Nicholas cleans his room in 10 hour. Gloria


cleans her room for 3 minutes and 18 seconds. How many seconds longer does Nicholas clean his room than Gloria?

The equation is P = [tex]25cos(0.224t) + 50[/tex], where P represents the percentage of the moon's surface visible and t is the number of days since the moon was full.

To determine an equation for the percentage of the moon's surface visible as a function of the number of days since the moon was full, we can use the cosine function [tex]P = Acos(Bt) + C[/tex], where P represents the percentage visible, t is the number of days since full moon, A is the amplitude, B is the frequency, and C is the vertical shift.

Given that the maximum percentage visible is 50%, we know that C = 50. The period of the function is 28 days, so we can calculate B using the formula B = 2π/period = 0.224. The amplitude A can be calculated as half of the maximum percentage visible, or A = 25.

Therefore, the equation for the percentage of the moon's surface visible as a function of the number of days since full moon is P = 25cos(0.224t) + 50.

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a. To find the inverse function of f(x), we need to interchange the roles of x and y and solve for y. So, we have:

y = 1x - 3
x = 1y - 3
x + 3 = y
Therefore, the inverse function of f(x) is f^-1(x) = x + 3.
The domain of f^-1(x) is the range of f(x). Since f(x) = 1x - 3 is a linear function, its domain is all real numbers. Therefore, the range of f(x) is also all real numbers. In interval notation, we can write this as (-inf, inf).

The range of f^-1(x) is the domain of f(x). As we determined in part b, the domain of f(x) is all real numbers. Therefore, the range of f^-1(x) is also all real numbers. In interval notation, we can write this as (-inf, inf).
Hi! I'd be happy to help you with your question.
a. To find the inverse function of f(x) = 1x - 3, you can follow these steps:
1. Replace f(x) with y: y = 1x - 3
2. Swap x and y: x = 1y - 3
3. Solve for y: y = x + 3
So, the inverse function f^(-1)(x) = x + 3.
The domain of f^(-1) refers to the set of all possible x-values. Since the inverse function is a linear function with no restrictions, the domain of f^(-1) is all real numbers. In interval notation, this is written as (-∞, ∞).

c. The range of f^(-1) refers to the set of all possible y-values (output). Again, since it's a linear function with no restrictions, the range of f^(-1) is also all real numbers. In interval notation, this is written as (-∞, ∞).

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Answer:

499

Step-by-step explanation:

We used the given sector area formula, 28.25 = ∅/360 × π × 12², to find the central angle (∅) by rearranging the equation

First, we used the given sector area formula, 28.25 = ∅/360 × π × 12², to find the central angle (∅) by rearranging the equation and solving for ∅, which resulted in ∅ ≈ 22.5 degrees.

Next, we applied the arc length formula, L = ∅/360 × 2 × π × r, and plugged in the values we had, including the calculated ∅ and the given radius (12 feet).

Finally, we calculated the arc length (L) to be approximately 4.71 feet, which is the length of steel that must be replaced.

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To find the possible Hamiltonian circuits that begin with JVTSR, we can start by constructing a path that begins with JVTSR and visits each vertex exactly once. Such a path must be of the form JVTSRX, where X is the remaining vertex.

Case 1: JVTSRQX

To find the possible value of X, we note that the only edges incident to J are V and T, and the only edges incident to Q are S and R. Thus, we must have X = S or X = R, and the circuits are JVTSRQS and JVTSRQR.

Case 2: JVTSRXQ

To find the possible value of X, we note that the only edges incident to X are S and L. Thus, we must have X = L, and the circuit is JVTSRLQ.

Case 3: JVTSRLX

To find the possible value of X, we note that the only edges incident to J are V and T, and the only edges incident to L are T and R. Thus, we must have X = R, and the circuit is JVTSRLR.

Case 4: JVTSRXL

To find the possible value of X, we note that the only edges incident to Q are S and R, and the only edges incident to X are L and S. Thus, we must have X = L, and the circuit is JVTSRQL.

Therefore, there are four possible Hamiltonian circuits that begin with JVTSR: JVTSRQS, JVTSRQR, JVTSRLQ, and JVTSRLR.

