Morgan takes a train from London to Bewford and then another train to Agon.
The tree diagram shows the probabilities of Morgan's trains being late or not late.
to Bewford
to Agon
Late
0.24
Late
0.35
0.76
Not late
Late
0.24
0.65
Not late
0.76
Not
late
Morgan will not catch the train to Agon if the train to Bewford is late and the train to Agon is not late.
Work out the probability that Morgan will catch the train to Agon.
Give your answer as a decimal.

To verify that the function f(x) = -4x^2 + 12x - 4ln x attains an absolute maximum and absolute minimum on [1/2,2], we can use the Extreme Value Theorem.

First, we need to check if the function is continuous on the interval [1/2,2] and differentiable on the open interval (1/2,2).

The function is continuous on [1/2,2] because it is a polynomial and the natural logarithm function is continuous on its domain.

To check if it is differentiable on (1/2,2), we need to take the derivative:

f'(x) = -8x + 12 - 4/x

This is defined and continuous on the open interval (1/2,2).

Now we can find the critical points by setting f'(x) = 0:

-8x + 12 - 4/x = 0

Multiplying both sides by x and rearranging, we get:

-8x^2 + 12x - 4 = 0

Dividing by -4, we get:

2x^2 - 3x + 1 = 0

This factors as (2x - 1)(x - 1) = 0, so the critical points are x = 1/2 and x = 1.

We also need to check the endpoints of the interval:

f(1/2) = -4(1/4) + 6 - 4ln(1/2) = 2 - 4ln(1/2)

f(2) = -4(4) + 12(2) - 4ln(2) = 8 - 4ln(2)

Now we can compare the function values at the critical points and endpoints to find the absolute maximum and minimum:

f(1/2) = 2 - 4ln(1/2) ≈ 5.39

f(1) = -4(1) + 12(1) - 4ln(1) = 8

f(2) = 8 - 4ln(2) ≈ 0.31

So the absolute maximum value is 8, which occurs at x = 1, and the absolute minimum value is 0.31, which occurs at x = 2.

Therefore, the function f(x) = -4x^2 + 12x - 4ln x attains an absolute maximum and absolute minimum on [1/2,2], and the absolute maximum value is 8 and the absolute minimum value is 0.31.
To verify that the function f(x) = -4x^2 + 12x - 4ln(x) attains an absolute maximum and minimum on the interval [1/2, 2], we will first find its critical points by taking the first derivative and setting it to zero, and then evaluate the function at the critical points and endpoints.

The first derivative of f(x) is:

f'(x) = -8x + 12 - 4/x

Setting f'(x) to zero, we have:

-8x + 12 - 4/x = 0

Multiplying by x to remove the fraction, we get:

-8x^2 + 12x - 4 = 0

Dividing by -4, we have:

2x^2 - 3x + 1 = 0

Factoring, we get:

(x-1)(2x-1) = 0

This gives us the critical points x = 1 and x = 1/2.

Now, we evaluate f(x) at the critical points and endpoints:

f(1/2) = -4(1/2)^2 + 12(1/2) - 4ln(1/2)
f(1) = -4(1)^2 + 12(1) - 4ln(1)
f(2) = -4(2)^2 + 12(2) - 4ln(2)

Calculating these values, we get:

f(1/2) ≈ 5.386
f(1) = 4
f(2) ≈ -4

The absolute maximum value is ≈ 5.386 at x = 1/2, and the absolute minimum value is ≈ -4 at x = 2.

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According to given data GR(x) * GR(y) = 3 * 2m - 5

The given monomial is P(x;y) = -mx^3m-1 * y^2m-7, and it is known that GA(P) = 17.

We need to find the values of GR(x) and GR(y), which are the degrees of the monomial with respect to x and y, respectively.

Using the formula GA(P) = GR(x) + GR(y), we get GR(x) + GR(y) = 17.

Now, we can write the monomial as P(x;y) = (-m) * x^(3m-1) * y^(2m-7).

Therefore, GR(x) = 3m-1 and GR(y) = 2m-7.

Multiplying these two values, we get GR(x) * GR(y) = (3m-1) * (2m-7) = 6m^2 - 23m + 7.

Hence, the final answer is GR(x) * GR(y) = 6m^2 - 23m + 7.

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The future value of Payton's investment will be $1,048.29 when he cashes in the bond on the maturity date 15 years from now.

