Natural selection and adaptation caused wings to become vestigial structures on flightless birds like the kiwi.
The evolution of flightless birds is an example of natural selection at work.
In the absence of predators, birds that were better adapted to life on the ground had a survival advantage over those that still relied on flight. This led to the gradual evolution of smaller, less developed wings in flightless birds, which were not needed for survival and reproduction.
Flightless-ness is a common adaptation among birds that live in environments where there are no natural predators, or where there is an abundance of food on the ground.
In the case of New Zealand, before human arrival, there were no mammalian predators that posed a significant threat to birds. As a result, many bird species on the islands evolved to become flightless, including the kiwi.
Over time, flightless birds that did not need to fly in order to escape predators or find food became adapted to their terrestrial environments.
The wings of these birds gradually became smaller and less developed, as there was no evolutionary pressure to maintain the large and strong wings needed for flight.
Eventually, these wings became vestigial structures, serving no present-day purpose, as is the case with the kiwi.
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Would samples that were digested with ecori have a different pattern than the same sample digested with smal?
Yes, samples that were digested with EcoRI would have a different pattern than the same sample digested with SmaI.
This is because EcoRI and SmaI are two different restriction endonucleases, which are enzymes that have the ability to cut DNA at specific sites. The DNA substrate of EcoRI has a recognition sequence of GAATTC, meaning that the enzyme will recognize and cleave the phosphodiester bond located between the G and A bases.
On the other hand, SmaI's recognition sequence is CCCGGG, meaning that the enzyme will recognize and cleave the phosphodiester bond located between the C and G bases. Therefore, EcoRI and SmaI will both recognize different sequences in the same sample and consequently cut the DNA in different places, resulting in a different pattern after digestion.
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Scientists have discovered that a species of bird has decreased in number
by over 60%. The scientists eliminated nutrient shortages and natural
cycles as reasons for the decline.
Which factor might have contributed to the birds' decline?
Choose 1 answer:
A Viral immunity
B Fewer predators
C Habitat destruction
D Increase in viable offspring
The factor that might have contributed to the birds' decline is habitat destruction (option C).
What is habitat loss?Habitat loss refers to the reduction in the amount of space where a particular species, or group of species can survive and reproduce.
Habitat loss can result in the reduction of a population of a species and can negatively affect biodiversity in general.
According to this question, scientists have discovered that a species of bird has decreased in number by over 60%. They ruled out nutrient shortages and natural cycles as reasons for the decline.
The possible reason left among the options is habitat destruction.
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In some new zealand estuaries, shellfish-bed populations have declined due to habitat modification and overharvesting. How will this affect the biodiversity of these ecosystems?.
The decline of shellfish-bed populations in New Zealand estuaries due to habitat modification and overharvesting can have significant impacts on the biodiversity of these ecosystems.
The shellfish play a crucial role in the estuarine food web by filtering the water and providing food for other organisms. The loss of shellfish populations can lead to an increase in water turbidity and a decline in water quality, which can negatively affect other aquatic species.
Additionally, the removal of a dominant species like shellfish can cause a shift in the community structure and alter the composition and abundance of other species. The overall impact of the decline of shellfish populations on biodiversity in New Zealand estuaries can have far-reaching consequences and underscores the importance of conservation efforts.
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If one strand of dna is cggtac, then the complementary strand would be.
If one strand of DNA is CGGTAC, the complementary strand would be formed by pairing each base with its complementary base. The complementary base for cytosine (C) is guanine (G), and the complementary base for guanine (G) is cytosine (C).
The DNA molecule consists of two complementary strands, each with a sequence of nucleotides. The four nucleotides in DNA are adenine (A), cytosine (C), guanine (G), and thymine (T). Adenine pairs with thymine (A-T), while cytosine pairs with guanine (C-G) through hydrogen bonds.
Given the strand CGGTAC, the complementary strand would be GCCATG. This is because cytosine (C) always pairs with guanine (G), and vice versa. Similarly, adenine (A) always pairs with thymine (T), and vice versa. So, to find the complementary strand, we simply replace each nucleotide with its complementary base.
Thus, the complementary strand of CGGTAC is GCCATG. It's worth noting that the two strands of DNA run in opposite directions, with one strand running in the 5' to 3' direction and the other running in the 3' to 5' direction. This is important in processes such as DNA replication and transcription.
