Net work W would accelerate an object from rest to velocity v. What net work is needed to accelerate the object from rest to velocity 2v?

Answer:

The toy car. An object that isn't moving has no momentum

Explanation:

Answer:

The toy car

Explanation:

the real car is parked so yeah but maybe in some way technically the real car has more "momentum"

The velocity of the experimental vehicle after 2 seconds is 14 m/s.

The displacement of the experimental vehicle after 2 seconds is 14 m.

The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.

The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:

v = u + at

where;

u is the initial velocity = 0 m/s

a is the acceleration = 7 m/s²

t is time = 2 seconds

v = 0 + 7 * 2

v = 14 m/s

The displacement, s, of the vehicle is calculated below as follows:

v² = u² + 2as

14² = 0² + 2 * 7 * s

s = 196 / 14

s = 14 m

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Answer:

Average speed [tex]= 2.5[/tex] meter per second

Explanation:

Given

The total distance walked [tex]= 2250[/tex] meters

The total time taken to walk [tex]2250[/tex] meters is [tex]15[/tex] minutes

In one minute there are [tex]60[/tex] seconds

As we know Average speed is equal to total distance travelled divided by total time taken

Hence,

Average speed

[tex]\frac{2250}{15*60} \\2.5[/tex]meter per second

Answer:

Explanation:

An electron accelerates through a 12.5 V potential difference, starting from rest, so it will acquire kinetic energy of 12.5 eV .

In hydrogen atom energy of n th orbit in terms of eV is given as follows

En = -13.6 / n² eV

Total energy of 1 st orbit  E₁ = - 13.6 eV

Total energy of 2 st orbit E₂ = - 13.6 eV / 2² = - 3.4 eV

Total energy of 3 st orbit E₃ = - 13.6 eV / 3² = - 1.5  eV

Total energy of 4 st orbit E₄ = - 13.6 eV / 4² = - 0.85 eV

E₄ - E₁ = 13.6 - 0.85 = 12.75 eV

E₃ - E₁ = 13.6 - 1.5 = 12.10 eV

E₂ - E₁ = 13.6 - 3.4 = 10.2 eV .

The electron has energy of 12,5 eV so it can excite electron from E₁ to E₃ . .

Jump possible = E₃ to E₂ , E₂ to E₁ and E₃ to E₁

Energy of E₃ to E₂ = 3.4 - 1.5 eV = 1.9 eV

wavelength = 1237 / 1.9 nm = 651 nm

E₃ - E₁ = 13.6 - 1.5 = 12.10 eV

wavelength  = 1237 / 12.10  nm = 102.23 nm

E₂ - E₁ = 13.6 - 3.4 = 10.2 eV

wavelength  = 1237 / 10.2  nm = 121.27  nm

wavelength of photon possible are 651 nm , 121.27  nm , 102.23 nm .

Answer:

I believe it's applied force (push)

The single cable will pull upward on the sign with a force of 38.3 N.

Single cable is a type of cable that is composed of a single electrical conductor. It is most commonly used in low voltage applications such as wiring for computers and domestic appliances. Single cable is typically insulated with rubber, PVC or other insulating materials. The insulator protects the conductor from short circuits and other electrical hazards.

This is because the sign is supported symmetrically by two cables, which means that the total downward force on the sign is equal to the total upward force. Since the two cables make an angle of 1.0 degrees with the horizontal, the total downward force on the sign is equal to the combined weight of the sign (38.3 N) and the two cables pulling down on it. Therefore, the single cable must pull up with a force of 38.3 N in order to keep the sign in equilibrium.

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Answer:

12.3 m/s

Explanation:

To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:

7100 = 1/2 (63.2 kg) v^2

Therefore, v^2 = 7100/31.6

v = √(7100/31.6)

v = 12.3 m/s

Answer: hello your question is poorly written attached below is the complete question

P(  ³₂He₊ )  at ground state = 1

Explanation:

Determine the probability that the  3He atom is in its ground state after decay

From the attached solution the coulomb interaction of ( ³₂He)  is double that of H³ . given that coulomb interaction is attractive ( -ve ) this will make  the product to become more stable hence the product ( ³₂He₊ ) will be gotten at the ground state

i.e. P(  ³₂He₊ )  at ground state = 1

attached below is a detailed solution

Answer:

AS

Explanation:

Explanation:

Dimensions help understand how physical amounts are related to their dependence on basic or fundamental volumes, i.e. how the body's dimensions rely on mass, time, length and temperature.

Understanding dimensions is of utmost importance as it helps us in studying the nature of physical quantities mathematically. The basic concept of dimensions is that we can add or subtract only those quantities which have same dimensions. Also, two physical quantities are equal if they have same dimensions.

