Matching equations with diagrams & finding unknown angles #3
Which equation(s) and angle measurements go with the
diagram. Choose ALL that apply.
Find the value of a.
(Select all that apply.)

please help

The number of ways Dr. Orchid can arrange all 9 paintings is 362880 and the number of ways she can choose the paintings she wishes to display is 126.

Combination is the way of arrangement or the collection of items in the particular order. The order of this group of items does not matter in the combination type of arrangement.

Dr. Orchid has 9 paintings she wants to hang side by side on her walls.

Total number of paintings is 9. She wants to arrange them side by side. Thus, the number of ways, she can arrange all 9 paintings is,

[tex]9!=9\times8\times7\times6\times5\times4\times3\times2\times1\\9!=362880[/tex]

She wants to display 4 of the paintings. The number of arrangement of 4 painting from 9 paintings is,

[tex]^9C_4=\dfrac{9!}{(9-4)!4!}\\^9C_4=\dfrac{9\times8\times7\times6\times5!}{5!\times4\times3\times2\times1}\\^9C_4=126[/tex]

Thus, the number of ways Dr. Orchid can arrange all 9 paintings is 362880 and the number of ways she can choose the paintings she wishes to display is 126.

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Answer:

The y-intercept is (0,-3

Step-by-step explanation:

Step-by-step explanation:

to find the y intercept you simply equate x to 0. therefore, the y intercept is -4.5

and its coordinate is:

(0, -4.5)

Answer:

a straight angle

Step-by-step explanation:

the minute and hour hand are straight lined up the hour being on the six and the minute being on the twelve

The relationship between corresponding terms in the two patterns is B(n) = 2A(n) where the A(n) and B(n) is the nth terms of the pattern A and pattern B.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have Pattern A starts at 0 and has the rule "add 3"

Pattern A:

0, 3, 6, 9, 12.....and so on

Pattern B starts at 0 and has the rule "add 6."

Pattern B:

0, 6, 12, 18, 24, 30.... and so one

In the pattern A we can find the nth term:

First term = 0, common difference = 3

A(n) = 0 + (n-1)3 = 3(n-1)

Similarly in the pattern B we can find the nth term

First term = 0, common difference = 6

B(n) = 0 + (n-1)6 = 6(n-1)

The relation can be derived between the nth term of pattern A and pattern B as follows:

B(n) = 2A(n)

Thus, the relationship between corresponding terms in the two patterns is B(n) = 2A(n) where the A(n) and B(n) is the nth terms of the pattern A and pattern B.

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Answer:

octagon; not regular

Step-by-step explanation:

This shape is an octagon because it has 8 sides (hence "oct") and it is irregular because not all the sides are of equal length and it does not look like a regular octagon..

Hope this helps!

Answer:

octagon; non regular

Step-by-step explanation:

because it have unequal sides and unequal angles.

Hey there!

5÷9v ≤ 45

5/9v ≤ 45

MUTLPLY 9/5 to BOTH SIDES
5/9v * 9/5 ≤ 45 * 9/5

CANCEL out: 5/9 * 9/5 because it give you 1

KEEP: 45 * 9/5 because it help solve for what is being compared to the v-value

NEW EQUATION: v ≤ 45 * 9/5

SIMPLIFY IT!
v ≤ 81

It is a CLOSED circle shaded to the LEFT

Therefore, your answer is: v ≤ 81

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

Step-by-step explanation:

In this question we have given an equation that is 3 ( q - 7 ) = 27 and we have asked to solve this equation that means to find the value of q .

Solution : -

[tex] \quad \: \longmapsto \: 3(q - 7) = 27[/tex]

Step 1 : Solving parenthesis :

[tex]\quad \: \longmapsto \:3q - 21 = 27[/tex]

Step 2 : Adding 21 on both sides :

[tex]\quad \: \longmapsto \:3q - \cancel{ 21} + \cancel{21} = 27 + 21[/tex]

On further calculations we get :

[tex]\quad \: \longmapsto \:3q = 48[/tex]

Step 3 : Dividing by 3 from both sides :

[tex]\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}} = \cancel {\frac{48}{3} }[/tex]

On further calculations we get :

[tex]\quad \: \longmapsto \: \pink{\boxed{\frak{q = 16}}}[/tex]

Verifying : -

Now we are very our answer by substituting value of q in the given equation . So ,

Therefore, our solution is correct .