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6. Charles Darwin is given credit for being the true father of the Theory of Natural Selection. Alfred
Wallace is also sometimes given partial credit for coming to the same conclusion without ever talking
with Charles Darwin. Which of the following statements is NOT part of the Darwin-Wallace Theory
of Natural Selection?
There is no statement that is NOT part of the Darwin-Wallace theory of natural selection.
What is Darwin-Wallace theory of natural selection?The Darwin-Wallace theory of natural selection includes the following four statements:
Individuals within a population exhibit variation in traits.Some trait variations are heritable, meaning they can be passed down from one generation to the next.More offspring are produced than can survive, leading to a struggle for existence.Individuals with advantageous traits are more likely to survive and reproduce, passing on those traits to their offspring.Therefore, the answer to your question is that there is no statement that is NOT part of the Darwin-Wallace theory of natural selection.
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A nurse is teaching about the energy needed at rest to maintain life-sustaining activities for a specific period of time. What is the nurse discussing? a. Resting energy expenditure (REE) b. Basal metabolic rate (BMR) c. Nutrient density d. Nutrients
The nurse is discussing about Basal metabolic rate (BMR).
B is the correct answer.
The body's BMR is a measure of how much energy it requires to stay in a state of equilibrium. Because lean mass requires a lot of energy to maintain, the total lean mass, particularly muscle mass, plays a significant role in determining your BMR.
Analysis of a person's oxygen and carbon dioxide intake and output is necessary for BMR estimates. This analysis is known as "calorimetry" among experts. It is a technique for calculating how many calories a person is using in their daily activities. A person's height is considered by BMR as well.
The vital bodily processes that keep life alive require between 60% and 75% of the energy used each day. The maintenance of body temperature (thermoregulation), respiration, heartbeat, nervous system activity, and hormone activity are among these tasks.
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Large-sized primates, like gorillas, have a ____ metabolic rate compared to smaller primates. Group of answer choices
Answer:
lower.
Explanation:
Large-sized primates, like gorillas, have a lower metabolic rate compared to smaller primates.
14 Elodea is a plant that grows in fresh water and is often found in aquariums, Three
elodea plants were placed inside inverted test tubes filled with water. One test tube
was exposed to low light, another to medium light while another was exposed to
high light. The table provided shows the results of this experiment. Notice that more
oxygen was produced by the elodea in high light.
Based on the information provided, what is the difference in volume (in ml) of
oxygen produced between the low light and high light plants at 45 minutes?
Time (min)
0
15
30
45
60
Oxygen Production (mL)
Elodea in Low Elodea in Medium Elodea in High
Light
Light
Light
0
0
0
0. 4
0. 8
0. 9
1. 2
1. 7
1. 8
1. 4
2. 0
2. 5
1. 8
2. 2.
3. 2.
F 1. 4
G 1. 1
H0. 6
J 0. 4
Elodea is a freshwater plant commonly found in aquariums. It thrives in aquatic environments, helping to maintain water quality and providing a habitat for aquatic organisms.
Freshwater plants called elodea are frequently found in aquariums. Due to its capacity to oxygenate the water and offer aquatic species with a natural habitat, it is a preferred option among aquarium aficionados. Elodea is a plant with a 14-inch maximum height and a green, leafy look. It also goes by the name "waterweed" because of how quickly it grows. Elodea is an excellent addition to any freshwater aquarium and can support the upkeep of a wholesome aquatic habitat.
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What is the second leading cause of unintentional death for teenagers?.
The second leading cause of unintentional death for teenagers is motor vehicle accidents.
Motor vehicle accidents are a major cause of death and injury among teenagers in many countries. In the United States, for example, motor vehicle accidents are the leading cause of death for teenagers aged 16-19, and the second leading cause of unintentional death overall for this age group.
There are a variety of factors that contribute to the high incidence of motor vehicle accidents among teenagers. Inexperience, risk-taking behavior, and distractions such as cell phone use are all common factors. Alcohol and drug use also increase the risk of motor vehicle accidents among teenagers.