To calculate the future value of Payton's 15-year treasury bond, we can use the formula for compound interest:

FV = PV * (1 + r/n)^(n*t)

where FV is the future value, PV is the present value (or face amount), r is the interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the time period in years.

In this case, the present value is $700, the interest rate is 2.5% or 0.025, the interest is compounded quarterly, so n = 4, and the time period is 15 years.

Plugging in the values, we get:

FV = $700 * (1 + 0.025/4)^(4*15)

FV = $700 * (1 + 0.00625)^60

FV = $700 * 1.49756

FV = $1,048.29

Therefore, the future value of Payton's investment will be $1,048.29 when he cashes in the bond on the maturity date 15 years from now.

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To determine how many containers of size 3.7 tons are needed to hold all the gravel from one truck, we need to first calculate how many tons of gravel are in one truck.

Since each truck holds 7.5 cubic yards of gravel, and the weight of one cubic yard of gravel is 1.48 tons, we can calculate the total weight of gravel in one truck as follows:

7.5 cubic yards x 1.48 tons per cubic yard = 11.1 tons

Therefore, each truck carries 11.1 tons of gravel.

To determine how many containers of size 3.7 tons are needed to hold all the gravel from one truck, we can divide the total weight of gravel in one truck by the capacity of each container:

11.1 tons ÷ 3.7 tons per container = 3 containers

Therefore, three containers of size 3.7 tons are needed to hold all the gravel from one truck.

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The expression for the total volume of the building is V = L × W × H.

Volume is defined as the space occupied within the boundaries of an object in three-dimensional space.

To write an expression for the total volume of a building, we'll need to consider the dimensions of the building: length (L), width (W), and height (H). The volume of a rectangular building can be calculated using the formula:

Total Volume (V) = Length (L) × Width (W) × Height (H)

So, the expression for the total volume of the building is V = L × W × H.

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The solution to the quadratic equation using quadratic formula is: -1 or -1/2

The general form of expression of a quadratic equation is:

ax² + bx + c = 0

The quadratic formula for solving quadratic functions is:

x = [-b ± √(b² - 4ac)]/2a

If we have a quadratic equation as: 5x² + 6x + 1 = 0.

Using quadratic formula, we have:

x = [-6 ± √(6² - 4(5*6))]/2*5

x = -1 or -1/2

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The size of the square that needs to be cut out of each corner to create a box of maximum volume is 5/3 inches.

To determine the function f given that f'(x)=6x² – 5 sin x+eˣ and f(0) = 20, we need to integrate f'(x) with respect to x to obtain f(x), and then use the initial condition f(0) = 20 to find the value of the constant of integration.

Integrating f'(x) with respect to x, we have:

f(x) = 2x³ + 5 cos x + eˣ + C

where C is the constant of integration.

Using the initial condition f(0) = 20, we have:

f(0) = 2(0)³ + 5 cos 0 + e⁰ + C = 6 + C = 20

Therefore, the constant of integration is C = 14, and the function f(x) is:

f(x) = 2x³ + 5 cos x + eˣ + 14

To determine the size of the square that needs to be cut out of each corner of a standard piece of notebook paper to create a box of maximum volume, we can start by drawing a diagram of the box and labeling the sides as follows:

| |

| |

| | h

| |

|__________|

L

Let x be the length of each side of the square that is cut out of each corner. Then, the length and width of the base of the box will be L - 2x and 11 - 2x, respectively, and the height of the box will be x. Therefore, the volume V of the box can be expressed as:

V(x) = x(L - 2x)(11 - 2x)

Expanding and simplifying, we get:

V(x) = -4x³ + 46x² - 110x

To find the size of the square that maximizes the volume of the box, we need to find the value of x that maximizes V(x). This can be done by finding the critical points of V(x) and determining whether they correspond to a maximum or minimum.

Taking the derivative of V(x) with respect to x, we get:

V'(x) = -12x² + 92x - 110

Setting V'(x) = 0 and solving for x, we get:

x = 5/3 or x = 11/6

To determine whether these values correspond to a maximum or minimum, we can use the second derivative test. Taking the second derivative of V(x) with respect to x, we get:

V''(x) = -24x + 92

Evaluating V''(5/3) and V''(11/6), we find that:

V''(5/3) = -4 < 0, so x = 5/3 corresponds to a maximum.

V''(11/6) = 20 > 0, so x = 11/6 corresponds to a minimum.