Answer:

speed

Explanation:

you need to move fast so the tornado can't reach you

Answer:

[tex]\% Error = 2.6\%[/tex]

Explanation:

Given

[tex]x: 1.54, 1.53, 1.44, 1.54, 1.56, 1.45[/tex]

Required

Determine the percentage error

First, we calculate the mean

[tex]\bar x = \frac{\sum x}{n}[/tex]

This gives:

[tex]\bar x = \frac{1.54+ 1.53+ 1.44+ 1.54+ 1.56+ 1.45}{6}[/tex]

[tex]\bar x = \frac{9.06}{6}[/tex]

[tex]\bar x = 1.51[/tex]

Next, calculate the mean absolute error (E)

[tex]|E| = \sqrt{\frac{1}{6}\sum(x - \bar x)^2}[/tex]

This gives:

[tex]|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}[/tex]

[tex]|E| = \sqrt{\frac{1}{6}*0.0132}[/tex]

[tex]|E| = \sqrt{0.0022}[/tex]

[tex]|E| = 0.04[/tex]

Next, calculate the relative error (R)

[tex]R = \frac{|E|}{\bar x}[/tex]

[tex]R = \frac{0.04}{1.51}[/tex]

[tex]R = 0.026[/tex]

Lastly, the percentage error is calculated as:

[tex]\% Error = R * 100\%[/tex]

[tex]\% Error = 0.026 * 100\%[/tex]

[tex]\% Error = 2.6\%[/tex]

Answer:

Approximately [tex]7.1 \times 10^{3}\; {\rm J}[/tex] (given: [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

To find the change in the gravitational potential energy ([tex]\text{GPE}[/tex]), use the formula:

[tex]\begin{aligned}& (\text{change in GPE}) \\ &= (\text{mass})\, (g)\, (\text{change in height})\end{aligned}[/tex].

Assume that gravitational field strength [tex]g[/tex] is constant (e.g., [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].) For an object of mass [tex]m[/tex], if the altitude of the object changes by [tex]\Delta h[/tex], the [tex]\text{GPE}[/tex] of that object would change by [tex]m\, g\, \Delta h[/tex].

In this question, the mass of Ben is [tex]m = 63.2\; {\rm kg}[/tex]. It is given that [tex]g = 9.8\; {\rm m\cdot s^{-2}} = 9.8\; {\rm N\cdot kg^{-1}}[/tex] and is constant. Since change in the altitude of Ben is [tex]\Delta h = 11.5\; {\rm m}[/tex], the change in the ([tex]\text{GPE}[/tex]) of Ben would be:

[tex]\begin{aligned} m\, g\, \Delta h &= (63.2\; {\rm kg}) \, (9.8\; {\rm N\cdot kg^{-1}})\, (11.5\; {\rm m}) \\ &\approx 7.1\times 10^{3}\; {\rm N\cdot m} = 7.1\times 10^{3}\; {\rm J} \end{aligned}[/tex].

Answer:

A) It is the length from the midpoint to the crest.

Explanation:

The correct statement about the amplitude of any transverse wave is: It is the length from the midpoint to the crest. The correct option is A.

A transverse wave is a type of wave in which the displacement of the medium is perpendicular to the direction of wave propagation.

Examples of transverse waves include light waves and water waves in which the surface of the water oscillates up and down while the wave moves horizontally.

The properties of a transverse wave include:

Amplitude: The maximum displacement of the medium from its rest position. This represents the intensity or strength of the wave.

Wavelength: The distance between two adjacent points in the wave that are in phase with each other, for example, between two consecutive crests or troughs. It is typically represented by the symbol λ.

Frequency: The number of complete wave cycles that pass a point in a given amount of time, usually measured in hertz (Hz). The frequency is inversely proportional to the wavelength and is represented by the symbol f.

Period: The time taken for one complete wave cycle to pass a given point, usually represented by the symbol T. The period is directly proportional to the wavelength and inversely proportional to the frequency.

Speed: The speed at which the wave propagates through the medium, usually represented by the symbol v. The speed is directly proportional to the frequency and wavelength.

These properties are related to each other by the wave equation:

v = fλ,

Where v = the speed of the wave,

f = the frequency,

and λ = the wavelength.

Therefore, The correct statement about the amplitude of any transverse wave is A. It is the length from the midpoint to the crest.

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Answer:

Explanation:

Let the luminosity of the star be I and luminosity of the sun be Isun.

