands on the outer edge of the Merry-Go-Round and has a mass of 58.0 kg. What is the final angular velocity of the system after the person jumps on
Answer:
ωf = 2.95 rad/sec
Explanation:
Assuming no external torques acting while the person jumps on, total angular momentum must be conserved.Angular momentum for a rotating rigid body can be expressed as follows:[tex]L = I * \omega (1)[/tex]
where I = moment of inertia regarding the rotating axis, and ω= angular velocity.Since total angular momentum must be conserved, this means that the following equality must be satisfied:[tex]L_{o} = L_{f} (2)[/tex]
The initial angular momentum, taking into account that the Merry-Go-Round can be modeled as solid disk, can be expressed as follows:[tex]L_{o} = I_{o} * \omega_{o} = \frac{1}{2}* M* R^{2}* \omega_{o} =\\ \frac{1}{2} * 77.0 kg* (2.70m)^{2}* 7.40 rad/sec = 2076.92 kg*m2*rad/sec (3)[/tex]
The final angular momentum, is just the product of the new moment of inertia times the final angular velocity.The new moment of inertia, is just the sum of the original moment of inertia I₀ and the moment of inertia due to the person that jumps on.Assuming that we can treat him as a point mass, his moment of inertia is just the product of his mass times to the distance to the axis of rotation (the radius of the Merry-Go-Round) squared.So, we can write the new moment of inertia If as follows:[tex]I_{f} = I_{o} +( m_{p} * R^{2}) = (\frac{1}{2} * M* R^{2}) + ( m_{p} * R^{2}) =\\ (\frac{1}{2} * 77.0 kg* (2.70m)^{2}) +( 58.0 kg * (2.70m)^{2}) = \\ 280.67 kg*m2 + 422.82 kg*m2 = \\ 703.49 kg*m2 (4)[/tex]
The final angular momentum can be written as follows:[tex]L_{f} = I_{f} * \omega_{f} (5)[/tex]
Since (3) and (5) must be equal each other, replacing If by its value from (4) in (5), we can solve for ωf, as follows:[tex]\omega_{f} = \frac{L_{o} }{I_{f}} = \frac{2076.92kg*m2*rad/sec}{703.49kg*m2} = 2.95 rad/sec (6)[/tex]
HELP PLEASE
Two 24 ohm resistors are in parallel and placed across a 12 V battery. What is the current in each branch of the circuit?
20 A
0.0125 A
0.5 A
.
Answer:
.5 A
Explanation:
If the radius of the Earth is 6400.0 km and the atmosphere is 10.0 km high, then the volume of air around the Earth is what?
Answer:
5.16 x 10^18 m^3
Explanation:
Find the Net Force on a truck with a mass of 1,500kg and an acceleration
of 10m/s2?
Answer:
15,000 N
Explanation:
F = ma = (1,500 kg)(10 m/s^2) = 15,000 N
An ideal horizontal spring-mass system is set into motion. At an instant when the mass passes through its equilibrium position: The potential energy in the spring is at its _____. The kinetic energy of the mass is at its ______. The magnitude of net force acting on the mass is at its ______.
Answer:
the potential energy is zero, and the kinetic energy must be maximum
F = 0
Explanation:
In this exercise you are asked to complete the sentences of a simple harmonic movement of a mass-spring system.
In this system mechanical energy is conserved
at the most extreme point the carousel potential energy is
K_e = ½ k x²
the kinetic energy is zero for that stopped.
At the equilibrium point
the spring elongation is x = 0 so the potential energy is zero
and the kinetic energy must be maximum since total energy of the system is conserved
the spring force is
F =- k x
as in the equilibrium position x = 0 this implies that the force is also zero
F = 0
In this exercise we have to use the knowledge of force to calculate the energy of a spring, in this way we find that:
The potential energy in the spring is at its [tex]K_e = 1/2 k x^2[/tex]. The kinetic energy of the mass is at its zero . The magnitude of net force acting on the mass is at its Zero.
In this system mechanical energy is conserved, at the most extreme point the carousel potential energy is:
[tex]K_e = 1/2 k x^2[/tex]
The kinetic energy is zero for that stopped or when at the equilibrium point, so:
the spring elongation is x = 0 so the potential energy is zero the kinetic energy must be maximum since total energy of the system is conserved
the spring force is:
[tex]F =- k x\\F=0[/tex]
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Determine the activity of the sample of cerium when the sample was 80 seconds old
Answer is in a photo. I can only upload it to a file hosting service. link below!
bit.[tex]^{}[/tex]ly/3a8Nt8n
the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67
Answer:
[tex]\theta_c = 36.78^o[/tex]
Explanation:
The relationship between the refractive index and the critical angle is given as follows:
[tex]\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )[/tex]
where,
η = refractive index = 1.67
θc = critical angle =?
Therefore,
[tex]\theta_c = Sin^{-1}(\frac{1}{1.67} )[/tex]
[tex]\theta_c = 36.78^o[/tex]
Which is a form of precipitation?