Preventing motor vehicle accidents among teenagers requires a multi-faceted approach, including education on safe driving practices, enforcement of traffic laws, and measures to discourage alcohol and drug use among young drivers.
New technologies, such as driver assistance systems and vehicle-to-vehicle communication, may also play a role in reducing the incidence of motor vehicle accidents among teenagers in the future.
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When performing compression only cpr the rate of compressions per minute should be:.
When performing compression-only CPR, the rate of compressions per minute should be at least 100 to 120 compressions.
Compression-only CPR is a type of cardiopulmonary resuscitation that involves only chest compressions without rescue breaths. It is recommended for untrained bystanders or those who are unwilling or unable to perform rescue breaths.
The American Heart Association recommends that compressions should be performed at a rate of 100 to 120 compressions per minute. This ensures that the blood flow to the heart and brain is maintained and helps to maximize the effectiveness of the CPR. It is also important to allow for full chest recoil between compressions to allow for blood flow back to the heart.
It is important to note that while compression-only CPR is better than no CPR at all, traditional CPR with both chest compressions and rescue breaths is still the gold standard for providing the best chance of survival for someone experiencing cardiac arrest.
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If wxyz is a kite, find the measure of z. w=8x-23 x=46 and y=6x+11
The measure of z is 699,608. The measure of z can be found by first solving for x and y. The equation w=8x-23 tells us that x is 46. The equation y=6x+11 tells us that y is 278.
With the values of x and y known, we can now find the measure of z. The equation wxyz indicates that z is equal to the product of w, x, and y, or 699,608. Therefore, the measure of z is 699,608.
To summarize, the measure of z can be found by first solving for x and y in the equations w=8x-23 and y=6x+11. The measure of z is equal to the product of w, x, and y, or 699,608.
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A student examines two bacterical cells, Cell I and cell II. He finds that cell I produces CO₂ and ethyl alcohol during cellular respiration while cell II produces carbon dioxide and water. What conclusions can you draw from his observation?
If a student examines two bacterial cells, Cell I and Cell II, and he finds that cell I produce CO₂ and ethyl alcohol during cellular respiration while cell II produces carbon dioxide and water, then the conclusions are that cell I produce energy by Fermentation, while cell II produce energy by cell respiration.
What is cell respiration?Cell respiration is a process that aerobic organisms use to produce energy, which releases carbon dioxide and water as byproducts of such chemical reactions in the organism.
Therefore, with this data, we can see that cell respiration produces energy and carbon dioxide, whereas fermentation does not produce carbon dioxide.
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PLEASE ANSWER FAST 100 PTS
In this assignment, you will use, evaluate, and improve a simulation to highlight human impact on coral
reef ecosystems. Then you will propose and evaluate real-world solutions to reduce the negative effects
of human activity on this ecosystem and its biodiversity
In order to complete this assignment, you will need to follow a few steps. First, you will need to use the simulation to understand the human impact on coral reef ecosystems. This will involve evaluating the simulation and identifying areas where human activity is having a negative effect on the ecosystem and its biodiversity.
Once you have a good understanding of the simulation, you can then propose and evaluate real-world solutions to reduce the negative effects of human activity on the ecosystem. These solutions may include things like reducing pollution and overfishing, implementing stricter regulations on coastal development, and increasing public awareness about the importance of coral reef conservation.
As you evaluate these solutions, it will be important to consider their feasibility and effectiveness in real-world settings. You may also want to consider the potential costs and benefits of each solution.
Overall, this assignment is an opportunity to explore the complex relationship between humans and coral reef ecosystems, and to think critically about ways we can reduce our negative impact on these important ecosystems.
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Question 1: How does increasing the size of the habitat affect carrying capacity? Explain your answer. Recall the scenarios: 0–15 years, Little land; 15–30 years, Moderate land; 30–45 years, Ample land.
Increasing the size of the habitat can increase the carrying capacity. Carrying capacity is the maximum population size that a particular environment can sustain, and it depends on factors such as resources, predation, and competition.
In general, larger habitats have more resources available, which can support a larger population size. In the scenarios presented, the carrying capacity is expected to increase as the land availability increases.