2.4 billion light years = 2.4 x 10⁹ light years .

brightness = luminosity / (distance)²

Given   Sun would have to be viewed from a distance of 1300 light-years to have the same apparent magnitude as 3C 273 so

For the sun

brightness = Isun / (1300 light years )²

For star

brightness = I / (2.4 x 10⁹ light years  )²

Both these brightness are same

Isun / (1300 light years )²  =  I / (2.4 x 10⁹ light years  )²

I = Isun x (2.4 x 10⁹ light years  )² / (1300 light years )²

= Isun x 3.4 x 10¹² .

Answer:

newtons

Explanation:

In the metric system of units, where force is measured in newtons (abbreviated N), work is measured in newton-meters (N-m). For reference, a newton is roughly equal to the force exerted on your hand by a baseball.

Answer:

newtons

In the metric system of units, where force is measured in newtons (abbreviated N), work is measured in newton-meters (N-m). For reference, a newton is roughly equal to the force exerted on your hand by a baseball.

Answer:

a. an increase in the mass on the spring.

Explanation:

An increase in the mass on the spring will increase the period of an oscillating spring mass system.

Mathematically, the period of an oscillating spring mass system is given by the formula;

T = 2π √(m/k)

Where;

T is the period.

m is the mass of the spring.

k is the spring constant.

Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.

This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant i.e there exist an inverse relationship between the period and spring constant.

Answer:

near a flame and a hot plate

Explanation:

Answer:

The mass is the amount of matter in something. Weight is mass times gravitational field strength and so also includes gravity. Mass is measured in grams (g) and weight is measured in Newtons (N)

The mass of ball B and the final velocity of ball A can complement the conservation of linear momentum. The answer is yes.

Momentum can simply be defined as the product of mass and velocity. It is a vector quantity.

Given that ball A with a mass of 0.280kg makes an elastic head-on collision with ball B initially at rest. After collision, ball B moves off with half the original speed of ball A.

In an elastic head-on collision, momentum is mostly always conserved. That is, the sum of the momentum before collision will be equal to the sum of the momentum after collision.

Mathematically, MaUa = MaVa + MbVb

Is the momentum conserved in the collision?

The answer is yes!

Why?

Because we need to consider the mass of the ball B and the final velocity of the ball A.

Therefore, In consideration of the mass of the ball B and the final velocity of the ball A, we can say that the momentum is conserved.

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Answer:

The moon is 1,079.4 mi.

Mars is 2,106.1 mi

Multiply your weight by the moon's gravity relative to earth's, which is 0.165. Solve the equation. In the example, you would obtain the product 22.28 lbs. So a person weighing 135 pounds on Earth would weigh just over 22 pounds on the moon

Being that Mars has a gravitational force of 3.711m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on mars. So an object or person on Mars would weigh 37.83% its weight on earth.

Explanation:

~Hope this helps

Answer:

The wavelength in vacuum is equal to 428.8 nm.

Explanation:

Given that,

The wavelength of light, [tex]\lambda=284\ nm[/tex]

The refractive index of glass, n = 1.51

We need to find the wavelength in vacuum. The relation between wavelength and refractive index is given by :

[tex]n=\dfrac{\lambda_v}{\lambda}\\\\\lambda_v=n\times \lambda\\\\\lambda_v=1.51\times 284\\\\\lambda_v=428.8\ nm[/tex]

So, the wavelength in vacuum is equal to 428.8 nm.

The work done to the mower is the product of force and the distance covered by the object which is equal to 40,811 Joules.

Work done can be defined as the product of external force and the distance over which the force is being applied. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.

From this we can see that:

X-Component:

cos(θ) = x/F

Then,

X= F cos(θ).…..(1)

Now putting the values of F and θ in equation (1) we get,

X = 72 N × cos(40)

X = 72 N × 0.766

X= 55.15 N this is the x-component force

The work done to the mower is:

W = F × d

W = 55.15 × 740

W = 40,811 Joules

The work done to the mower is 40811 Joules.

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Answer:

a

Explanation:

Answer: b. more precipitation

Explanation:

Answer:

4 rad/s

Explanation:

The angular velocity is velocity over time:

[tex]\displaystyle{\omega = \dfrac{v}{r}}[/tex]

We know that the velocity is 20 m/s and the radius is half of diameter which is 10m/2 = 5 m. Hence, substitute in the formula:

[tex]\displaystyle{\omega = \dfrac{20 \: \text{m/s}}{5 \: \text{m}}}\\\\\displaystyle{\omega = 4 \: \text{rad/s}}[/tex]

Therefore, the angular velocity is 4 rad/s

Answer:

628 J

Explanation:

ME = PE + KE

PE = mgh = 0,  because h = 0

KEi (initial KE) = 1/2mv² = 1/2(62.3 kg)(4.49 m/s)² = 628 J

KEf (final KE) = 0, because v-final = 0

All the initial ME, which is all KE, converts to thermal E due to friction