A. Runoff
B. Rain
C. Gas
D. Evaporation
Answer:
D. Evaporation
Explanation:
Just did it made 100%
What do microwaves have In common with light waves?
Answer:
Both are electromagnetic waves
Explanation:
Hope this helped!!
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answer:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Explanation:
In this case, we see a disk rotating at constant rate, the travelled distance of a point on the outside rim ([tex]s[/tex]), in centimeters, is determined by using this expression:
[tex]s = \omega \cdot r\cdot t[/tex] (1)
Where:
[tex]\omega[/tex] - Angular speed, in radians per second.
[tex]r[/tex] - Radius of the disk, in centimeters.
[tex]t[/tex] - Time, in seconds.
If we know that [tex]\omega \approx 10.472\,\frac{rad}{s}[/tex], [tex]r = 50\,cm[/tex] and [tex]t = 30\,s[/tex], then the travelled distance of the point is:
[tex]s = \omega \cdot r\cdot t[/tex]
[tex]s = 15708\,cm[/tex]
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Read each example and identify whether the data are observations or inferences from observations. The fish’s ventral fin measured 8.5 cm long.
Answer:
Observation
Inference
Inference
Observation
Inference
Explanation:
The result of the evolutionary process that preserves traits that enhance the adaptation of an organism and suppresses traits that do not is called
Answer:
Natural selection.
Explanation:
Natural selection can be defined as a biological process in which species of living organisms having certain traits that enable them to adapt to environmental factors such as predators, competition for food, climate change, sex mates, etc., tend to survive and reproduce, as well as passing on their genes to subsequent generations.
Simply stated, natural selection entails the survival of the fittest. Therefore, the species that are able to adapt to the environment will increase in number while the ones who can't adapt will die and go into extinction.
On the other hand, artificial selection is also known as selective breeding and it is a process that involves humans (breeders) selecting the animal or plant with desirable traits in order to reproduce favorable offspring having phenotypic traits.
How many joules of kinetic energy does a pendulum have when it has 100 joules of potential energy
Answer:
The maximum kinetic energy is 100 j.
Explanation:
The kinetic energy = (potential energy) + (kinetic energy) and the potential energy of 0 J implying its kinetic energy is 100 J, which is its maximum.
Answer :100J of KE.
Explanation:
Moira is experiencing noticeable memory loss, muscle loss, and bone loss. What age group is Moira most likely in?
adolescence
early adulthood
middle adulthood
late adulthood
Answer:
Late adulthood
Explanation:
Just did it :)
What is the mass of a jet that accelerates at 4 m/s2 after a 4,000 N force from the engines?
Answer:
1000kg
Explanation:
F=MA
Rearrange the formula: M=F/A
plug in values for F (force), and A (acceleration).
M=4000/4
M=1000kg
i think.
not sure tho.
The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
What is Newton's second law of motion?Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.
Rearranging the formula to solve for mass, we get:
m = F / a
Substituting the given values, we get:
[tex]m = 4000 N / 4 m/s^2[/tex]
m = 1000 kg
Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
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When a mass is suspended from a spring the latter extends over a distance of 10cm. What will be the period of oscillations of the same system if it is placed horizontal on a frictionless surface
Answer:
0.64 s
Explanation:
It's period of oscillation (T) can be determined by,
T = 2[tex]\pi[/tex][tex]\sqrt{\frac{l}{g} }[/tex]
Where l is the length (extension on the spring), and g the acceleration due to gravity.
But,
l = 10 cm = 0.1 m
g = 9.8 m/[tex]s^{2}[/tex]
Thus,
T = 2 x [tex]\frac{22}{7}[/tex] [tex]\sqrt{\frac{0.1}{9.8} }[/tex]
= 0.6350
T = 0.64 s
The period of oscillation would be 0.64 s.
Choose a tool or a device you can investigate. It must not have any source of power other than the person using it. It must use one or more of the six simple machines. Explain how the tool or device is used. What work does a person do while using it? What kind of motion do we see when it’s used?
Answer:
Wheelbarrows, fishing rods, shovels, brooms, arms, legs, boat oars, crow bars, and bottle openers are all examples of levers. Levers may be one of the most used simple machine. As with all simple machines like the lever, they are designed to help make work easier to do.
Explanation:
Answer:
Wheelbarrows- This tool/device is used for a variety of things, such as moving rock, mulch or compost to the garden, moving trees or large shrubs from one spot to another, hauling bricks, disposing of garden debris, for mixing concrete or fertilizers, and even used on farms for mucking horse stalls. The work you do is pushing it whcih also goes along with the montion you will see, forward motion.
Explanation:
After the initial experiment, students wondered how a person's weight would influence the results. They conducted a second experiment to determine if the mass of an object affected friction, assuming the types of surfaces remained constant. A spring scale was attached to a wooden block (1 kg). The block was placed on a wooden board and the spring scale was used to pull the block. The magnitude of the force required to start the block moving was recorded in the data table. The experiment was repeated using two, three, and four blocks. The data can be seen in the data table at the top of the page. What is the relationship between static friction and weight?