In the 0-15 years scenario, there is little land available, which can limit the resources available for the population, resulting in a lower carrying capacity. In the 15-30 years scenario, there is moderate land available, which can support a larger population size. In the 30-45 years scenario, there is ample land available, which can support the largest population size of the three scenarios.
However, it's important to note that the relationship between habitat size and carrying capacity is not always linear and can be influenced by other factors such as predation and competition.
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1) What economic values does the rainforest offer other than its worth as timber?
2) Based on this talk, why are people failing to preserve such assets as the rainforest?
3) How are forests comparable to other forms of natural resources?
4) How does Pavan believe we should think about the value of a mangrove tree?
5) What are some potential solutions to the problems Pavan identifies?
Clouds in rainforests contain a lot of water vapor. Rain falls as a result of the clouds moving to new locations. The crops on farms will benefit from this rain.
Numerous job opportunities are available in tropical rainforests, including those as tour guides and environmental stewards. In the rainforest, there are employment opportunities in industries like mining, logging, farming, and construction.
Wood, lumber, raw materials, vegetables, and fruits—all of which have major economic value—are all provided by forests. The timber is employed in furniture production and building. Additionally, wood is necessary for the manufacture of paper.
As a source of a variety of production inputs, environmental goods, food, fuel, medications, household goods, building materials, and raw materials for industrial processing, forests are acknowledged as being an essential component of national economies.
Therefore, the crops benefit from the rain.
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List the main components in our diet and state their function
The main components of a healthy diet are carbohydrates, proteins, fats, vitamins, minerals and water. Carbohydrates are the main source of energy for our bodies and are found in grains, legumes, fruits and vegetables.
Proteins are the building blocks of cells and are found in meats, eggs, nuts and dairy products. Fats help the body absorb vitamins and minerals and are found in oils, nuts and dairy products. Vitamins and minerals are essential for our bodies to function properly and are found in fruits, vegetables, whole grains and dairy products.
Each of these components provides our bodies with vital nutrients and energy. Carbohydrates are broken down into glucose, which is used by the body to provide energy. Proteins are used to build and repair cells and tissues, while fats help to transport vitamins and minerals around the body.
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Mom is heterozygous A and dad is type AB blood type. Do the Punnett square. What are the chances the offspring will be type B
Dad is type AB
Mom is heterozygous type A which is Ao
after drawing the punnet square (the image attached) you will find that mom and dad produced offsprings with the genotypes: AA, AB, Ao, and Bo
Parent AB X Ao offspring probabilities
1/4 type AB (25%)
1/4 type B (25%)
1/2 type A (50%)
hope this helps :)
How the genes found in DNA can make different proteins?
Before beginning the activity, collect water from two different water sources. One source should be
indoor tap water. The other source should be outdoors, such as a pond, stream, or well. You will need
approximately one gallon from each water source to complete each test.
Part A
Before analyzing the two water samples, predict the outcome of the test from each source. How
do you anticipate the concentration of contaminants will compare between the outdoor and
indoor water sources?
It is difficult to predict the concentration of contaminants in the two water sources without conducting the appropriate tests.
The presence and levels of contaminants in water can vary depending on several factors, including the source of water, its treatment, and its exposure to environmental factors. For example, outdoor water sources may be more likely to contain higher levels of natural contaminants, such as bacteria, algae, and minerals, while indoor tap water may be treated with chemicals, such as chlorine, to remove contaminants.
Therefore, it is important to conduct appropriate tests to determine the specific types and levels of contaminants in each water source before making any conclusions or predictions.
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2. There are 100 students in a class. Ninety-six did well in the course whereas four blew it totally and received a grade of F. Sorry. In the highly unlikely event that these traits are genetic rather than environmental, if these traits involve dominant and recessive alleles, and if the four (4%) represent the frequency of the homozygous recessive condition, please calculate the following:
The frequency of the recessive allele (q).
The frequency of the dominant allele (p)
The frequency of heterozygous individuals (2pq).
1) The frequency of the recessive allele (q) is 0.2.
2) The frequency of the dominant allele (p) is 0.8..
3) The frequency of heterozygous individuals (2pq) is 0.32
1) The frequency of the recessive allele (q) can be found using the Hardy-Weinberg equation:
p² + 2pq + q² = 1
where p² represents the frequency of the homozygous dominant genotype, 2pq represents the frequency of the heterozygous genotype, and q² represents the frequency of the homozygous recessive genotype.