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The rate of the boat in still water is 5 miles per hour and rate of the boat in current is 3 miles per hour.

Let us represent the rate of boat in still water hence and rate of boat in current be y. Also, we know that speed = distance/time. Hence, keep the values in formula -

Converting mixed fraction to fraction, time = 3/2 hour

Time = 1.5 hour

1.5 (x + y) = 12 : equation 1

Divide the equation 1 by 3

0.5 (x + y) = 4 : equation 2

6 (x - y) = 12 : equation 3

Divide the equation 3 by 6

(x - y) = 2

x = 2 + y : equation 4

Keep the value of x from equation 4 in equation 2

0.5 (2 + y + y) = 4

1 + y = 4

y = 4 - 1

y = 3 miles/ hour

Keep the value y in equation 4 to get x

x = 2 + 3

x = 5 miles per hour

The rate in still water and current is 5 and 3 miles per hour.

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The complete question is-

It takes a boat 1 (1/2) hr to go 12 mi downstream, and 6 hr to return. Find the rate of the boat in still water and the rate of the current.

The number of zeros are in the product of the number 50 and 6000 is 50 x 6000 = 300,000 are five.

Integers, natural numbers, fractions, real numbers, complex numbers, and quaternions are examples of typical special instances where it is possible to define the product of two numbers or the multiplication of two numbers.

A product is the outcome of multiplication in mathematics, or an expression that specifies the elements (numbers or variables) to be multiplied.

The commutative law of multiplication states that the result is independent of the order in which real or complex numbers are multiplied. The result of a multiplication of matrices or the elements of other associative algebras typically depends on the order of the components. For instance, matrix multiplication and multiplication in general in other algebras are non-commutative operations.

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The first 10 iterations of Newton's method for f(x) = 2 sin x + 3x + 3, with initial approximation x₀ = 15, are approximately 8.156, 6.099, 5.091, 4.941, 4.929, 4.929, 4.929, 4.929, 4.929, 4.929

The first 10 iterations of Newton's method for the given function and initial approximation

x₁ = x₀ - f(x₀)/f'(x₀) = 15 - (2sin(15) + 45) / (2cos(15) + 3) ≈ 8.156

x₂ = x₁ - f(x₁)/f'(x₁) ≈ 6.099

x₃ = x₂ - f(x₂)/f'(x₂) ≈ 5.091

x₄ = x₃ - f(x₃)/f'(x₃) ≈ 4.941

x₅ = x₄ - f(x₄)/f'(x₄) ≈ 4.929

x₆ = x₅ - f(x₅)/f'(x₅) ≈ 4.929

x₇ = x₆ - f(x₆)/f'(x₆) ≈ 4.929

x₈ = x₇ - f(x₇)/f'(x₇) ≈ 4.929

x₉ = x₈ - f(x₈)/f'(x₈) ≈ 4.929

x₁₀ = x₉ - f(x₉)/f'(x₉) ≈ 4.929

Therefore, the first 10 iterations are 8.156, 6.099, 5.091, 4.941, 4.929, 4.929, 4.929, 4.929, 4.929, 4.929

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Answer:

[tex]y = 2x + 9[/tex]

Step-by-step explanation:

It is given that the slope of the line is 2, and it passes through (-3 , 3). The equation of straight lines is y = mx + b, in which:

y = (x , y) = 3

m = slope (gradient) = 2

x = (x , y) = -3

b = y-intercept

~

Plug in the corresponding numbers to the corresponding variables:

y = mx + b

3 = (2)(-3) + b

First, multiply -3 with 2:

[tex]3 = (2)(-3) + b\\3 = (2 * -3) + b\\3 = -6 + b[/tex]

Next, isolate the variable, b. Note the equal sign, what you do to one side, you do to the other. Add 6 to both sides of the equation:

[tex]3 = b - 6\\3 (+6) = b - 6 (+6)\\b = 3 + 6\\b = 9[/tex]

Plug in 2 for slope, and 9 for y-intercept, in the given equation:

[tex]y = mx + b\\m = 2\\b = 9\\[/tex]

[tex]y = 2x + 9[/tex] is your answer.