Answer:
The greater the weight of the person, the more static friction.
Explanation:
USATestPrep
What are the issues that hinders efforts to achieve sustainability?
Answer:
who will solve environmental problems, who is responsible for environmental problems, and who pays the cost of implementing solutions
Explanation:
In this image of an atom, what does the outer area consisting of tiny blue
dots represent?
O A. The electron cloud
B. Protons
C. The nucleus
D. Neutrons
Would a 2021 Ford Mustang GT be light weight or heavy weight?
Answer:
Heavy weight
Explanation:
It's a muscle car, its weight its 3,825 lb, and it's classified as heavy for a car.
Answer:
Heavy Weight
Explanation:
A 2021 Mutsang GT could wrigh from 3,532 to 3,868 lbs. This would be considered a Heavy meadium to Heavy muscle car.
No where close to the boat of mopar the challenger almost weighting up to 4,500lbs
A 30 kg child went down a 10 m tall slide. Assuming no energy was lost as friction, what was the child's velocity when he reached the
bottom?
I
Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 246 Hz, while the other produces 289 Hz. When a tuning fork is sounded together with the 246-Hz tone, a beat frequency of 18.0 Hz is produced. When the same tuning fork is sounded together with the 289-Hz tone, a beat frequency of 25.0 Hz is produced. What is the frequency of the tuning fork
Answer:
[tex]264\ \text{Hz}[/tex]
Explanation:
Beat frequency of the first case = 18 Hz
Beat frequency of the second case = 25 Hz
Tone of first fork = 246 Hz
Tone of second fork = 289 Hz
First case
Beat frequency is given by
[tex]\Delta f=|f_2-f_1|\\\Rightarrow f_1=246\pm18\\\Rightarrow f_1=264, 228\ \text{Hz}[/tex]
Second case
[tex]f_2=289\pm 25\\\Rightarrow f_2=264, 314\ \text{Hz}[/tex]
The frequency of the tuning fork is [tex]264\ \text{Hz}[/tex].
A diffraction grating is placed 1.00 m from a viewing screen. Light from a hydrogen lamp goes through the grating. A hydrogen spectral line with a wavelength of 656 nm is seen 60.0 cm to one side of the center. Then, the hydrogen lamp is replaced with an unknown lamp. A spectral line is seen on the screen 36.4 cm away from the center. What is the wavelength of this spectral line
Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ
sin θ = y / L
we substitute
[tex]d \ \frac{y}{L}[/tex] = m λ
with the initial data we look for the distance between the lines
d = [tex]\frac{m \lambda \ L}{y}[/tex]
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
Which property of light is a constant in a vacuum?
Answer:
La velocidad de la luz en el vacío es una constante universal con el valor de 299 792 458 m/s (186 282,397 mi/s),aunque suele aproximarse a 3·108 m/s. Se simboliza con la letra c, proveniente del latín celéritās (en español, celeridad o rapidez).
¿Cuál es la consecuencia que a velocidad de la luz sea constante?
Respuesta. En modificaciones del vacío más sutiles, como espacios curvos, efecto Casimir, poblaciones térmicas o presencia de campos externos, la velocidad de la luz depende de la densidad de energía de ese vacío.
Question 9 of 10
What happens to light as it moves at an angle into a medium that has a higher index of refraction?
A. It slows down, and the angle decreases.
B. It speeds up, and the angle increases.
C. It slows down, and the angle increases.
D. It speeds up, and the angle decreases.
Answer:
v = C / n light slows entering a medium of higher index of refraction
ni sin theta i = nr sin theta r Snell's Law where i refers to incidence and r refers to refraction
sin theta r = (ni / nr) sin theta i
So if the index of refraction is greater than the angle of incidence then the light ray would be refracted towards the normal
Answer:
A. It slows down, and the angle decreases.
Explanation:
got it right, trust
If velocity decreases what happens to acceleration
Answer: Velocity is a vector; the word decreasing only applies to its magnitude (not its direction) which is called speed. If speed is increasing and direction is not changing, then acceleration is positive. If speed is constant then acceleration is zero. If speed is decreasing then acceleration is negative.
Explanation:
What structure is represented by the letter C?
PLEASE HELP!!!!!!!!!!!!!
Choose 1 answer:
A) Lysosome
B) Nucleus
C) Vacuole
D) Mitochondria
Answer:
The picture is blacked out.
Answer:
If I'm correct the answer would be A) Lysosome.
The attachment is black so I can't promise you that it's the one you're looking for. But I did it on khan
what happens to a neutron that is not attached to a proton?
what is the planet that scientists are exploring now?
Answer:
Mars
Explanation:
In the 1960s, humans set out to discover what the red planet has to teach us. Now, NASA is hoping to land the first humans on Mars by the 2030s. Mars has captivated humans since we first set eyes on it as a star-like object in the night sky.
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