Answer:

[tex] \: [/tex]

Step-by-step explanation:

So here, a equation is given and we are asked to solve the equation.

[tex] \\ \dashrightarrow \sf \qquad3(q-7)=27 \\ \\ [/tex]

For this, we have to use the Distributive property, which is :

[tex]\\ \dashrightarrow \sf \qquad3q-21=27 \\ \\ [/tex]

Transposing the constant term (-21) to the right side we get :

[tex]\\ \dashrightarrow \sf \qquad3q=27 + 21 \\ \\ [/tex]

Adding the like terms :

[tex] \\ \dashrightarrow \sf \qquad3q=48 \\ \\ [/tex]

Now, We'll divide both sides by 3 :

[tex] \\ \dashrightarrow \sf \qquad \frac{3q}{3} = \frac{48}{3} \\ \\ [/tex]

[tex]\dashrightarrow \bf \qquad \: q=16 \\ \\ [/tex]

73-96

For box plots, the two edges of the box represent the 25% and 75% mark, meaning everything in between those two lines is the middle 50%. In this case the lines are at 73 and 96.

Answer:

measure of angle EFG = 139°

measure of angle IFH = 49°

Since angles DEF and EFG are supplementary:

[tex]2x + 3 + 6x + 25 = 180[/tex]

[tex]8x + 28 = 180[/tex]

[tex]8x = 152[/tex]

[tex]x = 19[/tex]

So the measure of angle EFG is

6(19) + 25 = 114 + 25 = 139 degrees, and the measure of angle DFE is 41 degrees.

Angles DFE and GFH are vertical, so angle GFH measures 41 degrees.

Angles GFH and IFH are complementary, so angle IFH measures 49 degrees.

Answer:

[tex]19 sq.\ units[/tex]

Step-by-step explanation:

The best way to approach this is to figure out the area of the overall square, then remove any gaps.

The overall square is 5 by 5 so the area is:

[tex]A_t = s * s = 5 * 5 = 25\ sq.\ units[/tex]

There are 5 gaps in the shape of triangles, we will use the formula: [tex]A = \frac{bh}{2}[/tex], and subtract from the total.

1. (Top left)

[tex]A_1 = \frac{bh}{2} = \frac{2 * 1}{2} = 1[/tex]

2. (Top right)

[tex]A_2 = \frac{bh}{2} = \frac{2 * 1}{2} = 1[/tex]

3. (Bottom left)

[tex]A_3 = \frac{bh}{2} = \frac{2 * 1}{2} = 1[/tex]

4. (Bottom center)

[tex]A_4 = \frac{bh}{2} = \frac{2 * 1}{2} = 1[/tex]

5. (Bottom right)

[tex]A_3 = \frac{bh}{2} = \frac{2 * 2}{2} = 2[/tex]

The total triangle area is:

[tex]A = 1 + 1 + 1 + 1 + 2 = 6[/tex]

Subtract from total area to actual area:

[tex]A_s = A_t - A = 25 - 6 = 19 sq.\ units[/tex]

The statement that is true about the box plot is that More of the children were close to 12 years old than 6 years old.

A box plot is known to be a kind of plot that shows at least five-number that acts as the summation of all the set of a given data.

Conclusively, in the case above, the box plot is said to be showing the a lot of children whose age are close to 12 years old more than those who are 6 years old.

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Answer:

The answer is C

Step-by-step explanation:

Answer:

125 degrees

Step-by-step explanation:

Assuming l and m parallel, 125= x

work it out you cheater lol

Answer:

109.3 yard²

Step-by-step explanation:

Area of triangle = bh / 2

base is 23yd

height is 9.5yd

bh / 2 = 23 × 9.5 / 2

Area = 218.5 / 2

Area = 109.25 yd²; rounded to the nearest tenth is 109.3yd²

Answer:

the answer is c

Step-by-step explanation:

-then+

Answer:

g(x) =  - 1/2 * (x^2 - 8x + 12)

Step-by-step explanation:

Given the information, you have provided.

Zeros: (2,0) and (6,0).

Maximum: (4,2) which is also your (h,k)

f(x) = - (x - 2)*(x - 6)

g(x) =  - 1/2 * (x^2 - 8x + 12)

I do not know how to explain this, but -1/2 makes the graph get (4,2) as the maximum.