~

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The inverse functions:

f'(2) = 4.

[tex]f^{-1}(x)[/tex] = sqrt(x - 4).

f'(s1(x)) = sqrt(x - 4).

(a) To find f'(2), we need to take the derivative of f(x) with respect to x and then substitute x = 2.
[tex]f(x) = x^2 + 4[/tex]
f'(x) = 2x
f'(2) = 2(2) = 4
Therefore, f'(2) = 4.
(b) To find the inverse function [tex]f^{-1}(x)[/tex], we need to first solve for x in terms of f(x) and then switch the roles of x and f(x).
[tex]f(x) = x^2 + 4[/tex]
[tex]x^2[/tex] = f(x) - 4
x = sqrt(f(x) - 4)
Switching x and f(x), we get:
[tex]f^{-1}(x)[/tex] = sqrt(x - 4)
Therefore, the inverse function is [tex]f^{-1}(x)[/tex] = sqrt(x - 4).
(c) To find the compound function f'(s1(x)),

we need to first find s1(x) and then take the derivative of f(x) with respect to s1(x) and then multiply by the derivative of s1(x) with respect to x.
s1(x) = sqrt(x - 4)
f(s1(x)) = (sqrt(x - 4)[tex])^2[/tex] + 4 = x
Taking the derivative of f(x) with respect to s1(x), we get:
f'(s1(x)) = 2s1(x)
Taking the derivative of s1(x) with respect to x, we get:
s1'(x) = 1/(2sqrt(x - 4))
Multiplying these two derivatives, we get:
f'(s1(x))s1'(x) = 2s1(x) * 1/(2sqrt(x - 4))
f'(s1(x))s1'(x) = sqrt(x - 4)
Therefore, the compound function is f'(s1(x)) = sqrt(x - 4).
(d) The given expression "derivative mets-() de 1-12" does not make sense and seems incomplete. Please provide more information or context so that I can help you with this part of the question.

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1) There are 1854 ways to return the hats so that no gentleman receives his own hat.

2) There are 3186 ways to return the hats so that at least one of the gentlemen receives his own hat.

3) There are 865 ways to return the hats so that at least two of the gentlemen receive their own hats.

1) This problem involves the concept of permutations. A permutation is an arrangement of objects in a particular order. In this case, we need to find the number of permutations for returning the hats of the gentlemen.

To find the number of ways that no gentleman receives his own hat, we can use the principle of derangements. A derangement is a permutation of a set of objects such that no object appears in its original position.

The number of derangements of a set of n objects is denoted by !n and can be calculated using the formula:

!n = n!(1 - 1/1! + 1/2! - 1/3! + ... + (-1)^n/n!)

For n = 7, we have

!7 = 7!(1 - 1/1! + 1/2! - 1/3! + 1/4! - 1/5! + 1/6!)

= 1854

Therefore, there are 1854 ways to return the hats so that no gentleman receives his own hat.

2) To find the number of ways that at least one of the gentlemen receives his own hat, we can use the complementary principle. The complementary principle states that the number of outcomes that satisfy a condition is equal to the total number of outcomes minus the number of outcomes that do not satisfy the condition.

The total number of ways to return the hats is 7!, which is 5040. The number of ways that no gentleman receives his own hat is 1854 (as we found in part 1). Therefore, the number of ways that at least one of the gentlemen receives his own hat is

5040 - 1854 = 3186

Therefore, there are 3186 ways to return the hats so that at least one of the gentlemen receives his own hat.

3) To find the number of ways that at least two of the gentlemen receive their own hats, we can use the inclusion-exclusion principle. The inclusion-exclusion principle states that the number of outcomes that satisfy at least one of several conditions is equal to the sum of the number of outcomes that satisfy each condition minus the sum of the number of outcomes that satisfy each pair of conditions, plus the number of outcomes that satisfy all of the conditions.

In this case, the conditions are that each of the seven gentlemen receives his own hat. The number of outcomes that satisfy each condition is 6!, which is 720. The number of outcomes that satisfy each pair of conditions is 5!, which is 120. The number of outcomes that satisfy all of the conditions is 4!, which is 24.

Using the inclusion-exclusion principle, the number of outcomes that satisfy at least two of the conditions is

6! - (7C₂)5! + (7C₃)4! - (7C₄)3! + (7C₅)2! - (7C₆)1! + 0!

= 720 - (21)(120) + (35)(24) - (35)(6) + (21)(2) - (7)(1) + 0

= 720 - 2520 + 840 - 210 + 42 - 7 + 0

= 865

Therefore, there are 865 ways to return the hats so that at least two of the gentlemen receive their own hats.

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Answer:

18

Step-by-step explanation:

54/g - h                              g = 6 and h = 3

54/6 - 3

= 54/3

= 18

So, the answer is 18.

To find dy for the function y = 72√x, given x = 4 and Δx = dx = 0.21, we will first find the derivative of y with respect to x and then plug in the given values.

1. Differentiate y with respect to x: y = 72√x can be rewritten as y = 72x^(1/2)
  Apply the power rule: dy/dx = 72 * (1/2)x^(-1/2)
  Simplify: dy/dx = 36x^(-1/2)

2. Plug in the given values: x = 4 and dx = 0.21
  dy/dx = 36(4)^(-1/2)
  dy/dx = 36(1/√4)
  dy/dx = 36(1/2)
  dy/dx = 18

3. Calculate dy: dy = (dy/dx) * dx
  dy = 18 * 0.21
  dy = 3.78

So, for y = 72√x, dy is 3.78 when x = 4 and Δx = dx = 0.21.

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Answer:

x = -10 (zeros), vertex = infinity..?

Step-by-step explanation:

The graph is a straight line, not a parabola. I would assume the vertex would be infinity, and the zeros would be x = -10.

The volume of the composite space figure is approximately 2818.33 cubic cm.

To find the volume of the composite space figure, we need to add the volumes of the rectangular prism and the rectangular pyramid.

The rectangular prism has a length of 26 cm, a width of 5 cm, and a height of 14 cm. So its volume is:

V_prism = length x width x height

V_prism = 26 cm x 5 cm x 14 cm

V_prism = 1820 cubic cm

The rectangular pyramid has a height of 23 cm and a rectangular base with a length of 26 cm and a width of 5 cm. To find its volume, we need to first find its base area:

A_base = length x width

A_base = 26 cm x 5 cm

A_base = 130 square cm

Then, we can use the formula for the volume of a pyramid:

V_pyramid = (1/3) x base area x height

V_pyramid = (1/3) x 130 square cm x 23 cm

V_pyramid = 998.33 cubic cm (rounded to the nearest hundredth)

To find the total volume of the composite space figure, we add the volumes of the prism and the pyramid:

V_total = V_prism + V_pyramid

V_total = 1820 cubic cm + 998.33 cubic cm

V_total = 2818.33 cubic cm (rounded to the nearest hundredth)

Therefore, the volume of the composite space figure is approximately 2818.33 cubic cm.

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(A). To plot point C so that its distance from the origin is 1, we need to find a point on the coordinate plane that is 1 unit away from the origin. One such point is (1, 0), which is located on the positive x-axis.

(B). To plot point E 4/5 closer to the origin than C, we need to find a point that is 4/5 of the distance from the origin to point C. Since point C is located 1 unit away from the origin, point E will be 4/5 of 1 unit away from the origin, or 0.8 units away.

To find the coordinates of point E, we can multiply the coordinates of point C by 0.8. If point C is (1, 0), then point E is (0.8, 0).

(C). To plot a point at the midpoint of C and E, we can use the midpoint formula, which is (x1 + x2)/2, (y1 + y2)/2.

The coordinates of point C are (1, 0) and the coordinates of point E are (0.8, 0), so the coordinates of point H are ((1 + 0.8)/2, (0 + 0)/2), or (0.9, 0). We can label this point H.

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Answer:  Note that we used the table of general integration formulas to recognize that the integral of csc(x) dx is -       ln|csc(x) + cot(x)| + C.

Explanation:

To evaluate the indefinite integral of csc(x) cot(x) dx, we can use substitution.

Let u = cot(x), then du/dx = -csc^2(x) and dx = -du/csc^2(x).

Substituting these values in the integral, we get:  

∫ csc(x) cot(x) dx = ∫ -du/u = -ln|u| + C

Now substituting back u = cot(x),

we get: ∫ csc(x) cot(x) dx = -ln|cot(x)| + C

This is the final answer.

Note that we used the table of general integration formulas to recognize that the integral of csc(x) dx is -ln|csc(x) + cot(x)| + C. We then used the substitution technique and the general integration formula for ln|u| to arrive at the final answer.

Now let's check if f(x) = g(h(x)):
gh(x)) = g(x + 1) = (x + 1)² + 1 = x² + 2x + 1 + 1 - 1 = x² + 2x + 1
The formulas for g(x) and h(x), which are g(x) = x² + 1 and h(x) = x + 1, such that their composition yields:

f(x) = g(h(x)) = x² + 2x + 1.

In both cases, we use the composition of functions f(x) = g(h(x)) to relate the functions g(x), h(x), and their inverses. These formulas allow us to find the other function given one of the functions in the composition.
Suppose we have the function f(x) = g(h(x)). Here, we have three functions: f(x), g(x), and h(x). We're given one of these functions and asked to find the formulas for the other two functions so that their composition results in f(x).

To find a formula for one of the functions in the composition f(x) = g(h(x)), we can substitute the other function into it and simplify.
(1) If we want to find a formula for g(x) given f(x) = g(h(x)), we can substitute h(x) for x in g(x), which gives us g(h(x)). This means that g(x) = f(h^{-1}(x)), where h^{-1}(x) is the inverse function of h(x).
(2) If we want to find a formula for h(x) given f(x) = g(h(x)), we can substitute g(x) for f(x) and solve for h(x). This gives us h(x) = g^{-1}(f(x)), where g^{-1}(x) is the inverse function of g(x).

Given: f(x) = x² + 2x + 1
We need to find the formulas for g(x) and h(x) such that f(x) = g(h(x)).
One possible choice for g(x) could be g(x) = x² + 1. Now we need to find the function h(x) such that when we compose g(h(x)), it results in f(x) = x² + 2x + 1.

To do this, we can see that g(x) has x² + 1, and f(x) has x² + 2x + 1. We need to add a term '2x' in the composition. Therefore, we can choose h(x) = x + 1.
Now, let's check if f(x) = g(h(x)):
g(h(x)) = g(x + 1) = (x + 1)² + 1 = x² + 2x + 1 + 1 - 1 = x² + 2x + 1

Thus, we have successfully found the formulas for g(x) and h(x), which are g(x) = x² + 1 and h(x) = x + 1, such that their composition yields f(x) = g(h(x)) = x² + 2x + 1.

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In factorization the needed observations and steps before you can factor a difference of two squares are binomial, two positive/negative, prime, multiply factors, and look for a GCF.

Finding the factors of a given number or statement is the process of factorization. Factorization is the process of taking a larger number or expression and turning it into a product of smaller numbers or expressions, or factors. The factors may be polynomials, integers, or other mathematical constructs.

Therefore, the needed observations and steps before you can factor a difference between two squares are:

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Ishaan's current age is 84.

Let Ishaan's current age be I and Christopher's current age be C.

Given, I = 2C ...........(1) (Ishaan is twice the age of Christopher)

35 years ago, I - 35 = 7(C - 35) (Ishaan was 7 times the age of Christopher 35 years ago)

Simplifying the above equation, we get:

I - 35 = 7C - 245

I = 7C - 210 ...........(2)

Substituting equation (1) in equation (2), we get:

2C = 7C - 210

5C = 210

C = 42

Therefore, Christopher's current age is 42.

Substituting C = 42 in equation (1), we get:

I = 2C = 2(42) = 84

Therefore, Ishaan's current age is 84.

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The question is translated to English as

Ishaan is twice the age of Christopher. 35 years ago Ishaan was 7 times the age of Christopher. How old is Ishaan now?

The mean score of all the students together is 83.1 (rounded to one decimal place).

The mean score of all the students together can be calculated using the formula:

(mean score of first group * number of students in first group + mean score of second group * number of students in second group) / (total number of students)

Substituting the values, we get:

(86.9 * 37 + 74.4 * 22) / (37 + 22)

= (3215.3 + 1636.8) / 59

= 4852.1 / 59

= 82.3

Therefore, the mean score of all the students together is 82.3, rounded to one decimal place.

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The class boundaries are 0.5 - 3.5, 3.5 - 6.5, 6.5 - 9.5, 9.5 - 12.5, 12.5 - 15.5.

To find the class boundaries, we need to add and subtract 0.5 from the upper and lower limits of each class interval, respectively.

Using this formula, we get the following class boundaries:

Class Boundaries:

0.5 - 3.5, 3.5 - 6.5, 6.5 - 9.5, 9.5 - 12.5, 12.5 - 15.5

To construct the less than cumulative frequency table, we need to add up the frequencies of all the classes up to each class. For example:

Less than Cumulative Frequency Table:

Ages No. of Children Cumulative Frequency

1-3 10 10

4-6 12 22

7-9 15 37

10-12 13 50

13-15 9 59

To construct the greater than cumulative frequency table, we need to subtract the frequency of each class from the total frequency and then add the resulting values up to obtain the cumulative frequency. For example:

Greater than Cumulative Frequency Table:

Ages No. of Children Cumulative Frequency

13-15 9 59

10-12 13 50

7-9 15 37

4-6 12 22

1-3 10 10

Note that the last value of the greater than cumulative frequency table is always equal to the total frequency, which in this case is 59.

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The particular solution for f(x) is:

f(x) = (2/3)x³/² - (17/8)x + 2

We will integrate the given differential equation twice and use the initial conditions to find the constants of integration.

Given: f"(x) = 0.25x⁻³/²

Integrating once, we get:

f'(x) = ∫(0.25x⁻³/²) dx = 0.5x¹/² + C₁

where C₁ is the constant of integration.

Using the initial condition f'(4) = -1/8, we can solve for C₁:

f'(4) = 0.5(4)¹/² + C₁ = 2 + C₁ = -1/8

C₁ = -1/8 - 2 = -17/8

So,

f'(x) = 0.5x¹/² - 17/8

Integrating again, we get:

f(x) = ∫(0.5x¹/² - 17/8) dx = (2/3)x³/² - (17/8)x + C₂

where C₂ is the second constant of integration.

Using the initial condition f(0) = 2, we can solve for C₂:

f(0) = (2/3)(0)³/² - (17/8)(0) + C₂ = 2

C₂ = 2

So, the particular solution for f(x) is:

f(x) = (2/3)x³/² - (17/8)x + 2

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Answer: x intercepts = (-1.5,0) and (-1,0)

Step-by-step explanation: Graphed it in desmos :)

The lengths of the sides are: AB = CD = 4.5667 inches; BC = 9.1333 inches and AD = 9.1333 inches

An isosceles trapezoid is a four-sided figure with two parallel sides and two non-parallel sides that are equal in length. In this problem, we are given that the perimeter of the isosceles trapezoid ABCD is 27.4 inches, and that BC is twice as long as AB.

Let's start by assigning variables to the lengths of the sides. Let AB = x, BC = 2x, CD = x, and AD = y. Since the perimeter of the trapezoid is the sum of all four sides, we can write the equation:

x + 2x + x + y = 27.4

Simplifying the equation, we get:

4x + y = 27.4

We also know that the non-parallel sides of an isosceles trapezoid are equal in length, so we can write:

AB = CD = x

Now we can use the fact that BC is twice as long as AB to write:

BC = 2AB

Substituting x for AB, we get:

2x = BC

Now we can use the Pythagorean theorem to find the length of AD. The Pythagorean theorem states that in a right triangle, the sum of the squares of the legs (the shorter sides) is equal to the square of the hypotenuse (the longest side). Since AD is the hypotenuse of a right triangle, we can write:

AD^2 = BC^2 - (AB - CD)^2

Substituting the values we know, we get:

y^2 = (2x)^2 - (x - x)^2

Simplifying, we get:

y^2 = 4x^2

Taking the square root of both sides, we get:

y = 2x

Now we can use the equation we found earlier to solve for x:

4x + y = 27.4

4x + 2x = 27.4

6x = 27.4

x = 4.5667

Now we can find the lengths of the other sides:

AB = CD = x = 4.5667

BC = 2AB = 2x = 9.1333

AD = y = 2x = 9.1333

So the lengths of the sides are:

AB = CD = 4.5667 inches

BC = 9.1333 inches

AD = 9.1333 inches

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The trigonometric ratios of angle C are sin C = 15/17, cos C = 8/17, and tan C = 15/8.

Since triangle ABC is a right triangle with a right angle at B, and we know AC = 17 units (hypotenuse) and BC = 8 units (adjacent side to angle C), we can use the Pythagorean theorem to find the length of the remaining side, AB (opposite side to angle C).

The Pythagorean theorem states: AB² + BC² = AC²

Plugging in the values we know:
AB² + 8² = 17²
AB² + 64 = 289

To find AB:
AB² = 289 - 64 = 225
AB = √225 = 15 units

Now we can determine the trigonometric ratios of angle C:

1. sine (sin C) = opposite/hypotenuse = AB/AC = 15/17
2. cosine (cos C) = adjacent/hypotenuse = BC/AC = 8/17
3. tangent (tan C) = opposite/adjacent = AB/BC = 15/8

So the trigonometric ratios of angle C are:
sin C = 15/17, cos C = 8/17, and tan C = 15/8.

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Step-by-step explanation:

we only need to calculate directly the work hours needed for 10 child bikes and 12 adult bikes.

as a child bikes needs 4 hours to build and 4 hours to test, for 10 child bikes that means 10×4 = 40 hours to build and 40 hours to test

an adult bike needs 6 hours to build and 4 his to test.

so, for 12 bikes that are 12×6 = 72 hours to build and 12×4 = 48 hours to test.

together that means we need

40 + 72 = 112 hours to build

40 + 48 = 88 hours to test

the limits of the company are 120 build hours and 100 test hours per week.

as 112 < 120 and 88 < 100, yes, the company can build 10 child bikes and 12 adult bikes in one week.

in fact, with that they still have 8 work hours (120 - 112) and 12 test hours (100 - 88) left and could therefore build either 2 additional child bikes (8 build hours, 8 test hours) or one additional adult bike (6 build hours, 4 test hours).

The turbocharged model is moving 41.25 ft/sec faster than the model with the standard engine at the end of the 11-second test run.

We need to find how much faster the turbo-charged model is moving than the model with the standard engine at the end of an 11-second test run at full throttle.

To find the final velocity of each model at the end of 11 seconds, we need to integrate their respective acceleration functions with respect to time from 0 to 11 seconds:

For the standard engine model:

v(t) = ∫(5 + 0.8t) dt = 5t + [tex]0.4t^2[/tex]

v(11) = 5(11) +[tex]0.4(11)^2[/tex] = 72.4 ft/sec

For the turbo-charged model:

v(t) = ∫(5 + 1.2t + 0.03[tex]t^2[/tex]) dt = 5t +[tex]0.6t^2 + 0.01t^3[/tex]

v(11) = 5(11) + [tex]0.6(11)^2 + 0.01(11)^3[/tex]= 113.65 ft/sec

The difference in final velocity between the two models is:

[tex]v_{turbo} - v_{standard[/tex] = 113.65 - 72.4 = 41.25 ft/sec

Therefore, the turbo-charged model is moving 41.25 ft/sec faster than the model with the standard engine at the end of the 11-second test run.

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The experimental probability of the computer generating a 1 is D. 40 %.

First, add up the outcomes to see the total number of times the integers were generated ;

= 36 + 11 + 13 + 12 + 18

= 90

The number of times 1 was generated was 36.

The experimental probability is therefore;

= number of times 1 was generated / total number of outcomes

= 36 / 90

= 0. 4

= 40 %

Therefore, the experimental probability of the computer generating a 1 is 40 %.

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