Mintu wants to increase the heat transfer between a metal iron and another piece of metal he wants to shape. He decides to increase the time the two metals are in contact, use a larger metal iron, and use a new metal material with a higher specific heat.

Where is Mintu's error?

Answer:

7.47 × 10^-1 M-1 s-1

Explanation:

Using the form k[A]^m[B]^n we arrive at the fact that the rate constant of the reaction can be written in the form;

Rate = k[NO2] [CO] where both m and n =1

We can use data from any of the experiments to establish the rate constant hence;

From experiment 1

[NO2] = 0.374M

[CO] = 0.300 M

R= 8.39 × 10^-2

Hence k =8.39 × 10^-2 / [0.374] [0.300]

k= 7.47 × 10^-1 M-1 s-1

Answer:

Mass of liquid B = 271.2 gram

Explanation:

Given:

Density of liquid A = 1000 kg/m³

Density of liquid B = 600 kg/m³

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

Assume:

Volume of liquid A = Va

Volume of liquid B = Vb

So,

Volume of mixture = Va + Vb

Mass of liquid A = 1000(Va)

Mass of liquid B = 600(Vb)

Mass of mixture = Mass of liquid A + Mass of liquid B

1 = 1000(Va) + 600(Vb)

Volume of mixture = 1 / 850

So,

(1/850) = Va + Vb

Vb = (1/850) - Va

1 = 1000(Va) + 600[(1/850) - Va]

Va = 7.25 × 10⁻⁴

Vb = (1/850) - Va

Vb = (1/850) - [7.25 × 10⁻⁴]

Vb = 4.25 × 10⁻⁴

Mass of liquid B = 600(Vb)

Mass of liquid B = 600(4.25 × 10⁻⁴)

Mass of liquid B = 271.2 gram

The mass of liquid B in the 1 Kg mixture is 300 g

Let the volume of liquid A be Va

Let the volume of liquid B be Vb

From the question given above, the following data were obtained:

Density of liquid A = 1000 kg/m³

Density of liquid B = 600 kg/m³

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

For Liquid A:

Density of liquid A = 1000 kg/m³

Volume of liquid A = Va

Mass of Liquid A =?

Mass = Density × Volume

Mass of Liquid A = 1000 × Va

For Liquid B:

Density of liquid B = 600 kg/m³

Volume of liquid B= Va

Mass = Density × Volume

Mass of Liquid B = 600 × Va

Density of mixture = 850 kg/m³

Mass of mixture = 1 kg

Volume = mass /density

Volume of mixture = 1 / 850

Mass of mixture = 1 Kg

Mass of mixture = Mass of liquid A + Mass of liquid B

Volume of mixture = Va + Vb

Volume of mixture = 0.0012 m³

Thus,

0.0012 = Va + Vb

Substitute Vb in equation 2 into equation (1)

1 = 1000(Va) + 600[0.0012 – Va]

1 = 1000Va + 0.72 – 600Va

Collect like terms

1 – 0.72 = 1000Va – 600Va

0.28 = 400Va

Divide both side by 400

Va = 0.28 / 400

Volume of mixture = 0.0012 m³

Volume of liquid A (Va) = 0.0007 m³

Vb = 0.0012 – Va

Vb = 0.0012 – 0.0007

Volume of liquid B (Vb) = 0.0005 m³

Mass of liquid B = 600(Vb)

Mass of liquid B = 600(0.0005)

Mass of liquid B = 0.3 Kg

Multiply by 1000 to express in grams

Mass of liquid B = 0.3 × 1000

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Answer:

Rb = +1 , Sr = +2, In= +3,  Sn = +4, Sb= +5

Explanation:

Formula:

Zeff = Z - S

Z = atomic number

S = number of core shell or inner shell electrons

For Sn:

Electronic configuration:

Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²

Zeff = Z - S

Zeff = 50 - 46

Zeff = +4

For Rb:

Electronic configuration:

Rb₃₇ = [Kr] 5s¹

Zeff = Z - S

Zeff = 37 - 36

Zeff = +1

For Sb:

Electronic configuration:

Sb₅₁ = [Kr] 4d¹⁰ 5s² 5p³

Zeff = Z - S

Zeff = 51 - 46

Zeff = +5

For In:

Electronic configuration:

In₄₉ = [Kr] 4d¹⁰ 5s² 5p¹

Zeff = Z - S

Zeff = 49 - 46

Zeff = +3

For Sr:

Electronic configuration:

Sr₃₈= [Kr]  5s²

Zeff = Z - S

Zeff = 38 - 36

Zeff = +2

Answer:yes

Explanation:

I think so

There are more metals than nonmetals on the periodic table. The majority of elements on the periodic table are metals, which are found on the left and middle sections of the periodic table.

Metals typically have properties such as high electrical and thermal conductivity, luster, malleability, and ductility.

Nonmetals, on the other hand, are found on the right-hand side of the periodic table, along with the noble gases. Nonmetals generally have properties opposite to those of metals, such as poor electrical and thermal conductivity and a lack of metallic luster. There are fewer nonmetals compared to metals on the periodic table.

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Answer:

silver (III) phosphate

Explanation:

Answer:i believe 9-?

Explanation:

boron-10

boron-11

carbon-12

carbon-13

oxygen-16

oxygen-17

oxygen-18

chlorine-35

chlorine-37

Answer:Three mutual conversions of energy forms occur at nuclear power plants: nuclear energy is converted into thermal energy, thermal energy is converted into mechanical energy, and mechanical energy is converted into electric energy.