The red graph is f(x) = - (x - 2)*(x - 6)

The blue graph is your answer g(x) =  - 1/2 * (x^2 - 8x + 12)

Answer:

rotation and enlargements

Step-by-step explanation:

triangle XYZ is rotated to make triangle GHI and triangle GHI is enlarged by a scale factor of around 2.6? to make triangle MNO then triangle MNO is rotated to make triangle EDF

Answer: The three systems that would be reasonable

ΔXYZ to ΔGHI is a Rotation

ΔGHI to ΔMNO is an Enlargement

ΔMNO to ΔDEF is a Reflection

Step-by-step explanation:

Answer: C

Step-by-step explanation:

Answer:

7.11

Step-by-step explanation:

You will add all of those numbers and divide them by the amount of numbers you added. And I rounded the answer to 2 decimal places, seeing that it is a recurring decimal.

Answer:

885735

Step-by-step explanation:

5

x 3

15

x 3

45

x 3

135

x 3

405

x 3

1215

x 3

3645

x 3

10935

x 3

32805

x 3

98415

x 3

295245

x 3

885735

Answer:

885735

Step-by-step explanation:

Answer:

Company A = 35 Company B = 45

Step-by-step explanation:

70x3/4 = 52.5

70x1/4 = 17.5

52.5 - 17.5 = 35

90x1/4 = 22.5

90x3/4 = 67.5

67.5 - 22.5 = 45

Hence, Company A = [tex]35[/tex] and  Company B = [tex]45[/tex].

What is the equation?

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here given that,

The cumulative frequency diagram shows information about the ages of employees in two companies. Work out the IQR for both companies and compare them.

So, For the Company A

[tex]70[/tex]×[tex](\frac{3}{4})\\[/tex]

[tex]=70[/tex]×[tex](0.75)\\[/tex]

[tex]=52.5[/tex]

[tex]70[/tex]×[tex]\frac{1}{4}\\[/tex]

[tex]= 70[/tex]×[tex](0.25)\\[/tex]

[tex]=17.5[/tex]

So,

[tex]52.5- 17.5 = 35[/tex]

So, Company A is [tex]35[/tex].

For Company B,

[tex]90[/tex]×[tex]0.25 = 22.5[/tex]

[tex]90[/tex]×[tex]\frac{3}{4} = 67.5[/tex]

Then,

[tex]67.5 - 22.5 = 45[/tex]

So Company B is [tex]45[/tex].

Hence, Company A = [tex]35[/tex] and  Company B = [tex]45[/tex].

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Answer:

B

Step-by-step explanation:

y-y1=m(x-x1)

y+13=5(x+2)

Answer:

18 days

Step-by-step explanation:

since 1/2 is half, u will multiple 9 by 2 to get 18 days !

Answer:

128+8.50x+9.50y+10z

[tex]5^{-12} \cdot 32^{-3} \cdot 9^{-15}\\\\\\=\dfrac 1{5^{12}} \cdot \dfrac 1{32^3} \cdot \dfrac 1{9^{15}}\\\\\\=\dfrac 1{5^{12}} \cdot \dfrac 1{(2^5)^3}\cdot \dfrac 1{9^{15}}\\\\\\=\dfrac 1{5^{12} \cdot 2^{15} \cdot 9^{15} }\\\\\\=\dfrac 1{5^{12}\cdot 18^{15}}[/tex]

Answer:

[tex]\boxed{ \dfrac{1}{5^{12}} \times \dfrac{1}{32^{3}} \times \dfrac{1}{9^{15}}}[/tex]

Step-by-step explanation:

In this case, all the exponents are negative. To make them positive, take the term's reciprocal and change the exponents sign.

[tex]\implies 5^{-12} \times 32^{-3} \times 9^{-15}[/tex]

Changing the terms into it's reciprocal form:

[tex]\implies \dfrac{1}{5^{-12}} \times \dfrac{1}{32^{-3}} \times \dfrac{1}{9^{-15}}[/tex]

Changing the signs of the exponent:

[tex]\implies\boxed{ \dfrac{1}{5^{12}} \times \dfrac{1}{32^{3}} \times \dfrac{1}{9^{15}}}[/tex]

Answer: A

Step-by-step explanation: