Mr. Larson, a math teacher, assigned his students a project to do in pairs. He recorded the


grade each pair earned.


Math project grades


92 77 97 70 96 75


73


84


71


87


80


86


100


95


Which box plot represents the data?


Math project grades


50


60


70


80


90


100


Math project grades


50


60


70


80


90


100

The area of the parallelogram is 300 centimetres squared.

The length of the base is 20 centimetres. The length of the sides is 17 centimetres. The overhang of the base is 8 centimetres long. The angle between the overhang and the height is a right angle.

Therefore,

area of a parallelogram = b × h

where

Therefore, let's use Pythagoras's theorem to find the height of the parallelogram as follows
17² - 8² = h²

289 - 64 = h²

h = √225

h = 15 centimetres

Therefore,

area of the parallelogram = 20 × 15

area of the parallelogram = 300 cm squared

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The approximate values of y at x = 0.1, 0.2, 0.3, and 0.4 are all equal to y1 = y2 = y3 = y4 = 0.5, as we only used the first step of Euler's method.

We can use Euler's method with a step size of 0.5 to approximate the solution of the given initial-value problem as follows:

First, we need to find the slope at the initial point (0, -3):

y' = 1 - 2x - 2y

y'(0, -3) = 1 - 2(0) - 2(-3) = 7

Using Euler's method, we can approximate the solution at x = 0.5:

y(0.5) ≈ y(0) + hy'(0, -3) = -3 + 0.57 = 0.5

Next, we can use the approximate value y(0.5) to approximate the solution at x = 1:

y(1) ≈ y(0.5) + hy'(0.5, 0.5) = 0.5 + 0.5(1 - 2(0.5) - 2(0.5)) = -0.5

Similarly, we can use the approximate value y(1) to approximate the solution at x = 1.5:

y(1.5) ≈ y(1) + hy'(1, -0.5) = -0.5 + 0.5(1 - 2(1) - 2(-0.5)) = -1.25

Finally, we can use the approximate value y(1.5) to approximate the solution at x = 2:

y(2) ≈ y(1.5) + hy'(1.5, -1.25) = -1.25 + 0.5(1 - 2(1.5) - 2(-1.25)) = -2.4375

Therefore, the approximate values of y at x = 0.1, 0.2, 0.3, and 0.4 are all equal to y1 = y2 = y3 = y4 = 0.5, as we only used the first step of Euler's method.

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The equation for the line of symmetry for the function f(x) = -7x² + 14x -19 is x = 1.

The line of symmetry for a quadratic function, f(x) = ax² + bx + c, is a vertical line that passes through the vertex of the parabola, and its equation is given by x = -b/(2a). In the function f(x) = -7x² + 14x - 19, the coefficients are a = -7, b = 14, and c = -19.

Applying the formula, x = -b/(2a), we get:

x = -(14)/(2*(-7))

x = -14 / (-14)

x = 1

Thus, the equation for the line of symmetry for the function f(x) = -7x² + 14x - 19 is x = 1. This line divides the parabola into two symmetrical halves, and the vertex of the parabola lies on this line.

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The width of the toy train track is 4 cm.

To find the width of the toy train track, we need to consider the inner radius, the arc length of the inner sector, and the arc length of the outer sector.

Given:
Inner radius (r1) = 6 cm
Inner arc length (s1) = 33 cm
Outer arc length (s2) = 55 cm

Step 1: Find the central angle (θ) using the inner arc length and inner radius.
θ = s1/r1 = 33 cm / 6 cm = 5.5 radians

Step 2: Find the outer radius (r2) using the central angle and the outer arc length.
s2 = r2 × θ
55 cm = r2 × 5.5 radians
r2 = 55 cm / 5.5 radians = 10 cm

Step 3: Calculate the width of the track.
Width = Outer radius - Inner radius
Width = r2 - r1 = 10 cm - 6 cm = 4 cm

The width of the toy train track is 4 cm.

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The value of x is [tex]\sqrt{\frac{2}{6} }[/tex]

A function can be defined as a law or expression showing the relationship between two variables.

From the information given, we have that;

f(x) = x ^ 2 + 1

g(x) = 3x

To determine the composite function, substitute the value of the function inside the bracket and the value of x in the other function, we have;

fg(x) = (3x²) + 1

expand the bracket

fg(x) = 9x² + 1

Then,

gf(x) = 3(x² + 1)

expand the bracket

gf(x) = 3x² + 3

Equate the functions, we have;

9x² + 1 = 3x² + 3

collect the like terms

6x² = 2

Divide the value

x = [tex]\sqrt{\frac{2}{6} }[/tex]

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In the given ratio problem, Eli gets 21 sweets.

Let's assume that Dylan gets 7x sweets, Eli gets 3x sweets, and Fabian gets 5y sweets.

From the given information, we know that:

[tex]5y = 7x + 21[/tex] (since Fabian gets 21 more sweets than Dylan)

We can simplify this expression by dividing both sides by 5:

[tex]y = (7/5)x + 21/5[/tex]

We can also express the ratio of the amount of sweets that Dylan gets to the amount that Fabian gets as [tex]4:5[/tex], which means that:

[tex]4x = (5/1)y[/tex]

Substituting y from the first equation, we get:

[tex]4x = (5/1)*[(7/5)x + 21/5][/tex]

Simplifying this equation, we get:

[tex]4x = 7x + 21[/tex]

[tex]3x = 21[/tex]

[tex]x = 7[/tex]

Therefore, Dylan gets [tex]7x = 49[/tex] sweets, Eli gets [tex]3x = 21[/tex] sweets, and Fabian gets [tex]5y = 70[/tex] sweets.

Hence, Eli gets [tex]21[/tex] sweets.

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Answer:

2x + 3x = 475

= 5x = 475

= x = 475/5

= x = 95

Answer:

285 boys

Step-by-step explanation:

2 + 3 = 5

475/5=95

Girls: 2 x 95= 190

Boys: 3 x 95 = 285

Check

285 + 190= 475

To find the maximums and minimums of the function f(x,y)=x^2+y^2+xy in the region {(x,y): x^2+y^2<=1}, we need to use the method of Lagrange multipliers.

First, we need to find the gradient of the function and set it equal to the gradient of the constraint (which is the equation of the circle x^2+y^2=1).

∇f(x,y) = <2x+y, 2y+x>
∇g(x,y) = <2x, 2y>

So, we have the equations:
2x+y = 2λx
2y+x = 2λy
x^2+y^2 = 1

Simplifying the first two equations, we get:
y = (2λ-2)x
x = (2λ-2)y

Substituting these into the equation of the circle, we get:
x^2+y^2 = 1
(2λ-2)^2 x^2 + (2λ-2)^2 y^2 = 1
(2λ-2)^2 (x^2+y^2) = 1
(2λ-2)^2 = 1/(x^2+y^2)

Solving for λ, we get:
λ = 1/2 or λ = 3/2

If λ = 1/2, then we get x = -y and x^2+y^2=1, which gives us the critical points (-1/√2, 1/√2) and (1/√2, -1/√2). We can plug these into the function to find that f(-1/√2, 1/√2) = f(1/√2, -1/√2) = -1/4.

If λ = 3/2, then we get x = 2y and x^2+y^2=1, which gives us the critical point (2/√5, 1/√5). We can plug this into the function to find that f(2/√5, 1/√5) = 3/5.

Therefore, the local maximum is (2/√5, 1/√5) with a value of 3/5, the local minimum is (-1/√2, 1/√2) and (1/√2, -1/√2) with a value of -1/4, and the absolute maximum is also (2/√5, 1/√5) with a value of 3/5, and the absolute minimum is on the border, which occurs at (0,1) and (0,-1) with a value of 0.

There are no critical points in the interior of the disk (not the border) that are not extremes or saddle points.
(i) Local extrema:
To find the local extrema, we first find the partial derivatives of f(x, y) with respect to x and y:

f_x = 2x + y
f_y = 2y + x

Set both partial derivatives equal to zero to find critical points:

2x + y = 0
2y + x = 0

Solving this system of equations, we find that the only critical point is (0, 0).

(ii) Absolute extrema:
To determine whether the critical point is an absolute maximum, minimum, or saddle point, we must examine the second partial derivatives:

f_xx = 2
f_yy = 2
f_xy = f_yx = 1

Compute the discriminant: D = f_xx * f_yy - (f_xy)^2 = 2 * 2 - 1^2 = 3

Since D > 0 and f_xx > 0, the point (0, 0) is an absolute minimum of the function.

(iii) Critical points and their classification:
The only critical point in the interior of the disk is (0, 0). As determined earlier, this point is an absolute minimum. No saddle points or other extrema are present within the interior of the disk.

To find any extrema on the boundary of the disk (x^2 + y^2 = 1), we use the method of Lagrange multipliers. However, as the boundary is not part of the domain specified in the question, we will not delve into that here.

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The graph representing the ice sheet's thickness (y) over time (x, in weeks) is a linear equation with a negative slope.

We are given the initial thickness of the ice sheet (2 meters) and its thickness after 3 weeks (1.25 meters). The rate of decrease in thickness is constant.

To find the slope, we can use the formula: (change in y) / (change in x). Here, the change in y is (1.25 - 2) = -0.75 meters, and the change in x is 3 weeks.

Therefore, the slope is -0.75 / 3 = -0.25 meters/week. The graph will be a straight line with a negative slope, indicating that the ice sheet's thickness is decreasing at a constant rate over time.

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The combined time if Mike and Nancy worked together is approximately 1.71 hours.

To answer your question, we can use the concept of work rates. Mike can mop McDonald's in 3 hours and Nancy can do it in 4 hours. To find the combined work rate, we can use the formula:

1/Mike's rate + 1/Nancy's rate = 1/combined rate

1/3 + 1/4 = 1/combined rate

To solve for the combined rate, we can find a common denominator for the fractions:

(4 + 3) / (3 × 4) = 1/combined rate

7/12 = 1/combined rate

Now we can find the combined time by inverting the combined rate:

Combined time = 12/7

So, if Mike and Nancy worked together, they would mop McDonald's in 12/7 hours, which is approximately 1.71 hours.

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Main answer:

Working together, Mike and Nancy can mop the McDonald's in 12/7 hours or approximately 1.71 hours (rounded to two decimal places).

Explanation:

To solve the problem, we can use the following formula:

time = work / rate

where time is the time it takes to complete the job, work is the amount of work to be done (which in this case is mopping the McDonald's), and rate is the rate of work, or the amount of work done per unit of time.

Let's let x be the time it takes for Mike and Nancy to mop the McDonald's together. Then, we can set up two equations based on the given information:

x = work / (Mike's rate of work)

x = work / (Nancy's rate of work)

To solve for x, we can use the fact that the amount of work to be done is the same in both equations. So we can set the two equations equal to each other:

work / (Mike's rate of work) = work / (Nancy's rate of work)

Simplifying this equation by multiplying both sides by (Mike's rate of work)*(Nancy's rate of work), we get:

work * (Nancy's rate of work) = work * (Mike's rate of work)

We can cancel out the work on both sides, and then solve for x:

x = 1 / [(1/Mike's rate of work) + (1/Nancy's rate of work)]

Substituting in the given rates of work, we get:

x = 1 / [(1/3) + (1/4)] = 12/7

Therefore, it takes Mike and Nancy 12/7 hours, or approximately 1.71 hours (rounded to two decimal places), to mop the McDonald's together.

The volume of the fish tank is approximately 3,693,142,608 cubic inches

To find the volume of the rectangular prism-shaped fish tank, we need to multiply its width, length, and height.

Given the dimensions are 2014 inches wide, 1012 inches long, and 1812 inches tall, the calculation is as follows:

Volume = Width × Length × Height

Volume = 2014 in × 1012 in × 1812 in

Upon calculating the product, we get:

Volume ≈ 3,693,142,608 cubic inches

The volume of the fish tank is approximately 3,693,142,608 cubic inches

N.B: None of the answer choices has the correct answer.

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Quadrilaterals have four sides, two diagonals, and the sum of their interior angles is 360 degrees.

Quadrilaterals are four-sided polygons that have two diagonals connecting opposite vertices. One of the most important properties of quadrilaterals is that the sum of their interior angles is always equal to 360 degrees. This means that a quadrilateral can be divided into two triangles, each of which has a total of 180 degrees. This relationship between triangles and quadrilaterals is useful when calculating the area of a quadrilateral.

The formula for calculating the area of a quadrilateral is A = B x H, where A is the area, B is the base, and H is the height. This formula is applicable to all types of quadrilaterals, regardless of their shape or size. However, different types of quadrilaterals have unique properties and formulas for calculating their area.

For example, a square is a type of quadrilateral that has four sides of equal length and four right angles. The formula for finding the area of a square is A = s², where s is the length of the side. A rectangle is a type of quadrilateral with two pairs of parallel sides and four right angles. The formula for calculating the area of a rectangle is A = L x W, where L is the length and W is the width.

A rhombus is another type of quadrilateral that has four sides of equal length, but its angles are not necessarily right angles. The formula for finding the area of a rhombus is A = (D₁ x D₂) / 2, where D₁ and D₂ are the lengths of the diagonals.

A trapezoid is a quadrilateral with one pair of parallel sides. The formula for finding the area of a trapezoid is A = ((B₁ + B₂) / 2) x H, where B₁ and B₂ are the lengths of the parallel sides, and H is the height between them.

Kites are quadrilaterals with two pairs of adjacent equal-length sides. The formula for finding the area of a kite is A = (D₁ x D₂) / 2, where D₁ and D₂ are the lengths of the diagonals.

In summary, all quadrilaterals share some common characteristics, such as having four sides, two diagonals, and the sum of their interior angles being equal to 360 degrees. However, different types of quadrilaterals have distinct properties and formulas for finding their area. By understanding these properties and formulas, one can solve problems involving different types of quadrilaterals.

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Waterways Corporation's budget for Q1 2022 involves sales, inventory, materials, labor, overhead, expenses, and financing.

Waterways Corporation is preparing its budget for the first quarter of 2022. The company has gathered information from its managers to begin the budgeting process.

The company expects unit sales to be 112,000 in November 2021, 104,000 in December 2021, and 113,000 in January 2022. The company also expects to keep 10% of next month's unit sales in ending inventory. The company collects 85% of Accounts Receivable in the month of sale and 15% in the month after sale.

Raw materials cost 80 cents per pound, and two pounds of direct materials are required to produce each unit. The company likes to keep 5% of the materials needed for the next month in its ending inventory.

Labor requires 12 minutes per unit, paid at a rate of $9 per hour. The company has variable selling and administrative costs of $1.60 per unit, including advertising, insurance, salaries, and depreciation. The company also plans to make a $480,000 equipment purchase in February.

The company's cash balance on December 31, 2021, was $99,000, but the management wants to maintain a cash balance of at least $700,000 starting on January 31, 2022. The company pays dividends each month at the rate of $2.70 per share for 4,610 shares outstanding.

The company has an open line of credit with Romney's Bank with borrowing terms of $1,000 increments at 9% interest. The company borrows on the first day of the month and repays on the last day of the month.

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The measure of in quadrilateral GERA ∠GAR = 102° , ∠TAR = 23°, ∠GAN = 55° , m AG = 110° , m RE = 110° , m GE = 94°

∠REG = 78° , m AR = 46

The sum of the opposite angle of the quadrilateral is equal to 180°

∠REG + ∠GAR = 180°

∠GAR = 180 - ∠REG

∠GAR = 180 - 78

∠GAR = 102°

The tangent chord angle is half the intercept arc

∠TAR = 1/2 m AR

∠TAR = 1/2 ×46

∠TAR = 23°

The sum of straight angles is 180

m ∠GAN = 180 - (m ∠TAR + m ∠GAR )

m ∠GAN =  180 - (23 + 120)

m ∠GAN = 55°

The tangent chord angle is half the intercept arc

m AG = 2 m ∠GAN

m AG = 2(55)

m AG = 110°

as EG = GA

m RE = m GA

m RE = 110°

Complete angle sum = 360°

m GE = 360 - (m AG + m AR + m RE)

m GE = 360 - (110 + 46 + 110 )

m GE = 94°

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Maximum and Minimum values of f(x, y) = xy on the ellipse 3x² + y² = 9.

The maximum value is 3

The minimum value is -3

To find the maximum and minimum values of f(x, y) = xy on the ellipse 3x² + y² = 9, follow these steps:

1. Use the constraint equation (ellipse equation) to solve for one of the variables, either x or y.

Here, let's solve for y:
y² = 9 - 3x²
y = ±√(9 - 3x²)

2. Substitute y in the function f(x, y) with the expressions found in step 1:
f(x, y) = x(±√(9 - 3x²))

3. Differentiate f(x, y) with respect to x to find critical points (maximum or minimum):
f'(x, y) = ±(√(9 - 3x²) - (3x² / √(9 - 3x²)))

4. Set f'(x, y) = 0 and solve for x:
√(9 - 3x²) - (3x² / √(9 - 3x²)) = 0

5. Find the corresponding y values for the x values found in step 4 by substituting x back into the expressions found in step 1.

6. Evaluate f(x, y) at each critical point (x, y) found in steps 4 and 5 to determine the maximum and minimum values.

The maximum value of f(x, y) = xy on the ellipse 3x² + y² = 9 is 3, and the minimum value is -3.

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Answer:8

Step-by-step explanation:

Answer:

( 5 , 5½ )

Step-by-step explanation:

It's simple actually, use the midpoint formula,

[tex] \frac{x1 + x2}{2} ... \frac{y1 + y2}{2} = ( \frac{8 + 2}{2} ... \frac{4 + 7}{2} ) = (5..5 \frac{1}{2} )[/tex]

Take the ... as a comma.

So the final answer is ( 5 , 5.5 )

The probability of not rolling a multiple of 4 with the 6 sided dice is P =0.5

A 6D dice has the 6 outcomes {1, 2, 3, 4, 5, 6}, The ones that are a factor of 4 are:

{1, 2, 4}

Then 3 out of 6 outcomes are a factor of 4, thus, the other 3 aren't factors of 4.

Then the probability of not rolling a multiple of 4 is given by the quotient between the number of outcomes that arent multiples of 4 and the total number of outcomes.

P = 3/6 = 0.5

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To find the arc length between each car on the Ferris Wheel, we need to first find the measure of the central angle formed by each car.

The Ferris Wheel has a diameter of 150 ft, which means its radius is half that of 75 ft. We can use the formula s = rθ, where s is the arc length, r is the radius, and θ is the central angle in radians.

Since we have 25 cars on the Ferris Wheel, we can divide the circle into 25 equal parts, each representing the central angle formed by each car.

The total central angle of the circle is 2π radians (or 360 degrees), so each central angle formed by each car is:

(2π radians) / 25 = 0.2513 radians (rounded to four decimal places)

Now we can use this central angle and the radius of the Ferris Wheel to find the arc length between each car:

s = rθ
s = 75 ft * 0.2513
s = 18.8475 ft (rounded to four decimal places)

Therefore, the approximate arc length between each car on the Ferris Wheel is approximately 18.85 ft.

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Answer :

Step-by-step explanation:

60 minutes = 1 hour

1 minute = 1/60

1 minute = 0.016666666666667 hours

1.47 minutes = 0.016666666666667 × 1.47

1.47 minute = 0.0245 hours

Therefore, 1.47 Minutes is equal to 0.0245 Hours.

The direction of the vector is (-5, -8).

To find the direction in which the function is increasing most rapidly at point P(2, -1),

we need to find the gradient vector of the function at that point.

The gradient vector of the function f(x, y) = xy^2 - yx^2 is given by:

∇f(x, y) = ( ∂f/∂x , ∂f/∂y ) = ( y^2 - 2xy , 2xy - x^2 )

So, at point P(2, -1), we have:

∇f(2, -1) = ( (-1)^2 - 2(2)(-1) , 2(2)(-1) - 2^2 ) = (-5, -8)

The direction of greatest increase is in the direction of the gradient vector.

So, the direction in which the function is increasing most rapidly at point P(2, -1) is in the direction of the vector (-5, -8).

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A reasonable scale factor that could be applied to Shape 2 to create Shape 1 is 0.5.

When we talk about scaling a shape, we mean changing the size of the shape while maintaining its overall proportions.

This can be done by multiplying all of the dimensions of the shape by the scale factor.

For example, if we wanted to make a shape twice as big, we would multiply all of its dimensions (length, width, and height) by 2. If we wanted to make it half as big, we would multiply all of its dimensions by 0.5.

Looking at the two shapes, we can see that Shape 1 is half the size of Shape 2 in all dimensions.

For example, the height of Shape 1 is half the height of Shape 2, the width of Shape 1 is half the width of Shape 2, and the length of Shape 1 is half the length of Shape 2.

Therefore, to transform Shape 2 into Shape 1, we need to multiply all of its dimensions by 0.5. This will result in a scaled copy of Shape 2 that is identical in shape to Shape 1.

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Let's use the method of setting up a system of equations to solve this problem.

Let x be the number of pints of the first type of fruit drink (30% pure), and y be the number of pints of the second type of fruit drink (55% pure). We want to find the values of x and y that will produce 60 pints of a mixture that is 40% pure.

We can start by setting up two equations based on the information given:

Equation 1: x + y = 60 (since we want to produce 60 pints of the mixture)

Equation 2: 0.3x + 0.55y = 0.4(60) (since we want the mixture to be 40% pure)

Simplifying Equation 2, we get:

0.3x + 0.55y = 24

Now we have a system of two equations with two unknowns:

x + y = 60

0.3x + 0.55y = 24

We can solve this system using substitution or elimination. Here, we'll use substitution:

Solving Equation 1 for x, we get x = 60 - y. Substituting this expression for x in Equation 2, we get:

0.3(60 - y) + 0.55y = 24

Expanding and simplifying, we get:

18 - 0.3y + 0.55y = 24

Combining like terms, we get:

0.25y = 6

Dividing by 0.25, we get:

y = 24

Substituting this value of y back into x + y = 60, we get:

x + 24 = 60

Solving for x, we get:

x = 36

Therefore, we need 36 pints of the 30% pure fruit drink and 24 pints of the 55% pure fruit drink to make 60 pints of a mixture that is 40% pure.

Answer:

Part 1: 73 periods

Part 2: 73 periods in 1 year - 365/5=73

Part 3: 0.075 periodic interest rate - 180/2400=0.075

This is just a rough estimate, and the actual number of pumpkins that weigh less than 15.5 pounds could be slightly higher or lower.

What is the median?

The median is a measure of central tendency that represents the middle value in a dataset when the values are arranged in order of magnitude.

Assuming that the quartiles divide the pumpkins' weights into four equal parts, we can use the value of the second quartile (Q2) to estimate the median weight of the pumpkins. Since there are 80 pumpkins, Q2 would be the average of the 40th and 41st heaviest pumpkins.

We don't know the exact values of the quartiles, but we can make some reasonable assumptions. For example, if we assume that the first quartile (Q1) is around 12 pounds and the third quartile (Q3) is around 20 pounds, then we can estimate the median weight as follows:

Median = (Q2) = (Q1 + Q3)/2 = (12 + 20)/2 = 16 pounds

Based on this estimate, we can expect that roughly half of the 80 pumpkins (i.e., 40 pumpkins) weigh less than 16 pounds. Therefore, we might expect that slightly fewer than 40 pumpkins would weigh less than 15.5 pounds.

However, this is just a rough estimate, and the actual number of pumpkins that weigh less than 15.5 pounds could be slightly higher or lower depending on the distribution of the pumpkin weights.

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To find dy/dx implicitly, we need to differentiate both sides of the equation with respect to x, treating y as a function of x and using the chain rule.

In this problem, we are given the equation X^2e^{-x} + 3y^2 - xy = 0, and we need to find dy/dx. To do this, we first differentiate each term with respect to x, using the product rule for the xy term and the chain rule for the y^2 term. Then we can solve for dy/dx by isolating the derivative term on one side of the equation. Implicit differentiation is a powerful technique used in calculus to find derivatives of functions that are not easily expressed in terms of a single variable. This technique is used extensively in many areas of mathematics, science, and engineering, including optimization, physics, and economics.

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The solution of the system of equations is

A system of equations is a set of two or three equations.

Given the system of equations

x + y = 5 (1)

y + z = 6 (2)

z + x = 9 (3)

Givent he guide (1) - (2) x - z = - 1 (4), we proceed to solve the system of equations

Now, taking equations (3) and (4), we have that

z + x = 9 (3)

x - z = - 1 (4)

Adding them we have that

z + x = 9 (3)

+

x - z = - 1 (4)

2x = 9 - 1

2x = 8

x = 8/2

x = 4

From equation (3)

z = 9 - x

So, substituting the value of x into the equation, we have that

z = 9 - x

z = 9 - 4

z = 5

From equation (2)

y = 6 - z

So, substituting z into the equation, we have that

y = 6 - z

= 6 - 5

= 1

So,

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No, quadrilaterals ABCD and EFGH are not similar because the ratio of their corresponding sides is not proportional.

In Geometry, two (2) quadrilaterals are similar when the ratio of their corresponding sides are equal in magnitude and their corresponding angles are congruent.

Additionally, two (2) geometric figures such as quadrilaterals are considered to be congruent only when their corresponding side lengths are congruent (proportional) and the magnitude of their angles are congruent.

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