Therefore, the size of the square that needs to be cut out of each corner to create a box of maximum volume is 5/3 inches.

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Dilating the figure by a scale factor of 3, the new coordinates are:

A' (-3, 12)

B' (9, 6)

C' (5886, -6)

D (unknown)

To dilate a figure by a scale factor, we need to multiply the coordinates of each point by the scale factor. Given the scale factor K = 3, we can dilate the figure using the formula:

New x-coordinate = K * original x-coordinate

New y-coordinate = K * original y-coordinate

Let's apply this to the given coordinates:

(-1, 4)

New x-coordinate = 3 * (-1) = -3

New y-coordinate = 3 * 4 = 12

A' (-3, 12)

(3, 2)

New x-coordinate = 3 * 3 = 9

New y-coordinate = 3 * 2 = 6

B' (9, 6)

(1962, -2)

New x-coordinate = 3 * 1962 = 5886

New y-coordinate = 3 * (-2) = -6

C' (5886, -6)

Dilating the figure by a scale factor of 3, the new coordinates are:

A' (-3, 12)

B' (9, 6)

C' (5886, -6)

D (unknown)

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1) function g is increasing on all intervals of x.

2) the same is true about both s and t.

3) functions s and g have the same x-intercept.

The phrase "function g is ___ on all intervals of x" refers to the behavior of the function g with respect to its input variable x. If we know that g is increasing on all intervals of x, this means that as we move from left to right along the x-axis, the values of g are increasing. In other words, if we were to plot the graph of g, it would be sloping upwards from left to right.

The phrase "the same is true about ____" is asking us to identify another function that has the same behavior as function g. The options given are both s and t, function s, function t, or neither s nor t. Without any further information about s and t, we cannot definitively say whether they are increasing on all intervals of x like g. Therefore, the correct answer is "both s and t," because this option covers the possibility that either s or t may have the same behavior as g.

The phrase "functions ____ have the same x-intercept" refers to the point(s) where the graph of each function intersects the x-axis. If we know that functions s and g have the same x-intercept, this means that they intersect the x-axis at the same point(s). Therefore, the correct answer is "s and g." However, there is no information given to suggest that function t has the same x-intercept as either s or g, so it is not a correct answer option.

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1. decreasing

2. function t

3. s and t

4. x

Got it right on Edmentum

Answer:

4.

Step-by-step explanation:

What is elimination method?

In the elimination method you either add or subtract the equations to get an equation in one variable

Lets solve for X first.

We have the equations:

5x+3y=8

4x+y=8

We take the GCM (3) and multiply everything on the bottom by -3 and multiply everything on the top by 1 (which in this case, dont touch the top) which we should now have:

5x+3y=8

-12x-3y=-36

We can now eliminate the Y and add like terms from the top to bottom, from which we should now have remaining:

-7x=-28

Solve for X

x=4

Now that we have 4, plug it in to one of the equations, which we should plug it in to 4x+y=12

4(4)+y=12

Simplify:

16+y=12

Subtract 16 to the other side:

y=-4

So now we got our x and y vaule, from which is how we get the answer (4,-4)

The amount of more sauce needed is 5/12.

Thus we are given that the total amount of sauce required for making the pizza is 2/3 cup.

Thus we already have 1/4 cup of tomato sauce present.

Hence, for making the recipe the leftover amount of sauce will be the difference in the sauce we have got to the sauce required.

Tomato sauce required= Total tomato sauce needed - Sauce already present

Therefore,

Tomato sauce required= 2/3-1/4

Thus we have to make the denominators qual by taking their LCM as the denominator.

The LCM of the denominators comes out to be 12.

Therefore,

[tex]=\frac{8-3}{12}[/tex]

[tex]=\frac{5}{12}[/tex]

Therefore, the amount of sauce required is 5/12.

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The police dog spends 1/6 of its workday at the police station.

To find the fraction of the police dog's workday spent at the police station, we need to add up the fractions of time spent in each location and subtract them from 1, since the dog spends the rest of the day at the police station.

Fraction of time spent in police car =  [tex]1/3[/tex]

Fraction of time spent in public = [tex]1/2[/tex]

To add these fractions, we need to find a common denominator:

[tex]1/3 = 2/6\\1/2 = 3/6[/tex]

So, the fraction of the dog's day spent at the police station is:

[tex]1 - (2/6 + 3/6) = 1 - 5/6[/tex]

                        = [tex]1/6[/tex]

Therefore, the police dog spends 1/6 of its workday at the police station.

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To determine which postulate can be used to prove that triangle CAT and triangle DOG are congruent, we need information about the side lengths and angles of each triangle. Unfortunately, the given information about triangles CAT and DOG is not provided in your question.

However, I can briefly explain each of the mentioned postulates to help you understand how they can be applied to prove congruence:

1. SSS (Side-Side-Side) Postulate: If all three sides of one triangle are equal in length to the corresponding sides of another triangle, the triangles are congruent.

2. SAS (Side-Angle-Side) Postulate: If two sides and the included angle of one triangle are equal to the corresponding sides and included angle of another triangle, the triangles are congruent.

3. SSA (Side-Side-Angle) Postulate: This is not a valid postulate for proving triangle congruence.

4. ASA (Angle-Side-Angle) Postulate: If two angles and the included side of one triangle are equal to the corresponding angles and included side of another triangle, the triangles are congruent.

5. AAS (Angle-Angle-Side) Postulate: If two angles and a non-included side of one triangle are equal to the corresponding angles and non-included side of another triangle, the triangles are congruent.

Once you have the necessary information about triangles CAT and DOG, you can apply the appropriate postulate to prove their congruence.

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Answer:

Step-by-step explanation:

P(0,7), Q(6,5), R(5,2), and S(-1,4) form the vertices of a rectangle. To prove this, we need to show that the opposite sides of the quadrilateral are parallel and that the diagonals are equal in length and bisect each other.

To explain this solution in more detail, we can start by finding the slopes of the line segments connecting each pair of points. The slope of a line segment can be calculated using the formula:

slope = (change in y) / (change in x)

For example, the slope of the line segment connecting P and Q is:

slope PQ = (5 - 7) / (6 - 0) = -2/6 = -1/3

We can calculate the slopes of the other line segments in a similar way. If the opposite sides of the quadrilateral are parallel, then their slopes must be equal. We can check that this is true for all pairs of opposite sides:

slope PQ = -1/3, slope SR = -1/3

slope QR = (2 - 5) / (5 - 6) = -3/-1 = 3, slope PS = (4 - 7) / (-1 - 0) = -3/-1 = 3

Next, we can calculate the lengths of the diagonals using the distance formula:

distance PR = sqrt[(5 - 0)^2 + (2 - 7)^2] = sqrt(5^2 + (-5)^2) = sqrt(50)

distance QS = sqrt[(6 - (-1))^2 + (5 - 4)^2] = sqrt(7^2 + 1^2) = sqrt(50)

If the diagonals are equal in length, then we should have distance PR = distance QS, which is indeed the case.

Finally, we need to show that the diagonals bisect each other. This means that the midpoint of PR should be the same as the midpoint of QS. We can calculate the midpoint of each diagonal using the midpoint formula:

midpoint of PR = [(0 + 5)/2, (7 + 2)/2] = (2.5, 4.5)

midpoint of QS = [(6 + (-1))/2, (5 + 4)/2] = (2.5, 4.5)

Since the midpoints are the same, we have shown that the diagonals bisect each other.

Therefore, we have shown that the points P(0,7), Q(6,5), R(5,2), and S(-1,4) form the vertices of a rectangle.

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The total lease cost for Clayton's SUV is $23,056.24.

Before any additional fees or deposits, the total lease cost is $421.38 per month for 48 months, which equals:

Total cost of the lease  = $421.38/month x 48 months = $20,236.24

Clayton also paid a $2,500 down payment, a $85 title charge, and a $235 license cost in addition to the monthly lease payments.

The entire cost of the lease is $20,236.24 + $2,500 + $85 + $235 = $23,056.24 in total.

Therefore, the total lease cost for Clayton's SUV is $23,056.24.

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The value from the Student's t distribution that we would use to calculate a 95% confidence interval is 2.048

When the population standard deviation, σ, is unknown, we use the sample standard deviation, s, to estimate it. The t-distribution is used to calculate the confidence interval when we have a small sample size (less than 30) and the population standard deviation is unknown.

The value from the t-distribution that we would use to calculate a 95% confidence interval for the mean with a sample size of 28 is the t-value with 27 degrees of freedom, denoted by t(0.025,27) is 2.048.

This value can be obtained from a t-distribution table or calculator, and it represents the number of standard errors away from the mean that corresponds to a 95% confidence interval.

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The lower and upper quartiles are calculated by finding the average of two values when there is an even number of data points in the dataset. Specifically, the lower quartile (Q1) is the average of the middle two values when the dataset is sorted in ascending order, and the upper quartile (Q3) is the average of the middle two values when the dataset is sorted in descending order.

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Answer:

It is a trapezoid

Step-by-step explanation:

Yes, the given points represent the vertices of a trapezoid.

A trapezoid is a quadrilateral with one set of parallel sides. In this case, the parallel sides are AB and CD. The other two sides, AD and BC, are not parallel.

The trapezoid is not isosceles because the two non-parallel sides are not congruent. AD has a length of 6 units, while BC has a length of 4 units.

Here is a diagram of the trapezoid:

A(-4,-1)

B((-4,6)

C(2,6)

D(2,-4)

A trapezoid is a quadrilateral with at least one pair of parallel sides. In this case, sides AB and CD are parallel because they have the same slope. So, the given points do represent the vertices of a trapezoid.

An isosceles trapezoid has two congruent legs (non-parallel sides). In this case, the length of side AD is `sqrt((-4-2)^2+(-1+4)^2)=sqrt(36+9)=sqrt(45)` and the length of side BC is `sqrt((-4-2)^2+(6-6)^2)=sqrt(36+0)=sqrt(36)`. Since `sqrt(45)` is not equal to `sqrt(36)`, the trapezoid is not isosceles.

The probability that a randomly chosen part has either a major flaw or a minor flaw is 22% or 0.22.

To find the probability that a randomly chosen cast aluminum part has a flaw (major or minor), we can simply add the percentages of parts with minor flaws and major flaws together.

From the given information, 20% of the parts had minor flaws and 2% had major flaws. When we add these percentages together, we get:

20% (minor flaws) + 2% (major flaws) = 22%

Thus, there is a 22% probability that a randomly chosen part has a flaw, either major or minor. Rounded to two decimal places, this would be written as 0.22.

In summary, by considering the percentages of parts with minor and major flaws, we can determine the overall probability of selecting a flawed part. In this case, the probability is 22% or 0.22 when rounded to two decimal places.

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Answer:

x = 150

Step-by-step explanation:

We know that the total amount of degrees in a circle is 360°.

We also know that a right angle is 90°.

Using this information, and the given 120° angle, we can form the following equation to solve for x:

90° + 120° + x° = 360°

210° + x° = 360°

x° = 360° - 210°

x° = 150°

x = 150

Step-by-step explanation:

120° + 90° + x = 360°

210° + x = 360°

x = 360° - 210°

= 150°

Step-by-step explanation:

area= base*height (8+10)*16=288

perimeter=2L+2B

to find L we will use Pythagorean theorem(check attachment for the solving to find L)

L=17.8

perimeter= 2(17.8)+2(18)

=71.77

=71.8

Based on study, it appears that mind-set does matter for maids in terms of weight loss - simply thinking they are exercising more may have led to greater weight loss in the informed group.

To determine whether mind-set matters in terms of weight loss for the maids, we need to conduct a hypothesis test.

Null Hypothesis: The average weight loss for the informed group of maids is equal to the average weight loss for the uninformed group of maids.

Alternative Hypothesis: The average weight loss for the informed group of maids is greater than the average weight loss for the uninformed group of maids.

We can use a one-sided t-test to test this hypothesis, since we are interested in whether the informed group lost more weight than the uninformed group.

Using the data provided, we can calculate the sample mean and standard deviation for each group:

Informed group:

Sample size (n) = 44

Sample mean = 2.00 lbs

Sample standard deviation = 2.50 lbs

Uninformed group:

Sample size (n) = 76

Sample mean = 1.33 lbs

Sample standard deviation = 2.31 lbs

We can use a t-test with unequal variances (since the sample standard deviations are different) to test the hypothesis. Using a significance level of 0.05 and a one-tailed test, the critical t-value is 1.67 (from a t-distribution with 118 degrees of freedom).

The calculated t-value is: t = (2.00 - 1.33) / sqrt((2.50^2/44) + (2.31^2/76)) = 1.80

Since the calculated t-value (1.80) is greater than the critical t-value (1.67), we reject the null hypothesis and conclude that there is evidence that the informed group of maids lost more weight than the uninformed group of maids.