Given that 4% of the students are homozygous recessive, q² = 0.04. Solving for q, we get:
q² = 0.04
q = √(0.04)
q = 0.2
2) The frequency of the dominant allele (p) can be found by subtracting the frequency of the recessive allele (q) from 1:
p = 1 - q
p = 1 - 0.2
p = 0.8
3) The frequency of heterozygous individuals (2pq) can be found using the value of p and q that we have calculated:
2pq = 2 x 0.8 x 0.2
2pq = 0.32
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The complete question is:
There are 100 students in a class. Ninety-six did well in the course whereas four blew it totally and received a grade of F. Sorry. In the highly unlikely event that these traits are genetic rather than environmental, if these traits involve dominant and recessive alleles, and if the four (4%) represent the frequency of the homozygous recessive condition, please calculate the following:
1) The frequency of the recessive allele (q).
2) The frequency of the dominant allele (p)
3) The frequency of heterozygous individuals (2pq).
Which sequence of processes occurs in the production of a cloned plant
The sequence of processes in the production of a cloned plant involves taking a cutting from a parent plant, inducing the cutting to form roots and a shoot, and then allowing the cutting to grow into a genetically identical plant to the parent.
In more detail, the process of cloning a plant typically involves taking a cutting from a parent plant that has desirable characteristics, such as disease resistance or high yield. This cutting is then treated with a rooting hormone and placed in a growing medium that encourages the formation of roots and a shoot.
Once the cutting has developed into a small plant, it can be transplanted into soil and grown into a mature plant that is genetically identical to the parent. This process is known as asexual reproduction and is commonly used in agriculture to produce crops with consistent traits.
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What process is occurring in the image: DNA replication, transcription, or translation?
In what organelle is this process taking place: ribosome, nucleus, or chloroplast?
What molecule is used as a template in this process: DNA or RNA?
What molecule is the end product of this process: DNA, RNA, or protein?
Please help!!!
Answer:
1. Translation
2. ribosomes
3. RNA
Explanation:
Here's a similar picture:
Hoped this helped :)
plis help asapppppppp
Answer:
i would say Maine
Explanation:
the red areas demonstrate the hotter areas as it goes to blue ou can see it's getting colder
The zebra mussel is originally native to the Black and Caspian Seas of Asia. Zebra mussels were first detected in the Hudson River of New York in 1991. Before the arrival of zebra mussels, the Hudson River supported populations of native mussels. (a) Describe ONE way an invasive species, such as the zebra mussel, can decrease the carrying capacity for a native species in an ecosystem. B) Describe ONE characteristic of an r-selected species that could increase the likelihood of the r-selected species being a more successful invasive species than K-selected species. (c) Scientists want to reduce the population of zebra mussels in the Hudson River. (i) Propose a practical solution for reducing the zebra mussel population in the Hudson River. (ii) Describe ONE potential negative ecological consequence of your proposed solution for reducing the zebra mussel population in the Hudson River
(a) An invasive species like the zebra mussel can decrease the carrying capacity of a native species in an ecosystem by outcompeting them for resources such as food and space. Zebra mussels are filter feeders and can filter large amounts of phytoplankton from the water, which is the main food source for many native mussel species. As a result, the native mussels may not be able to get enough food and can starve to death.
(b) An r-selected species is characterized by a high reproductive rate, a short lifespan, and the ability to colonize new habitats quickly. These traits could increase the likelihood of r-selected species being more successful invasive species than K-selected species because they can reproduce rapidly and establish large populations in a short amount of time. This can enable them to quickly dominate and outcompete native species for resources.
(c) (i) One practical solution for reducing the zebra mussel population in the Hudson River could be to introduce a natural predator that feeds on zebra mussels. One example of a potential predator is the round goby, which is known to feed on zebra mussels.