Explanation:

Answer: below -45

Explanation:

Answer:

magnesium oxide

Explanation:

hope this helps

Answer:

it is nanometers the third one

Explanation:

hope this helps

The correct answer is:

(D) Micrometers

Hope this helps!

Answer:

Liquid: water

Solid: Rocks

Gas: Air

Explanation:

Answer:

2.98 moles of NaCl are produced.

Explanation:

Given data:

Moles of sodium = 2.98 mol

Amount of chlorine = excess

Moles of NaCl produced = ?

Solution:

Chemical equation:

2Na + Cl₂    →     2NaCl

Now we will compare the moles of sodium chloride with only sodium because sodium is limiting reactant and chlorine is in excess thus sodium limit the yield of product.

                    Na        :        NaCl

                    2          :            2

                 2.98        :          2.98

2.98 moles of NaCl are produced.

Answer:

feel slippery

Explanation:they physical properties are due to its slippery nature when touched

Answer:

A. color change

Explanation:

changing the color of a metal does not change its physical properties.

hope it helps.

Answer:B

Explanation: an object in motion will stay in motion until acted on by another force and an object in rest will stay in test until acted on by another force

Answer:

protons and neutrons so A and C

Answer:

Ammonia > Urea > Ammonium nitrate > Ammonium sulphate

Explanation:

Percentage by mass of nitrogen in NH3:

Molar mass of NH3= 17 g/mol

Hence % by mass = 14/17 × 100 = 82.35%

% by mass of NH4NO3

Molar mass of NH4NO3 = 80.043 g/mol

Hence; 28/80.043 × 100 = 34.98%

% by mass of (NH4)2SO4;

Molar mass of (NH4)2SO4= 132.14 g/mol

Hence; 28/132.14 × 100 = 21.19%

% by mass of CH4N2O

Molar mass of urea = 60.0553 g/mol

Hence 28/60.0553 × 100 = 46.62%

Answer:

math si hard

Explanation:

The mole fration of ethanol and water in a sample of rectified spirit which contains 95% of ethanol by mass is 0.8 and 0.11.

Mole fraction of any substance will be calculated by dividing the moles of that substance from the total moles of the solution.

Moles (n) will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given that 95% of ethanol by mass is present in the sample, so 95g of ethanol is present in 100g of solution.

Mass of solvent (water) = 100 - 95 = 5g

Moles of water = 5g / 18g/mol = 0.27mol

Moles of ethanol = 95g / 46g/mol = 2.06mol

Mole fraction of water  = 0.27 / (0.27+2.06) = 0.11

Mole fraction of ethanol = 2.06 / (0.27+2.06) = 0.8

Hence required mole fraction of water & ethanol is 00.11 and 0.8 respectively.

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Answer:

Test variable (independent variable): Predators, Pollution, Food.Outcome variable (dependent variable): Cricket Frogs.Control group: Beginning Frog Count

Explanation:

If pollution isincreased, then the cricket frog population will (stay the same) over the span offive years.If the amount of food available isincreased, then the cricket frog population will (increase) overthe span of five years.Procedure:The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sureto identify the test variable (independent variable), outcome variable (dependent variable), andcontrol group for this experiment.

Answer:

yes

Explanation:

everything will change

Answer:

Volume of N₂ = 14.76 L

Volume of H₂ = 29.52 L

Explanation:

Given data:

Mass of N₂H₄ formed = 28.5 g

Pressure = 1.50 atm

Temperature = 30°C (30+273 = 303 k)

Volume of N₂ and H₂ needed = ?

Solution:

Chemical equation:

N₂ + 2H₂  →  N₂H₄

Number of moles of N₂H₄ formed = mass/ molar mass

Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol

Number of moles of N₂H₄ formed = 0.89 mol

Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.

                N₂H₄                :                 N₂

                   1                     :                   1

                  0.89               :               0.89

                N₂H₄                :                 H₂

                   1                    :                  2

                 0.89               :                2×0.89 = 1.78 mol

Volume of H₂:

PV = nRT

1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K

V = 44.28atm.L /1.50 atm

V = 29.52 L

Volume of N₂:

PV = nRT

1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K

V = 22.14 atm.L /1.50 atm

V = 14.76 L

Answer:

106.7 degrees f

Explanation:

Answer:

Explanation:

The given values are:

a= 6m/s²

u= 0 m/s

v = 30 m/s

t= ?

The formula is :

[tex]a=\frac{v-u}{t}[/tex]

thus,

[tex]t=\frac{v-u}{a}\\t=\frac{30-0}{6}\\t= 5 seconds[/tex]

Answer:

11 g/mL

Explanation:

From the question given above, the following data were obtained:

Mass of metal = 102.06 g

Volume of water = 38 mL

Volume of water + metal = 47 mL

Density of metal =.?

Next, we shall determine the volume of the metal. This can be obtained as shown below:

Volume of water = 38 mL

Volume of water + metal = 47 mL

Volume of metal =..?

Volume of metal = (Volume of water + metal) – (Volume of water)

Volume of metal = 47 – 38

Volume of metal = 9 mL

Finally, we shall determine the density of the metal as follow:

Mass of metal = 102.06 g

Volume of metal = 9 mL

Density of metal =.?

Density = mass /volume

Density of metal = 102.06 / 9

Density of metal = 11.34 ≈ 11 g/mL

Therefore, the density of the metal is 11 g/mL