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68.2% confidence of the students drink between: 131 and 175 bottles of water per day.

We can use the empirical rule, also known as the 68-95-99.7 rule, to determine the range of values that contain 68.2% of the data in a normal distribution. According to the rule, approximately 68.2% of the data falls within one standard deviation of the mean.

We know that the mean amount of bottled water consumed is 153 bottles, with a standard deviation of 22 bottles. Therefore, one standard deviation below the mean is 153 - 22 = 131 bottles, and one standard deviation above the mean is 153 + 22 = 175 bottles.

Thus, we can say with 68.2% confidence that the number of bottled water consumed by students each day falls between 131 and 175 bottles.

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Answer: Apartment

Confidence

Cooperating

Disrespect

Encode

Forearm

Injustice

Intercontinental

Interplanetary

Mold

Overgrown

Refuel

Repaid

Semi-Sweet

Semicircular

Shield

Subzero

Supermarket

Transportation

Unbelievably

Step-by-step explanation:

Answer:

15

13

6

11

7

1

4

12

17

16

10

8

9

19

3

18

2

5

14

20

The measure of an angle that goes through 2/8 of a circle is 90°

A circle is a 2-dimensional shape that is round in shape it is equidistant from the center.

A circle has a total angle of 360°

That is the whole complete angle of the circle = 360°

The 2/8 th of the complete angle of the circle = 360 * 2/8

= 360 * 1/4

= 360/4

=90°

Thus, the 90° of the circle is given as 2/8th of an angle of the circle or we can say that the quarter angle of a circle comes out to 90°.

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The given data is an example of a nonlinear function. Therefore, the answer is A.

The given data consists of two sets of numbers, X and Y, where each value of X has a corresponding value of Y. We can observe that the points do not lie on a straight line. Instead, the plotted points form a curved shape, which indicates that the relationship between X and Y is not a linear function.

A linear function is a function where the relationship between the input variable (X) and output variable (Y) is a straight line. In this case, we can observe that as the value of X increases, the value of Y increases at an increasing rate, which means the relationship between X and Y is not linear.

In particular, the relationship between X and Y is a quadratic function since the values of Y are the squares of the corresponding values of X.

Therefore, the answer is A.

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The area of the region bounded by the curves is 4/3 square units.

To find the area of the region bounded by the curves y = 10 - [tex]x^2[/tex] and y = [tex]x^2[/tex] + 8, we need to find the points of intersection between the two curves.
Setting the two equations equal to each other, we have:
10 - [tex]x^2[/tex] = [tex]x^2[/tex] + 8
Simplifying, we get:
[tex]2x^2[/tex] = 2
[tex]x^2[/tex] = 1
x = ±1
Substituting x = 1 into either equation gives us:
y = 10 - [tex]1^2[/tex] = 9
And substituting x = -1 gives us:
y = 10 - [tex](-1)^2[/tex] = 10
So the two curves intersect at the points (1, 9) and (-1, 10).
To find the area of the region bounded by the curves, we need to integrate the difference between the two equations with respect to x, from x = -1 to x = 1:
∫[10 - [tex]x^2[/tex]] - [[tex]x^2[/tex] + 8] dx, from x = -1 to x = 1
= ∫(2 - 2[tex]x^2[/tex]) dx, from x = -1 to x = 1
= [2x - (2/3)[tex]x^3[/tex]] from x = -1 to x = 1
= 4/3
So

The area of the region bounded by the curves y = 10 - [tex]x^2[/tex] and y = [tex]x^2[/tex] + 8 is 4/3 square units.

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∠AOD≅∠COB,∠AOB≅∠COD by vertical angle theorem. ΔAOD≅ΔCOB,ΔAOB≅ΔCOD by SAS. ∠DAC≅∠BCA,∠BAC≅∠DCA by CPCTC. AB║CD,AD║BC by converse alternate interior angles theorem

Vertical angles theorem states that perpendicular angles, angles that are contrary each other and formed by two cutting straight lines, are harmonious.

Alternate angle theorem states that when two resemblant lines are cut by a transversal, also the performing alternate interior angles or alternate surface angles are harmonious.

SAS Side angle side

CPCTC Corresponding corridor of harmonious triangles are harmonious.

discourse of alternate interior angle theorem If two alternate interior angles are harmonious also the two lines are resemblant.

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