(ii) One potential negative ecological consequence of introducing a predator to control zebra mussels is that it may also impact other species in the ecosystem. For example, the introduction of a new predator could affect the population dynamics of other native species in the Hudson River, including those that are not considered invasive. Additionally, there is a risk that the predator may become invasive itself and cause further damage to the ecosystem. Therefore, careful consideration and monitoring would be necessary before implementing such a solution.
a) One way an invasive species, such as the zebra mussel, can decrease the carrying capacity for a native species in an ecosystem is by outcompeting the native species for resources, such as food and habitat. Zebra mussels are filter feeders that can remove large amounts of phytoplankton and suspended particles from the water, which can reduce the food supply for native species, such as fish and other aquatic organisms. Additionally, zebra mussels can attach to and cover native mussel shells, which can prevent them from feeding, breathing, and reproducing.
b) One characteristic of an r-selected species that could increase the likelihood of the r-selected species being a more successful invasive species than K-selected species is their ability to reproduce rapidly and produce large numbers of offspring in a short period of time. R-selected species typically have a short generation time and allocate more resources toward reproduction than towards survival or parental care. This can give them an advantage in colonizing and dominating new environments, where resources are abundant and competition is low.
c)
(i) One practical solution for reducing the zebra mussel population in the Hudson River is to introduce a biological control agent, such as a parasitic flatworm or bacteria, that can infect and kill zebra mussels. These agents could be introduced in areas with high zebra mussel populations and could help reduce their numbers over time.
(ii) One potential negative ecological consequence of introducing a biological control agent to reduce the zebra mussel population in the Hudson River is that the agent could also affect non-target species. For example, the parasitic flatworm or bacteria could also infect and harm native mussel species or other aquatic organisms, leading to unintended ecological consequences. Therefore, it is important to carefully evaluate and test any proposed solutions before implementing them to ensure that they are effective and do not cause additional harm to the ecosystem.
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PLEASE HELP!!!!!!!!!
Transcription and translation are the two processes involved in protein synthesis. 1a- mRNA codons: AUG AUU CCG CCA GCA UAC UAG. 1b- Amino Acids: Met-Ile- Pro-Pro-Ala-Tyr. 2- Severe mutation replaces isoleusine by threonine. The middle uracyl from the second codon must be replaced by a cytosine. 3- Alteration in enzymatic activity.
What are transcription and translation?
Transcription and translation are two processes involved in protein synthesis.
Transcription occurs first in the nucleus. During this event, mRNA is synthesized by copying a segment of the DNA molecule. The template DNA strand is used to pair its nucleotides and grow the new mRNA strand.
Translation occurs in the cytoplasm. During this event, the protein is grown by reading the mRNA codon sequence. tRNA, associated with rRNA, recognizes the codons and adds the correct amino acid to the new growing polypeptide.
DNA triplets: TAC TAA GGC GGT CGT ATG ATC
1a- mRNA codons: AUG AUU CCG CCA GCA UAC UAG
1b- Amino Acids: Met Ile Pro Pro Ala Tyr Stop
2- Mutation
mRNA codons: AUG ACU CCG CCA GCA UAC UAG
Amino Acids: Met Thr Pro Pro Ala Tyr Stop
The severe PKU mutation occurs when a nucleotide substitutes another nucleotide. In this case, in mRNA molecule, an uracyle from the second codon was replaced by a cytosine. Hence, the new codon coded for Threonine instead of coding for isoleusine as the original sequence.
The column Amino acid change in PHA enzyme shows that the severe mutation involves the change in which isoleusine is replaced by threonine.
In order to produce this point mutation, the middle uracyl from the codon must be replaced by a cytosine.
3- Mutations impact on phenylalanine hydroxylase (PHA) enzymatic activity, causing a phenotypic range that varies between the severe PKU and the mild PKU. Alterations in the enzyme activity may drive the enzyme to consume all the stored phenylalanine and to produce wastes that are toxic to the organism, specially to te brain.
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After evaluating his colleague's claim about plant pathogens being
carried in African dust clouds, the ecologist decides to isolate and
genetically test fungi samples from all of his outdoor and greenhouse
plants. He compares the results to DNA samples of the Alternaria fungi
commonly found in both North America and Africa, as shown in this
table.
Genetic Similarity of Alternaria Fungi from Ecologist's Samples
with Common Species Found in North America and Africa
Alternaria
Species
1
2
3
Plant
Location
Greenhouse
Outdoors
Outdoors
Percent Similarity
to North
American Species
90%
92%
10%
(→
Percent
Similarity to
African Species
20%
14%
88%
44
HEAVAN
The African Alternaria species causes
disease to the ecologist's plants. Which
species of Alternaria would most likely
cause damage to the ecologist's plants, and
where could the ecologist keep his plants to
help protect them from this species of
Alternaria? Enter your
swer in the box
provided.
UTE
I
According to the table, the Alternaria species that has a larger proportion of genetic resemblance to the African species is the one that would most likely harm the ecologist's plants.
According to the table, the Alternaria fungus from the outdoor area had an 88% similarity rate to the African species. The ecologist could keep his plants in the greenhouse to help protect them from this type of Alternaria as the greenhouse sample had a higher percentage resemblance to the North American species and a lower percentage similarity to the African species.
This implies that the atmosphere in a greenhouse would be less favorable for the development and spread of the African Alternaria species and might thus offer some protection against it. Fungus helps to restore ecosystem by undergoing decomposition.
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Correct question:
After evaluating his colleague's claim about plant pathogens being carried in African dust clouds, the ecologist decides to isolate and genetically test fungi samples from all of his outdoor and greenhouse plants. He compares the results to DNA samples of the Alternaria fungi commonly found in both North America and Africa, as shown in this table. Genetic Similarity of Alternaria Fungi from Ecologist's Samples with Common Species Found in North America and Africa Alternaria Species Plant Location Greenhouse Outdoors
Percent Similarity to North American Species 90% 92% 10%
Percent Similarity to African Species 20% 14% 88%
The African Alternaria species causes disease to the ecologist's plants. Which species of Alternaria would most likely cause damage to the ecologist's plants, and where could the ecologist keep his plants to help protect them from this species of Alternaria? Enter your answer in the box provided.
The fact that trees are more likely to be vertical or horizontal than slanted is an example of ____.
The fact that trees are more likely to be vertical or horizontal than slanted is an example of natural selection.
As the tree grows, it is subject to the forces of gravity, wind, and other environmental conditions. Gravity pulls the tree downwards, while wind and other environmental conditions push against the tree in various directions.
Over time, the forces of gravity and the environment shape the tree into a vertical or horizontal position as the tree seeks to achieve the most stability and support. The vertical or horizontal orientation of the tree gives it the best chance to survive and thrive in its environment.
This natural selection helps the tree to be better adapted to its environment, as its shape will help it to better withstand strong winds, support more weight, and absorb more sunlight. Trees that are slanted are often suffering from external forces such as strong winds, or are in a location that is not ideal for its environmental needs.
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What traits do green algae and plants have in common?.
Green algae and plants share several traits due to their close evolutionary relationship. They are both members of the Plantae kingdom and have similar photosynthetic pigments, such as chlorophyll a and b.
Additionally, they both have cell walls made of cellulose and store energy as starch. Green algae and plants also share the same basic life cycle, alternating between a haploid and a diploid stage.
Furthermore, they both have a similar method of reproduction, with some green algae and plants being able to reproduce sexually and asexually. These shared traits between green algae and plants suggest a close evolutionary relationship and highlight the evolutionary transition from aquatic green algae to terrestrial plants.
To know more about the Green algae refer here :
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Griffith studied two strains of bacteria, the S strain and the R strain. Mice injected with the S strain died, while mice injected with the R strain did not become ill. When he used heat to kill'S cells and then injected the dead cells into the mice, the mice did not die. However, when he mixed the heat treated S cells with living R cells, the mice got sick and died What was Griffith's conclusion? What was the significance of his findings?
Which would cause a plant to stop growing?
Lack of water, nutrient shortages, inadequate lighting, severe temperatures, pests or illnesses, and physical harm are some of the conditions that might halt a plant from growing. Furthermore, plants have a genetically predetermined growth cycle that affects when they stop growing. Extreme weather can stress a plant and interfere with its regular growth processes, which can result in stunted or stopped growth when any of these elements are present.
Answer: Many things could cause a plant to stop growing like lack of sunlight, too much sunlight, lack of water, too much water, wrong ph level for soil, etc.
Explanation: Like us humans plants need their basic needs met just like how we need to eat and drink water, and just like us they can over do this(eating too much food=problems or if you don't eat your growth could become stunted)